The most stable group of elements on the periodic table is the?
A) halogens
B) noble gases
C) alkali earth metals
D) alkaline earth metals

Answer:

a) 2.632 kg

b) 41.36 kg

Explanation:

Given data:

Mass of CO react = ?

Mass of Fe formed = 3.50 Kg (3.50 /1000 =3500 g)

Mass of CO₂ formed = ?

Solution:

Chemical equation;

Fe₂O₃ + 3CO     →   2Fe + 3CO₂

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles =  3500 g/55.85 g/mol

Number of moles = 62.67 mol

now we will compare the moles of iron with CO.

            Fe         :       CO

             2          :       3

          62.67     :        3/2×62.67 = 94 mol

Mass of CO:

Mass = number of moles × molar mass

Mass = 94 mol × 28 g/mol

Mass = 2632 g

In kilogram:

2632g × 1 Kg /1000 g

2.632 kg

Now we will compare the moles of Fe with CO₂

                 Fe         :           CO₂

                  2          :           3

               62.67     :        3/2×62.67 = 94 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 94 mol × 44 g/mol

Mass = 4136 g

In kilogram:

4136g × 1 Kg /1000 g

41.36 kg

Answer: Compound A, a salt of a strong acid and a feeble base, is most likely represented by the solubility curve designated C. The solubility of the chemical, which is typical of salts of strong acids and weak bases, is shown by the graph to increase fast with rising temperature.

As a result, the salt becomes more soluble as the temperature rises and more of the weak base dissociates. This is because the strong acid entirely dissociates in solution while the weak base only partially does the same.

The curve also demonstrates that the compound's solubility remains mostly unchanged at increasing temperatures, which is a sign of a strong acid-weak base salt.

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The distribution of electrons is not the same in sodium-chlorine bonds and carbon-chlorine bonds (electronic configuration)

The electronic configuration of sodium chlorine

sodium atom is 2, 8, 1
chlorine atom is 2, 8, 7

Carbon chlorine

Carbon - 2,8,2
Chlorine - 2,8,7

Electronic Configuration refers to how the electrons are the distribution of electrons within an atom. The greatest number of electrons that can be found in an orbit can be calculated using the formula 2n2, where n is the orbit number. The formula also referred to as "Bohr Bury Schemes," aids in figuring out how electrons are arranged in the distribution of electrons.

In order to determine the distribution of electrons by the electrical configuration of cations, electrons are first removed from the outermost p orbital, then from the s orbital, and finally from the d orbitals (if any more electrons need to be removed)

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The phenomenon observed when water seeps into the sand in the riverbed groove can be related to certain steps of the water cycle on Earth's surface.

The water cycle, also known as the hydrological cycle, involves the continuous movement of water between the Earth's surface and the atmosphere. The steps of the water cycle being modeled as the water soaks into the sand are evaporation and infiltration.

Evaporation is the process in which liquid water transforms into water vapor, primarily from the Earth's surface. In the context of the sand riverbed, as water is added to the beginning of the groove and seeps into the sand, a portion of it is likely to evaporate. The heat from the surroundings aids in the conversion of liquid water into water vapor.

Infiltration, on the other hand, refers to the movement of water from the surface into the subsurface or soil. As the water is added to the riverbed groove, it percolates through the sand, gradually infiltrating into the pores and spaces between the sand particles.

This process mimics the natural infiltration of water into the ground during rainfall or when water seeps into the soil near rivers or lakes.

By observing the seepage of water into the sand in the riverbed groove, we can draw a parallel to the water cycle's evaporation and infiltration processes.

This modeling demonstrates how water on the Earth's surface can evaporate into the atmosphere and infiltrate into the ground, replenishing groundwater reserves or feeding into natural drainage systems.

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Therefore, the volume occupied by the amount of ethyl alcohol containing 48.0 moles of hydrogen atoms is approximately 61.41 mL.

To calculate the volume occupied by the given amount of ethyl alcohol, we need to use the density of ethyl alcohol and convert moles of hydrogen atoms to grams.

First, we need to find the molar mass of ethyl alcohol (C2H5OH).

The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol.

Adding these up gives a molar mass of 46.08 g/mol for ethyl alcohol.

Next, we can calculate the mass of 48.0 moles of hydrogen atoms using the molar mass of hydrogen (1.01 g/mol).

