. The temperature of a sample of water increases from 20°C to 46.6°C as it absorbs 5650 calories of heat. What is the mass of the sample? (Specific heat of water is 1.0 cal/g °C) DE Miss(46.6-20 ) = 30.290

Answers

Answer 1

mass of the water sample is approximately 212.78 grams. To find the mass of the water sample, we can use the formula:

Q = mcΔT

where Q is the heat absorbed (in calories), m is the mass of the sample (in grams), c is the specific heat capacity of water (1.0 cal/g°C), and ΔT is the change in temperature (46.6°C - 20°C).

We are given Q = 5650 calories and the specific heat of water, c = 1.0 cal/g°C. Let's calculate ΔT and solve for the mass, m.

ΔT = 46.6°C - 20°C = 26.6°C

Now we can rearrange the formula to solve for m:

m = Q / (cΔT)

m = 5650 calories / (1.0 cal/g°C × 26.6°C)

m ≈ 212.78 grams

The mass of the water sample is approximately 212.78 grams.

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Related Questions

What is high density polyethylene?

Answers

High-density polyethylene (HDPE) or polyethylene high-density (PEHD) is a thermoplastic polymer produced from the monomer ethylene.

A thermoplastic polymer is a type of polymer that can be melted and reshaped multiple times when heated and then cooled. Thermoplastics are widely used in a range of industrial, commercial, and consumer applications due to their versatile properties, ease of processing, and recyclability.

Thermoplastic polymers are made up of long chains of repeating molecular units, called monomers, that are linked by covalent bonds. The monomers in thermoplastics are usually small and simple, such as ethylene, styrene, or vinyl chloride, and they can be polymerized using various methods, such as injection molding, extrusion, or blow molding. The properties of thermoplastic polymers depend on the type and number of monomers used, as well as the processing conditions and additives used during production.

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A ball with a weight of 14 N falls off a ledge 65 cm high. How much work is done by gravity?

Answers

Answer:

91 J is the work done by gravity.

Explanation:

Work done = Force (N)* Distance (m)

   

Here the force given is 14N and distance is 65cm

here the distance is in cm, so we should change it in m.

1 cm --> 0.01 m

65 cm --> ( 0.01 * 65) m

65 cm --> 0.65 m

So work done = 14 * 0.65 = 91 Joules
Force=14NDistance=65cm=6.5m

Work done

\(\\ \tt\hookrightarrow Force\times Distance\)

\(\\ \tt\hookrightarrow 14(6.5)\)

\(\\ \tt\hookrightarrow 91J\)

for which colour of light is. the index of refraction of glass largest​

Answers

Answer:

don't know sorry for the irreverent answer..

Answer:

The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.

Pls Help Fast I will give Brainliest and Points:
To ensure that a vehicle crash is inelastic, vehicle safety designers add crumple zones to vehicles. A crumple zone is a part of a vehicle designed to crumple easily in a crash. Use Newton’s second law to explain why crumple zones reduce the force in a collision.

Answers

Answer:

Crumple Zones are parts of a car that are designed to deform and absorb large amounts of energy from car collisions and impacts. This helps reduce the force that acts on the driver in a car accident [1]. 2: Newton's Second Law states that Force= Mass x Acceleration

Explanation:

Question 21 of 25
Calculate the capacitance of a system that stores 6.5 x 10-10 C of charge at
Q
50.0 V. Use C =
AV
A. 7.7 * 1010 F
B. 3.1 x 107 F
C. 1.3 x 10-11 F
D. 3.2 x 10-8 F
SUBMIT

Answers

Answer:

C. 1.3 x 10-11 F

I took the test and got this correct, hope this helps

Explanation:

a medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. to do this, he measures the blood pressure just before the region of blockage and finds that it is 1.20×104 pa , whereas in the region of blockage it is 1.15×104 pa . furthermore, the technician knows that blood flowing through the normal artery just before the point of blockage is traveling at 30.0 cm/s , and the density of this patient’s blood is 1050 kg/m3 . what percentage of the cross-sectional area of the patient’s artery is blocked by the plaque?

Answers

The percentage of the patient's artery blocked by plaque is approximately 4.16%.

Blood pressure measurements taken just before and in the region of blockage indicate a decrease in pressure from 1.20×10^4 Pa to 1.15×10^4 Pa. This pressure difference is caused by the presence of plaque in the artery. To determine the percentage of the artery blocked, we can use the principle of continuity equation, which states that the product of cross-sectional area and velocity of a fluid remains constant along a flow path.

Given that the blood velocity just before the blockage is 30.0 cm/s, and the density of blood is 1050 kg/m^3, we can calculate the velocity in the blocked region using the continuity equation. By rearranging the equation and plugging in the values, we find that the velocity in the blocked region is approximately 28.57 cm/s.

Since the flow rate remains constant, we can use the ratio of velocities to determine the ratio of cross-sectional areas. The ratio of velocities (28.57 cm/s / 30.0 cm/s) is equal to the square root of the ratio of cross-sectional areas (blocked area / normal area). By rearranging the equation, we can solve for the blocked area as a percentage of the normal area, which is approximately 0.0416, or 4.16%.

In conclusion, approximately 4.16% of the patient's artery is blocked by plaque, based on the blood pressure measurements and the principles of fluid dynamics.

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4. Magnets with one pole are now routinely made.
True or False

Answers

Answer:

False

Explanation:

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.

Answers

Electric field strength decreases as the distance from the source increases.

How the distance from the charge affects the magnitude of the electric field?

The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.

So we can conclude that Electric field strength decreases as the distance from the source increases.

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Compared to the speed of the heavier cooler, what is the speed of the light cooler after both coolers move the same distance d? My friend and I plan a day of ice fishing out on a frozen lake. We each pack our own cooler full of supplies to be pushed out to our fishing spot. Initially both coolers are at rest and one has four times the mass of the other. In parts A and B we each exert the same horizontal force F on our coolers and move them the same distance d, from the shore towards the fishing hole. Friction may be ignored.

Answers

The light cooler will have more speed than the heavier cooler when they cover the same distance.

Given information:

Initially both coolers are at rest and one has four times the mass of the other.

In parts A and B we each exert the same horizontal force F on our coolers and move them the same distance d, from the shore towards the fishing hole. Friction may be ignored.

The speed of the light cooler after both coolers move the same distance d compared to the speed of the heavier cooler is given by the formula as follows:

`f=ma`or`a=F/m`

where

a= acceleration,

F = force applied,

m = mass of the object.

Force F is applied on both coolers and both are moved by distance d.

Here, friction is ignored and hence no force is present to oppose the motion of the object.The acceleration of the lighter cooler will be more than the heavier cooler because it requires less force to push the lighter object than the heavier object.

From the above information, it is clear that acceleration of lighter cooler is more than the heavier cooler.

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A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0. 20 kg, and the robot has a mass of 0. 30 kg. The robot pushes on the doll with a force of 0. 30 n. The magnitude of the acceleration of the robot is.

Answers

The magnitude of the acceleration of the robot is 1m/s^2 .

Given ,

A toy doll and a toy robot are standing on a frictionless surface facing each other .

The mass of the doll = 0.20kg

The mass of the robot = 0.30kg

Force applied by the robot on the doll = 0.30N

We know the force and mass of the robot , so from this we can calculate the acceleration by applying Newton's laws of motion ,

Thus , F= ma

a = F/m = 0.30N / 0.30k

a = 1 m/s^2

Hence , the magnitude of the acceleration of the robot is 1m/s^2 .

What is acceleration ?

Acceleration is the rate of change in velocity.

Positive acceleration it occurs when an object speeds up. Negative acceleration it occurs when an object slows down.

Acceleration is a change of velocity over a period of time, expressed by the equation,

A=Δv/t

The unit of acceleration is m/s^2.

The dimensional formula of acceleration is [M^0 L^1 T^-2] .

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If electric field lines point radially toward a charge, that charge must be ________.

Answers

Answer: Negative

Explanation: If electric field lines point radially toward a charge, that charge must be Negative

(1) A block of mass 800g is pulled from rest on a horizontal
frictionless bench by a steady force of F and it travels 16m in 2
seconds. Find:
(a) The acceleration?
(b) The value of F?

Answers

Answer:

a) 8m.\(s^{-2}\)

b) 6.4N

Explanation:

a)Using \(s=ut+1/2at^{2}\)

s=16

u=0

t=2

a=?

16=1/2a(4)

a=8m.\(s^{-2}\)

b) F=ma

Where m is in kg

Convert 800g to kg

800/1000=0.8kg (1000g in a kg)

F= 0.8 x 8 = 6.4N

SIMPLY !!!! I don’t get this either so please help !

SIMPLY !!!! I dont get this either so please help !

Answers

Answer:

its 3rd one I'm pretty sure

Explanation:

3rd one it might be wrong tho

Need help! Photo says all! Will mark brainliest :)

Need help! Photo says all! Will mark brainliest :)

Answers

Answer:

C-D

Explanation:

As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.

Divide 6 meters by 3 seconds to find the speed:

6 ÷ 3 = 2 m/s

B-C is not moving due to a straight line as said in the graph, so speed is

0 m/s.

There is also C-D since the car traveled from a distance of 9 meters

(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)

Divide 9 meters by 3 seconds to get the speed:

9 ÷ 3 = 3 m/s

Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.

A-D does not count here as the line has no connection between point A and point D.

Cheers!

Assignment: Ultrasound and Infrasound Research Exploration Ultrasound and infrasound are categories of sound with different frequencies. These categories of sound can be used for a variety of different applications. In this research assignment, you will take a look at the industrial applications of ultrasound and infrasound. Your essay should do the following things: • Define and describe in detail (and in your own words) ultrasound and infrasound • Describe how ultrasound and infrasound are used in specific industrial applications and provide detailed examples. When conducting your research, remember to gather information from multiple sources. Start your research by defining ultrasound and infrasound. Then find ideas about industrial applications. The essay should be about 350-450 words, which is 1-1.5 typed pages, double-spaced, using 12-pt. font. Check the rubric to review how you will be graded for this assignment. plz no funny answers

Answers

Answer:

Infrasound vs. Ultrasound: Infrasound is sound that is below the lower limit of human hearing, below 20 Hz, and ultrasound is above the upper limit of human hearing, above 20,000 Hz.  Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes, graphing rock and oil developments underneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, a few creatures, for example, whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, water falls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

Explanation:

idk how many words this is but its a start for u to add on to and i hope this helps and its in my own words - pls mark me brainiest

Answer:

Ultrasound vs. Infrasound Research Exploration

Beyond the limit of human hearing, ultrasound is above 20,000 Hz. Under the limit of human hearing, infrasound is below 20 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes as well as graphing rock and oil developments beneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, creatures like whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, waterfalls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

(Not turned in yet, but this is what i have so far. Good luck 8th graders <33)

-Sav xx

A woman stands in a boat at rest on a calm lake. She throws a 10 kg anchor off the front of the boat, which has a mass of 1,000 kg
What is the initial momentum of the anchor-boat system?

A)1,000 kg m/s

B)zero because both objects are at rest.

C)1,010 kg m/s

D)10,000 kg m/s

PLEASE HELP!! I don’t understand

Answers

Answer: B) zero because both objects are at rest

Explanation:

Given the following :

Mass of anchor = 10kg

Mass of boat = 1000kg

Note : both boay and anchor are at rest, this gives a Velocity of zero

The momentum of a body is given as the product of Mass and velocity, that is,

Momentum = mass × velocity

Initial Momentum of anchor-boat system =

(mass of boat× initial velocity of boat) + (mass of anchor × initial velocity of anchor)

Initial Velocities of boat and anchor = 0

Therefore,

Initial momentum = (1000 × 0) + (10 × 0)

Initial momentum = (0 + 0) = 0

This is ecause both objects are at rest.

A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.

Answers

The electric potential at point b experienced by the charge cab be determined using the formulas given.

Electric potential

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

V is the electric potentialF is electric forceE is the electric fieldq is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

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An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds Which describes the acceleration?
4 m/s in negative acceleration
4 m/s in positive acceleration
9 m/s in positive acceleration
Oms in negative acceleratio
Save and Exit
Next
Subini
Mark this and return


Answers

Answer:

4 m/s in negative acceleration

Explanation:

Acceleration = V- U/t

Where V is the final velocity

U is the initial velocity and t is the time given.

U = 65 m/s

V= 25 m/s

T= 10 seconds

Acceleration= (25m/s - 65m/s)÷10secs

= - 40/10

= -4m/s^2

Hence, it has a negative acceleration.

Answer:

A. negative acceleration of 4 m/s2

Hope this helps!

Explanation:

For a mass suspended on a spring in the vertical direction, the time for one complete oscillation will depend on:

Answers

The time for one complete oscillation will not depend on any of the factors listed. Option D

What is a pendulum?

A pendulum is composed of a string that is vertically suspended and the end of the string has a mass attached to it. The period of the pendulum refers to the umber of oscillations that occur after the pendulum is displaced through  small angle.

Given that the period of a pendulum is;

T = 2π√l/g

T = period of the pendulum

l = length of the pendulum

g = acceleration due to gravity

Hence, the time for one complete oscillation will not depend on any of the factors listed. Option D

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Missing parts;

For a mass suspended on a spring in the vertical direction, the time for one complete oscillation will depend on: a)the value for g (the acceleration due to gravity) b)the distance the mass was originally pulled down c)the maximum speed of the oscillating mass d)the time doesn't depend on any of the above

What is the average (mean) of these numbers: 13,43, 12, 3,66​

Answers

Answer:

27.4

Explanation:

(13+43+12+3+66)/5

137/5

27.4

Answer:

27.4 because you add them all together and divide the number you get by 5

How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2? a 0.013 N b 75 N c 108 N d 1080 N

Answers

The answer would be C. 108 N, this is because you have to use the equation F=MA so F=90*1.2, which equals 108 Newton’s.

Name HUAWEI P smart 2021 3. What is a rarefaction? Honors Physics: Sound Worksheet 1---Sound Basics 1. What type of wave are all sounds? 2. What is a compression? Date 4. In the diagram below, underneath each arrow, label the compressions with a C and the rarefactions with an R. Class Period 5. Many times in futuristic movies, an explosion occurs in space and loud 'boom' is created. Is this possible? Why or why not? 6. Sound travels approximately 340 m/s in air. Sound travels faster in steel. Explain why. Answer: 7. The pitch of any sound we hear is a result of what characteristic of the sound wave. 8. Humans are only able to hear sounds above 20Hz and below 20kHz. What is it called when: a. the frequency is above 20kHz? b. the frequency is below 20Hz? Answer: 9. The loudness of any sound is a result of what part of the sound wave? 10. Loudness of sound is measured in what unit?​

Name HUAWEI P smart 2021 3. What is a rarefaction? Honors Physics: Sound Worksheet 1---Sound Basics 1.

Answers

Rarefraction  is decrease of substance density .

What is the difference between Rarefraction and Compression?

1) Rarefraction is a space in a longitudinal wave  where particles are furthest apart and Compression is a place in a longitudinal waves and particles are in close vicinity.

2)The region where the substance in compressed is called Compression and the region where Medium spread out is Rarefraction . They are antagonist to each other.  

*All sounds are longitudinal waves and they also include compression and Rarefraction.

*Compression is decrease of Volume by applying stress on that substance.

* The force attraction between the Molecules of solid is more as compare to liquid and air . So ,that is steel has more sound as Compare to air ,it 17times faster than Air .

*Frequency is also known pitch in sound.

*If the frequency will be above than 20khz , it can lead to deafness or can make you uncomfortable for hearing.

*The loundness of any sound is a part of Amplitude .

*The loundness is measured in decibel.The normal person can hear only 50Decibels.

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In three to four sentences, explain how climate change could impact the formation of hurricanes. (4 points)

Answers

The climate change can directly impact the formation of hurricanes because increasing temperature increases intensity of hurricanes.

How climate change could impact the formation of hurricanes?

Evaporation increases as temperatures rise which also causes the transfer of heat from the oceans to the atmosphere. As the storms travel across oceans whose water is warm, they absorb more water vapor and heat which increases rainfall as well as intensity of hurricanes.

So we can conclude that the climate change impacted the formation of hurricanes due to increasing temperature that increases intensity of hurricanes.

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a motor operates at 200 W how high could it lift 15 g in a time of 8 seconds

Answers

The motor could  lift 15 g in a time of 8 seconds 10884 meter.

What is power?

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Given that motor operates at 200 W.

At time interval of 8 second, it do a work = 200×8 joule = 1600 joule.

Hence,  it lift 15 g in a time of 8 seconds = 1600/(0.015×9.8) meter

= 10884 meter.

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electromagnetic radiation that travels as a wave is perceived as which type of sensory information?

Answers

The only sense that can respond to photos is vision. Visible light is a very minor portion of the electromagnetic radiation spectrum and travels in waves.

What aspect of electromagnetic radiation affects how saturated something feels?

Monochromatic radiation is that which only carries one frequency. When this frequency is within the range of the visible spectrum, a saturated hue is perceived as the resulting color.

How is the level of visual acuity determined?

Combining light intensity with how evenly it is dispersed over the spectrum of different wavelengths will yield the saturation of a color. When a single wavelength is used at a high intensity, as in laser light, the purest (most saturated) color is produced.

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a deer with a mass of 176 kg is running head-on towards you with a velocity of 19 m/s. you are going north. find the magnitude and direction of the deer's momentum​

Answers

Momentum = Mass × Velocity

According to this formula,

Momentum of deer = 176 × 19 = 3344 kg•m/s.

Since you are heading north and the deer is running towards you, the direction of the deer' s momentum is north as well.

A squirrel runs at a speed of 9.9 m, with 25 J of kinetic energy. What is the squirrel’s mass?

Answers

Answer:

The mass of the squirrel is 0.51kg

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

Find the derivative of the function y=sin x² with respect to x at x=√π.

Answers

Answer: y'=-0.3924695585

Explanation: Find the first derivative of the function y then plug in x.

y'=2(sinx)(cosx)

y'=2(sin(√π))(cos(√π))

y'=2(.9797359)(-0.2002935)

y'=-0.3924695585

Do 26-30! I’ll give brainlist!

Do 26-30! Ill give brainlist!

Answers

26) Energy is a scalar quantity. Option 2

27) Energy is measured in the same unit as work. Option 4

28) The unit that is correctly paired is work. Option 4

29) The unit of gravitational potential energy is Joule. Option 4

30) The greatest gravitational potential energy is possessed by the object that is 6Kg at a height of 5 m. Option 4

31) he gravitational potential energy and the speed decreases. Option 1

What is a quantity?

We know that when we talk about a quantity in physics, our minds should be able to go to something that can be measured. In Physics we can be able to classify the quantities that we have into the vector quantities and the scalar quantities.

The vector quantities are the ones that have both a magnitude and a direction while the scalar quantities are the ones that have only a magnitude but do not have a direction that is attached to them.

The unit of the quantity can be used to deduce the dimensions of the quantity that we are looking at and this is key when we are looking at the relationship between the quantities in an equation.

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Tujuan kita membuat bermacam macam arah dan bentuk garis dalam dalam menggambar adalah ...... A.agar gambar kita bagus B.agar tangan lentur dalam menggambar terlihat lebih bagus C.mengisi waktu kosong​

Answers

Answer:

A.agar gambar kita bagus

Explanation:

semoga membantu

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