The table shows the scores for three students on a math test. Who earned the highest grade?

Answer:

P = 70.6 cm

Step-by-step explanation:

Given that,

The diameter of the semicircle, d = 45 cm

Radius, r = 22.5 cm

We need to find the perimeter of the semicircle. The formula for the perimeter of a semicircle is given by :

\(P=\pi r\\\\P=\pi \times 22.5\\\\P=70.6\ cm\)

So, the required perimeter is 70.6 cm.

Answer:

do the butterfly method if you don't know how to do that comment and I'll show you a screenshot

The solution of the equation -x² + 4 = x + 2 is at x = -2 and x = 1

An equation is an expression that shows how numbers and variables are related to each other.

Given the quadratic equation:

-x² + 4 = x + 2

Collecting like terms:

x² + x - 2 = 0

Plotting using a graph; the solution of the equation can be gotten by getting the point the graph crosses the x axis.

The solution is at x = -2 and x = 1

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Answer:

Step-by-step explanation:

To find the new coordinate of a point after it has been scaled by a factor of 1/2, you can multiply the x- and y-coordinates of the point by 1/2.

For example, to find the new coordinate of point K', you can multiply the x-coordinate of K' (-8) by 1/2 to get the new x-coordinate, and multiply the y-coordinate of K' (8) by 1/2 to get the new y-coordinate. This gives you the new coordinate of K' as (-4,4).

You can use the same method to find the new coordinates of points L' and M'. The new coordinate of L' is (4,4) and the new coordinate of M' is (-2,4).

I hope this helps! Let me know if you have any questions.

Step-by-step explanation:

we know about vertical angels that are equal

so <2=<4

(in fact they are congruent angles)

we found those only from the definition of vertical angles.

Answer:

m<DFG = 55°

Step-by-step explanation:

m<FDE + 125° = 180° (Linear angle pair)

m<FDE = 180° - 125° (Subtraction property of equality)

m<FDE = 55°

m<DFG = m<FDE (alternate interior angles are congruent)

m<DFG = 55° (substitution)

Using the relation between velocity, distance and time, the items and graphs are matched as follows:

1. D.

2. B.

3. A.

4. C.

Velocity is distance divided by time, that is:

v = d/t.

Hence the distance is given by:

d = vt.

Along a city street, we have that:

We can verify this that when graph C(velocity) is zero, graph D(position) is constant.

Along a superhighway we have that:

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Answer:

y=7x

Step-by-step explanation:

that's the most simplified you can get this equation.

The value of the expression in terms of x is,

x = y/7

Given that;

The expression is,

y = 9x - 2x

Now simplify the expression and solve for x by combining like terms,

y = 9x - 2x

Combine like terms;

y = 7x

Divide both sides by 7;

y/7 = x

x = y/7

Therefore, the expression is x = y/7.

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Answer:

115 degrees and next time use a protractor.

Step-by-step explanation:

Answer:

Plagiarism is the act of using someone else's work/idea and claiming it as your own. :)

Answer:

Plagairism is where you steal somebody elses work.

Step-by-step explanation:

Ok. hello I am not new here, but somehow my account I think got deleted. I was dating someone on here and I don't know how to get a hold of him. Please help!

Answer:

Slope= 2 / 10 = 1 / 5 = 0.2

y-intercept= (0, -4/5) or (0, -0.8)

Step-by-step explanation:

The similar triangles for this problem are given as follows:

RST and VUT.

Then the measure VT is given as follows:

VT = 5.4 units.

Similar triangles are triangles that share these two features listed as follows:

Hence the similar triangles for this problem are given as follows:

RST and VUT.

The proportional relationship for the side lengths is given as follows:

6/14 = (x + 2)/(4x - 1).

Applying cross multiplication, the value of x is obtained as follows:

14(x + 2) = 6(4x - 1)

14x + 28 = 24x - 6

10x = 3.4

x = 3.4.

Then the length VT is given as follows:

VT = 3.4 + 2

VT = 5.4 units.

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Answer:

30

Step-by-step explanation:

150/5 = 30

Answer: 30

Step-by-step explanation:

Answer:

x=48

Step-by-step explanation:

12 divided by 0.25 is equal to being multiplied by 4.

Applying the tangent ratio, the value of x in the image, rounded to the nearest thousandth is: 15.824.

The tangent ratio, commonly referred to as "tangent," is a trigonometric function that relates the ratio of the length of the side opposite an angle to the length of the side adjacent to that angle in a right triangle. It is expressed as:

tan (∅) = opposite/adjacent

We have the following:

Reference angle (∅) = 53 degrees

Length of opposite side = 21

Length of adjacent side = x

Plug in the values:

tan 53 = 21/x

x * tan 53 = 21

x = 21 / tan 53

x = 15.824

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The total length of the centre circle and the two goal semi circles to be repainted is 56.22 meters.

