The sum of two numbers is 45 and their product is 500. What are the two numbers?

so is the question right?

Answer:

Factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.

Step-by-step explanation:

The median of the given data set as required to be determined in the task content is; 4.

It follows from the task content that the value which represents the median of the data set is to be determined.

By observation, the number of data values in the data set is; 15. On this note, the median value would be the eighth term in an orderly arrange of the values.

Consequently, the median of the data set as required is; 4.

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Answer:

Question 1 is G.

Question 2 is B

Question 3 is D

Question 4 is A.

Step-by-step explanation:

g sio2 is always 0.4 mg too high regardless of the weight of the sample taken for analysis. The relative error in parts per thousand would be 400.

This is because the relative error is calculated by taking the difference between the actual value and the measured value, and dividing this by the actual value.

In this case, the actual value is 0.4 mg and the measured value is

0.4 mg + (10% x 0.4 mg) = 0.44 mg. Thus the relative error is

(0.44 – 0.4)/0.4 = 0.1/0.4 = 0.25 = 400 parts per thousand.

The relative error in parts per thousand would be 400.

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a) The set Z (integers) is not open.

b) The set O = ∩(i=1 to ∞)Oi, where Oi = (-1/i, 1/i), is open.

a) The set Z (integers) is not open.

An open set is a set that does not contain its boundary points.

In the case of the set of integers, every point in the set is a boundary point since there are no open intervals around any integer that lie entirely within the set.

Therefore, the set Z is not open.

b) The set O = ∩(i=1 to ∞)Oi, where Oi = (-1/i, 1/i), is open.

Each individual interval Oi = (-1/i, 1/i) is an open interval, and the intersection of open sets is also an open set.

This means that for any point x in O, there exists an open interval around x that is entirely contained within O.

Therefore, O is an open set.

Neither set Z nor set O is closed.

In the case of set Z, it does not contain all of its boundary points since the boundary points include all non-integer numbers.

set O is not closed since it does not contain its boundary points, which include the points -1 and 1.

Neither set Z nor set O is compact.

A compact set is a set that is both closed and bounded. As mentioned earlier, neither set Z nor set O is closed.

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Answer:

Step-by-step explanation:

et A=120°

and B=5Pi /6

Pi radians ---------> 180°

  x<----------------------- 120°

so x =120 x Pi / 180 = 12 xPi / 18 = 2 Pi/3

so A = 2Pi / 3 radian  

let 's compare A and B

we know that 5Pi /6 = 0.8 Pi and  2P/3= 0.6 Pi, 0.8>0.6,  

finally 5Pi /6 > 2P/3

so B>A

For Quadrilateral ABCD and Quadrilateral PQRS, if AD = 3, DC = 2x + 4, PS = 2, and SR = 5, the value of x is = 3.

Here's how to solve the problem:

Given, AD = 3, DC = 2x + 4, PS = 2 and SR = 5. Now, we need to find x.

A quadrilateral is a four-sided figure. The given quadrilateral ABCD and quadrilateral PQRS are shown below:

From the above figure, we can see that:

AB + BC + CD + DA = PQ + QR + RS + SP (Opposite sides of a quadrilateral are equal)

So,

3 + BC + (2x + 4) + DA = 2 + 5 + QR + 2 (Substituting the given values)

Simplifying the above equation, we get:

BC + DA + 2x = QR - 4

Let us consider the below figure:

From the above figure, we can see that:

QR + RS = AD (Sum of two opposite sides of a parallelogram is equal to the sum of the other two opposite sides)

QR + 5 = 3 + DC

QR + 5 = 3 + (2x + 4)

QR = 2x + 2

Simplifying the above equation, we get:

QR = 2(x + 1)

Substituting the value of QR in the above equation, we get:

BC + DA + 2x = 2(x + 1) - 4

BC + DA + 2x = 2x - 2

Simplifying the above equation, we get:

BC + DA = - 2

But the length of a line segment is always a positive number.

So,BC + DA > 0

Putting the values of BC and DA as BC = x + 1 and DA = 2, we get:

x + 1 + 2 > 0x + 3 > 0x > - 3

So, the value of x is greater than - 3.

Hence, the correct answer is (3) 3.

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(a) (An B)° = Aºn Bº: The interior of the intersection of sets A and B is equal to the intersection of their interiors. (b) A°UB° C (AUB)°: The union of the interiors of sets A and B is a subset of the interior of their union. (c) A° U B° ≠ (AUB)°: There are sets A and B in R where the union of their interiors is not equal to the interior of their union.

