The total charge on 7 particles is −42 units. All the particles have the same charge.

What is the charge on each particle?

6 units
5 units
−5 units
−6 units

The length of A'B' = 5 units

The line segment AB is of 5 units. AB is then transformed through translation of 3 units to the right.

The translation only means change through a straight line. This transformation does not change the length of a line segment.

So the length of A'B' will also be 5 units.

But the position of A'B' will be different from that of AB on the co-ordinate plane. To be exactly, A'B' would be 3 units right to the position of AB on the co-ordinate plane.

Also the co-ordinates of A'B' will be different. Still their lengths will be same.

Thus the length of A'B' = 5 units

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Answer:

To calculate the surface area and volume of a cylinder, we can use the following formulas:

a) Surface Area of a Cylinder:

The surface area of a cylinder consists of two circles (top and bottom) and the curved surface area.

The formula for the surface area of a cylinder is:

SA = 2πr² + 2πrh

Where:

SA = Surface Area

r = Radius of the base (half the diameter)

h = Height of the cylinder

Given that the diameter is 16 yards, the radius is half of that, so r = 8 yards. The height is 20 yards.

Substituting the values into the formula, we get:

SA = 2π(8)² + 2π(8)(20)

= 2π(64) + 2π(160)

= 128π + 320π

= 448π

So, the surface area of the cylinder is 448π square yards.

b) Volume of a Cylinder:

The formula for the volume of a cylinder is:

V = πr²h

Using the same values for the radius (r = 8 yards) and height (h = 20 yards), we can calculate the volume:

V = π(8)²(20)

= 64π(20)

= 1280π

The volume of the cylinder is 1280π cubic yards.

The intervals, if any, where h is decreasing will be B. 4.323 ≤ x ≤ 5.461.

A function simply has to do with the statement that illustrates the variables given. In this case, it is vital to note that two or more components are considered in order to be able to describe the scenario.

Based on the information, function h is given by h(x)=∫x 1 ln(t sint 5)ⅆt for 1≤x≤7. It should be noted that x will give the range of 4.323 and 5.4613.

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The parametric form can be written as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

A matrix equation of the form \($A\overrightarrow x=0\) is called homogeneous matrix equation.

A matrix equation of the form  \($A\overrightarrow x=\overrightarrow b\) is called non - homogeneous matrix equation.

Given is to find the solution in parametric vector form.

If there are {m} free variables in the homogeneous equation, the solution set can be expressed as the span of {m} vectors :

\($\overrightarrow x=s_{1} \overrightarrow v_{1} + s_{2} \overrightarrow v_{2}+......+s_{m} \overrightarrow v_{m}\)

We have a matrix where {A} is the row equivalent to that matrix -

\(\begin{bmatrix} 1&3&0&-4 \\ 2&6&0&-8 \end{bmatrix}\)

Given matrix can be written in Augmented form as -

\(\left[ \begin{array}{cccc|c} 1&3&0&-4 & 0\\2&6&0&-8&0\\ \end{array} \right]\)

Row Reduced Echelon Form can be obtained using the following steps -

{ 1 } - Interchanging the rows R{1} and R{2}.

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0 \\ 1&3&0 &-4 & 0 \\ \end{array} \right]\)

{ 2 } - Applying the operation R{2} -> 2R{2} - R{1}, to make the second 0.

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\1&3&0&-4&0 \\ \end{array} \right] \;\;\;\;\;\;R_2 \rightarrow 2R_2 - R_1\)

\(\left[ \begin{array}{cccc|c} 2 & 6 & 0 & -8 & 0 \\ 0 & 0 & 0 & 0 & 0 \\ \end{array} \right]\)

{ 3 } - Using R{1} -> R{1}/2

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\0&0&0&0&0\\ \end{array} \right]  \;\;R_1 \rightarrow \dfrac{1}{2} R_1\)

{ 4 } - Following equation can be deducted as

\(x_1 + 3x_2 - 4x_4 =0\)

{ 5 } - We can write the parametric form as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

Therefore, the parametric form can be written as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

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Answer: 3/52

Step-by-step explanation:

You want to pick a diamond jack, diamond queen or diamond king

There are only 3 of those so

P(DJ or DQ or DK) = 3/52        There are 3 of those out of 52 total

The z-values for the given situations are approximate:

a. The area to the left of z is 0.1827. z = -0.90

b. The area between −z and z is 0.9830. z = 2.17

c. The area between −z and z is 0.2148. z = 0.85

d. The area to the left of z is 0.9997. z = 3.49

e. The area to the right of z is 0.6847. z= -0.48

a. For an area of 0.1827 to the left of z, the corresponding z-value can be found using a standard normal distribution table or a statistical calculator. The z-value is approximately -0.90.

b. To find the z-value for an area between -z and z equal to 0.9830, we need to find the value that corresponds to (1 - 0.9830)/2 = 0.0085 in the upper tail of the standard normal distribution. Using the table or calculator, the z-value is approximately 2.17.

c. Similarly, for an area between -z and z equal to 0.2148, we find the value that corresponds to (1 - 0.2148)/2 = 0.3926 in the upper tail. The z-value is approximately 0.85.

d. For an area of 0.9997 to the left of z, we find the value that corresponds to 0.9997 in the upper tail. The z-value is approximately 3.49.

e. To find the z-value for an area to the right of z equal to 0.6847, we find the value that corresponds to 1 - 0.6847 = 0.3153 in the upper tail. The z-value is approximately -0.48.

In summary, the z-values for the given situations are approximate:

a. -0.90

b. 2.17

c. 0.85

d. 3.49

e. -0.48

These values can be used to determine the corresponding percentiles or probabilities for the standard normal distribution. The values are typically found using standard normal distribution tables or statistical calculators that provide the cumulative probability distribution function (CDF) for the standard normal distribution.

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Answer: The tree is 27 feet tall.

Step-by-step explanation:

Here's what we know:

6/10 = x/45 (a 6 foot object creating a 10 shadow is equivalent to something else making a 45 shadow)

We need to isolate x. Multiply both sides by 45:

6*45/10 = x

We can factor out a 2:

3*45/5 = x

We can also factor out a 5:

3*9/1 = x

27 = x

The tree is 27 feet tall.

The set of probabilities for the number of eaglets is the

probabilities for how many eaglets will survive.

The table that shows the probability distribution is the option C;

X      0         1         2

p(x)   0.35   0.60   0.05

  P(O) = 0.5 is the likelihood that the elder eaglet will live.

  Therefore;

   P(O') = 1 - 0.5 = 0.5 is the probability that the older eaglet won't survive.

  The likelihood that the younger eaglet will survive if the older eaglet              does not P(Y|O) = 10%

Therefore;

The likelihood that the elder eaglet will live while the younger eaglet does not survive is P(Y'|O) = 1 - 10% = 90%.

When the older eaglet does not survive, the younger eaglet has a 30% survival chance (P(Y|O')).

Therefore;

The likelihood that the younger eaglet will not survive, compared to the elder eaglet, is P(Y'|O') = 1 - 30% = 70%

The collection of potential probabilities for the number of eaglets that survive is expressed as the probability distribution, or P(X)

The range of potential results includes:

Never survives:

The likelihood that no eaglets survive is equal to P(O') × P(Y'|O') = 0.5 × 0.7 = 0.35.

The only survivor is:

The likelihood that only one eaglet survives is determined by P(O) = P(Y'|O) × P(O') = P(Y|O'), which results in P = 0.5 × 0.9 + 0.5 × 0.3 = 0.6 Both survive:

The odds of both eaglets surviving are P(O) ×P(Y|O) = 0.5 × 0.1 = 0.05.

The table of the probability distribution is therefore;

X      0         1         2

p(x)   0.35   0.60   0.05

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Answer:

Domain and range: [0, ∞)

Step-by-step explanation:

There is no limit to the number of concert tickets someone can buy, but there cannot be negative concert tickets. The domain, or what the input can be, is [0, ∞) as it can be greater than or equal to 0

The range is the total cost, or what the output can be. Since the total cost is the number of tickets multiplied by 55 (as it is $55 per ticket), this can be represented by 55 * number of tickets. The total cost cannot be negative, but it can be 0 if no one buys tickets. As there is no limit to the amount of tickets someone can buy, there is no limit to what the total cost could be, making the range [0, ∞)

The interest practice described in the question is known as "bundling." Bundling refers to the act of combining individual campaign contributions from multiple sources into a single larger contribution from a group or organization.

