The molecular scene depicts the relative concentrations of H₃O⁺ (purple) and OH⁻ (green) in an aqueous solution at 25°C. (Counter ions and solvent molecules are omitted for clarity.) (a) Calculate the pH.

Answer:

look up hope that helps you

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 30 × 2.2

We have the final answer as

Hope this helps you

Answer:

The density of the  substance is 1.0611 \(\frac{g}{cm^{3} }\)

Explanation:

The density of a substance is a characteristic property that matter, whether solids, liquids or gases, has to be compressed in a given space, that is, it allows us to measure the amount of mass in a certain volume of a substance.

Density is expressed as follows:

\(density=\frac{mass}{volume}\)

In this case:

Replacing:

\(density=\frac{21.1164 grams}{19.9 cm^{3} }\)

density= 1.0611 \(\frac{g}{cm^{3} }\)

The density of the  substance is 1.0611 \(\frac{g}{cm^{3} }\)

The technique used to separate oil from water is known as decantation.

Oil has less density compared to that of water.

By the process of decantation we can separate mixtures by removing a liquid layer that is free of a precipitate.

The final temperature of the sample, in degrees Celsius is 36.6 °C

From the question, we are to determine the final temperature of the sample

From the formula for heat capacity, we have that

Q = mcΔT

Where Q is the heat energy

m is the mass

c is the specific heat capacity of the subtance

ΔT is the change in temperature (\(\Delta T= T_{f} -T_{i}\))

From the given information

m = 687.6 g

Q = 8284.4 J

\(T_{i}\) = 23.1 °C

Putting the parameters into the equation, we get

\(8284.4 = 687.6 \times 0.89 \times (T_{f} -23.1)\)

NOTE: Specific heat capacity of aluminum = 0.89 J/ g °C

Then,

\(8284.4 = 611.964 \times (T_{f} -23.1)\)

\((T_{f} -23.1)= \frac{8284.4}{611.964}\)

\((T_{f} -23.1)= 13.5\)

\(T_{f} = 13.5 + 23.1\)

\(T_{f} = 36.6 \ ^\circ C\)

Hence, the final temperature of the sample, in degrees Celsius is 36.6 °C

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Answer: You have the values of P1, V1, T1, T2, and V2.  Plug in the numbers and get P2.

Explanation:

Work with the relation

P1V1 / T1 = P2V2 / T2 ⇒

P2 = (P1V1 / T1) (T2 / V2)

Answer:

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus.

Explanation:

Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

Answer:

It is carried to the lungs to be exhaled

Explanation:

Answer:

I dont know

Explanation:

I dont know

Answer: i think b.

Explanation:

The attraction forces between mercury atoms in liquid mercury are stronger than the intermolecular forces between water molecules because it has a higher surface tension than does water.

Surface tension is the propoerty of the surface of liquids by which they will shrink into the minimum possible surface area.

Surface tension of the liquid mercury is greater than the surface tension of water means cohesive attraction force between the molecules of mercury is greater than water molecules.

Hence option (A) is correct.

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Answer:

It has a higher surface tension than does water.

Explanation:

got it right on edge on 12-15-22

EDTA (ethylenediaminetetraacetic acid) is commonly used to determine the hardness of water due to its ability to form complexes with metal ions, particularly calcium and magnesium ions.

Water hardness refers to the concentration of calcium and magnesium ions present in water. These ions can cause scaling, reduce the effectiveness of soaps, and have other negative effects. EDTA acts as a chelating agent, meaning it can bind to metal ions and form stable complexes.

In the process of determining water hardness, a known amount of EDTA solution is added to a water sample. The EDTA molecules form complexes with the calcium and magnesium ions present in the water.

The endpoint of the titration is reached when all the metal ions are complexed by the EDTA, resulting in a color change or an indicator reaching a specific endpoint.

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Answer: LOL. I think thats how-

False

complete combustion produces carbon dioxide + water

Answer:

Acetone is captured and cooled.

Explanation:

The boiling point of acetone is lower than that of water, so it will vaporise before water. Then acetone will be captured and cooled to separate it from its mixture with water.

The statement which is correct about distilling a mixture of acetone and water is as follows:

Thus, the correct option is C.

Distillation may be defined as a procedure that generally involves the conversion of a liquid into a vapor that is eventually condensed back to liquid form. With the help of this process, the separation of components or substances from a liquid mixture by using selective boiling and condensation occurs.

Acetone has the lowest boiling point as compared to water. So, it boils faster than that water and vaporizes before water. After the termination of this process, the acetone will be predominantly captured and cooled to separate it from its mixture with water.

Therefore, the correct option for this question is C.

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During electrolysis, a current is passed through the molten MgCl2, and when this happens, the Mg2+ ions move to the negative electrode where they PICK UP OR GAIN ELECTRONS. This is reduction. The Cl- ions move to the positive electrode where they LOSE ELECTRONS. This is oxidation.

The mole fraction of NH3 in the solution prepared by dissolving 15.0 g of nh3 in 250.0 g of water is 0.0597.

To find the mole fraction of NH3 in the solution, we need to first calculate the moles of NH3 and water in the solution.

The moles of NH3 can be found by dividing the mass of NH3 by its molar mass:
moles of NH3 = 15.0 g / 17.03 g/mol = 0.881 mol

The moles of water can be found by dividing the mass of water by its molar mass:
moles of water = 250.0 g / 18.02 g/mol = 13.874 mol

The total moles of solute and solvent in the solution are:
total moles = moles of NH3 + moles of water = 0.881 mol + 13.874 mol = 14.755 mol

The mole fraction of NH3 can now be calculated as the ratio of moles of NH3 to total moles:
mole fraction of NH3 = moles of NH3 / total moles = 0.881 mol / 14.755 mol = 0.0597

Therefore, the mole fraction of NH3 in the solution is 0.0597.

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The order of formation of coal types from lower burial depths and temperatures to higher is peat, lignite, sub-bituminous, bituminous, and anthracite.

Coal is a fossil fuel formed from the remains of plants that lived and died millions of years ago. The type of coal formed depends on the depth of burial and the amount of heat and pressure applied to the plant material over time. The following is the order of formation of coal types from lower burial depths and temperatures to higher:

1. Peat: This is the earliest stage of coal formation and is formed from the accumulation of plant material in wetlands. Peat is partially decomposed plant matter that has not been subjected to high temperatures or pressure.

2. Lignite: This is the next stage of coal formation and is formed from the compaction and heating of peat. Lignite is a soft, brownish-black coal with a high moisture content and a low energy content.

3. Sub-bituminous: This is the next stage of coal formation and is formed from the further compaction and heating of lignite. Sub-bituminous coal is a dull black coal with a lower moisture content and a higher energy content than lignite.

4. Bituminous: This is the most common type of coal and is formed from the further compaction and heating of sub-bituminous coal. Bituminous coal is a dense, black coal with a high energy content and a low moisture content.

5. Anthracite: This is the highest grade of coal and is formed from the further compaction and heating of bituminous coal.

The order of formation of coal types from lower burial depths and temperatures to higher is peat, lignite, sub-bituminous, bituminous, and anthracite.

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The solution for this question is A. Destructive; constructive

The weathering of a tall mountain down into a low-lying hill involves the breakdown and erosion of the mountain over time, which is a destructive process. This process typically occurs due to various factors such as wind, water, and ice erosion, which gradually wear away the mountain's structure.

On the other hand, the buildup of sand dunes through the deposition of sediment is a constructive process. This occurs when wind or water carries and deposits sand or sediment in a specific location, gradually forming dunes over time.

Therefore, the weathering of a tall mountain represents a landform being changed through a destructive process, while the creation of sand dunes through the deposition of sediment represents a landform being created through a constructive process.

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Answer:

no

Explanation:

Answer:

Not yet!

Note:

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No, the metal has not disappeared. Chemical reactions only rearrange atoms and do not destroy or create them.

In the case of reclaiming metals from solutions, a chemical reaction is used to separate the metal ions from other elements in the solution, allowing the metal to be recovered in a pure form. This is typically achieved by adding a reactant that will cause the metal ions to precipitate out of the solution as a solid, which can then be separated and processed further to extract the metal.