(a) To prove (An B)° = Aºn Bº, we need to show that any point in the interior of the intersection of A and B is also in the intersection of their interiors, and vice versa. Suppose x is in (An B)°, then there exists ε > 0 such that V₂(x) ⊆ An B. By definition of intersection, we can write V₂(x) ⊆ A and V₂(x) ⊆ B. Hence, x is in A° and B°, implying x is in A°n B°. The reverse inclusion can also be shown similarly. (b) To prove A°UB° C (AUB)°, we need to show that any point in the union of the interiors of A and B is also in the interior of their union. Let x be in A°UB°, then x is either in A° or B° (or both). Without loss of generality, let x be in A°. There exists ε > 0 such that V₂(x) ⊆ A. Since A ⊆ AUB, we have V₂(x) ⊆ AUB, which implies x is in (AUB)°. (c) Consider the sets A = [0, 1] and B = (1, 2) in R. The interior of A is (0, 1) and the interior of B is (1, 2). The union of their interiors is (0, 1) U (1, 2) = (0, 2). On the other hand, the interior of their union is the interior of [0, 2] which is (0, 2]. Therefore, A° U B° ≠ (AUB)°, showing that the inclusion in part (b) may not be strict.

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The surface area of the triangular base prism is 18.87 cm².

The prism is a triangular base prism . Therefore, the surface area of the prism can be found as follows:

Surface area of the prism  = (a + b + c)l + bh

where

Therefore,

a = 1 cm

b = 1 cm

c = 1 cm

l = 6 cm

b = 1 cm

h = 0.87 cm

Therefore,

surface area of the triangular prism = (1 + 1 + 1)6 + 1(0.87)

surface area of the triangular prism =3(6) + 0.87

surface area of the triangular prism = 18 + 0.87

surface area of the triangular prism = 18.87 cm²

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The transformation T: R^3 → R^2 defined by T(x1, x2, x3) = (|x1|, 0) is not linear transformation as it violates the additivity and homogeneity properties of linearity.

To show that the transformation T: R^3 → R^2 defined by T(x1, x2, x3) = (|x1|, 0) is not linear, we need to demonstrate that it violates at least one of the two properties of linearity, namely, additivity and homogeneity.

Additivity: T(u + v) = T(u) + T(v) for all vectors u and v in R^3.

Let u = (1, 2, 3) and v = (4, 5, 6) be two vectors in R^3. Then,

T(u) = T(1, 2, 3) = (|1|, 0) = (1, 0)

T(v) = T(4, 5, 6) = (|4|, 0) = (4, 0)

T(u + v) = T(1+4, 2+5, 3+6) = T(5, 7, 9) = (|5|, 0) = (5, 0)

However,

T(u) + T(v) = (1, 0) + (4, 0) = (5, 0)

Since T(u + v) ≠ T(u) + T(v), the transformation T is not additive and hence not linear transformation.

Homogeneity: T(cu) = cT(u) for all vectors u in R^3 and all scalars c.

Let u = (1, 2, 3) be a vector in R^3, and let c = 2 be a scalar. Then,

T(u) = T(1, 2, 3) = (|1|, 0) = (1, 0)

T(cu) = T(2, 4, 6) = (|2|, 0) = (2, 0)

However,

cT(u) = 2(1, 0) = (2, 0)

Since T(cu) ≠ cT(u), the transformation T is not homogeneous and hence not linear.

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The required measure of side y = 8

Given : Triangle TUV and triangle XWV are similar

Thus \(\frac{UV}{VW} = \frac{6}{21}\)

this is further equal to \(\frac{2}{7}\)

Thus the ratio UV : VW = 2 : 7

this implies that the ratio TV : VX should also be equal to the ratio of UV : VW = 2 : 7 because of cpst or also called corresponding parts of similar triangles.

Given  UV : VW = 2 : 7

thus TV : VX = \(\frac{y}{28 }\) which on equation will give y as 8

because \(\frac{8}{28}\) when divided by 4 will give us the required ratio that is 2 : 7

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No, there cannot be a horizontal tangent at the point where the curve intersects the x-axis.

A smooth-drawn figure or line with a bend or turn is referred to as a curve.

A circle is an illustration of a curved shape.

The path, also known as the topological arc, is the name of the curve (or just arc).

If a curve is the continuous injective image of an interval or a circle, it is considered simple.

If a curve is determined by a continuous function, in other words.

