The temperature of sulfur dioxide is changed, causing a change in volume from 20. 923 L to 29. 508 L. If the new temperature is 260. 93 K,


what was its original temperature?


Your answer must include the following:


• The name of the law that applies to this problem


• The equation that you are going to use expressed in variables


• The answer with correct units

Answers

Answer 1

The law that applies to this problem is Charles's Law.

The equation for Charles's Law is \(\frac{V_{1} }{T_{1} }\) = \(\frac{V_{2} }{T_{2} }\)

The original temperature of sulfur dioxide was 185.12 K.

The law that applies to this problem is Charles's Law, which states that at constant pressure, the volume of a fixed amount of gas is directly proportional to its temperature in kelvin.

The equation for Charles's Law is \(\frac{V_{1} }{T_{1} }\) = \(\frac{V_{2} }{T_{2} }\), where \(V_{1}\) is the initial volume, \(T_{1}\) is the initial temperature, \(V_{2}\) is the final volume, and \(T_{2}\) is the final temperature.

Using the given values, we can plug them into the equation and solve for the initial temperature:

\(\frac{V_{1} }{T_{1} }\) = \(\frac{V_{2} }{T_{2} }\)
20.923/\(T_{1}\) = 29.508/260.93

Multiplying both sides by \(T_{1}\) and dividing by 29.508, we get:

\(T_{1}\) = (20.923/29.508) x 260.93 = 185.02 K

Therefore, the original temperature of sulfur dioxide was 185.12 K.

The answer with correct units is 185.12 K.

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Related Questions

Name the nutrient present in cooked rice , a boiler eggs

Answers

Explanation:

cooked rice

nutrient

carbohydrate.

Boiler eggs

nutrient

Protein.

I need some help with this I would really appreciate if you could help out. Thank You

I need some help with this I would really appreciate if you could help out. Thank You

Answers

The type of chemical reaction occuring in the table above is as follows:

DecompositionCombination CombustionSingle replacementDouble displacement

What is a chemical reaction?

A chemical reaction is a process involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

There are several types of chemical reactions as illustrated in the equation given in the above table. They are as follows:

Decomposition reaction; This involves the breaking down of a large substance into its subsequent parts.

Combination reaction: This involves the joining of two or more chemical elements to become one compound.

Combustion reaction: It is a process wherein a fuel is combined with oxygen, usually at high temperature, releasing heat.

Displacement reaction: In this reaction, one or more element is replaced in a compound by another in a chemical reaction.

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how would your calculations of the concentration of [fescn]2 been affected if the cuvette you used had a 1.5 cm path length rather than the 1.0 cm value you were told to use?

Answers

The increased distance across the cell will result in an increase absorbance reading.

The concentration of \([Fescn]_2\) would be affected if the cuvette had a 1.5 cm path length rather than the 1.0 cm value used.Since the absorbance of a sample is proportional to the concentration of a sample (as described by the Beer-Lambert law), increasing the path length of the cuvette would result in a decrease in absorbance. This means that the concentration of the sample would be lower than if the 1 cm path length was used. In other words, the concentration of \([Fescn]_2\)would be lower if the cuvette had a 1.5 cm path length than if it had a 1.0 cm path length.

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Which of the following diagrams represents the winter in the southern hemisphere?

Which of the following diagrams represents the winter in the southern hemisphere?

Answers

Answer:

Left position

If this don't help i am sorry but i tried

Explanation:

The figure is representing the motion of revolution of the Earth around the Sun.

This motion lasts approximately 365 days (one year). Since the axis of rotation of the Earth is tilted (by about 23 degrees from the vertical), the amount of light received by different parts of the Earth at the different part of the year is different.

