the minimum temperature at which a flame will ignite and continue to burn fuel oil vapor as it rises from a pool of liquid fuel oil is called the .

The daughter nucleus that is formed in the process is  152/64Gd .

Gadolinium-152 and a beta particle are produced during the beta decay of europium-152. An electron that is released from the nucleus during the decay process is the beta particle.

A beta ray is released from an atomic nucleus during a radioactive decay process known as beta decay. The proton in the nucleus changes from a proton to a neutron during beta decay, and vice versa.

The beta particle is represented by the symbol "β" with a superscript indicating its charge (-1 for an electron)

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Explanation:

21. The given molecule for cracking is tetradecane.

On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.

The chemical equation is shown below:

\(C_1_4H_3_0->C_1_0H_2_2+2C_2H_4\)

22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.

Thus among the given options, the first option is the correct one.

23. Isomers of butanol are shown below:

It is 2-butanol.

The position of -OH group changes to the second carbon.

The energy is coming from the battery that is in the torchlight.

In the case of an object in motion, energy is coming from the kinetic energy of the object. Kinetic energy is the energy an object possesses due to its motion. This energy is transferred to the object by an external force, such as a push or a pull, which causes the object to start moving or to change its motion.

Energy is the ability to do work and can take many forms, such as thermal, kinetic, potential, and chemical energy. Energy can be transformed from one form to another and can also be transferred from one object to another.

Therefore, In the case of an object being put into motion, energy is coming from the potential energy of the object. Potential energy is the energy an object possesses due to its position or configuration. This energy is transferred to the object by an external force, such as gravity, which causes the object to start moving or to change its motion.

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\(=3h\ x\ \frac{60 \min}{1h }\ x\ \frac{60\ sec}{1\ min}\)

\(=10800\ sec\)

Set up your equation so that your units cancel until you get to the unit you want. Hours and hours would cancel, and min and min would cancel, leaving you with sec which is the unit you want.

Remember: they can only cancel if one is on top and the other is on the bottom.

Answer:

1hr=60minutes

1min=60 seconds

then we have to convert 3hrs into seconds

now,

3*60*60=10,800

Eocell represents the electromotive force or cell potential of an electrochemical cell. It is calculated by subtracting the initial potential of the anode (Eoinitial) from the final potential of the cathode (Eofinal).

An electrochemical cell is made up of two half-cells, which are connected by a wire and a salt bridge. The anode and cathode are the sites of oxidation and reduction reactions, respectively. During these reactions, electrons flow from the anode to the cathode, producing a potential difference between the two half-cells. This potential difference is measured in volts and is known as the cell potential or Eocell.
To calculate Eocell, the potential of the anode (Eoinitial) and the potential of the cathode (Eofinal) are measured. The potential difference between the two is then calculated by subtracting Eoinitial from Eofinal. The resulting value gives us the cell potential or Eocell.
In summary, Eocell is the measure of the cell potential of an electrochemical cell and is calculated by subtracting the potential of the anode from the potential of the cathode.

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The two quantities in this module for which we will develop unit factors to do dimensional analysis with chemical substances are mass (m) and volume (V).

To calculate the unit factor, we need to divide the unit of the desired quantity by the unit of the given quantity. For example, to convert from mass to volume, the unit factor is V/m.

This unit factor can then be used to convert mass to volume or vice versa. Dimensional analysis helps us to determine the proper units for a given equation and to convert from one unit to another.

It also allows us to compare different units of measurement and to check that the units in both sides of an equation match. This is especially useful in chemical calculations, where it is important to ensure the correct units are used.

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Answer:

d) 1.8 atm

Explanation:

According to Boyle's Law,

Here, we are given :

Solving

The statement "The sum of the stoichiometric coefficients on each side of a balanced equation must be equal" is FALSE.

In a balanced equation, the stoichiometric coefficients ensure that the number of atoms of each element is equal on both sides of the equation, not necessarily the sum of the coefficients themselves. This is because the coefficients represent the relative amounts of reactants and products in a chemical reaction, ensuring the conservation of mass. Hence, the given statement is false.

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Answer:

Therefore, 1.00 mole of the gas is present in the container.

Explanation:

The following data were obtained from the question:

Volume (V) = 22.41L

Temperature (T) = 273K

Pressure (P) = 101.325 kPa

Gas constant (R) = 8.31 L.kPa/mol.K.

Number of mole (n) =...?

The number of mole of the gas in the container can obtained by applying the ideal gas equation as illustrated below:

PV = nRT

Divide both side by RT

n = PV /RT

n =101.325  x 22.41 / 8.31 x 273

n = 1.00 mole.

Therefore, 1.00 mole of the gas is present in the container.

