The planet that has an axis that points roughly straight up, and thus has no seasons to speak of, is

According to the problem The barbell's mass is 178 kg.

What is barbell's mass ?

The mass of a barbell can vary depending on the size and type of barbell. Standard barbells typically range from 10 kilograms (22 pounds) to 45 kilograms (99 pounds). Olympic barbells are typically 25 millimeters (1 inch) in diameter and are available in weights ranging from 15 kilograms (33 pounds) to 25 kilograms (55 pounds). Barbells with a smaller diameter, such as a women's barbell, usually weigh between 5 kilograms (11 pounds) and 15 kilograms (33 pounds). Powerlifting barbells are thicker and longer than standard barbells and usually weigh between 20 kilograms (44 pounds) and 25 kilograms (55 pounds).

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The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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Answer:

t = 4.5 second

Explanation:

A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function as follows :

\(h(t)=-16t^2+144t\)

t is time in seconds

We need to find the time when the rocket return to the ground.

When it reaches ground, h(t) = 0

So,

\(-16t^2+144t=0\\\\t(-32t+144)=0\\\\t=0\ \text{and} -32t+144=0\\\\t=0\ \text{and}\ t=4.5\ s\)

So, at 4.5 second the rocket will return to the ground.

Where a tap supplies water at 26°c while another supply at 82°c. If a man wishes to bath with water at 40°c, then the ratio of the mass of hot water to that of cold water is: 1/3.

The ratio of the mass of hot water to that of Cold water is determined as follows:

M₁C (82  40) = M₂C (40-26)

Where M₁C is the Mass of Tap 1; and

M₂C is the Mass of Tap 2.

Thus,

M₁C (82  40) = M₂C (40-26)

M₁/M₂ = 14/42

= 1/3

Thus, it is right to state that the ratio of the mass of hot water to that of cold water is: 1/3.

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The total electric flux through the infinite surface placed at a distance "d" from each charge, perpendicular to the line on which the point charges are located, is approximately 20.56 Nm².

Gauss's Law can be used to determine the total electric flux through an infinite surface that is set "d" units away from each charge and perpendicular to the line on which the point charges are situated.

According to Gauss's Law, the electrical flux across a closed surface is determined by the total charge it contains divided by the permittivity of empty space (0).

This situation involves two identical point charges with charges q = 91.0 pc (picocoulombs) and r = 30.0 cm between them.

We want to determine the electric flux via an infinite surface that is perpendicular to the line connecting the charges and situated at a distance "d" from each charge.

According to Gauss's Law,

Φ = (q / ε₀)

Φ = (2q / ε₀)

Φ = (2 * 91.0 pc) / (8.854 × \(10^{(-12)\))

Φ = (2 * 91.0 ×  \(10^{(-12)\) C) / (8.854 × \(10^{(-12)\))

Φ = (182 ×  \(10^{(-12)\) C) / (8.854 ×  \(10^{(-12)\))

Φ = (182 ×  \(10^{(-12)\)) * (N·m² / 8.854 ×  \(10^{(-12)\))

Φ ≈ 20.56 Nm²

Therefore, the total electric flux through the infinite surface placed at a distance "d" from each charge, perpendicular to the line on which the point charges are located, is approximately 20.56 N·m².

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Answer:

B

Explanation:

remember that you are looking for the value of the graph

to take into account or value a lot: prize, estimate to value your opinion. 2nd: estimate or assign the monetary value of: appraise a necklace. b: qualify or scale in utility, importance or general value: evaluate. value.

The statement "Gas tungsten arc welding was developed to weld magnesium and aluminum on world war ii fighter planes" is a TRUE statement.

Gas tungsten arc welding (GTAW), also known as tungsten inert gas (TIG) welding, was developed in the 1930s and 1940s to weld magnesium and aluminum on World War II fighter planes. This welding process uses a non-consumable tungsten electrode, an inert gas (usually argon), and a filler metal to create strong and precise welds.

GTAW is most commonly used to weld thin sections of stainless steel and non-ferrous metals such as aluminum, magnesium, and copper alloys. The process grants the operator greater control over the weld than competing processes such as shielded metal arc welding and gas metal arc welding, allowing for stronger, higher quality welds.

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The person can jump a distance of approximately 0.541 meters in the standing broad jump.

To calculate the distance that a person can jump in the standing broad jump, we can use the equation for the horizontal displacement of an object subject to constant acceleration:

x = v0t + (1/2)at^2

where x is the displacement (in meters), v0 is the initial velocity (in meters per second), t is the time of flight (in seconds), and a is the acceleration (in meters per second squared).

We can use the information provided in the problem to solve for the time of flight:

t = √(20.670 m / (1.26g))

The acceleration due to gravity, g, is approximately 9.8 m/s^2. Substituting this value into the equation for t gives us:

t = √(20.670 m / (1.269.8 m/s^2)) = 0.293 s

Now that we know the time of flight, we can use the equation for horizontal displacement to solve for the distance traveled:

x = v0t + (1/2)at^2

= 0 + (1/2)(1.26g)*(0.293 s)^2

= 0.541 m

Assumptions:

The acceleration achieved from the crouch position is constant during the jump.

The person's arms do not contribute significantly to the horizontal displacement of the jump.

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Answer:

Explanation:

For refraction , the formula is

sin i / sin r = μ₂ / μ₁

where light is travelling from medium 1 to 2 having refractive index of μ₁ and μ₂ . Angle of incidence in medium 1 is i and angle of refraction in medium 2 is r .

Here i = 70°, r = 37°

μ₁ = 1.8 ,μ₂ = ?

sin70 / sin 37 = μ₂ / 1.8

.939 / .602 = μ₂ / 1.8

1.56 =  μ₂ / 1.8

μ₂ = 2.81 .

The value of refraction index for the second medium will be  \(\mu_2=2.16\)

Every material has a different refractive index. The refracted index of any material shows that the light is refracted by how much angle.

So like for water its value will be different also for glass its value will be different.

Now it is given in the question that

Angle of incidence \(i=70^o\)

Refractive index of the first medium \(\mu_1=1.8\)

Angle of refraction \(r=37^o\)

Now from snells law

\(\dfrac{Sin \ i}{Sin \ r} = \dfrac{\mu_2}{\mu_1}\)

\(\dfrac{Sin70}{Sin37} = \dfrac{\mu_2}{1.8}\)

\(\mu_2= \dfrac{Sin70\times1.8}{Sin37}\)

\(\mu_2=2.16\)

Thus the value of the refraction index for the second medium will be  \(\mu_2=2.16\)

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The electric force between the two balloons is approximately 1.04 x \(10^{-12}\) N.

Coulomb's Law:

The electric force between two charged objects can be calculated using Coulomb's Law, which states that the magnitude of the electric force F between two charged objects is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:

F = k * (q1 * q2) / r²

where k is the Coulomb constant, which has a value of approximately 9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\).

In this case, each balloon acquires a charge of 1.2 x \(10^{-7}\) C, so the total charge on both balloons is 2 * 1.2 x \(10^{-7}\)C = 2.4 x \(10^{-7}\)C. The distance between the balloons is 0.5 m.

Plugging in these values into Coulomb's Law, we get:

F = (9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\)) * [(1.2)²x (\(10^{-7}\) C)²/ (0.5m)²]

Simplifying this expression gives:

F = 1.0368 x \(10^{-12}\) N

Therefore, the electric force between the two balloons is approximately 1.04 x\(10^{-12}\)    N.

What is magnitude?

Magnitude refers to the size or extent of something, usually measured in numerical or quantitative terms. It can refer to a physical quantity, such as length, mass, or volume, or it can refer to other measurable attributes, such as brightness, intensity, or force. In general, magnitude is a relative measure, meaning that it is typically expressed as a comparison between two or more things.

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Radio waves of 21-cm wavelength originate from Cool, neutral atomic hydrogen. Option A is the Correct answer.

The 21-cm wavelength radiation is produced by the spin-flip transition of the electron in the hydrogen atom's ground state. This transition occurs when the electron's spin changes from parallel to antiparallel or vice versa with respect to the proton's spin.

Since the hydrogen atom is the most abundant element in the interstellar medium, the 21-cm radiation is an important tool for studying the properties of the interstellar gas. The 21-cm radiation is primarily emitted by cool, neutral atomic hydrogen, which is the dominant constituent of the interstellar gas in the Milky Way galaxy. Option A is the Correct answer.

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Answer:

2/5 v

Explanation:

Use conservation of momentum

originally    mv = 2m v

  after the crash   mv is still the same (2mv)

        but the mass is now   5m x      where x is the new velocity

                   2mv = 5 mx

                  x = 2/5 v

The momentum of two objects in a collision is conserved. Hence, the total initial momentum is equal to the final momentum of the coupled mass. Here the final velocity will then be 2/5 v.

Momentum of a moving object is the product of mass and velocity. It is a vector quantity with direction and magnitude. The total momentum of two colliding bodies is equal to the total final momentum after collision.

Let m1 and m2 be the masses and v1 and v2 be the final velocities. Vt be the velocity of the coupled mass.

Then, m1 v1 + m2 v2 = (m1 + m2) Vt

Given, mass of cart 1 = 2m

cart 2 = 3m

velocity of cart 1 = v

cart = 0 since it was at rest.

Then, 2m v + 0 = (2m + 3m) Vt

Vt = 2/5 v

Therefore, the final velocity of the couple of carts will be 2/5 v.

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Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

Answer:

Coal was one of man's earliest sources of heat and light. The Chinese were known to have used it more than 3,000 years ago. The first recorded discovery of coal in this country was by French explorers on the Illinois River in 1679, and the earliest recorded commercial mining occurred near Richmond, Virginia, in 1748

Explanation:

Answer:

I think it is law of inertia or Newton first law

A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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The magnetic moment of an orbiting electron can be expressed as μ = IA, where I is the current and A is the area of the orbit. For a circular orbit, the current can be expressed as I = -ev/2πr. The area of the orbit is given by A = πr^2. Combining these equations, the magnetic moment isμ = -(e/2m)rv, where m is the mass of the electron.

The magnetic moment of an orbiting electron is given by the formula μ = IA, where I is the current flowing in the loop and A is the area of the loop. For a circular orbit, the current is given by I = -ev/2πr, where e is the charge of the electron, v is its velocity, and r is the radius of the orbit. The negative sign in the formula for current indicates that the current flows in the opposite direction to the motion of the electron.

The area of the circular orbit is given by A = πr^2, where r is the radius of the orbit. Substituting the expression for current and area into the formula for magnetic moment, we obtain:

μ = IA = (-ev/2πr)πr^2 = -e/2mr(rv)

where m is the mass of the electron. This equation shows that the magnitude of the magnetic moment is proportional to the product of the radius of the orbit, the velocity of the electron, and its charge. It also shows that the magnetic moment is negative, indicating that it is opposite in direction to the angular momentum of the electron. This is known as the "spin magnetic moment" of the electron, and is one of the fundamental properties of the electron.

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a) The general equation for a traveling wave in one dimension is given by y(x,t) = A cos(kx - ωt + φ), where A is the amplitude, k is the wave number, ω is the angular frequency, and φ is the phase constant.

Comparing with the given equation y(t) = (4.20 cm) cos(2.10t), we can see that the amplitude A = 4.20 cm, wave number k = 0 (since it's a transverse wave), angular frequency ω = 2.10 rad/s, and phase constant φ = 0 (since y(0) = A cos(0) = 0).

Therefore, the equation for the traveling wave is y(x,t) = 4.20 cos(2.10t).

b) To find the transverse velocity as a function of time for a particle located at 3.10 cm, we need to take the derivative of y(x,t) with respect to time, and then evaluate it at x = 3.10 cm.

∂y/∂t = -2.10A sin(2.10t)

Substituting A = 4.20 cm, we get:

∂y/∂t = -8.82 sin(2.10t)

At x = 3.10 cm, we have kx = 0, so the transverse velocity as a function of time is:

v(t) = -8.82 sin(2.10t)

c) Similarly, for a particle located at 5.10 cm, we have kx = π, so the transverse velocity as a function of time is:

v(t) = -8.82 sin(2.10t + π)

d) The two answers are so different because the particles at x = 3.10 cm and x = 5.10 cm have different initial phases. The particle at x = 3.10 cm starts at the equilibrium position, so its velocity at any time is purely transverse.

However, the particle at x = 5.10 cm starts at the maximum displacement, so its velocity at any time is a combination of transverse and longitudinal components.  

Physically, this means that particles at different locations in a transverse traveling wave can have different motion patterns, depending on their initial conditions.

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Answer:

I believe it is True... I hope it is correct :)

Explanation:

Answer : False

Explanation :

Complete question is;

Kamal said the distance from the top of the balloon to the ground in the Example image attached is √353 ft. What mistake might Kamal have made?

Answer:

the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse

Explanation:

From the image attached, we can see that the distance from the top of the balloon which is blue in color to the ground is denoted by "b".

Now the triangle is a right angle triangle with hypotenuse = 15ft + 2ft = 17 ft; the adjacent side = 8 ft, while the opposite side is "b".

Thus, we can use pythagoras theorem to solve this as;

b = √(17² - 8²)

b = √(289 - 64)

b = √225

b = 15ft

However,we are told Kamal got b as √353 ft.

From inspection of the calculations we just did, if we had used addition instead of subtraction, we would have gotten b = √353 ft.

Thus, we can under that the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse.

Answer:

i. 170 m

ii. 850 m

Explanation:

Question

Arjun and his son Arav were standing ‘x’ m away from each other. They are equidistant (Y m) from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculate

i. the distance between Arjun and Arav

ii. the distance between the cliff and Arjun

The parameters given are;

The time for the sound to reach Arav, \(t_D\) = 0.5 s

Time for the echo to echo to reach Arav, \(t_E\) = 2 s

The distance between Arjun and Arav = \(D_D\)

The distance between Arav and the cliff = \(D_E\)

The speed of sound in air, s = 340 m/s

The formula for speed, s, is \(s = \dfrac{Distance, D}{Time, t}\), therefore;

\(s = \dfrac{D_D}{t_D} = \dfrac{D_D}{0.5} = 340\)

\(D_D\) = 0.5 s × 340 m/s = 170 m

The distance between Arjun and Arav = 170 m

ii. Since Arav hears the direct sound before the echo, he is closer to the cliff than Arjun, therefore, we have;

\(s = \dfrac{D_E}{t_E} = \dfrac{D_E}{2} = 340\)

\(D_E\) = 2 s × 340 m/s = 680 m

Therefore, the distance between Arav and the cliff = 680 m

Which gives the distance between the cliff and Arjun, \(D_{cliff}\) = The distance between Arav and the cliff + The distance between Arjun and Arav

\(D_{cliff}\) = 680 + 170 = 850 m.

Answer:that's 16 I think Explanation:

Answer:

It is either 16 or 17

Explanation:

:)

Answer:

2000J

Explanation:

The formula for work is W=Force x Distance

W=FxD

W=500N x 4m

W=2,000 Joules

If the coefficient of friction is.2, the frictional force is 100 N.

The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.

F = N is the equation for frictional force. Let's use the 2-kg block of wood that is resting on a table to be pushed from rest as an example. The static friction coefficient is taken into account in this situation. The static coefficient of wood is 0.5.

F = μN

F = 2 × 100 ×cos60°

F = 200 × 1/2

F = 100 N

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Answer:

Explanation:

lll

Answer:

Unbalanced

Explanation:

Hussein is pushing 2 N harder.

Answer:

Mass is an substance which occupies space

Explanation:

Answer: a coherent, typically large body of matter with no definite shape.

Explanation:

Answer:

18m/s/s

Explanation:

6 times 3= 18

The plane flies at speed of 160m/s should drop the package when it reaches at a distance of 824m.

A dropped object travels quickly in the direction of the earth's center. Newton's second law states that the net force applied on an object determines its acceleration. If air resistance is small, the gravitational force, which is also known as an object's weight (w), acts as the net force on any falling object.

Free-fall acceleration seems to be another name for gravitational acceleration. Gravitational fields established by masses pull other masses approach them.

\(h = ut + 1/2 gt^2 ; u=0130 = 1/2 \times 9.8 \times t^2t= 5.15sec\)

The packet travel with the time period of 5.15sec

The distance = v x t

                      160m/s x 5.15s = 824m

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