The new number, 200, is 400 less than the original number. What is the approximate percent change?
The percent change is approximately 0.6%.
The percent change is approximately 1.5%.
The percent change is approximately 66%.
The percent change is approximately 150%.

Answer:

Yes

Step-by-step explanation:

29×29=841

21×21=441

20×20=400

29^2-21^2=20^2

841-441=400

400=400

Yes it is a right angle triangle

Answer:

100%

50%

50%

50%

300%

300%

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

150 cookies = 6 hours

÷6 ÷6

25 cookies = 1 hour

Answer:

Yes

Step-by-step explanation:

To find this, we need to know what number multiplied by itself will give us 4/16, also written as 1/4.

When multiplying fractions, you multiply the top together and the bottom together. Making a function with this rule, we get (1/4)=(1/x^2) With this in mind, we can just figure out what the denominator would need to be as the top is 1 on both sides. So now all we're solving for is x^2=4. Taking the square root of both sides, we get x=2.

Thus, (1/2)^2 is 1/4 or 4/16, and proves that the square root of 4/16 is in fact rational.

Answer:

Step-by-step explanation:

if m is the slope of given line.

Then eq. of parallel line through (-4,-6) is

y+6=m(x+4)

Answer:

y=-6

Step-by-step explanation:

The line shown is a horizontal line through the y-axis and has the equation y=4. A parallel line to it is a line that does not cross it. It will also have the form y=a where a is the y-coordinate of its points. The point (-4,-6) is on the line so y=-6 is the line.

\(\mathbb{ANSWER:}\)

\(\sf \frac{-3-\sqrt{2} }{3\sqrt{17} }\)

\(\sf = \frac{-3-\sqrt{2} }{3\sqrt{17} } \cdot \frac{\sqrt{17} }{\sqrt{17} }\)

\(\sf = \boxed{\sf \frac{-3\sqrt{17} - \sqrt{34} }{51} }\)

The original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

To show that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves, we need to take the derivative of the equation and set it equal to -1/b^2, the slope of the orthogonal line.

First, we take the derivative of the equation with respect to x:

2x/a^2 = -2y/b^2 * dy/dx

Simplifying, we get:

dy/dx = -b^2*x/a^2*y

Now, we set this equal to -1/b^2:

-b^2*x/a^2*y = -1/b^2

Cross-multiplying and simplifying, we get:

x/a^2*y = 1/b^2

Finally, we can rearrange this equation to get:

y = b^2*x/a^2

This equation represents the orthogonal family of curves to the original family of conics. Since the original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

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Answer:

Step-by-step explanation:

It will be 115$

Answer:  the answer is $21.7391304348 or round to $21.74 is the cost for 50 gallons

Step-by-step explanation: I did the calculations and it costs $2.30  a gallon

Answer:

The discriminant of f is 92, and it has no real zeros

Step-by-step explanation:

The discriminant of a quadratic is \(b^2-4ac\), where the quadratic is in the form \(ax^2+bx+c\). The discriminant of this one is therefore:

\(2^2-4(4)(6)=4-96=-92\)

Since the square root of a negative number is imaginary, this quadratic has no real number zeros. Hope this helps!

To achieve a 5% juice concentration in a solution, add an indeterminate amount of pure water, while the specific values of added juice and total solution depend on additional information.

To achieve a remaining solution containing 5% juice, the following steps can be followed:

1. Calculate the amount of juice in the original solution:

  a = 10 gallons * 15% = 1.5 gallons

2. Determine the original amount of solution in gallons:

  b = 10 gallons

3. Calculate the amount of juice added:

  c = (b + d) * 5% - a

  Here, 'd' represents the amount of pure water added.

4. Determine the total solution added:

  d = (a - (b * 5%)) / 5%

  Rearranging the formula, d = (1.5 gallons - (10 gallons * 5%)) / 5%

The specific values of 'c' and 'd' cannot be determined without additional information.

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Answer:

-2

Step-by-step explanation:

because it is on the -2 area

The correct option for this questions is Option C

1/3, 2/6, 3/9, 4/12, 5/15, 6/18, 7/21, 8/24, 9/27, 10/30, 11/33, 12/36, 13/39, 14/42, 15/45, 16/48, 17/51, 18/54, 19/57, 20/60, and so on ...

Two frations are equivalent when they have the same value when written in lowest terms. The fraction 8/24 is equal to 1/3 when reduced to lowest terms. To find equivalent fractions, just multiply the numerator and denominator of that reduced fraction (1/3) by any interger number, ie, multiply by 2, 3, 10, 30.

Equivalent fractions may look different, but when you reduce then to the lowest terms you will get the same value. If any fraction is not reduced to lowest terms, you can get other equivalent fractions just dividing both numerator and denominator by the same number.

Thus, option c is your answer

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Answer:

y=3x+6

Step-by-step explanation:

The slope form can be written as y=mx+b

m is the slope, which is 3 in this case.

b is the y-intercept (6).  

Add those values into the slope form equation.  Just leave y as is.

In  Arithmetic Progression , 56 inches of snowfall will cause the snowplow to be immobile.

What is Arithmetic Progression in math?

Let x inches of snowfall will cause the showplow to be immobile .

By a.p. formula ,

                aₙ = a + ( n - 1) d

                 aₙ= 0 ( show plow's speed is 0 ,miles/hour )

              a = 39

              n = x inches

             d = - 2.5 mile/hour

         0 = 39 + ( n - 1 ) ( -2.5)

            ( n - 1 ) ( -2.5) = -39

              n- 1 = -39/2.5 = 15.6

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Answer:

The slope of the line is zero

Another point on the line is (3,10).

The equation of the line is y = 10.

Step-by-step explanation:

an i get brainliest plz

Answer:

got right on edge

Step-by-step explanation:

The decoded answer is: "The difference between a teacher and a railroad engineer is that a teacher is 70."

To decode the answer, we need to match the average values calculated with the corresponding letters. Let's calculate the averages and see which values match with the given code.

S = Average of 78 and 56 = (78 + 56) / 2 = 134 / 2 = 67

H = Average of 75, 181, 114, and 78 = (75 + 181 + 114 + 78) / 4 = 448 / 4 = 112

W = Average of 92 and 110 = (92 + 110) / 2 = 202 / 2 = 101

N = Average of 45, 19, 67, 7, and 12 = (45 + 19 + 67 + 7 + 12) / 5 = 150 / 5 = 30

M = Average of 45, 98, and 73 = (45 + 98 + 73) / 3 = 216 / 3 = 72

G = Average of 97, 89, and 57 = (97 + 89 + 57) / 3 = 243 / 3 = 81

I = Average of 96, 94, 85, 97, and 93 = (96 + 94 + 85 + 97 + 93) / 5 = 465 / 5 = 93

T = Average of 15, 6, 99, 145, and 85 = (15 + 6 + 99 + 145 + 85) / 5 = 350 / 5 = 70

O = Average of 63, 124, 90, 42, and 51 = (63 + 124 + 90 + 42 + 51) / 5 = 370 / 5 = 74

L = Average of 128, 175, and 165 = (128 + 175 + 165) / 3 = 468 / 3 = 156

E = Average of 7, 18, 12, 24, 4, and 91 = (7 + 18 + 12 + 24 + 4 + 91) / 6 = 156 / 6 = 26

Y = Average of 22, 38, 70, 42 = (22 + 38 + 70 + 42) / 4 = 172 / 4 = 43

D = Average of 38, 27, 12, and 19 = (38 + 27 + 12 + 19) / 4 = 96 / 4 = 24

C = Average of 17, 102, 36, and 37 = (17 + 102 + 36 + 37) / 4 = 192 / 4 = 48

A = Average of 78, 198, 176, 49, 186, and 201 = (78 + 198 + 176 + 49 + 186 + 201) / 6 = 888 / 6 = 148

R = Average of 77, 8, 35, 10, 56, and 24 = (77 + 8 + 35 + 10 + 56 + 24) / 6 = 210 / 6 = 35

Now, let's match the averages with the code provided:

Coded Answer:

70 - 112 - 26

70 - 26 - 148 - 48 - 112 - 26 - 35

70

35 148 - 93 - 30 - 67

70 - 112 26.

72 93 30 24

101 112 93 - 156 - 26

70 - 112 - 26

26 30 81 - 93 - 30 - 26 - 26 - 35

72 93 30 24 - 67

70 - 112 26

70 35 148 - 93 - 30

Matching the values with the coded answer, we get:

S = 70, H = 112, W = 26, N = 70, M = 26, G = 148, I = 48, T = 112, O = 26, L = 35, E = 26, Y = 35, D = 24, C = 30, A = 81, R = 93

So, the decoded answer is:

"The difference between a teacher and a railroad engineer is that a teacher is 70."

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a) The probability that his weight is greater than 175 lb is approximately 0.4602 (b) the probability that the mean weight of 20 randomly selected men is greater than 175 lb is approximately 0.6772.

To determine the minimum score for admission consideration at George Mason University, we need to find the 90th percentile score of the normally distributed college entrance examination scores. The mean score is 550 and the standard deviation is 100.

Using a standard normal (Z) table, we find that the Z-score corresponding to the 90th percentile is 1.28. To calculate the required minimum score (X), we can use the formula: X = μ + Zσ, where μ is the mean, Z is the Z-score, and σ is the standard deviation. Thus, X = 550 + (1.28)(100) = 550 + 128 = 678. An applicant must score at least 678 to be considered for admission.

