Answer:
The options are
A.on racetracks
B.in real-world conditions
C.in flooded environments
D.on closed courses
The answer is B. In real world conditions
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin
how the cars perform based on real world conditions.
This will ensure they encounter the real and first hand experiences about the challenges and also the advantages associated with using this type of fuel.
Which of the following is an appropriate unit for speed?
miles/hour
meters/second
blocks/min
newtons/sec
please help. i will give u brainliest
Answer:
the newtons/second is an improper unit for speed
How long is the runway? And what is the planes take off speed
These relationships are referred to as the equation of motion.
s = ut + ½at². and v = u + at.
length of the Run way = 1350m
Take of speed of the plane is 90 m/s.
How many formulas of motion are there?We will learn how to relate quantities such as velocity, time, acceleration, and displacement as long as the acceleration is constant. These relationships are referred to as the equation of motion.The three equations of motion are as follows:
v = u + a t is the first equation of motion.s = u t + 1 /2 a t^2 is the second equation of motion. Third Element of Motion: v 2 = u 2 + 2 a sfrom equation of motion
s = ut + ½at².
here u =0 a =3 m/s^2 t= 30s
put these values on the above equation
s= 1/2x 3x 30x30= 1350 m
length of the Run way = 1350m
from equation of motion ,
v = u + at.
= 0+ 3x 30 = 90m/s.
Take of speed of the plane is 90 m/s.
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Distance = 1350m, speed = 90m/s
Given:
Initially the Aero plane is at rest. Therefore, initial velocity:
u = 0m/s
Acceleration = 3m/\(s^{2}\)
Time taken = 30 seconds
So according to question, we have to find distance & speed
How to find distance?we know that
s = ut + 1/2a\(t^{2}\)
Putting all the values, we get S = 1350 m
Now to find speed, we know,
\(v^{2} = u^{2} + 2aS\)
Putting all the values,
v = \(\sqrt{8100}\)
v = 90m/s
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Plz help me fast WITH EXTRA POINTS AFTER SUBMITTING
Answer:
4 bobux
Explanation:
one bobux
two bobux
three bobux
four bobux
What is the kinetic energy of a moving toy car if the car has a mass of 15.0 kg and the velocity is 7.2 m/s ? ______ J
Answer:
389 J
Explanation:
m = 15.0 kg, v = 7.2 m/s
Kinetic energy = mv²/2 = 15.0 * 7.2²/2 = 389 J
A girl and her sledge have a combined mass of 40kg. She starts from rest and descends a slope which is inclined at 25 degrees to the horizontal. At the bottom of the slope the ground becomes horizontal for 15m before rising at 6 degrees to the horizontal. The girl travels 25m up the slope before coming to rest once more. There is a constant resistance to motion of magnitude 18N. Calculate the distance the girl travels down the slope.
To solve this problem, we can use the principle of conservation of energy. According to this principle, the total mechanical energy of an object remains constant as long as there are no external forces doing work on the object.
The initial mechanical energy of the girl and sledge is the potential energy they have due to their height above the ground. This potential energy is given by the formula:
PE = m * g * h
where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.
The final mechanical energy of the girl and sledge is the sum of their kinetic energy and potential energy at the end of their motion.
We can set up the following equation to represent the conservation of energy:
Initial PE + Initial KE = Final KE + Final PE
Since the girl and sledge start from rest, their initial kinetic energy is zero. Therefore, the equation simplifies to:
Initial PE = Final KE + Final PE
We can determine the distance the girl and sledge travel down the slope by calculating the final kinetic energy and potential energy and solving for the distance.
The final kinetic energy is given by the formula:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity.
The final potential energy is given by the formula:
PE = m * g * h
where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.
To calculate the final kinetic energy, we need to determine the velocity of the girl and sledge at the end of their motion. We can use the principle of conservation of energy to solve for the velocity.
