The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), acetic acid (CH3COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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The experimental yield is 2.9 g, the theoretical yield is 2.96 g, and the percent yield is 97.97%.

How to find the experimental yield, theoretical yield and Percent yield?

To find the experimental yield, we need to determine the weight of copper chloride (CuCl) obtained from the reaction. We can calculate this by subtracting the weight of the watch glass and filter paper from the weight of the watch glass, filter paper, and CuCl precipitate:

Weight of CuCl = (Weight of Watch Glass + Filter Paper + CuCl Precipitate) - (Weight of Watch Glass and Filter Paper)

Weight of CuCl = 13.4 g - 10.5 g

Weight of CuCl = 2.9 g

To find the theoretical yield, we need to calculate the amount of copper that should be produced based on the reaction stoichiometry. The balanced chemical equation for the reaction between copper and nitric acid is:

Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

From the equation, we can see that one mole of copper reacts with four moles of nitric acid to produce one mole of copper(II) nitrate (Cu(NO3)2). The molar mass of copper is 63.55 g/mol, so the amount of copper used in the reaction is:

Amount of Cu = Weight of Cu / Molar mass of Cu

Amount of Cu = 1.034 g / 63.55 g/mol

Amount of Cu = 0.016 mol

Since one mole of copper produces one mole of copper(II) nitrate, the theoretical yield of copper(II) nitrate is also 0.016 mol.

The theoretical yield of copper(II) nitrate is:

Theoretical yield = Amount of Cu(NO3)2 x Molar mass of Cu(NO3)2

Theoretical yield = 0.016 mol x 187.57 g/mol

Theoretical yield = 2.96 g

Finally, we can calculate the percent yield using the formula:

Percent yield = (Experimental yield / Theoretical yield) x 100%

Plugging in the values we calculated, we get:

Percent yield = (2.9 g / 2.96 g) x 100%

Percent yield = 97.97%

Therefore, the experimental yield is 2.9 g, the theoretical yield is 2.96 g, and the percent yield is 97.97%.

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Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

Answer:

3

Explanation:

3 different elements are found

Mg - magnesium

O -oxygen

H - hydrogen

'

mark brainliest

Answer: 3

Explanation:

Answer:

d. 10

Explanation:

The 24 means the atomic mass and twelve means the number of electrons. You subtract the number of electrons from the atomic mass. 24-12=12

Then, since there's +2, you subtract 2 from 12 which equals 10 which means there are 10 electrons now.

The confusing thing is that + means subtract and - means add here.

Hope this helps.

Answer:

Explanation:

The pH of 0.02 M hydrochloric acid is approximately 1.7.

THANKS

IF THE ANSWER IS CORRECT , THEN MARK ME AS BRAINLIST

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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The pOH of a solution can be calculated using the formula: pOH = -log[OH-]. To find the [OH-] concentration when the pOH is 7, we need to convert the pOH value to the OH- concentration.

Starting with pOH = 7, we can rearrange the equation to find [OH-]. Taking the antilog of both sides, we get 10^(-pOH) = 10^(-7). This simplifies to [OH-] = 10^(-7) or 0.0000001 M.

Therefore, the [OH-] concentration in the solution with a pOH of 7 is 0.0000001 M or 1 x 10^(-7) M.

It's worth noting that the pOH and pH of a solution are related by the equation: pH + pOH = 14. In this case, if the pOH is 7, the pH of the solution would be 14 - 7 = 7.

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Because digital information is frequently encrypted and compressed, digitizing signals is safer.

A signal path is one that expresses data as a series of distinct values; it is unable to take on one of a limited number of different values at any given moment. An analog signal, on the other hand, conveys continuous values; anywhere at given instant, it represents an actual number within such a continuous value range.

Simple digital signals encode information in discrete analog level bands. All levels in a value band indicate the very same information state. The signal throughout most digital circuits can have two correct values; this is known as a binary signal as well as logic signal. Because digital information is frequently encrypted and compressed, digitizing signals is safer.

Therefore, because digital information is frequently encrypted and compressed, digitizing signals is safer.

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Diagram represents an element that is likely to form covalent bonds is a purple circle with 3 concentric circles around it

Covalent bond means it consist of mutual sharing of one or more pair of electron between two atom and covalent bond diagram consist of in the middle the small circle which is purple color and three concentric circles around the purple circle and covalent bond diagram show the electron dot formulas and they often reffred to as lewis structure and are little different than electron dot formula used to represent the ionic bond

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Alkyne chemistry refers to the branch of chemistry that deals with triple bonds between carbon atoms. Due to the presence of pi-electrons that are not tightly bound, alkynes undergo addition reactions.

Alkynes have a triple bond, which makes it possible to add halogens, water, and other substances to them through an addition reaction. A series of steps are used to create addition goods. The development of addition products is caused by the stability of vinylic cations. Asymmetric alkynes must adhere to Markovnikov's rule in order to conduct addition reaction. Below are a few addition reactions of alkynes that are explained: Alkenes are created when alkynes react with dihydrogen in the presence of catalysts like Pt/Pd/Ni. Alkanes are created when the produced alkenes further react with dihydrogen.

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Answer:

I hope that help you

Explanation:

energy is change from one form to another called    _energy conversion

energy can neither be created nor destroyed it can only be transformed from one form to another called --The law of conservation of energy

cause to change in form character or function called - convert

the last sentensce

energy  transformation

Answer:

0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP

Explanation:

The balanced chemical equation for the decomposition of KNO3 is:

2 KNO3 (s) → 2 KNO2 (s) + O2 (g)

From this equation, we can see that 2 moles of KNO3 produce 1 mole of O2. Therefore, we need to calculate the number of moles of KNO3 we have and use the mole ratio to find the number of moles of O2 produced.

First, we need to convert the mass of KNO3 given to moles:

moles of KNO3 = mass of KNO3 / molar mass of KNO3

The molar mass of KNO3 is 101.1 g/mol (39.1 g/mol for K, 14.0 g/mol for N, and 3 x 16.0 g/mol for 3 O atoms), so we have:

moles of KNO3 = 3.25 g / 101.1 g/mol = 0.0321 mol

Now we can use the mole ratio from the balanced equation to find the number of moles of O2 produced:

moles of O2 = 0.5 x moles of KNO3

moles of O2 = 0.5 x 0.0321 mol = 0.01605 mol

Finally, we can convert the number of moles of O2 to volume at STP using the ideal gas law:

V(O2) = n x RT/P = (0.01605 mol)(0.0821 L·atm/(mol·K) x 273.15 K)/(1 atm) = 0.359 L

Therefore, 0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP.

Answer:

will be 9.7 Liters

Explanation:

Solution :

The reaction :

\($\text{TrisH}^+ + \text{H}_2\text{O} \rightarrow \text{Tris}^- +\text{H}_3\text{O}^+$\)

We have

\($K_a = \frac{[\text{Tris}^-]\times[\text{H}_3\text{O}^-]}{[\text{TrisH}^+]}$\)

     \($=\frac{x^2}{0.02-x}$\)

     \($= 8.32 \times 10^{-9}$\)

Clearing x, we have \($x=1.29 \times 10^{-5}$\) moles of acid

Now to reach pH = \($7.8 (\text{ pOH} = 14-7.8 = 6.2)$\), we must have an \($OH^-$\) concentration of

\($[OH^-] = 10^{-pOH}$\)

          \($=10^{-6.2}$\)

         \($=6.31 \times 10^{-7}$\) moles of base

We must add enough NaOH of 1 M to neutralize the acid calculated above and also add the calculated base.

\($n \ NaOH = 1.29 \times 10^{-5} + 6.31 \times 10^{-7}$\)

               \($=1.35 \times 10^{-5}$\) moles

Vol \($NaOH = 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \ mL}{1 \ mol}$\)

                 = 0.0135 L

Tris mass \($H^+ = 0.02 \text{ mol} \times 157.6 \ g/mol$\)

                        = 3.152 g

To prepare the said solution we must mix

-- \($3.152 \ g \text{ TrisH}^+$\)

-- \($0.0135 \ mL \ NaOH \ 1M$\)

-- \($\text{Gauge to 1000 mL with H}_2\text{O}$\)

Answer:

The table feels cold because it is at a lower temperature than the students' hands, and thermal energy is being pulled into the table.

Explanation:

The thermal conductivity of the table is low and so it feels cold.

Thermal conductivity is the measure of the ability of a material to conduct heat.

The rate at which heat is transported by conduction through a material's unit cross-section area when a temperature gradient exits perpendicular to the area is known as thermal conductivity.

Thermal energy is the energy contained within a system that accounts for the temperature of the system.

The human body cannot measure the temperature of any object but it can feel the difference in the temperature.

If one body is at 20 degrees Celsius, and an object is at 30 degrees Celsius, then the body will feel hot when the object is touched.

Similarly, when the students touched the table, the conductivity of the wood is very low, and it feels cold.

The thermal energy of the table is lower than the thermal energy of the body.

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Answer:

0.1334

Explanation:

The number of atoms per unit (n) is given by:

\(n=\frac{\rho a^2bN_a}{A} \\\\where\ a=5.83*10^{-8}cm,b=a=3.18*10^{-8}cm,\rho=7.3\ g/cm^3,\\N_a=Avogadro\ number=6/022*10^{23} mol^{-1},A=atomic\ weight\\=118.68 \ g/mol\\\\n=\frac{7.3* (5.83*10^{-8})^2*(3.18*10^{-8})*6.02*10^{23}}{118.69}\\\\n=4\ atoms/unit\)

The atomic packing factor (APF) is:

\(APF=\frac{n(\frac{4\pi R^3}{3} )}{a^2b} \\\\But\ R=atomic\ radius=1.51*10^{-8}\ cm\\\\APF=\frac{4(\frac{4\pi (1.51*10^{-8})^3}{3} )}{(5.83*10^{-8})^2*3.18*10^{-8}}\\\\APF=0.1334\)

The reaction is given by

\(\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs\)

Barium goes underneath beta decay to form Ceaseum

\(\sf {}^{127}_{56}Ba\longrightarrow {}^0_{1}\beta+{}^{127}_{55}Cs\)

Remember

Considering the Hess's Law, the enthalpy change for the reaction is -84.4 kJ.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

2 C (graphite) + 3 H₂(g) → C₂H₆(g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: C₂H₆(g) + \(\frac{7}{2}\) O₂(g) → 2 CO₂(g) + 3 H₂O(l) ; ΔH° = –1560 kJ

Equation 2:  H₂(g) + \(\frac{1}{2}\) O₂(g) → H₂O(l) ; ΔH° = –285.8 kJ

Equation 3: C(graphite) + O₂(g) → CO₂(g) ; ΔH° = –393.5 kJ

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 2 moles of C(graphite) on reactant side and it is present in third equation. In this case it is necessary to multiply it by 2 to obtain the necessary amount. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

Now, you need 3 moles of H₂(g) on reactant side and it is present in second equation. In this case it is necessary to multiply it by 3 to obtain the necessary amount and the variation of enthalpy also is multiplied by 3.

Finally, 1 mole of C₂H₆(g) must be a product and is present in the first equation. Since this equation has 1 mole of C₂H₆(g) on the reactant side, it is necessary to locate the C₂H₆(g) on the reactant side (invert it). When an equation is inverted, the sign of delta H also changes.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1:  2 CO₂(g) + 3 H₂O(l) → C₂H₆(g) + \(\frac{7}{2}\) O₂(g); ΔH° = 1560 kJ

Equation 2:  3 H₂(g) + \(\frac{3}{2}\) O₂(g) → 3 H₂O(l) ; ΔH° = –857.4 kJ

Equation 3: 2 C(graphite) + 2 O₂(g) → 2 CO₂(g) ; ΔH° = –787 kJ

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

2 C (graphite) + 3 H₂(g) → C₂H₆(g)    ΔH= -84.4 kJ

Finally, the enthalpy change for the reaction is -84.4 kJ.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

Exposure of 2-methyl-2-butene to oxymercuration-demercuration conditions provides 2-methyl-2-butanol.

Explanation:

Please see the attachments below

Answer

48.3 °C

Explanation

Given parameters:

Mass of the chunk material, m = 328.0 g

The specific heat of the material, c = 1.17 J/g°C

Initial temperature, T₁ = 71.0 °C

The heat lost, Q = 8.7 kJ = 8700 J

What to find:

The final temperature (T₂) of the chunk after it loses 8.7 kJ of heat in a pot of water.

Step-by-step solution:

The final temperature (T₂) of the chunk after it loses 8.7 kJ of heat in a pot of water can be calculated using the formula for heat lost.

Putting the values of the given parameters into the formula, we have:

Therefore, the final temperature of the chunk after it loses 8.7 kJ of heat in a pot of water is 48.3 °C.

Answer:

The estimate is \(N = 1936 \)

Explanation:

From the question we are told that

The molecular weight of the protein is \(MW_p = 213 kD = 213 *10^{3} \ D\)

Generally the average molecular weight of amino acid is \(MW_a = 110 \ D\)

Generally the number of amino acids in the protein is mathematically represented as

\(N = \frac{MW_p}{MW_a}\)

         \(N  = \frac}{213 *10^{3}{110}\)

=> \(N = 1936 \)

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Answer:

3.7mL is the volume of the object

Explanation:

To convert the mass of any object to volume we must use density that is defined as the ratio between mass of the object and the space that is occupying. For an object that weighs 7.9g and the density is 2.28g/mL, the volume is:

7.9g * (1mL / 2.28mL) =