Answer:
the radius
Step-by-step explanation:
Answer:
radius
Step-by-step explanation:
What is 19,067 divided by 43
Answer:
443.418604651
Step-by-step explanation:
Thank you for the points!
Let X be the amount of time (in minutes) a USPS clerk spends with a customer. It is known that X follows an exponential distribution and USPS clerks take care of 38.1 percent of customers less than two minutes. Find P(0.5 < X < 3).
Answer: 0.4
Step-by-step explanation:
Given: Cumulative exponential distribution:
\(P(x<k)=1-e^{\frac{-x}{k}}\)
As per given,
\(P(x<2)=1-e^{\frac{-2}{k}}=0.381\\\\\Rightarrow\ e^{\frac{-2}{k}}=1-0.381\\\\\Rightarrow\ e^{\frac{-2}{k}}=0.619\\\\\Rightarrow\ {\frac{-2}{k}}=\ln(0.619) \ \ \ [\text{Taking natural log on both sides }]\\\\\Rightarrow\ {\frac{-2}{k}}=-0.47965\\\\\Rightarrow\ k=\dfrac{2}{0.47965}\\\\\Rightarrow\ k=4.17\)
\(P(0.5 < X < 3) \\\\=P(X<3)-P(X<0.5) \\\\=(1-e^{-\frac{3}{4.17}})-(1-e^{-\frac{0.5}{4.17}}) \\\\=e^{-\frac{0.5}{4.17}}-e^{-\frac{3}{4.17}}\\\\= 0.4\)
Hence, the required probability = 0.4
Which symbol makes -121. That make -21 a true statement
Answer:
<
Step-by-step explanation:
To solve this correctly you need to remember how to compare integers.
Given the following proportion, find x
3/7 = 6/x
Answer:
x = 14
Step-by-step explanation:
3/7 = 6/x
3(x) = 6(7)
3x = 42
x = 14
Answer:
3/7 = 6/x
3x = 6*7
3x = 42
x = 42/3
x = 14
I hope you can know this answer...
Mike bought 2 1/3 yards of ribbon. Jim bought four times the amount of ribbon that Mike bought. How many yards of ribbon did Jim buy?
Thus, the length of ribbon bought by Milke is 28/3 yards (in proper fraction).
Explain about the mixed fractions:The sum of the whole number and a legal fraction is contained in a mixed fraction or number. Using the fundamental mathematical processes, we can change an improper fraction into such a mixed fraction. An incorrect fraction is one in which the numerator exceeds the denominator.
Given data:
Length of ribbon bought by Mike = 2 1/3 yards
Convert given mixed fraction in proper fraction:
= 2 1/3
= (2*3 + 1)/3
= 7/3 yards ..eq 1
now, Jim bought 4 times the length of ribbon Mike bought.
multiplying eq 1 with 4
= 4* 7/3 yards
= 28/3 yards
Thus, the length of ribbon bought by Milke is 28/3 yards (in proper fraction).
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help quick pleaseeeeeee
The following angles and length of sides for the given right triangle are-
1. m∠DGE = 45; 2. m∠EDG = 85; 3. FD = 10; 4. GD = 10√2; 5. EG = 28.34.
Explain about the alternate interior angles?Alternative Interior Angles: Angles are created on the inside, the interior, of two other lines when a third line known as the transversal crosses them. These other lines are typically parallel. The alternate internal angles are those that are perpendicular to one another.
From the given angles on the figure:
1. m∠DGE = ?
m∠DGE = m∠BAD = 45 (alternate interior angles)
2. m∠EDG = ?
m∠EDG = 180 - 45 - 50 (angle sum property of triangle)
m∠EDG = 85
3. FD = ?
tan 45 = FD / FG
FD = 10 * tan 45
FD = 10
4. GD = ?
Cos 45 = FG / DG
DG = 10 / cos 45
DG = 10/ (1/√2)
DG = 10√2
5. EG = ?
EG = EF + FG
EF = 13 / cos 50
EF = 18.34
EG = 18.34 + 10 = 28.34
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Find the missing angle according to the Triangle Exterior Angle Theorem
Answer:
k = 36
Step-by-step explanation:
By exterior angle theorem:
\(k \degree + 110 \degree = 146 \degree \\ \\ k \degree = 146 \degree - 110 \degree \\ \\ k \degree = 36\degree \\ \\ k = 36\)
The cost (in dollars) of producing x units of a certain commodity is C(x) = 7000 + 6x + 0.15x2. (a) Find the average rate of change of C with respect to x when the production level is changed from x = 100 to the given value. (Round your answers to the nearest cent.) (i) x = 103 $ per unit (ii) x = 101 $ per unit (b) Find the instantaneous rate of change of C with respect to x when x = 100. (This is called the marginal cost.) $ per unit
Answer:
The instantaneous rate is 36.
Step-by-step explanation:
Given the cost of producing a commodity,
\(C(x) = 7000 + 6x + 0.15x^{2}\)
Now calculate the average rate of change in cost of producing commodity.
Use below formula to calculate average rate of change when (i) x = 103 $ per unit:
\(\text{Average rate of change} = \frac{C(103) – C(100) }{103 - 100} \\C(x) = 7000 + 6x + 0.15x^{2} \\C(100) = 7000 + 6 \times 100 + 0.15 (100)^{2} = 9100 \\C(103) = 7000 + 6 \times 103 + 0.15 (103)^{2} = 9209.35 \\\text{Average rate of change} = \frac{9209.35 - 9100}{103 - 100} = 36.45\)
Now calculate average rate of change when (ii) x = 101 $ per unit:
\(\text{Average rate of change} = \frac{C(101) – C(100) }{101 - 100} \\C(x) = 7000 + 6x + 0.15x^{2} \\C(100) = 7000 + 6 \times 100 + 0.15 (100)^{2} = 9100 \\C(101) = 7000 + 6 \times 101 + 0.15 (101)^{2} = 9136.15 \\\text{Average rate of change} = \frac{9136.15 - 9100}{101 - 100} = 36.15\)
Now to find the Instantaneous Rate of Change we just need to find the differentiation of given function.
\(C(x) = 7000 + 6x + 0.15x^{2} \\C’(x) = 6 + 0.3x \\\)
Instantaneous Rate of Change when x = 100
\(= 6 + 0.3 \times (100) \\= 36\)
The Pythagorean Identity states that:
(sin x)2 + (cos x)2 = 1
Given sin, find cos 0.
10
√51
COS = [?]
Simplify the fraction.
Enter
H
for the purpose of pythagorean identity
What is pythagorean identity ?
We are shown sin as 10/51. You can square the Pythagorean Identity to get the following result:
(sin x)2 + (cos x)2 = 1
sin²x + cos²x = 1
Substituting sin = 10/√51, we get:
(10/√51)² + cos²x = 1
100/51 + cos²x = 1
cos²x = 1 - 100/51
cos²x = 51/51
cos x = √51/51
Cos 0 thus equals 51/51.
There is no need to simplify the fraction any more because it is already in its simplest form.
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I need help with aleks
Answer:
All angles are equal because all sided are equal so the 1st 1 is 60 .
the 2nd is 80
which point on the line number line represntes -1/3
Answer:
c
Step-by-step explanation:
Answer:
Aaaaaaaaa because -1/3=0.3333
The drama club has 120 members. 48
members attended summer camp. What
percent of the drama club attended summer
camp?
Work Shown:
48/120 = 0.40 = 40%
Answer:
40 percent of the club members attended
also is this a true drama club like a in real life?
Step-by-step explanation:
hope it helped mark me brainly
have a great day
Select the correct answer.
Each statement describes a transformation of the graph of f(x) = x. Which statement correctly describes the graph of g(x) if g(x) = f(x - 11)?
A. It is the graph of f(x) where the slope is increased by 11.
It is the graph of f(x) translated 11 units to the left.
It is the graph of f(x) translated 11 units up.
It is the graph of f(x) translated 11 units to the right.
B.
C.
OD.
The correct answer is C. It is the graph of f(x) translated 11 units to the left.
The correct answer is:
C. It is the graph of f(x) translated 11 units to the left.
When we have a function of the form g(x) = f(x - a), it represents a horizontal translation of the graph of f(x) by 'a' units to the right if 'a' is positive and to the left if 'a' is negative.
In this case, g(x) = f(x - 11), which means that the graph of f(x) is being translated 11 units to the right. However, the answer options do not include this specific transformation. The closest option is option C, which states that the graph of g(x) is translated 11 units to the left.
The graph of f(x) = x is a straight line passing through the origin with a slope of 1. If we apply the transformation g(x) = f(x - 11), it means that we are shifting the graph of f(x) 11 units to the right. This results in a new function g(x) that has the same shape and slope as f(x), but is shifted to the right by 11 units.
Therefore, the correct answer is C. It is the graph of f(x) translated 11 units to the left.
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There are 16 marbles in total . Maria has 2 more than Felipe. How many marbles does each person have
Answer:
maria has 9 and felipe has 7
Step-by-step explanation:
if felipe has 7 then 9+7=16
J&L Electrical Services had a beginning balance (1 January 2019) in accounts receivable (debtors) of R200 000 and a beginning balance of allowance for credit losses of R4 000. During the financial year (1 January 2019 – 31 December 2019) they delivered services on credit for R660 000 and collected R640 000 from debtors. If J&L Electrical Services estimates that 2% of ending accounts receivable will not be collected, his adjusting journal entry will include a: A. credit to allowance for credit losses of R4 400. B. debit to allowance for credit losses of R400. C. debit to allowance for credit losses of R4 400. D. credit to allowance for credit losses of R400.
The adjusting journal entry will include a debit to the allowance for credit losses of R4,400.
the correct answer is C. debit to allowance for credit losses of R4,400.
To determine the adjusting journal entry for J&L Electrical Services, we need to calculate the ending balance of accounts receivable and the necessary adjustment for the allowance for credit losses.
Beginning balance of accounts receivable: R200,000
Services delivered on credit: R660,000
Collections from debtors: R640,000
To find the ending balance of accounts receivable, we subtract the collections from the sum of the beginning balance and services delivered on credit:
Ending accounts receivable = (Beginning balance + Services delivered) - Collections
Ending accounts receivable = (R200,000 + R660,000) - R640,000
Ending accounts receivable = R220,000
Now, we need to calculate the adjustment for the allowance for credit losses. J&L Electrical Services estimates that 2% of the ending accounts receivable will not be collected:
Allowance for credit losses adjustment = Ending accounts receivable * Estimated uncollectible percentage
Allowance for credit losses adjustment = R220,000 * 2% = R4,400
Since the allowance for credit losses has a beginning balance of R4,000, we need to increase it by R4,400 to match the estimated uncollectible amount:
the correct answer is C. debit to allowance for credit losses of R4,400.
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For the arithmetic sequence beginning with the terms {-1, 2, 5, 8, 11, 14...}, what is the sum of the first 16 terms?
Answer:
S₁₆ = 344
Step-by-step explanation:
the sum to n terms of an arithmetic sequence is
\(S_{n}\) = \(\frac{n}{2}\) [ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
here a₁ = - 1 and d = a₂ - a₁ = 2 - (- 1) = 2 + 1 = 3 , then
S₁₆ = \(\frac{16}{2}\) [ (2 × - 1) + (15 × 3) ]
= 8 (- 2 + 45)
= 8 × 43
= 344
how do i find the measure of these? i’m lost in math
Answer: Answers and work are all in the picture that I attached. Hope this helps
Which of these integers is not a whole number? A. -6 B. 6 C. 66
Answer:
-6
Step-by-step explanation:
Cuz it’s negative?
Answer:
-6 I think
Negative numbers are not whole numbers.
Find the area of this problem
The area of the kite is A = 48 units²
Given data ,
Let the area of the kite be represented as A
Now , the value of A is
Let the first diagonal of the kite be d₁ = 12 units
Let the second diagonal of the kite be d₂ = 8 units
Now , Area of kite = ( 1/2 ) d₁ x d₂
On simplifying , we get
A = ( 1/2 ) ( 12 ) ( 8 )
A = 48 units²
Therefore , the value of A is A = 48 units²
Hence , the area of the kite is A = 48 units²
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If ∠WOZ and ∠WOX are supplementary angles and ∠WOX and ∠XOY are complementary angles, then what is the value of x and m∠XOY?
Answer:
b.) x= 6, m∠XOY= 18
Step-by-step explanation:
comment if u need explanation :))
Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 samples, a total of 135 items were found to be defective.
What is an estimate of the proportion defective when the process is in control (to 3 decimals)?
What is the standard error of the proportion if samples of size 100 will be used for statistical process control (to 4 decimals)?
Compute the upper control limit and lower control limit for the control chart (to 4 decimals, if necessary)?
a) The estimate of the proportion of defectives when the process is in control is 0.054
b) The standard error of the proportion if the sample size is 100 is 0.0226.
c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).
What are the formulas for finding the estimate of the proportion, standard variation, and control limits?1) The estimate of the proportion of success is
p = (number of success)/(total number of samples)
I.e., p = x/N
2) The standard deviation of the proportion of success is
\(\sigma_p = \sqrt{\frac{p(1-p)}{n} }\)
3) The upper and lower control limits for a control chart are:
L.C.L = p - 3\(\sigma_p\)
and U.C.L = p + 3\(\sigma_p\)
Calculation:It is given that, there are 25 samples of 100 items each.
So, the total number of items i.e., the total sample size,
N = 25 × 100 = 2500
In 25 samples, a total of 135 items were found to be defective.
So, the number of defectives x = 135
a) The estimate of the proportion of defectives is p = x/N
On substituting, we get
p = 135/2500 = 0.054
b) The standard error of the proportion if the sample of size 100 is calculated by
\(\sigma_p = \sqrt{\frac{p(1-p)}{n} }\)
On substituting p = 0.054 and n = 100, we get
\(\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }\)
= 0.0226
c) The control limits for the control chart are:
Upper control limit = p + 3\(\sigma_p\)
⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218
Lower control limit = p - 3\(\sigma_p\)
⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0
(Since we know that the lower control limit should not be a negative value, it is made equal to 0).
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How do you write y − 4 = 2(x − 6) in slope-intercept form?
Sorry answered for more points for more questions I'm so sorry.
A movie theater has been charging $10.00 per person and selling about 500 tickets on a typical weeknight. After surveying their customers, the theater management estimates that for every 50 cents that they lower the price, the number of moviegoers will increase by 50 per night. Find the demand function. (Let x represent the number of tickets sold and p represent the price.)
Answer:
\(p(x) = -0.01x + 15\)
Step-by-step explanation:
Given
Let x represent the number of tickets, and p the charges
\((x_1,p_1) = (500,10)\)
A reduction of 50c gives an increment of 50 tickets.
This gives:
\((x_2,p_2) = (500+50,10-0,5)\) ---- \(50c = \$0.5\)
\((x_2,p_2) = (550,9.5)\)
Required
Determine the demand function
First, calculate the slope:
\(m = \frac{p_2 - p_1}{x_2 - x_1}\)
\(m = \frac{9.5 - 10}{550-500}\)
\(m = \frac{-0.5}{50}\)
\(m = -0.01\)
So, the equation is:
\(p = m(x - x_1) + y_1\)
\(p = -0.01(x - 500) +10\)
\(p = -0.01x + 5 +10\)
\(p = -0.01x + 15\)
Hence, the function is:
\(p(x) = -0.01x + 15\)
Derek has 4 shirts, 7 pairs of pants, and 3 blazers. How many possible outfits can he make?
rogress: The movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer A motor oil retailer needs to fill 50 one quart bottles, and he has two tanks: one that contains 12 gallons of oil and one that contains 2 gallons of oil. Which will he need to fill the bottles? The 2 gallon tank is enough. He will need both tanks. The 2 gallon tank is not enough, but the 12 gallon tank is enough. Question ID: 53297 Even both tanks will not be enough.
The motor oil dealer will have to use both tanks since he needs 15 gallons of oil but will still be short by one gallons.
Find the solution ?The motor oil dealer will have to use both tanks since he needs 15 gallons of oil but will still be short by one gallons.
A motor oil store has two tanks: one holds 12 gallons of oil, and the other holds 2 gallons of oil. In order to determine which tank will require to fill the bottles, the following computation must be done:
Quarts to gallons is 4 to 1.
1/4 x 60 = X
60/4 = X
15 = X
Since the motor oil vendor requires 15 gallons of oil, he must use both tanks but will still be short by 1 gallons
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Special Triangles part 2: Please help me #5-6
9514 1404 393
Answer:
5. 4√2 N
6. 20 N
Step-by-step explanation:
We're not sure how your diagram relates to the notion of the weight being "pushed". Usually T represents "tension," which would indicate a "pull" in up and to the right.
__
5. The side ratios in this triangle match exactly those in your problem 1. T is √2 times the equal side lengths, so is T = 4√2 N.
__
6. The sides ratios in the triangle match exactly those in your problem 2. T is 2 times the shorter side length, so is T = 20 N.
An account pays 7% per year simple interest. In year 1, the amount in the
account is
$950. How much is in the account in year 6?
The amount in year 6 is $1282.5.
What is simple interest?
Simple interest is a quick and easy method of calculating the interest charge on a loan. Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
Given,
rate of interest = 7%
time = 1 year
Amount on first year = $950
First we will calculate simple interest for 5 years, because amount is available for 1 year.
SI =PRT
SI = 950(7/100)1
SI = $332.5
Therefore, the amount after 6 years = 950+332.5
=$1282.5
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The value of a school bus reduces from $512000 to $343000in 3 years. Find the
uniform rate of depreciation per annum (R).
Answer:
The uniform rate of depreciation is $56,333 per year, or 11% per year.
Step-by-step explanation:
Rate of Depreciation
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:
\(\displaystyle R=\frac{P-Q}{t}\)
It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:
\(\displaystyle R=\frac{512,000-343,000}{3}\)
\(\displaystyle R=\frac{169,000}{3}\)
R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
Calculus please help
f(x) is discontinuous.
Since LHS ≠ RHS ≠ f(x).
What is a function?A function is a relationship between inputs where each input is related to exactly one output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
here, we have,
We have,
f(x) = x + 1, for x ≤ 2
f(x) = 2x - 1, for 1 < x < 2
f(x) = x - 1, for x < 1
Now,
A x = 1
LHS of f(x) = lim f((h - 1)) = (h - 1 - 1) = 0 -2 = -2
RHS of f(x) = lim f(h + 1) = (2(h + 1) - 1) = 2h + 2 - 1 = 0 + 1
f(1) = x + 1 = 1 + 1 = 2
We see that,
LHS ≠ RHS ≠ f(x)
So,
f(x) is not continuous, it is discontinuous.
Thus,
f(x) is discontinuous.
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The complete question.
Show that the following functions are continuous or discontinuous at x = 1.
f(x) = x + 1, for x ≤ 2
f(x) = 2x - 1, for 1 < x < 2
f(x) = x - 1, for x < 1
y - ( -3y ) what is the answer????
Answer:
4y
Step-by-step explanation:
y - -3y
Subtracting a negative is like adding
y+3y
Combine like terms
4y
Answer:
\(4y\)
Step-by-step explanation:
\(y - ( - 3y) \\ y + 3y \\ = 4y\)
hope this helps
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