The speed of light in transparent gasoline is 2.10E+08 m/s. What is the refractive index of gasoline? The speed of light in vacuum is 3.00E+08 m/s.1.431.331.41.250.70
Answers
Therefore, the refractive index of gasoline is 1.43.
The refractive index of gasoline can be calculated using the formula Refractive index (n) = Speed of light in vacuum (c) / Speed of light in the medium (v).
To find the refractive index of gasoline, we'll use the formula:
refractive index = speed of light in vacuum / speed of light in gasoline
Here, c = 3.00E+08 m/s and v = 2.10E+08 m/s.
n = (3.00E+08 m/s) / (2.10E+08 m/s) = 1.43
Substituting the given values:
refractive index = 3.00E+08 m/s / 2.10E+08 m/s
refractive index = 1.43
So, the refractive index of gasoline is 1.43.
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Related Questions
Suponga que la pelota de la figura se proyecta desde una altura de 35.0 m sobre el suelo y se le imprime una velocidad horizontal inicial de 8.25 m/s. a) ¿Cuánto tiempo tardará la pelota en golpear el suelo? b) ¿A qué distancia del edificio tocará el suelo la pelota?
Answers
Answer:
Explanation:
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If the displacement of a horizontal mass-spring system was doubled, the elastic potential energy in the system would change by a factor of
Answers
Answer:
K'=4K
Explanation:
The electric potential energy is given by :
\(E=\dfrac{1}{2}kx^2\)
Where
k is spring constant
x is compression or extension in the spring
If the displacement of a horizontal mass-spring system is doubled, x'= 2x
New elastic potential energy :
\(E'=\dfrac{1}{2}kx'^2\\\\E'=\dfrac{1}{2}k(2x)^2\\\\=\dfrac{1}{2}k\times 4x^2\\\\K'=4\times \dfrac{1}{2}kx^2\\\\K'=4K\)
So, new elastic potential energy 4 times the initial elastic potential energy.
What is a proton?
A.A particle inside the nucleus that has no charge B.A negative particle inside the nucleus C.A positive particle inside the nucleus D.A negative particle outside the nucleus
Answers
C. A proton is a positively charged particle that is located inside the nucleus of an atom.
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, in terms of time is given by h=−4.9t 2
+286t+311 How high is the rocket after 7 seconds? meters How high was the rocket when it was initially launched? meters Question Help: □ Message instructor
Answers
The rocket's height when it was initially launched is 311 meters above sea level.
The rocket's height, in meters above sea level, is described by the equation h = -4.9t^2 + 286t + 311. To determine the rocket's height after 7 seconds, we substitute t = 7 into the equation and solve for h. Additionally, to find the height when the rocket was initially launched, we substitute t = 0 into the equation and calculate h.
To find the rocket's height after 7 seconds, we substitute t = 7 into the equation h = -4.9t^2 + 286t + 311:
h = -4.9(7)^2 + 286(7) + 311
h = -4.9(49) + 2002 + 311
h = -240.1 + 2002 + 311
h = 2072.9 meters
Therefore, the rocket's height after 7 seconds is 2072.9 meters above sea level.
To determine the height when the rocket was initially launched, we substitute t = 0 into the equation:
h = -4.9(0)^2 + 286(0) + 311
h = 0 + 0 + 311
h = 311 meters
Hence, the rocket's height when it was initially launched is 311 meters above sea level.
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A ball is thrown into the air at an angle of 50 from the horizontal with an initial velocity of 12 m/s. Calculate both of the steps in the solution: 1- The time of the ball's flight in the air 2- The maximum height the ball reaches
Answers
Answer:
\(\begin{gathered} (1)\Rightarrow t=1.8760 \\ (2)\Rightarrow h_{\max }=4.0268m \\ \end{gathered}\)Explanation: A ball is thrown into the air at an angle of 50 degrees with a horizontal, and initial velocity of 12m/s. (i) we to find the total time of the flight, and (ii) maximum height that the ball reaches
(i) Total flight time:
To find the total time, we much keep in mind that it is the time that the bill would take to reach the same height level as its starting height, the equation that will be used is as follows:
\(\begin{gathered} y(t)=y_o+v_o\sin (\theta)t-\frac{1}{2}gt^2\Rightarrow(1) \\ y_o=0 \\ v_o=12ms^{-1} \\ g=9.8ms^{-2} \end{gathered}\)By setting equation (1) equal to zero and solving for the "t" , the total flight time can be solved, it can be done as follows:
\(\begin{gathered} y_o+v_o\sin (\theta)t-\frac{1}{2}gt^2=0 \\ \therefore\rightarrow \\ 0+(12ms^{-2})\sin (50)t-\frac{1}{2}(9.8ms^{-2})t^2=0 \\ \therefore\rightarrow \\ (12ms^{-2})\sin (50)t=\frac{1}{2}(9.8ms^{-2})t^2\Rightarrow t=\frac{(2)(12ms^{-2})\sin(50)}{(9.8ms^{-2})} \\ t=\frac{(2)(12ms^{-2})(0.76604444)}{(9.8ms^{-2})}=1.8760s \\ t=1.8760 \end{gathered}\)(ii) Maximum height of the ball:
The maximum height that the ball can reach would be attained in half of the total flight time, therefore we need to simply find the y(t) at half of the total flight time, this is done as follows:
\(\begin{gathered} t_{h_{}}=\frac{t}{2}\Rightarrow t_{h_{}}=\frac{1.8760}{2}=0.938s \\ t_{h_{}}=\text{ }0.938s \\ \therefore\rightarrow \\ y(t_{h_{}}=\text{ }0.938s)=(12ms^{-2})\sin (50)(0.938s)-\frac{1}{2}(9.8ms^{-2})(0.938s)^2 \\ y(t_{h_{}}=\text{ }0.938s)=(12ms^{-2})(0.76604444)(0.938s)-\frac{1}{2}(9.8ms^{-2})(0.938s)^2 \\ y(t_{h_{}}=\text{ }0.938s)=8.623-4.5962=4.0268m \\ y(t_{h_{}}=\text{ }0.938s)=h_{\max } \\ \therefore\rightarrow \\ h_{\max }=4.0268m \end{gathered}\)Imagine driving down the road and you suddenly doubled your velocity. What then happens to your overall kinetic energy?
it is halved
it remains unaffected
it is doubled
it is quadrupled
Answers
How many grams of oxygen would there be in 8.00 g of KClO3?
Answers
Answer:
6.266829864 g
Explanation:
10 Claims · Evidence · Reasoning Suppose
that 273 g of one of the substances listed
above displaces 26 mL of water. What is the
substance? Explain your reasoning.
Answers
From the table shown we can see that the substance that has a density of 10.50g/cm³ is Silver. Hence the required substance is silver
Density is the ratio of the mass of an object to its volume. Mathematically,
Density = Mass/Volume
Given the following from the question
Mass = 273g
Volume of water = 26mL
Convert the volume to cm³
1ml = 1cm³ Hence;
26mL = 26cm³
Get the density of the object
Density = 273g/26cm³
Density = 10.50g/cm³
Hence the required density is 10.50cm³. From the table shown we can see that the substance that has a density of 10.50g/cm³ is Silver. Hence the required substance is silver
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A box is raised at constant speed by a man pulling up on a rope. Assume that air resistance on the box is negligible. During the ascent, which of these statements are true? a. The work performed by all conservative forces on the box is 0. b. The work performed by all non-conservative forces on the box is 0.
c. The net work performed on the box is 0. d. The work performed by all conservative forces on the box is positive.
e. The work perfomed by all non-conservative forces on the box is positive.
Answers
During the constant-speed ascent of a box pulled up by a man with negligible air resistance, the work performed by conservative forces on the box is zero, and the net work performed on the box is also zero.
When the box is raised at a constant speed, the force applied by the man pulling the rope is equal in magnitude but opposite in direction to the gravitational force acting on the box. Since the box moves with constant speed, the net force acting on it is zero.
The work done by a force is given by the product of the force and the displacement of the object in the direction of the force. In this case, the displacement is upward, while the gravitational force and the force applied by the man are in the opposite direction. Therefore, the work performed by the conservative forces, which include the gravitational force, is zero.
Similarly, since the box moves with constant speed, there is no change in its kinetic energy, and hence the work performed by non-conservative forces, such as friction, is also zero. Thus, both statements a and b are true. The net work performed on the box is zero because the work done by the conservative forces cancels out the work done by the non-conservative forces.
Overall, the work-energy theorem states that the work done on an object is equal to its change in kinetic energy. In this case, as the box moves with constant speed, there is no change in kinetic energy, so the net work performed on the box is zero.
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Q9. Two points P and Q on a progressive wave are separated by distance d. The phase difference between P and Q is rad. What is the wavelength?
Answers
Two points P and Q on a progressive wave are separated by distance d. The phase difference between P and Q is rad. The wavelength of the wave would be 8 times the distance between points P and Q.
