the pressure inside a tire is measured as 28.0 poundsinch2. what is its pressure in newtonscentimeter2? 1 pound

Answer:

c...........................

Like forces (vectors), moments can be added together to determine their collective effect known as the resultant moment.

By performing a series of equivalent transformations, you will see that any loading system can be replaced with a simpler statically equivalent system consisting of one resultant force at a specific point and one resultant moment.

Force system results provide a convenient representation for complex force interactions at engineering connections, which we will use in a variety of contexts later. For the time being, we will concentrate on the specifics of reducing a system to a single force and couple.

The resultant force, moment, or both may be zero depending on the original loading system. If they both equal zero, the object is in equilibrium under this load condition. If they are not zero, the supports must provide an equal amount of support.

R=∑F=F1+F2+F3+....

The resultant moment,  MO,  about a point  O,  can be found from adding all of the moments  M,  about that point, including both  r×F  moments and concentrated moments.

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Answer:

Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration

Answer:

Resistance is a measure of the opposite to current flow in an electrical circuit. Resistance is measured in ohms.

Hope this helps

negotiation.

SANA MAKATULONG.

In the conflict resolution, promotes competition a win-lose outcome. Competition results into conflict when two parties tend to seek control over a situation.

Competition results when one's own needs are advocated over the needs and requirements of others. It relies on an aggressive style of communication, which is of low regard for future relationships, and the exercise of coercive power. Those who are using a competitive style tend to seek control over a situation, in both the substance and ground rules.

There are times, when competition between two individuals can escalate into an unproductive, and dangerous conflict. The danger can range from unproductive behavior of a person to unethical behavior which could include physical attack. This results into a win-lose outcome.

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The drift velocity v will give us the answer.

\(v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))\)

To find the drift velocity of charges in the wire, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the applied voltage and inversely proportional to the resistance. The equation for Ohm's Law is:

I = V / R

Where:

I is the current flowing through the wire,

V is the applied voltage (in this case, 5 Volts),

R is the resistance of the wire (given as 10^2 Ohms).

Now, we need to calculate the current flowing through the wire using Ohm's Law. The current is the rate at which charges (electrons) move through the wire. The equation for current is:

I = n * A * v * q

Where:

n is the number of charges per unit volume (given as 2x10^20 electrons),

A is the cross-sectional area of the wire (given as 2 mm² or 2x10^-6 m²),

v is the drift velocity of the charges (what we need to find),

q is the charge of each electron (1.6x10^-19 C).

Rearranging the equation and solving for v, we have:

v = I / (n * A * q)

Substituting the given values:

v = (5 V) / ((2x10^20 electrons/m³) * (2x10^-6 m²) * (1.6x10^-19 C))

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The velocity of the combined weight at rest following the collision. 15 m/sec.

The amount of material that makes up every object and body is the simplest method for comprehending mass. Everything that we can see has mass. Examples of objects with mass include a desk, a seat, your mattress, a football, a glass, or even air. The mass of a thing determines whether it is light or heavy.

A measure of how much matter is present in or makes up a physical body. In classical mechanics, an object's mass is crucial to Newton's motion laws because it influences the force needed to accelerate it and, consequently, how much inertia it has.

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Answer:

rotation

Explanation:

Im pretty sure. Please heart and mark brainliest

Answer:

cycle

Explanation:

either rotation or cycle. I would think.

The total sound intensity level in dB is approximately 96 when two dogs are barking at the same intensity level.

What is the total sound intensity level in dB when two dogs are barking at the same intensity level?

Hi! To answer your question about the sound intensity level of two dogs barking: A single dog barks at a sound intensity level of 8, which is equal to 93 dB. We have randomized variables: 8 = 93 dB, and 50% is irrelevant in this case.

Another dog runs up beside the first dog and starts barking at the same sound intensity level. To find the total sound intensity level in dB that you hear from the two dogs barking, we can follow these steps:

Convert the dB levels to intensity values (I1 and I2) using the formula:
I = 10^(dB/10)
For both dogs, I1 = I2 = 10^(93/10) = 1.995 × 10^9

Add the intensity values together:
I_total = I1 + I2 = 1.995 × 10^9 + 1.995 × 10^9 = 3.99 × 10^9

Convert the total intensity value back to dB using the formula:
dB_total = 10 * log10(I_total)
dB_total = 10 * log10(3.99 × 10^9) ≈ 96 dB

So, when the two dogs are barking at the same sound intensity level, you hear a total sound intensity level of approximately 96 dB.

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Answer:

120km

Explanation:

it will covered 120km

Answer:

\(F_{g} = 4.8\) × \(10^{-7}\) \(N\)

Explanation:

The law of gravitational attraction states :

\(F_{g} = G\frac{Mm}{R^{2} }\)

G is the gravitational constant \((6.67\) × \(10^{-11}\)\()\)

M is the larger mass (kg)

m is the smaller mass (kg)

R is the distance separating the two objects (\(m^{2}\))

∴ \(F_{g} =\) \((6.67\) × \(10^{-11}\)\()\)  \((4000)(180)/(10)^{2}\)

\(F_{g} = 4.8\) × \(10^{-7}\) \(N\) is the gravitational force between the elephant and the lion.

Answer:

n =1.33 revolutions

Explanation:

Uniform Circular Motion

The angular speed can be calculated in two different ways:

\(\displaystyle \omega=\frac{v}{r}\)

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\(\omega=2\pi f\)

Where:

f = frequency

Solving for f:

\(\displaystyle f=\frac{\omega}{2\pi}\)

Since the frequency is calculated when the number of revolutions n and the time t are known:

\(\displaystyle f=\frac{n}{t}\)

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\(\displaystyle \omega=\frac{25}{90}\)

\(\displaystyle \omega=0.278\ rad/s\)

Now we calculate f:

\(\displaystyle f=\frac{0.278}{2\pi}\)

\(f=0.04421\ Hz\)

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

The scientific theory cannot be accepted immediately, because there is always the possibility of discovering new information or modification.

A scientific theory is an explanation of the natural world and universe that has been repeatedly tested in accordance with the scientific method. Theories are tested under controlled conditions in an experiment and are evaluated through principles of abductive reasoning.

A scientific theory differs from scientific law in that a theory explains how or why is a basic observation, whereas a law is a statement about a relationship between facts. Newton’s Law of Gravity is a mathematical equation that can be used to find the attraction between objects, but it is not a theory to describe how gravity works.

If experimental results contrary to predictions of the theory are observed, scientists evaluate whether the experimental design was good and confirm the results by independent replication.

Solutions may need some changes to the theory, or none at all, and after the successive modifications, theories consistently improve and greater accuracy is achieved.

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Answer:

true

Explanation:

just took the test

Answer:

True

Explanation:

Answer:

W = 1493.9 J = 1.49 KJ

Explanation:

The work done by the elevator on the object will be equal to the gain in is potential energy:

W = ΔP.E

W = mgΔh

where,

W = Work = ?

m = mass of object = 7.4 kg

g = 9.8 m/s²

Δh = gain in height = 20.6 m

Therefore,

W = (7.4 kg)(9.8 m/s²)(20.6 m)

W = 1493.9 J = 1.49 KJ

The total weight of the riders lifted into air is determined as 10,290 N.

The total weight of the riders lifted into air is calculated by applying the following kinematic equation as shown below.

Mathematically, the total weight of the riders is calculated as follows;

W = Nmg

where;

W = ( 15 ) ( 70 kg ) ( 9.8 m/s² )

W = 10,290 N

Thus, the total weight lifted by the rider is a function of the individual mass of the riders.

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Answer:

Weight

a) weight's vertical component = Normal upward force

b) weight's horizontal component = Friction force = (mass of ball)(acceleration)

These forces depend upon the track,

1) inclined or horizontal

2) steepness.

Explanation

The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.

weight's horizontal component = Friction force = (mass of ball)(acceleration)

The other component pushes the ball into the ramp, and the ramp pushes back.

If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest

Explanation:

Science later greatly advanced when Galileo favored experiment over philosophical discussions is the correct statement.

Galileo Galilei, an Italian physicist, mathematician, and astronomer, is considered one of the pioneers of the scientific method. He played a crucial role in advancing scientific knowledge during the Scientific Revolution in the 16th and 17th centuries.

Galileo's approach to science emphasized empirical evidence and experimentation. He believed that the best way to understand the natural world was through direct observation and measurement. Galileo's famous experiments, such as his studies of falling bodies and his observations of celestial objects through telescopes, provided concrete evidence that challenged prevailing philosophical and Aristotelian views.

While Galileo did engage in philosophical discussions and debates, his emphasis on experimentation and empirical evidence set him apart from the prevailing philosophical traditions of his time. His reliance on observation, measurement, and repeatable experiments laid the foundation for the scientific method and greatly advanced scientific thinking.

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Answer:

30 M/S

Explanation:

25×120×÷100 = 30 M/S

Sorry if the answer wrong

i try mu best to help u

tq

The new pressure of the gas after expanding to a volume of 10.00 L is 0.75 atm. The correct answer is (a) 0.75 atm.

To find the new pressure of a gas that initially has a pressure of 2.50 atm and a volume of 3.00 L and expands to a volume of 10.00 L, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature and amount of gas remain constant.

Boyle's Law formula: P1 * V1 = P2 * V2

Plug in the initial pressure (P1) and volume (V1), as well as the final volume (V2).
(2.50 atm) * (3.00 L) = P2 * (10.00 L)

Solve for the new pressure (P2).
P2 = (2.50 atm * 3.00 L) / 10.00 L

Calculate P2.
P2 = 7.50 atm / 10.00 L = 0.75 atm

After growing to a volume of 10,000 litres, the petrol has a new pressure of 0.75 atm. The appropriate response is (a) 0.75 atm.

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If I am not mistaken it is Japan

Free fall motion is motion in which the only force acting on the body is gravity.

A free-falling object is one that moves only due to the effect of gravity, and its motion is defined by Newton's second law of motion. We can use algebra to calculate the acceleration of a free-falling particle.

The student should launch the sphere at 2v₀, for the sphere will land at approximately 1.41D, which is in the 3 point zone

The given parameter are;

The distance covered by the sphere when launched at height, H = D

The velocity with which the ball reaches D = v₀

The current available height of launcher= H/2

The available velocities = v₀, and 2v₀

Now,

From H = ut + (1/2)gt², where, initial velocity of the vertical motion of the ball, u = 0

we know;

H = (1/2)gt²

Therefore, the time it takes the ball to drop from H, t = √(2H/g)

The distance, D = v₀ × √(2H/g)

When the height is H/2, we get;

t = √(2H/(2g)) = √(H/g)

Thus, the distance covered, D₁ = v₀ × √(H/g)

Therefore, D = (√2) × v₀ × √(H/g) = (√(2))D₁

Now, D₁ = D/(√2) ≈ 0.71D

D₁ ≈ 0.71D

At speed 2v₀, we have;

D₂ = 2v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2H/g) = √2D₁ ≈ 1.41D

D₂ ≈ 1.41D

The 2 point zone = D/2 < x < D = 0.5D < x < D (Position D₁ ≈ 0.71D is located here)

The 3 Point Zone =  D < x < 3D/2 = D < x < 1.5D (Position D₂ ≈ 1.41D is located here)

Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2v₀, so that the ball will land at D₂ ≈ 1.41D,  which is in the 3 Point Zone

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The complete question is as follows:

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.

The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.

When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.

Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.

Answer: A rolling ball eventually slows down and comes to a stop.

Explanation: Right on Edge2020, not C or B or D.

Answer:

A

Explanation:

Person above me might be right

False. someone with the characteristics of an autotelic personality does not prefer medium-skill, high-challenge situations to stimulate growth.

Contrary to the statement,  In fact, individuals with an autotelic personality are more inclined towards high-skill, high-challenge situations. The term "autotelic" refers to a person's ability to find intrinsic satisfaction and enjoyment in activities for their own sake, rather than relying on external rewards or motivations. These individuals actively seek out tasks and endeavors that require their full engagement and offer opportunities for personal growth, learning, and mastery.

Autotelic individuals thrive when their existing skills are matched with challenging situations that push their limits. By immersing themselves in demanding activities, they enter a state of flow, where they feel completely absorbed and in the zone. This optimal state of engagement leads to a sense of fulfillment and enhances their overall well-being. It is through these high-skill, high-challenge tasks that individuals with an autotelic personality experience the most growth and development.

In summary, an autotelic personality is characterized by a preference for high-skill, high-challenge situations rather than medium-skill, high-challenge situations. They actively seek out opportunities to stimulate their personal growth and find intrinsic satisfaction in pushing themselves beyond their current abilities.

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The planetary properties that are measurable with current extrasolar planet detection includes:

Mass

Radius

Orbital Period

Orbital Eccentricity

Atmospheric Composition

The mass of an exoplanet can be determined through various techniques such as radial velocity measurements, transit timing variations, or astrometry.

On the other hand, the radius of an exoplanet can be estimated from transit observations that  measure the decrease in brightness of the host star as the planet passes in front of it.

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1) Note that the Roof is dark colored. Given the laws of physics, it will absorb all light.

2) the window is transparent, hence, it will transmit ALL light.

3) the door is dark-colored but has some glass on it. Thus, it will absorb MOST but not all light.

4) the side of the building which is painted white will reflect all light.

Note that dark surfaces absorb light because they are able to absorb photons, or particles of light, and convert them into other forms of energy.

This is because the atoms and molecules in dark surfaces have a large number of unpaired electrons that are able to absorb the energy of photons and transition to a higher energy state.

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