So, it possible for the curve to have a horizontal tangent:

On the curve, horizontal tangents appear where:

x = -1 and y ≠ -1

y = 0 where the curve crosses the x-axis.

-1² + 2(-1) + 0⁴ + 4.0 ≠ 5

No, the point where the curve crosses the x-axis cannot have a horizontal tangent.

Therefore, no, there cannot be a horizontal tangent at the point where the curve intersects the x-axis.

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Complete question:

Consider the closed curve in the xy-plane given by : x²+2x+y⁴=4y = 5

Is it possible for this curve to have a horizontal tangent at points where it intersects the x-axis? explain your reasoning.

Answer:

5(-4)-7(6)=-62

Answer:

13

Step-by-step explanation:

Prime numbers are only divisible by 1 or themselves.

No other factors

Answer:

you will ??? thats cool

Step-by-step explanation:

Answer:

Help with what?

Step-by-step explanation:

The average waiting time for a tourist who isn't served immediately is approximately 0.9375 minutes, which is closest to option d. 0.333 minutes.

To calculate the average waiting time for a tourist who isn't served immediately, we need to consider the arrival rate of tourists, the service rate of the employees, and the number of employees available.

The arrival rate is given as one tourist every 60 minutes, which means that the arrival rate (λ) is 1/60 tourists per minute. The service rate (μ) is the reciprocal of the average service time, which is 1/30 tourists per minute.

Since we have 8 employees available, the effective service rate (μ') is 8 times the individual service rate, which gives us 8/30 tourists per minute.

To calculate the average waiting time (W), we can use the formula:

W = (ρ / (μ - λ)) * (1 / μ),

where ρ is the traffic intensity, which is equal to λ / μ'.

Substituting the values into the formula:

ρ = (1/60) / (8/30) = 0.25,

W = (0.25 / (8/30)) * (1 / (8/30)) = 0.25 * (30/8) = 0.9375 minutes.

Therefore, the average waiting time for a tourist who isn't served immediately is approximately 0.9375 minutes, which is closest to option d. 0.333 minutes.

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Answer:

2(11*9) + 2(11*h) + 2(9*h) = 558

h = 9 in.

Step-by-step explanation:

2(11*9) + 2(11*h) + 2(9*h) = 558

198 + 22h + 18h = 558

40h = 558-198

40h = 360

h = 9 in.

Answer:

There is a positive correlation in the data set.

General Formulas and Concepts:

Statistics - Scatterplots

Step-by-step explanation:

According the data set on the graph, we can see that if we draw a line of best fit, the overall data would be increasing. Therefore, we would have a positive correlation.

The equation of the line tangent to the curve at the point corresponding to the given value of t.

x = t²-23 and y = t³ + t, at t = 5 is

38x - 5y + 574 = 0

Given, a curve with the points represented by

x = t²-23 and y = t³ + t, at t = 5

we have to find an equation of the line tangent to the curve at the given point on the curve.

so, the given point is (x , y) = (5² - 23 , 5³ + 5)

(x , y) = (2 , 130)

Now, the slope of the curve at that point be,

dy/dx = (3t² + 1)/(2t)

dy/dx = 76/10

Now, on using the slope-intercept form, we get

(y - 130)/(x - 2) = 38/5

5(y - 130) = 38(x - 2)

5y - 650 = 38x - 76

38x - 5y + 574 = 0

Hence, the equation of the line tangent to the curve at the point corresponding to the given value of t.

x = t²-23 and y = t³ + t, at t = 5 is

38x - 5y + 574 = 0

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Answer:

She spends 111 minutes doing cardio workouts and 39 minutes doing weight training

Step-by-step explanation:

Call the time she spend on cardio workouts : a
And the time she spend on weight training : b

We have : a + b = 150
                 a - b = 72
Add them together, we get : a + b + (a-b) -> a+ b + a - b = 150 + 72 = 222
                                                                      = 2a
=> 2a = 222, and we have a = 111
=> b = 150 - 111 = 39

Hope this helps :)

Answer:

-8

Step-by-step explanation:

5r= -40 | :5

r= -8

.....

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1200\\ r=rate\to 0.2\%\to \frac{0.2}{100}\dotfill &0.002\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{weekly, thus fifty two} \end{array}\dotfill &52\\ t=years\dotfill &10 \end{cases} \\\\\\ A = 1200\left(1+\frac{0.002}{52}\right)^{52\cdot 10}\implies A \approx 1224.24\)

Answer: $1248 in compound interest for 10 years

Step-by-step explanation:

Answer:

33.60

Step-by-step explanation:

Multiply 28 by 20%

28*20%=5.6

Add 5.6 and 28 together

28+5.6=33.60

Sorry if it is wrong Im still really tired

Based on the given options, the situation that would give the best estimate of a population proportion is Sample size 120, sample proportion 0.58 . Option B is the correct option.

We must take into account the sample size and sample percentage to evaluate which scenario would provide the most accurate estimate of a population proportion.

Larger sample sizes are often used to get the best estimates of population proportions since they give more accurate and trustworthy data about the population. A bigger sample size lowers the error margin and boosts the estimation's level of confidence.

The scenario that would provide the most accurate estimate of a population proportion based on the available alternatives is Sample proportion 0.58 and sample size 120.

Compared to the other alternatives, this option has a considerably higher sample size, which raises the estimate's accuracy and precision. A greater representation of the predicted population proportion is also indicated by the sample proportion of 0.58.

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The inverse of the function and the secret code obtained from the table of values are;

A. C⁻¹(x) = (x + 9)/4

B. The secret code is; FUNCTIONS

The inverse of a specified function reverses the effect of a the specified function.

A. The specified function is; c(x) = 4·x - 9

The inverse of the function c(x) can be found as follows;

c(x) = 4·x - 9

c(x) + 9 = 4·x

4·x = c(x) + 9

x = (c(x) + 9)/4

c⁻¹(x) = (x + 9)/4

B. The table for c(x) and c⁻¹(x) are presented as follows;

c(x)   \({}\)    c⁻¹(x)

15 \({}\)        c⁻¹(x) = (15 + 9)/4 = 6

75 \({}\)        c⁻¹(x) = (75 + 9)/4 = 21

47 \({}\)        c⁻¹(x) = (47 + 9)/4 = 14

3 \({}\)          c⁻¹(x) = (3 + 9)/4 = 3

71 \({}\)         c⁻¹(x) = (71 + 9)/4 = 20

27 \({}\)        c⁻¹(x) = (27 + 9)/4 = 9

51 \({}\)        c⁻¹(x) = (51 + 9)/4 = 15

47 \({}\)        c⁻¹(x) = (47 + 9)/4 = 14

67 \({}\)        c⁻¹(x) = 67 + 9)/4 = 19

The letters are; 6 = F, 21 = U, 14 = N, 3 = C, 20 = T, 9 = I, 15 = O, 14 = N, 19 = S

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July is the seventh month of the year in the Gregorian calendar, which is the most widely used calendar system in the world.

It is considered the seventh month because it falls between June, the sixth month, and August, the eighth month. July is also the last month of the second quarter of the year, having 31 days.

July is known for many events and holidays, such as Independence Day in the United States, Canada Day, and Bastille Day in France. It's also the middle of the summer season, and people often take vacations and enjoy outdoor activities during this month.

It's important to note that in different cultures and regions the months of the year may be ordered differently.

For example, some cultures may have a lunar calendar which is based on the cycles of the moon rather than the sun, and the months may be ordered differently.

However, the Gregorian calendar is widely used around the world and it considers July as the seventh month of the year.

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Answer:

5

Step-by-step explanation:

5 is greater than 1 because it is further to the right from zero on the number line

Answer:

5 because 5 is a bigger number than 1.

Step-by-step explanation:

5 is bigger by for an example if you have 5 apples vs 1 apple.

5 apples is more right.

The correct interpretation of the confidence interval concerning the study is that the researchers expect that 98% of all similarly constructed intervals will contain the true mean number of oocytes that could be retrieved from the population of women aged 36-40 years.

The reported interval of (8.1, 11.3) represents the range of values that is likely to contain the true mean number of oocytes retrieved from the population of women aged 36-40 years, with 98% confidence. This means that if the study were repeated multiple times with different random samples of women aged 36-40 years, and if the same statistical methods were used, then 98% of the resulting confidence intervals would contain the true population means.

It is important to note that this confidence interval applies only to the population of women aged 36-40 years, and not to other populations or age groups. Additionally, the confidence interval does not guarantee that the true population means falls within the reported interval with 98% probability, but rather that 98% of intervals constructed from repeated sampling will contain the true population means.

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Answer: 1/3

Step-by-step explanation:

They are both divisible by each other. 2187/2187 is 1, and 6561/2187 is 3, so it's 1/3.

Answer:3x4=x

Step-by-step explanation: