The sound wave has a frequency of 426 Hz. What is the period? What is the wavelength?​

Answer:

because I dont know

Explanation:

first you add the multiply

The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

Instantaneous velocity = Position with respect to time / Time

1 ) At d = 60 m, the instantaneous velocity is zero because the car is at rest.

2 ) At d = - 40 m, t = 40 s

Instantaneous velocity = - 40 / 40

Instantaneous velocity = - 1 m / s

3 ) At t = 15 s, d = 60 m

At 60 m, the car is at rest, so the Instantaneous velocity is zero

4 ) At t = 25 s, d = 20 m

Instantaneous velocity = 20 / 25

Instantaneous velocity = 0.8 m / s

Instantaneous velocity of a given curve in a position-time graph can be found by drawing a tangent to the curve and finding the slope of the tangent. Instantaneous velocity = 0

Instantaneous velocity = - 1 m / s

Instantaneous velocity = 0

Instantaneous velocity = 0.8 m / s

Therefore, The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

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Answer:

x = 1.1*10^-7 m

Explanation:

You can consider that the electron travels in the horizontal positive x direction. Furthermore, you can consider that the electric field between the plates is totally vertical and points upward (which means that the negative plates is above the line of motion of the proton).

In order to calculate the vertical distance traveled by the electron when it has passed the region between the plates, you take into account the acceleration experienced by the proton, due to the electric field between the plates.

You first calculate the electric field between the plates, by using the following formula:

\(E=\frac{\sigma}{\epsilon_o}\)        (1)

σ: surface charge density of each plate = ±1.0*10^6 C/m^2

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

You replace the values of the parameters in the equation (1):

\(E=\frac{1.0*10^6C/m^2}{8.85*10^{-12}C^2/Nm}=1.12*10^{17}\frac{N}{C}\)

Next, you calculate the acceleration of the electron produced by the electric force. You use the second Newton law for the electric force:

\(F_e=qE=ma\)       (2)

q: charge of the electron = 1.6*10^-19C

m: mass of the proton = 1.67*10^-27 kg

You solve the equation (2) for a:

\(a=\frac{qE}{m}=\frac{(1.6*10^{-19})(1.12*10^{17}N/C)}{1.67*10^{-27}kg}\\\\a=1.07*10^{25}\frac{m}{s^2}\)

Next, you calculate the time that proton takes to reach the negative capacitor. You use the following formula:

\(y=v_{oy}t+\frac{1}{2}at^2\)     (3)

y: vertical distance from the center of the capacitor to the negative plate = 3.5cm/2 = 1.75cm = 0.0175m

voy: vertical initial speed of the proton = 0m/s (the proton enter to the region of electric field horizontally)

You solve the equation (3) for t:

\(y=\frac{1}{2}at^2\\\\t=\sqrt{\frac{2y}{a}}=\sqrt{\frac{2(0.0175m)}{1.05*10^{25}m/s^2}}=5.77*10^{-14}s\)

Next, you calculate the horizontal distance traveled by the proton in the time calculated. You use the following formula:

\(x=v_ot\)         (4)

x: length of the capacitor = 3.5cm = 0.035m

vo: initial speed of the proton = 1.9*10^6 m/s

\(x=(1.9*10^6m/s)(5.77*10^{-14}s)=1.1*10^{-7}m\)

The horizontal distance traveld by the electron when it impacts the negative plate of teh capacitor is 1.1*10^-7m

Answer:

Explanation:

a) F = ma

a = F/m

a = 9(800) / 1 x 10⁹ = 7.2 x 10⁻⁶ m/s

b) t = v/a

t = 200 / 7.2 x 10⁻⁶

t = 2.8 x 10⁷ s       about 10½ months

c) v² = u² + 2as

s = (v² - u²) / 2a

s = (200² - 0²) / (2( 7.2 x 10⁻⁶))

s = 2.8 x 10⁹ m    nearly 7 times around the earth

And all this assumes NO FRICTION.

A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².

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Answer:

im going between 2 of them b and c but i would have choose b

Answer:

A. the motion of an object along a curved path

Answer:

Refraction involves passing through a boundary (choice a) and changing speed (choice ... A ray of light in air is incident on an air-to-glass boundary at an angle of 30. ... If the index of refraction of the glass is 1.65, what is the angle of the refracted ray ... The critical angle is the angle of incidence (which is always in the more ...

Explanation:

Answer:

because the book's is covered by papers

In this case, the force is 23 N, and the distance is 4.2 m. Therefore, the work required is 97.6 joules (J).

Joules is a unit of energy. It is a derived unit of the International System of Units (SI) and is used to measure energy, work, or the amount of heat generated or absorbed. It is typically used to measure energy in various forms, such as the kinetic energy of a moving object, the energy of a wave, or the energy stored in an electric field or a magnetic field. In the SI, one joule is equal to the energy expended by a force of one newton when its point of application moves one meter in the direction of the force. The joule is also a unit of energy in many other systems of measurement, including the British thermal unit (BTU), the calorie, and the watt hour.

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Widening the prism adds additional glass, which slows light down even further and increases the amount of refraction.

The angles and plane sides of a prism cause light to be bent, or refracted, when it flows through them; the degree of refractive distortion varies somewhat depending on the wavelength of light.

When light travels from the air to the prism's glass, its speed changes, causing the light to bend and shift course. Once light enters the prism, it bends because the refraction indices of the air and glass differ. The light exits the prism bent even more since the sides are slanted.

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Answer: 0.25A

Explanation: To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the total resistance of the circuit is the sum of the individual resistances of the three bulbs in series, which gives us:

R = 2 + 2 + 2 = 6 ohms

The voltage of the battery is given as 1.5V.

So, using Ohm's Law, we can calculate the current in the circuit as:

I = V / R = 1.5 / 6 = 0.25 amps

Therefore, the current in the circuit is 0.25 amps.

The current in the circuit is 0.25 A.

Voltage across the circuit, v = 1.5 V

Resistance in each resistors, R = 2Ω

Since, the resistors are connected in series combination, their effective resistance,

R' = 3R

R' = 3 x 2

R' = 6Ω

According to Ohm's law, if the temperature and all other physical factors remain constant, the voltage across a conductor is directly proportional to the current that is flowing through it.

So, according to Ohm's law,

V = IR

Therefore, current flowing through the given circuit,

I = V/R

I = 1.5/6
I = 0.25 A

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Answer:

the magnitude F of the total friction force is 2456.7 lb

Explanation:

Given the data in the question;

maximum speed = 35 mi/hr = ( 35×5280 / 60×60) = 51.3333 ft/s

diameter = 200ft

radius = 200/2 = 100 ft

First we calculate the normal component of the acceleration;

\(a_{n}\) = v² / p

where v is the velocity of the car( 51.3333 ft/s)

p is the radius of the curvature( 100 ft)

so we substitute

\(a_{n}\) = (51.3333 ft/s)² / 100ft

\(a_{n}\) = (2635.1076 ft²/s²) / 100ft

\(a_{n}\) = 26.35 ft/s²

we convert Feet Per Second Squared (ft/s²) to Standard Gravity (g)

1 ft/s² = 0.0310809502 g

\(a_{n}\) = 26.35 ft/s² × 0.0310809502 g

\(a_{n}\) =  0.8189g

Now consider the dynamic equilibrium of forces in the Normal Direction;

∑\(F_{n}\) = m\(a_{n}\)

F = m\(a_{n}\)

we know that mass of the car is 3000-lb =  3000lb(\(\frac{1}{g}slug\)/1 lb)

so

we substitute

F =  3000lb(\(\frac{1}{g}slug\)/1 lb)  × 0.8189g

F = 2456.7 lb

Therefore; the magnitude F of the total friction force is 2456.7 lb

Answer: 3m

Explanation: If he is already 2m away from the mirror then if he walks away 1m then it would equal out to 3. You could also add 1 to 2 so you could get the same results.

Answer:

D because the line isn't changing which means constant speed it's going at the same rate so yea it's D

Answer:

D.

Hope that helps!?

Explanation:

Answer:

No se pregunta a alguien mas carnalito.

Explanation:

Lo siento:(

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Researching information

Explanation: Edge 2020

hope this helps :3. pls mark me brainiest Brainliest

Answer:

It is C.

Explanation:

Got it right on edge.

Statement A. The sun is located at one focus is true about the foci of a planet in an elliptical orbit (option A).

An elliptical orbit can be defined as any movement of a celestial body in which the attained object (for example a planet around its star) moves in an eccentric manner or oval-shaped way, which is a feature of the planets in the solar systems including the Earth planet.

The movement of a planet in an elliptical orbit is called an ellipse, while two points that are selected chosen at the start site are known as foci in such orbits.

Therefore, with this data, we can see that an elliptical orbit is an excentric movement of a celestial body such as the earth's planet around the sun, and foci are called to fixed points located inside this orbit.

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a higher energy than an electron near the nucleus

In an electron cloud, an electron that is farther away from the nucleus has a higher energy than an electron near the nucleus. Thus, the correct option is C.

An electron cloud is the region which is surrounding an atomic nucleus in which there is a very high probability of an electron being located in an atom. The probability of finding an electron is greater than the more dense regions of the electron cloud in the atom.

One way in which the elements differ from each other is the structure of the electron cloud in each of the element's atoms in an electron cloud and the electrons which is farther from the nucleus has a higher energy than an electron near the nucleus of the atom.

Therefore, the correct option is C.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Answer:

60 ohms

Explanation:

To find the equivalent resistance of two resistors R₁ and R₂ in parallel, we can use the formula:

1/Req = 1/R₁ + 1/R₂

where Req is the equivalent resistance.

Substituting the values given, we get:

1/Req = 1/30 + 1/20

Simplifying, we get:

1/Req = 1/60

Multiplying both sides by Req, we get:

Req = 60 ohms

Therefore, the equivalent resistance of the two resistors R₁ and R₂ in parallel is 60 ohms.

It follows from Newton's second law that there is some counteractive force that cancels out the force exerted by the engine - it's most likely drag due to air resistance in combination with static friction between the tires and the road. The car is moving at constant speed past a certain point, so the net force on the car is

∑ F = (force from engine) - (resistive forces) = 0

given data

the mass of a hoop with a radius of 1.0m is 6.0kg.

it rolls across a horizontal surface with a speed of 10.0m/s

we know that,

Total energy of the hoop=Translational Kinetic energy+ Rotational Kinetic energy=21mv2+21Iω2

For hoop, I=mr2

Also v= r ω

Thus total energy=21mv2+21mr2(r v)2=mv2

Hence the work required to stop the hoop=Its total energy=mv2=100×0.1J=1J

1JOULE work is required stop to hoop.

What is translational energy?

translational energy (plural translational energies) (physics) The energy of the molecules of a fluid due to motion (translation rather than rotation or vibration).

What is an example of translational kinetic energy?

A train moving along a railroad track, an object in free fall due to gravity, a car driving on a road, the motion of a bullet fired from a gun, or the expansion of a galaxy are examples of translational kinetic energy.

rotational energy

Rotational energy, or angular kinetic energy, is the kinetic energy due to the rotation of an object and is a fraction of its total kinetic energy.

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Answer: B im sorry if its wrong

Explanation:

Answer:

    x₁ = 3.481 m

Explanation:

In this exercise the acceleration of the dog and the sled are given, for which we can use the kinematic relations.

Let's start by fixing a reference system located on the sled and suppose that it moves to the right, the sled acceleration a₁ = 0.2 m / s, the dog is on the other side of the rope, so if the acceleration is a₂ = -0.5 m / s2, the negative sign indicates that it is moving to the left.

The initial position of the sled is x₁₀ = 0 and the initial position of the dog is x₂₀ = 12.2 m, let's write the expressions for the position

            x₁ = x₁₀ + v₁₀ t + ½ a₁ t²

            x₂ = x₂₀ + v₂₀ t + ½ a₂ t²

in this case the two bodies start from rest so their initial velocities are zero

we substitute the values

           x₁ = 0 + 0 + ½ (0.2) t²

           x₂ = 12.2 + 0 + ½ (-0.5) t²

at the point where the two meet, the position is the same

           x₁ = x₂

          ½ 0.2 t² = 12.2 - ½ 0.5 t²

          (0.1 + 0.25) t² = 12.2

                t = \(\sqrt{ \frac{12.2}{0.35} }\)

                t = 5.9 s

we look for the position of the sled (subscript 1)

            x₁ = ½  0.2  5.9²

            x₁ = 3.481 m

Answer:

The centripetal acceleration of the car will be 12.32 m/s² .

Explanation:

Given that

radius ,R= 57 m

Velocity , V=26.5 m/s

We know that centripetal acceleration given as follows

\(a_c=\dfrac{V^2}{R}\)

Now by putting the values in the above equation we get

\(a_c=\dfrac{26.5^2}{57}=12.32\ m/s^2\)

Therefore the centripetal acceleration of the car will be 12.32 m/s² .

The acceleration of the mass in terms of {m} is -

a = 2F/m.

The force acting on a body is given by -

Force {F} = mass {m} x acceleration {a}

Given is that a net force of {F} is applied to half the mass {m/2}.

We know that -

Force {F} = mass {m} x acceleration {a}

F = {m/2} x a

a = 2F/m

Therefore, the acceleration of the mass in terms of {m} is -

a = 2F/m.

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Black is not a color, but rather a shade. In color theory, a shade is a pure color mixed with black. It decreases its lightness while nearly conserving its chromaticity. Strictly speaking, a "shade of black" is always a pure black itself and a "tint of black" would be a neutral gray. Unlike these, many off-black colors possess a hue and a colorfulness (also called saturation).

Attached is an image showing a few of the different shades of black.

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

The answer is "no" because black is not made of all colors, in fact black is not a color, but black is the absence of light.

Light is an electromagnetic radiation which can be recognized by the human eye. Electromagnetic radiation occurs at a wide variety of wavelengths, from cosmic rays with wavelengths smaller than around 1 1011 meters to radio waves estimated in meters.

Within that large spectrum, the colors visible to humans comprise a relatively small band, ranging from around 700 nanometers for red light to roughly 400 nm for violet light. The spectral areas close to the visible band are also referred to as light, with infrared at one side and ultraviolet the other.

The absence or full assimilation of visible light produces the color black. It is an anamorphic lens color with no tint, similar to white and gray. It is frequently used symbolically or colloquially to denote darkness.

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