The production rate per hour of a purse factory that can manufacture 200 purses in 8 hours.

Answer:

4 > \(-\frac{n}{4}\)

-16 > n

Step-by-step explanation:

Greater than would mean that the "arrow" is not facing the number. It would mean it is larger than the other number. Also, you have to construct the other part of the inequality which would be \(-\frac{n}{4}\).

4×4 > \(-\frac{n}{4}\)×4

16 > -n

-16 > n

The cosine of angle A is 0.94 (rounded to two decimal places).

To find the cosine of the angle between two vectors,  we will use the cosine similarity formula:

cos(A) = (u · v) / (||u|| ||v||),

where

u · v = the dot product of vectors u and v,

||u|| and ||v|| = the magnitudes of vectors u and v, respectively.

Using the provided vectors, let's find the cosine of angle A:

u = (5, 0, 14) and v = (0, 0, 1)

u · v = (5 * 0) + (0 * 0) + (14 * 1) = 0 + 0 + 14 = 14.

||u|| = √(5² + 0² + 14²) = √(25 + 0 + 196) = √221 ≈ 14.87,

||v|| = √(0² + 0² + 1²) = √(0 + 0 + 1) = √1 = 1.

Placing the values into the formula, we have:

cos(A) = (u · v) / (||u|| ||v||)

cos(A) = 14 / (14.87 * 1)

cos(A) ≈ 0.94 (rounded to two decimal places).

Therefore, the cosine of angle A is 0.94.

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Answer:

$120

Step-by-step explanation:

Total Parts = 3+2+5 = 10

400 / 10 = $40 per part

Amy = 40 x 3 = 120

Answer:

The interval estimate is:

41.5 - 2.45 ≤ true average time ≤ 41.5 + 2.45

or

38.05 ≤ true average time ≤ 44.95

Inequality notation:

[38.05, 44.95]

The interval estimate that will estimate the true average time that people spend brushing their teeth is [39.05, 43.95] seconds.

Given that the mean time spent brushing teeth from the sample is 41.5 seconds, and the margin of error is 2.45 seconds, we can construct a confidence interval estimate using the formula:

(sample mean) ± (margin of error)

Substituting the given values, we get:

41.5 ± 2.45

Simplifying, we get:

[39.05, 43.95]

Therefore, we can be 95% confident that the true average time that all people spend brushing their teeth falls within this interval.

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Answer:

honestly idc use a calculator

Step-by-step explanation:

There are 20 cars traveling at constant speeds on a 1 mile long ring track and the cars can pass each other freely. On the track 25% of the cars are traveling at 20 mph, 50% of the cars are traveling 10 mph, and the remaining 25% of the cars are traveling at an unknown speed. It was known that the space mean speed of all the cars on the track is 20 mph.

Therefore, the total number of cars with speed 20 mph is 0.25 × 20 = 5, and the total number of cars with speed 10 mph is 0.5 × 20 = 10.

Then, 5 cars are left with an unknown speed.

Given that the space mean speed of all the cars on the track is 20 mph,Therefore,5 × v + 10 × 10 + 5 × 20 = 20 × 20= 5v + 200 = 400

Thus, the speed of the remaining 25% of cars is:v = 40 mph(b) If an observer standing on the side of the track counted the number and measured t

Summary If an observer standing on the side of the track counted the number of cars passing him in 1 minute, he would see 20 cars and take 3 minutes to count them all.

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The equation that best represents the number of weeks, p, Poppy needs to save for the jacket is A. 7.00w = 82

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario.

In this situation, Amie earns $24.50 per week for her allowance and she saves $7 of her allowance each week for a new jacket.

Let the number of weeks be w.

The equation will be:

(Amount saved × number of weeks) = Total cost

(7 × w) = 82

7w = 82

The correct option is A

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Answer:

\(328units^2\)

Step-by-step explanation:

First off,  I do want to say that you could word this more easily.

98 is the perimeter. length is 41. width is 8.

the area is length*width for rectangles.

98-41=57

57-41=16

16/2=8

8*41=328 units^2

Since the exponential function is always positive, there is no solution for e^(-2t) = -1/6. This means that the derivative is never equal to zero, and there is no point of maximum steepness for this curve.

To find the point at which the curve is steepest, we need to find the maximum value of the derivative of the function. Let's start by finding the derivative of the given function:

y = 50 / (1 + 6e^(-2t))

To find the derivative, we can use the quotient rule:

y' = [50(0) - (1 + 6e^(-2t))(-12e^(-2t))]/(1 + 6e^(-2t))^2

Simplifying this expression, we get:

y' = (72e^(-2t))/(1 + 6e^(-2t))^2

To find the maximum point, we need to find the value of t for which the derivative is equal to 0. Setting y' = 0 and solving for t, we have:

(72e^(-2t))/(1 + 6e^(-2t))^2 = 0

Since the numerator cannot be zero, we focus on the denominator:

(1 + 6e^(-2t))^2 = 0

Taking the square root of both sides, we get:

1 + 6e^(-2t) = 0

Solving for e^(-2t), we have:

e^(-2t) = -1/6

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Answer:

0.0533

Step-by-step explanation:

first remove the decimal points, then add a zero to the end.

205*

260  0*5,0*0,0*2=0. 6*5=30, but you carry the 3, so its another 0.

6*0+3=3

6*2=12

2*5=10, but you carry the one, so it is 0. 2*0+1=1

2*2=4

1230

4100=

5330, but we moved 0.26 2 spaces forward, and we moved 0.205 3 spaces forward too. in total, that makes 6 spaces, so now we have to move it back. 533-1 space

53.3-2 spaces           5.33-3 spaces          0.533-4   0.0533-5 spaces

Answer:

\( {3}^{3} + 5(4) \div 5 + 8 \\ 9 + 20 \div 13 \\ 29 \div 13 \\ 2.230\)

Answer:

x³ + 5y/w + z =39 is the answer working is down

Step-by-step explanation:

x³ + 5y/w + z

33 + 5×4/5 +8

Calculate

27 + 5×4/5 + 8

Calculate

27+20/5 + 8

Transform the expression

135+20+ 40/5

Calculate

195/5

Simplify

39

The slash (/) means divide!!

Answer:

A. 68 degrees

Step-by-step explanation:

since the segments are congruent, you can be sure that the angles must be opened up to the same degree. They must be the same degree to produce identical segments. since the opposing side is 68 degrees and it has congruency, the angle KOJ is = 68 degrees

The counterclockwise circulation around c is 12 and the outward flux through c is zero.

Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.

In this case,

we have a field f=(7x−4y)i+(9y−4x)j and

a square curve c bounded by x=0, x=4, y=0, y=4.

To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.

The curl of f is given by (0,0,3), so the line integral evaluates to 12.

To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.

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One-half of the dogs in each shelter are between the weights represented by the first and third quartiles, which are approximately 20-55 pounds for the first shelter and 25-65 pounds for the second shelter, respectively.

A box plot is a visual representation of a set of data that shows the median, quartiles, and outliers of the data. The box represents the middle 50% of the data, with the bottom and top edges of the box representing the first and third quartiles, respectively. The line inside the box represents the median, or the middle value of the data set. The "whiskers" extend from the edges of the box to the minimum and maximum values of the data set, but outliers beyond the whiskers are represented as individual points.

Now, let's look at the two box plots showing the weights of dogs in two different animal shelters. One-half of the dogs in each shelter are between the first and third quartiles, which are represented by the edges of the box in each plot.

If we take the first box plot, we can see that the first quartile is approximately 20 pounds and the third quartile is approximately 55 pounds. Therefore, one-half of the dogs in this shelter weigh between 20 and 55 pounds.

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Answer:

8

Step-by-step explanation:

Vertical angles are congruent.  That means that they have the same measurement.  Set them equal to each other and solve for x

x = 4x - 24  Subtract x from both sides of the equation

o = 3x - 24  Add 24 to both sides

24 = 3x  Divide both sides by 3

8 = x

m<A is 8

Answer:

braiiiiiiiiinlllllllyyyyyyyyest

Step-by-step explanation:

Answer:.41 and also take down all thoses tabs theyll mess up your computer

Step-by-step explanation:

Answer:

E

Step-by-step explanation:

Have a good day :)

Answer:

4 and 3 are coefficanta and 12 will be a constant.

if 4 and 3 are being shared by the variable they would be coefficants

if x is not a variable then all the numbers are constants

Step-by-step explanation:

The probability that the next piece of track Carly picks will be straight is 8/24 or 1/3

From the given information, Carly has picked 8 straight, 7 curved, 4 cross, and 5 switch tracks.

The total number of pieces of the track she has picked is 8 + 7 + 4 + 5 = 24

The probability that the next piece of track Carly picks will be straight is calculated as follows:

Probability = Number of straight tracks/Total number of tracks= 8/24= 1/3T

Therefore, the probability that the next piece of track Carly picks will be straight is 1/3.

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Answer: 1/3

Step-by-step explanation: i did this question and got it right

Answer:

b) y = (1/4)x+2

Step-by-step explanation:

In slope intercept form, y = mx + b, m is the slope and b is the intercept. Plug in the provided answers to the formula and you have an equation.

a) To find a 95% confidence interval for the mean mass of the concrete blocks, we will use the formula:

Confidence interval = mean ± (critical value * standard deviation / square root of sample size)

The critical value for a 95% confidence level is 1.96 (based on the standard normal distribution).

Plugging in the values, we have:

Confidence interval = 38.3 ± (1.96 * 0.6 / √75)

Calculating this, we get:

Confidence interval ≈ 38.3 ± 0.162

Therefore, the 95% confidence interval for the mean mass of the concrete blocks is approximately 38.138 kg to 38.462 kg.

b) To find a 99% confidence interval for the mean mass of the concrete blocks, we will use the same formula as above, but with a different critical value.

The critical value for a 99% confidence level is 2.62 (based on the standard normal distribution).

Plugging in the values, we have:

Confidence interval = 38.3 ± (2.62 * 0.6 / √75)

Calculating this, we get:

Confidence interval ≈ 38.3 ± 0.215

Therefore, the 99% confidence interval for the mean mass of the concrete blocks is approximately 38.085 kg to 38.515 kg.

c) To determine the level of confidence for the engineer's claim, we need to see if the claim falls within the calculated confidence intervals.

The engineer's claim states that the mean mass is between 38.2 kg and 38.4 kg.

Based on the 95% confidence interval calculated in part (a), the engineer's claim falls within the interval of 38.138 kg to 38.462 kg.

Therefore, the engineer's claim can be made with a 95% confidence level.

d) To determine the number of blocks needed for a 95% confidence interval to specify the mean mass within ±0.1 kg, we can rearrange the formula for the confidence interval:

Sample size = (critical value * standard deviation / margin of error)²

The margin of error is ±0.1 kg. The critical value for a 95% confidence level is 1.96 (based on the standard normal distribution).

Plugging in the values, we have:

Sample size = (1.96 * 0.6 / 0.1)²

Calculating this, we get:

Sample size ≈ 6.0756²

Therefore, we would need a sample size of approximately 37 blocks to achieve a 95% confidence interval that specifies the mean mass within ±0.1 kg.

e) To determine the number of blocks needed for a 99% confidence interval to specify the mean mass within ±0.1 kg, we use the same formula as above, but with a different critical value.

The critical value for a 99% confidence level is 2.62 (based on the standard normal distribution).

Plugging in the values, we have:

Sample size = (2.62 * 0.6 / 0.1)²

Calculating this, we get:

Sample size ≈ 9.924²

Therefore, we would need a sample size of approximately 99 blocks to achieve a 99% confidence interval that specifies the mean mass within ±0.1 kg.

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Using the information, combine the individual probabilities to compute the probability that Peter will pass the quiz is (c) 0.0035.

To compute the probability that Peter will pass the quiz (i.e., get at least 7 questions correct), we need to sum the probabilities of getting exactly 7, exactly 8, exactly 9, and exactly 10 questions correct.

So, the probability of passing the quiz is:

P (getting at least 7 correct) = P (getting exactly 7 correct) + P (getting exactly 8 correct) + P (getting exactly 9 correct) + P (getting exactly 10 correct)

= 0.0031 + 0.000386 + 2.86 × 10⁻⁵ + 9.54 × 10⁻⁷

= 0.0035

Therefore, the result is c. 0.0035.

The binomial formula can be used to solve a wide range of problems in probability and statistics. The binomial formula is used to calculate the probability of getting a specific number of successes in a fixed number of independent trials, where each trial has only two possible outcomes (success or failure).

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Answer:

Radius = 10

Step-by-step explanation:

Volume of a cylinder=πr^2h

1600πcm^3=πxr^2x16

π cancels out

1600=r^2x16

1600/16=r^2

100=r^2

√100=r

r=10

Answer:

just add lool

Step-by-step explanation:

Area :-

\(\\ \rm\rightarrowtail side^2\)

\(\\ \rm\rightarrowtail 13^2\)

\(\\ \rm\rightarrowtail 169\)

Square root:-

Thus, the equation of the plane determined by the intersecting lines L1 and L2 is: -2x + 14y + 18z - 48 = 0.

To find the plane determined by the intersecting lines L1 and L2, we need to find a normal vector to the plane.

First, we'll find two direction vectors for the lines L1 and L2.

For L1:

x = -1 + t

y = 2 + 4t

z = 1 - 3t

Taking the differences of these equations, we obtain two direction vectors for L1:

v1 = <1, 4, -3>

For L2:

x = 1 - 4s

y = 1 + 2s

z = 2 - 2s

Again, taking the differences of these equations, we obtain two direction vectors for L2:

v2 = <-4, 2, -2>

Since the plane contains both lines, the normal vector to the plane will be perpendicular to both direction vectors, v1 and v2.

To find the normal vector, we can take the cross product of v1 and v2:

n = v1 x v2

n = <1, 4, -3> x <-4, 2, -2>

Using the cross product formula, the components of the normal vector n can be calculated as follows:

n = <(4 * -2) - (-3 * 2), (-3 * -4) - (1 * -2), (1 * 2) - (4 * -4)>

n = <-8 - (-6), 12 - (-2), 2 - (-16)>

n = <-2, 14, 18>

So, the normal vector to the plane determined by the intersecting lines L1 and L2 is n = <-2, 14, 18>.

Now we can write the equation of the plane using the normal vector and a point on the plane (which can be any point on either L1 or L2).

Let's choose the point (-1, 2, 1) on L1.

The equation of the plane can be written as:

-2(x + 1) + 14(y - 2) + 18(z - 1) = 0

Simplifying:

-2x - 2 + 14y - 28 + 18z - 18 = 0

-2x + 14y + 18z - 48 = 0

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Answer:

1.Equivalent

2.Equaivalent

3.Not Equivalent

4.Equivalent

Answer:x=-7+1/2

Step-by-step explanation:You move all terms to the left: x-15/2-(2x)=0

then add all the numbers together, and all the variables:-1x-15/2=0

You multiply all the terms by the denominator:-1x*2-15=0

Multiply elements:-2x-15=0

You move all terms containing x to the left, all other terms to the right-2x=15

x=15/-2

x=-7+1/2

Step-by-step explanation:

F(x) = 4x^3 - 3x^2 + 5 neither

F(x) = -7x^2+1 even

y = cos (-x) even

y = csc x odd

y = sin x/cos x odd