In fact, we observe 4 "extreme" cases:

- Situation at the bottom: here the situation is symmetrical in the two hemispheres, which receive an equal amount of light. So, we have 12 hours of daylight and 12 hours of dark at every point on Earth - this is called equinox, and it occurs in September

- Situation on the right: here we see that the Southern Hemisphere receive much more light than the Northern Hemisphere - so the Southern Hemisphere has more hours of sunlight per day. This is called winter solstice, and it occurs in December - in this case, it is summer in the Southern Hemisphere and winter in the Northern Hemisphere

- Situation at the top: here the situation is symmetrical in the two hemispheres, which receive an equal amount of light. So, we have 12 hours of daylight and 12 hours of dark at every point on Earth - this is called equinox, and it occurs in March

- Situation on the left: here we see that the Northern Hemisphere receive much more light than the Southern Hemisphere - so the Northern Hemisphere has more hours of sunlight per day. This is called summer solstice, and it occurs in June - in this case, it is summer in the Northern Hemisphere and winter in the Southern Hemisphere

do all-stars mak energy through fusions

Answers

Yes they do make stars through fusions

we can consider a liquid-liquid extraction to be efficient if >90% of the desired compound can be recovered. presuming (i) the desired compound is soluble in the organic solvent and (ii) we use equal volumes of the organic solvent and water, what is the minimum value of the partition coefficient (k) to get an efficient extraction with only one extraction step (i.e. only mixing the organic solvent and water once, without further extractions using fresh portions of organic solvent)?

Answers

The minimum value of the partition coefficient (k) to get an efficient extraction with only one extraction step is 1.8.

To answer your question, we need to understand the concept of partition coefficient (k). Partition coefficient (k) is the ratio of the concentration of a solute in the organic phase to its concentration in the aqueous phase at equilibrium. It is a measure of the solubility of a solute in a particular solvent system.
Now, to get an efficient extraction with only one extraction step, we need to ensure that more than 90% of the desired compound is recovered. Given that the desired compound is soluble in the organic solvent and we use equal volumes of the organic solvent and water, the minimum value of the partition coefficient (k) can be calculated using the following formula:
k = [concentration of the desired compound in the organic phase] / [concentration of the desired compound in the aqueous phase]
To achieve an efficient extraction with only one extraction step, we need to ensure that more than 90% of the desired compound is extracted into the organic phase. This means that the concentration of the desired compound in the organic phase should be at least 90% of the initial concentration of the compound. Assuming equal volumes of the organic solvent and water are used, this can be represented as:
[concentration of the desired compound in the organic phase] >= 0.9 x [initial concentration of the desired compound]
Similarly, the concentration of the desired compound in the aqueous phase can be represented as:
[concentration of the desired compound in the aqueous phase] = [initial concentration of the desired compound] / 2
Substituting these values in the formula for k, we get:
k >= (0.9 x [initial concentration of the desired compound]) / ([initial concentration of the desired compound] / 2
Simplifying the expression, we get:
k >= 1.8
In summary, for an efficient extraction with only one extraction step, we need to ensure that the desired compound is soluble in the organic solvent and the partition coefficient (k) is equal to or greater than 1.8.

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If 67.5 mol of an ideal gas occupies 71.5 L at 47.00 °C, what is the pressure of the gas?

Answers

Ideal Gas Law: P = nRT/V
n = 67.5 mol
V = 71.5 L
T = 47°C + 273 K = 320 К
R = 0.0821

P = (67.5•0.0821•320) / 71.5 = 24.8 atm

Answer:

24.8 atm

Explanation:

For this problem, first identify all of the given quantities, and the requested quantity:

Amount: 67.5 mol

Volume: 71.5 L

Temperature: 47.00 °C

Pressure: ??

Since we are given that the gas is an "ideal gas", we can apply the ideal gas law, which relates all of the above quantities:

\(PV=nRT\), where

P is the pressure, V is the Volume, n is the amount in moles, R is the ideal gas constant (the value of R is different depending on which units are used for Pressure and Volume), and T is the Temperature measured in Kelvin.

