The standard free energy of formation of liquid water is -237.2 kJ/mol at 25 degrees Celsius. What is the equilibrium constant at 25 degrees Celsius for the following reaction?
2H₂O(l) → 2H₂(g) + O₂(g)

Starch is a covalent compound as it possesses long chains of glucose molecules that are bonded through covalent bonds.

In a covalent compound, the covalent bonds are involved where the mutual sharing of electrons that can hold all atoms or molecules together. Shared electrons are difficult to give away as nuclei of two atoms together share the electrons and create the bond stronger.

Ionic compounds can be demonstrated as compounds prepared between a cation and an anion. A cation can be defined as an electropositive ion and can lose valence electrons. Similarly, anions are electronegative ions and can a tendency to gain electrons.

Starch can be defined as a polysaccharide composed of 1,4 linkages between glucose monomers. The linear polymer amylose can be defined as the most basic form of starch, while amylopectin can be defined as the branched form.

Therefore, Starch is a covalent compound because of the covalent bonds between the glucose molcules.

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The reaction of 10.0 g of \(H$_2$\) and 64.0 g of \(O$_2$\) will produce 74.0 g of water. In order to calculate the grams of water produced, we need to determine the limiting reactant, which is the reactant that is completely consumed in the reaction and limits the amount of product formed.

The balanced equation for the reaction is:

\(2H$_2$ + O$_2$ $\rightarrow$ 2H$_2$O\)

Using the molar masses of \(H$_2$\) (2.02 g/mol) and \(O$_2$\) (32.00 g/mol), we can convert the masses of the reactants into moles:

moles of \(H$_2$\) = 10.0 g / 2.02 g/mol = 4.95 mol

moles of \(O$_2$\) = 64.0 g / 32.00 g/mol = 2.00 mol

From the balanced equation, we can see that 2 moles of \(H$_2$\) react with 1 mole of \(O$_2$\) to produce 2 moles of \(H$_2$O\) . Since the ratio of \(H$_2$\) to \(O$_2$\) is 2:1, we have an excess of \(H$_2$\). Therefore, \(O$_2$\) is the limiting reactant.

Now, we can calculate the moles of water produced using the limiting reactant:

moles of \(H$_2$O\) = 2.00 mol (moles of \(O$_2$\)) × 2 mol (moles of \(H$_2$O\)) / 1 mol (moles of \(O$_2$\)) = 4.00 mol

Finally, we can convert the moles of water into grams:

grams of \(H$_2$O\) = 4.00 mol × 18.02 g/mol = 72.08 g

Therefore, the reaction of 10.0 g of \(H$_2$\) and 64.0 g of \(O$_2$\) will produce 74.0 g of water.

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The missing term in the given question is "molecules".

The given two ball-and-stick models represent molecules. Molecules are groups of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

The first model represents a molecule that has a chain of four black balls connected successively. Each of the two black balls, which are at the ends of the chain, has three white balls attached. Each of the two other balls has two white balls attached to them.

The second model represents a molecule that has a chain of three black balls connected successively. The central ball has one white ball and one black ball attached. This last-mentioned black ball has three white balls attached to it. Each of the two black balls, which are at the ends of the chain, has three white balls attached.

Hence, the missing term in the given question is "molecules".

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U has a total of six electrons. This corresponds to carbon (C). A is the second most common element in the atmosphere.

The second most common element in the atmosphere is oxygen (O). E is a noble gas.

Noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Based on the given options, E could be xenon (Xe).

S is an alkali metal.

Alkali metals include lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). Based on the given options, S could be sodium (Na).

O is a halogen.

Halogens include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). Based on the given options, O could be bromine (Br).

O has an atomic number larger than V but smaller than W.

Based on the periodic table, the atomic number of oxygen (O) is 8, which is larger than the atomic number of vanadium (V) (23) and smaller than the atomic number of tungsten (W) (74).

The charge on an L ion is +2.

The charge of +2 indicates that L must lose two electrons to form the ion. Based on the given options, L could be calcium (Ca).

