the mirror in the hubble space telescope has a radius of curvature of 21.5m. what is the focal length of the mirror?

Based on this information, we can use the formula for the path length of a beam of light traveling through a medium with a varying index of refraction to calculate the total path length through the tumor, and thus the depth of the tumor.

To calculate the depth of the tumor below the surface of the liver, we need to use the formula for the path length of a beam of light traveling through a medium with a varying index of refraction. This formula is given by:

Path length = ∫n(x) dx

Where n(x) is the index of refraction of the medium at position x, and the integral is taken along the path of the beam. In this case, the beam enters the liver and reflects off the tumor, so we can break up the path into two segments: one through the liver before the reflection, and one through the tumor after the reflection.

Let's assume that the index of refraction of the liver is approximately constant, and that the tumor has a higher index of refraction due to its density. Then we can write:

Path length = ∫n_liver(x) dx + ∫n_tumor(x) dx

Where n_liver(x) is the index of refraction of the liver, and n_tumor(x) is the index of refraction of the tumor. We can also assume that the path length through the liver before the reflection is simply the distance traveled by the beam, which is 13.0 cm. Thus:

Path length = 13.0 cm + ∫n_tumor(x) dx

To calculate the integral, we need to know the profile of the index of refraction in the tumor. This will depend on the size and shape of the tumor, as well as its composition. Without more information, we cannot provide an exact answer to this question. However, we can make some general statements about how the depth of the tumor might affect the path length.

If the tumor is small and located near the surface of the liver, the path length through the tumor will be relatively short, and the depth of the tumor will be small. Conversely, if the tumor is large or located deep within the liver, the path length through the tumor will be longer, and the depth of the tumor will be greater.

In summary, to calculate the depth of the tumor below the surface of the liver, we need to know the profile of the index of refraction in the tumor, which will depend on its size, shape, and composition. Based on this information, we can use the formula for the path length of a beam of light traveling through a medium with a varying index of refraction to calculate the total path length through the tumor, and thus the depth of the tumor.

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The wavelength of the light with specified separation and angle is calculated to be 578.45 nm.

The formula for light going through a double slit with separation is,

d = 2.42 × 10⁻⁵ m.

Line number m = 2

Angle θ = 2.74°

The wavelength is the separation between the peak and trough of two sound waves.

To find the wavelength, here we use the formula as,

sin θ = Line number × λ ÷ (distance)

where,

λ is wavelength

By substituting all the given values,

Sin (2.74°) = 2 × λ ÷ (2.42 × 10⁻⁵)

Rearranging the equation,

λ = [Sin (2.74°)×(2.42 × 10⁻⁵] ÷ (2)

λ = 578.45 nm.

Thus, wavelength λ of the light is calculated to be 578.45 nm.

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Option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.

An arch is indeed a vertical curving construction that covers an elevated space that may or may not sustain the load above it or the pressure gradient against it

In the case of a horizontally arched, such as an embankment dam. While arches and vaults are often confused, A vault is defined as an ongoing arch forming a roof.

Option D satisfies the fill-in blanks option.

Hence option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.

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To keep the seesaw balanced, the torque on both sides of the pivot must be equal. Assuming that the pivot is in the middle of the seesaw, the torque on the left side of the pivot must be equal to the torque on the right side of the pivot.
The torque is calculated by multiplying the force by the distance from the pivot. Since the seesaw is balanced, the total force on each side of the pivot must be equal. Let's call this force "F".
On the left side of the pivot, we have a 4.0 kg cat standing at a distance "d" from the pivot. The torque on this side is then: T_left = F * d

On the right side of the pivot, we have an unknown weight (let's call it "W") standing at a distance "x" from the pivot. The torque on this side is:
T_right = F * x
Since the seesaw is balanced, T_left = T_right. Therefore:
F * d = F * x
Dividing both sides by F:
d = x

So the distance the cat must stand from the pivot is equal to the distance the unknown weight is from the pivot. We don't know the weight or the distance, but we know that they must be equal. The cat must stand the same distance from the pivot as the unknown weight. We don't know the exact distance, but it must be equal to keep the seesaw balanced.

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The statement 'establishing a high critical value in a statistical test is associated with more confidence' is TRUE.

The statistical significance is a arbitrary value used to indicate that data collected can be used to confirm (or reject) my working hypothesis.

The most widely used value to measure the statistical significance is the p threshold.

In conclusion, the statement 'Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established' is TRUE.

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Answer:

The answer is F or false

Explanation:

correct edge 2023

Answer:

r = 41.1 10⁹ m

Explanation:

For this exercise we use the equilibrium condition, that is, we look for the point where the forces are equal  

                  ∑ F = 0

                  F (Earth- probe) - F (Mars- probe) = 0

                  F (Earth- probe) = F (Mars- probe)

Let's use the equation of universal grace, let's measure the distance from the earth, to have a reference system

the distance from Earth to the probe is        R (Earth-probe) = r

the distance from Mars to the probe is        R (Mars -probe) = D - r

where D is the distance between Earth and Mars

                 \(G \ \frac{m \ M_{Earth}}{r^2} = G \ \frac{m \ M_{Mars}}{(D-r)^2}\)

                 M_earth (D-r)² = M_Mars r²

                 (D-r) = \(\sqrt{ \frac{M_{Mars}}{ M_{Earth}} }\)    r

                  r ( \(1 + \sqrt{ \frac{M_{Mars}}{M_{Earth}} }\)) = D

                  r = \(\frac{D}{ 1+ \sqrt{\frac{M_{Mars}}{ M_{Earth}} } }\)

We look for the values ​​in tables

                  D = 54.6 10⁹ m (minimum)

                  M_earth = 5.98 10²⁴ kg

                  M_Marte = 6.42 10²³ kg = 0.642 10²⁴ kg

let's calculate

                  r = 54.6 10⁹ / (1 + √(0.642/5.98)  )

                  r = 41.1 10⁹ m

Answer:

The desk is pushing back on Arianna

Explanation:

If you read newton's 3rd law, it states that for every action force (Arianna pushing the desk), there is an equal reaction force (The desk pushing back on her). This is true for EVERY OBJECT THAT HAS MOTION!

It has been demonstrated that modified sports, in which the equipment and rules are altered to improve skill performance, foster skill learning and may even boost participation.

The sport is replicated in a modified game, although some of the regulations are altered. Limited touches or time with the ball, a smaller field or court, different-sized balls or goals, or the obligation to defend repeatedly are some examples of modified rules. Like any other sport you may have played, such as basketball or football, modified sports feature regulations that have been modified to take into account the talents and abilities of older or less mobile participants. Depending on the skills of the participants who want to participate, modified sports can be altered.

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A vector is a mathematical object that has both magnitude and direction.  Both the vectors and analogue multimeter shows the magnitude as well as direction of the value that measures.

To find the answer, we have to know about the multimeters.

Thus, we can conclude that, Both the vectors and analogue multimeter shows the magnitude as well as direction of the value that measures.

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Answer: True

Answer:

0. 75A

Explanation:

R1=20omh

R2=20omh

R3=20omh

equivalent voltage (V)= 5.00V

equivalent resistance (R) = ?

equivalent current (I)= ?

since, they are in parallel so,

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/20 + 1/20 + 1/20

1/R = 3/20

R = 6.67 ohm

Now,

from ohm's law

V= IR

or, 5 = 6.67*I

or, I = 0.749

hence, I= 0.75A

The spring has 3.7 J energy when a force of 37. N act on it.

Energy is the ability or the capacity to perform work.

To calculate the energy of the spring, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the spring has 3.7 J energy.

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The conservation laws are very important to understand about the physical world. Because they describe which processes can or cannot occur in nature.

In physics, a conservation law states that a particular measurable property of an isolated system does not change as the system evolves over time. The four important conservation laws are conservation of mass and energy, conservation of linear momentum, conservation of angular momentum and conservation of electric charge.

The energy and mass can neither be created nor be destroyed, but can be transformed from one form to another form. This is called Law of conservation of mass and energy. The total momentum of a system remains constant according to law of conservation of linear momentum.

When no external torque acts on an object, no change of angular momentum occur according to law of conservation of  angular momentum. The total amount of electric charge in a closed system remain constant according to law of conservation of electric charge.

Your question is incomplete most probably your full question was:

What are the four conservation laws in physics?

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Answer:

1. Voltage across 600 pF is 10 V.

2. Voltage across 300 pF is 20 V.

3. Voltage across 200 pF is 30 V.

Explanation:

We'll begin by calculating the total capacitance of capacitor. This can be obtained as follow:

Capicitance 1 (C₁) = 600 pF

Capicitance 2 (C₂) = 300 pF

Capicitance 3 (C₃) = 200 pF

Total capacitance (Cₜ) =?

1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃

1/Cₜ = 1/600 + 1/300 + 1/200

1/Cₜ = 1 + 2 + 3 / 600

1/Cₜ = 6/600

1/Cₜ = 1/100

Cₜ = 100 pF

Next, we shall convert 100 pF to Farad (F). This can be obtained as follow:

1 pF = 1×10¯¹² F

Therefore,

100 pF = 100 pF × 1×10¯¹² F / 1 pF

100 pF = 1×10¯¹⁰ F

Thus, 100 pF is equivalent to 1×10¯¹⁰ F.

Next, we shall determine the charge. This can be obtained as follow:

Voltage (V) = 60 V

Capicitance (C) = 1×10¯¹⁰ F

Charge (Q) =?

Q = CV

Q = 60 × 1×10¯¹⁰ F

Q = 6×10¯⁹ C

1. Determination of the voltage across 600 pF.

Capicitance 1 (C₁) = 600 pF = 6×10¯¹⁰ F

Charge (Q) = 6×10¯⁹ C

Voltage 1 (V₁) =?

Q = C₁V₁

6×10¯⁹ = 6×10¯¹⁰ × V₁

Divide both side by 6×10¯¹⁰

V₁ = 6×10¯⁹ / 6×10¯¹⁰

V₁ = 10 V

2. Determination of the voltage across 300 pF.

Capicitance 2 (C₂) = 300 pF = 3×10¯¹⁰ F

Charge (Q) = 6×10¯⁹ C

Voltage 2 (V₂) =?

Q = C₂V₂

6×10¯⁹ = 3×10¯¹⁰ × V₂

Divide both side by 3×10¯¹⁰

V₂ = 6×10¯⁹ / 3×10¯¹⁰

V₂ = 20 V

3. Determination of the voltage across 200 pF.

Capicitance 3 (C₃) = 200 pF = 2×10¯¹⁰ F

Charge (Q) = 6×10¯⁹ C

Voltage 3 (V₃) =?

Q = C₃V₃

6×10¯⁹ = 2×10¯¹⁰ × V₃

Divide both side by 2×10¯¹⁰

V₃ = 6×10¯⁹ / 2×10¯¹⁰

V₃ = 30 V

1. The deceleration of the aeroplane in the 35s is -1.6m/s²

2. The force acting on the aeroplane is 4.0× 10⁵N

3. The momentum of the aeroplane when its speed is 6.0m/s is 15 ×10⁶kgm/s

The equation of motion are used in solving problems related to motion. The equations of motion are

1. v = u+ at

2 S = ut + 1/2at²

3. v² = u²+2as

where v is the final velocity

u is the initial velocity

S is the distance

t is time

a is the acceleration

The deceleration of the plane after 35s can be calculated as;

v = u+at

v= 6m/s, u= 62m/s , t = 35s

6 = 62+35a

35a = 6-62

35a =- 56

a = - 56/35

a = -1.6m/s²

the negative sign shows that the plane decelerates.

The force acting on the plane is calculated as;

F = ma

F = 2.5×10⁵× 1.6

F = 4× 10⁵N

The momentum of the plane at 6m/s is ;

p = mv

p = 2.5×10⁵ × 6

p = 1.5× 10⁶ kgm/s

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The coefficeint of friction given that the object weighing 7.6 N requires a force of 3.1 N to push it along at constant velocity, is 0.41

We know already that coefficient of friction is related to frictional force and normal reaction according to the following formula:

Frictional force (N) = coefficient of friction (μ) × normal reaction (N)

F = μN

Using the above formula, we can obtain the coefficient of friction as illustrated below:

Frictional force (N) = coefficient of friction (μ) × normal reaction (N)

F = μN

3.1 = μ × 7.6

Divide both sides by 7.6

μ = 3.1 / 7.6

μ = 0.41

Thus, we can conclude that the coefficient of friction is 0.41

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Answer: The longer the lever, the greater the force on the load will be.

