the motion of earth's rigid plates known as plate tectonics is driven by the flow of hot rock in the ________.​

Answer:

3.26mph

Explanation:

To calculate speed, use the formula distance/time. In this case, just divide 14.7  by 4.5.

The speed with which the cat runs towards its food bowl is 7.3 Miles per hour.

Given the data in the question

Speed of the cat; \(v = \ ?\)

Speed is the time rate at which an object is moving along a path

Speed is the time rate at which an object is displaced.

Speed = Distance / Time

\(v = s / t\)

We substitute our values into the equation

\(v = \frac{14.7m}{4.5s}\\\\v = 3.267 m/s\\\\v = 7.3mph\)

Therefore, the speed with which the cat runs towards its food bowl is 7.3 Miles per hour.

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A projectile's horizontal velocity is constant (a never changing in value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion.

For relatively small displacements, the force of gravity has little effect on an object's horizontal motion. This indicates that while the vertical velocity is accelerating, the horizontal velocity is remaining constant. The cause is that perpendicular vectors behave differently from one another. A projectile's vertical velocity is zero at its maximum height. There is now only the horizontal velocity.

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Answer:

D

Explanation:

D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.

(a) The average acceleration of this sprinter is 3.31 m/s².

(b) The time taken for the sprinter to reach the speed is 3.5 s.

The average acceleration of this sprinter is calculated as follows;

v² = u² + 2as

where;

v² = 0 + 2as

a = v² / 2s

a = ( 11.5² ) / ( 2 x 20 )

a = 3.31 m/s²

The time of motion of the sprinter is calculated as follows;

v = u + at

v = 0 + at

t = v / a

t = ( 11.5 ) / ( 3.31 )

t = 3.5 s

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Answer:

B. Randomly assigning students to the two different groups

Explanation:

The bias can be controlled by making use of the randomized block design where we divide the subject into subgroups also called blocks and randomly assign treatment conditions to each block.

In this case, the blocks or sub groups are learning math from a video game and learning it from traditional classroom activities.

So the best way to control the bias is by randomly assigning students to the different groups.

Answer:

86.7

Explanation:

sana makatulong yung answer ko

Answer:

The answer will be it has a mass of 40 kg.

Explanation:

Because Force = mass x acceleration or F = m a, we can say Force divided by mass or F/a = m or mass so 600 divided by 15 equals 40 kg.

Answer:

Work is the energy needed to apply a force to move an object a particular distance, where force is parallel to the displacement. Power is the rate at which that work is done.

Answer: Work is the energy needed to apply a force to move an object a particular distance, where force is parallel to the displacement. Power is the rate at which that work is done.

Explanation:

Everything but blue & orange would now be present in the spectrum of light observed.

Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.

The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.

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Complete Question: -

Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?

Given,

The radius of Sun, \(r=1.5\times 10^{11}\ m\)

To find,

The centripetal acceleration of the Earth towards the Sun.

Solution,

The centripetal acceleration of an object is given by the formula as follows :

\(a=\omega^2 r\) ....(1)

Where

\(\omega\) is angular velocity

First calculate the angular velocity.

\(\omega=\dfrac{2\pi}{1\ \text{day}}\\\\=\dfrac{2\pi}{24\times 3600\ s}\\\\=7.27\times 10^{-5}\ s^{-1}\)

Put all the values in formula (1)

\(a=\omega^2 r\\\\=(7.27\times 10^{-5})^2\times 1.5\times 10^{11}\\\\=792.79\ m/s^2\)

So, the centripetal acceleration of the Earth towards the Sun is \(792.79\ m/s^2\).

Answer:800 Joules

Explanation: Energy = Power × Time = 100∗8100∗8 = 800 joules

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

\(K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ\)

So, the required kinetic energy is equal to 1800 kJ.

Time = (20 km) x (1 hr/2 km) x (3,600 sec/hr)

Time = (20 x 1 x 3,600 km-hr-sec) / (2 km-hr)

Time = (20 x 1 x 3,600 / 2) (km-hr-sec / km-hr)

Time = 36,000 seconds

(That's 10 hours.)

Answer:

  v = 10 m / s

Explanation:

For this exercise we will use the relationship between the speed of a wave and its frequency and wavelength

         v = λ f

the wavelength is the distance at which the wave repeats, in this case the distance between the two ridges λ = 48 m.

the frequency is the number of oscillations per unit of time, it is also the inverse of the period which is the time in a complete oscillation, in this case they give us the time of half a period, ½ T = 2.4 s

   T = 4.8 s

the frequency is

        f = 1 / T

        f = 1 / 4.8

        f = 0.2083 Hz

let's calculate

        v = 0.2083 48

        v = 10 m / s

The potential energy at Point A is 44 joules. The potential energy at a height of 0.8 m is 32 joules, and to find the mechanical energy at point A, one need to consider both the potential energy and the kinetic energy of the ball.

