The number of formula units found in a 5.674 g sample of Mg(NO3)2Carbon

Answer:

Over time, the plant matter transforms from moist, low-carbon peat, to coal, All types of coal also contain sulfur, which, when burned, releases toxic air pollution. Sulfur All this coal comes from mines, which are either underground or run on diesel—a major source of air toxins, nitrogen oxide, and soot.

In this system, thermal energy from the sunlight causes the solar panel to create electrical energy which flows into the incandescent light bulb.In the light bulb, the  electrical energy is transformed into two different types of energy mechanical energy and chemical energy.

The term thermal energy is defined as the energy where within a system that is causative for its temperature. Heat is the flow of thermal energy. How heat is displaced between different systems and how work is done in the process.

When the sun shines onto a solar panel, energy from the sunlight is take up by the PV cells in the panel. This energy make up electrical charges that move in reaction to an internal electrical field in the cell, causing electricity to flow.

Thus, In this system, thermal energy from the sunlight causes the solar panel to create electrical energy which flows into the incandescent light bulb.

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Look at the mole ratio in the balanced equation

2CO + O2 ==> 2CO2

3.44 mol O2 x 2 mol CO/mol O2 = 6.88 moles CO

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

it's very easy and simple answer u can't do it

Answer:

Should the government invest more money in nuclear energy than

in solar energy

Explanation:

This is because some people might think government should invest in nuclear energy while others might want the government to invest in solar energy.

Answer:

B. "Should the government..."; the answer to this relies on subjective input (what the audience thinks the government should do).

Explanation:

Think about the differences between statements that are subjective and objective. If you look at A, C, or D, these results of these experiments are all objective:

A) The amount of electricity generated by a power plant isn't "arguable"; it's a definite value that I can't just "make up" or "think" is correct/valid.

C) The byproducts generated by manufacture aren't "arguable" either; if a byproduct is heat, there's no subjective input.

D) Try to use the above reasoning for D!

The solubility of the salts is affected by the temperature changes. 1. NaCl is least affected by temperature. 2. supersaturated. 3. 60 grams KBr. 4. Ethanol has both polar and non-polar groups. 5. Mixing and shaking.

A KBr solution with 90 gm solute in 100 grams of water at 50 degrees is classified as supersaturated. 60 grams of KBr are needed to make a saturated solution in 100 gm of water at 30 degrees.

Ethanol is a general solvent due to the presence of both the polar and the non-Polar groups. As a result, it is easier to dissolve both polar molecules and non-Polar molecules. The dissolving rate can be increased by mixing or shaking the solution. Also, the sugar dissolves faster in hot than cold tea.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Answer:

T = 308.57 K

Explanation:

Given data:

Number of moles of K = 0.335 mol

Volume of vessel = 2.00 L

Pressure in vessel = 4.32 bar

R = 0.08314 L.bar /mol.K

Temperature of K = ?

Solution:

Formula:

PV = nRT

T = PV/nR

By putting values,

T = 4.32 bar ×2.00 L /0.335 mol× 0.08314 L.bar /mol.K

T = 8.64 bar.L / 0.028 L.bar /K

T = 308.57 K

150 grams of NaOH is approximately equal to 2.256 x 10^24 particles of NaOH.

To convert grams of NaOH to particles of NaOH, we need to use the concept of molar mass and Avogadro's number. The molar mass of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) together. It can be determined as follows:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can use the molar mass to convert grams of NaOH to moles. Since 1 mole contains Avogadro's number (approximately 6.022 x 10^23) particles, we can determine the number of particles as follows:

150 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (6.022 x 10^23 particles / 1 mol NaOH) ≈ 2.256 x 10^24 particles

It's important to note that this calculation assumes the substance is pure NaOH and that the molar mass and Avogadro's number are accurate.

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Answer:

habitat/shelter

Explanation:

The IUPAC name for each of the compounds would be:

A. 2,6-Dimethyl octane

B. Octane

IUPAC naming is a system of naming organic compounds according to the rules set up by the International Union of Pure and Applied Chemistry.

According to these rules:

Applying these rules to the structures in the image, the IUPAC names would be as follows:

A. 2,6-Dimethyl octane

B. Octane

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Answer:

a. The pressure of a fixed amount of gas is inversely proportional to its volume.

Explanation:

At constant temperature, the relationship between pressure (P) and volume (V) illustrated in the plot for a gas gives a straight line from the origin.

This relationship was described by a law stated by Robert Boyle, an English Chemist, in 1662.

Boyle's law states that the pressure of a fixed mass of gas is inversely proportional to the volume, provided the temperature remains constant.

The relationship for Boyle’s Law can be expressed mathematically as follows:

P1V1 = P2V2; where P1 and V1 are the values of the initial pressure and volume, and P2 and V2 are the final values of the pressure and volume of the gas.

Answer:B

Explanation: I guessed and got it right. Also (1/V).

The value of Kc at that temperature, based on the given information, is zero. This implies that at the specified temperature, the equilibrium strongly favors the reactant side, resulting in a very low concentration of products.

To determine the value of Kc, we need to set up and solve the equilibrium expression for the given reaction. The balanced equation for the reaction is:

2 HBr (g) ⇌ H2 (g) + Br2 (g)

The equilibrium expression is given by:

Kc = ([H2] * [Br2]) / ([HBr]^2)

Given that the initial number of moles of HBr is 0.600 mol and the number of moles of H2 at equilibrium is 0.104 mol, we can calculate the equilibrium concentrations as follows:

[HBr] = (0.600 mol) / (2.00 L) = 0.300 M

[H2] = (0.104 mol) / (2.00 L) = 0.052 M

Since there is no information provided about the concentration of Br2, we assume it to be zero initially, as it is not mentioned that it is present initially. Therefore, [Br2] = 0 M at equilibrium.

Substituting these values into the equilibrium expression, we have:

Kc = (0.052 M * 0 M) / (0.300 M)^2

Kc = 0 / 0.090 M^2

Kc = 0

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Answer:

true

Explanation:

Answer:

True

Explanation:

In a displacement reaction, more reactive element displaces less reactive element. Whereas in a double displacement reaction there is exchange of ions of two compounds.

Please find the equation to form copper (I) ion from neutral copper (Cu) below:

Hence, the correct equation is   mentioned above.

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Answer:

Within smokestacks and tailpipes

Explanation:

this is where manmade ozone is usually produced

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer: 177.23 g.

Explanation:

the volume of the aluminum bar is

1.7 cm x 3.0 cm x 12.9 cm

= 65.61 cm^3

2.7 g/cm^3 x 65.61 cm^3

177.23g

Answer:

The moon

Explanation:

The moon pulls on the earth, causing the tides to raise as the water is being pulled by the moon.

Exothermic reactions only release thermal energy, raising the temperature of the immediate environment. The environment is cooled through an endothermic process that absorbs heat.

An exothermic process is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.

The most exothermic reaction is the burning of methane because it generates a significant quantity of heat.

Thus, Exothermic reactions only release thermal energy.

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The Sun rotates at different rates at different latitudes on the Sun

The sun revolves around its axis like a ball in motion. One cycle of the sun takes approximately 27 days. But the sun rotates at various rates in various parts. The sun's equator rotates more quickly than its poles. Differential rotation is the name given to this phenomena.

The depth of the sun also affects how quickly it rotates, with the core regions rotating more slowly than the outer regions.

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Missing parts;

Which statement about the Sun's rotation is TRUE?

The Sun rotates only at the equator, where the sunspots are found; the rest of the Sun does not rotate

Only the atmosphere of the Sun rotates, not the main body of the Sun

The Sun rotates at different rates at different latitudes on the Sun

The Sun rotates once a day

The Sun does not rotate; only planets rotate

Answer: An exothermic reaction's equilibrium shifts to the left when pressure is increased and shifts to the right when temperature is increased.

