The mass of 2.75 mol K₂S is 303.24 grams.
Applying the mole concept:Number of moles(n) = given mass(m) / molar mass(M)
n = m / M
Now applying the formula for the number of moles-i.e. number of moles of K₂S = mass of K₂S / Molas mass of K₂S
As per question, Molar mass of K₂S, M = 110.27 g/mol
and, number of moles of K₂S, n = 2.75 moles
∴ n = m / 110.272.75 = m / 110.27
m = 2.75 x 110.27
= 303.24
m = 303.24 grams.
Hence, the mass of 2.75 mol K₂S is 303.24 grams.
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9. A gas sample occupies 3.25 liters at 24.5 °C and 1825 mm Hg. Determine
the temperature at which the gas will occupy 4250 mL at 1.50 atm.
Answer: 243K
Explanation:
Does NaCI have a high melting point
Answer:
Yes, at 801 °C
Explanation:
Which of the following is a result of the specific heat differences between land and ocean?
A. Ocean tides are created.
B. Volcanoes are created.
C. Saltwater is created.
D. Breezes are created.
Calculate the new volume in liters of a 0.500 L water bottle at 25.0 degrees when the plastic bottle is submerged in ice water at 1.00 degree Celsius.
Answer:
0.02L
Explanation:
Using the formula V1/T1 = V2/T2
Given
V1 = 0.5L
T1 = 25 degrees
T2 = 1 degree
V2 =?
Substitute
0.5/25 = V2/1
Cross multiply
25V2 = 0.5
V2 = 0.5/25
V2 = 0.02L
Hence the new volume will be 0.02L
*15-20 POINTS IF YOU ANSWER CORRECTLY & ADDED BRAINIEST*
An electron configuration of 2-7-6 represents the atom of...
A.) phosphorus and is in the ground state
B.) phosphorus and is in the excited state
C.) potassium and is in the ground state
D.) potassium and is in the excited state
Answer:
2 8 5
Is phosphorus normal ground state configuration this configuration 2 7 5 is not possible for phosphorus or potassium
Explanation:
Answer:
D) Potassium and is in the excited state.
Explanation:
a decrease in free hydrogen ion concentration (h ) in the serum results in a/an in serum ph, and a/an in serum alkalinity:
A decrease in free hydrogen ion concentration (H⁺) in the serum results in an increase in serum pH, and an increase in serum alkalinity.
A hydrogen ion is an ion that is created when a hydrogen (H) atom either loses or gains an electron. The concentration of this ion would affect the pH of the aqueous solution that it is in; as the concentration increase, the pH would decrease.
While a base provides hydroxide ions (OH⁻) that will combine with hydrogen ions to reduce their concentration (which results in a raising pH), an acid will simply increase the H⁺ concentration, usually by having one of its hydrogen atoms dissociate.
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The more variation in a species, the less likely the chance that species has of surviving. true or false
Answer:
The more variation in a species, the less likely the chance that species has of surviving. false
Explanation:
As species have heritable variation the species produce more offsprings that can survive and offsprings within a favorable variation are more likely to survive and reproduce. Hence favorable variation makes the species diverse and more in population. Thus greater are the chances of survival, a decrease in diversity will lead to a decline in variability, and fewer chances of survival.04. (a) Explain briefly what you understand by Corrosion penetration rate and how it is measured The rate of oxidation and how it is measured (b) Explain the following deterioration mechanism of polymetric materials; 17 marles (i) Thermal degradation 17 marks) (1) Weathering (c) In respect to corrosion, explain the consequences of; (4 marks (i) Riveting a steel plate with copper rivets (ii) Connecting buried steel pipework to zinc plates (4 marks (d) One-half of an electrochemical cell consists of a pure nickel electrode in a solution of Nid'ions, other half is a cadmium electrode immersed in a Cda solution. If the cell is a standard one, (6 marks (1) Write the spontaneous overall reaction (6 mark (ii) Calculate the voltage that is generated
(a) Corrosion Penetration Rate (CPR) is a measurement of the thickness of a material's corrosion layer in terms of linear millimeters per year. Corrosion Penetration Rate is an important parameter that is widely used in the corrosion field to estimate the corrosion rate of a metal.
The penetration rate is determined by exposing a metal sample to the corrosive environment and measuring the quantity of metal that has been lost due to corrosion over a certain period of time. The formula used to calculate CPR is: CPR = Weight loss of the sample (mg) x 31556926.0 / A x D x t Where, A= Surface area of the sample (m²), D= Density of the sample (g/cm³), t= Exposure time in seconds
(b)Deterioration mechanism of polymetric materials:
(i) Thermal degradation: It is the process in which chemical decomposition occurs when a polymer is exposed to elevated temperatures, which can result in the loss of essential properties of the polymer.