Given:

Court lines are 50 mm wide.

Court paint covers 7 m² per litre of paint.

The centre circle is a complete circle, so the circumference is given by the formula: Circumference = 2πr

Radius of the entire circle = 9 m / 2 = 4.5 m

Radius of the centre circle = 4.5 m - 0.05 m (converted 50 mm to meters) = 4.45 m

Circumference of the centre circle = 2π(4.45 m) = 27.94 m

Next, let's calculate the circumference of the semicircles:

The semicircles are half circles, so the circumference is given by the formula: Circumference = πr

The radius (r) of the semicircles is the same as the radius of the entire circle, which is 4.5 m.

Circumference of a semicircle = π(4.5 m) = 14.14 m

Total length = Circumference of the centre circle + 2 x Circumference of a semicircle

Total length = 27.94 m + 2(14.14 m)

Total length = 56.22 m

Therefore, the total length of the centre circle and the two goal semi circles to be repainted is 56.22 meters.

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Answer:

(i) x ≤ 1

(ii) ℝ except 0, -1

(iii) x > -1

(iv) ℝ except π/2 + nπ, n ∈ ℤ

Step-by-step explanation:

(i) The number inside a square root must be positive or zero to give the expression a real value. Therefore, to solve for the domain of the function, we can set the value inside the square root greater or equal to 0, then solve for x:

\(1-x \ge 0\)

\(1 \ge x\)

\(\boxed{x \le 1}\)

(ii) The denominator of a fraction cannot be zero, or else the fraction is undefined. Therefore, we can solve for the values of x that are NOT in the domain of the function by setting the expression in the denominator to 0, then solving for x.

\(0 = x^2+x\)

\(0 = x(x + 1)\)

\(x = 0\)     OR     \(x = -1\)

So, the domain of the function is:

\(R \text{ except } 0, -1\)

(ℝ stands for "all real numbers")

(iii) We know that the value inside a logarithmic function must be positive, or else the expression is undefined. So, we can set the value inside the log greater than 0 and solve for x:

\(x+ 1 > 0\)

\(\boxed{x > -1}\)

(iv) The domain of the trigonometric function tangent is all real numbers, except multiples of π/2, when the denominator of the value it outputs is zero.

\(\boxed{R \text{ except } \frac{\pi}2 + n\pi} \ \text{where} \ \text{n} \in Z\)

(ℤ stands for "all integers")

Answer:

(i)  x ≤ 1

(ii)  All real numbers except x = 0 and x = -1.

(iii)  x > -1

(iv)  All real numbers except x = π/2 + πn, where n is an integer.

Step-by-step explanation:

The domain of a function is the set of all possible input values (x-values).

\(\hrulefill\)

\(\textsf{(i)} \quad f(x)=\sqrt{1-x}\)

For a square root function, the expression inside the square root must be non-negative. Therefore, for function f(x), 1 - x ≥ 0.

Solve the inequality:

\(\begin{aligned}1 - x &\geq 0\\\\1 - x -1 &\geq 0-1\\\\-x &\geq -1\\\\\dfrac{-x}{-1} &\geq \dfrac{-1}{-1}\\\\x &\leq 1\end{aligned}\)

(Note that when we divide or multiply both sides of an inequality by a negative number, we must reverse the inequality sign).

Hence, the domain of f(x) is all real numbers less than or equal to -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x \leq 1\\\textsf{Interval notation:} \quad &(-\infty, 1]\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \leq 1 \right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(ii)} \quad g(x) = \dfrac{1}{x^2 + x}\)

To find the domain of g(x), we need to identify any values of x that would make the denominator equal to zero, since division by zero is undefined.

Set the denominator to zero and solve for x:

\(\begin{aligned}x^2 + x &= 0\\x(x + 1) &= 0\\\\\implies x &= 0\\\implies x &= -1\end{aligned}\)

Therefore, the domain of g(x) is all real numbers except x = 0 and x = -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x < -1 \;\;\textsf{or}\;\; -1 < x < 0 \;\;\textsf{or}\;\; x > 0\\\textsf{Interval notation:} \quad &(-\infty, -1) \cup (-1, 0) \cup (0, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq 0,x \neq -1 \right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(iii)}\quad h(x) = \log_7(x + 1)\)

For a logarithmic function, the argument (the expression inside the logarithm), must be greater than zero.

Therefore, for function h(x), x + 1 > 0.

Solve the inequality:

\(\begin{aligned}x + 1 & > 0\\x+1-1& > 0-1\\x & > -1\end{aligned}\)

Therefore, the domain of h(x) is all real numbers greater than -1.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x > -1\\\textsf{Interval notation:} \quad &(-1, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x > -1\right\} \end{aligned}}\)

\(\hrulefill\)

\(\textsf{(iv)} \quad k(x) = \tan x\)

The tangent function can also be expressed as the ratio of the sine and cosine functions:

\(\tan x = \dfrac{\sin x}{\cos x}\)

Therefore, the tangent function is defined for all real numbers except the values where the cosine of the function is zero, since division by zero is undefined.

From inspection of the unit circle, cos(x) = 0 when x = π/2 and x = 3π/2.

The tangent function is periodic with a period of π. This means that the graph of the tangent function repeats itself at intervals of π units along the x-axis.

Therefore, if we combine the period and the undefined points, the domain of k(x) is all real numbers except x = π/2 + πn, where n is an integer.

\(\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &\pi n\le \:x < \dfrac{\pi }{2}+\pi n\quad \textsf{or}\quad \dfrac{\pi }{2}+\pi n < x < \pi +\pi n\\\textsf{Interval notation:} \quad &\left[\pi n ,\dfrac{\pi }{2}+\pi n\right) \cup \left(\dfrac{\pi }{2}+\pi n,\pi +\pi n\right)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq \dfrac{\pi}{2}+\pi n\;\; (n \in\mathbb{Z}) \right\}\\\textsf{(where $n$ is an integer)}\end{aligned}}\)

Answer:4,461,600

Step-by-step explanation:

Using the arrangements formula, it is found that there are 1152 ways for the students to be arranged alternatively at the table.

The number of possible arrangements of n elements is given by the factorial of n, that is:

\(A_n = n!\)

In this problem, we have that:

Hence the number of ways is:

2 x 4! x 4! = 1152

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Tim's score range would be between 20.2 - 56.25 and 20.2 + 56.25, or between -36.05 and 76.45. To find the percentage of games

a. To find the percentage of candy wrappers that would have between 3.4 and 3.6 ounces, we need to calculate the z-scores for each of the values:

\(z-score for 3.4 ounces = (3.4 - 3.5) / 0.16 = -0.625\)

\(z-score for 3.6 ounces = (3.6 - 3.5) / 0.16 = 0.625\)

Using a z-table or a calculator with a normal distribution function, we can find that the percentage of candy wrappers between these two values is approximately 47.70%.

b. To find the percentage of candy wrappers that would have less than 3.3 ounces, we need to calculate the z-score for this value:

\(z-score for 3.3 ounces = (3.3 - 3.5) / 0.16 = -1.25\)

Using a z-table or a calculator with a normal distribution function, we can find that the percentage of candy wrappers with less than 3.3 ounces is approximately 10.92%.

To find the percentage of candy wrappers with more than 3.62 ounces, we need to calculate the z-score for this value:

\(z-score for 3.62 ounces = (3.62 - 3.5) / 0.16 = 0.75\)

Using a z-table or a calculator with a normal distribution function, we can find that the percentage of candy wrappers with more than 3.62 ounces is approximately 22.77%.

c. To find how many of the 1358 packets made that day have between 3.35 and 3.65 ounces, we need to convert these values to z-scores:

\(z-score for 3.35 ounces = (3.35 - 3.5) / 0.16 = -0.9375\)

\(z-score for 3.65 ounces = (3.65 - 3.5) / 0.16 = 0.9375\)

Using a z-table or a calculator with a normal distribution function, we can find the percentage of candy wrappers between these two values, which is approximately 62.97%. To find how many packets this represents, we can multiply this percentage by the total number of packets made:

\(0.6297 * 1358 = 856 packets\)

Therefore, approximately 856 packets made that day have between 3.35 and 3.65 ounces.

d. To find how many games Tim would have scored 22 points or more if he plays 32 games, we first need to calculate the z-score for this value:

\(z-score for 22 points = (22 - 20.2) / 25 = 0.072\)

Using a z-table or a calculator with a normal distribution function, we can find the percentage of games with a z-score greater than or equal to 0.072, which is approximately 53.10%. To find how many games this represents, we can multiply this percentage by the total number of games:

\(0.5310 x 32 = 17 games\)

Therefore, Tim would have scored 22 points or more in approximately 17 games out of 32.

e. To find how many games Tim would have scored within 2.25 standard deviations from his average if he plays 32 games, we first need to calculate 2.25 standard deviations:

\(2.25 x 25 = 56.25\)

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Answer:

Step-by-step explanation:

To get the y values all you need to do is substitute the x value in the equation y=-2/3x+7.

For example:

y=-2/3(-6)=7

-2/3x6=-4

-4+7=3

(-6,3)

You can double check your work by filling the x and y coordinates in the equation and when solved if it it true you know you were correct.