Explanation: In exothermic reactions, the side comprising fewer gas moles is deemed to be positively impacted by enhanced pressure, resulting in a shift towards the reactants. Elevated temperatures provide a preferential environment for endothermic reactions which are characterized by the absorption of thermal energy. When an exothermic reaction occurs, the application of heat results in a shift of the equilibrium towards the endothermic side, as a means of absorbing the excess thermal energy.

Answer:

0.93 M

Step-by-step Explanation:

First, we have to calculate the molar mass (MM) of ZnSO₄ by using the molar mass of each chemical element:

MM(ZnSO₄) = 65.4 g/mol Zn + 32 g/mol S + (16 g/mol x 4) = 161.4 g/mol

Then, we divide the mass of ZnSO₄ into its molar mass to obtain the number of moles:

moles ZnSO₄ = mass/MM = 150 g/(161.4 g/mol)= 0.93 mol

Since the molarity of a solution expresses the number of moles of solute per liter of solution, we calculate the molarity (M) as follows:

M = moles ZnSO₄/1 L =  0.93 mol/1 L = 0.93 M

The one that does not demonstrates the law of conservation of matter would be the third option: \(2NO_2 + H_2O -- > HNO_3 + HNO_2\)

It is a law that explains that matters are conserved during the course of chemical reactions. They can neither be destroyed nor created.

Thus, the number of moles of the species in a reaction remains the same before and after the reaction.

Thus, an equation that demonstrates the law of conservation of matter will be balanced in terms of the number of moles of species.

The only equation, in this case, is \(2NO_2 + H_2O -- > HNO_3 + HNO_2\)

There are 3 oxygen species on the reactant while 5 are present on the product side.

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Answer:

Explanation:

When the Lewis base  (CH3)2NH reacts with Lewis acid Lewis acid (CH3CH2)3C⁺  which is also a carbocation , a new bond is formed as follows by the donation of a loan pair of electrons by the nitrogen atom of

(CH3)2NH . Here (CH3)2NH donates electrons so it acts as base and the second group accepts electrons so it is acid .

THe structure of the product formed is shown in the file attached .

The balanced redox reaction is \(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)

To balance the redox reaction: \(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}\), we need to ensure that the number of atoms and charges are balanced on both sides of the equation.

First, let's balance the atoms. We have one Fe atom on both sides, so it's already balanced. Next, we have two oxygen atoms on the reactant side (from \(NO^{2-}\) and \(H_{2}O\)) and three on the product side (from \(NO^{3-}\)). To balance oxygen, we can add an \(H_{2}O\) molecule to the reactant side:

\(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)

Now, let's balance the charges. On the reactant side, the total charge is 3+ (from \(Fe^{3+}\) ) + 1- (from \(NO^{2-}\)) = 2+. On the product side, the total charge is 2+ (from \(Fe^{2+}\)) + 1+ (from \(H^{+}\)) + 1- (from \(NO^{3-}\)) = 2+. The charges are already balanced.

Therefore, the balanced redox reaction is:

\(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)

By adding an additional H2O molecule to the reactant side, we balanced both the atoms and charges in the equation.

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Answer: A

Explanation:

q=heat absorbed=+250J

W=−PΔV=−0.5atm×(10−1)

=−4.5L−atm

=−4.5×101J=−454.5J

Now q=ΔE−W

ΔE=q+W=250−454.5

=−204.5J

The change in internal energy (ΔU) is -211 J.

According to the first law of thermodynamics;

ΔU = q + w

ΔU = change in internal energy

q = heat absorbed/ emitted

w = work done on or by the system

We can see from the question that  250 J of heat was absorbed from the surroundings hence q =  250 J

w= PΔV = 0.50 atm(10.1 L -  1.0 L) = 4.55 atm L

But;

1 L atm = 101.325 J

4.55 atm L =  4.55 atm L ×  101.325 J/ 1 L atm

= 461 J

Now;

ΔU = 250 J - 461 J

ΔU = -211 J

Note that work done is negative because the gas expands and does work on the surrounding.

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