The starships of the Solar Federation are marked with the symbol of the Federation, a circle, whereas starships of the Denebian Empire are marked with the Empire's symbol, an ellipse whose major axis is n times its minor axis (a = nb in the figure (Figure 1)). How fast, relative to an observer, does an Empire ship have to travel for its markings to be confused with those of a Federation ship? Use c for the speed of light in a vacuum. Express your answer in terms of n and c.
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The bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s can travel up to a height of 825.4 meters and a horizontal distance of 80.1 meters after 2 seconds.

To determine the height and horizontal distance traveled by a bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s after 2 seconds, we can use the equations of motion.

Firstly, we can break down the initial velocity of the bullet into its horizontal and vertical components. The horizontal component remains constant throughout the motion and is given by:

Vx = Vcosθ

where V is the initial velocity and θ is the angle of projection. Substituting the given values, we get:

Vx = 420cos80° = 40.05 m/s (approx.)

The vertical component of the initial velocity can be calculated as:

Vy = Vsinθ

Substituting the given values, we get:

Vy = 420sin80° = 416.95 m/s (approx.)

Now, we can use the following equations of motion to determine the height and horizontal distance traveled by the bullet after 2 seconds:

Vertical motion:

y = yo + Voyt + (1/2)gt^2

where y is the vertical displacement, yo is the initial height (assumed to be zero), Voy is the initial vertical velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Substituting the given values, we get:

y = 0 + 416.95(2) - (1/2)(9.8)(2)^2

y = 825.4 m (approx.) Therefore, the bullet can travel up to a height of 825.4 meters after 2 seconds. Horizontal motion:

x = xo + Voxt

where x is the horizontal displacement, xo is the initial horizontal position (assumed to be zero), Vox is the initial horizontal velocity, and t is the time.

Substituting the given values, we get:

x = 0 + 40.05(2)

x = 80.1 m (approx.)

Therefore, the bullet can travel a horizontal distance of 80.1 meters after 2 seconds.

In summary, the bullet fired at an angle of 80° with the horizontal and an initial velocity of 420 m/s can travel up to a height of 825.4 meters and a horizontal distance of 80.1 meters after 2 seconds.

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Answer:

with what? I can help but with what

Answer:

2

Explanation:

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

the answer is b reducing the thickness of the conductor

Explanation:

The resistance to electric current increases as the cross-section of the conductor is reduced, as the conductor is lengthened, and as the conductor is heated. Replacing the conductor with a less-conductive material increases the resistance as well.

Answer:

Reducing the thickness of the conductor

Explanation:

The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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Answer:

cos 0 = 1.

Fs = 7×8 = 56 J

Explanation:

Answer:

24.2 m/s

Explanation:

Mass is irrelevant in this situation....

Displacement:  ( to find time)

 x = xo + vo t - 1/2 at^2

 30= 0   + 0  - 1/2 (9.8)t^2

              t = 2.47 seconds

Velocity:

vf = a t   = 9.8 (2.473)  = 24.2 m/s

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer: deceleration is considered to describe a decrease or negative change of speed or velocity. ... Three of these namely time, distance and speed are scalar quantities, whereas the remaining three attributes namely displacement, velocity and acceleration are vectors.

Explanation:

Read it online

Answer:

just multiply the frequency and wavelength

200× 2

400

Answer:

As the service marks the start of every rally and subsequently dictates its flow, it is a crucial aspect of the game to get right in badminton.

These are the four main types of services in badminton and most can be executed with either your forehand or backhand.

1. Low serve

This low serve is almost a gentle tap over the net with the shuttle, with the aim of flying just over the net, yet falling just over the front line of his service court. It must not be too high or predictable, otherwise it would be easy for your opponent to do an outright smash or net kill.

2. High serve

The high serve is a powerful strike upwards with the shuttle, that aims to travel a great distance upwards and fall deep at the rear end of the court.

Although it is a strong serve and the popular choice of beginner players, its a serve that isn't so easy to disguise especially since you're using a forehand grip. Your opponent will already expect the shuttlecock to land at the back of the court.

Do remember that shuttlecocks have to fall within the corresponding service areas and this is different in singles and doubles.

3. Flick serve

This flick serve is also played upwards but at a much lesser altitude. It is most common for players to use their backhand to execute the flick serve and the trajectory is lower as this grip has less power.

The whole point of the backhand flick serve is deception, by mixing your serves up and making it look like you're doing a low serve. For this reason, serving with your backhand is thus very popular with competitive players.

It becomes hard for your opponent to predict if you are going to do a flick or a low serve as your stroke will look exactly the same until the point of contact.

4. Drive Serve

This is an attacking serve that is used by top badminton players like Lin Dan. The idea is to hit the shuttle directly at your opponent, limiting their return options and catching them off guard, winning you easy points. It's a good change of pace but it is also risky as if your opponent is prepared, he could just smash the shuttlecock back at you.

This serve is executed with your forehand through underarm action and following through. The shuttle should be dropped a bit sideways rather than in front of your body and hit flatter.

Now that you've determined the type of serve you want to make, here are a four tips on how to execute these serves well.

1. Keep your feet still

During the service, some part of both your feet must be in contact with the ground for it to be a legal serve.

2. Disguise your shots

Make sure your stroke is the same up to the point of contact with the shuttle. This will make your serve possible to predict only at the last possible second. Advanced players can try to trick their opponent by making it deliberately look like you're leaning back and about to do a high serve when you're really going to do a low serve.

3. Observe your opponents position

Is your opponent leaning towards the back already anticipating a high serve to the rear-court? In that case, you may want to execute a low serve to catch him off-guard. Always be aware of the position of your opponent. Try to imagine what he's expecting and do the opposite to gain an advantage.

4. Mix up your serves

Using just one type of service will make you too easy to predict. Make sure you incorporate at least two types of serves into your play. Once you've mastered the basic high and low serves, you can learn the flick and drive serves to add more dimension to your play.

In a nutshell, executing a service well allows you to start the rally strong and dictate its flow.

Explanation:

I hope it's help

Answer:

Hopeit helps you

Explanation:

PLS RATE AS BRAINLIEST ANSWER

Constipation is a condition characterized by infrequent bowel movements or difficulty passing stool. It can also refer to the passage of small, hard, and dry stools, straining during bowel movements, and the feeling of incomplete evacuation of the bowels.

Infrequent bowel motions or trouble passing stool are symptoms of the illness known as constipation.

Constipation is a common digestive problem that can be caused by a variety of factors, including inadequate fiber and water intake, lack of physical activity, certain medications, hormonal imbalances, and underlying medical conditions. It is generally considered to be present when bowel movements occur less than three times a week, or when the passage of stool is accompanied by discomfort or difficulty.

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Answer:

372.94 km

d= st

= (64.3 km/h)(5.8h)

=372.94 km

Answer:

Answer 1: 8

Answer 2: Protons and Valence Electrons

Answer 3: Hydrogen

Answer 4: When atoms have fewer than eight electrons, they tend to react and form more stable compounds.

Explanation:

.Atoms lose, gain, or share electrons to have a full valence shell of eight electrons. Hydrogen although is an exeption exception because it can hold a maximum of two electrons in its valence level. They may react and form more stable compounds.

Answer:

isnt heat transfer

Explanation:

sorry if im wrong

Answer:

C. Methane

Explanation:

A chemical equation can be defined as a reaction between two chemical elements.

For a chemical reaction (equation) to be balanced, the condition which must be met is that the number of atoms contained in the reactants must be equal to the number of atoms in the products.

This ultimately implies that, the mass and charge of the chemical equation are both balanced properly.

Methane is a hydrocarbon compound formed by the reaction between four (4) hydrogen atoms with a carbon atom. It belongs to the alkane group of hydrocarbons and has the following physical and chemical properties; colorless, highly flammable, non-toxic and odorless gas. The empirical formula for Methane is CH4.

Methane is a gas at 45 degrees celsius. This ultimately implies that, at 45°C methane is a gas because it is still within the range of standard temperature and pressure.

The radius of the Sun is approximately 654497.9 kilometers.

A subtended angle in geometry is an angle created by a common point (in this case, the Earth) that crosses two points of a nearby circular arc (the Sun in this case). Below is a visual illustration of the subtended angle.

The law of cosine can be used to calculate the sun's radius, which is 654497.950 kilometers in kilometers.

The Sun's radius is nearly 109 times bigger than the Earth's. The Earth's radius is 6378 kilometers. Or to put it another way, both dimensions are 1: 109 ratios.

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Answer:

the power output of the car is 29.43 kW (rounded to two decimal places).

Explanation:

To find the power output of the car, we need to use the formula:

power = work / time

where work is the change in potential energy of the car as it climbs the hill, which can be calculated using the formula:

work = force x distance

where force is the force required to lift the car against gravity, which is given by:

force = mass x gravity

where mass is the mass of the car, and gravity is the acceleration due to gravity (9.81 m/s^2).

So, the force required to lift the car against gravity is:

force = 1000 kg x 9.81 m/s^2 = 9810 N

The distance the car travels up the hill is 30 m.

Therefore, the work done by the car is:

work = force x distance = 9810 N x 30 m = 294300 J

The time taken by the car to climb the hill is 10 s.

Therefore, the power output of the car is:

power = work / time = 294300 J / 10 s = 29430 W

Answer:

It is the physics that explains how everything works, the nature of the particles that make up matter and the forces with which they interact.

Its types: Electromagnetism, the strong nuclear force, and the weak nuclear force.

Hope this help :)

Answer:

Airbags reduce chances of injury by absorbing most of the impact force from the body during a car crash

Explanation:

In a car collision, the speed of the vehicle is suddenly bought to rest. All the kinetic energy is suddenly converted into other forms of energy.

The body of the driver keeps travelling forward under his inertia force due to his mass until he is slammed against the steering wheel. The steering wheel is a very rigid component, and so when the body slams against it, the body takes the deformation, absorbing some of the energy of the moving car. This sudden impact of energy can be fatal enough to gravely injure the driver because the body does not undergo much deformation. When an airbag is used, the crash automatically triggers the release of the airbag. Instead of the body colliding against the rigid steering wheel, it is now collided against the soft air bag. The airbag is very collapsible, and some of the kinetic energy of the car on the driver is converted into the deformation energy used to deform the airbag when they collide. In the process of deformation, the time of impact is extended, reducing the force impacted on the driver, reducing the fatality of the impact.

The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.

The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.

The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.

Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.

\(Iz = ICM + MR^{2}\)

(1)We can obtain the moment of inertia of the rectangle about its center as: \(ICM = (1/12) ML^{2}\)

(2) where M is the mass of the rectangle, and L is the length of the rectangle.

Substituting values, we get: ICM = \((1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )\)

ICM = \(5 kg m^{2}\)

Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:

\(IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}\)

The moment of inertia of the system about Z-axis is: \(Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}\)

The kinetic energy of a rotating body is given as:\(K.E. = (1/2) I\omega^{2}\) where I is the moment of inertia of the system, and ω is the angular velocity of the system.

The rotational kinetic energy of the system is:\(K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)

2)\(I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)

Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

B. 10 cm

x^3 = 1 L

1 L = 1000 cm^3 (since 1 L = 1000 cm^3)

x^3 = 1000 cm^3

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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Answer:

where u put it last time or retrace ur steps to where u last put it

Answer:

Resistivity and conductivity are reciprocal quantities.

Doubling one will cause the other to be reduced to one half.