Temperature is change by 1.0201 times if rms speed of a gas is increased by 1% and pressure of gas remains same as volume is held constant.
The root-mean-square speed is fundamental in estimating the typical speed of particles contained in a gas, characterized as \(v_r_m_s\)=√3RT/M.
In Motor Sub-atomic Hypothesis, gasified particles are in a state of steady irregular movement; every molecule moves at something else entirely, unendingly conflicting and taking a different path reliably speed is utilized to depict the development of gas particles, in this way considering both speed and course.
Albeit the speed of vaporous particles is continually changing, the circulation of speeds doesn't change. We can't measure the speed of each and every individual molecule, accordingly we much of the time reason regarding the particles' typical way of behaving.
\(v_r_m_s\)=√3RT/M.
Squaring on both sides,we get
=>\(v_r_m_s\)²=3RT/M
=>T₁= (\(v_r_m_s^{2}\) )×M/3R------------(eq1)
Now,when \(v_r_m_s^{2}\) is increased by 1%,in that case
[v\(_r_m_s\)+(1× \(v_r_m_s\))/100] =√3RT/M.
=>(101 × \(v_r_m_s\) /100)=√3RT/M.
Squaring on both side,we get
=>(101 × \(v_r_m_s\)/100)²=3RT/M
=>T=(101 × \(v_r_m_s\)/100)²/3RM
=>T=(101/100)²×( \(v_r_m_s\)/3RM)²
=>T=(1.01×1.01)T₁ (from eq1)
=>T=1.0201T₁
Now, on comparing with the given temperature we got that new temperature will become 1.0201 times of original temperature.
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What is the acceleration of gravity on Venus?
Answer:
8.87 m/s^2
Explanation:
A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?
The horizontal distance travelled by the football is 3.1 m.
What is the angle of projection of the ball?
The angle of projection of the football is calculated as follows;
tan ( θ ) = Vy / Vx
where;
Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal directiontan ( θ ) = 5 / 3
tan ( θ ) = 1.667
θ = arc tan (1.667)
θ = 59⁰
The resultant velocity of the ball is calculated as follows;
v = √ (Vx² + Vy²)
v = √ (3² + 5²)
v = 5.83 m/s
The horizontal distance travelled by the football is calculated as follows;
x = v² sin(2θ) /g
where;
v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ballx = [ (5.83)² sin(2 x 59) /9.8 ]
x = 3.1 m
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29.In which of the following pictures is the average kinetic energy of molecules the highest?Select one:a. Ab. Bc. Cd. D
We will have that the picture that shows the highest average kinetic energy is image B.
a reaction occurs in which carbon combines with sulfur to form carbon disulfide is this a chemical reaction or a nuclear reaction and how do you know
Answer:
a chemical reaction where electrons mix.
Explanation:
A nuclear reaction is when atomic nuclei combine, forming a new chemical element
A chemical reaction occurs when electrons from the last layer of atoms mix, forming molecules that have the same chemical elements as the reactants.
According to these definitions
C + 2 S → CS2
in a chemical reaction where electrons mix.
Answer:
This is a chemical reaction, because only the electrons were rearranged.
HELP PLZ HELP !!!!!!!!!!!
Answer:
From least to greatest: Neon, Sodium, Silicon, Iron, Uranium
Explanation:
Here are all the atomic numbers for each one:
Iron = 26
Sodium = 11
Uranium = 92
Neon = 10
Silicon = 14
Hope this helps! :D
Can someone please help me with this?? It's due in an hour and I've been stuck on it!
I've gotten the first three of all of them done, but I am stuck on the last two. You can probably look them up.
[Part One]
Mercury:
1. What shape is the orbit of Mercury?
2. Why do you think the Sun is not at the center of Mercury’s orbit?
3. What did you notice about the motion of Mercury in its orbit?
Click on each highlighted section and record the area. What do you notice about each area?
4. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
Earth:
1. What is the orbit of the Earth?
2. Is the Sun at the center of the Earth’s orbit?
3. Describe the motion of the Earth throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
Mars:
1. What is the orbit of the Mars?
2. Is the Sun at the center of the Mars’s orbit?
3. Describe the motion of Mars throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
[Part Two]
Saturn:
1. What is the orbit of the Saturn?
2. Is the Sun at the center of the Saturn’s orbit?
3. Describe the motion of Saturn throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
Neptune
1. What is the orbit of the Neptune?
2. Is the Sun at the center of the Nepturn’s orbit?
3. Describe the motion of Neptune throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
Comet
1. What is the orbit of the comet?
2. Is the Sun at the center of the comet’s orbit?
3. Describe the motion of the comet throughout its orbit? Does it move at constant speed?
4. Click on each highlighted section and record the area. What do you notice about each area?
5. Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
Answer:
Earth:1. What is the orbit of the Earth?
365 days
2. Is the Sun at the center of the Earth’s orbit?
Yes
3. Describe the motion of the Earth throughout its orbit? Does it move at constant speed?
Yes, the Earth moves pretty quickly and orbits around the Sun at a rate of approximately 67,000 miles per hour.
Mars:1. What is the orbit of Mars?
The shape is circular, 687 days
2. Is the Sun at the center of Mars’s orbit?
Yes
3. Describe the motion of Mars throughout its orbit? Does it move at constant speed?
Travels at a regular steady speed, yes moves at a constant speed
Saturn:
1. What is the orbit of Saturn?
Circular, 29 years
2. Is the Sun at the center of Saturn’s orbit?
Yes
3. Describe the motion of Saturn throughout its orbit? Does it move at constant speed?
Just like Mars, it moves faster when it is closer to the sun, so yes.
Neptune:1. What is the orbit of Neptune?
Circular, 165 years
2. Is the Sun at the center of Nepturn’s orbit?
Yes
3. Describe the motion of Neptune throughout its orbit? Does it move at constant speed?
A steady consistent speed and yes it moves at a constant speed.
Comet:1. What is the orbit of the comet?
An oval, 200 years
2. Is the Sun at the center of the comet’s orbit?
No
3. Describe the motion of the comet throughout its orbit? Does it move at constant speed?
A comet starts off slow then picks up speed and no it does not move at a constant speed.
Explanation:
I hope this helps, You're welcome.
Write a set of turtle instructions to draw an AND gate.
The turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
To draw an AND gate using turtle graphics, you can use the following set of instructions:
Set up the turtle:
a. Set the turtle's initial position.
b. Set the turtle's pen color and size.
Draw the first input line:
a. Move the turtle forward to the starting point of the line.
b. Draw a straight line segment to represent the first input.
Draw the second input line:
a. Move the turtle to the starting point of the second line.
b. Draw a straight line segment to represent the second input.
Draw the output line:
a. Move the turtle to the starting point of the output line.
b. Draw a straight line segment to represent the output.
Draw the logic gate shape:
a. Move the turtle to the starting point of the gate.
b. Draw a rectangle to represent the gate.
c. Add any necessary labels or symbols to indicate it as an AND gate.
Add connections between lines and gate:
a. Move the turtle to the intersection point of the first input line and the gate.
b. Draw a small line segment to connect the input line to the gate.
c. Repeat the above step for the second input line and the gate.
d. Draw a small line segment to connect the output line to the gate.
Repeat the above steps as necessary to draw multiple AND gates or any additional components.
Remember to adjust the turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
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A ball has an initial velocity of 4m/s and a final velocity of 16m/s. The ball travels a distance of 25m. What is the acceleration of the ball? Give your answer to 2 decimal places.
The acceleration of the ball which experiences an initial velocity of 4m/s and a final velocity of 16m/s and covers a distance of 25 m is 4.80 m/s².
What is Acceleration?Acceleration can be defined as the change in the velocity of an object. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second square (m/s²).
The acceleration of the ball can be calculated through initial velocity, final velocity and distance through the equation:
2as = v² - u²
where, a = acceleration of the object,
s = distance covered by the object,
v = final velocity of the object,
u = initial velocity of the object
2 × a × 25 = (16)² - (4)²
50a = 256 - 16
50 a = 240
a = 240/ 50
a = 4.80 m/s²
Therefore, the acceleration of the ball is 4.80 m/s².
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A cheerleader launches a t-shirt from an air gun.The shirt leaves the gun at with a speed of 29m/s.
A. Ignoring air resistance, how long would it take the shirt to reach the top of it arc?
B. Ignoring air resistance, if the cheerleader launches with an intial height of 1.75m, what is the maximum height reached by the shirt?
With the use of vertical motion formula, the shirt will take 3 s to reach the top of its arc. And the maximum height reached is 44.7 m
Motion Under GravityThe motion of an object under is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a cheerleader launches a t-shirt from an air gun. The shirt leaves the gun with a speed of 29 m/s.
A. Ignoring air resistance, the time it will take the shirt to reach the top of its arc can be found by using the equation
v = u - gt
Where
final velocity v = 0 at maximum heightinitial velocity u = 29 m/sacceleration due to gravity g = 9.8 m/s²time t = ?Substitute all the parameters into the equation
0 = 29 - 9.8t
9.8t = 29
t = 29/9.8
t = 2.96 s
t = 3 s approximately
B. Ignoring air resistance, if the cheerleader launches with an initial height of 1.75m, let us first calculate the maximum height reached by the shirt by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = 29² - 2 × 9.8 × H
0 = 841 - 19.6H
19.6H = 841
H = 841/19.6
H = 841/19.6
H = 42.9 m
The maximum height reached = 42.9 + 1.75 = 44.7 m
Therefore, the time taken for the shirt to reach the top of its arc is 3 s and the maximum height reached is 44.7 m
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If Ari's mass is 50 kg, Bari's mass is 70 kg, and Bari's initial jump height is 4 m.
What is Ari's final vertical jump height?
Ari's final vertical jump height is 5.2 m.
What is Ari's final vertical jump height? Ari's final vertical jump height is calculated from the law of conservation of energy as shown below.
P.E ( of Ari ) = P.E ( of Bari )
m1gh1 = m2gh2
where;
m1 is the mass of Arim2 is the mass of Barih1 is the final height of Airh2 is the initial height of Barih1 = ( m2h2 ) / ( m1 )
h1 = ( 70 x 4 ) / ( 50 )
h1 = 5.6 m
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Please help
How does sound move from the source to the receiver? (a slinky moving back and forth)
Answer:
through a chain reaction of particle collisions in a medium.
Explanation:
Help me please if you don’t mind. The question is:
Blaine hit the ball with 50 newtons of force. It accelerated of his bat at 50 meters per second squared. What is the mass of the ball? *
50 points
a baseball player picks up a ball from the back of the field and throws it towards home plate with a speed of 47.9m/s at an agngle of 32.1 degrees above the horizontal. How far does it go before its caught by another player
The distance traveled by the plate before it was caught by another player is 210.71 m.
The given parameters;
initial velocity of the plate, u = 47.9 m/sangle of projection, = 32.1 degreesThe distance traveled by the plate before it was caught by another player is the range of the projectile.
The range of projectile is influenced by;
angle of projectileinitial velocity\(R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{47.9^2 \times sin(2\times 32.1)}{9.8} \\\\R = 210.71 \ m\)
Thus, the distance traveled by the plate before it was caught by another player is 210.71 m.
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A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.
a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.
Answer:
a) Answer: 0.16331 m/s
b) Answer: 8522.66 joules
Explanation:
The final speed is 0.1633 m/s.
When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.
What is momentum?A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.
(a) Given parameter:
Mass of the railroad car, M = 2900 Kg.
Mass of the scrap metal, m= 11750 Kg.
Initial speed of the car, u = 0.0825 m/s.
Initial speed of the scrap metal = 0 m/s.
Final speed of the system, v = ?
Then, initial momentum of the system = initial momentum of the car + initial momentum of the scrap metal .
= (29000×0.825 + 117500×0) kg.m/s.
= 23925 kg.m/s.
Final momentum of the system = total mass of the system× final speed
= (29000 + 117500)× v kg.m/s
= 146500v kg.m/s.
Hence, from principle of conservation of momentum,
initial momentum of the system = Final momentum of the system
⇒ 23925 = 146500v
⇒ v = 0.1633 m/s.
The final speed of the loaded freight car is 0.1633 m/s.
(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.
= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.
= 7915.72 Joule.
Hence, 7915.72 Joule kinetic energy is lost in this process.
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a model house that runs completely on renewable energy uses 2 windmills and 3 solar panels. each windmill generates mmm kilowatt-hours (kwh) of energy per year, and each solar panel generates sss kwh per year. which expressions can we use to describe how many kwh of energy the model house will output in 10 years? choose 2 answers: choose 2 answers:
The model house on remote renewable energy will generate (20mmm + 30sss) kilowatt-hours of energy in 10 years.
Given:
Remote Renewable House= 2 windmills + 3 turbines
1 windmill generate mmm kilowatts-hours in a year
Therefore,
2 windmills will generate,
2×mmm=2mmm kwh in a year
In 10 years, 2 windmills will generate
10×2mmm=20mmm
1 solar panel generate sss kilowatt-hour each in 1 year
3 solar panels will generate yearly
3×sss=3sss
In 10 years, 3 solar panels will generate
10×3sss=30sss
Therefore, the total energy generated in the renewable model house is in 10 years
(20mmm+30sss) kwhr
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A car moves 4 km in an easterly direction and
then turns to move 3 km in a northerly direction.
By means of a graphical approach, find the
resultant displacement of the car.
When the car moves 4km east and then turns 3km north then the resultant displacement of car will be :
5km
Explanation:Here initially the car moves 4km east , that is a straight line towards east direction with a value of 4kms (let the point be A).
then, from the point A it turns 3km towards north direction. here
North and east are perpendicular to one another.
ie, it forms 90° that means it is a right angle.
The displacement of a car is the distance between its initial and final positions.
The displacement is
S = \(\sqrt{3^{2} + 4^{2} }\)
S = \(\sqrt{25}\)
= 5
so the resultant displcement is 5km
the resultant graph is attached below:
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Drag each label to the correct location on the table.
Sort the processes based on the type of energy transfer they involve.
The correct processes based on the type of energy transfer they involve can be linked as ;
condensation - thermal energy removedfreezing -thermal energy removeddeposition - thermal energy removedsublimation - thermal energy addedevaporation - thermal energy addedmelting - thermal energy addedWhat is energy transfer ?Conduction, radiation, and convection are the three different ways that thermal energy is transferred. Only fluids experience the cyclical process of convection.
The total amount of energy in the universe has never changed and will never change because it cannot be created or destroyed.
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A spring has an maximum displacement of 6m and a period of 8s. What is its position as a function of time?
Answer: The position of the spring as a function of time is given by: x(t) = 6 * sin(π/4 * t)
where t is the time in seconds and x(t) is the position of the spring in meters.
Explanation:
The position of a spring as a function of time can be described by a sinusoidal function. The general form of such a function is:
x(t) = A * sin(ωt + φ) + x₀
where:
x(t) is the position of the spring at time t
A is the amplitude of the motion (maximum displacement)
ω is the angular frequency (related to the period T by ω = 2π/T)
φ is the phase angle (determines the starting point of the motion)
x₀ is the equilibrium position of the spring (where it would be at rest)
In this case, we know that the maximum displacement (amplitude) of the spring is 6m and the period T is 8s. Therefore, we can calculate the angular frequency ω as follows:
ω = 2π/T
ω = 2π/8
ω = π/4
We also know that the spring is at its equilibrium position when t = 0 (i.e., x(0) = x₀). Therefore, we can set x₀ to 0.
Finally, we need to determine the phase angle φ. This can be a bit tricky without more information, as there are many possible starting points for the motion that would produce a sinusoidal function with the given amplitude and period. For simplicity, we will assume that the spring is at its maximum displacement (positive direction) when t = 0. This means that the phase angle φ is 0.
Putting all of this together, we get:
x(t) = 6 * sin(π/4 * t)
This is the position of the spring as a function of time. It describes a sinusoidal motion with an amplitude of 6m and a period of 8s. The motion starts at the maximum displacement (positive direction) and oscillates back and forth around the equilibrium position (0).
1600cm of fresh water of density 1g/cm are mixed with 1200 cm of sea water of
density 1.2g/cm'. Determine the density of the mixture..
Answer:
\(\boxed{\mathrm{Density = 1.1 \ g/cm^3}}\)
Explanation:
Volume of fresh water:
Volume = Mass / Density
Volume = 1600/1
\(V_{1}\) = 1600 cm³
Volume of sea water:
Volume = Mass / Density
Volume = 1200/1.2
Volume = 1000 cm³
So,
Total Volume when they are mixed = 1600+1000
Total Volume when they are mixed = 2600 cm³
And,
Total Mass when they are mixed = 1600+1200
Total Mass when they are mixed = 2800 g
Now, Measuring the density of the mixture:
Density = Mass / Volume
Density = 2800/2600
Density = 1.1 g/cm³
Answer:
\(\mathrm{1.086 \: g/cm^3 }\)
Explanation:
Volume of fresh water ⇒ 1600 cm³
Density of fresh water ⇒ 1 g/cm³
Volume of sea water ⇒ 1200 cm³
Density of sea water ⇒ 1.2 g/cm³
\(density=\frac{mass}{volume}\)
\(mass=density \times volume\)
Calculate mass of fresh water.
\(m=1600 \times 1\)
\(m=1600 \: g\)
Calculate the mass of sea water.
\(m=1200 \times 1.2\)
\(m=1440 \: g\)
Find the density of the mixture.
\(density=\frac{mass}{volume}\)
\(\rho = \frac{1600+1440}{1600 + 1200}\)
\(\rho = \frac{3040}{2800}\)
\(\rho= 1.0857...\)
How do the current and coltage readings compare to before the wires were switched. Explain how to interpret them physically?
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An arrow fired horizontally at 44m/s travels 23m horizontally before it hits the ground From what height was it fired?
In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?
Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.
Thermal energy is the energy possesed by a system due to its temperature.
In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.
Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy
ANSWER:
A. Entropy
A stunt bicycle rider goes 39m in 3.0s. How fast is the cyclist riding?
Answer:
Speed of stunt bike rider = 13 meter/ Second
Explanation:
Given:
Distance cover by stunt bike rider = 39 meter
Time taken by stunt bike rider = 3 seconds
Find:
Speed of stunt bike rider
Computation:
Speed = Distance / Time
Speed of stunt bike rider = Distance cover by stunt bike rider / Time taken by stunt bike rider
Speed of stunt bike rider = 39 / 3
Speed of stunt bike rider = 13 meter/ Second
a car travels at 90 km per hour how much distance in metre does the car travel in 25 seconds
Answer:
90000m÷3600s=25m25m×25s=625msan electric dipole with a dipole moment of magnitude p is placed at various orientations in an electric field E that is directed to the left.What orientation of the dipole will result in maximum torque directed into the page?
An electric field with intensity ′E′ is applied to an electrical dipole with dipole moment ′p′. The dipole moves into a place where its axis forms an angle with the electric field.
What is the electric field's direction at point p?Justification: Since electric fields are subject to the of superposition, the overall electromagnetic current of a system typically equal to the total of its individual electric fields. Each charge produces an electric field at pixel Value that is equal in size but moves in the opposite direction.
How should a surface be oriented in an electrostatic potential to allow the most flux to pass through it?The flux through a surface is at its maximum when it is horizontal to field (left panels) and the paddock vector is parallel to a vector, A. When a surface is perpendicular to the field (figure 3d), no field lines intersect it and there is no flux through it.
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The sun has a surface temperature of approximately 5800 k. at what wavelength does the maximum energy radiated by the sun occur?
wavelength at the maximum energy radiated by the sun is
499× 10⁻⁹m (499nm)
wavelength at the maximum energy radiated by the sun occur measure by:
wien's displacement law : The black body radiation at a wavelength is inversely proportional to temperature.
acc. to wien's displacement law
λ= b/T
λ is wavelength
where T is the temperature
The sun has a surface temperature of approximately 5800 k.
b is constant of proportionality
b = 2.8977×10⁻³mk
T = 5800k
using values in above equation
λ = 2.8977 × 10⁻³ mk/ 5800k
λ= 499× 10⁻⁹m =499nm
wavelength at the maximum energy radiated by the sun is
499× 10⁻⁹m =499nm
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24 1 point
Complete the fission reaction below by choosing the right isotope to go in the blank.
23U+n-
+Sr +3 n
a trout stream in in equilibrium with air at 0/989 atm. what is the concentration of o2 in this stream? kh for o2 in water = 1.28x10-3 mol/(lxatm)
The concentration of O2 in the trout stream is approximately 7.14 mg/L.
The concentration of O2 in a stream at equilibrium with air at 0.989 atm can be determined using the Henry's law constant (KH) for O2 in water. KH is the ratio of the concentration of a gas in a liquid to its partial pressure in the air above the liquid.
By using the KH value of 1.28 x 10^-3 mol/(L x atm) and the partial pressure of O2 in air at 0.989 atm, we can calculate the concentration of O2 in the stream.
To do so, we multiply the KH value by the partial pressure of O2, which gives us the concentration of O2 in the stream in units of mol/L. This value can then be converted to units of mg/L by multiplying by the molecular weight of O2, which is approximately 32 g/mol.
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radio signals 9 billion light years what did it say?
Unfortunately, it is impossible to "speak" anything literally with radio waves that are 9 billion light-years away.
Radio transmissions are only electromagnetic waves that transmit information; meaning cannot be inferred from them without the appropriate tools and a context. The fact that light moves at a finite speed and takes 9 billion years to reach us should also be taken into consideration. As a result, any information carried by radio waves would be billions of years old and might not be applicable to the current condition of the universe.
In radio transmission, a radio transmitter's antenna couples electromagnetic energy into the atmosphere or other open space. Electromagnetic radio waves are caught by a receiving antenna during radio reception and coupled into a receiver for detection.
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The frequency of waves from a radio station is 15 megacycles per second. Calculate their wavelength. Please help!!
The wavelength of waves whose frequency of waves from a radio station is 15 megacycles per second is 20m
Given the frequency of radio waves (f) = 15 megacycles per second
The number of complete wave cycles that pass a location in a unit of time is the definition of frequency. The SI frequency unit is called a Hertz (Hz). A sinusoidal wave's frequency is defined as the total number of full oscillations that every wave constituent performs in a unit of time.
Let the wavelength = ∧
The speed of light waves (v) = 3 x 10^8m/s
We know that frequency = velocity/wavelength
Then f = v/∧ such that ∧ = v/f
∧ = 3 x 10^8/15 x 10^6 = 20m
Hence the wavelength of radio waves = 20m
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