(ii) Weathering: The process by which a polymer's structure and properties are altered as a result of exposure to the natural elements is referred to as weathering.
(c) Consequences of corrosion:
(i) Riveting a steel plate with copper rivets: When riveting a steel plate with copper rivets, galvanic corrosion is caused as a result of the contact between copper and steel. The steel will corrode more quickly than it would if it were in contact with a material that is less reactive than copper.
(ii) Connecting buried steel pipework to zinc plates: Connecting buried steel pipework to zinc plates can cause galvanic corrosion. Because zinc is more reactive than steel, the zinc plate corrodes and prevents the steel pipe from corroding. As a result, the zinc plate will corrode away, leaving the steel pipe vulnerable to corrosion.
(d) One-half of an electrochemical cell consists of a pure nickel electrode in a solution of Nid'ions, other half is a cadmium electrode immersed in a Cda solution. If the cell is a standard one:
(i) Spontaneous overall reaction: Ni(s) + Cd²⁺ (aq) → Cd(s) + Ni²⁺ (aq)
(ii) The voltage generated by the cell is: E°cell = E°cathode - E°anode
E°cell = E°Cd - E°Ni
E°cell = (-0.40) - (-0.25)
E°cell = -0.15V
Therefore, the voltage generated by the cell is -0.15V.
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A gold cube is 150.00 mm long, 10.00 cm wide, and 0.95 m thick. If gold has a density of 19.3g/cm3. Calculate the mass of the gold cube.
Help?
Answer:
V = l * w * h
V = 150.00 mm x 1cm/10 mm x 10.00 cm x 0.95 m x 100 cm/1 m = 1.4 x 104 cm3 D = M/V
M = D * V = 19.3 g/cm^3 * 1.4 * 104 cm^3 = 2.7 x 10^5 g = 270000 grams
You have a stock solution of HNO3 with a concentration of 4.5 x 10^-4 M. However, you need 275 ml of a 2.50 x 10^-5 M solution. How much of the stock solution will you need?
Answer:
15.28 mL
Explanation:
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 4.5x10¯⁴ M
Volume of diluted solution (V₂) = 275 mL
Molarity of diluted solution (M₂) = 2.5×10¯⁵ M
Volume of stock solution (V₁) needed =.?
The volume of the stock solution needed can be obtained by using the dilution formula as illustrated below:
M₁V₁ = M₂V₂
4.5x10¯⁴ × V₁ = 2.5×10¯⁵ × 275
4.5x10¯⁴ × V₁ = 0.006875
Divide both side by 4.5x10¯⁴
V₁ = 0.006875 / 4.5x10¯⁴
V₁ = 15.28 mL
Therefore, the volume of the stock solution needed is 15.28 mL
If the frequency is doubled and the speed is kept constant,
which of the following is true about wavelength?
a. wavelength will not change
b. wavelength will also double
c. wavelength will decrease to half its value
d. wavelength will be 3 times larger.
(science)
Answer:
done
Explanation:
Ca(OH)2 + Na2CO3 --> CaCO3 + NaOH
Answer:
caco3+Na2OH
Explanation:
to balance
How many moles of sodium atoms are in 6. 80 x 1024 molecules of Na3PO4
The number of moles of sodium atoms in a given quantity of sodium phosphate (Na₃PO₄), consider the stoichiometry of the compound. In 6.80 x 10²⁴ molecules of Na₃PO₄, there are 2.04 x 10²⁵ sodium atoms.
The chemical formula of sodium phosphate is Na₃PO₄, indicating that each formula unit of Na₃PO₄ contains three sodium (Na) atoms. Therefore, we can calculate the number of moles of sodium atoms by multiplying the number of molecules of Na₃PO₄ by the ratio of sodium atoms to molecules in the compound.
Given that there are 6.80 x 10²⁴ molecules of Na₃PO₄, we can set up the following calculation:
Number of moles of sodium atoms = (6.80 x 10²⁴ molecules Na₃PO₄) x (3 moles Na / 1 mole Na₃PO₄)
Using the stoichiometry, we find that there are 3 moles of sodium atoms for every 1 mole of Na₃PO₄. Therefore, the number of moles of sodium atoms is 2.04 x 10²⁵ moles.
Note that we multiply the number of molecules of Na₃PO₄ by 3 moles Na / 1 mole Na₃PO₄ to account for the three sodium atoms present in each formula unit of Na₃PO₄.