Potential Energy at Point A: Potential energy is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Given: Mass of the ball (m) = 4 kg

Height at Point A (h) = 1.1 m

Acceleration due to gravity (g) = 10 m/s²

Potential Energy at Point A = mgh

Potential Energy at Point A = 4 kg × 10 m/s² × 1.1 m

Potential Energy at Point A = 44 Joules

So, the potential energy at Point A is 44 Joules.

Potential Energy at Height 0.8 m: To find the potential energy at a height of 0.8 m, one will use the same formula.

Given: Height at Point = 0.8 m

Potential Energy at Height 0.8 m = mgh

Potential Energy at Height 0.8 m = 4 kg × 10 m/s² × 0.8 m

Potential Energy at Height 0.8 m = 32 Joules

So, the potential energy at a height of 0.8 m is 32 joules.

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The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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8.27 x 1013 meres is the orbital radius.

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

To calculate the work done by a force, we can use the formula:

Work = ∫F dx

In this case, the force is given by Fx = (2x + 7) N, and the particle moves along the X-axis from X1 = 1 m to X2 = 5 m. Let's calculate the work done.

Work = ∫(2x + 7) dx

Integrating the function (2x + 7) with respect to x, we get:

Work = (x^2 + 7x) evaluated from X1 to X2

Plugging in the values X2 = 5 and X1 = 1 into the expression, we have:

Work = (5^2 + 7 * 5) - (1^2 + 7 * 1)

= (25 + 35) - (1 + 7)

= 60 - 8

= 52

Therefore, the work done by the force is 52 Joules (J).

Explanation:

The momentum of an 8 kg bowling ball rolling at 2 m/s straight to the pins is  16 kg m/s.

As momentum depends on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Since velocity is a vector and mass is a scalar, momentum is a vector quantity. It is given by the formula:

p = mv

p = 8 × 2

p = 16 kg m/s

Velocity can be defined as the rate at which something moves in a specific direction. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.

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When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.

Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.

Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.

To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²

Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds

Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

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Answer:

jupiter

Explanation:

from the list, Jupiter is closest to the sun.

Answer:

A)   F_g = 4.05 10⁻⁴⁷ N, B)   F_e = 9.2 10⁻⁸N, C)    \(\frac{F_e}{F_g}\) = 2.3 10³⁹

Explanation:

A) It is asked to find the force of attraction due to the masses of the particles

Let's use the law of universal attraction

            F = \(G \frac{m_1m_2}{r^2}\)

let's calculate

            F = \(6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }\)

            F_g = 4.05 10⁻⁴⁷ N

B) in this part it is asked to calculate the electric force

Let's use Coulomb's law

            F = \(k \ \frac{q_1q_2}{r^2}\)

let's calculate

            F = \(9 \ 10^9 \ \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}\)

             F_e = 9.2 10⁻⁸N

C) It is asked to find the relationship between these forces

        \(\frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }\)

        = 2.3 10³⁹

therefore the electric force is much greater than the gravitational force

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:

P=126W

Explanation:

Sorry if im wrong!

Answer:

125.5 watts

Explanation:

P=work/time

work=F*d

P=(F*d)/t

P=(15*251)/30

P=125.5 watts

Answer:

No. of protons = 15

No. of electrons = 15

No. of Neutrons = 16

Answer:

1. Number of protons: 15

2. Number of electrons: 15

3. Number of Neutrons: 16

Hope this Helped!!!!!

The buoyant force acting on the cylinder is, \(Fb = \rho Ahg\). Here A is the cross-sectional area of the cylinder, h is the height of the cylinder, ρ is the density of the cylinder, and g is the acceleration due to gravity.

This buoyant force is also equal to the volume of the fluid displaced. \(Fb = \sigma h(A-x)g\). Here σ is the density of the fluid.

Equate the above two equations and solve for x.

\(\rho Ahg = \sigma A(h-x)g\\\rho h = \sigma h - \sigma x\\x = \frac{(\sigma - \rho)h}{\sigma}\)

So, the distance x depends on the density of the fluid, density of the cylinder and the height of the cylinder.

1. The density of the cylinder is same and distance x is independent of the diameter of the cylinder. Therefor, there will be no change in the distance x. Hence, the correct answer is No change.

2. Now the height is changing keeping the density same. As the distance x is directly proportional to the height, the distance x will increase.

3. The density of the added liquid is greater than of the water and it does not mix with the water. So, the liquid will settle down and there will be no change in the distance x.

4. The density of the added liquid is less than that of the water and it does not mix with the water. So, the liquid will not settle down and the distance x will change. The change in distance x can be determined as follow:

\(\rho Agh = \sigma' Axg + \sigma A(h-x)g\\\rho h=\sigma' x + \sigma h - \sigma x\\x=(\frac{\sigma - \rho}{\sigma - \sigma'})h\)

Here, σ' is the density of the added liquid.

From the above relation it is clear, that on adding the liquid of the density less than that of water, the denominator term become small ando so the value of x will increase.  

5. On removing some of the water inside the glass, the height of the water column will decrease, but the value of x does not depend on the height of the water column. So, there will be no change in the distance x.

6. The density of the new cylinder is smaller than that of the earlier one. So, the numerator term will increase. Therefore, the value of x will increase.

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Answer: a

Explanation: