the table shows the distance that distance that members of the track team jumped. What fraction of the total distance did Madelyn and Melissa jump?

By using the graph, the amount of snacks that the charity must sell if 10 seats are sold is equal to 40 snacks.

In order to graphically solve the equation, we would write an equation that models the situation by assigning variables to the cost of seats and cost of snacks, and then translate the word problem into algebraic equation as follows:

Since the seats cost $32 each and snacks cost an additional $8 each while the charity needs to raise $640, an equation that models the situation is given by;

32s + 8y = 640

By critically observing the graph, the charity must sell 40 snacks if 10 seats are sold.

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The shock in part (c) leads to a decrease in capital per worker and consumption per worker, potentially affecting the standard of living. In contrast, the shock in part (d) leads to an increase in output per effective worker, which can positively impact the standard of living.

(c) When the tax funds are assumed to be gone without any goods or services purchased or government employees paid, it implies that the tax revenue is completely removed from the economy. In this case, the impact on the steady state levels of capital per worker and consumption per worker would depend on the specific economic model and assumptions.

Generally, the removal of tax revenue would lead to a reduction in both capital per worker and consumption per worker. The exact magnitude of the impact would depend on various factors, such as the marginal propensity to consume and the saving behavior of individuals. In steady state, the reduction in capital per worker could lead to lower productivity and potentially lower output per worker, affecting the standard of living.

To sketch a diagram showing the impact of this shock, you would typically have the levels of capital per worker and consumption per worker on the y-axis and time or steady state on the x-axis. The diagram would show a downward shift in both the capital per worker and consumption per worker curves, indicating a decrease due to the removal of tax revenue.

(d) When the tax funds are used by the government to implement plans that increase the growth rate of labor-augmenting technological change to 3% per year, it implies that the tax revenue is directed towards productivity-enhancing investments or policies. In this case, the impact on the steady state levels of capital per effective worker, output per effective worker, and consumption per effective worker can be analyzed.

The increase in the growth rate of labor-augmenting technological change would lead to higher productivity and potentially higher output per effective worker in steady state. This increase in output per effective worker could also translate into higher consumption per effective worker, depending on the saving and consumption behavior.

To sketch a diagram showing the impact of this shock, you would typically have the levels of capital per effective worker, output per effective worker, and consumption per effective worker on the y-axis and time or steady state on the x-axis. The diagram would show an upward shift in the output per effective worker curve, indicating an increase due to the improved technological change.

Overall, the shock in part (c) leads to a decrease in capital per worker and consumption per worker, potentially affecting the standard of living. In contrast, the shock in part (d) leads to an increase in output per effective worker, which can positively impact the standard of living.

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Answer:

umm let me see

Step-by-step explanation:

If only 4 pipes are used instead of ten, the time required to drain the pool can be determined by finding the proportion between the number of pipes and the time. It is an inverse proportion.

Let's assume the volume of the pool is represented by V. Since ten pipes can drain the pool in 2 hours, it means that each pipe can drain 1/10th of the pool's volume in 2 hours. Therefore, the rate at which each pipe drains the pool is (1/10)V per 2 hours.

Now, if we only use 4 pipes instead of 10, the rate at which the pool will be drained will decrease. Let's represent the time it takes to drain the pool with 4 pipes as T.

Using the idea of an inverse proportion, we can set up the following equation:

(1/10)V / 2 hours = (1/4)V / T

To solve for T, we can cross-multiply and simplify:

T = 2 hours * (4/10)

T = 0.8 hours

Therefore, if only 4 pipes are used instead of 10, it will take 0.8 hours (or 48 minutes) to drain the pool.

In conclusion, the relationship between the number of pipes and the time taken to drain the pool is an inverse proportion. As the number of pipes decreases, the time required to drain the pool increases.

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The number of houses left to be sold is 30

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.

Given here: Total houses =75

Now as per question we have 1/3 of them were sold

Thus the number of houses sold = 1/3×75

                                                       =25

Remaining houses = 75-25=

                                =50

Again 3/5 of the remaining houses were sold

Thus number of house sold =3/5 ×50

                                               =30

Hence, remaining houses to be sold we get

= 50-30

=20

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Answer:

Please see the attached picture for full solution.

Answer:

Step-by-step explanation:

1) Cannot be determined.

2) Surface area of the cylinder with radius 4 inches and height 3 inches is 100.48 square inches.

3) Exact surface area of the cylinder with radius 1 and three-fourths centimeters and height 3 and one-fourth centimeters is 35 and seven-eighths times pi square centimeters.

4) The area of icing needed for one red velvet cake with a radius of 13 centimeters and a height of 15 centimeters is approximately 459 square centimeters.

What is the surface area of the cylinder?

The surface area of a cylinder is the total area of all its curved and flat surfaces. It is given by the formula:

Surface Area = 2πr² + 2πrh

To answer these questions, we need to use the formula for the surface area of a cylinder:

Surface Area = 2πr² + 2πrh

where r is the radius of the circular base of the cylinder, h is the height of the cylinder, and π is the mathematical constant pi.

We are given that the container was covered in plastic wrap during manufacturing. We are not given the dimensions of the container, but we can assume it is a cylinder. Therefore, we need to calculate the surface area of the cylinder. We are not given the values of r and h, so we cannot calculate the surface area directly. Therefore, we cannot determine the answer to this question.

We are given the net of a cylinder with a labeled radius of 4 inches and a labeled height of 3 inches. To find the surface area of the cylinder, we need to use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 4 and h = 3, and using π ≈ 3.14, we get:

Surface Area = 2(3.14)(4²) + 2(3.14)(4)(3) = 100.48 in²

Therefore, the surface area of the cylinder is 100.48 in².

We are given a cylinder with a labeled radius of 1 and three-fourths centimeters and a labeled height of 3 and one-fourth centimeters. To find the surface area of the cylinder, we need to use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 1.75 and h = 3.25, we get:

Surface Area = 2(3.14)(1.75²) + 2(3.14)(1.75)(3.25) = 35.875π cm²

Therefore, the exact surface area of the cylinder in terms of π is 35 and seven-eighths times pi square centimeters.

We are given a red velvet cake with a radius of 13 centimeters and a height of 15 centimeters. We need to find the area of the circular top of the cake, which is the same as the surface area of a cylinder with radius 13 and height 0. We can use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 13 and h = 0, we get:

Surface Area = 2(3.14)(13²) + 2(3.14)(13)(0) = 1061.76 cm²

We need to subtract this from the surface area of the whole cylinder (the cake) to find the area of the icing. Using the formula again with r = 13 and h = 15, we get:

Surface Area = 2(3.14)(13²) + 2(3.14)(13)(15) = 1520.6 cm²

Therefore, the area of icing needed for one cake is:

1520.6 - 1061.76 = 458.84 cm²

Rounding this to the nearest square centimeter, we get:

459 cm²

Therefore, approximately 459 square centimeters of icing is needed for one cake.

Hence,

1) Cannot be determined.

2) Surface area of the cylinder with radius 4 inches and height 3 inches is 100.48 square inches.

3) Exact surface area of the cylinder with radius 1 and three-fourths centimeters and height 3 and one-fourth centimeters is 35 and seven-eighths times pi square centimeters.

4) The area of icing needed for one red velvet cake with a radius of 13 centimeters and a height of 15 centimeters is approximately 459 square centimeters.

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Not performing qualitative tests in duplicate can introduce certain risks and potential issues:

False positives: Without duplicate testing, there is a higher risk of obtaining false positive results. False positives occur when a test incorrectly indicates the presence of a particular characteristic or condition. Duplicate testing helps verify the accuracy and reliability of the results, reducing the chances of false positives.

False negatives: Similarly, not performing qualitative tests in duplicate increases the risk of false negatives. False negatives occur when a test fails to detect a characteristic or condition that is actually present. Duplicate testing provides an additional opportunity to identify any missed detections and reduces the likelihood of false negatives.

Variability and uncertainty: Qualitative tests can be subject to variability due to factors such as sample preparation, test conditions, or interpretation. Duplicate testing helps assess the consistency and reproducibility of the results, providing a measure of confidence and reducing uncertainty.

Quality control issues: Duplicate testing is an essential component of quality control protocols. It helps ensure the reliability and accuracy of the testing process and minimizes the potential for errors or inconsistencies. Not performing duplicate tests can compromise the overall quality control procedures, leading to compromised data and unreliable conclusions.

Validation and reproducibility: Duplicate testing is often required for validation purposes and to demonstrate the reproducibility of results. It helps establish the robustness and reliability of the testing method. Without duplicate testing, it becomes more challenging to validate and reproduce the results, which can undermine the credibility of the findings.

In summary, not performing qualitative tests in duplicate increases the risks of false positives, false negatives, variability, uncertainty, quality control issues, and challenges in validation and reproducibility. Duplicate testing plays a crucial role in ensuring the accuracy, reliability, and validity of qualitative test results.

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The answer is correct, we can plot both triangles on a Coordinate plane and visually inspect the result. If we plot triangle ABC with vertices A(-3, 3), B(0, 4), and C(-3, 0), and then plot the image triangle A'B'C' with vertices A'(-3, -1), B'(0, 0), and C'(-3, -4), we can see that the image is a translation of the original triangle down by 4 units.

To determine the coordinates of the vertices of the image of triangle ABC after being translated 4 units down, we need to subtract 4 from the y-coordinates of each vertex. This is because a translation is a type of transformation that moves each point of a figure a certain distance in a certain direction.

So, starting with the preimage of triangle ABC with vertices at A(-3, 3), B(0, 4), and C(-3, 0), we can find the image by subtracting 4 from the y-coordinates:

A'(-3, 3 - 4) = A'(-3, -1)

B'(0, 4 - 4) = B'(0, 0)

C'(-3, 0 - 4) = C'(-3, -4)

Therefore, the coordinates of the vertices for the image after the translation are A'(-3, -1), B'(0, 0), and C'(-3, -4).

So, the correct option is A) A′(−3, −1), B′(0, 0), C′(−3, −4).

To check if the answer is correct, we can plot both triangles on a coordinate plane and visually inspect the result. If we plot triangle ABC with vertices A(-3, 3), B(0, 4), and C(-3, 0), and then plot the image triangle A'B'C' with vertices A'(-3, -1), B'(0, 0), and C'(-3, -4), we can see that the image is a translation of the original triangle down by 4 units.

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Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

\(1 \frac{1}{5} \)

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

\(1 \frac{1}{5} \)

So option a = 3/5 x 2/1 is ur answer

is \( \sf \frac{3}{2} \times \frac{2}{1} [B]\)

\( \sf \frac{ 3}{5} \div \frac{1}{2} \)

\( \sf = \frac{3}{2} \times \frac{2}{1} [B]\)

Which multiplication expression is equal to 3/5 1/2 the answer is \( \sf \frac{3}{2} \times \frac{2}{1} [B]\).

Answer:

x = 9.5

Step-by-step explanation:

Since you are given the adjacent side and need to find the hypotenuse then you need to use cos = adj/hyp so cos (47) = 6.5/x

So x = 6.5/.682, since cos 47 = .6819983601

x = 9.5

Answer:123

67

Step-by-step explanation:

2by2

sides

13 X 42 = 546 square foot there are four of these

546 X 4 = 2184 square foot.

triangles

A= 0.5 X b X h

0.5 X 13 X 12 = 78 square foot again there are four of these 78 X 4 = 312 square foot

2184 + 312 = 2496 square foot

2496/277 = 9.010

9 gallons of paint will need to be purchased.

Answer:

9 gallons

Step-by-step explanation:

The option that shows a two-way conditional frequency table is option B as shown in the image attached.

A two-way conditional frequency table is a type of table that shows the frequency determined by two variables. In this case, the variables are:

Moreover, this table uses numbers from 0 to 1 to express frequency rather than percentages or numbers of people.

The correct option is option B because it meets the following requirements:

Answer:

28 cubs

Step-by-step explanation:

Since one and a half bear produces one and a half cub, then 6 bears will produce 6 cubs in one and a half days.

We need to find 7 days, though but we have the rate for six bears for 1.5 days which 6 bears one a half day.

What is the rate for a day?

6/1.5 =

6 bears produce 4 cubs a day.

Now just do 4 x 7

4 x 7 = 28

Therefore, 6 bears produce 28 cubs in 7 days.

Answer: its 40 because its a whole number

Step-by-step explanation:

The candle has burned down  \(3 \frac{3}{4}\)  inches after 6.5 hours.

To calculate this, we first need to determine the rate at which the candle burns by dividing the total burn time (11 hours) by the total length of the candle ( \(5 \frac{1}{2}\)  inches). This gives us a burn rate of 2 hours per inch.

Next, we can multiply the burn rate by the time the candle has been burning (6.5 hours) to determine how far the candle has burned. This gives us a result of 13 inches, which is equal to \(3 \frac{3}{4}\) inches in standard units. Therefore, the candle has burned down  \(3 \frac{3}{4}\)  inches after 6.5 hours.

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7 lawns / 4 hours = 1.75 hours per lawn.

1.75 hours per lawn x 21 lawns = 36.75 hours total ( 36 hours and 45 minutes)

Answer:

question 1: answer is 4

question 2: answer is 1

Step-by-step explanation:

The exact values of the remaining trigonometric functions are listed below:

Case 3: cos θ = 3 / 5, tan θ = 4 / 3, cot θ = 3 / 4, sec θ = 5 / 3, csc θ = 5 / 4

Case 4: sin θ = √11 / 6, tan θ = √11 / 5, cot θ = 5√11 / 5, sec θ = 6 / 5, csc θ = 6√11 / 11

Case 5: cos θ = 8√73 / 73, sin θ = 3√73 / 73, tan θ = 3 / 8, cot θ = 8 / 3, csc θ = √73 / 3

Case 6: sin θ = 1 / 2, cos θ = √3 / 2, tan θ = √3 / 3, sec θ = 2√3 / 3, csc θ = 2

In this problem we find four cases of trigonometric functions, whose exact values of remaining trigonometric functions must be found. The trigonometric functions are defined below:

sin θ = y / √(x² + y²)

cos θ = x / √(x² + y²)

tan θ = y / x

cot θ = x / y

sec θ = √(x² + y²) / x

csc θ = √(x² + y²) / y

Now we proceed to determine the exact values of the trigonometric functions:

Case 3: y = 4, √(x² + y²) = 5

x = √(5² - 4²)

x = 3

cos θ = 3 / 5

tan θ = 4 / 3

cot θ = 3 / 4

sec θ = 5 / 3

csc θ = 5 / 4

Case 4: x = 5, √(x² + y²) = 6

y = √(6² - 5²)

y = √11

sin θ = √11 / 6

tan θ = √11 / 5

cot θ = 5√11 / 5

sec θ = 6 / 5

csc θ = 6√11 / 11

Case 5: x = 8, √(x² + y²) = √73

y = √(73 - 8²)

y = 3

cos θ = 8√73 / 73

sin θ = 3√73 / 73

tan θ = 3 / 8

cot θ = 8 / 3

csc θ = √73 / 3

Case 6: x = √3, y = 1

sin θ = 1 / 2

cos θ = √3 / 2

tan θ = √3 / 3

sec θ = 2√3 / 3

csc θ = 2

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Answer:

Step-by-step explanation:

Eu sei comprei a só não lembro a conta

Answer:

Domain is x ∈ R

Step-by-step explanation:

There weren't any options given, but for f(x) = 2x + 15, the domain is x ∈ R.

This is because the graph is a linear function, which exists for all values of x. You can express this in lots of different ways, but R (all reals) is the conventional way to do it.

In case you don't know what a domain is: it is a set of numbers that the x-values of an equation can fit into.

Example:

f(x) = \(x^{2}\) -> x ∈ R

This is because, if you draw a quadratic graph, you can see that the values of x are neverending.

Hope this helped : )

Given ,IV solution of 110 mL at a drip rate of 5 gtt/min using a tubing factor of 10 gtt/ mL. The formula used to solve infusion time is: Infusion time = Volume ÷ Flow Rate Substitute the values in the formula given above.  Infusion time

= 110 ml ÷ 50 gtt/min Infusion time = 2.2 min/ml To convert minutes into hours, we divide by 60. 2.2 min/ml ÷ 60 min/h = 0.0367 h/ml To determine the total time for 110 ml, multiply 110 ml × 0.0367 h/ml

= 4.037 h Round the time to the nearest tenth of an hour, which is one decimal place. Thus, the infusion time is 4.0 hours. Therefore, the infusion time for the given problem is 4.0 hours (rounded to the nearest tenth of an hour).

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9514 1404 393

Answer:

  12.4

Step-by-step explanation:

FD is marked as 6.2. It is a "midline" parallel to AC. A midline is half as long as the side it is parallel to.

  AC = 2×6.2

  AC = 12.4

Answer:

2:1:1

Step-by-step explanation:

Divide the whole ratio by the greatest common factor. That GCF is two.

Answer:

8

Step-by-step explanation:

total: 28 water attractions

pools: p

game areas: p + 2

water slides: 50% of 28 = 14

14 + p + p + 2 = 28

2p = 12

p = 6

game areas:

p + 2 = 6 + 2 = 8

The size of the largest angle of the given triangle can be calculated using cosine rule : c² = b² + a² - 2abcosC , where 'C' represents the largest angle of the triangle.

As given in the question,

Let the given triangle be ABC,

Side opposite to ∠A, ∠B, and ∠C is BC, AC, and AB respectively.

BC = a

AC =b

AB = c

let us consider ∠C be the largest angle of the given triangle.

Value of ∠C can be calculated by substituting other values in the cosine rule given by :

cosine rule : c² = b² + a² - 2abcosC

If Pythagoras theorem satisfied then largest angle is right angle.

Therefore, the size of the largest angle of the given triangle can be calculated using cosine rule : c² = b² + a² - 2abcosC

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