C has five electrons in its outer energy fever.

Carbon (C) has four valence electrons, not five. This contradicts the given statement, so we need to revisit the deductions.

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When you have taken too much of a chemical for an experiment, you should carefully pour the extra back in its original container.

Select the option c: Carefully pour the extra back in its original container.

It is very important to measure the chemicals accurately and precisely as overdosing can lead to serious consequences. But, if by mistake you have taken too much of a chemical for an experiment, you should carefully pour the extra back in its original container because it helps you to avoid waste and keep the chemicals from getting contaminated. The leftover chemical can be used later in other experiments. So, option c is the correct answer.

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Answer:

See explanation

Explanation:

The to main chemicals that lead to acid rain are SOx and NOx. The major source of oxides of sulphur are power plants while the major source of oxides of nitrogen is the combustion of fossil fuels.

B. There are two types of acid rain; wet and dry. Wet type acid rain occurs when NOx and SOx combine with water vapour in the atmosphere and fall as precipitation while in dry type, wind deposits these acidic gases/matter on the surfaces of buildings, cars, trees etc. Rain water washes off these acidic deposits and the runoff is more acidic than the rain water.

C. Natural rain water has a pH of about 5.5 due to the fact that water dissolve CO2 in the atmosphere. This means that natural rain water is also slightly acidic. Rain water that dissolves SOx or NOx is often more acidic than these hence the term 'enhanced acid rain' may be used.

Again, since precipitation could be solid or liquid, the term 'acid deposition' is better.

K2SO4 (aq)  will form a precipitate when mixed with a solution of aqueous Ba(NO3)2 .

Response and justification The outcomes of this process are sodium nitrate and barium carbonate, according to the full chemical formula. Because barium carbonate is thought to be inert in water, it will manifest in the solid state (as a precipitate).

When dissolved substances react, one (or more) solids products are produced, which is termed as a precipitation reaction. These kinds of reactions, which are also sometimes known as double displace, double replacement, or catalysed reactions, frequently require the transfer of ions between ionic substances in water-based solutions.

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Answer: D

Explanation:

O=C=O

Carbon is in group 14 having four valence electrons and oxygen is in group 16 having six valence electrons hence the correct structure of CO2 is O=C=O.

Carbon and oxygen are nonmetals. Nonmetals form compounds by sharing electrons in a covalent bond.Carbon, a group 14 element has four valence electrons while oxygen, a group 16 element has six valence electrons.

Carbon  can share four valence electrons with two oxygen atoms in CO2 to form the structure O=C=O. In this way, all the atoms now obey the octet rule.

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The lunar phase or Moon phase can be defined as the shape of the Moon's directly sunlit portion, which can be expressed in four major phases: new moon, first quarter, full moon, last quarter, and four minor phases: waxing gibbous, waxing crescent, waning gibbous, and waning crescent.

There are four principal lunar phases which can be expressed as the new moon, first quarter, full moon, and last quarter when the Moon's ecliptic longitude is at an angle to the Sun of 0°, 90°, 180°, and 270°, respectively.

Each of the phases appears at slightly different locations on Earth at different times. The intervals between principal phases can be described as the intermediate phases, during which the apparent shape of the Moon is either crescent.

A new moon will appear lowest on the winter solstice and highest on the summer solstice. A first-quarter moon appears lowest on the autumn equinox and highest on the spring equinox.

A full moon appears lowest on the summer solstice and highest on the winter solstice. A last-quarter moon appears lowest on the spring equinox and highest on the autumn equinox.

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Answer:

1.5 mol H2O

Explanation:

Limiting reactant was C2H6 - 0.5 moles

Fomula became .5C2H6 + 1.75O2 = 1CO2 + 1.5H2O

Answer:

Beta Decay

Explanation:

Beta decay conserves the number of electrons and their associated neutrinos  Since a proton or neutron has lepton number zero, β+ decay (a position, or antielectron) must be accompanied with an electron neutrino, while β− decay (an electron) must be accompanied by an electron antineutrino. An example of electron emission (β− decay) is the decay of C 14 into N14 with a  half-life of about 5,730 years

In this form of decay, the original element becomes a new chemical element. This new element has an unchanged mass number A, but an atomic number Z that is increased by one.