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What mass of iron should be produced if 11. 0g of aluminum react with 30. 0g of iron (III) oxide?
The mass of iron should be produced if 11. 0g of aluminum reacts with 30. 0g of iron (III) oxide is 10.50 g.
To determine the mass of iron produced, we need to use stoichiometry and the balanced chemical equation for the reaction between aluminum and iron(III) oxide.
The balanced chemical equation is:
2 Al + \(Fe_{2} O_{3}\) → + 2 Fe
From the equation, we can see that 2 moles of aluminum react with 1 mole of iron(III) oxide to produce 1 mole of iron.
First, we need to determine the limiting reactant by comparing the number of moles of aluminum and iron(III) oxide.
Moles of aluminum = mass of aluminum / molar mass of aluminum
= 11.0 g / 26.98 g/mol (molar mass of aluminum)
= 0.407 mol
Moles of iron(III) oxide = mass of iron(III) oxide / molar mass of iron(III) oxide
= 30.0 g / 159.69 g/mol (molar mass of iron(III) oxide)
= 0.188 mol
Since the stoichiometric ratio of aluminum to iron(III) oxide is 2:1, we can see that 0.188 mol of iron(III) oxide requires 0.376 mol of aluminum. However, we have only 0.407 mol of aluminum, which is in excess.
Therefore, the limiting reactant is iron(III) oxide. The amount of iron produced is determined by the moles of iron(III) oxide used. Moles of iron = 0.188 mol (same as moles of iron(III) oxide)
Now we can calculate the mass of iron produced using its molar mass (55.85 g/mol):
Mass of iron = Moles of iron × Molar mass of iron
= 0.188 mol × 55.85 g/mol
= 10.50 g
Therefore, the mass of iron produced is approximately 10.50 grams.
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The rate of decomposition of radioactive radium is proportional to the amount present at any time. The half-life of radioactive radium is 1599 years. What percent of a present amount will remain after 560 years
A number of radium isotopes are artificially created or are byproducts of artificial isotope decay. Many common products, including many that are used in construction, as well as soil, minerals, food, and groundwater all contain radium.
Thus, Drinking water in areas where wells are used can be a significant source of radium intake.
Commercial luminous paints for watch and instrument dials as well as for other luminescent objects have been made with radium. Additionally, internal radiation therapy has made use of it.
The comprehensive research of 224Ra, 226Ra, and 228Ra in experimental humans and animals serve as the main sources of knowledge regarding the health consequences and dosimetry of radium isotopes.
Thus, A number of radium isotopes are artificially created or are byproducts of artificial isotope decay. Many common products, including many that are used in construction, as well as soil, minerals, food, and groundwater all contain radium.
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Four students presented different analogies to describe the formation of an ionic bond.
Student A: A tug of war between seven middle school students and a high school student
Student B: A small dog and a big dog tugging at a bone with equal strength
Student C: Two neighbors carpooling to work
Student D: A group of high school students reading from the same book in the library
Which student presented a correct analogy?
A
B
C
D
Answer:
the correct answer is A
Explanation:
I took the test!
Answer:
A probably because its ionic
what's the correct answer? brainliest
Answer:
Explanation:accurate but not precise
1. Which statement is true for the following reaction at equilibrium at 25°C?
N2(g) + O2 (g) ⇌ 2NO(g); K = 4.1 × 10-31
A. Concentration of N2 and O2 are low.
B. The rate of the reaction is very slow.
C. The reaction goes in the reverse direction.
D. Concentration of NO is low.
2. How would you change the volume of the reaction container that holds the following reaction in order to increase the yield of C?
2 A(g) + B(s) ↔ 3 C(g)
a. Increase the volume of the container.
b. Decrease the volume of the container.
c. Do not change the volume of the container.
d. Cannot be predicted.
1. The correct answer is C. The reaction goes in the reverse direction for the given reaction at equilibrium at 25°C.
The equilibrium constant (K) for this reaction is very small, indicating that the reaction heavily favors the reactants (N2 and O2) over the products (NO). Therefore, at equilibrium, the reaction will be predominantly in the reverse direction.
2. To increase the yield of C, the volume of the container should be decreased.
According to Le Chatelier's principle, when the volume of a reaction container is decreased, the system will try to compensate by shifting the equilibrium in the direction that produces fewer gas molecules. In this case, decreasing the volume will shift the equilibrium towards the product side, which contains fewer gas molecules (3 moles of gas on the product side vs. 2 moles on the reactant side). Therefore, decreasing the volume will increase the yield of C.
