The number 1.725 appears in the t chart corresponding to 20 degrees of freedom and aType I error value of 5%. Write down a deductive statement (that is, starting with the word "If")indicating how the number 1.725 was derived. (You do not have to discuss any mathematicalcalculation, which is indeed very difficult. Just outline the nature of the deductive statement.)

Answer:

5 years. Correct answer is D.

Step-by-step explanation:

Answer:

m∠JKM = 63°

m∠MKL = 27°

Step-by-step explanation:

Since ∠JKL is a right angle. This means that by summing up both m∠JKM and m∠MKL will result in the same as ∠JKL figure. Thus, m∠JKM + m∠MKL = m∠JKL which is 90° by a right angle definition.

\(\displaystyle{\left(12x+3\right)+\left(6x-3\right) = 90}\)

Solve the equation for x:

\(\displaystyle{12x+3+6x-3 = 90}\\\\\displaystyle{18x=90}\\\\\displaystyle{x=5}\)

We know that x = 5. Next, we are going to substitute x = 5 in m∠JKM and m∠MKL. Thus,

m∠JKM = 12(5) + 3 = 60 - 3 = 63°

m∠MKL = 6(5) - 3 = 30 - 3 = 27°

Answer:

yes

Step-by-step explanation:

The solution to the initial value problem 2y'' - 5y' - 3y = 0, with initial conditions y(0) = -3 and y'(0) = 1, is given by \(y(x) = 2e^{3*x}-3e^{-x}\) The graph of the solution will exhibit exponential growth and decay.

To solve the given initial value problem, we assume the solution has the form \(y(x)=e^{rx}\) and substitute it into the differential equation. We obtain the characteristic equation:

\(2r^{2} - 5r -3 =0\)

Factoring the quadratic equation, we get:

(2r + 1)(r - 3) = 0

Solving for r, we find two distinct roots: r = \(-\frac{1}{2}\) and r = 3.

Therefore, the general solution to the differential equation is given by:

\(y(x) = c_{1} e^{1/2x} + c_{2} e^{3x}\)

To find the particular solution, we use the initial conditions. Applying y(0) = -3, we have:

c₁ + c₂ = -3          (Equation 1)

Next, we differentiate y(x) to find y'(x):

\(y'(x) = -\frac{1}{2} c_{1} e^{-\frac{1}{2x} } + 3c_{2} e^{3x }\)

Applying y'(0) = 1, we have:

\(-\frac{1}{2} c_{1} + 3c_{2} =1\)  (Equation 2)

Solving Equations 1 and 2 simultaneously, we find c₁ = -2 and c₂ = -1.

Therefore, the particular solution is:

\(y(x) = -2e^{(-1/2x)} - e^{3x}\)

Simplifying further, we get:

\(y(x)=2e^{3x}-3e^{-x}\)

The graph of the solution will exhibit exponential growth as the term \(2e^{3x}\) dominates and exponential decay as the term \(-3e^{-x}\) takes effect.

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The equations which are equivalent to -1/4(x) + 3/4 = 12 are -1(x/4) + 3/4 = 12 and -x/4 +3/4 = 12. Choose the 2nd and 5th options

Equivalent equations are equations that work the same way even though they look different

The given equation is -1/4(x) + 3/4 = 12 which can simplified as:

-1/4(x) + 3/4 = 12

(-x + 3)/4 = 12

Compare with options:

1. 4x/1 + 3/4 = 12

4x/1 + 3/4 = 12

This is not equivalent

2. -1(x/4) + 3/4 = 12

-1(x/4) + 3/4 = 12

-x/4 + 3/4 = 12

(-x + 3)/4 = 12

This is equivalent

3. -(x+3)/4 = 12

-(x+3)/4 = 12

This is not equivalent

4. 1/4(x+3) = 12

1/4(x+3) = 12

This is not equivalent

5. -x/4 +3/4 = 12

-x/4 +3/4 = 12

(-x+3)/4 = 12

This is equivalent

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Answer:it’s b and d

Step-by-step explanation:

Two different ways to write f dA as an iterated integral for the shaded region R. 1 + R 1, in the order dy dx and dx dy.

To write f dA as an iterated integral in two different ways for the shaded region R. 1 + R 1, we need to first determine the limits of integration for each variable.

If we start with the order dy dx, we can see that the shaded region is bounded by y = 0, y = 2, x = 1 and x = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dy dx
= ∫1^2 ∫0²-x f(x,y) dy dx + ∫2³ ∫0 f(x,y) dy dx
= ∫1^2 [∫0²-x f(x,y) dy] dx + ∫2³ [∫0 f(x,y) dy] dx
(Note: We split the integral into two parts based on the two different regions.)

Alternatively, if we switch the order to dx dy, we can see that the shaded region is bounded by x = 1, x = 2, y = x-1 and y = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dx dy
= ∫0 ∫x+1² f(x,y) dy dx + ∫1² ∫1 f(x,y) dx dy
= ∫0 [∫x+1² f(x,y) dy] dx + ∫1² [∫1 f(x,y) dx] dy
(Note: We split the integral into two parts based on the two different regions.)

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Two different ways to write f dA as an iterated integral for the shaded region R. 1 + R 1, in the order dy dx and dx dy.

To write f dA as an iterated integral in two different ways for the shaded region R. 1 + R 1, we need to first determine the limits of integration for each variable.

If we start with the order dy dx, we can see that the shaded region is bounded by y = 0, y = 2, x = 1 and x = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dy dx
= ∫1^2 ∫0²-x f(x,y) dy dx + ∫2³ ∫0 f(x,y) dy dx
= ∫1^2 [∫0²-x f(x,y) dy] dx + ∫2³ [∫0 f(x,y) dy] dx
(Note: We split the integral into two parts based on the two different regions.)

Alternatively, if we switch the order to dx dy, we can see that the shaded region is bounded by x = 1, x = 2, y = x-1 and y = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dx dy
= ∫0 ∫x+1² f(x,y) dy dx + ∫1² ∫1 f(x,y) dx dy
= ∫0 [∫x+1² f(x,y) dy] dx + ∫1² [∫1 f(x,y) dx] dy
(Note: We split the integral into two parts based on the two different regions.)

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there are no domain restrictions for the expression x+5/27x^7y^5.

This is because there are no variables in the denominator and the only exponent is on the variable x. To determine domain restrictions, we need to look for values of the variables that would make the expression undefined. This can occur when there are variables in the denominator or when there are even roots (such as square roots) of negative numbers. However, in this expression, there are no variables in the denominator and no even roots. Therefore, there are no restrictions on the values that x and y can take. In summary, the expression x+5/27x^7y^5 has no domain restrictions and can be evaluated for any values of x and y.

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Answer:

B. 7 - 9i

Step-by-step explanation:

1) Remove Parentheses.

2 - 8i + 5 - i

2) Add 2 and 5.

7 - 8i - i

3) Subtract i from -8i.

7 - 9i

Answer:

Option B

The answer is 7 – 9i

Step-by-step explanation:

(2 – 8i) + (5 – i)

2 – 8i + 5 – i

7 – 9i

Thus, The answer is 7 – 9i

-TheUnknownScientist 72

"B: degrees of freedom > 10"  is not a way to check for the nearly normal condition.

To check the nearly normal condition, we can use several methods such as histogram, normal probability plot, and goodness of fit test. The central limit theorem can also be used when the sample size is large enough. However, checking the degrees of freedom is not a way to check for the nearly normal condition. Degrees of freedom refer to the number of independent pieces of information that are used to estimate a statistic. While it is important in hypothesis testing and confidence intervals, it is not related to checking for the nearly normal condition.

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Answer:

According to the equations in your comment.

C is the correct answer.

(x) = (x + 4)(x – 2)(3x – 2

x+4 = 0

x = -4

x-2 = 0

x = 2

3x - 2 = 0

3x = 2

x = 2/3

the angle bisector theorem formula yields the value x=10.

The angle bisector theorem states that RU/RT=US/ST or a/b = x/y. A line or ray known as an angle bisector divides an angle in a triangle into two identically sized parts.

The geometry concept known as the angle bisector theorem examines the ratios of the two segments that a line that bisects the opposing angle splits a triangle's side into. It contrasts their relative lengths with the ratios of the other two sides of the triangle.

Side ratio: RU/RT=US/ST

3x/40 = x+2/16

6x=5x +10

x=10

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Answer:

57*57*1000= 3249000

(>'-'<)    

Answer:

Figure needed

GOOD LUCK FOR THE FUTURE! :)

a0 is the regression term that describes the constant or intercept in the linear regression equation.

In a simple linear regression model, the equation takes the form of y = a0 + a1x + e1, where y is the dependent variable (or response variable), x is the independent variable (or predictor variable), a0 is the intercept or constant term, a1 is the coefficient of the independent variable, and e1 is the error term.

The intercept term, a0, represents the value of the dependent variable when the independent variable is zero. For example, in a linear regression model that predicts salary based on years of experience, the intercept would represent the starting salary for someone with zero years of experience. The intercept is an important component of the regression equation because it allows us to make predictions for values of x that are outside the range of our observed data.

The coefficient, a1, represents the change in the dependent variable for each one-unit increase in the independent variable. In the salary example, the coefficient would represent the average increase in salary for each additional year of experience.

Both the intercept and coefficient are estimated from the data using methods such as least squares regression. Once these values are estimated, we can use them to make predictions for new values of x.

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The expected number of matchings goes to infinity as N › [infinity].

Matching in Graph Theory:A matching in Graph Theory is a set of edges of a graph where no two edges share a common vertex. In other words, a matching is a set of independent edges of a graph. A perfect matching in a Graph Theory is a matching of size equal to half the number of vertices in a graph.The expected number of matchings goes to 0 as N › [infinity]:The expected number of matchings goes to zero as N › [infinity] when |E| = 3/N. It is because 3/N is a relatively dense number of edges that are independent of the number of vertices that can exist between A and B. The expected number of matchings is thus very small in comparison to the total number of matchings possible as N › [infinity].The expected number of matchings goes to infinity as N › [infinity]:The expected number of matchings goes to infinity as N › [infinity] when |E| = 4.V. It is because 4.V is a relatively large number of edges that are independent of the number of vertices that can exist between A and B. The expected number of matchings is thus very large in comparison to the total number of matchings possible as N › [infinity]. Hence the expected number of matchings goes to infinity as N › [infinity].

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The volume of the given figure is 434 ft³. The volume of the figure is obtained in the two parts.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The volume of the given figure is;

\(\rm V = l_1 \times b_1 \times h_1 + l_2 \times b_2 \times h_2 \\\\ V= 7 \times 13 \times 4 + 2\times 5 \times 7 \\\\ V= 434 \ fT^3\)

Hence, the volume of the given figure is 434 ft³.

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Answer:

Spend on gas each month with the new car=$120.

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

Considering the definition of a line and zero of a linear function, the zero of the linear function that passes through the point (3, 2) and has a slope of 2 is 2.

A linear equation o line can be expressed in the form y = mx + b

where

The points where a linear function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, zeros of the function are those values ​​of x for which the expression is equal to 0.

In this case, you know:

Substituting the value of the slope m, you get:

y= 2x +b

Replacing the value of the point in the  previous expression, the value of the ordinate to the origin b can be obtained:

2= 2×3 + b

2= 6 + b

2-6= b

-4= b

The equation of the line that passes through the point (3, 2) and has a slope of 2 is y= 2x -4.

The zero of the function is calculated as:

0= 2x -4

Solving:

0 + 4= 2x

4= 2x

4÷2= x

2=x

Finally, the zero of the linear function is 2.

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To test the hypothesis H0: μ1 − μ2 = −10 versus Ha: μ1 − μ2 < −10, a two-sample t-test is used. Given the data m = 8, x = 115.6, s1 = 5.04, n = 8, y = 129.3, and s2 = 5.32, we can calculate the test statistic and determine the p-value.

The test statistic for a two-sample t-test is calculated as follows:

t = (x - y - d) / sqrt((s1^2 / m) + (s2^2 / n))

where x and y are the sample means, d is the hypothesized difference in means (in this case, -10), s1 and s2 are the sample standard deviations, and m and n are the sample sizes.

Substituting the given values, we have:

t = (115.6 - 129.3 - (-10)) / sqrt((5.04^2 / 8) + (5.32^2 / 8))

Calculating the numerator and denominator separately:

t = -23.7 / sqrt(3.15 + 3.34)

t ≈ -23.7 / sqrt(6.49)

t ≈ -23.7 / 2.55

t ≈ -9.29

The degrees of freedom for the t-test is (m + n - 2) = 8 + 8 - 2 = 14.

To determine the p-value, we compare the test statistic to the t-distribution with the appropriate degrees of freedom. In this case, with a one-tailed test and a significance level of 0.01, the p-value is less than 0.01.

Therefore, the test statistic is approximately -9.29, and the p-value is less than 0.01.

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==================================================

Work Shown:

4x^3 - 4

4(x^3 - 1)

4(x - 1)(x^2 + x + 1)

In the last step, I used the difference of cubes factoring formula which is

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

Answer: (a)

Step-by-step explanation:

Given

The given graph is y=-2x+6 and it changed to y=3x+2

The slope of the graph determines the steepness

Slope changes from -2 to 3. So, latter graph is more steeper.

Also, y intercept is obtained by putting x as 0

Y intercept changes from 6 to 2 i.e. decrease of 4 units

Hence, option (a) is correct.

The graph of N(t) = 75t + 120 is a straight line with a positive slope of 75. It intersects the y-axis at (0, 120) and has a y-intercept of -8/5. As t approaches infinity, N(t) increases without bound, indicating a positive relationship between the number of days of training and the average number of components assembled per day.

To sketch the graph of N(t) = 75t + 120, we can plot points on the coordinate plane by substituting different values of t into the equation.

For example, when t = 0, N(0) = 75(0) + 120 = 120. So, we have the point (0, 120).

When t = 1, N(1) = 75(1) + 120 = 195. So, we have the point (1, 195).

We can continue to calculate more points using different values of t.

The intercept is when N(t) = 0:

0 = 75t + 120

-120 = 75t

t = -120/75

t = -8/5

So, we have the intercept (0, -8/5).

To find the asymptote, we need to check what happens to N(t) as t approaches infinity. As t becomes larger and larger, the constant term 120 becomes less significant compared to the term 75t. Therefore, as t approaches infinity, N(t) approaches infinity as well.

In practical terms, this means that as the number of days of training (t) increases, the average number of components assembled (N) per day also increases. However, it is important to note that this is based on past records and the actual performance of new employees may vary. The equation provides an average trend and does not account for individual variations or other factors that may affect productivity.

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Answer:

Step-by-step explanation:

2700x y = 3 * 3 * 3 * 2 * 2 * 5 * 2 * x * y

27y³ = 3 * 3 * 3 * y * y * y

GCF = 3*3*3*y

        = 27y

Answer:  2√33

Step-by-step explanation:  First we will find all factors under the square root: 132 has the square factor of 4. Let's check this width √4*33=√132.

Answer:

2731.87324

Step-by-step explanation:

i just know

Answer:

hmm.. very blurry repost please

Step-by-step explanation:

Answer:

what kind of thesis are you wanting?

a) The series (+1) + 22/ns is absolutely convergent, and

b)  The series (-1)n / ln(n) is also convergent.

(a) The given series is (+1) + 22/ns.

To determine if this series is absolutely convergent, conditionally convergent, or divergent, we need to examine the behavior of the absolute values of the terms. In this case, the series of absolute values is 1 + 22/ns.

When we take the limit as n approaches infinity, we can see that the term 22/ns approaches zero, and the term 1 remains constant. Therefore, the series of absolute values simplifies to 1, which is a convergent series.

Since the series of absolute values converges, the original series (+1) + 22/ns is absolutely convergent.

(b) The given series is (-1)n / ln(n), where n starts from 2.

Similarly, we need to analyze the behavior of the series of absolute values: |(-1)n / ln(n)|.

The absolute value of (-1)n is always 1, so we are left with |1 / ln(n)|. To determine the convergence or divergence of this series, we can use the limit comparison test.

Let's consider the series 1 / ln(n). Taking the limit as n approaches infinity, we have:

lim(n→∞) (1 / ln(n)) = 0.

Since the limit is zero, the series 1 / ln(n) converges. Now, we compare the original series |(-1)n / ln(n)| with 1 / ln(n).

Using the limit comparison test, we have:

lim(n→∞) (|(-1)n / ln(n)| / (1 / ln(n))) = lim(n→∞) |(-1)n| = 1.

Since the limit is a nonzero constant, the series |(-1)n / ln(n)| behaves in the same way as the series 1 / ln(n). Therefore, both series have the same convergence behavior.

Since the series 1 / ln(n) converges, the original series (-1)n / ln(n) is also convergent.

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According to unitary method, Beau needs 60 wheels in all to build 9 puppy bots and 6 kitty bots.

The unitary method is a mathematical technique used to solve problems by finding the value of one unit and then calculating the value of the required quantity by multiplying or dividing it with the given value of units.

Given that each bot needs 4 wheels, we can find the number of wheels required to build one bot. Using the unitary method, we can say that one bot needs 4 wheels. Therefore, 9 puppy bots will need 9 times 4 wheels, which is 36 wheels.

Similarly, 6 kitty bots will need 6 times 4 wheels, which is 24 wheels. To find the total number of wheels required to build all the bots, we can add the number of wheels required for puppy bots and kitty bots

Total number of wheels required = 36 + 24 = 60

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Answer:

3.6 hours

Step-by-step explanation:

One person can complete a typing project in 6 hours,

Hence, in 1 hour, 1/6 of the project is completed by person A

Another can complete the same project in 9 hours.

Hence, in 1 hour, 1/9 of the project is completed by person B

Let the number of hours of completing the project be represented by 1

Hence,

x/6 + x/9 = 1

We find the L.C.M

9x + 6x/54= 1

15x/54 = 1

Cross Multiply

15x = 54

x = 54/15

x = 3.6 hours.

Therefore, both people can complete the project in 3.6 hours.