The mass is given by:

mass = moles × molar mass

mass = 48.0 mol × 1.01 g/mol

mass = 48.48 g.

Now, we can use the density of ethyl alcohol (0.789 g/mL) to find the volume.

Density is defined as mass divided by volume, so we can rearrange the equation to solve for volume:

volume = mass/density

volume = 48.48 g / 0.789 g/mL

volume = 61.41 mL.

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The correct option is (C). The approximate final volume of a solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40 M is 86 mL (option C).

To find the final volume of the solution, we can use the formula:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the values we know, we get:

(8.25 M) (25 mL) = (2.40 M) (V2)

Solving for V2, we get:

V2 = (8.25 M x 25 mL) / 2.40 M
V2 = 86.25 mL

Therefore, the approximate final volume of the solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40 M is 86 mL (option C).

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Answer: hewo, there! your answer is Below

CH4(g) + 2O2(g) CO2(g) + 2H2O(g) + 802 kJ/mol

Explanation:

Hope this helps!!!

Have a great day!!!

The reaction \(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

shows combustion reaction of methane in which energy 802 KJ/mol energy produces.

A combustion reaction occurs when a substance combines with oxygen gas and produces energy in the form of light and heat. One of the reactants in combustion reactions must be oxygen. Water vapor is produced when hydrogen gas is burned.

It can be seen that this reaction give carbon di-oxide and water hence, combustion reaction will show this reaction.

\(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

the correct answer will be option (c).

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Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:

As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:

Answer:

A

Explanation:

kinetic and mass are directly proportional

so if one increases the other does to

The relationship between the kinetic energy of an object and the mass of an object is Kinetic energy gets bigger at the same rate as the mass of an object.

The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body keeps the kinetic energy it acquired throughout its acceleration unless its speed changes.

Potential energy can be moved into motion by a variety of catalysts, including gravity and chemical reactions, to release kinetic energy. As a result, kinetic energy rises and potential energy falls. Mechanical energy is the sum of all kinetic and potential energy.

The capacity to perform work is arguably the most significant characteristic of kinetic energy. Force acting on an object while it is moving is referred to as work. Energy and work are interchangeable because of their tight relationship.

Thus, option A is correct.

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Answer:

56.0774g/mol

Explanation:

hope you like it ☺️

The molarity of the NaCl in the 250 ml slat solution is 2.8M.

The molarity of a solution is defined as the concentration of a solute per unit volume of the solution.

Given, the volume of the solution is 250 ml converted into l 0.25

The number of moles of NaCl is 0.70.

By the formula  of molarity

\(M = \dfrac{n}{V}\\\\\\M = \dfrac{0.70}{0.25} = 2.8 M\)

Thus, the molarity is 2.8 M.

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Answer:

A parasite.

Explanation:

A virus usually invades cells and replicates.

A bacteria usually just replicates and either is beneficial or can harm.

A fungus usually decomposes or can make you sick.

A parasite usually is parasitism - it invades the organisms and leeches off them for shelter and nutrients and can harm.

Answer:

A parasite.

Explanation:

i got it right

To achieve the desired pH of 3.87, one would need to add 4.7 moles of HCl to the 1-liter buffer solution.

To calculate the amount of HCl that must be added to the buffer, we need to determine the change in concentration of acetic acid required to achieve the desired pH.

Volume of the buffer solution = 1 liter

Initial concentration of acetic acid ([HA]) = 1.3 M

Initial concentration of sodium acetate ([A-]) = 0.75 M

Desired pH = 3.87

pKa of acetic acid = 4.75

Using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

3.87 = 4.75 + log(0.75/[HA])

Rearranging the equation:

log(0.75/[HA]) = 3.87 - 4.75

log(0.75/[HA]) = -0.88

Taking the antilog of both sides:

0.75/[HA] = 10^(-0.88)

[HA] = 0.75 / 10^(-0.88)

[HA] = 0.75 / 0.125

[HA] = 6 M

To find the change in concentration of acetic acid:

Change in [HA] = Initial [HA] - Final [HA]

Change in [HA] = 1.3 M - 6 M

Change in [HA] = -4.7 M

Therefore, to achieve the desired pH of 3.87, you would need to add 4.7 moles of HCl to the 1-liter buffer solution.

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The reaction is included in a redox reaction

Further explanation:

Given

Reaction

2 Ca + O₂ → 2 CaO

Required

a redox reaction

Solution

Redox reactions are reactions where there is a change in oxidation number

Oxidation is an increase/increase in oxidation number, while reduction is a decrease/decrease in oxidation number.

Reducing agents are substances that experience oxidation  and oxidizing agent are substances that experience reduction

in the above reaction is included in a redox reaction because there is a change in oxidation number

Ca⇒Ca²⁺+ 2e⁻(for balanced equation : 2Ca⇒2Ca²⁺+4e⁻)

Oxidation ( 0 to +2)

O₂+2e⁻⇒O²⁻(for balanced equation : O₂+4e⁻⇒2O²⁻)

Reduction (0 to -2)

yes it isssss abcdefghijk

Answer:

Answer is D dont forget to mark btainlist

Answer:

\(\boxed {\boxed {\sf D. \ H_2O_2}}\)

Explanation:

A covalent compound is a molecule made up of covalent bonds, where the atoms share pairs of valence electrons. These compounds consist of two or more nonmetals.

Essentially, if a compound contains a metal, it is an ionic or metallic compound, not a covalent compound.

A. NaCl

This is sodium chloride. It contains sodium (Na) and chlorine (Cl). Sodium is a metal, so this is ionic.

B. CaO

This is calcium oxide. It contains calcium (Ca) and oxygen (O). Calcium is a metal, so this is ionic.

C. MgS

This is magnesium sulfide. It contains magnesium (Mg) and sulfur (S). Magnesium is a metal, so this is ionic.

D. H₂O₂

This is hydrogen peroxide. It contains hydrogen (H) and oxygen (O). Both of these elements are non-metals, so this is a covalent compound.

The correct choice is D. H₂O₂

Based on the moles of z per mole of the compound (z₃j)₂q₃, there are 9 moles of z in 1.75 moles of (z₃j)₂q₃.

The number of moles of "z" in 1.75 moles of  (z₃j)₂q₃ is determined using the molecular formula and the ratio of "z" to the rest of the compound.

From the given formula  (z₃j)₂q₃, there are 6 (3 * 2) moles of z in 1 mole of the compound (z₃j)₂q₃.

Since we are given 1.75 moles of  (z₃j)₂q₃, the number of moles of z present will be:

Number of moles of z = 1.75 moles × 6 moles of z

Number of moles of z = 9 moles

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Answer:

B

Explanation:

because when you put sugar in water you actually have to stir it in the water or it will just seat at the bottom of the water it also the same for sand except whener you mix the sand or not it will not dissolve unlike the sugar.

The microscopic interface asymmetry of grown semiconductor heterostructures.

The dispersion of restricted electrons. beginning from a multiband envelope formulation we practice matrix perturbation theory to derive specific expressions. Interface asymmetry, which in the conduction band Hamiltonian appear as a warping and a spin-splitting term. The warping term consequences in an inequivalence of the dispersion.

The microscopic interface asymmetry of grown semiconductor heterostructures that gives upward thrust to heavy-light hole coupling even at 0 in-plane wave vector, modifies also the dispersion of restricted electrons. beginning from a multiband envelope method we practice matrix perturbation principle to derive explicit expressions as a result of this interface asymmetry, which inside the conduction band.

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The work needed to isentropically compress 2 kg of steam in a cylinder from 400 kPa and 400°C to 2 MPa is 404.2 kJ.

Work is the energy that is transmitted to or from an item by means of a force acting on it across a distance in physics thermodynamics. It has a scalar value and is measured in joules (J). When an item moves as a result of an applied force, the amount of work is equal to the force times the distance traveled in the direction of the applied force.

To calculate the work needed to isentropically compress 2kg of steam, we can use the first law of thermodynamics:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

For an isentropic process, there is no heat transfer (Q = 0), and the change in internal energy is given by:

ΔU = m × (h2 - h1)

where m is the mass of the steam and h1 and h2 are the specific enthalpies of the steam at the initial and final states, respectively.

To find the specific enthalpies, we can use steam tables or a thermodynamic calculator. For the initial state, at 400 kPa and 400°C, we find:

h1 = 3339.1 kJ/kg

For the final state, at 2 MPa, we find:

h2 = 3541.2 kJ/kg

Substituting these values into the equation for ΔU, we get:

ΔU = 2 kg × (3541.2 kJ/kg - 3339.1 kJ/kg) = 404.2 kJ

Since the process is isentropic, the work done is given by:

W = ΔU = 404.2 kJ

Therefore, the work needed to isentropically compress 2 kg of steam in a cylinder from 400 kPa and 400°C to 2 MPa is 404.2 kJ.

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Your question is incomplete. The complete question is:

What is the work needed to isentropically compress 2kg of steam in a cylinder at 400kPa and 400C to 2 MPa?

Answer:

200.00 mol

Explanation:

Nitric acid: Nitrogen dioxide is 2:3

and nitrogen dioxide is already 300.00 mol so using the ratio, nitric acid is 200.00 mol

Answer:

200.00

Explanation:

Did it on edge GL

Answer:

Water in different phases moves through the atmosphere (transportation). Liquid water flows across land (runoff), into the ground (infiltration and percolation), and through the ground (groundwater). Groundwater moves into plants (plant uptake) and evaporates from plants into the atmosphere (transpiration).

Saccharin, an artificial sweetener that is 3000 times sweeter than sucrose, is composed of a) C₁₄H₁₀O₆N₂S₂.

45.90% carbon, 2.73% hydrogen, 26.23% oxygen, 7.65% nitrogen, and 17.49% sulfur. is the molecular formula of saccharin.

To determine the molecular formula of saccharin, we first need to calculate the empirical formula using the given percentages of each element.

Assuming we have 100 grams of saccharin, we have:

Carbon: 45.90 g / 12.01 g/mol = 3.82 mol

Hydrogen: 2.73 g / 1.01 g/mol = 2.70 mol

Oxygen: 26.23 g / 16.00 g/mol = 1.64 mol

Nitrogen: 7.65 g / 14.01 g/mol = 0.55 mol

Sulfur: 17.49 g / 32.07 g/mol = 0.55 mol

We can divide each value by the smallest one, which is 0.55 mol, to get the following ratios:

Carbon: 3.82 / 0.55 = 6.95

Hydrogen: 2.70 / 0.55 = 4.91

Oxygen: 1.64 / 0.55 = 2.98

Nitrogen: 0.55 / 0.55 = 1

Sulfur: 0.55 / 0.55 = 1

The resulting ratios are close to whole numbers, so we can assume the empirical formula to be C₇H₅NO₃S. To find the molecular formula, we need to determine the actual molecular mass of saccharin.

The empirical formula mass of C₇H₅NO₃S is approximately 183 g/mol. The molecular mass of saccharin is known to be around 452 g/mol, so we can calculate the ratio of the molecular mass to the empirical formula mass:

452 g/mol / 183 g/mol = 2.47

This means that the molecular formula is 2.47 times the empirical formula, or:

C₇H₅NO₃S * 2.47 = C₁₇H₁₃N₂O₅S

Therefore, the molecular formula of saccharin is (a) C₁₄H₁₀O₆N₂S₂. The other options (b) CSH,ONS, (c) C&H₉O₂NS, and (d) C;H₅O₃NS are not correct.

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Answer:

it disappeared loll jk

it obviously dried

well you may Mark me as brainliest

The rate, v, of the reaction was measured when different concentrations of isocitrate ion were present at 25°C. The following results were obtained.

It seems that you haven't provided the actual results. In this case, the rate of the reaction is measured as a function of the concentration of isocitrate ion. By varying the concentration of isocitrate ion and observing the corresponding rates, you can determine the relationship between concentration and rate of the reaction. This information is useful for understanding the reaction mechanism and for predicting how changes in concentration may affect the rate.

The rate of a chemical reaction is the speed at which reactants are converted into products. It can be determined by measuring the change in concentration of a reactant or product over time. In this particular case, the rate of the reaction was measured at 25°C using various concentrations of isocitrate ion. By varying the concentration of isocitrate ion and observing the corresponding rates, you can determine the relationship between concentration and rate. This information is important for understanding the reaction mechanism and for predicting how changes in concentration may affect the rate. Experimental data like these can be used to determine the rate equation, which describes the relationship between the concentrations of reactants and the rate of the reaction.

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Answer:

14.7 g of chromium

Explanation: