The minute hand on a watch is 2.00 cm cm in length. What is the displacement vector of the tip of the minute hand Part A From 8:00 to 8:20 a.m.? Express vector Δ r ⃗ Δr→ in the form Δ r x ΔrxDeltar_x , Δ r y ΔryDeltar_y , where the x and y components are separated by a comma. Δ r ⃗ Δr→ = nothing cm SubmitRequest Answer Part B From 8:00 to 9:00 a.m.? Express vector Δ r ⃗ Δr→ in the form Δ r x ΔrxDeltar_x , Δ r y ΔryDeltar_y , where the x and y components are separated by a comma.

P=F/A

A=F/P

P = 0.1 atm = 10132.5 Pa

A=4 x 10⁵/10132.5

A=39.477 m²

for one wing=39.477 : 2 = 19.739 m²

Answer: In a circuit with parallel resistors, the voltage across each resistor is the same, and the total resistance is equal to the reciprocal of the sum of the reciprocals of the individual resistances.

Since the total resistance is 550Ω and there are four resistors of equal value, the value of each resistor is 550Ω / 4 = 137.5Ω.

Since the voltage across each resistor is 12V and there are four resistors, the voltage across each resistor is 12V / 4 = 3V.

The current through each resistor can be found using Ohm's law, which states that the current through a resistor is equal to the voltage across the resistor divided by the resistance.

Thus, the current through each resistor is 3V / 137.5Ω = 0.0218A.

So, the voltage across each resistor is 3V, and the current through each resistor is 0.0218A.

The voltage across and the current through each parallel resistor is respectively 12 V and 0.384 amp.

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.

Given that:

the total voltage is 12 V.

the total resistance is 550Ω.

The resistance of every resistor = 500/4 Ω = 125 Ω.

As they are connected in parallel combination, the equivalent resistance of them = 125/4 Ω

=31.25 Ω.  

As they are connected in parallel combination,  the voltage across  each resistor is same and it is 12 Volt.

And the current through each parallel resistor = V/R

= 12/31.25 amp

=0.384 amp.

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Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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The REE decreases as a person ages, indicating a decrease in metabolism and muscle mass.

To investigate how calorie prerequisites change as an individual progresses in years, we can utilize the information table that shows the assessment of the day to day resting energy use (REE). We should pick a female grown-up with a load of 70 kg for instance.

Utilizing the Harris-Benedict condition, we can compute the REE for the grown-up at each age range:

Age 18-29:

REE = (447.593 + (9.247 x load in kg) + (3.098 x level in cm) - (4.330 x age)) x 1.0 (female)

= (447.593 + (9.247 x 70) + (3.098 x 165) - (4.330 x 25)) x 1.0

= 1565.14 calories/day

Age 30-60:

REE = (88.362 + (13.397 x load in kg) + (4.799 x level in cm) - (5.677 x age)) x 1.0 (female)

= (88.362 + (13.397 x 70) + (4.799 x 165) - (5.677 x 45)) x 1.0

= 1437.45 calories/day

More than 60:

REE = (447.593 + (8.126 x load in kg) + (3.481 x level in cm) - (4.938 x age)) x 1.0 (female)

= (447.593 + (8.126 x 70) + (3.481 x 165) - (4.938 x 65)) x 1.0

= 1263.95 calories/day

As the individual ages, the REE diminishes. The assessed REE for a grown-up at age 18-29 is 1565.14 calories/day, while the assessed REE for a grown-up more than 60 is 1263.95 calories/day.

These outcomes show that the body's digestion changes over the long haul and turns out to be less effective at consuming calories. Maturing likewise prompts a decline in bulk, which further adds to the diminishing in REE.

Hence, as individuals progress in years, they might have to change their calorie admission to keep a solid weight and stay away from weight gain.

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The y-intercept of a graph is the point at which the graph crosses the y-axis. In this case, the y-intercept of the graph showing the relationship between the motor's force and the boat's acceleration would represent the force required to produce zero acceleration.

In this scenario of the boats being used in an experiment, if the boats have the same mass and the motors are producing force, and the forces are graphed against the acceleration, this will give us a straight line, and the y-intercept of this graph will be the force required to keep the boat at a zero acceleration, this force is known as "friction force" which includes the friction force of the water and the friction force of the bearings in the motor and other mechanical parts in the boats and motor.