Explanation:

Answer:

Decaying

Explanation:

Dead plants and animals go through decaying process as their body is broken down into many pieces which later becomes the part of soil. Decaying process is done by decomposers like bacteria, fungi, etc.

Answer:

If this is your question... the answer is C.

Explanation:

For edge:)

Answer:

C on edge2021

To determine flow rate, I conducted an experiment by measuring the volume of water collected in a container over a specific period of time.

To determine the flow rate of water from a tap or water source, I followed a simple experiment using a container and a stopwatch. First, I selected a suitable container with known volume markings, such as a measuring jug. Then, I placed the container under the tap and ensured it was positioned securely to collect all the water without any spillage.

Next, I turned on the tap to its maximum flow and started the stopwatch simultaneously. I allowed the water to flow into the container for a specific duration, such as one minute, to ensure accurate measurements. During this time, I made sure to avoid any disruptions or obstructions to the water flow.

Once the predetermined time elapsed, I stopped the stopwatch and carefully measured the volume of water collected in the container. It is essential to ensure accurate measurements by aligning the container with the appropriate volume markings and checking from eye level.

By dividing the measured volume of water by the duration of time in minutes, I calculated the flow rate in liters per minute. For instance, if 1 liter of water was collected in one minute, the flow rate would be 1 liter/minute.

To improve the accuracy of the flow rate measurement, it is advisable to repeat the experiment multiple times and calculate the average flow rate. Additionally, it is important to note that the flow rate can vary depending on factors such as water pressure, pipe diameter, and any obstructions in the plumbing system. Regular maintenance and inspection of the tap or water source can help ensure optimal flow rates.

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Answer:

←13

Explanation:

You see the two men pushing it the opposite direction from each other. When you see different net forces you subtract the numbers from each other. So 53- 40=13. You see which value holds the greatest amount and say that the answer you got is supposed to be that side of the net force. The answer is "13 net force to the left, OR ←13"

Answer:

B: C + O2 = CO2

Explanation:

In Chemistry,a synthesis reaction is one that occurs when two or more reactants combine in such a manner that they form a single product.

Looking at the options, the only one where 2 reactants combine to form a single product is option C where Carbon reacts with Oxygen to form carbon (IV) oxide.

The total kinetic energy of the two-cart system is 2 Joules (J). The total kinetic energy is the sum of the individual kinetic energies of all the objects in a system.

The kinetic energy of an object is given by the formula: KE = 1/2 * mass * velocity².

For cart A, with a mass of 1 kg and a velocity of 1 m/s:

KE(A) = 1/2 * 1 kg * (1 m/s)

= 1/2 * 1 kg * 1 m²/s²

= 1/2 * 1 J

= 0.5 J

For cart B, with a mass of 1 kg and a velocity of 1 m/s:

KE(B) = 1/2 * 1 kg * (1 m/s)²

= 1/2 * 1 kg * 1 m²/s²

= 1/2 * 1 J

= 0.5 J

To find the total kinetic energy of the two-cart system, we simply add the kinetic energies of the individual carts:

Total KE = KE(A) + KE(B)

= 0.5 J + 0.5 J

= 1 J + 1 J

= 2 J

Therefore, the total kinetic energy of the two-cart system is 2 Joules (J).

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Answer:

4.26 m/s

Explanation:

h = 0.925

v = 0

u = ?

v = u^2 - 2gh

0 = u^2 - 2gh

u = sqrt 2gh

= sqrt 2*9.8*0.925

= 4.258

= 4.26

Answer:

Below

Explanation:

If they are all in parallel, the quivalent resistance is given by

            1                     =    3.6 Ω

  1/R1   + 1/R2  + 1/R3

Explanation:

Michael should put the vase at the bottom of the shelf to reduce the potential energy because the height of the vase to the floor is nearly zero.

Answer:

The SI unit for activity is one decay per second and is given the name becquerel (Bq) in honor of the discoverer of radioactivity. That is, 1 Bq = 1 decay/s. Activity R is often expressed in other units, such as decays per minute or decays per year.