The angle ϕ after the deflection of the horizontal laser beam is equal to 30 degrees.
Based on the figure, we can see that the incoming laser beam is reflected by the mirror and deviates by an angle of 60 degrees from its original direction.To determine the angle ϕ, we need to use the law of reflection, which states that the angle of incidence is equal to the angle of reflection. In this case, the incoming beam makes an angle of 90 degrees with the mirror surface, since it is perpendicular to the mirror. The reflected beam makes an angle of 60 degrees with the incoming beam, as given in the question. Therefore, the angle of reflection is 90 - 60 = 30 degrees.
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In a motor, electrical current enters through the brushes.
Please select the best answer from the choices provided
T
F
THE ANSWER IS TRUE
Answer: ITS T
Explanation:
In a motor, electrical current enters through the brushes. TRUE.
The magnitude of a black hole's tidal force is proportional to and inversely proportional to
Answer:
the square distance i think doubble check me with others from brainly if i am wrong then i am so sorry.
Ball A od mass 5.0 kilograms moving at 20. meters per second colides with ball B of imknnown mass moving at 10 meters per scond in the same direction. After the collision, ball A movies at 10. meters per second and ball B at 15 meters per second, both still in the same direction. What is the mass of ball B
Answer:
10 kg
Explanation:
Use law of conservation of momentum
momentum of system before collision = momentum of system after collision
5 kg * 20 m/s + x kg * 10 m/s = 5 kg * 10 m/s + x kg * 15 m/s
100 + 10x = 50 + 15 x
50 = 5x
x = 10 kg
WILL MARK BRAINLIEST!!!
From the choices below, select the one that best describes the difference between distance and displacement.
Distance includes direction,
Distance includes acceleration, displacement does not
Displacement includes direction, distance does not
Distance include speed, displacement, does not
Displacement includes direction, distance does not
is your answer. hope it helps!
Use the concept of inertia to explain why Newton’s first law of motion is accepted as true
A small particle with charge q = -6.0 times 10^-6 C is released from rest at point a. When the particle reaches point b its kinetic energy is 48.0 times 10^-6 J. The only force acting on the particle is the electric force. If the electric potential at point b is 12.0 V. what is the electric potential at point a? -8.0 V zero +4.0 V +8.0 V +20.0 V none of the above
The electric potential at point a (a small particle with charge q = -6.0 times 10⁻⁶ C is released from rest at point a. When the particle reaches point b its kinetic energy is 48.0 times 10⁻⁶ J) is +20.0 V (option 5)
The change in electric potential energy of a charged particle moving in an electric field is given by the equation:
ΔU = qΔV
Where,
ΔU is the change in electric potential energy
q is the charge of the particle, and
ΔV is the change in electric potential.
The change in kinetic energy of the particle is given by the equation:
ΔK = ½mv² - ½mv₀²
Where,
ΔK is the change in kinetic energy
m is the mass of the particle
v is the final velocity, and
v₀ is the initial velocity.
Since the particle is released from rest, v₀ = 0 and the equation simplifies to:
ΔK = ½mv²
The change in electric potential energy is equal to the negative of the change in kinetic energy:
ΔU = -ΔK
Hence,
qΔV = -½mv²
ΔV = -(½mv²)/q
ΔV = -(48.0 x 10⁻⁶ J) / (-6.0 x 10⁻⁶ C)
ΔV = +8.0 V
The electric potential at point a is the electric potential at point b plus the change in electric potential:
Va = Vb + ΔV
Va = 12.0 V + 8.0 V
Va = 20.0 V
Therefore, the electric potential at point a is +20.0 V (option 5)
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A spring has a force of 2.0N and an extension of 0.30m. What will the extension be if the force applied is 6 N.