It's worth noting that, in practice, getting the y-intercept in this experiment might be very hard as it's very rare to get zero acceleration. Still, one can aim for the lowest possible acceleration, and the force measured can be considered as an approximation for the friction force.

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A solid maintains its volume and shape.

Answer:

140 beats per minute

Explanation:

You have to multiply the ratio 14 beats/6 seconds by 10 because 6 seconds times 10 to get 1 minute. The answer you get is 140 beats/60 seconds.

The centripetal acceleration (a) of an object moving in a circular path is given by the formula:

a = v^2 / r

where v is the speed of the object and r is the radius of the circular path.

If the object moves at a uniform speed of 4v instead, we can plug this value into the formula to find the new centripetal acceleration (a'):

a' = (4v)^2 / r

Simplifying the expression, we get:

a' = 16v^2 / r

Now, we can compare the new centripetal acceleration (a') to the original centripetal acceleration (a):

a' = 16(a)

So, if the object moves in the same circular path at a uniform speed of 4v, the centripetal acceleration will be 16 times greater than the original centripetal acceleration.

Answer: V 2 /r

Explanation: "If a particles move with a uniform speed of V on any given circular path having the radius (r), the particle will have a centripetal acceleration of magnitude (v 2 /r). However, the direction continuously changes and always maintains its position towards the circle."

∑ F (horizontal) = (150 N) cos(60°) - 15 N = (20 kg) a

==>   a = ((150 N) cos(60°) - 15 N)/(20 kg) = 3 m/s²

To calculate the acceleration of the box, we need to consider the net force acting on it. So, the acceleration of the box is 3 m/s².

The net force is the vector sum of the applied force and the force of friction. First, let's find the horizontal and vertical components of the applied force:

Horizontal component of the applied force (F\(_{horizontal}\)) = F\(_{applied}\) × cos(θ)

F\(_{horizontal}\) = 150 N × cos(60°)

F\(_{horizontal}\) = 150 N × 0.5

F\(_{horizontal}\) = 75 N

Vertical component of the applied force (F\(_{vertical}\)) = F\(_{applied}\) × sin(θ)

F\(_{vertical}\) = 150 N × sin(60°)

F\(_{vertical}\) = 150 N × (√3 / 2)

F\(_{vertical}\) ≈ 129.9 N

Now, let's calculate the net force in the horizontal direction:

Net Force in the horizontal direction (F\(_{net horizontal}\)) = F\(_{horizontal}\) - F\(_{friction}\)

F\(_{net horizontal}\) = 75 N - 15 N

F\(_{net horizontal}\) = 60 N

Now, we can calculate the acceleration (a) using Newton's second law of motion, F = ma:

F\(_{net horizontal}\) = m × a

60 N = 20 kg × a

Now, solve for acceleration (a):

a = 60 N / 20 kg

a = 3 m/s²

So, the acceleration of the box is 3 m/s².

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A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)

To arrive at the above conclusion, we must recall that radial acceleration is defined by:

Ac = v²/r; where

Ac - is the magnitude of radial acceleration

v -  is the linear or tangential speed

r - is the radius of the circular path

A′c -  is the new magnitude of the radial acceleration.

Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:

A'c = (2v²)/(0.5r)

= 4v²/(0.5r)

= 8 · (v²/r)

= 8 · Ac

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Full Question:

A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?

A. It remains the same.

B. It increases by a factor of 2.

C. It increases by a factor of 4.

D. It increases by a factor of 8.

E. It decreases by a factor of 2.

Answer:

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sysydyydydysysysysyxhxyt56fys7w727ueudu

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

The electric potential at x=3.0m is  - 180 Volt according to the figure 1.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.

Electric charges and time-varying electric currents are the building blocks of electric fields.

The electric potential at x=3.0m is given by = initial potential energy + electric field× distance

= - 180 Volt + 0 Volt/meter×3 meter

= - 180 Volt.

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Answer:

Explanation:

A. We know that 1microsecond= 10^-6s

So = 9.12*10^-6=9.12*10^-6s

B 1km= 1000m

So 3.42km= 3240m

C.1ms= 10^-3s

And 1cm= 10^-2m

So 44*10^-2m/10^-3s=440m/s

D. 80km/hr= 80*1000/3600= 22.2m/s

Because 1km= 1000m

1hr= 3600s

Well, the tension in the thread will probably quadruple, but the hanging body will continue to just hang there.  

The question gives us no evidence that it is doing any oscillating, and there's no reason for it to start just because it suddenly got heavier.

Based on the value of the Young's modulus, the strand of the metal is made of copper.

The Young's modulus of the metal is calculated as follows;

E = stress/strain

The stress of the metal is calculated as follows;

σ = F/A = mg/A

where;

A is area of the metal

A = πr²

A = π( 2 x 10⁻³)²

A = 1.257 x 10⁻⁵ m²

σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)

σ = 5.5 x 10⁷ N/m²

The strain is calculated as follows;

strain = x/L

where;

x is extension

L is original length

strain = (1 x 10⁻³ m) / 2 m

strain = 5 x 10⁻⁴

E = stress/strain

E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)

E = 1.1 x 10¹¹ N/m²

E = 110 Gpa

The Young's modulus of copper metal is 110 Gpa

Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

It does not affect. The closest nebula is the Orion Nebula at more than 1300 light years from Earth. It is so remote that nothing that happens there can influence the Earth. The only influence is to have beautiful colors and shapes and to let us dream one day to go there and explore them.

Explanation:

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The average velocity of the rider over the course of his trip to the store is 1.0607m/s.

By definition;

The path of the bike rider towards the west and then towards the north signifies a right angle path.

As such the displacement, s can be given as;

s = √(75² + 75²).

Therefore, the displacement, s = 106.07m

The time taken to cover the 75meters in each direction, t = distance/speed = 150/1.5

Therefore, the time taken = 100s.

The average velocity, v = displacement/time

v = 106.07/100

Therefore, Average velocity, v = 1.0607m/s.

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Answer:

1.1

Explanation:

Answer:

Answer C: Climate Zones

Explanation:

Describing the common conditions someplace is called climate zones

Answer:

c- They are types of climate zones

When the painter swinging on the boar, his tangential speed is 3.8 m/s.

A force that causes a body to follow a curved path is known as a centripetal force. It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path.

It is "a force by which bodies are dragged or driven, or in any manner tend, towards a point as to a center," according to Isaac Newton. Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics.

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Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

Explanation:

The formula for determining the Emf induced in a loop is:

\(\varepsilon = \dfrac{d \phi}{dt}\)

\(\varepsilon = \dfrac{d (B*A)}{dt}\)

\(\varepsilon = A \times \dfrac{dB}{dt}\)

\(\varepsilon = (side (l))^2 \times \dfrac{dB}{dt}\)

where;

square area A = ( l²)

l² = 6.0 cm = 6.0 × 10⁻²

∴

\(\varepsilon = ( 6.0 \times 10^{-2})^2 \times 5.0 \times 10^{-3} \ T/S\)

\(\varepsilon =18 \times 10^{6} \ V\)

Recall that:

The resistivity of copper = \(1.68 \times 10^{-8}\) ohm m

We can as well say that the length of the copper wire = perimeter of the square loop;

The perimeter of the square loop = 4L

Thus, the length of the copper wire  = 4 (6.0 × 10⁻² )m

= 24× 10⁻² m

Finally, the current in the loop is determined from the formula:

V = IR

where,

V = voltage

I = current and R = resistance of the wire

Making "I" the subject:

I = V/R

where;

\(R = \dfrac{\rho \times l}{A}\)

\(R = \dfrac{\rho \times l}{\pi * r^2}\)

\(R = \dfrac{1.68 *10^{-8} \times 24*10^{-2}}{\pi * (1*10^{-3})^2}\)

\(R = 0.001283 \ ohms\)

∴

\(I = \dfrac{18*10^{-6}}{0.001283}\)

I = 14.029 mA

If v(t) is speed measured in meters per second (m/s), and t is time measured in seconds (s), then the constants A and B in

v(t) = At ³ - Bt

must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.

[m/s] = A [s]³ - B [s]

[m/s] = [m/s⁴] [s]³ - [m/s²] [s]

[m/s] = [m/s] - [m/s]

[m/s] = [m/s]