In a progressive wave, the phase difference between two points is related to the wavelength of the wave. To find the wavelength (λ) given the phase difference (ϕ) and the distance (d) between two points, we can use the formula:
ϕ = 2π(d/λ)
Rearranging the equation to solve for λ, we have:
λ = (2πd) / ϕ
In this case, the phase difference between points P and Q is given as ϕ radians. The distance between these points is denoted by d. By substituting these values into the equation, we can determine the wavelength of the wave.
It's important to note that the phase difference is typically measured in radians, and one complete wave cycle corresponds to 2π radians.
For example, let's say the phase difference between points P and Q is π/4 radians, and the distance between them is d. Using the formula above, the wavelength would be:
λ = (2πd) / (π/4)
λ = (8πd) / π
λ = 8d
This calculation demonstrates how the phase difference and distance between points on a wave are related to the wavelength. By knowing the phase difference and distance, we can determine the wavelength of the wave using the formula derived from the wave's periodic nature.
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1. Do you think your memories can be altered? Explain
Answers
Answer:
Yes
Explanation:
I think our memories can be altered by emotions. If someone tells you something over and over and over again with strong emotion you will start to remember that more than the memory.
Emotions are very powerful and if you feel a certain emotion connected with a different memory I think that is stronger and can trick your brain into thinking that is the memory because of the strong emotion, even though the true memory was right, since it might not have as strong of mental emotion your brain will think that is the false memory because whatever is more memorable your brain will remember.
If that makes any sense,
A beam of light of which of the following pure colors is made up of photons of the lowest energy?
Select one:
A. Blue
B. Green
C. Red
D. Yellow
Answers
The answer to your question is red. A beam of light made up of pure red color consists of photons with the lowest energy. This is because the energy of a photon is inversely proportional to its wavelength, and red light has the longest wavelength of all the colors in the visible spectrum.
As a result, photons of red light have the lowest energy. On the other hand, blue light has the shortest wavelength and therefore has photons with the highest energy. It is important to note that the energy of a photon increases as the frequency of the light increases. So, while red light has the lowest energy in the visible spectrum, ultraviolet and gamma rays have much higher energy than blue light.
In summary, red light is made up of photons with the lowest energy, followed by green, yellow, and blue light in increasing order of energy.
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consider the following. x = t ln(t), y = t − ln(t) dy dx = d2y dx2 = for which values of t is the curve concave upward? (enter your answer using interval notation.)
Answers
To determine the interval where the curve y = t − ln(t) is concave upward, the second derivative was calculated and solved for positivity. The resulting interval is (0,1) U (e, ∞).
We have:
y = t − ln(t)
x = t ln(t)
Differentiating y with respect to x, we get:
dy/dx = (dy/dt) / (dx/dt)
Using the chain rule, we get:
dy/dx = (1 - 1/t) / ln(t)
Differentiating again with respect to x, we get:
d²ʸ/dx² = d/dx[(1 - 1/t) / ln(t)]
Using the quotient rule and simplifying, we get:
d²ʸ/dx² = -1 / (t² ln(t)²)
For the curve to be concave upward, we need d²ʸ/dx² to be positive. Therefore, we need:
-1 / (t² ln(t)²) > 0
Solving for t, we get:
0 < t < 1
t > e
Therefore, the curve is concave upward for t ∈ (0,1) U (e, ∞).
In interval notation, the answer is: (0,1) U (e, ∞).
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2
A simple circuit contains a battery and a resistor.
Over 3.0 hours, 29 000 C of charge passes through the resistor.
Calculate the current flowing through the circuit during this time.
Give your answer to two significant figures.
Answers
Answer:
Approximately \(2.69\; {\rm A}\).
Explanation:
Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:
\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).
Electric current \(I\) is the rate of flow of electric charge.
In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:
\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).
a space vehicle travels at (about ) relative to the earth. how much time will its clocks gain or lose, as compared to earth- based clocks, in a day?
Answers
The clocks on the space vehicle will gain approximately 0.0031 day or 4.5 minutes per day compared to Earth-based clocks due to time dilation. This means that if the space vehicle travels for a year, its clocks would be ahead of Earth-based clocks by approximately 26 hours.
According to the theory of relativity, time is not absolute and can vary depending on the relative motion of two observers. When an object travels at a high velocity relative to another object, time dilation occurs, which means that time appears to move slower for the moving object. In the case of a space vehicle traveling at a high velocity relative to the Earth, its clocks will appear to move slower than Earth-based clocks.
To calculate the exact amount of time dilation, we need to use the formula:
Δt' = Δt * √(1 - v²/c²)
where Δt' is the time interval measured by the moving clock, Δt is the time interval measured by the stationary clock (Earth-based clock), v is the velocity of the moving clock relative to the stationary clock, and c is the speed of light.