So, the metal is still present in the reaction mixture, but it is now in a more concentrated and recoverable form. This process is important for reducing the amount of toxic waste generated from industrial processes and can also help to conserve natural resources by recycling valuable metals.

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Answer:

The ammonia production design process has two design requirements;

Explanation:

In the following process, ammonia is provided by natural gas:

\(H_2 + RSH \to RH + H_2S\\\\H_2S + ZnO \to ZnS + H_2O \ \ (Waste \ water)\\\\CH_4 + H_2O \to CO + 3H_2\\\\CO + H_2O \to CO_2 + H_2\\\\\)

Ammonia would then be generated in a process called also as Haber-Bosch process by responding to produced hydrogen to nitrogen throughout the presence of catalysts.

\(3H_2 + N_2 \to 2NH_3\)

Answer:

Sustainable renewable energy production of hydrogen.

Sustainable use of another thermal ammonia-water process to retrieve ammonia throughout the wastewater.

Explanation:

Grinding the calcium hydroxide to a finer powder would speed up the collisions.

The reaction between calcium hydroxide and carbon dioxide to produce calcium carbonate is a slow process that requires the collision of calcium hydroxide and carbon dioxide molecules. In order to speed up the reaction rate, one approach is to increase the surface area of calcium hydroxide by using it in a powdered form, which increases the number of collisions with carbon dioxide molecules. Another way is to increase the concentration of carbon dioxide by pumping it into the reaction chamber at a higher pressure, which increases the number of collisions with calcium hydroxide molecules. Additionally, raising the temperature of the reaction can increase the kinetic energy of the molecules and promote collisions, leading to a faster reaction rate. Using a catalyst, such as a small amount of sodium chloride, can also enhance the reaction by lowering the activation energy needed for the reaction to occur. These approaches can help speed up the production of calcium carbonate from the reaction between calcium hydroxide and carbon dioxide.

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Answer:

it would be C! 0.0520 Km

A large net force of 280N  is required to accelerate a 2000 kg suv from rest with an acceleration of 0.14m/s2 .

According to Newton’s 2nd law of motion,  force is  equal to the change in momentum per change in time.Acceleration of an object depends on the mass of the object and the amount of force applied.

            Force=mass* acceleration

Here, mass is equal to 2000 kg and acceleration is equals to 0.14m/s/s.putting these values,

      F= ma

     F= 2000kg * 0.14 m/s2

        = 280 kg m/s2

        =280N

So, 280N of force is required.

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The most common agent resulting in nephrotoxicity and subsequent acute tubular necrosis (ATN) in hospitalized patients is an infection of the kidney.

These two are the most deadly diseases caused by defects in the human kidney.

The infection releases harmful poison which affects the cell of the kidney and damages the whole tissue too.

Therefore, the most common agent resulting in nephrotoxicity and subsequent acute tubular necrosis (ATN) in hospitalized patients is an infection of the kidney.

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This means that they are true for all possible combinations of truth values for p, q, and r

a) (p∧q)→p

p | q | p∧q | p→p

-- | -- | -- | --

T | T | T | T

T | F | F | T

F | T | F | T

F | F | F | T

b) p→(p∨q)

p | q | p∨q | p→(p∨q)

-- | -- | -- | --

T | T | T | T

T | F | T | T

F | T | T | T

F | F | F | T

c) ¬p→(p→q)

p | ¬p | p→q | ¬p→(p→q)

-- | -- | -- | --

T | F | T | F

F | T | F | T

d) (p∧q)→(p→q)

p | q | p∧q | p→q | (p∧q)→(p→q)

-- | -- | -- | -- | --

T | T | T | T | T

T | F | F | T | T

F | T | F | T | T

F | F | F | T | T

10. [p∧(p→q)]→q

p | q | p→q | p∧(p→q) | [p∧(p→q)]→q

-- | -- | -- | -- | --

T | T | T | T | T

T | F | F | F | F

F | T | T | F | F

F | F | T | F | F

22. (p→q)∧(p→r) and p→(q∧r)

p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | F | T | F

T | F | F | T | F | T | F

F | T | T | T | T | T | T

F | T | F | T | T | T | F

F | F | T | T | F | T | F

F | F | F | T | F | T | F

23. (p→r)∧(q→r) and (p∨q)→r

p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | T | T | T

T | F | F | T | T | T | T

F | T | T | T | T | T | T

F | T | F | T | T | T | T

F | F | T | T | T | T | T

F | F | F | T | T | T | F

24. (p→q)∨(p→r) and p→(q∨r)

p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | T | T | T

T | F | F | T | T | T | T

F | T | T | T | T | T | T

F | T | F | T | T | T | T

F | F | T | T | T | T | T

F | F | F | T | T | T | F

As you can see, all of the conditional statements are tautologies.

This means that they are true for all possible combinations of truth values for p, q, and r

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a) (p∧q)→p  is shown as a tautology by using truth tables

b) p→(p∨q)   is shown as a tautology by using truth tables

c) ¬p→(p→q)   is shown as a tautology by using truth tables

d) (p∧q)→(p→q)   is shown as a tautology by using truth tables

This can be explained as meaning that  they are true for all possible combinations of truth values for p, q, and r

a)

for (p∧q)→p

p | q | p∧q | p→p

-- | -- | -- | --

T | T | T | T

T | F | F | T

F | T | F | T

F | F | F | T

b)

p→(p∨q)

p | q | p∨q | p→(p∨q)

-- | -- | -- | --

T | T | T | T

T | F | T | T

F | T | T | T

F | F | F | T

c) ¬p→(p→q)

p | ¬p | p→q | ¬p→(p→q)

-- | -- | -- | --

T | F | T | F

F | T | F | T

d) (p∧q)→(p→q)

p | q | p∧q | p→q | (p∧q)→(p→q)

-- | -- | -- | -- | --

T | T | T | T | T

T | F | F | T | T

F | T | F | T | T

F | F | F | T | T

10. [p∧(p→q)]→q

p | q | p→q | p∧(p→q) | [p∧(p→q)]→q

-- | -- | -- | -- | --

T | T | T | T | T

T | F | F | F | F

F | T | T | F | F

F | F | T | F | F

22. (p→q)∧(p→r) and p→(q∧r)

p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | F | T | F

T | F | F | T | F | T | F

F | T | T | T | T | T | T

F | T | F | T | T | T | F

F | F | T | T | F | T | F

F | F | F | T | F | T | F

23.

for   (p→r)∧(q→r) and (p∨q)→r

p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | T | T | T

T | F | F | T | T | T | T

F | T | T | T | T | T | T

F | T | F | T | T | T | T

F | F | T | T | T | T | T

F | F | F | T | T | T | F

24.

(p→q)∨(p→r) and p→(q∨r)

p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)

-- | -- | -- | -- | -- | -- | --

T | T | T | T | T | T | T

T | T | F | T | T | T | T

T | F | T | T | T | T | T

T | F | F | T | T | T | T

F | T | T | T | T | T | T

F | T | F | T | T | T | T

F | F | T | T | T | T | T

F | F | F | T | T | T | F

In conclusion, we see that all of the conditional statements are tautologiesand  that they are true for all possible combinations of truth values for p, q, and r

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Adding CH4 to the exothermic reversible reaction at equilibrium will cause the reaction to shift to the left, favoring the formation of C(s) and 2H2(g).

To understand how adding CH4 will affect the equilibrium, we can use Le Chatelier's Principle, which states that if a change is made to a system at equilibrium, the system will adjust itself to counteract that change and restore the equilibrium.

The reaction is represented as:

C(s) + 2H2(g) ⇌ CH4(g)

In this case, the change is an increase in the concentration of CH4. According to Le Chatelier's Principle, the equilibrium will shift in the direction that decreases the concentration of CH4. In this reaction, that means the equilibrium will shift to the left, favoring the formation of the reactants C(s) and 2H2(g). This will continue until a new equilibrium is established.

So, the exothermic reversible reaction that is at equilibrium will move to the left when CH4 is added, favoring the synthesis of C(s) and 2H2(g).

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