The probability of winning a three-person game of rock paper scissors is 1/3. If you just
won the last 2 rounds, what is the probability you will win the next round?

a. 1/27
b. 1/9
c. 2/3
d. 1/3
e. 1/18

The real-world problem involving a related set of two equations is given below:

Problem: Cost of attending a concert  is made up of base price and variable price per ticket. You are planning to attend a concert with your friends and want to know the number of tickets to purchase for lowest overall cost.

The related set of two equations are:

Equation 1: The total cost (C) of attending the concert is given by:

The equation C = B + P x N,

where:

B  = the base price

P  = the price per ticket,

N = the number of tickets purchased.

Equation 2: The maximum budget (M) a person have for attending the concert is:

The  equation M = B + P*X

where:

X = the maximum number of tickets a person can afford.

So by using the values of B, P, and M, you can be able to find the optimal value of N that minimizes the cost C while staying within your own budget M. so, you can now determine ticket amount to minimize costs and stay within budget.

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The requirements for a hypothesis test are satisfied.

To test the claim that the rate of polio is less for children given the Salk vaccine, we need to check if the requirements for a hypothesis test about two population proportions are met. The requirements are:

1. The samples are simple random samples and independent.
2. For each of the two groups, the sample size is at least 1000.

In this case, the study involved 401,974 children who were randomly assigned to two groups: the treatment group with 201,229 children and the placebo group with 200,745 children. This satisfies the first requirement, as the samples are simple random samples and independent. The sample size for both groups is also larger than 1000, meeting the second requirement.

Therefore, the requirements for a hypothesis test are satisfied, and we can proceed with testing the claim that the rate of polio is less for children given the Salk vaccine.

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Answer:

C and D

Step-by-step explanation:

\( \frac{k}{2} = \frac{1}{2} k = k \div 2\)

Answer:

c and d

Step-by-step explanation:

yes thats the answer

Answer:

rectangular prism

Step-by-step explanation:

a.  We are 95% confident that the true average porosity of the seam is between 4.25 and 5.45.

b. We are 98% confident that the true average porosity of the seam is between 3.68 and 5.44.

c. A sample size of at least 14 is necessary.

d. A sample size of at least 138 is necessary.

a. To compute a 95% confidence interval for the true average porosity of a certain seam, we use the formula:

CI = x ± tα/2 (s/√n)

where x is the sample average porosity, s is the sample standard deviation, n is the sample size, and tα/2 is the t-value with n-1 degrees of freedom and α/2 probability (0.025 for a 95% confidence interval).

Substituting the given values, we get:

CI = 4.85 ± 2.093 (0.75/√20)

= (4.25, 5.45)

Therefore, we are 95% confident that the true average porosity of the seam is between 4.25 and 5.45.

b. To compute a 98% confidence interval for the true average porosity of another seam, we use the same formula as in part (a), but with a different t-value (2.602 for a 98% confidence interval).

Substituting the given values, we get:

CI = 4.56 ± 2.602 (0.75/√16)

= (3.68, 5.44)

Therefore, we are 98% confident that the true average porosity of the seam is between 3.68 and 5.44.

c. To find the necessary sample size for a 95% confidence interval with a width of 0.40, we use the formula:

n = (tα/2 (s/width))^2

Substituting the given values and solving for n, we get:

n = (1.96 (0.75/0.40))^2

= 13.55

Therefore, a sample size of at least 14 is necessary.

d. To find the necessary sample size for a 99% confidence interval with a width of 0.2, we use the same formula as in part (c), but with a different t-value (2.576 for a 99% confidence interval).

Substituting the given values and solving for n, we get:

n = (2.576 (0.75/0.2))^2

= 137.68

Therefore, a sample size of at least 138 is necessary.

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Inequality stating that there are 8000 sq. m. of land available: Let B be the number of units of house B and C be the number of units of house C.

Therefore,B+C ≤ 8000/200 [Reason: House C requires 200 sq. m. of land]⇒B+C ≤ 40b. Inequality that the engineer has at most 6400 man-hour available for construction:

160B + 256C ≤ 6400c

Inequality stating that the engineer has at least 12 million pesos to spend for materials:

600B + 800C ≤ 12000d

. Let us write down a table to calculate the cost, income and profit as follows:Units of house BLabor Hours per unit of house BUnits of house CLabor Hours per unit of house CTotal Labor HoursMaterial Cost per unit of house BMaterial Cost per unit of house CTotal Material CostIncome per unit of house BIncome per unit of house C

Total IncomeTotal ProfitBC=8000/200-B160CB+256C600000800000+256C12,000,0003,500,0004,000,0003,500,000B+C ≤ 40 160B + 256C ≤ 6400 600B + 800C ≤ 12000 Units of house B requires 160 man-hour and a unit of house C requires 256 man-hour.

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Let's write and equation for both cases.

In plan 1, it is 500 plus 3% comission. 3% is equivalent to multiply the amount it sale in the week, "x", by 0.03.

So, the equation for plan 1 is:

For plan 2, there is no fixed value, only comission of 5%, which is equivalent of multiplying the weekly sales, "x", by 0.05, so the equation is:

For both plans to result in the same salary, we have:

So, for both plans to result in the same salary, she have to sale 25,000 in a week.

The candy store will use 103 grams of sugar in 10 hours.

To find out how many grams of sugar the store will use in 10 hours, we can simply multiply the amount of sugar used in one hour (10.3 grams) by the number of hours (10).

To solve the problem, we use a simple multiplication formula: the amount used per hour (10.3 grams) multiplied by the number of hours (10) to find the total amount of sugar used in 10 hours.

We can interpret this problem using a rate equation: the rate of sugar usage is 10.3 grams/hour, and the time period is 10 hours. Multiplying the rate by the time gives the total amount of sugar used.

So the calculation would be:

10.3 grams/hour x 10 hours = 103 grams

Therefore, the candy store will use 103 grams of sugar in 10 hours.

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Answer:

6y + 11x

Step-by-step explanation:

Let's simplify step-by-step.

6y+4x+7x

Combine Like Terms:

=6y+4x+7x

=(4x+7x)+(6y)

=11x+6y

Answer:The answer would be the first one 6y + 11x

Step-by-step explanation:All you would have to do is do 4x + 7x which would equal 11x. So the answer would be 6y +11x

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Number of recipes already known = 4

Number of new recipes learnt per week = 3

Relationship between number of weeks and appetizer recipe :

y = 3w

number of weeks = w

Number of appetizer recipe = y

B.) Linear equation:

y = mx + c

x and y are the independent(x = number of weeks) and dependent variables (y = number of recipes learnt)

C = intercept, value of y, when x = 0 ; number of recipes already known before learning ; 4

m = gradient change in y per change in x; number of recipes Learnt per week ; m = 3

y = 3x + 4

Number of recipes known after 18 weeks :

x = 18

y = 3(18) + 4

y = 54 + 4

y = 58

58 recipes

After 18 weeks, Tara would have learnt (18 * 3) = 54 new recipes plus the already known 4 = (54 + 4) = 58

Answer:

4 1/2

Step-by-step explanation:

4 full sections of 2 and one section that is just 1

also 3 divided by 2/3 is also 9/3 divided by 2/3 and 2 goes into 4.5 times

the value of the iterated integral is (π/8) (2 - e^(-16)).

We have the iterated integral:

∫[0,4] ∫[0,√(16-x^2)] e^(-x^2-y^2) dy dx

To convert this to polar coordinates, we need to express x and y in terms of r and θ.

We have:

x = r cos(θ)

y = r sin(θ)

We also need to express the differential element dA in terms of polar coordinates. We have:

dA = r dr dθ

Substituting these expressions into the given integral, we get:

∫[0,π/2] ∫[0,4] e^(-r^2) r dr dθ

The limits of integration for θ are 0 to π/2 because the region lies in the first and second quadrants.

We can evaluate this integral using the fact that the integral of e^(-r^2) is √π/2:

∫[0,π/2] ∫[0,4] e^(-r^2) r dr dθ

= ∫[0,π/2] [-1/2 e^(-r^2)] [0,4] dθ

= ∫[0,π/2] (1/2 - 1/2 e^(-16)) dθ

= π/4 - π/8 (1 - e^(-16))

= (π/8) (2 - e^(-16))

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The set of all triples of real numbers with the standard vector addition but with scalar multiplication defined by k(x, y, z) = (k²x, k²y, k²

What are the real numbers?

Real numbers are a set of numbers that includes all the rational and irrational numbers. The set of real numbers is denoted by the symbol R.

We need to check if the set of all triples of real numbers with the standard vector addition, denoted by (V, +), and scalar multiplication defined by k(x, y, z) = (k²x, k²y, k²z), denoted by (V, ·), is a vector space.

First, we need to check the vector space axioms:

Closure under addition: For any vectors u = (u1, u2, u3) and v = (v1, v2, v3) in V, their sum u + v = (u1 + v1, u2+v2, u3+v3) is also in V. This is true since the standard vector addition is used.

Commutativity of addition: For any vectors u, v in V, u + v = v + u. This is true since the standard vector addition is commutative.

Associativity of addition: For any vectors u, v, w in V, u + (v + w) = (u + v) + w. This is true since the standard vector addition is associative.

Identity element of addition: There exists a vector 0 in V, called the zero vector, such that for any vector u in V, u + 0 = u. The zero vector is (0, 0, 0), and this axiom holds.

Inverse elements of addition: For any vector u in V, there exists a vector -u in V, called the additive inverse of u, such that u + (-u) = 0. This is true since the standard vector addition is used.

Closure under scalar multiplication: For any vector u in V and any scalar k, k · u = (k²u1, k²u2, k²u3) is also in V. This is true since scalar multiplication is defined as k(x, y, z) = (k²x, k²y, k²z).

Distributivity of scalar multiplication over vector addition: For any vectors u, v in V and any scalar k, k · (u + v) = k · u + k · v. This is true since scalar multiplication is defined using the standard scalar multiplication of the real numbers.

Distributivity of scalar multiplication over scalar addition: For any vector u in V and any scalars k, l, (k + l) · u = k · u + l · u.

This is true since scalar multiplication is defined using the standard scalar multiplication of the real numbers.

Associativity of scalar multiplication: For any vector u in V and any scalars k, l, (kl) · u = k · (l · u).

This is true since scalar multiplication is defined using the standard scalar multiplication of the real numbers.

The identity element of scalar multiplication:

For any vector u in V, 1 · u = u, where 1 is the multiplicative identity of the real numbers.

This is not true in this case, since 1 · (x, y, z) = (x, y, z), whereas the scalar multiplication defined in this problem is k(x, y, z) = (k²x, k²y, k²z).

Thus, the set of all triples of real numbers with the given operations is not a vector space, since it violates the identity element of scalar multiplication axiom.

Therefore, the set of all triples of real numbers with the standard vector addition but with scalar multiplication defined by k(x, y, z) = (k²x, k²y, k²).

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What is the correct answer for the mathematics equation 9 + 10 = is that to simple or too hard to answer

9 + 10 would = 19

I hope this helps~

No, they should not adjust the parameters to weaken that character based on this sample alone.

To make a decision about adjusting the parameters of a character based on a test of significance, we need to determine if the observed outcome (winning 232 out of 400 contests) is unlikely to occur by chance alone, assuming the character's current parameters are the same. This is done by calculating a p-value, which represents the probability of observing a result as extreme or more extreme than the one we observed, assuming the null hypothesis is true (i.e., the parameters are the same).

If the p-value is very small (e.g., less than 0.05), we reject the null hypothesis and conclude that the observed outcome is unlikely to occur by chance alone and that the character's parameters may need to be adjusted. However, if the p-value is not small (e.g., greater than 0.05), we fail to reject the null hypothesis and conclude that the observed outcome is not statistically significant and that the character's parameters may not need to be adjusted.

In this case, we can calculate the p-value using a binomial test. The null hypothesis is that the probability of winning a contest is 0.5 (i.e., the character is equally likely to win or lose). The alternative hypothesis is that the probability of winning is less than 0.5 (i.e., the character is more likely to lose). Using a one-tailed binomial test with a significance level of 0.05, we find that the p-value is approximately 0.013, which is less than 0.05. Therefore, we reject the null hypothesis and conclude that the observed outcome is statistically significant and that the character's parameters may need to be adjusted.

However, it is important to note that this decision should not be based solely on this sample. It is possible that the sample is not representative of the true population of contests involving the character, and that a larger sample may lead to a different conclusion. Therefore, it is important to consider the context of the situation and gather additional information before making a final decision about adjusting the character's parameters.

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Answer:

-1 or anything lower than -1

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

0.7

Step-by-step explanation:

7 ÷ 10 = 0.7

Answer:

0.7 = 10=7.

I hope I helped

Step-by-step explanation:

10= 7.

Answer:

63, 15, 90

Step-by-step explanation:

a) ⟨α∣ΔA^α∣α⟩ = ⟨α∣A^2∣α⟩ - ⟨α∣A^∣α⟩

b) If ∣α⟩ is an eigenstate of A^, the variance vanishes.

c) [ΔA^α, ΔB^α] = [A^, B^]

a) To show that ⟨α∣ΔA^α∣α⟩ = ⟨α∣A^2∣α⟩ - ⟨α∣A^∣α⟩, we start with the definition of the Hermitian operator ΔA^α = A^−⟨α∣A^∣α⟩. We substitute this expression into ⟨α∣ΔA^α∣α⟩, which gives us ⟨α∣A^2∣α⟩ - ⟨α∣A^∣α⟩.

b) If ∣α⟩ is an eigenstate of A^, it means that A^∣α⟩ = α∣α⟩, where α is a constant. In this case, when we calculate the variance of ΔA^α, we find that ⟨α∣ΔA^α∣α⟩ = ⟨α∣A^2∣α⟩ - ⟨α∣A^∣α⟩ = ⟨α∣α∣α⟩ - ⟨α∣α∣α⟩ = 0. Therefore, the variance vanishes.

c) To show that [ΔA^α, ΔB^α] = [A^, B^], we first express ΔA^α and ΔB^α in terms of A^ and B^ using their definitions. We then calculate the commutator [ΔA^α, ΔB^α] by substituting the expressions and applying the commutation relations of A^ and B^. After simplification, we find that [ΔA^α, ΔB^α] = [A^, B^], which shows that the commutator of the variances is equal to the commutator of the operators.

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Answer:

I,dont know but use M A T H W A Y it will explain with all the stepp by step and answere

Step-by-step explanation:

Answer:

- 6 and - 4

Step-by-step explanation:

Given

- \(\frac{1}{2}\) x + 4 ≥ 6 ( subtract 4 from both sides )

- \(\frac{1}{2}\) x ≥ 2

Multiply both sides by - 2 to clear the fraction, reversing the symbol as a result of multiplying by a negative quantity.

x ≤ - 4

The only values from the set which satisfy the inequality are

- 4 and - 6

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The distance between the point Q and the ground is, h-[L cos(80°)].

Since, The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

tan θ = perpendicular / base

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The Base is the adjacent smaller side of the angle θ.

Let the height of the support be h and the height between the point q and the ground is x. Also, the distance between point Q and the support of the seesaw is L.

Now if we look at the ΔQAR, the measure of the ∠QRA is 80°, therefore, the sine of ∠QRA can be written as,

cos θ = base / perpendicular

cos ∠QRA = AR/QR

cos ∠QRA = (h - x) / L

L × cos ∠QRA = (h - x)

x = h - L cos ∠QRA

Hence, the distance between the point Q and the ground is,

⇒ h-[L cos(80°)].

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The number of 8-character passwords that consist of 8 different letters that are in alphabetical order such that each letter can be uppercase or lowercase is 26C8 x 2⁸, which is approximately equal to 5.58 x 10¹².

To arrive at this answer, we first need to choose 8 letters out of 26, which can be done in 26C8 ways. Then, we need to assign each of these 8 letters to either an uppercase or lowercase letter, giving us 2 possibilities for each letter.

Therefore, there are 2⁸ possible ways to assign cases to the letters. Multiplying these two values together gives us the total number of possible passwords.

Note that we assume that the letters must be in alphabetical order, which greatly reduces the number of possible passwords. If we did not require alphabetical order, the number of possible passwords would be much larger.

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The given eqation is:

Notice that the slope of the line is 4

Recall that the slopes of parallel lines are equal

Hence the slope of the required line is 4.

Since the line passes through the point (5,1)

The equation is:

This is simplified to give:

Therefore the equation of the line is:

Answer:

a+7b+3a-4b+5c

4a+3b+5c

Hope you have a good day, Loves!~

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

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Complete question

The system of equations below has no solution.

2/3x + 5/2y = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?