Answer:

Beta decay

In beta decay, a neutron is converted into a proton and an electron. The electron is then fired out of the nucleus whilst the proton remains.

This means that the the neutron number decreases by 1, and the proton number increases by 1 (therefore the nucleon number remains unchanged).

Answer:

The answer is 2

Explanation:

when viewed from earth number 2 would be a waning gibbous

Answer

1. The name of the first structure is c1hloromethan and has a tTetrahedra geometry..

2. The name of the second structure is ammonium ion and has a tetrahedral geometry.

3. The name of the third structure is sulfur hexafluoride anion and has an octahedral geometry.

Answer:

Does the Big Bang theory count?

The bulky group hinders one face of the molecule, forcing the second bromine to add from the opposite face, resulting in anti-addition of the bromine atoms.

It is due steric hindrance, which at a given atom in a molecule is the crowding caused by the  presence of the neighbouring ligands, which may slow down or prevent reactions at the atom.

Bromine molecule is liquid at room temperature, with atomic number 35. Addition of Bromine to alkenes is stereospecifically trans. Stereochemistry is the branch of chemistry that studies different spatial arrangements of atoms in molecules.

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The maximum safe operating temperature the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

To calculate the maximum safe operating temperature, we need to consider the dimensions of the vessel, the maximum safe pressure, and the amount of gas inside.

First, let's convert the dimensions of the vessel from centimeters to meters:

Width = 48.0 cm = 0.48 m

Height = 57.6 cm = 0.576 m

Next, we need to calculate the volume of the vessel:

Volume = π * (radius)^2 * height

The radius of the vessel can be calculated as half of the width:

Radius = 0.48 m / 2 = 0.24 m

Volume = π * (0.24 m)^2 * 0.576 m

Volume ≈ 0.099 m^3

Now, we can use the ideal gas law to determine the maximum safe operating temperature. The ideal gas law is given by:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Rearranging the equation to solve for T:

T = (PV) / (nR)

To calculate the number of moles, we can use the molar mass of carbon dioxide (CO2):

Molar mass of CO2 = 12.01 g/mol (for carbon) + 2 * 16.00 g/mol (for oxygen)

Molar mass of CO2 ≈ 44.01 g/mol

Converting the mass of carbon dioxide from kilograms to grams:

Mass of CO2 = 2.45 kg * 1000 g/kg

Mass of CO2 = 2450 g

Now, we can calculate the number of moles:

Number of moles = Mass of CO2 / Molar mass of CO2

Number of moles = 2450 g / 44.01 g/mol

Number of moles ≈ 55.67 mol

The gas constant R is approximately 8.314 J/(mol·K).

Now, we can substitute the values into the equation:

T = (3.40 MPa * 0.099 m^3) / (55.67 mol * 8.314 J/(mol·K))

T ≈ 1063.77 K

Converting from Kelvin to Celsius:

T ≈ 1063.77 °C

The maximum safe operating temperature that the engineer should recommend for this reaction is approximately 1063.77 degrees Celsius.

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Answer:

convection is the answer

Snowman melting in the sun is an example of convection  which causes difference in temperature.

Convection works by areas of a liquid or gas heating or cooling greater than their surroundings, causing differences in temperature. These temperature differences then cause the areas to move as the hotter, less dense areas rise, and the cooler, more dense areas sink.

Often the areas of heating and cooling are fixed, and allow convective cycles or currents to become established. For example, a saucepan of water over a flame may develop convective currents as the water is heated from below, rises to the surface, and cools. Once cooled enough, the water then sinks back to the bottom of the saucepan where the cycle is repeated, and the convective overturning continues.

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Answer:

step 1- wash the rice cooker

step2-

Nucleophilic aromatic substitution (NAS) is a type of reaction where a nucleophile substitutes a leaving group on an aromatic ring. In the presence of a strong nucleophile and an appropriate leaving group, phenol can be formed by NAS.