Bundling allows interest groups or individuals to pool their resources and present a more substantial contribution to a candidate. By consolidating smaller contributions into a larger sum, bundlers can demonstrate greater financial support and influence.

This practice is often employed by special interest groups, lobbyists, or individuals with shared political objectives who want to maximize their influence on the political process. Bundlers can leverage their collective financial power to gain access to candidates, shape policy agendas, and potentially gain favorable treatment or influence over decision-making.

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Answer: you would make $440

Answer: $660 monthly

Step-by-step explanation:

1 Hour = $ 11

15 Hour = $ 165

That means you make $ 165 dollars in a week .

There are 4 weeks in a month which means 165 x 4

That is $660 in 4 weeks .      

Answer:

Second and Third

Step-by-step explanation:

Simple math.

4*1.25=5 and 5*4=20 20+5=25 Wrong

8*1.25=10 and 5*4=20 20+10=30 Right

24*1.25=30 right

5*1.25=6.25 and 8*4=32 Wrong

it is 24 children , 7.5 adult

30/1.25 and 30/4.00

The acute angle that the ladder makes with the ground is 70.94°.

To work out the size of the acute angle that the ladder makes with the ground, we need to use trigonometry. Let's call the angle we're trying to find "theta" (θ). We know that the ladder is the hypotenuse of a right-angled triangle, with the wall being one side and the ground being the other. Using the Pythagorean theorem, we can work out the length of the ladder's side of the triangle:
a² + b² = c²
where a = 1.8m (the distance from the wall to the base of the ladder), b =? (the distance from the base of the ladder to the ground), and c = 5.1m (the length of the ladder).
Rearranging this formula, we get:
b² = c² - a²
b² = (5.1)² - (1.8)²
b² = 24.21
b = √24.21
b = 4.92m (to 2 decimal places)
Now that we know the lengths of the sides of the triangle, we can use trigonometry to find the angle θ. Specifically, we can use the tangent function:
tan(θ) = opposite/adjacent
where opposite = b (the distance from the base of the ladder to the ground) and adjacent = a (the distance from the wall to the base of the ladder).
tan(θ) = 4.92/1.8
tan(θ) = 2.7333 (to 4 decimal places)
Now we need to find the inverse tangent (or arctan) of this value to get the angle θ:
θ = arctan(2.7333)
θ = 70.94° (to 1 decimal place)
Therefore, the acute angle that the ladder makes with the ground is 70.94°.

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The percent of adult American males could enter this contest is 2.23%

Normal usually refers to the word "normal" in a normal distribution.

The word normal is used when something occurs that has occurred frequently. The normal distribution is somewhat similar where the main observation (mean or its surrounding) occurs frequently and as we go far from the mean, its chances decrease.

We solve using z score formula

z = (x-μ)/σ,

where, x is the raw score = < 64 inches

μ is the population mean = 69

σ is the population standard deviation = 2.5

Here Participants must be less than 64 inches tall.

For x < 64 inches

z = 64 - 69/2.5

z = -2

Probability value from Z-Table:

P(x<64) = 0.02275

Converting to percentage;

= 0.02275 × 100

= 2.275%

Approximately = 2.23%

The participants must be less than 64 inches tall to participate in this limbo contest, the percent of adult American males thag could enter this contest is 2.23%

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Answer:

a = 1,. b = 2, c = -15

Step-by-step explanation:

\(x^2+2x-15=0\)

Comparing the above equation with \(ax^2+bx+c=0\), we find :

a = 1

b = 2

c = -15

Traits can be dominant or recessive, and the recessive traits were obscured by the dominant ones in the F1 generation.

Given,

In the question:

Mendel accounted for the observation that traits which had disappeared in the f1 generation reappeared in the f2 generation by proposing that___

Now, According to the question:

Fill up the above blank:

Mendel accounted for the observation that traits which had disappeared in the f1 generation reappeared in the f2 generation by proposing that__

Solution:

In the Mendel’s experiment, some traits which were absent in the F1 generation appeared in the second generation cross. By this he concluded, that the traits expressed in the F1 generation were dominant and hence they capped the expression of traits associated with recessive allele. He classified the traits in F2 generation as recessive, because these traits can occur only when they are in pair i.e they form individuals with homozygous recessive genotype.  

For instance – If “R” is allele for dominant red color trait and “r” is the allele for recessive white color trait, then the cross between true breeding red flowers and white flowers will produce following offspring  

RR * rr

Rr, Rr, Rr, Rr

Thus, in F1 generation all the offspring are heterozygous red

F2 generation-  

Rr * Rr

RR, Rr, Rr, rr

The recessive trait of white colored flower reappears in second generation.

Hence, Traits can be dominant or recessive, and the recessive traits were obscured by the dominant ones in the F1 generation.

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Answer:

AUB = B

Step-by-step explanation:

If A ⊂ B then every element of A is also in B.

There are two real number solutions for x2 − 5x + 7 = 0: x = 2 and x = 7.

1. x2 − 5x + 7 = 0

2. (x - 2)(x - 7) = 0

3. x = 2 or x = 7

When solving for the real number solutions of x2 − 5x + 7 = 0, we first need to factor the equation into two linear terms: (x - 2)(x - 7) = 0. From here, we can use the Zero Product Property to determine that x = 2 and x = 7 are the two real number solutions of this equation. This means that when x is equal to 2 or 7, the equation will equal 0 and all other values of x will result in a non-zero answer. Therefore, the only two real number solutions of x2 − 5x + 7 = 0 are x = 2 and x = 7.

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Answer:

x = 6

Step-by-step explanation:

The perimeter is the sum of the 3 sides of the triangle. Sum the 3 sides and equate to 51, that is

15 + 5x - 6 + 2x = 51

7x + 9 = 51 ( subtract 9 from both sides )

7x = 42 ( divide both sides by 7 )

x = 6

Therefore, the center of the circle is located at (0, 6), and the length of the radius is approximately equal to 7.43.

To determine the coordinates of the center and length of the radius of the circle, we need to rewrite the given equation in standard form, which is\((x - h)^2 + (y - k)^2 = r^2\), where (h, k) represents the center coordinates and r represents the radius.

Given equation: \(x^2 + y^2 - 12y - 20.25 = 0\)

To complete the square, we need to add and subtract the appropriate terms on the left side of the equation:

\(x^2 + y^2 - 12y - 20.25 + 36 = 36\)

\(x^2 + (y^2 - 12y + 36) - 20.25 + 36 = 36\)

Simplifying further:

\(x^2 + (y - 6)^2 = 55.25\)

Comparing this equation with the standard form, we can identify the following values:

Center coordinates: (h, k) = (0, 6)

Radius length:\(r^2\) = 55.25, so the radius length is √55.25.

Therefore, the center of the circle is located at (0, 6), and the length of the radius is approximately equal to 7.43.

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Answer:

ok that is so hard I CAN not do it

Answer:

i am tired of being single but i do not no at all that seems really hard i feel bad for u

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Since one place to the right is greater than or equal to 5 you round up.

Answer:a and d

Step-by-step explanation:

Answer:

\(-\frac{1}{64}\)

Step-by-step explanation:

Evaluate the following limit.