Assuming that the space vehicle is traveling at a velocity of 27,500 km/h, which is about the speed of the International Space Station (ISS), we can calculate the time dilation as follows:
Δt' = Δt * √(1 - v²/c²)
Δt' = 1 day * √(1 - (27,500 km/h)²/(299,792 km/s)²)
Δt' = 1 day * √(1 - 0.0002525)
Δt' = 1 day * √(0.9997475)
Δt' = 0.999873 day or 23.9969 hours
Therefore, the clocks on the space vehicle will gain approximately 0.0031 day or 4.5 minutes per day compared to Earth-based clocks due to time dilation. This means that if the space vehicle travels for a year, its clocks would be ahead of Earth-based clocks by approximately 26 hours.
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A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?
Answers
W=9000*0
W=0
W:Work
F:Force
s:Distance
what parts of earth would the biosphere exclude
Answers
The biosphere includes all the parts of Earth that support life, which includes the atmosphere, hydrosphere (water), and lithosphere (land). However, within these spheres, there are certain regions that are inhospitable to life, such as the polar ice caps, deserts, and deep ocean trenches. The biosphere also includes the living organisms themselves, from bacteria and fungi to plants and animals.
Therefore, the biosphere would not necessarily exclude any specific parts of the Earth, but rather it would encompass all regions that support or can support life in some way. However, certain regions may have lower levels of biodiversity or have specific adaptations for survival, such as the extremophiles found in deep-sea vents or hot springs.
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Explain why the Ray of light is refracted towards the normal
Answers
Light rays bend towards the normal because they slow down when moving from a rarer medium to a denser medium.
How do light rays always refracted towards the normal?The reason behind the refraction of rays of light towards normal is that because slow down when moving from a rarer medium to a denser medium.
If the light rays enter any substance with a higher refractive index (which includes air into glass) then it will slow down. The light always bends towards the ordinary line. If mild travel enters into a substance with a lower refractive index (which includes from water into the air) then it will speed up. Therefore the ray of light always refracted towards the normal.
When the light rays enter from the air into a denser medium like water or glass then the ray of light will refract towards the normal. When light travels from a denser medium into the air, it will refract away from the normal.
So we can conclude that light rays slow down when moving from a rarer medium to a denser medium.
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If you had a converging lens with a focal length of 2.5 cm, where would you place an object in order to have no image created?Question 10 options:At 2.5 cm24 cmBetween the lens and 5 cm Less than 12 cm
Answers
Given that the focal length of the object is F = 2.5 cm.
We have to find the position of the object such that no image is formed.
For a convex lens, the image will not be formed if it is placed at the focus.
Thus, the object should be placed at 2.5 cm as it is the focal length.
A pring of force contant 120 N/m i acted up by a contant force of 240n. Calculate the elatic potential tored in the pring
Answers
A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.
The elastic potential energy stored in the spring is formulated as follows
PE = ½kx²
Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.
In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:
F = kx
Where F is the force acting on the spring, x is the displacement, and k is the force constant,
So that:
F = kx
240 N = 120 N/m . x
x = 240 N/120 N/m
x = 2 m
Once x is known, then we can calculate the potential energy of the spring:
PE = ½kx²
PE = ½ (120) (2²)
PE = 60 x 40
PE = 240 Nm
So, the elastic potential energy stored in the spring is 240 Nm.
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pls answer this i need it
Answers
Answer:
timothy 50
jovanniel 80
PJ 100
Explanation:
tras me
an old streetcar rounds a flat corner of radius 8.0 m, at 13 km/h. what angle with the vertical will be made by the loosely hanging hand straps?
Answers
Angle with the vertical will be made by the loosely hanging hand straps is 13 degrees.
A string attached to an object can also exert a force but only if the string is pulled taut, and only in the direction of the string. This force is called tension.
We usually make the approximation that the string is massless and unstretchable, so we don’t need to worry about it sagging in the middle or about its length changing, our strings which we consider in questions are also usually unbreakable.
The force transmitted through a string, rope, cable, or wire that is pulled tight. The rope pulls with a tension force on both objects.
For examples, A box hangs from the ceiling by a cable. The cable exerts an upward tension force on the box. A dog is pulled by a dog chain. The chain exerts a force upon the dog.
Given,
V=13km/h = 4.4 m/s
TsinФ = mv^2/R------(1)
TcosФ = mg-------(2)
Divide (1) by (2)
tanФ = v^2/Rg
Ф = tan ^-1(4.4*4.4)/8.50*9.80
Ф = 13 degrees.
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Which statement correctly compares sound and light waves?
O Both light and sound waves need matter to carry energy from one place to another.
Neither light nor sound waves need matter to carry energy from one place to another.
O Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it.
Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
Answers
Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
What is the correct comparison of light and sound?We know that light is electromagnetic wave and also we have to know that light is a transverse wave. The implication of that is that the direction of the wave motion is parallel to that of the disturbance that is causing the wave.
Light waves have higher intensity than sound waves and can cause more damage. The human eye is much more sensitive to light than the human ear is to sound.
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Answer:
D is the answer
Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
Explanation:
Ice at 0. 0∘c has a density of 917 kg/m3. a 3. 00 cm3 ice cube is gently released inside a small container filled with oil and is observed to be neutrally buoyant. what is the density of the oil, rhooil?
Answers
The density of the oil is 917kg/ m³.
An object is said to be naturally buoyant when ithas the tendency to float in a fluid.
from the law of floating when a body float in a liquid,the weight of the liquid displaced by its immersed part is equal to the total weight of body.
That is
weight (w)=upthrust (u)
w=u
therefore
u=Dvg
where, D= density of the ice
v= volume of ice
g= acceleration due to gravity
from the question
given:
D = 917kg/m {}^{3} \)
v = 3.00cm {}^{3} \)
g = 9.8m/s {}^{2} \)
substitute these values in above equation
u = 917(3 \times 10 {}^{ - 6} )(9.8)\)
u=0.027N
but,
upthrust= weight of oil displaced.And the ice will displaced an amount of oil,equal to its own weight.
therefore,
density of oil = u/gv = (0.027)/3 \times 10 {}^{ - 6)} (9.8)\)
density of oil = 917kg/m {}^{3} \)
hence the density of the oil is 917kg/m {}^{3} \)
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A light wave traveling through glass strikes the boundary with a second medium at a 45° angle and then refracts away from the boundary. What could the second medium be? A. Glass B. Diamond C. Water D. Air
Answers
The material with the lowest refractive index is air. The correct option is D. Air.
What is light wave ?Light waves are a type of electromagnetic wave that travel through space at the speed of light.
In this case, the light wave is traveling through glass and then strikes the boundary with a second medium at a 45° angle, refracting away from the boundary. For the light wave to refract away from the boundary, the second medium must have a lower refractive index than glass.
Out of the options given, the material with the lowest refractive index is air. Therefore, the correct answer is D. Air.
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The Boston Tea Party was an act of civil disobedience by those who believed the Crown to be abusing its power to do what?
Answers
They were upset because the British were taxing them without any represeetatio in paliatment.
After t seconds the displacement, s(t), of a particle moving rightwards along the x-axis is given (in feet) by s(t) = 5t^2 − 7t + 2 . Determine the average velocity of the particle over the time interval [1, 2]. 1. average vel. = 6 ft/sec 2. average vel. = 5 ft/sec 3. average vel. = 8 ft/sec 4. average vel. = 7 ft/sec 5. average vel. = 4 ft/sec
Answers
the average velocity is given by the change in displacement divided by the change in time: average velocity = (change in displacement) / (change in time) = 8 ft / 1 sec = 8 ft/sec.
To determine the average velocity of the particle over the time interval [1, 2], we need to find the change in displacement and divide it by the change in time.
Given that the displacement function is s(t) = 5t^2 - 7t + 2, we can find the displacement at the endpoints of the interval:
s(1) = 5(1)^2 - 7(1) + 2 = 5 - 7 + 2 = 0
s(2) = 5(2)^2 - 7(2) + 2 = 20 - 14 + 2 = 8
The change in displacement is s(2) - s(1) = 8 - 0 = 8 feet.
The change in time is 2 - 1 = 1 second.
Therefore, the average velocity is given by the change in displacement divided by the change in time:
average velocity = (change in displacement) / (change in time) = 8 ft / 1 sec = 8 ft/sec.
Therefore, the correct answer is 3. average vel. = 8 ft/sec.
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someone help me plz
Answers
Answer:
Aerobic exercise includes?
(C) All activities that make you tired and short of breathe.
2. Which choice is an intense exercise that involve short burst of activity in which the muscles worked so hard that they produce energy without using energy?
(B) anaerobic exercise
Explanation:
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answers
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?
Answers
By Newton's second law, the car slows down with an average acceleration a such that
-7100 N = (1500 kg) a ⇒ a ≈ -4.7 m/s²
If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that
0² - (25 m/s)² = 2a ∆x ⇒ ∆x ≈ 66 m
The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The acceleration is found as;
F=ma
-7100 N = (1500 kg) a
a= -4.7 m/s²
If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;
v²=u²+2as
v²-u²=2as
0² - (25 m/s)² =2×(-4.7) s
s=66 m
Hence,the car slide before it comes to rest will be 66 m.
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