However, when cyclopentadiene is used as a solvent in NAS, it can act as a nucleophile itself and react with the electrophile, which results in the formation of a cyclopentadienyl cation. The cyclopentadienyl cation can then undergo various reactions, such as rearrangements and addition reactions with other nucleophiles, depending on the reaction conditions.

Therefore, in the presence of cyclopentadiene as a solvent, instead of phenol, other products such as cyclopentadiene adducts, rearranged cyclopentadienes, or other byproducts can be formed. It is important to carefully consider the choice of solvent in NAS reactions to ensure that it does not interfere with the desired reaction mechanism and does not lead to the formation of unwanted products.

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Answer:

The mass of the atom, its atomic mass, depends upon the sum of the number of protons and the number of neutrons present in the nucleus. Since the properties of the electrons depend upon the number of protons in the nucleus of an atom, each different atomic number corresponds to a qualitatively different kind of atom.

Answer:

This is really an extended comment to Geoffrey's answer, so please upvote Geoffrey's answer rather than this.

The mass of a hydrogen atom is 1.67353270×10−27 kg. If you add the masses of a proton and electron together then they come to 1.67353272×10−27 kg. The difference is about 13.6eV, which is the ionization energy of hydrogen (though note that the experimental error in the masses isn't much less than the difference so this is only approximate).

This shouldn't surprise you because you have to add energy (in the form of a 13.6eV photon) to dissociate a hydrogen atom into a free proton and electron, and this increases the mass in accordance with Einstein's famous equation

Answer:

B) heterotrophs

Explanation:

hetero meaning other or different from its own species

Answer:

Answer:

♡ hi fairy ♡

-- the answer is heterotrophs

~ madeline ✧･ﾟ: *✧･ *:･ﾟ✧*

Explanation:

pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.

When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.

In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.

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Answer:

hope it helps and thank you for the points

Answer:

A. Polar Easterlies

B. Westerlies

C. Northeast Trades

D. Southeast Trades

E. Westerlies

F. Polar Easterlies

G. Hadley cell

Explanation:

I am pretty sure this is right. Hope that helps

The pKa of Evan's oxazolidinone (benzyl) is approximately 8.5, which reflects its moderate acidity and importance in asymmetric synthesis reactions.

1. pKa is a measure of the acidity of a compound, specifically how easily a proton (H+) can be donated to a solution. A lower pKa value indicates a stronger acid.

2. Evan's oxazolidinone is a type of chiral auxiliary used in asymmetric synthesis. It consists of a benzyl group, which is a phenyl (aromatic ring) attached to a CH2 group, and an oxazolidinone ring.

3. The pKa value for Evan's oxazolidinone (benzyl) is around 8.5, which means it has a moderate acidity. This acidity is essential for the compound's role in asymmetric synthesis, as it helps control the stereochemistry and reactivity of the reaction.

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Answer:

See the answer below

Explanation:

Since no fresh air is coming into the elevator while the people are still trapped in it, the breathing of the people will alter the composition of the air inside the lift.

Breathing involves taking-in of oxygen and the release of carbon dioxide. Hence, less and less oxygen will become available within the lift while the concentration of the carbon dioxide keeps increasing as time goes on.

If the people remain trapped for a long time, the oxygen composition of the air inside the elevator will become exhausted, the carbon dioxide concentration will increase, and the people will suffocate due to lack of oxygen.

The mass of potassium chlorate is 0.3439 to generate 114.0 L  \(O_{2}\) at 0.720 atm and 291K

The decomposition of potassium chlorate is represented as

\(2KClO_{3} (s) - > 2KCl(s) + 3O_{2} (g)\)

Given, Volume = 114.0 L

pressure = 0.720 atm

temperature = 291 K

According to the Ideal gas Equation

Pv = nRT

\(n=\frac{Pv}{RT}\)

\(n=\frac{0.720*114.0}{0.82*291}\)

n= 0.3439

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