\(\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}\)

(1) - Simplify the limit

\(\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}\\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{1(8)}{(x+8)(8)} -\frac{1(x+8)}{8(x+8)} }{x}\\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{8-x-8}{8(x+8)} }{x} \\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{ -x}{8(x+8)} }{x} \\\\\Longrightarrow \lim_{x \to 0} \frac{-x}{8x(x+8)} \\\\\Longrightarrow \boxed{\lim_{x \to 0} \frac{-1}{8(x+8)} }\)

(2) - Plug in the limit

\(\lim_{x \to 0} \frac{-1}{8(x+8)}\\\\\Longrightarrow \lim_{x \to 0} \frac{-1}{8((0)+8)}\\\\\Longrightarrow \lim_{x \to 0} \frac{-1}{8(8)} \\\\\therefore \boxed{\boxed{\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}=-\frac{1}{64} }}\)

Answer:

Volume = 261.8 cm³

Surface area = 254.2 cm²

Step-by-step explanation:

To calculate the volume of the cone, we have to use the following formula:

\(\boxed{V = \frac{1}{3} \pi r^2 h}\),

where:

V ⇒ volume

r ⇒ radius = 5 cm

h ⇒ height = 10 cm

Using the above formula and the provided measures, we get:

V = \(\frac{1}{3}\) × π × (5)² × 10

    = \(\frac{1}{3}\) × π × 25 × 10

      = 261.8 cm³

In order to calculate the surface area of the cone, we have to use the following formula:

\(\boxed{SA = \pi r^2 + \pi r l}\)

where:

SA ⇒ surface area

r ⇒ radius = 5 cm

l ⇒ slant length = \(\sqrt{r^2+h^2}\) = \(\sqrt{5^2+10^2}\) = 5√5 cm

Using the formula,

SA = π × (5)² + π × 5 × 5√5

     = π × 25 + π × 25√5

     = 254.2 cm²

Let's start solving the expression using the product to sum formulae.

Here's the given expression,

\[\sin \frac{x}{3} \cos \frac{2 x}{3}+\cos \frac{x}{3} \sin \frac{2 x}{3}\]

Using the product-to-sum formula,

\[\sin A \cos B=\frac{1}{2}[\sin (A+B)+\sin (A-B)]\]

Applying the above formula in the first term,

\[\begin{aligned}\sin \frac{x}{3} \cos \frac{2 x}{3} &= \frac{1}{2} \left[\sin \left(\frac{x}{3}+\frac{2 x}{3}\right)+\sin \left(\frac{x}{3}-\frac{2 x}{3}\right)\right] \\&= \frac{1}{2} \left[\sin x+\sin \left(-\frac{x}{3}\right)\right]\end{aligned}\]

Using the product-to-sum formula,

\[\cos A \sin B=\frac{1}{2}[\sin (A+B)-\sin (A-B)]\]

Applying the above formula in the second term,

\[\begin{aligned}\cos \frac{x}{3} \sin \frac{2 x}{3}&= \frac{1}{2} \left[\sin \left(\frac{2 x}{3}+\frac{x}{3}\right)-\sin \left(\frac{2 x}{3}-\frac{x}{3}\right)\right] \\ &= \frac{1}{2} \left[\sin x-\sin \left(\frac{x}{3}\right)\right]\end{aligned}\]

Substituting these expressions back into the original expression,

we have\[\begin{aligned}\sin \frac{x}{3} \cos \frac{2 x}{3}+\cos \frac{x}{3} \sin \frac{2 x}{3} &= \frac{1}{2} \left[\sin x+\sin \left(-\frac{x}{3}\right)\right]+\frac{1}{2} \left[\sin x-\sin \left(\frac{x}{3}\right)\right] \\ &=\frac{1}{2} \sin x + \frac{1}{2} \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)\\ &= \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)\end{aligned}\]

Therefore, the given expression can be written in terms of a single trigonometric function as:

\boxed{\sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)}

Hence, the required expression is \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right). The solution is complete.

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The standard deviation of x is 3 cars. So the option A is correct.

Suppose that x is the number of cars per minute that pass through a certain intersection, and that x has the Poisson distribution.

If the mean of x is equal to 9 cars, then we have to determine the standard deviation of x.

An indicator of how much variance from the mean there is is the standard deviation, which can be expressed as spread, dispersion, or spread. A "typical" departure from the mean is represented by the standard deviation. As a result of returning to the data set's original units of measure, it is a well-liked measure of variability.

The Mean = 9 cars

Standard Deviation = Square Root of Mean

Standard Deviation = √9

Standard Deviation = 3 cars

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