For the second question, a) the probability that a randomly selected man weighs more than 175 lb can be determined using the Z-score formula: Z = (X - μ) / σ. Plugging in the values, Z = (175 - 172) / 29 ≈ 0.10. Checking the Z-table, we find the probability to be approximately 0.4602.

b) To find the probability that the mean weight of 20 randomly selected men is greater than 175 lb, we first determine the standard error (SE) of the sample mean using the formula: SE = σ / √n, where σ is the population standard deviation and n is the sample size. In this case, SE = 29 / √20 ≈ 6.48. Now, we calculate the Z-score: Z = (175 - 172) / 6.48 ≈ 0.46. Referring to the Z-table, the probability is approximately 0.6772.

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It is true, as The term "ecological correlation" refers to correlations based on rates or averages that frequently appear in political science or sociology and tend to exaggerate the significance of a link.

Correlations describe the connections between different variables. Strong, weak, positive, or negative expressions are all possible. 1 = Causation need not always follow from correlation. A statistical measure of the linear relationship between two variables is called correlation (that is, do they change at a constant rate). Without defining cause and effect, this is a common method for illustrating straightforward connections. To illustrate the connection between two quantitative variables, statistical language employs correlation. Additionally, we consider that this connection is linear. In other words, when one variable changes by a given amount, the other variable also changes by a fixed amount, but only by one unit.

The term "ecological correlation" refers to correlations based on rates or averages that frequently appear in political science or sociology and tend to exaggerate the significance of a link.

So, it is true.

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It will take both machines approximately 1.71 hours or 1 hour and 42 minutes to produce widgets together.

To solve this problem, we can use the formula:

1 / time taken by machine 1 + 1 / time taken by machine 2 = 1 / time taken by both machines

Let's denote the time taken by the old machine as x hours and the time taken by the new machine as y hours.

From the problem statement, we know that the old machine can produce widgets in 3 hours, so we have:

1 / x = 1 / 3

Solving for x, we get:

x = 3

Similarly, we know that the new machine can produce widgets in 4 hours, so we have:

1 / y = 1 / 4

Solving for y, we get:

y = 4

Now, we can plug in the values of x and y into the formula and solve for the time taken by both machines:

1 / 3 + 1 / 4 = 1 / t

Multiplying both sides by 12t, we get:

4t + 3t = 12

7t = 12

t = 12 / 7

Therefore, it will take both machines approximately 1.71 hours or 1 hour and 42 minutes to produce widgets together.

In conclusion, we used the formula for the combined work rate of two machines to calculate the time taken by both machines to produce widgets. We first found the individual work rates of the old and new machines and then substituted those values into the formula to solve for the time taken by both machines working together.

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Answer: 60

Step-by-step explanation:

1=10. x6=60

Form the given five quadratics , the one representing the repeated roots is equal to option d. 25x² - 30x + 9 and repeated roots are 3/5 or 3/5.

Quadratics representing repeated roots has discriminant equals to zero.

Standard quadratic equation is:

ax² + bx + c = 0

Discriminant 'D' = b² - 4ac

option a. -x²+ 18x + 81

Discriminant

'D' = 18² - 4(-1)(81)

      = 324 + 324

      = 648

D>0 has distinct roots.

option b. 3x²- 3x - 168

Discriminant

'D' = (-3)² - 4(-3)(-168)

      = 9 - 2016

      = -2007

D< 0 has distinct roots.

option c. x²- 4x -  4

Discriminant

'D' = (-4)² - 4(1)(-4)

      = 16 + 16

      = 32

D>0 has distinct roots.

option d. 25x²- 30x + 9

Discriminant

'D' = (-30)² - 4(25)(9)

      = 900 - 900

      = 0

D = 0 has repeated roots.

Repeated roots are:

x = ( -b ±√D ) / 2a

  = [-(-30)±√0 ]/ 2(25)

  = 30/ 50

  = 3/5.

option e.  x² - 14x + 24

Discriminant

'D' = (-14)² - 4(1)(24)

      = 196 - 96

      = 100

D>0 has distinct roots.

Therefore, the quadratics which represents the repeated roots are given by option d. 25x² - 30x + 9 and its repeated roots are 3/5 or 3/5.

The above question is incomplete, the complete question is:

One of the five quadratics below has a repeated root. (There other four have distinct roots.) What is the repeated root?

a. -x²+ 18x + 81

b. 3x² - 3x - 168

c. x² - 4x - 4

d. 25x² - 30x + 9

e. x² - 14x + 24

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The probability that at least one box in a selection of three candy gift boxes will weigh less than 34 ounces needs to be found.

To calculate the probability, the weight of a box can be considered as the sum of the weights of the individual candies in the box. The weights of the individual candies are normally distributed with known means and standard deviations.

Using the properties of normal distributions, the weights of the boxes can be modeled as normally distributed with a mean of 27 ounces (9 candies x 3 ounces per candy) and a standard deviation of 0.374 ounces (sqrt(4*(0.2^2)+5*(0.3^2)+0.1^2)). Then, the probability of at least one box weighing less than 34 ounces can be calculated using the normal distribution function.

The calculated probability is 0.0569, or approximately 5.69%. Thus, there is a 5.69% chance that at least one of the three selected candy gift boxes will weigh less than 34 ounces.

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The probability that at least one box will weigh less than 34 ounces is approximately 0.117.

To solve this problem, we can use the Central Limit Theorem to approximate the distribution of the total weight of three gift boxes. The mean weight of one gift box is 3*(4)+5*(3) = 27 ounces, and the standard deviation is sqrt((4*(0.2)^2 + 5*(0.3)^2)) = 0.69 ounces.

The probability that one gift box weighs less than 34 ounces is given by the standard normal distribution, which we can find using a z-score of (34-27)/0.69 = 10.14.

The probability that all three boxes weigh at least 34 ounces is (1-0.117)^3 = 0.770, so the probability that at least one box weighs less than 34 ounces is approximately 1 - 0.770 = 0.117.

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Expressing 198 : 1287 in its simplest form, gives the value 2 :13 ; Hence, the two ratio expressions are equivalent.

In other to determine if 198:1,287 and 2:13 are equivalent ratios ;

Dividing both values by 99 ;

198 : 1287 = 2 : 13

Since, the ratio 198 : 1287 simplified to its lowest term equals 2 : 13 ; then both ratios are equivalent.

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False. A mapping T: Rn → Rm is onto Rm if and only if every vector in Rm has a pre-image in Rn, not necessarily every vector in Rn maps onto some vector in Rm.

the statement "A mapping T: Rn → Rm is onto Rm if every vector x in Rn maps onto some vector in Rm" is false.

to determine if a mapping T: Rn → Rm is onto Rm, we need to check if every vector in the target space Rm has a pre-image in the domain Rn. In other words, for the mapping to be onto, every vector in Rm must have at least one vector in Rn that maps to it. However, it is not necessary for every vector in Rn to map onto some vector in Rm.

A counterexample can be a mapping from R2 to R3, where the vectors in R2 are mapped to the x-y plane in R3. In this case, since the z-coordinate is not used, there are vectors in R3 that do not have a pre-image in R2. Therefore, the mapping is not onto.

Hence, the statement is false because it incorrectly implies that every vector in Rn maps onto some vector in Rm is a sufficient condition for a mapping to be onto Rm, which is not the case.

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Answer:

80° and 100°

Step-by-step explanation:

let 'x' and 'y' equal each angle

x + y = 180

now we could let y = .8x and use substitution to get this equation:

x + 0.8x = 180

1.8x = 180

x = 100

y = 80

Answer:

5750

Step-by-step explanation:

add the 3 populations together, divide by the number of populations (3)

Answer:

=-0.809

Step-by-step explanation:

3x^2+5x+7=0 complete the square

3x^2+5x=-7 divide both sides by 3

x^2+5/3 x = -7/3  to complete the square add term(b/2)^2=((5/3)/2)²=25/36

X^+5/3 x+25/36=-7/3 +25/36 factorize

(x+5/6)²= -59/36

x+5/6= + or - √59/36

solution for x= -5/6-√59/6i  (u) OR -5/6+√59/6i (v)

u/v + v/u=(-5/6-√59/6i)/(-5/6+√59/6i) +(-5/6+√59/6i)/(-5/6-√59/6i)=-17/21

=-0.809

Answer:

\(\large \boxed{\sf \ \ \ -\dfrac{17}{21}=-0.80952... \ \ \ }\)

Step-by-step explanation:

Hello,

First of all we can verify that 0 is not a solution of the equation so that we can divide by u or v

\(\dfrac{v}{u}+\dfrac{u}{v}=\dfrac{u^2+v^2}{uv}=\dfrac{(u+v)^2-2uv}{uv}=\dfrac{(u+v)^2}{uv}-2\)

And we know that

\(u+v=-\dfrac{5}{3}\\\\uv=\dfrac{7}{3}\\\\\\as \ \ (x-u)(x-v)=x^2-(u+v)x+uv\)

So it comes

\(\dfrac{v}{u}+\dfrac{u}{v}=\dfrac{5^2*3}{7*3^2}-2=\dfrac{25-42}{21}=-\dfrac{17}{21}=-0.80952...\)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you