Will mark as brainliest
Answer:
0.9 m
Explanation:
Hooke’s Law
\(\large\boxed{F = ke}\)
where:
F is the force in newtons (N).k is the 'spring constant' in newtons per metre (N/m).e is the extension in metres (m).Given values:
F = 2.0 Ne = 0.30 mSubstitute the given values into the formula to find k:
\(\implies 2.0=0.30k\)
\(\implies k=\dfrac{2.0}{0.30}\)
\(\implies k=\dfrac{20}{3}\; \sf N/m\)
To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:
\(\implies 6=\dfrac{20}{3}e\)
\(\implies 18=20e\)
\(\implies e=\dfrac{18}{20}\)
\(\implies e=0.9\; \sf m\)
Post-exposure radiation levels are approximately Normally distributed. The levels (in Sv) of a random sample of three trauma victims who were recently exposed are 5.5, 6.2, and 4.8. A 95% confidence interval for the mean based on these data is:
Answer:
0.404
Explanation:
The calculation of confidence interval for the mean is shown below:-
Data provided in the question
Mean = 5.5
The Standard deviation for three values is 0.7
Since there is 95% of the confidence interval so the critical value is
\(t_{0.025.5} = 4.303\\\)
Now
Margin error is
\(t_{0.025.5} = 4.303\times \frac{s}{\sqrt{n} }\)
\(= 4.303\times \frac{0.7}{\sqrt{3} }\)
= 1.74
Now,
The Standard error is
\(= \frac{s}{\sqrt{n} }\)
\(= \frac{0.7}{\sqrt{3} }\)
= 0.404
Hence, the confidence interval for the mean based is 0.404
A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
A 5kg block is pushed 3m at a constant velocity up a vertical wall by a constant force applied at an angle of 37 degree with the horizontal, if the coefficient of kinetic friction between the block and the wall is 0.3. what is the work done by the force on the block?
The work done by the force on the block is:
\(W=135.41*3=406.23 \: J\)
The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.
Using trigonometric functions:
\(F_{y}=Fsin(37)\)
This component is in the positive y-direction.
Now, there is a friction force between the block and the wall, so we need to find the friction force.
\(F_{f}=\mu N\)
Where:
μ is the coefficient of kinetic frictionN is the normal force (Here N = Fcos(37))Let's use the first Newton's Law to get F.
F(y) is upward (+) and F(f) and the weight is downward (-).
\(F_{y}-F_{f}-W=0\)
\(F_{y}-F_{f}=mg\)
Factoring F in the left side:
\(F(sin(37)-\mu cos(37))=mg\)
\(F=\frac{mg}{sin(37)-\mu cos(37)}\)
\(F=\frac{5*9.81g}{sin(37)-(0.3*cos(37))}\)
\(F=135.41\: N\)
Therefore, the work done will be:
\(W=Fd\)
\(W=135.41*3=406.23 \: J\)
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Shrek finds donkey in a cart (total mass 50 kg) on the side of the road. He starts to pull the cart along a smooth road with a coefficient of friction 0. 2 with a force of 120 N [FWD]. If he accelerated to a speed of 15 km/h, how far did the cart move during acceleration?
Continued from Question 1 - so hey guess what? This is a multiple motion question. Shrek maintains a constant speed after his initial acceleration, then breaks into a sprint. He at this point is pulling on the cart with a force of 125 N (FWD 20 UP) and maintains this for 10s. How fast is he going at this point?
The acceleration phase, the cart moves approximately 1.724 meters. During the sprint, Shrek is going approximately 33.6 m/s.
Shrek is pulling a cart with a total mass of 50 kg along a smooth road. The coefficient of friction on the road is 0.2. He applies a forward force of 120 N to the cart, causing it to accelerate. The question asks how far the cart moves during this acceleration period when Shrek reaches a speed of 15 km/h.
To find the distance the cart moves during acceleration, we can use the equation:
distance = (initial velocity^2 - final velocity^2) / (2 * acceleration)
Since the cart starts from rest, the initial velocity is 0. We need to convert the final velocity from km/h to m/s by multiplying it by 1000/3600:
final velocity = 15 km/h * (1000 m/1 km) * (1 h/3600 s) = 4.17 m/s
The acceleration can be calculated using Newton's second law:
force = mass * acceleration
Rearranging the equation, we can solve for acceleration:
acceleration = force / mass = 120 N / 50 kg = 2.4 m/s^2
Plugging in the values, we have:
distance = (0^2 - 4.17^2) / (2 * 2.4) = -4.17^2 / 4.8 ≈ -1.724 m^2/s^2 ≈ -1.724 m
The negative sign indicates that the cart is moving in the opposite direction of the force applied by Shrek. However, since distance cannot be negative, we take the absolute value of the result. Therefore, the cart moves approximately 1.724 meters during the acceleration phase.
Continued from Question 1, after Shrek's initial acceleration, he maintains a constant speed and then breaks into a sprint. During this sprint, he pulls the cart with a force of 125 N in the forward direction and 20 N upwards. The question asks how fast Shrek is going at this point.
To find Shrek's speed during the sprint, we can use Newton's second law:
force = mass * acceleration
The force acting on the cart is the sum of the forward force and the upward force:
total force = forward force + upward force = 125 N + 20 N = 145 N
Rearranging the equation, we can solve for acceleration:
acceleration = force / mass = 145 N / 50 kg = 2.9 m/s^2
Since Shrek maintains this acceleration for 10 seconds, we can calculate the change in velocity using the equation:
change in velocity = acceleration * time = 2.9 m/s^2 * 10 s = 29 m/s
Since Shrek started from his constant speed, his final speed during the sprint is:
final speed = initial speed + change in velocity = 15 km/h + 29 m/s ≈ 33.6 m/s
Therefore, Shrek is going approximately 33.6 m/s during the sprint.
In summary, during the acceleration phase, the cart moves approximately 1.724 meters. During the sprint, Shrek is going approximately 33.6 m/s.
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The main goal of every defense is to __________. A. stop the ball B. regain possession of the ball C. protect the goal or basket D. all of the above
Answer:
D.
Explanation:
I believe it is D. Because in defense you are to stop others from scoring, while trying to score. But also while trying to protect the Goal or basket. I hope this helps you out.
Answer:
d
Explanation:
Susan was traveling in an airplane. She looked out of a window in the airplane and saw clouds in the sky. Why could Susan see clouds through the window of the airplane?
A.
Most of the light hitting the window was transmitted when it passed through the window.
B.
Most of the light hitting the window was reflected off of the window instead of passing through it.
C.
Most of the light hitting the window was refracted when it passed through the window.
D.
Most of the light hitting the window was absorbed by the window instead of passing through it
Susan sees cloud through the window because most of the light hitting the window was transmitted when it passed through the window. Option A
Why can the cloud be seen through the window of an airplane?The windows of an airplane are designed to be transparent, allowing light to pass through them with minimal distortion. This makes it easy to see outside the window and observe the clouds, the ground, or other objects.
Thus the fact that the window can be seen to be transparent means that it is able to transmit light as we have said above here.
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Most of the light hitting the window was transmitted when it passed through the window.
option A.
What is the direction of light?
Light travels in straight lines unless it is reflected, refracted, or absorbed by a material. When light passes through a material, such as a window, it can be transmitted (pass through the material), reflected (bounce off the material), or refracted (bend as it passes through the material).
In the case of the airplane window, it is designed to be transparent, which means that it allows most of the light hitting it to pass through, without significant absorption or reflection. This is because the window is made of a material that is highly transparent to visible light, such as glass or acrylic.
Thus, the reason Susan could see the clouds through the window of the airplane is that the window was made of materials that allow most of the light hitting it to pass through, which is called transmission.
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A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?
Answer:
1275J
Explanation:
Given parameters:
Force on box = 85N
Distance moved = 15m
Unknown:
Work done = ?
Solution:
Work done is the amount of force applied on a body to move it through a specific distance.
Work done = Force x distance
Now insert the parameters and solve;
Work done = 85 x 15 = 1275J
Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52
The solution to the equation is; x =4 and x = 10
How do you solve an equation?In most cases, the goal is to isolate the variable (usually represented by x) on one side of the equation. To do this, you can use inverse operations (e.g., adding, subtracting, multiplying, or dividing both sides of the equation by the same value) to cancel out any other terms.
If the equation contains more than one variable, you will need to repeat the above steps to solve for the other variables.
Now we have that;
(x – 3)^2 = 49
x^2 - 6x + 9 = 49
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if you were standing on the far side of the moon, which object would you never see?
If you were standing on the far side of the moon, you would never be able to see the Earth.
The moon is tidally locked to Earth, which means that the same side of the moon always faces Earth. This is why we only ever see one side of the moon from Earth. Similarly, if you were standing on the far side of the moon, the Earth would always be blocked from view by the moon itself. So, no matter where you stood on the far side of the moon, you would never be able to see the Earth.
In addition, there are no other objects in space that would consistently block the view of the Earth from the far side of the moon. So, the only thing preventing you from seeing the Earth would be the moon itself.
Overall, standing on the far side of the moon would offer a unique and breathtaking view of the universe, but unfortunately, the Earth would not be visible from that vantage point.
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You are building a PV powered water pumping station in Broken Hill (latitude 32° S). You expect that you will need to pump more water in summer than in winter. Which of these angles would be the most appropriate tilt for your solar cells array? 32° 50° 90° 20⁰
The most suitable tilt for a solar array on Broken Hill (32 degrees south latitude) is 32 degrees. This selection is based on the concept of maximizing solar energy production throughout the year. By tilting the solar panels at an angle that matches their latitude, the panels are positioned to receive the most direct sunlight at noon on the vernal equinox, resulting in optimal energy production.
For Broken Hill at 32 degrees south latitude, orienting the solar panels at an inclination of 32 degrees ensures that they match the path of the sun at that particular location. This tilt angle allows the panels to capture maximum sunlight at any time of the year, taking into account the changing sun angle throughout the year.
By optimizing the tilt angle according to latitude, solar panel arrays can maximize energy yields and efficiently power water pumping stations. In this way enough energy is generated in other seasons while covering the high water demand in summer.
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A solid cylinder with radius 0.120 m is mounted on a frictionless, stationary axle that lies along the cylinder axis. the cylinder is initially at rest. then starting at t = 0 a constant horizontal force of 7.00 n is applied tangentially to the surface of the cylinder. you measure the angular displacement θ−θ0 of the cylinder as a function of the time t since the force was first applied. when you plot θ−θ0 (in radians) as a function of t2 (in s2), your data lie close to a straight line. If the slope of this line is 16.0 rad/s2 , what is the moment of inertia of the cylinder for rotation about the axle?
The moment of inertia of the cylinder with radius 0.120m mounted on a frictionless stationary axle for rotation about the axle is 0.026kgm^2.
At the initial time the body was at rest, so the initial angular velocity wo=0. According to the equation , theta -theta o = 1/2×a0 ×t +wo×t.
Now when the function for angular displacement (θ−θ0) = f(t^2) ( in radians ) is drawn the data lies close to a straight line, the slope is equal to =16.0 rad/s^2.
So the value of angular acceleration a0 is, k=1/2×a0 ,a0=2×k , a0=32 rad/s^2.
In rotational motion of the cylinder , I×a0= Tz ,I×a0=F×r , I= (F×r)/ a0 ,I=(7×0.12)/32, I= 0.026 kgm^2.
So the moment of inertia of the cylinder for rotation about the axle is 0.026kgm^2.
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A radioactive sample has a count rate of 10,000 Bq. 24 days later the activity has fallen to 625 Bq. What is the half-life of the sample?
Answer:
10000 Bq / 625 Pq = 16
Radioactivity has decreased by a factor of 16
2^4 = 16
So the sample has gone thru 4 half-lives
24 da / 4 = 6 da
6 da is the half-life
a race car is moving at a constant speed around a track.What about the race car is changing and why
A race car is moving at a constant speed around a track. The race car is changing its velocity as the direction of motion changes.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
As the race car is moving at a constant speed around a track, the magnitude of velocity remains same but during race it may changes its direction of motion, that is why, velocity of it, which depends on both magnitude and direction, may changes.
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What is your average velocity if you drive a distance of 481.5 km at a speed of 45 km/h, then the same distance at a speed of 62 km/h
The average velocity is zero. .Average velocity is the ratio of the total displacement to the total time taken. For example, suppose you travel a total distance of 481.5 km, at a speed of 45 km/h, and then travel the same distance at a speed of 62 km/h.
Total distance traveled = 481.5 kmLet the first part of the distance be x km and the second part be (481.5 - x) km. So, the time taken for the first part of the journey =x/45 and the time taken for the second part of the journey is (481.5 - x)/62.The total time taken = x/45 + (481.5 - x)/62= (62x + 45 (481.5 - x))/(45 × 62)= (62x + 21667.5 - 45x)/2790= (17x + 21667.5)/2790The average velocity is the ratio of the total displacement to the total time taken.The total displacement is zero because the car starts and ends at the same point.
Hence, the average velocity is zero.
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If you view a lunar eclipse... the Sun is hidden bclow the horizorf. the Moan is hidden botion the Sun. the Sun is relatively high in the sky, since Earth-Moon line is at right angles to Earth-Sun line.
If you view a lunar eclipse, the Sun is hidden below the horizon.
The Moon is hidden behind the Earth. The Sun is relatively high in the sky since the Earth-Moon line is at right angles to the Earth-Sun line.The above statements about a lunar eclipse are true.
A lunar eclipse occurs when the Earth comes between the Moon and the Sun and as a result, the Earth's shadow falls on the Moon. The Earth's shadow has two parts: the penumbra and the umbra.
The penumbra is the lighter outer part of the shadow, while the umbra is the darker inner part of the shadow. The penumbra causes a partial eclipse of the Moon, while the umbra causes a total eclipse of the Moon.
During a total lunar eclipse, the Moon appears to be red in color, which is why it is sometimes called a "blood moon." This is because the Earth's atmosphere bends some of the sunlight that passes through it and reflects it onto the Moon.
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A student placed a short candle and a slightly taller candle in a small dish filled with baking soda as
shown in the figure. The child then lights both the candles and poured vinegar into the dish of baking
soda.
Baking Soda +
Vinegar
(a) What happens to the candles? Why? In what order?
(b) Mention one precaution the student needs to follow while pouring the vinegar into the dish of
baking soda.
a) As carbon dioxide is formed the shorter candle's flame goes off first, followed by the taller candle. This shows, that in absence of air, the flame goes off. Hence, the air is necessary for combustion.
b) Although both reactants are common home chemicals and foods, care should be taken to avoid splashing in the eyes, and protective clothing should be used. The reaction's byproducts can be disposed of by thoroughly filling the sink with water and washing down the sink with no chemicals touched.
Baking soda and vinegar react with one another to create carbon dioxide gas. The carbon dioxide gas sinks to the bottom of the bowl because it is heavier than the air around it. More and more carbon dioxide gas is produced as the reaction progresses, progressively filling the bowl as it does so. The flame will go out owing to a shortage of oxygen once the level of carbon dioxide reaches that of the flame.
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Aniyah is driving down 7th street. She drives 150 meters in 25
seconds. Assuming she does not speed up or slow down, what
is her speed in meters per second?
Answer:
6m/s
Explanation:
formula used; S= d/t
the "7th Street"doesn't matter it's just apart of the scenario. The only thing that matters is the distance and time which we have. the speed in seconds is 6. I had the same question on my phsyics quiz lol.
Predict what happens to the mechanical advantage of a machine if friction is reduced through the use of oil or some other means.
A big machine is composed of several moving and stationary parts. Some of these parts are in a state of constant motion hence they periodically rub against each other.
Explain about mechanical advantage:The Mechanical Advantage (MA) of a machine is the ratio between the output force produced by the machine divided by the input force exerted on it:The MA is generally a number larger than 1, since machines are used to "multiply" the force applied.There are actually 2 values of the mechanical advantage for a machine:The Ideal Mechanical Advantage (IMA), which is the MA when there are no frictional force acting on the machine, and so when all the work done in input is transferred as energy in output The Actual Mechanical Advantage (AMA), which is the MA when taking into account the frictional forces, which cause a dissipation of part of the energy; so, not all the work done in input is transferred as energy in outputThe efficiency of a machine is defined as the ratio between the two:A machine cannot have an efficiency of 100% because there are always some frictional/resistive forces acting on the system, so part of the energy in input is always dissipated, and therefore AMA < IMA, and so the efficiency is not 100%.As we know that friction force is the resistive force due to relative motion of two surface. When one surface is moving relative to other surface then the motion is resisted by the interaction force between two surface which is known as friction force.To learn more about mechanical advantage refer to:
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A 4357-kg roller coaster car starts from rest at the top of a 36.5-m high track. Determine the speed of the car at the top of a loop that is 10.8 m high.
Answer:17.24 m/s
Explanation:
Astronomers believe _____ was originally a part of earth.at.the sun.jupiter's.the moond.mars
Astronomers believe moon was originally a part of the earth.
It is said that years before a protoplanet - A large body of matter which orbited the sun - called Theia.
This protoplanet had a size which was almost equal to the size of planet mars. Due to some reason, Theia collided with earth and as a result of the collision, a large amount of earth's matter was ejected out into outer space which remained afloat for a long period of time.
Later this mass got accumulated into a spherical body that we now refer to as the moon which we see in the sky.
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Sushant went on an educational trip to a village. There he found a potter making pots. He found that the soil used for making pots was different from normal soil. Name the soil and also tell its characteristics.
The soil used for making pots by potters is commonly known as "Potter's Clay" or "Potter's Soil."
Characteristics of Potter's Clay:
1. Plasticity: Potter's clay has high plasticity, which means it can be easily molded and shaped into different forms without cracking or breaking.
2. Cohesiveness: It exhibits good cohesion, allowing the clay particles to stick together when moistened, forming a workable material.
3. Fine Particle Size: Potter's clay consists of fine particles that contribute to its plasticity and workability.
4. High Water Retention: It has the ability to retain water, which helps maintain the moisture content necessary for the clay to be shaped and formed.
5. Low Shrinkage: Potter's clay exhibits low shrinkage when it dries or undergoes firing, ensuring minimal distortion or cracking during the drying and firing processes.
6. Good Bonding Properties: The clay particles have the ability to bond together, creating a strong and durable structure once fired.
7. Good Porosity: After firing, the clay retains some porosity, allowing the pot to breathe and allowing for the exchange of air and moisture.
Measure the value of the radius of curvature and deduce the value of the focal length.
The radius of curvature is observed to be equal to twice the focal length for spherical mirrors with small apertures. Hence R = 2f.
Does focal length increase with a radius of curvature?As the radius of curvature for a lens grow (R2 > R1), the curvature of the lens decreases, and the focal length of the lens expands (f2 > f1) We can say clearly that the main focus of a spherical mirror lies at the core between the center of curvature and the pole.
the radius of curvature becomes longer the circle gets larger. As the circle gets larger, its curve gets praised, as the curve gets admired on a clear material Focal length of a lens depends on the deform index of the glass from which it is built, and on the curvature of its two surfaces.
So we can conclude that the result of a radius of curvature on the focal length of a convex lens.
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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