For Pressure in units of "atmospheres" and Volume in units of "Liters", \(R=0.0821\frac{L \cdot atm}{mol \cdot K}\)

Recall that to convert Celsius to Kelvin, one must add 273.15 or use the equation \(T_C+273.15=T_K\)

So  \(T_K=(47.00 + 273.15)K=320.15K\), which is the temperature that we'll need for the Ideal Gas Law.

Since the Pressure is the unknown quantity, we can isolate P in the equation before substituting the known values:

\(PV=nRT\)

divide both sides by V...

\(P=\dfrac{nRT}{V}\)

Now, substitute and calculate:

\(P=\dfrac{(67.5~mol)(0.0821\frac{L \cdot atm}{mol \cdot K})(320.15~K)}{(71.5~L)}\)

\(P=24.8138638111888~atm\)

Accounting for significant digits, \(P=24.8~atm\)

Which solution contains the biggest amount of chloride ions?
I don’t understand why it’s B not D

Which solution contains the biggest amount of chloride ions? I dont understand why its B not D

Answers

Answer:

the quantity of solution to moles for d is significantly lower.

Explanation:

the larger the amount of liquid, the less amount of ions to dissociate hence having a lesser amount of chloride ions.

compared to b which is less liquid and a higher concentration

Solution B (MgCl₂) has a molarity of 0.20 mol/dm³ and a volume of 60 cm³.

Option (B) is correct.

First, we need to convert the volume from cubic centimeters (cm³) to cubic decimeters (dm³) because the molarity is given in moles per cubic decimeter (mol/dm³). There are 1000 cm³ in 1 dm³, so:

Volume = 60 cm³ × (1 dm³ / 1000 cm³) = 0.060 dm³

Now we can calculate the moles of chloride ions in solution B:

Moles = Molarity × Volume = 0.20 mol/dm³ × 0.060 dm³ = 0.012 moles

None of the other options have both a high molarity and a high volume to yield a higher amount of chloride ions. Option A has a higher molarity but a smaller volume, option C has a higher volume but a smaller molarity, and option D doesn't have a high molarity or volume for chloride ions.

Therefore, among the given options, solution B (MgCl₂) contains the largest amount of chloride ions, which is 0.012 moles.

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The complete question is:

Which solution contains the biggest amount, in mol, of chloride?

A. 20 cm³ of 0.50 mol dm⁻³NH,CL

B. 60 cm³ of 0.20 mol dm⁻³ MgCl₂

C. 70 cm³ of 0 30 mol dm⁻³ NaCl

D. 100 cm³ of 0.30 mol dm⁻³ CICH₂ COOH

\(\huge\bold\red{{HELP}}\)
Help me ireally need it cause i will pass it tommorow​

[tex]\huge\bold\red{{HELP}}[/tex]Help me ireally need it cause i will pass it tommorow

Answers

Answer:

Question 1 :

• A compound is ionic if it is made up of a metal or a cation (+) and a non metal or anion (-)

Question 2 :

• While naming ionic compounds, follow the formula → "metal" + "non-metal ending with ide "

• i.e; Sodium Chloride:

\({ \rm{Na {}^{ + } _{(aq)} + Cl {}^{ - } _{(aq)} \: \dashrightarrow \: NaCl _{(aq)}} \: \: \: \: \: \: \: \: } \\ { \rm{sodium + chloride \: \dashrightarrow \: sodium \: chloride}} \)

Question 3 :

• The answer above that question is perfect.

Question 4 :

1 atom → Mono. But it is highly recommended to ignore it

2 atoms → DI

3 atoms → TRI

4 atoms → TETRA

5 atoms → PENTA ( such as pentaoxide )

7 atoms → HEPTA ( such as heptaoxide )

Question 5 and 6:

Are perfectly answered.

in general, how do the periodic properties of the d-block elements compare with those of the main - group elements?

Answers

The periodic properties of the d-block elements differ from the main group elements in that they are less sensitive and less reactive.

The periodic table is divided into blocks; s-block, p-block, f-block, and d-block. The d-block elements are also known as transition metals.

The s and p-block elements are known as the main group elements. Compared to these, the d-block elements have some different properties because of their partially filled d-orbitals.

However, the d-block elements still have many similar properties. These elements can still displace hydrogen from dilute acid and some of them can react with water under appropriate conditions.

The first row of these transition metals are found to be more reactive than the second and third row. However, they are not as reactive as the s-block and p-block elements.

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What is the formula for Iron(IV) phosphite

Answers

Answer:

The answer is Iron phosphide (Fe2P)

Here is the actual question from before, I forgot to put the question in 0-0

Here is the actual question from before, I forgot to put the question in 0-0

Answers

Answer:

Evaluate \dfrac {9}m+4

m

9

+4start fraction, 9, divided by, m, end fraction, plus, 4 when m=3m=3m, equals, 3.

Explanation:

Consider the titration of 30. 0 mL of 0. 050 M NH3 with 0. 025 M. HCl. Calculate the PH after the following volumes of titrant have been added 0 ml 20 mL 59. 1 mL 60. 0 mL 71. 4 mL 73. 4 mL

Answers

The pH after the following volumes of titrant have been added 0 ml 20 mL 59. 1 mL 60. 0 mL 71. 4 mL 73. 4 mL are 11.89, 11.89, 8.45, 8.45, 7.98, 8.95 respectively.

The reaction between NH3 and HCl can be represented by the following equation: NH3 + HCl → NH4+ + Cl-

To calculate the pH after different volumes of titrant have been added, we need to determine the amount of titrant that has reacted with the analyte and the resulting concentration of the products.

A. 0 mL of titrant (initial state)

At the start, there is no titrant added to the analyte, so the concentration of NH3 is 0.050 M. NH3 is a weak base, so we can use the Kb expression to calculate the concentration of OH-:

\(Kb = [NH4+][OH-] / [NH3]\)

\(1.8 * 10^{-5} = x^2 / (0.050 - x)\)

initial concentration of NH3 is much greater than the initial concentration of HCl, we can assume that the concentration of NH3 does not change significantly during the titration.

\(Kb = x^2 / 0.050\\x = \sqrt{Kb * 0.050} = 1.3 * 10^{-3} M\)

The concentration of OH- is equal to \(1.3 * 10^{-3} M\), so we can calculate the pH:

\(pH = 14 - pOH = 14 - (-log[OH-]) = 11.89\)

Therefore, the pH at the start of the titration is 11.89.

B. 20 mL of titrant

After adding 20 mL of 0.025 M HCl, the volume of the solution is 50 mL (30 mL NH3 + 20 mL HCl). The moles of HCl added is:

moles of HCl = volume x concentration = 0.020 L x 0.025 mol/L = 5 x 10^-4 mol

Since the reaction is a 1:1 reaction, the moles of NH3 remaining is equal to the moles of HCl added.

concentration of NH3 = moles of NH3 / volume of NH3 = (0.050 mol/L x 0.030 L - 5 x 10^-4 mol) / 0.030 L = 0.048 mol/L

Since the concentration of NH3 has decreased, we need to recalculate the concentration of OH- using the new concentration of NH3:

\(Kb = [NH4+][OH-] / [NH3]\\1.8 * 10^{-5} = x^2 / (0.048 - x)\)

Solving for x, we get:

\(x = 1.3 * 10^{-3} M\)

The concentration of OH- is still \(x = 1.3 * 10^{-3} M\), so we can calculate the pH:

pH = 14 - pOH = 14 - (-log[OH-]) = 11.89

Therefore, the pH after adding 20 mL of titrant is still 11.89.

Similarly for  C. 59.1 mL of titrant

The pH after adding 59.1 mL of titrant is 8.45.

D. 60 mL of titrant

The pH after adding 60 mL of titrant is 8.45.

E. 71.4 mL of titrant

The pH after adding 71.4 mL of titrant is 7.98.

F. 73.4 mL of titrant

The pH after adding 73.4 mL of titrant is 8.95.