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A sample of helium has a volume of 3.20x10^2 mL at STP. What will be its new volume (inL) if the temperature is increased to 425.0 K and its pressure is increased to 3.50 atm?
Let's see that the STP represents the conditions for the temperature of 0°C (273 K) and for the pressure of 1 atm.
We have this initial data and a volume of 3.20 x 10 ^(2) mL. To solve this problem, we need to use the ideal gas formula:
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2},\)where T is temperature, P is pressure, and V volume. Subindex 1 is the initial data and subindex 2 is the final data.
We want to find the final volume, so clearing for V2 in the formula, we're going to obtain:
\(V_2=\frac{P_1V_1T_2}{T_1P_2}\text{.}\)And the final step is replacing the data that we have, where the final data is 425.0 K and 3.50 atm (remember that the volume must be in liters, 1 liter is 1000 mL, so 3.20 x 10^2 mL is 0.32 L):
\(\begin{gathered} V_2=\frac{1\text{ atm }\cdot\text{ 0}.32\text{ L }\cdot425.0K}{273\text{ K }\cdot\text{ 3.50 atm}}, \\ V_2=0.14\text{ L.} \end{gathered}\)The answer is that the new volume of the sample of helium would be 0.14 L.
The ____number can vary among atoms of the same element.
Answer:
Mass number
Explanation:
All atoms of the same element have the same number of protons, but some may have different numbers of neutrons, which would cause a different mass number
Answer:
The answer is mass number
Calculate the probability of observing an average american ladybug length between 0. 95 cm and 1. 05 cm for a random sample of 20 ladybugs. Give your answer accurate to four decimal places. If you found assumptions to be violated in the previous question, answer this question as if the assumptions had not been violated.
The probability of observing an average American ladybug length between 0.95 cm and 1.05 cm for a random sample of 20 ladybugs is given below:
The given information is,
μ = 1cm,
σ = 0.2/√20 cm
= 0.0447 cm.
To calculate the probability of observing an average American ladybug length between 0.95 cm and 1.05 cm, we need to standardize the interval [0.95, 1.05] as follows:
P(0.95 < x < 1.05)
= P[(0.95 - 1) / 0.0447 < (x - μ) / 0.0447 < (1.05 - 1) / 0.0447]
= P(-2.24 < Z < 2.24)
The probability can be determined using a standard normal distribution table or calculator.
Using a calculator, the probability can be found as:
P(-2.24 < Z < 2.24) = 0.9833 - 0.0167
= 0.9666
Therefore, the probability of observing an average American ladybug length between 0.95 cm and 1.05 cm for a random sample of 20 ladybugs is probability (accurate to four decimal places).
Note: It is important to note that no assumptions were mentioned in the question that needs to be violated.
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The water at the upper part boils but the ice cubes
at the lower part do not melt. Give a conclusion.
guys please help mee
Answer:
HOPE IT HELPS....
Explanation:
Water has a very large heat capacity, so it takes a lot of energy to change the temperature. Warmer water will be less dense and move upward to the top of the test tube to boil while the colder water can stay at the bottom. Water does not conduct heat through it very much and ice conducts the heat through much less.
Describe three ways to prepare for a tsunami.
Please I only have 30minutes
Answer:
High ground dont do any thing but get to high ground and get as far away
Explanation
Answer:
There are several ways to prepare for a tsunami. The most important safety measure is to recognize the warning signs of a tsunami, which include an earthquake and the rapid receding of water from shore. In addition to knowing the warning signs of a tsunami, it is important to plan an evacuation route and put together a disaster supply pack that includes food, water, first aid supplies, clothing, bedding, etc. Lastly, if you hear an official tsunami warning or experience any of the warning signs, evacuate as quickly as possible and move to higher ground.
Explanation:
a solution with an [OH-] concentration of 1.20 x 10-7M has a pOH and pH of?
Taking into account the definition of pH and pOH, the solution has a pOH of 6.92 and a pH of 7.08.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
pOH and pH in this caseA solution has an [OH⁻] concentration of 1.20×10⁻⁷ M. Replacing in the definition of pOH:
pOH= - log (1.20×10⁻⁷ M)
Solving
pOH= 6.92
Then, pH is calculated as:
pH + 6.92= 14
pH= 14 - 6.92
pH= 7.08
Finally, the solution has a pOH of 6.92 and a pH of 7.08.
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Which best describes how the Sun causes wind?
Energy from the sun promotes condensation, which in turn creates winds.
Condensation definitionWater vapor turns into liquid through a process called condensation. Either the air cools to its air temperature or it gets so dissolves in water that it is no longer hold any more water, which leads to condensation. Dry Point
Why does condensation happen?Condensation happens when warm air bumps into cold surfaces or when your environment is very humid. When this moist warm air strikes a chilly area, it swiftly cools down and sheds the water, which condenses into liquid on the chilly surface.