Substituting the given values into the equation for conservation of energy, we get:
Initial PE = Final KE + Final PE
= 1/2 * 40 kg * v^2 + 40 kg * 9.8 m/s^2 * h
We can solve for the velocity by rearranging the terms and substituting the values for the mass, initial potential energy, and final potential energy:
v = sqrt((2 * (Final PE - Initial PE)) / m)
= sqrt((2 * (40 kg * 9.8 m/s^2 * h - 40 kg * 9.8 m/s^2 * h)) / 40 kg)
= 0
Since the velocity is zero, the final kinetic energy is also zero. This means that the final mechanical energy is equal to the final potential energy, which is equal to the initial potential energy.
We can therefore set up the following equation to solve for the distance the girl and sledge travel down the slope:
Initial PE = Final KE + Final PE
= 0 + Final PE
= Initial PE
This equation tells us that the initial potential energy is equal to the final potential energy. Since the girl and sledge start from rest at the top of the slope and end at rest at the bottom of the slope, the final potential energy is equal to the initial potential energy.
Therefore, the distance the girl and sledge travel down the slope is equal to the distance they travel up the slope, which is 25m.
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Particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC are in a line. Particles q1 and q2 are separated by 0.876m and particles q2 and q3 are separated by 0.432m. What is the net force on particle q3?
The net force on q3 due to q1 and q2 is \(-13.76 * 10^{-3} N\).
Electrostatic force is the fundamental force between charged particles. The electrostatic force is responsible for many phenomena in our daily life, from the attractive force between a magnet and a metal object to the lightning that occurs during a thunderstorm. We can calculate the net force between charged particles using Coulomb's law. In this question, we have three particles q1 = -75.8 uC, q2 = +90.6 uQ, and q3 = -84.2 uC, which are separated by distances r1 = 0.876m and r2 = 0.432m. The electrostatic force on q3 due to q1 and q2 can be calculated by using the formula: \(F13 = k q_1 q_3 / r_1^2 + k q_2 q_3 / r_2^2\), where k is the Coulomb's constant \(k = 9 * 10^9 N m^2 / C^2\). Plugging in the given values of q1, q2, q3, r1, r2, and k in the above formula, we can calculate the electrostatic force on q3 due to q1 and q2.F13 = (9 x 10^9) (-75.8 x 10^-6) (-84.2 x 10^-6) / (0.876)^2 + (9 x 10^9) (90.6 x 10^-6) (-84.2 x 10^-6) / (0.432)^2F13 = \(-13.76 * 10^{-3} N\). The negative sign indicates that the force is attractive and is directed towards q1 and q2. Therefore, the net force on q3 is given by the vector sum of the forces on q3 due to q1 and q2. Since the forces are collinear, we can add them algebraically. Fnet = F13 Fnet = \(-13.76 * 10^{-3} N\)The net force on q3 due to q1 and q2 is -13.76 x 10^-3 N. The negative sign indicates that the force is attractive and is directed towards q1 and q2.For more questions on net force
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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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what causes diffferent air density?
Answer:
The temperature and gravity both affects the density
How long does it take for light from the Sun to reach the Earth?365 secondseight weekseight minutes365 days
ANSWER:
Eight minutes
STEP-BY-STEP EXPLANATION:
We know that the distance from the Sun to the Earth is 150 million km and light moves at 300000 kilometers/second. Therefore, we can calculate the time as follows:
\(\begin{gathered} v=\frac{d}{t} \\ \text{ replacing} \\ 300000=\frac{150000000}{t} \\ t=\frac{150000000}{300000} \\ t=500\text{ s}\cdot\frac{1\text{ min}}{60\text{ s}}=8.33\text{ min} \\ t=8\text{ min} \end{gathered}\)So it takes about 8 minutes
An object of height 5cm is placed 20cm in front of pin hole camera from a cubic box of side 6cm . Determine the height of the image formed
what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)
Pressure (P) = Density (ρ) × g × Depth (h)
Given: Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Depth (h) = 6 m
Using the given values, one can calculate the pressure:
Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure
= 58800 kg·m⁻¹·s⁻²
Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:
Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)
Pressure = 580.124 atm
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How can we show that air can do work?
Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.
Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.
To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.
The work done by the air can be calculated using the equation:
Work = Force * Distance * cos(θ)
Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.
In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:
Work = Force * Distance * 0
Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.
However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.
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A frying pan is connected to a 1500 volt circuit. If the resistance of the frying pan is 25 ohms, how many amperes does the frying pan draw?
The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes
How do i determine the current drawn by the frying pan?From the question given above, the following data were obtained:
Voltage of circuit (V) = 1500 V Resistance of frying pan (R) = 5 Ω Current (I) =?The current drawn by the frying pan can be obtained as follow:
Voltage (V) = Current (I) × resistance (R)
Inputting the given parameters, we have:
1500 = Current × 25
Divide both sides by 25
Current = 1500 / 25
Current = 60 amperes
Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes
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Thom draws a line of bicycles at a stand with the first one in the full view and the others behind it in partial view. What BEST describes this effect?
A.
asymmetry
B.
diminishing detail
C.
overlapping of objects
D.
radial balance
The BEST option that describes the effect of Thom drawing a line of bicycles with the first one in full view and the others behind it in partial view is C. overlapping of objects.
What is partial view?A partial view is a view of an object or scene that only shows a portion or a part of it, as opposed to a full view that shows the entire object or scene. In art or photography, a partial view can be used to create a sense of intrigue or mystery, as it leaves some details to the viewer's imagination. In architecture or interior design, a partial view can be used to create a sense of openness and connection between spaces, as it allows glimpses of other areas without revealing everything at once. In the context of the original question, the line of bicycles is partially visible, meaning that only a portion of each bicycle is visible due to the overlap effect created by their arrangement.
Here,
Overlapping is a technique in art where objects are positioned so that some are partially or fully covered by others. In this case, the first bicycle is fully visible, and the others are partially hidden behind it, creating an overlapping effect. This technique can be used to create depth and perspective in a drawing and can also be used to create a sense of movement, as in this case with the line of bicycles.
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What is the final velocity of the ball that is dropped from a height of 200m?
The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .
What is velocity with example?The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.
Briefing:Given the initial velocity of the ball (u) = 0
Distance travelled by the ball (s) = 200m
Acceleration (a) = 10 m/s²
As we know:
v² = u² + 2as
Putting values:
v² = 0+2 × (10 m/s²) × (200 m)
v = 44.73 m/s.
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Car A and car B set off from the same point to travel the same journey. Car A sets off three minutes before car B. If car A travels at 60 km/h and car B travels at 70 km/h, how many kilometres from the starting point will the two cars draw level?
Answer:
Let's start by calculating how much of a head start Car A has in distance before Car B starts.
In 3 minutes, Car A will have travelled:
d = r * t = (60 km/h) * (3/60) h = 3 km
So when Car B starts, Car A is 3 km ahead.
Now let's consider the time it takes for both cars to meet. Let's call the time it takes for both cars to meet t.
During that time, Car A will travel at a speed of 60 km/h, and Car B will travel at a speed of 70 km/h.
The distance that Car A will travel during that time is:
dA = 60 km/h * t
The distance that Car B will travel during that time is:
dB = 70 km/h * t
The total distance between the two cars when they meet is:
d = dA + dB
We want to find the value of t that makes dA + dB = 3 km (the distance that Car A is ahead of Car B when Car B starts).
Substituting the expressions for dA and dB, we get:
60 km/h * t + 70 km/h * t = 3 km
Simplifying, we get:
130 km/h * t = 3 km
t = 3 km / 130 km/h
t = 0.0231 h
Now we can calculate the distance that both cars will have travelled when they meet:
dA = 60 km/h * 0.0231 h = 1.38 km
dB = 70 km/h * 0.0231 h = 1.61 km
d = dA + dB = 1.38 km + 1.61 km = 2.99 km
Therefore, the two cars will draw level after travelling approximately 2.99 km from the starting point.
How much heat is required to raise the temperature of 90 g of water from 12C to 88C?
It would require 28618.56 J of heat to raise the temperature of 90 g of water from 12°C to 88°C.
How much heat is required to raise the temperature of 90g of water from 12°C to 88°C?Given that:
Mass of water m = 90g
Initial temperature = 12°C
Final temperature = 88°C,
The amount of heat required to raise the temperature of a substance is given by:
Q = mCΔT
Where Q is the amount of heat, m is the mass of the substance, C is the specific heat capacity of the substance, and ΔT is the change in temperature.
Note that: the specific heat capacity of water is 4.184 J/g°C.
So, for raising the temperature of 90 g of water from 12°C to 88°C, we have:
Q = mCΔT
Q = (90 g) × (4.184 J/g°C) × (88°C - 12°C)
Q = (90 g) × (4.184 J/g°C) × (76°C)
Q = 28618.56 J
Therefore, the required heat is 28618.56 Joules.
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Why does an energy transfer not always result in phase change?
Answer:
Explanation:
The energy transfer are not changing in kinetic energy. They are changes in bonding energy between the molecules.
An inventor claims to have developed a power cycle capable of delivering a net work output of 400 kJ for an energy input by heat transfer of 1200 kJ. The system undergoing the cycle receives heat from a source of 550K and rejects heat to a sink of 350K. Determine if this is a valid claim.
Answer: Valid claim
Explanation:
Given
Work output is \(W=400\ kJ\)
Work input is \(Q=1200\ kJ\)
The temperature of the source \(T_h=550\ K\)
The temperature of the sink is \(T_l=350\ K\)
Efficiency is given by
\(\eta =\dfrac{\text{W}}{\text{Q}}\times 100\)
Insert the values
\(\Rightarrow \eta=\dfrac{400}{1200}\times 100\\\\\Rightarrow \eta=\dfrac{100}{3}\\\\\Rightarrow \eta=33.3\%\)
For ideal cycle it is
\(\Rightarrow \eta=\dfrac{T_h-T_l}{T_l}\times 100\\\\\Rightarrow \eta=\dfrac{550-350}{550}\times 100\\\\\Rightarrow \eta=36.36\%\)
The efficiency of the cycle is less than the ideal situation, therefore, it is valid claim.
A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?
Answer:
The velocity of the box is related to the angular velocity of the spool, which is given by the equation:
v = r * ω
where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:
τ = I * α
where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.
The tension in the string is equal to the weight of the box, which is given by:
T = m * g
Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:
First, we can find the angular acceleration of the spool using the torque equation:
τ = I * α
T = m * g = τ
m * g = I * α
α = (m * g) / I
α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2
α = 86.53 rad/s^2
Next, we can find the angular velocity of the spool using the kinematic equation:
ω^2 = ω_0^2 + 2 * α * θ
where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:
ω^2 = 2 * α * θ
ω = sqrt(2 * α * θ)
ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))
ω = 166.6 rad/s
Finally, we can find the time it takes for the box to reach the floor using the equation:
v = r * ω
v = 0.10 m * 166.6 rad/s
v = 16.66 m/s
t = d / v
t = 3.50 m / 16.66 m/s
t = 0.21 s
It takes Serina 0.68 hours to drive to school. Her route is 34 km long. What is Serina's average speed on her drive to school?
Speed = distance / time
Speed = 34 km / 0.68 hrs
Speed = 50 km/hr
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15. A puck is set in motion across a frozen pond. Friction and air resistance may be neglected. If you see the puck change its direction but not its speed, then the
force on the puck is
OA Non-zero, and equal to the product of its mass times its weight
OB. Non-zero, and equal to its weight
OC. Zero
OD. Non-zero, and depends on the puck's new direction
Reset Section
Answer:
the answer is equal to non zero
The __ clause of the ___ amendment states that a person born in the United States is a us citizen.
A person born in the United States is considered a citizen of the country, according to the 14th Amendment's "Citizenship" provision.
Citizens of both the United States and the State in which they live include everyone who was born or naturalised in the country and is subject to its laws. No State may enact or carry out any legislation that restricts the rights or privileges of US citizens; no State may rob anyone of their life, liberty, or property without first providing them with a fair trial; and no State shall deny anyone living under its jurisdiction the equal protection of the law.
Based on the first clause of Section 1,1, the Court has determined that a child born in the United States to Chinese parents who were not qualified for naturalisation themselves is nonetheless a citizen of the United States with all the rights.
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In a
DC source, which has more cuwent?
(i)R L Circuit
(ii)RC Circuit (series)
(iii)LC Cirenit (series)
(iv)RLC Circuit (series)
Answer:
Answer is LC Cirenit (seres)
A pilot wants to fly north. The plane has an air speed of
350 km/h. There is a 25 km/h wind blowing to the west.
(a) What is the plane's velocity relative to the ground?
(b)What is its heading?
Explain me in details. I’ll give u the brainliest if you give me the right answer.
Answer:
A? Cause is needs the Velocity more than the Heading.
Hi please answer the question labeled d
If Q1 is 5 times larger than Q2 the force that Q1 exerts on Q2 is?
(greater than, smaller than, or exactly the same as) the force that Q2 exerts on Q1.
part a) If Q increases by 5 times its original value, the electrostatic force (F) will increase5 times as well.
part b) If r is halved (reduced by 2), the force will become four times stronger (since 2² = 4).
part c) If Q1 is positive and Q2 is negative, the charges will attract each other.
part d) If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same.
What is electrostatic force?The electrostatic force is described as the force of attraction or repulsion between two charged particles.
With regards to Coulomb's Law, we have that the electrostatic force between two charges separated by a distance is :
Force = k * (Q1 * Q2) / r²
Where:
F_ = electrostatic force
k = electrostatic constant
Q1 and Q2 = magnitudes of the charges
r = distance
for case a:
If one of the charges, Q1 or Q2, increases by 5 times then the electrostatic force will also increase by 5 times.
case b)
If the distance between the charges, r, is halved, the electrostatic force will become four times stronger because (1/r²).
for case c.
if Q1 is positive and Q2 is negative, the charges will attract each other because of magnetic laws.
for case d.)
If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same as there is a resulting stronger gravitational or electromagnetic force.
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who is sitting in the rear of their boat in still water, entertains Juliet by playing his guitar. After the song, Juliet, who was sitting in the front of the boat (closest to shore), carefully moves to the rear to plant a kiss on Romeo's cheek. The 100-kg boat is facing shore and the 50 kg Juliet moves towards the 70 kg Romeo. The length of the boat is 4 m, and we can neglect water resistance when the boat moves. How far does the boat move? Does it move toward or away from the shore?
Answer:
Δx = -1.27 m
the boat moves away from the shore
Explanation:
Let's analyze the exercise a little, to know when the boat has moved, we can fixate on a point, let's use the point of the center of mass, before and after the movement of people.
The center of mass is defined by.
\(x_{cm}\)= 1 /M ∑ m_i x_i
where M is the total mass of the object, x_i and m_i are the positions and masses of each part of the system.
let's find the total mass
M = m_boat + m_Juliet + m_Romeo
M = 100 + 50 + 70
M = 220 kg
now let's look for the center-mass position
initial. Before the movement of people
x_{cm1} = 1/M (x_boat m_boat + x_juliet m_juliet + x_romeo m_romeo)
Let's find the position of each object, let's fix our reference system on the front of the boat
The boat its center of mass coincides with its geometric center
x_boat = 2 m
Julliet is sitting in the front of the boat
x_juliet = 0 m
Romeo is sitting in the back of the boat
x_romeo = 4 m
we substitute
x_{cm1} = 1/220 (2 100 + 50 0 + 70 4)
x_{cm1} = 2.1818 m
final. After the movement of people
positions
boat
x_boat = 2 m
Juliet
x_juliet = 0 m
Romeo
x_romeo = 0 m
we substitute
x_{cm2} = 1/220 (2 100 + 50 0 + 500 0)
x_{cm2} = 0.9090 m
the movement of the boat is
Δx = x_cm2 - xcm1
Δx = 0.9090 - 2.1818
Δx = -1.27 m
The negative sign indicates that the boat moves in the opposite direction to the movement of people, therefore the boat moves away from the shore
4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)
The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
How to find reaction?To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.
First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:
ΣFy = R − 7 kN − 3 kN
ΣFy = 0
This gives:
R = 10kN
Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:
ΣFx = L
ΣFx = 0
This indicates that there is no horizontal force acting on the structure.
Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).
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