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(25 POINTS AND BRAINLIEST)What is the volume of 2 mol of chlorine gas at STP?
2.0 L
11.2 L
22.4 L
44.8 L

Answers

Answer:

44.8

Explanation:

According to standard temperature and pressure and ideal gas equation , the volume of 2 mole of chlorine gas at STP  is 44.8 liters.

What are standard temperature and pressure conditions?

Standard temperature and pressure are defined as a standard set of conditions required for experimental measurements which are established to allow comparison between different sets of data.

Standards which are commonly used are those International Union of pure and applied chemistry and national institute of standards and technology.These are not universally accepted standards but are the ones which are commonly used.

Standard conditions of pressure and temperature are necessary to define standard reference conditions used to express volumes of liquids and gases.

These values are important to physicists, chemists ,engineers ,pilots and navigators.On substituting values in ideal gas equation, volume= 2×8.314×273/1=44.8 liters.

Thus, the volume of 2 mole of chlorine gas at STP  is 44.8 liters.

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Atoms lose, gain, or share valence electrons to satisfy ________.

Options
1.Hund’s Rule
2.The rule of Nines
3.the Heisenburg Uncertainty Principle
4.the Octet Rule

Answers

The Octet Rule requires all atoms in a molecule to have 8 valence electrons--either by sharing, losing or gaining electrons--to become stable. For Covalent bonds, atoms tend to share their electrons with each other to satisfy the Octet Rule.

Explain the large variation in boiling temperatures, given the small range in Me values.

Explain the large variation in boiling temperatures, given the small range in Me values.

Answers

Answer:

32.0 is the answer which is divide able to 65 or -85

An unknown metal has a mass of 51.842 grams. when placed in a graduated cylinder, the volume of water rose from 17.1 ml to 19.8 ml. what is the identity of the metal?

Answers

The density of the metal, given that it has a mass of 51.842 grams is 19.2 g/mL

How to determine the density

First, we shall determine the volume of the metal. This can be obtained as follow:

Volume of water = 17.1 mL Volume of water + metal = 19.8 mL Volume of metal =?

Volume of metal = (Volume of water + metal) - volume of water

Volume of metal = 19.8 – 17.1

Volume of metal = 2.7 mL

Finally, we shall determine the density of the metal. This is illustrated below:

Mass of metal = 51.842 gramsVolume of metal = 2.7 mL Density of metal = ?

Density = mass / volume

Density of metal = 51.842 / 2.7

Density of metal = 19.2 g/mL

From the above calculations, we can conclude that the density of the metal is 19.2 g/mL

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PLZ HELP PLZ SOMEONE PLZ How old do u need to work as a secret agent

Answers

I THINK 18 OR 21 I AM SORRY IF I AM WRONG BRO

the solubility of solute in a solvent in a solid solution is governed by hume-rothery rules. the solubility is more if:

Answers

If solute has low valence radii are much smaller than that of solvent, then the solubility will be higher.

How do you increase the solubility of a substance?

Increase in the temperature of the solution increases the solubility of a solute. For example, a high amount of sugar will dissolve in warm water as compared to cold water.

Solubility of solute in a solvent in a solution is control by Hume Rothery rules. The solubility is more if solute has low valence radii and the solute are smaller than the solvent.

Solubility is defined as the maximum amount of a substance that will dissolve in a specific amount of solvent at a particular temperature. There are two main factors that affect solubility of a solution i.e. temperature and pressure.

So we can conclude that If solute has low valence radii are smaller than solvent.

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How could IR spectroscopy distinguish between 1-hexyne, 2-hexyne, and 3-hexyne? Check all that apply.
2-Hexyne will show neither the absorption band at ∼3300cm−1 nor the one at ∼2100cm−1 (there is no change in dipole moment when the C≡C stretches).
1-Hexyne will show absorption bands at ∼3300cm−1 for a hydrogen bonded to an sp carbon and at ∼2100cm−1 for the triple bond.
3-Hexyne will show the absorption band at ∼2100cm−1 but not the one at ∼3300cm−1.
3-Hexyne will show neither the absorption band at ∼3300cm−1 nor the one at ∼2100cm−1 (there is no change in dipole moment when the C≡C stretches).
1-Hexyne will show the absorption band at ∼2100cm−1 but not the one at ∼3300cm−1.
2-Hexyne will show absorption bands at ∼3300cm−1 for a hydrogen bonded to an sp3 carbon and at ∼2100cm−1 for the triple bond.
1-Hexyne will show neither the absorption band at ∼3300cm−1 nor the one at ∼2100cm−1 (there is no change in dipole moment when the C≡C stretches).
1-Hexyne will show absorption bands at ∼2100cm−1 for a hydrogen bonded to an sp carbon and at ∼3300cm−1 for the triple bond.
2-Hexyne will show the absorption band at ∼2100cm−1 but not the one at ∼3300cm−1.

Answers

1-Hexyne will show absorption bands at ∼3300cm−1 for a hydrogen bonded to an sp carbon and at ∼2100cm−1 for the triple bond.

2-Hexyne will show absorption bands at ∼3300cm−1 for a hydrogen bonded to an sp3 carbon and at ∼2100cm−1 for the triple bond.

3-Hexyne will show the absorption band at ∼2100cm−1 but not the one at ∼3300cm−1.

IR spectroscopy is a technique that measures the vibrational modes of molecules. Each molecule has a unique set of vibrational modes that correspond to different types of bonds within the molecule. In the case of alkynes, the C≡C triple bond is a strong bond that will produce a characteristic peak in the IR spectrum at around 2100 cm^-1. The presence or absence of other peaks will depend on the specific structure of the molecule.

For 1-hexyne, the hydrogen bonded to the sp carbon will produce a peak at around 3300 cm^-1 due to the stretching of the C-H bond. The C≡C triple bond will produce a peak at around 2100 cm^-1.

For 2-hexyne, the hydrogen bonded to the sp3 carbon will produce a peak at around 3300 cm^-1 due to the stretching of the C-H bond. The C≡C triple bond will produce a peak at around 2100 cm^-1.

For 3-hexyne, the C≡C triple bond will produce a peak at around 2100 cm^-1, but there is no hydrogen bonded to an sp carbon, so there will be no peak at around 3300 cm^-1.

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While you are conducting your experiment, you notice that the ball bounces at a different height and in a different direction for each trial. You look at the ground and see it is uneven. What could you do?​

Answers

Bounce the ball on flat surface

T or F: All electrons are alike

T or F: All electrons are alike

Answers

Answer:

True

Explanation:

Every electron in the universe has exactly the same mass, and exactly the same charge.

IUPAC name for CH2(OH)-CH2-CH2(OH)​

Answers

Answer:

The IUPAC name for CH2(OH)-CH2-CH2(OH) is 1,2,3-propanetriol. It is also commonly known as glycerol or glycerin.

Explanation:

The IUPAC name for a molecule is a systematic way of naming a compound based on the rules set by the International Union of Pure and Applied Chemistry (IUPAC). In the case of CH2(OH)-CH2-CH2(OH), the IUPAC name is based on the longest carbon chain, which is a three-carbon chain. The -OH groups attached to the carbon chain are named as substituents, with the prefix "hydroxy-" indicating the presence of an -OH group. The first carbon atom in the chain is numbered as "1," and the -OH groups are assigned the lowest possible numbers.

Therefore, the IUPAC name for CH2(OH)-CH2-CH2(OH) is 1,2,3-propanetriol. It is named as propanetriol because it contains a three-carbon chain and three -OH groups. It is also commonly known as glycerol or glycerin and is an important compound used in many industries, including food, cosmetics, and pharmaceuticals.

can someone pls help! If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas? Enter the unit of your answer here. Enter it as a symbol, not words spelled out.

Answers

Answer: Therefore, to convert the moles of gas to pressure, the scientist must know the volume and temperature of the gas, in addition to the number of moles of gas. The pressure is then given by P = nRT / V. Convert the volume and temperature to units of liters and Kelvin, respectively, if necessary

what is the percent yield for a reaction where the theoretical yield of the product was 45.9 g while the actual yield obtained in the lab for this product was 39.6 g?

Answers

(39.6/45.9)x100 = 86.3%

How do instantaneous speed and average speed differ?

Instantaneous speed happens all the time, but average speed only happens once per hour.
Instantaneous speed is always faster than average speed.
Instantaneous speed is the speed of an object at a specific time, but average speed is the total distance over the total time.
Instantaneous speed is always slower than average speed.

Answers

Answer:

Option 3

Explanation:

Option 3: Instantaneous speed is the speed of an object at a specific time, but average speed is the total distance over the total time. This is why they are called instantaneous and average, because instantaneous is at any one instance and average is the average speed it was moving over the total time which is calculated by the total distance/total time.

Hope this helped!

Answer:

Average Speed

Explanation:

a sealed flask at 298 k is half full of water. which is a correct statement after the flask has been heated to 308 k and the equilibrium has re-established?

Answers

When the flask has been heated to 308 K and the equilibrium has been re-established, the volume of water in the flask will have changed. It is known that the density of water decreases as the temperature increases. This implies that, when the flask is heated, the volume of water will expand.

As a result, the pressure in the flask will rise due to the water vapor that has accumulated as a result of the increased temperature.

After the temperature has been increased and the equilibrium re-established, the correct statement will be that the water level has increased in the flask, and the pressure has also increased. This implies that the water molecules in the flask have expanded as a result of the increased temperature.

In addition, the increased volume of water molecules increases the number of collisions of water molecules with the flask walls.



Therefore, the water molecules in the flask absorb some energy from the heat source and then transfer it to the flask walls in the form of collisions. As a result of these increased collisions, the pressure in the flask increases. This is because the number of collisions between water molecules and the walls of the flask has increased as a result of the increased temperature.

In conclusion, when the sealed flask is heated to 308 K, the volume of water in the flask increases, and the pressure inside the flask also increases. This is due to the increased number of collisions between water molecules and the flask walls, which are caused by the increased volume of water molecules due to the increase in temperature.

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Choose the proper whole-number coeffi-

cients for each substance to yield a balanced

equation.


D

1. 2, 1, 2

2. 1, 1, 1

3. 1, 2, 1

4. 2, 1,1

Answers

The proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2.

The proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2. Balancing a chemical reaction is done to find out the overview of that reaction and to find the answers related to that equation. like we can tell many things about the equation just by knowing the coefficients of the terms in that equation. we can tell about the percentage and existence of the products and reactants in the equation. if we know the coefficients of the elements and products we can tell about the mole of the reactants and products in the chemical equation. By this information, we can consider that the proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2.

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The Sun keeps all of the planets orbiting it because _____.

A. he Law of Ellipses states that the planets orbit the Sun in circular patterns
b. the Law of Universal Gravitation states that an increase in mass causes an increase in gravitational force
C. the Law of Harmonies states that the motion of the planets will not stop unless an outside force is applied
D. the Law of Equal Areas states that planets sweep equal areas in equal periods of time around the Sun

Answers

Answer:

a. because of how the earth circulates around the sun.

Arrange the following ions in order of increasing ionic radius: K+, p3-, S2-, Cl". Select one: O a. Kt

Answers

The correct arrangement of ions in increasing ionic radius is as follows:

p3- < S2- < Cl- < K+

Therefore, the correct option is:

b. p3-, S2-, Cl-, K+

In general, the ionic radius increases as you move from right to left across a period and from top to bottom within a group on the periodic table. Therefore, the arrangement of ions in increasing ionic radius is p3- < S2- < Cl- < K+.

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