the pKa of Et2NC(O)CH2NMe3+ (amide) is?

The properties most likely belong to a metal are ductile and malleable.

Malleability - Those metals that can be beaten into thin sheets with a hammer or any heavy object. For example - Cu, Au etc

Ductility- The property of the metals which can lead the metals to form them into wires.

Conductivity - Conductivity is the measure of the ease at which an electric charge or heat can pass through a material. For example - Metals are good conductors of heat and electrolytic solution is conductors of electricity.

Metals have many other properties including the given above, like sonority,  lustrous surface, very hard etc.

Therefore, The properties most likely belong to a metal are ductile and malleable.

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Answer:

How many atoms are there in 1g of silver approximately? The atomic weight of silver is 108. Thus number of moles of silver in 1 gram is 1÷108=0.009 mole

Explanation:

Pork must be held in hot holding at a minimum temperature of 135°F.

Between 42°F and 134°F, food is deemed to be in the "Danger Zone". The microorganisms that cause food related disease grow swiftly in food stored in the "Danger Zone" temperature range. Foods that are kept hot must always be kept at 135 degrees or higher.

The recommended storage temperature for hot meals is 135 degrees Fahrenheit or higher. Here are some suggestions for keeping hot meals safe: Never reheat food in a hot holding appliance. Food should be cooked to a safe temperature before being stored. Aseptic canning, also known as high-temperature-short-time (HTST) processing, is the process of filling presterilized containers with a sterile, cooled product and sealing them in a sterile environment with a sterile cover.

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Answer:

Warming it would make it come out. On a cold day the honey is frozen and atoms will not move as fast and are close toghether. When you warm it the atoms will move faster and the honey will come out of the bottle

Explanation:

Switching lighting from white to cool green for worker comfort is not the primary objective of the Green Lights program. While the program may indirectly contribute to increasing the amount of light in the workplace, the focus is on energy efficiency and conservation. Option (d) is the correct answer.

The basic concept embodied in the Green Lights program is energy conservation. This program was initiated by the Environmental Protection Agency (EPA) to promote the use of energy-efficient lighting systems and to reduce the overall energy consumption in commercial and industrial buildings. The program provides technical assistance and resources to businesses to help them adopt energy-efficient lighting practices, such as installing high-efficiency bulbs and fixtures, using occupancy sensors and timers, and implementing daylighting strategies. The aim is to help businesses reduce their energy bills, lower their carbon footprint, and contribute to a more sustainable environment.

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Answer:

3

Explanation:

think about it that's why we eat bro!

Explanation:

-26011130

Plss let me brainleist

52,475.39 J thermal energy is needed to completely vaporize 36.04 g of water at 100°C.

Thermal energy is the energy contained within a system which is responsible for the temperature.

Given data:

36.04 grams of water.

Since the molecular weight of water is about 18 g/mol.

\(Moles = \frac{36.04 grams}{18 g/mol}\)

Moles = 2

Q = mcΔT

Q  = 36.04 x 4.184 J/g-K x 348 J/g-K x 348

Q = 52,475.39 J

Hence, 52,475.39 J thermal energy is needed to completely vaporize 36.04 g of water at 100°C.

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Answer:

\(\boxed {\boxed {\sf SO_3}}\)

Explanation:

An empirical formula shows the smallest whole-number ratio of the atoms in a compound.

So, we must calculate this ratio. Since we are given the amounts of the elements in moles, we can do this in just 2 steps.

The first step is division. We divide the amount of moles for both elements by the smallest amount of moles.

There are 0.300 moles of sulfur and 0.900 moles of oxygen. 0.300 is smaller, so we divide both amounts by 0.300

The next step is writing the formula. We use the numbers we just found as the subscripts. These numbers go after the element's symbol in the formula. Remember sulfur is S and there is 1 mole and oxygen is O and there are 3 moles.

This formula is technically correct, but we typically remove subscripts of 1 because no subscript implies 1 representative unit.

\(\bold {The \ empirical \ formula \ for \ the \ compound \ is \ SO_3}}\)

Answer:

A

Explanation:

By nature, a hybrid has one dominante allele and one recessive allele

Hi, you've asked an incomplete question. However, I assumed you are referring to the article found on the Scientific American website.

Explanation:

Remember, according to that article we are told that scientists notice that these insects have a long nymphal (immature form before becoming adults) stage, one that can last up to 13 to 17 years on the ground before they leave the ground looking for mating partners.

Because it is only after mating occurs at this point that their eggs are laid, that is why scientists believe that cicadas only reproduce every 13 or 17 years.

The sample initially contains 1.35mg of Pu-236, the mass of Pu-236 is present after 5.00 years is 0.402mg.

Calculation shown in image below.

The 1/2-life of a radioactive isotope is the amount of time it takes for one-half of of the radioactive isotope to decay. The half-life of a specific radioactive isotope is steady; it's far unaffected by means of situations and is unbiased of the preliminary quantity of that isotope.

information the concept of half of-life is useful for figuring out excretion quotes as well as steady-nation concentrations for any precise drug. different drugs have different half-lives; but, they all follow this rule: after one half of-existence has passed, 50% of the initial drug amount is removed from the body.

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Answer: D 25 degrees

Explanation: The reason because is 25x4=100 and slightly tilted =1/4 of the earth which is 25

Answer:

well with that you can make a water maker that might make you brother happy because it will keep him alive

Explanation:

Answer:

you could sew a doll for him

or you could punch him in the face and tell him to cheer up

Explanation:

Answer:

Scientists study Earth's interior by studying

seismic waves. Seismic waves are waves of energy that travel

through Earth.

Explanation:

a) Data:

F = 600 N

t = 1.5 s

The equation for Impulse:

Impulse = I = F x t,

then the change in momentum: pf - pi

Impulse and the change in momentum are related like this:

pf - pi = I = F x t = 600 N x 1.5 s = 900 N.s

Therefore the change in momentum: pf-pi = 900 N.s

b) Velocity (t) = initial velocity + a x t

We can assume initial velocity = 0 m/s

From F = m x a = mass x acceleration, we clear "a",

m = 275 g = 0.275 kg (1 kg = 1000 g)

Then, F/m = a => 600 N/0.275 kg = 2182 m/s^2

Velocity (t) = 0 + 2182 m/s^2 x 1.5 s = 3273 m/s

Velocity = 3273 m/s

Answer:

A. 7

(assuming the water is neutral)

The Rack Stop is a small, movable metal stopper located at the bottom of the microscope body tube. Its purpose is to prevent the objective lenses from hitting the microscope slide or specimen, which could damage both the lenses and the sample.

Here is a list of microscope parts and their uses, including the Rack Stop:

1. Eyepiece or Ocular Lens: The lens at the top of the microscope that you look through to view the specimen.

2. Body Tube: The long, cylindrical part of the microscope that holds the eyepiece at the top and the objective lenses at the bottom

3. Arm: The curved part of the microscope that connects the body tube to the base.

4. Base: The flat, sturdy part of the microscope that supports the rest of the instrument.

5. Stage: The flat platform on which you place the specimen for viewing.

6. Stage Clips: Small metal clips that hold the microscope slide in place on the stage.

7. Coarse Focus Knob: A large knob that moves the body tube up and down to bring the specimen into rough focus.

8. Fine Focus Knob: A smaller knob that moves the body tube slightly to fine-tune the focus of the specimen.

9. Diaphragm: A rotating disc or lever that controls the amount of light entering the microscope and illuminating the specimen.

10. Light Source: The bulb or mirror that provides light for illuminating the specimen.

11. Objective Lenses: A set of lenses located at the bottom of the body tube that magnify the specimen.

12. Rack Stop: A small, movable metal stopper located at the bottom of the microscope body tube. Its purpose is to prevent the objective lenses from hitting the microscope slide or specimen.

13. Nosepiece: The rotating turret at the bottom of the body tube that holds the objective lenses.

14. High Power Objective: The objective lens with the highest magnification, typically 40x or higher. It is used for detailed examination of the specimen.

To use the microscope, first place the specimen on the stage and secure it with the stage clips. Turn on the light source and adjust the diaphragm to control the amount of light entering the microscope. Then, use the coarse focus knob to bring the specimen into rough focus. Once you have achieved this, use the fine focus knob to fine-tune the focus and bring the specimen into clear view. To change the magnification, rotate the nosepiece to select the desired objective lens. Finally, adjust the focus as needed and observe the specimen at the desired magnification.

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The correct option that illustrates a dipeptide and an amino acid in the optimal position to form a tripeptide is:

a) R O R O H R O

  | || | || | | ||

  H-N-C-C-N-C-C H-N-C-C

  | | | | | | ||

  H H H H OH H OH

This diagram represents the bonding between amino acids in a peptide chain, with the "R" representing different side chains of the amino acids. The "H" represents the hydrogen atom.

The dipeptide and amino acid are connected through peptide bonds, and the optimal position shows how the tripeptide can be formed by the addition of another amino acid.

Therefore, (a) is the correct answer.

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The options given, let's analyze each group to determine if they are both electron donating by resonance and electron withdrawing by induction when attached to a benzene ring, This group is electron-withdrawing by both resonance and induction, so it doesn't meet the criteria.

This group is electron-donating by resonance (due to the presence of lone pair electrons on the oxygen atom) and electron-withdrawing by induction due to the electronegativity of the oxygen atom. Therefore, it meets the criteria.
This group is electron-donating by both resonance lone pair electrons on the nitrogen atom) and induction (due to the partial positive charge on the nitrogen atom). Thus, it doesn't meet the criteria. This group is electron-donating by resonance lone pair electrons on the oxygen atom and electron-withdrawing by induction (due to the electronegativity of the oxygen atom. Therefore, it meets the criteria. This group is electron-withdrawing by both resonance and induction due to the high electronegativity of the fluorine atom, so it doesn't meet the criteria.

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Answer:

small i think

Explanation:

Answer:

0.35 moles

Explanation:

To convert grams to moles, divide by the atomic weight of the element in question. In this case, that would be 59/56= 0.35

Answer: 1.05 moles

Explanation: To convert to moles you would take the given amount and divide it by the molar mass of Fe.

When the number of protons in the nucleus is different from the number of electrons surrounding that nucleus, an electrical charge is created in the atom of matter.

When put in an electromagnetic field, matter experiences a force due to its physical characteristic known as electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively, by convention).

Unlike charges attract one another while like charges repel one another. Neutral refers to an object that carries no net charge. Classical electrodynamics, the name given to early understanding of how charged particles interact, is still accurate for issues that do not call for taking into account quantum effects.

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The answer is (e) 60, 160: there are 60 moles of copper ions and 160 moles of oxygen atoms in 20 moles of copper (II) phosphate.

The formula for copper(II) phosphate is Cu3(PO4)2.

To find the number of moles of copper ions in 20 moles of copper (II) phosphate, we must first find the number of moles of copper in one mole of copper (II) phosphate.

We have 3 moles of copper in one mole of copper (II) phosphate.

Therefore, we have:3 x 20 = 60 moles of copper ions

To find the number of moles of oxygen atoms in 20 moles of copper (II) phosphate, we first need to find the total number of oxygen atoms in 20 moles of copper (II) phosphate.

In one mole of copper (II) phosphate, there are 8 oxygen atoms (2 from each phosphate ion).

We have:8 x 20 = 160 oxygen atoms.

So, the answer is (e) 60, 160: there are 60 moles of copper ions and 160 moles of oxygen atoms in 20 moles of copper (II) phosphate.

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Answer:

SYMBOLS, FORMULAS AND MOLAR MASSES

OBJECTIVES

1. To correctly write and interpret chemical formulas

2. To calculate molecular weights from chemical formulas

3. To calculate moles from grams using chemical formulas

INTRODUCTION

Part I. Symbols and formulas

An element is a homogeneous pure substance made up of identical atoms. All matter is made

up of elements and, since chemistry is the study of matter, it is convenient to use symbols to represent

the elements rather than using the entire name.

By international agreement, specific symbols are assigned to each element (Note: This means

that while names of the elements vary with language, symbols are constant throughout the world.) Each

element is assigned a one- or two-letter symbol. The first letter is capitalized, the second (if there is

one) is not. While this often seems trivial, it is in fact a very important point. For example, in chemical

language Co represents cobalt, which is a metal and an element, while CO represents carbon monoxide,

a compound which is a colorless, odorless gas! Even when there is not an obvious correspondence,

for instance "MN", it can cause confusion. Do you mean the element manganese? Did you forget a

letter and mean something else? Are you using "M" to represent something else entirely? Chemists

sometimes use "M" to represent any metal. It is well worth the trouble to memorize the symbols for

common elements.

Since compounds consist of elements, the chemical formulas of compounds also consist of

elements with subscripts used to denote the number of atoms per molecule. If there is no subscript, it is

implied that there is one of that kind of atom. Ones never appear in chemical formulas. Not only do

subscripts denote ratios of atoms, they also denote the ratio of moles of element to one mole of

compound. Parentheses can be used to show groups of atoms, with the subscripts showing how many

groups there are. Parentheses are not used if there is only one group.

Examples: For one mole of the following compounds, how many moles of each element are

present?

MgCl2 1 mole Mg, 2 moles Cl

Mg(NO3)2 1 mole Mg, 2 moles N, 6 moles O

NaNO3 1 mole Na, 1 mole N, 3 mole O

AgCl 1 mole Ag, 1 mole ClPart II. Molar Masses

Each atom has a different size and therefore a different mass. The relative masses of each

element can be found on the periodic table. For example, one atom of magnesium weighs 24.31 amu

(atomic mass units). However, one mole of magnesium weighs 24.31 g. (Moles were planned that

way!) Since one mole of MgCl2 consists of one mole of magnesium and two moles of chlorine, the

mass of one mole of MgCl2 must be the sum of the masses of the elements. The mass of one mole of a

substance is called the molar mass or molecular weight.

Examples: What is the molar mass of the following compounds?

MgCl2 24.31 + 2(35.45) = 95.21 g/mol

Mg(NO3)2 24.31 + 2(14.01) + 6(16.00) = 148.33 g/mol

NaNO3 23.00 + 14.01 + 3(16.00) = 85.01 g/mol

AgCl 107.9 + 35.45 = 143.4 g/mol

(Note: Yes! You DO have to count significant figures when calculating molecular weight/molar

mass. However, the number of significant figures may vary depending on which periodic table you use.)

Chemists are generally interested in number of moles. Unfortunately, it is impossible to measure

moles directly. However, masses are easily measured, and if the chemical formula of the compound is

known, the molar mass can be used to determine the number of moles. The molar mass is defined as:

molar mass = grams/moles = g/mol (1)

Moles may be calculated by using molar mass as a conversion factor in dimensional analysis where

molar mass in grams = 1 (exactly) mole of compound (2)

This method is used in multi-step calculations. For example, if 0.873 g of MgCl2 is weighed out, it

is 9.17 x 10-3

moles.

1 mole

0.873g x 95.21 g = 9.17 x 10-3

mol MgCl2 (3)

However, 0.873 g of AgCl is only 6.09 x 10-3

mol.

1 mole

0.873g x 143.4 g = 6.09 x 10-3

mol AgCl (4)Molar mass may also be used to relate moles to grams. For example, 0.158 mol of MgCl2 is 15.2 g.

0.158 mol x 95.21 g = 15.2 g MgCl2 (5)

1 mol

Percent is used to express parts per one hundred. Usually in chemistry, it refers to

g of species of interest x 100 = % (6)

g of whole thing

Example: For the % Mg in MgCl2: In one mole of MgCl2, there are 24.31 g of Mg (molar mass of Mg,

the part we are interested in) and 95.21 g of MgCl2 (the whole thing), so %Mg in MgCl2 is

(24.31/95.21) x 100 = 25.53% Mg (7)

PROCEDURE

Work individually.

The formula for calcium phosphate is Ca3(PO4)2. Weigh about 2 g of calcium phosphate to the

nearest 0.001 g. In other words, you do not have to have exactly 2.000g, but you must know the

weight you have exactly. Acceptable results include but are not limited to: 1.985g , 2.035g, 2.314g

etc.

Be sure to report all results with the correct number of significant figures and appropriate units!

The molecular formula of the compound, given the data from the question is C₁₄H₂₄O₂

The following data were obtained from the question:

The molecular formula of the compound can be obtained as follow:

Molecular formula = empirical × n = mass number

[C₇H₁₂O]n = 224

[(7×12) + (12×1) + 16]n = 224

[84 + 12 + 16]n = 224

112n = 224

Divide both side by 112

n = 224 / 112

n = 2

Molecular formula = [C₇H₁₂O]n

Molecular formula = [C₇H₁₂O]₂

Molecular formula = C₁₄H₂₄O₂

Thus, the molecular formula of the compound is C₁₄H₂₄O₂

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