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Magnesium metal reacts with a solution of silver nitrate in a single-replacement reaction, producing aqueous magnesium nitrate and silver metal. Write the balanced equation for the reaction. If a reaction starts with 0.480 mol Mg, how many moles of silver are produced?
Answer:
0.96 mol AG
Explanation:
To see the number of atoms of an element, we need to multiply stoichiometry of that molecule to the number that is written on the foot of element. Thus the balanced reaction is
\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)
And the mole of silver produced from 0.480 mol is 0.96 mol
What is Balanced equation?Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.
The unbalanced equation is
\(\rm Mg+AgNO_{3}\rightarrow Mg(NO_{3})_{2}+Ag\)
Magnesium atoms on reactant and product side is 1.
Nitrogen atoms on reactant side is 1 and on product side it is 2 so, multiply \(AgNO_{3}\) by 2, now the reaction becomes
\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+Ag\)
Silver atom on reactant side is 2 while on product side it is 1 so, multiply Ag by 2, now the balanced equation is
\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)
The mole ratio of Mg to silver is 1:2
1mole of Mg produce=2 mole of Silver
0.480 mol of magnesium produce= 2×0.480=0.96 mol fo silver
Thus the balanced reaction is
\(\rm Mg+2AgNO_{3}\rightarrow Mg(NO_{3})_{2}+2Ag\)
And the mole of silver produced from 0.480 mol is 0.96 mol
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Suppose you are studying the K sp Ksp of K C l O 3 KClOX3 , which has a molar mass of 122.5 g/mol, at multiple temperatures. You dissolve 4.00 g of K C l O 3 KClOX3 in 12 mL of water at 85 oC and cool the solution. At 74 oC, a solid begins to appear. What is the K sp Ksp of K C l O 3 KClOX3 at 74 oC
According to the question the Ksp of KClO₃ at 74°C is 1.07 x 10-3 mol²/L²
What is temperature?Temperature is a physical property of matter that quantitatively expresses the common notions of hot and cold. It is measured by a thermometer and indicated by a numerical value on a mutually agreed-upon temperature scale such as Celsius, Fahrenheit, or Kelvin.
The Ksp of a substance is the equilibrium constant for the dissolution reaction for that substance. To calculate the Ksp of KClO₃ at 74 oC, we first need to calculate the molar concentration of KClO₃ in the solution.
Since 4.00 g of KClO₃ has a molar mass of 122.5 g/mol, the molar concentration of KClO₃ would be
c = 4.00 g/122.5 g/mol = 0.0327 mol/L
The Ksp of KClO₃ at 74 oC can then be calculated using the following equation:
Ksp = [K+] x [ClO³⁻]
where [K+] and [ClO³⁻] are the molar concentrations of the K+ and ClO3- ions, respectively.
Since KClO₃ dissociates completely into K⁺ and ClO³⁻ ions, the molar concentration of each ion is equal to the molar concentration of KClO₃, which we calculated to be 0.0327 mol/L.
Therefore, the Ksp of KClO₃ at 74 oC is
Ksp = [K⁺] x [ClO³⁻] = (0.0327 mol/L) x (0.0327 mol/L) = 0.00107089 mol²/L²
or
Ksp = 1.07 x 10-3 mol²/L²
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In the reduction reaction, the hot water and the 95% ethanol act as a solvent pair for the benzil. Which is the better solvent and which is the poorer one?
In the reduction reaction involving benzil, hot water and 95% ethanol act as a solvent pair. Among the two, ethanol is the better solvent as it can dissolve benzil more efficiently, while hot water serves as the poorer solvent due to its lower solubility for benzil.
In the reduction reaction, the 95% ethanol is the better solvent for benzil as it is able to dissolve more of the compound due to its polar nature. Hot water, on the other hand, is a poorer solvent for benzil as it is less polar and less able to dissolve the compound. However, both solvents are necessary for the reduction reaction as they help to create the necessary conditions for the reduction of benzil to take place.
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Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium?
A sample of ammonia gas is stored in a 227 ml flask at 600 mm of Hg and 10.0°C. The gas is allowed to expand into another flask of volume 1.78L at 27°C. What is the pressure of ammonia in the second flask ?
Answer:
P1V1/T1 = P2V2 / T2.
- combined gas
equation
(227×600) / 283. = (1780× P2 )/300
P2 = (300 ×227×600)/283 ×1780
P2 = 81.11
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