The real root of the equation x3 10x2 29x 30 = 0 is –6. what are the nonreal solutions? 2 i, 2 – i –2 i, –2 – i –4 2i, –4 – 2i 4 2i, 4 – 2i

Answer:

By the midpoint theorem,

\(2ST = XY\\or, 2(x+15) = x+21\\or, 2x+30 = x+21\\or, x = 21-30\\or, x = -9cm\\So, TS = x+15 = -9+15 = 6cm\)

The answer is three

None, one or infinitely many solutions

The coordinates of point Q are (29.3, 21.7).

To find the coordinates of Q, we can use the following steps:

Find the length of OP.

Find the angle TOQ.

Find the coordinates of Q.

Step 1: Find the length of OP

The length of OP can be found using the Pythagorean Theorem. In this case, we have:

OP² = 2² + (√3)²

OP² = 4 + 3

OP² = 7

OP = √7

Step 2: Find the angle TOQ

The angle TOQ can be found using the tangent function. In this case, we have:

tan(TOQ) = OQ/OP

tan(TOQ) = 20/√7

TOQ = arctan(20/√7)

TOQ ≈ 66.9°

Step 3: Find the coordinates of Q

The coordinates of Q can be found using the distance formula. In this case, we have:

Q = (a, b)

a = x + 20 * cos(66.9°)

b = √3 + 20 * sin(66.9°)

a ≈ 29.3

b ≈ 21.7

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Answer:

points C and B

Step-by-step explanation:

becuse they lie at the same points on the number line, only one it oto the rights of zero and the other is to the left; making them oppsites.

Answer:The answar is B and C

Step-by-step explanation: I know this because i did this kind of questions before and it says wich two are oppsites, none of the other points are the exact oppsites of eachother.

No, the current optimal solution may not remain optimal.

To determine if the current optimal solution remains optimal after adding a new variable x3, we need to examine the relation between primal optimality and dual feasibility.

In the primal LP, the current optimal tableau indicates that the artificial variables a1 and a2 are present in the basis. This suggests that the original problem is infeasible. The presence of artificial variables in the basis indicates that the original problem had no feasible solution. Thus, the current optimal solution is not valid.

When we add a new variable x3 and modify the primal LP accordingly, we need to solve the modified LP to determine the new optimal solution. The modified LP has a different constraint and objective function, which can lead to different optimal solutions compared to the original LP.

Therefore, the current optimal solution may not remain optimal when we add a new variable and modify the primal LP.

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You dilate a line segment around a point by following a simple procedure mentioned below that begins with identifying the center of a line segment.

Dilating a line segment around a point is a simple process. First, you need to identify the center of the line segment.

Then, use a ruler or other measuring device to measure the distance from the center of the line segment to each end point.

To dilate the line segment, multiply the measured distance by the desired scale factor. Finally, draw a new line segment connecting the two new end points.

This will give you the dilated line segment around the point you identified at the beginning.

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Answer:

is it 7?

Step-by-step explanation:

Answer:

neither ordered pair is a solution

Step-by-step explanation:

to determine if the pairs are a solution, substitute the x- coordinate into the left side of the equation and if equal to the right side then they are a solution.

(- 9, 3 ) with x = - 9

6(- 9) = - 54 ≠ 14 ← not a solution

(2, - 4 ) with x = 2

6(2) = 12 ≠ 14 ← not a solution

Here is the completed table:

Range   Number of Values

1 – 5            3

6 – 10          1

11 – 15          4

16 – 20         5

21 – 25         2

The value that should be placed in the second column for the range 16 - 20 is 5.

A frequency table is a table that is used to condense a dataset. A frequency table divides the data into a class and frequency.

A class is a group of values that are binned together. A class has a upper boundary and the lower boundary. An example of a class is 1 - 5. 1 is the lower boundary and 5 is the upper boundary.

The frequency is the number of times the values in the class occur in the data set. For example, the number of values for range 1 - 5 is 3. This means that there are 3 values in the dataset that has a value between 1 and 5.

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Step-by-step explanation:

using long division..........

Answer: 3

Step-by-step explanation:

\(\frac{1}{3}\) × 3 = 1

When you add -1/4 to itself four times, you get: -1
When you multiply -1/4 by 4, you also get: -1.
Yes, both the results are same which is: -1.

To answer your question, let's break it down into two parts:

1. What do you get if you add -1/4 to itself four times?
To find the answer, you simply add -1/4 four times:
(-1/4) + (-1/4) + (-1/4) + (-1/4) = -1

2. What is -1/4 × 4?
To multiply -1/4 by 4, you perform the multiplication:
(-1/4) × 4 = -1

In conclusion, when you add -1/4 to itself four times, you get -1, and when you multiply -1/4 by 4, you also get -1.

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Answer:

So using process of elimination it isnt possible for it to be AA or not similiar bc they are similiar since there vertical angles so were left with picking between SSS and SAS which I know that there is an angle that is congruent which is at the midpoint so if i were you I would put SAS similarity.

Step-by-step explanation:

I just took a test of this lesson so I hope im right.

Answer:

Step-by-step explanation:

$4.7 billion ..

Answer:

1 13/30

Step-by-step explanation:

First you want to make the denominators the same.  You do this by multiplying them.  However, whatever you do you to the denominator, you must also do to the numerator:

\(\frac{8x6}{5x6}\)-\(\frac{1x5}{6x5}\)=\(\frac{48}{30}\)-\(\frac{5}{30}\)=\(\frac{43}{30}\)

Now reduce to simplest terms:

\(\frac{43}{30}\)=1\(\frac{13}{30}\)

The sample space of the experiment of rolling three fair coins consists of all possible outcomes when three coins are tossed simultaneously. Therefore, there are 2 x 2 x 2 = 8 possible outcomes in the sample space.

In this experiment, we are rolling three fair coins. To find the number of elementary events in the sample space, we need to consider all possible outcomes.

An elementary event is an individual outcome in the sample space. The sample space is the set of all possible outcomes for an experiment. In this case, each coin can have 2 possible outcomes: heads (H) or tails (T).
Each outcome in the sample space is an elementary event, which is an outcome that cannot be further broken down into simpler outcomes. Therefore, there are 8 elementary events in the sample space of this experiment.

Since there are three coins, we can determine the number of elementary events in the sample space by multiplying the number of outcomes for each coin: 2 (for the first coin) x 2 (for the second coin) x 2 (for the third coin) = 8.

So, there are 8 elementary events in the sample space of this experiment. The correct answer is c. 8.

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Step-by-step explanation:

0.9(17) -2.7(3) =

15.3-8.1

=7.2

Answer:

try c hope this helps

Step-by-step explanation:

After 24 days, there will be approximately 25 atoms of I13153 remaining. The nuclear process that occurs during the decay is the transformation of I13153 into Xe13154.

The half-life of I13153 is nearly 8 days, which means that after each 8-day period, half of the atoms will decay into Xe13154. Starting with a sample of 200 atoms of I13153, we can calculate the number of remaining atoms after 24 days. Since the half-life is 8 days, the number of remaining atoms after each 8-day period is halved. After the first 8 days, there will be 100 atoms of I13153 remaining.

After the second 8 days, there will be 50 atoms remaining. And after the third 8 days, there will be 25 atoms of I13153 remaining. The nuclear process that occurs during the decay of I13153 is radioactive decay. Specifically, it undergoes beta decay, where a neutron in the nucleus of I13153 is converted into a proton, resulting in the formation of Xe13154. This process releases radiation and transforms the original isotope into a different element.

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The equation of the curve that passes through the point (0, 1) and has a slope of 5xy at any point (x, y) is y = (5/2) * x^2y + 1. This equation represents a curve where the y-coordinate is a function of the x-coordinate, satisfying the conditions.

To determine an equation of the curve that satisfies the conditions, we can integrate the slope function with respect to x to obtain the equation of the curve. Let's proceed with the calculations:

We have:

Point: (0, 1)

Slope: 5xy

We can start by integrating the slope function to find the equation of the curve:

∫(dy/dx) dx = ∫(5xy) dx

Integrating both sides:

∫dy = ∫(5xy) dx

Integrating with respect to y on the left side gives us:

y = ∫(5xy) dx

To solve this integral, we treat y as a constant and integrate with respect to x:

y = 5∫(xy) dx

Using the power rule of integration, where the integral of x^n dx is (1/(n+1)) * x^(n+1), we integrate x with respect to x and get:

y = 5 * (1/2) * x^2y + C

Applying the initial condition (0, 1), we substitute x = 0 and y = 1 into the equation to find the value of the constant C:

1 = 5 * (1/2) * (0)^2 * 1 + C

1 = C

Therefore, the equation of the curve that passes through the point (0, 1) and has a slope of 5xy at any point (x, y) is:

y = 5 * (1/2) * x^2y + 1

Simplifying further, we have:

y = (5/2) * x^2y + 1

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Answer:

0.5

Step-by-step explanation:

The rate of change is the same as the slope. The equation y=0.5x+9 is written in slope intercept form, so 0.5 is the slope.

Answer:

Slope: 0.5

Y - Intercept: (0, 9)

x           y

-18        0

0           9

(pretend that's a graph)

Proportional: Ratios are equivalent.

Non-proportional: Ratos are not equivalent.

-18/ 0 is not equal to 0/9.

Undefined                  =0

Non-proportional

Answer: x = 1.4

Step-by-step explanation:

Simplify:

6-5x+1 = 0

Subtract 1 from both sides:

6 -5x = -1

Subtract 6 from both sides:

-5x = -7

Divide both sides by -5:

x = 1.4

An expression for the sequence of operations described "Subtract three from the product of seven and eight." is (7 × 8) - 3.

In order to evaluate and solve this expression, we would have to apply the PEMDAS rule, where mathematical operations within the parenthesis (grouping symbols) are first of all evaluated, followed by exponent, and then multiplication or division from the left side of the equation to the right. Lastly, the mathematical operations of addition or subtraction would be performed from left to right.

Based on the information provided, we have the following mathematical expression:

Expression: (7 × 8) - 3

56 - 3

53

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The VSWR on the 50 Ω line is 2.68.

(a) To calculate the reflection coefficient at the input of the line, we can use the equation:

Γin = (ΓL + e^(j2βL))/(1 + ΓL*e^(j2βL))

where Γin is the reflection coefficient at the input of the line, ΓL is the reflection coefficient of the load, β is the propagation constant of the line, L is the electrical length of the line in radians, and j is the imaginary unit.

In this case, ΓL = 0.5, β = 2π/λ (where λ is the wavelength of the signal on the line), L = 45° = π/4 radians, and the line has a characteristic impedance of 50 Ω.

To find the wavelength, we can use the equation:

λ = v/f

where v is the speed of light and f is the frequency of the signal. Assuming a frequency of 1 GHz, we get:

λ = 3e8 m/s / 1e9 Hz = 0.3 m

So, β = 2π/λ = 20.94 rad/m.

Substituting these values into the equation for Γin, we get:

Γin = (0.5 + e^(j220.94π/4))/(1 + 0.5e^(j220.94*π/4))

Using Euler's formula (e^(jθ) = cos(θ) + j*sin(θ)), we can simplify this expression:

Γin = (0.5 + j0.5)/(1 + 0.5*j)

Multiplying the numerator and denominator by the complex conjugate of the denominator, we get:

Γin = (0.5 + j0.5)(1 - 0.5j)/(1 + 0.25) = (0.75 + j0.25)/1.25

So, the reflection coefficient calculated at the input of the line is:

Γin = 0.6 + j0.2

(b) To calculate the VSWR on the 50 Ω line, we can use the formula:

VSWR = (1 + |Γin|)/(1 - |Γin|)

where |Γin| is the magnitude of the reflection coefficient at the input of the line.

In this case, we calculated that Γin = 0.6 + j0.2. The magnitude of this complex number is:

|Γin| = sqrt(0.6^2 + 0.2^2) = 0.632

So, the VSWR on the 50 Ω line is:

VSWR = (1 + 0.632)/(1 - 0.632) = 2.68

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B. 2 and OD. 15 are not possible lengths for the third side of the triangle.

To determine the possible values for the length of the third side of a triangle, we need to consider the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

Given that two sides have lengths 6 and 9, we can analyze the possibilities:

6 + 9 > x

x > 15 - The sum of the two known sides is greater than any possible third side.

6 + x > 9

x > 3 - The length of the unknown side must be greater than the difference between the two known sides.

9 + x > 6

x > -3 - Since the length of a side cannot be negative, this inequality is always satisfied.

Based on the analysis, the possible values for the length of the third side are:

A. 7

C. 4

□E. 10

O F. 12

B. 2 and OD. 15 are not possible lengths for the third side of the triangle.

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The association in this graph can best be described as C. Negative linear.

A negative linear association is one that moves from the left to the right. In this kind of association, the predictor increases while the response decreases. The linear nature of this association is seen in the straight line formed from the plot.

A positive linear association would fall from the right towards the left side and a non-linear association will form a curve. So, the association in the table is negative linear.

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Answer:

-3

Step-by-step explanation:

We know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Accordingly, let us solve the given fraction.

-7 - ( - 4 )

-7 + 4

-3

The estimated crop yield from the simulation is 443 (option b).

To estimate the crop yield from the given random numbers, we need to assign a specific meaning to each random number. Let's assume that each random number represents the crop yield for a particular year.

Given random numbers: 37, 23, 92, 01, 69, 50, 72, 12, 46, 81

To find the estimated crop yield, we sum up all the random numbers:

37 + 23 + 92 + 01 + 69 + 50 + 72 + 12 + 46 + 81 = 443

Therefore, the estimated crop yield from the simulation is 443. The correct option is b.

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