The radioactive hydrogen isotope 3h is called tritium. it decays by beta-minus decay with a half-life of 12.3 years. What is the daughter nucleus of tritium?

The answer to this is B, C, and D. hope this helped

Explanation:

Wave front, imaginary surface representing corresponding points of a wave that vibrate in unison. ... Wave fronts for longitudinal and transverse waves may be surfaces of any configuration depending on the source, the medium, and the obstructions encountered.

The eccentricity of the majority of the planetary orbits in our solar system is approximately less than 0.1

The eccentricity of a planetary orbit refers to how much the orbit deviates from a perfect circle. Most of the planets in our solar system have nearly circular orbits, with eccentricities less than 0.1. Only a few planets have slightly more elliptical orbits, with eccentricities ranging up to 0.25, such as Pluto. The eccentricity of an orbit affects the planet's distance from the Sun and its speed as it moves through its orbit.

The more eccentric an orbit, the greater the variation in a planet's distance from the Sun throughout its year. Overall, the majority of the planetary orbits in our solar system are close to circular, making them stable and predictable.

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An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.

(d) No bliss point. and, (e) Steeper indifference curves.

(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.

(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.

(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.

(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.

(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.

In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.

These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.

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Answer:

Explanation:

The higher the object is relative to some defined baseline (like the ground), the greater the potential energy.

Potential Energy = U = mgh

U is directly proportional to h (height of the object), so the greater the h the greater the U.

Two stars with the same mass number can be different in their luminosity, life time and distance with respect other stars and planets.

Stars are spatial objects with brightness and are made of gases and dust. The major part of stars are hydrogen and helium gases. There are trillions of stars for each galaxies in the universe.

The energy formed inside the stars is from  the nuclear fusion of hydrogen nuclei forming helium nuclei releases tones of heat and light energy. The light and heat energy produced from each stars differ.

The luminosity or brightness of stars with same mass will be different. The life time of each stars also differ from other stars.

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Taking into account the Boyle's law, Charles's law and Gay-Lussac's law, you get:

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as

P×V=k

Considering an initial state 1 and a final state 2, it is fulfilled:

P₁×V₁=P₂×V₂

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas.

This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases: the volume is directly proportional to the temperature of the gas.

Charles's law is expressed mathematically as:

V÷T=k

Considering an initial state 1 and a final state 2, it is fulfilled:

V₁÷T₁=V₂÷T₂

Gay-Lussac's law determines that gas pressure is directly proportional to its temperature when the volume is constant: when there is a constant volume, when the temperature increases, the gas pressure increases and when the temperature decreases, the gas pressure decreases.

Gay-Lussac's law is expressed mathematically as:

P÷T=k

Considering an initial state 1 and a final state 2, it is fulfilled:

P₁÷T₁=P₂÷T₂

In this case, you know:

Replacing in the Boyle's law:

5 atm× 3.5 L= 6 atm×V₂

(5 atm× 3.5 L)÷ 6 atm= V₂

2.92 L= V₂

Finally, the volume will be 2.92 L.

In this case, you know:

Replacing in Gay-Lussac's law:

2 atm÷ 288 K=P₂÷ 303 K

(2 atm÷ 288 K)× 303 K=P₂

2.104 atm= P₂

Finally, the pressure will be 2.104 atm.

In this case, you know:

Replacing in Charles's law:

6 L÷293 K=4 L÷T₂

(6 L÷293 K)× T₂= 4 L

T₂= 4 L÷ (6 L÷293 K)

T₂= 195.33 K

Finally, the temperature will be 195.33 K.

In this case, you know:

Replacing in the Boyle's law:

5.5 atm× 40 L= 8.2 atm×V₂

(5.5 atm× 40 L)÷ 8.2 atm= V₂

52.38 L= V₂

Finally, the volume will be 52.38 L.

In this case, you know:

Replacing in Gay-Lussac's law:

1.5 atm÷ 291 K= P₂÷ 305 K

(1.5 atm÷ 291 K)× 305 K=P₂

1.43 atm= P₂

Finally, the pressure will be 1.43 atm.

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Answer: A gravitational pull is keeping the ball in place and not letting it go flying into the air. so simple answer is gravity

(a) The moment of inertia of the wheel is 22.8 kg·m².

(b) The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

(a) To find the moment of inertia of the wheel, we can use the formula for torque:

Torque = Moment of inertia * Angular acceleration

The total torque is 36.1 N·m and the angular acceleration is the change in angular speed divided by the time, we have:

36.1 N·m = Moment of inertia * (9.8 rad/s - 0 rad/s) / 6.20 s

Simplifying the equation:

Moment of inertia = (36.1 N·m * 6.20 s) / 9.8 rad/s

Moment of inertia = 22.8 kg·m²

Therefore, the moment of inertia of the wheel is 22.8 kg·m².

(b) After the applied force is removed, the wheel comes to rest, indicating that the torque due to friction is acting in the opposite direction to oppose the wheel's motion. We need to find the magnitude of this frictional torque.

The frictional torque can be found using the equation:

Torque = Moment of inertia * Angular acceleration

Since the wheel comes to rest, its final angular speed is 0 rad/s, and the time taken for it to come to rest is 60.9 s. Therefore, the angular acceleration can be calculated as:

Angular acceleration = (0 rad/s - 9.8 rad/s) / 60.9 s

Plugging in the values:

Angular acceleration = -0.161 rad/s²

Now we can find the frictional torque:

Torque = 22.8 kg·m² * (-0.161 rad/s²)

The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions can be calculated by finding the total angle rotated by the wheel in radians and converting it to revolutions.

During the first 6.20 s, the wheel rotates from 0 rad/s to 9.8 rad/s. The total angle rotated can be found using the equation:

θ = 0.5 * (initial angular speed + final angular speed) * time

θ = 0.5 * (0 rad/s + 9.8 rad/s) * 6.20 s

θ = 30.38 rad

During the next 60.9 s, the wheel comes to rest, so the total angle rotated is 0 rad.

Therefore, the total angle rotated by the wheel in 67.1 s is 30.38 rad.

To convert this to revolutions, we divide by 2π radians, since there are 2π radians in one revolution:

Number of revolutions = 30.38 rad / (2π rad/rev)

Number of revolutions ≈ 4.83 revolutions

Therefore, the total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

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Answer:

c = λ f

Explanation:

In the electromagnetic spectrum, the wavelength and frequency of a specific radiation are related to the speed of the wave, which in this case the speed of light

         c = λ f

where c is the speed of light, λ the wavelength and f the frequency of radiation

The small detected irregularities in the uniformity of the cosmic microwave background (CMB) are crucial in studying the evolution of our universe because they provide evidence of the initial density fluctuations that gave rise to the large-scale structures we observe today.

These tiny temperature variations in the CMB, a relic radiation from the early universe, serve as a snapshot of the conditions present approximately 380,000 years after the Big Bang.

By analyzing these irregularities, scientists can refine cosmological models, determine the age, composition, and geometry of the universe, and gain insight into the processes that shaped its development, such as inflation and the formation of galaxies.

In essence, the CMB irregularities serve as a valuable tool for understanding the origins and history of our universe.

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Out of the four factors in the Drake equation, the factor that is best known is the number of stars in the Milky Way. This is because it is based on observations and data gathered by astronomers over many years. The estimated number of stars in the Milky Way is around 100 billion, give or take a few billion.

On the other hand, the other three factors - the chance that life will arise on an Earth-like planet, the number of Earth-like planets per system, and how long a technological civilization will last - are more uncertain and subject to ongoing research and debate. However, recent advances in exoplanet studies have provided more information about the frequency of Earth-like planets, and astrobiologists are working to better understand the conditions necessary for the emergence and evolution of life. As for the longevity of technological civilizations, this is a difficult question to answer because it depends on so many unknown factors, including the potential impact of catastrophes like asteroid impacts or climate change.

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The intensity of the Sun's radiation at the position of the Earth is approximately 1400 W m-2, which is the total amount of energy that reaches the Earth's surface from the Sun. However, the average power received per unit area of the Earth is only 350 W m-2. This is because the Sun's radiation is not evenly distributed over the Earth's surface.

Some parts of the Earth receive more of the Sun's radiation and some parts receive less. Factors like the Earth's tilt, the atmosphere and clouds, and the Earth's rotation all play a role in determining the amount of solar radiation reaching different areas on the planet. Additionally, the intensity of the Sun's radiation at the position of the Earth is reduced as it passes through the atmosphere, further reducing the amount of energy available for the Earth's surface. Thus, the average power received per unit area of the Earth is only 350 W m-2, significantly lower than the 1400 W m-2 of the Sun's radiation at the position of the Earth.

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A No. 12 THHN conductor is required for a 19.7-ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.

To determine the size of the THHN conductor required for a 19.7-ampere load, we will need to use the ampacity tables from the National Electric Code (NEC).

The ampacity tables provide the maximum current-carrying capacity of various types and sizes of conductors based on factors such as ambient temperature and the number of current-carrying conductors in the raceway or cable.

Assuming a copper conductor, we can use NEC Table 310.15(B)(16) to find the ampacity of a No. 12 THHN conductor at an ambient temperature of 75F with nine current-carrying conductors. According to the table, the ampacity of a No. 12 THHN conductor with nine current-carrying conductors at 75F is 20 amperes.

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Answer:

The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.

When compared to winds at the surface, winds at 2,000 feet are typically higher due to the absence of friction.

At the surface, winds are affected by friction with the Earth's surface, which slows them down and causes them to move in a more turbulent and erratic fashion. However, as winds move up in altitude, they encounter less and less friction, allowing them to increase in speed and flow in a more uniform and predictable manner.
While friction may still have some influence on winds at 2,000 feet, it is not as significant as at the surface. Therefore, winds at this altitude tend to move more smoothly and follow a more consistent path, often perpendicular to the isobars (lines of equal pressure) on a weather map. This makes them useful for aviation purposes, as pilots can use this information to plan their flight paths and take advantage of favorable tailwinds or avoid dangerous crosswinds.
In contrast, winds at the surface are more affected by local topography, temperature gradients, and other factors that can cause them to vary widely in direction and speed. Overall, winds at 2,000 feet are an important component of the Earth's atmospheric circulation system, and understanding their behavior is essential for predicting weather patterns and ensuring safe air travel.

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Answer:

Now, think on the electrons flowing through a conductor (we can think on the resistor as a simple conductor, like a piece of metal)

Inside the conductor, we have some "fixed" (they do not flow with the current) electrons, such that as the current flows in the conductor, the flowing electrons can interact with the fixed ones in the conductor. Then we can have collisions inside the conductor.

In those collisions, the flowing electrons leave energy in the conductor, and as we know, heat is a form of energy. Then when we have a lot of these collisions, the temperature of the conductor increases.

That is why electronic devices get hot.

Also, as the temperature of a conductor increases, the electrons inside of it start to move more, then the probability of an interaction with the flowing electrons increases.

Answer:

The northern hemisphere receives more direct sunlight during the summer.

Answer:

Third option: "A nucleus collides with a neutron and splits, releasing energy."

Explanation:

When nucleus that collides with a neutron splits (fission) releases energy in the process. This is a case of fission.

This is how a fission nuclear reactor works.

Answer:

It be C

Explanation:

Right on edg

Answer:

The distance that the honey flowed would be the dependent or outcome variable and the temperature of the honey would be the independent variable.

The dependent variable is what is being measured in an experiment. You can remember it by thinking “it depends on what you’re changing.”

The independent variable in an experiment is what is being changed. You can remember this by thinking “the Independent variable is what I as the scientist change.”

Explanation:

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In the experiment " Temperature" is dependent variable and the distance honey flows is independent variable.

It is the factor that one can purposely control or change to observe its effect , is called independent variable.

It respond to the change in the independent variable , is called dependent variable.

Hence temperature is dependent and distance honey flow is independent variable.

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Answer:

6.67 Nm/s

Explanation:

As we know, the rate at which work is done is called power.

Power = Work done/ Time

Power = F * D / T

Where,

F = Force

D = Distance

T = Time

Given,

F = 10N

D = 20m

T = 30s

Power = 10*20/30

Power = 200/30

Power = 6.67 Nm/s

Hope it helps! :)

Answer:

6.67 watts

Explanation:

power=force × velocity

10×20÷30

=6.67 watts

The net force exerted on the car is 2000 N, which corresponds to option (b).

The net force exerted on an object can be calculated using Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).

In this case, the mass of the car is given as 1000 kg, and the acceleration is 2 m/s². Plugging these values into the equation, we have:

F_net = m × a

F_net = 1000 kg × 2 m/s²

F_net = 2000 N

Therefore, the net force exerted on the car is 2000 N.

The correct answer is (b) 2000 N.

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The net force performs a total amount of work equal to

(45 N) (0.80 m) = 36 J

on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have

W = ∆K = 1/2 mv²

since the bullet starts at rest, where m = its mass and v = its final velocity.

Solve for v :

36 J = 1/2 (0.0050 kg) v²   ⇒   v = 120 m/s

The kinematics to find the time to go from the office to the living room is: 2.81 s

Given Parameters

To find

Kinematics allows us to find the relationships between the position, velocity and acceleration of bodies, let's use the relationship  

             x = v₀ t + ½ a t²

Where x is the position, v₀ the initial velocity, at acceleration and t the time

In this case, as he leaves the office, the initial velocity is zero.

           x = ½ a t²

            t = \(\sqrt{\frac{2x}{a} }\)

Let's calculate

           t = \(\sqrt{\frac{2 \ 125}{4} }\)

          t = 2.81 s

In conclusion, using the kinematics, we find that the time to go from the office to the classroom is: 2.81 s

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According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it the total momentum of the system before and after the collision will be conserved. The correct option d.

The law of conservation of momentum states that in a closed system, the total momentum before a collision is equal to the total momentum after the collision, provided there are no external forces acting on the system. The law applies to both linear and angular momentum.

In the given scenario, the total momentum of the system before the collision is the sum of the momenta of the two disks. After the collision, the total momentum of the system should still be the same as before the collision if no external forces are present.

The individual velocities and directions of the disks after the collision may change, and they may continue to move at different velocities or even come to rest. The law of conservation of momentum does not dictate the velocities or outcomes of the individual objects involved in the collision. It only states that the total momentum of the system remains constant.

Therefore, option d) The total momentum of the system before and after the collision will be conserved is the correct statement according to the law of conservation of momentum.

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Answer:

No

Explanation:

The fastest recorded time for a person to run 100 metres is 9.58 seconds, which is the equivalent of 10.4 metres per second

Answer:

No

Explanation:

Humans can run as fast as 19.3m/s, using their full possible energy.