To get the x value, you need to fill in the y in the equation y=-2/3x+7

for example:

5=-2/3x+7

-2=-2/3x

3=x

(3,5)

y=-2/3x+7

y=-2/3(15)+7

y=-10+7

y=-3

(15,-3)

y=-2/3x+7

15=-2/3x+7

8=-2/3x

-12=x

(-12,15)

Step-by-step explanation:

Let's call the average speed of the tortoise "t" (in meters per hour) and the average speed of the hare "h" (in meters per hour).

From the problem, we know that:

The tortoise leaves 8 minutes before the hare, so they have a 4-minute head start.

The hare crosses the finish line 4 minutes before the tortoise, so they have a 4-minute lead.

Therefore, the total time it takes for the hare to finish the race is 8 minutes less than the time it takes for the tortoise to finish the race. Let's call this time difference "dt".

The distance the hare runs is 21 meters, and the distance the tortoise runs is also 21 meters, so we have:

h * dt = 21 - t * (dt + 4 minutes)

To solve for the average speeds "t" and "h", we need to convert everything to units of hours. Let's convert 4 minutes to hours:

4 minutes = 4/60 hours = 1/15 hours

So, we can now rewrite the equation in terms of hours:

h * dt = 21 - t * (dt + 1/15 hours)

Rearranging and solving for t, we find:

t = (21 + h * dt) / (dt + 1/15)

Now, the hare runs 0.5 meters per hour faster than the tortoise, so:

h = t + 0.5

Substituting h = t + 0.5 into the equation for t, we get:

t = (21 + (t + 0.5) * dt) / (dt + 1/15)

Solving for t, we find:

t = 40/3 meters per hour

Finally, we can find the average speed of the hare by using h = t + 0.5:

h = 40/3 + 0.5 = 40/3 + 30/60 = 40/3 + 30/3 / 60 = 70/3 meters per hour

So the average speed of the tortoise is 40/3 meters per hour, and the average speed of the hare is 70/3 meters per hour

Answer:

\(m = -\frac{2}{3}\)

Step-by-step explanation:

Given

\(P_1 = (-1,3)\)

\(P_2 = (5,-1)\)

Required

Determine and interpret slope

Slope is calculated using:

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Where

\((x_1,y_1) = (-1,3)\)

\((x_2,y_2) = (5,-1)\)

\(m = \frac{y_2 - y_1}{x_2 - x_1}\) becomes

\(m = \frac{-1 - 3}{5 - (-1)}\)

\(m = \frac{-1 - 3}{5 +1}\)

\(m = \frac{-4}{6}\)

\(m = -\frac{2}{3}\)

The above slope is negative and it implies that x increases when y decreases and vice versa.

Answer:

D. Bank charges a large fee for bouncing a check is not an example of overdraft protection.

Step-by-step explanation:

Overdraft protection is a service offered by banks that allows you to link your checking account to another account, such as a savings account or a line of credit. If you overdraw your checking account, the bank will automatically transfer funds from the linked account to cover the shortfall, which helps you avoid overdraft fees and other penalties.

Option A is not an example of overdraft protection as it refers to earning interest on money in your savings account, which is a separate service.

Option B refers to additional fees collected by the bank when you bounce a check, which is a penalty for not having sufficient funds in your account to cover the check.

Option C refers to an ATM machine providing you with cash, which is a basic function of an ATM and is not related to overdraft protection.

Answer:

28°

Step-by-step explanation:

x+85°+67°=180°(being sum of all interior angle of triangle)

x+152°=180°

x=180°-152°

x=28°

To simplify:

1- Remove parenthesis: The negative sing before a parenthesis change the symbols of the terms in the parenthesis:

2-Combine like terms: Like terms are terms whose variables and their exponents are the same:

The 30th percentile of the data is 9 and the 75th percentile is 21.

The given data is 1, 3, 5, 6, 9, 10, 11, 13, 14, 15, 16, 18, 18, 24, 27, 31 and 32.

Here, consider 1, 3, 5, 6, 9, 10, 11, 13, 14

30th percentiles is 9.

Consider 15, 16, 18, 18, 24, 27, 31, 32

75th percentiles = (18+24)/2

= 42/2

= 21

Therefore, the 30th percentile of the data is 9 and the 75th percentile is 21.

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The initial value of the function is 1.

What is a function?

A function in mathematics from a set X to a set Y assigns exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively. Initially, functions represented the idealized relationship between two varying quantities.

A relationship in which one input value exactly equals one output value is known as a function. A function's initial value is a crucial component. A starting value or starting point is exactly what it sounds like: It is an initial value.

The line intersects the y-axis at (0,1).

The initial value of the function is 1.

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Solution:

Given the relation below

The general form, an absolute value function is

The vertex coordinates are (h, k)

Solving to find the vertex below

Hence, the coordinates of the vertex is