Answer:

1 mole of gas is contained in 22.41 liters at 101.325 kPa and 0ᴼC

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

Replacing:

1 atm*22.41 L=n* 0.082 \(\frac{atm*L}{mol*K}\)*273 K

Solving:

\(n=\frac{1 atm*22.41 L}{0.082\frac{atm*L}{mol*K} *273 K}\)

n=1  mole

1 mole of gas is contained in 22.41 liters at 101.325 kPa and 0ᴼC

The rate law for the given reaction is Rate = 0.208[A], where the reaction is first-order and the rate constant (k) is 0.208 h⁻¹.

The rate law for the reaction is: Rate = k[A]
1. Since you are given that when ln[A] is plotted against time, a straight line with a slope of -0.208 h⁻¹ is obtained, we can infer that the reaction is a first-order reaction.

This is because a first-order reaction follows the integrated rate law equation: ln[A] = -kt + ln[A₀], where k is the rate constant, t is the time, and [A₀] is the initial concentration of A.
2. The slope of the straight line obtained is equal to the negative of the rate constant (k). In this case, the slope is -0.208 h⁻¹. So, k = 0.208 h⁻¹.
3. Now that we have determined the reaction to be first-order and found the rate constant (k), we can write the rate law for the reaction: Rate = k[A]. Since k = 0.208 h⁻¹, the rate law becomes: Rate = 0.208[A].
The rate law for the given reaction is Rate = 0.208[A], where the reaction is first-order and the rate constant (k) is 0.208 h⁻¹.

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Approximately 81637 Joules (or 81.637 kJ) of heat is needed to convert 230.0 g of ice at -10ºC to water at 0ºC.

To calculate the amount of heat needed to convert ice at -10ºC to water at 0ºC, we need to consider two separate processes:

1. Heating the ice from -10ºC to 0ºC without phase change.

2. Melting the ice at 0ºC to water at 0ºC.

Let's calculate each step:

1. Heating the ice from -10ºC to 0ºC (no phase change)

The specific heat capacity of ice (c) is approximately 2.09 J/g·°C.

The formula to calculate the heat (q) required to change the temperature of a substance is:

q = m * c * ΔT

Where:

q is the heat (in joules)

m is the mass of the substance (in grams)

c is the specific heat capacity (in J/g·°C)

ΔT is the change in temperature (in °C)

Substituting the values:

m = 230.0 g

c = 2.09 J/g·°C

ΔT = (0°C) - (-10°C) = 10°C

q1 = 230.0 g * 2.09 J/g·°C * 10°C

q1 ≈ 4817 J

2. Melting the ice at 0ºC to water at 0ºC

The heat of fusion for water (ΔH_fusion) is approximately 334 J/g.

The formula to calculate the heat (q) required for a phase change is:

q = m * ΔH_fusion

Substituting the values:

m = 230.0 g

ΔH_fusion = 334 J/g

q2 = 230.0 g * 334 J/g

q2 ≈ 76820 J

Now, to calculate the total amount of heat needed, we sum up the heat from both steps:

Total heat = q1 + q2

Total heat ≈ 4817 J + 76820 J

Total heat ≈ 81637 J

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Answer:

inside cells are removed

The final temperature of the mixture when no heat loss to the surroundings is equal to 69.57 °C

The specific heat capacity can be defined as the amount of heat required to increase the temperature in 1 unit of substance by 1° Celcius.

The specific heat capacity can be expressed in the form of the mentioned formula below:

Q = mSΔT

The specific heat capacity of the water, S = 4.184 J/g°C

The heat lost by water = heat gained by the ice

Heat lost by water = heat gained by the ice + heat increased by the water

m₁S₁ (T₂ - T₁) = m₂L + m₂S₂ (T₂ - T₁)

103.5 × 4.18 × (73- T) = 13.1  × (2.03) + 5 × 4.18 × (T-0)

31582 - 432.63 T = 26.59 + 20.9 T

453.53 T = 31555

T = 69.57 °C

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Answer:

A. The gas particles have strong attraction for one another.

Explanation:

The gas particles have a large volume and weak attraction for one another. To correct this statement and make it true, it should be: "The gas particles have a small volume and weak attraction for one another." Gases have large volume, and low density and the particles in a gas are far apart from one another and have very weak attractive forces between them.

Answer: B. The gas particles have almost no

volume.

Explanation:

Answer:

0.645 liters

Explanation:

THE QUESTION IS equivalent 0.645 Liters

The boiling point of an aqueous solution that has enough magnesium chloride added to create a 1. 0 molal solution is 100. 7°C.

An aqueous solution is a mixture of two or more substances in which water is the solvent. The substances can be ions, molecules, or larger particles that are dissolved in the water. The solution can be composed of a single type of particle, such as a solution of salt in water, or it can contain multiple types of particles, such as a solution of sugar and salt in water. Aqueous solutions are very common in everyday life, such as in the preparation of drinks and food, in cleaning, in pharmaceutical products, industrial processes, and in nature.

This is calculated by multiplying the van't Hoff factor (2. 7) by the boiling point elevation constant (Kpwater = 0. 52°C/mole) to get 1. 404°C/mole. Then, multiplying the 1. 404°C/mole by 1 mol of MgCl2 yields 100. 7°C.

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Answer:

D. The amount of nitrogen dioxide and sulfur dioxide would increase.

Explanation:

Because the reaction is exothermic, heat is a product. According to Le Chaetelier's Principle, a system in equilibrium will adjust itself so as to relieve any stress placed upon it. If the temperature of the system increases, there are more products, and therefore the system is no longer at equilibrium. Thus, it will shift to favor the reactant side of the equation, where sulfur dioxide and nitrogen dioxide are located. This makes the answer D.

Edit: Brainly thinks that the correct spelling of 'Le Chaetelier' is a bad word so that's why it is spelled wrong lol.

Answer:

Iodine

Explanation:

Hope this helps. Think about me, when giving out brainiest.

Answer:

Igneous rocks must go through the sedimentary process to change into metamorphic rocks. Igneous rocks are chemically changed into metamorphic rocks because of high temperature and pressure. Metamorphic rocks are formed from melting igneous rocks. Metamorphic rocks and igneous rocks do not follow a rock cycle.

Explanation:

hope this helps!

Answer:

C

Explanation:

It's igneous rocks must go through the sedimentary process answer thing

The pH of the aqueous solution that is the mixture of 0.10 M NaNO₂ and 0.20 M Ca(NO₂)₂ is 2.52.

To calculate the pH of the given aqueous solution, we need to first determine the concentration of HNO₂ in the solution. HNO₂ is a weak acid, and its Ka value is given as 4.5 x 10⁻⁴. We can write the dissociation reaction of HNO₂ as:

HNO₂ + H₂O ⇌ H₃O⁺ + NO₂⁻

The equilibrium constant expression for this reaction can be written as:

Ka = [H₃O⁺][NO₂⁻] / [HNO₂]

Assuming that the initial concentration of HNO₂ is negligible compared to the equilibrium concentration, we can simplify the expression as:

Ka = [H₃O⁺]² / [HNO₂]

Solving for [H₃O⁺], we get:

[H₃O⁺] = √(Ka * [HNO₂]) = √(4.5 *10⁻⁴ * 0.10) = 0.015

Now, we can use the concentration of Ca(NO₂)₂ to calculate the concentration of NO₂⁻ in the solution. Ca(NO₂)₂ dissociates into Ca²⁺ and 2NO₂⁻. Since NO₂⁻ is the conjugate base of HNO₂, it can react with H₃O⁺ to form HNO₂ and H₂O. This reaction can be written as:

NO₂⁻ + H₃O⁺ ⇌ HNO₂ + H₂O

The equilibrium constant expression for this reaction can be written as:

Kb = [HNO₂][H₂O] / [NO₂⁻][H₃O⁺]

Since Kb for NO₂⁻ is related to Ka for HNO₂ as:

Ka x Kb = Kw = 1.0 * 10⁻¹⁴

We can use this relation to calculate Kb for NO₂⁻ as:

Kb = Kw / Ka = 1.0 x 10⁻¹⁴ / 4.5 x 10⁻⁴ = 2.22 x 10⁻¹¹

Assuming that the initial concentration of NO₂⁻ is negligible compared to the equilibrium concentration, we can simplify the expression for Kb as:

Kb = [HNO₂][H₂O] / [NO₂⁻]

Solving for [HNO₂], we get:

[HNO₂] = Kb * [NO₂⁻] / [H₂O] = 2.22 * 10⁻¹¹ * (2 * 0.20) / 55.5 = 1.59 * 10⁻¹²

Now, we can use the concentrations of HNO₂ and NO₂⁻ to calculate the pH of the solution using the equation:

pH = -log[H₃O⁺] = -log(√(Ka x [HNO₂] / [NO₂⁻])) = -log(√(4.5 x 10⁻⁴ x 0.10 / (2 x 0.20))) = 2.52

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Answer T

Explanation:

Answer:

The things that are changing in an experiment are called variables. A variable is any factor, trait, or condition that can exist in differing amounts or types.

Answer:

Ca2+ represents an ion with 20 protons and 18 electrons.

Explanation:

A calcium atom has 20 protons and 20 electrons. The 2+ charge next to the symbol indicates a loss of two electrons: 20-2=18.

Answer:

D.NaOH

Explanation:

The compound that contains both ionic and covalent bonds from the given choices is NaOH, sodium hydroxide.

An ionic bond is formed between a metal and non-metal. In this compound, the metal is the Na and non - metal is the OH. To form this bond type, an atom transfers its electrons to the non-metal to attain stability.

The radical group OH⁻ which acts as a single unit is made up of a covalent bond. It involves the sharing of electrons between two non-metals whose electronegativity difference is very similar to one another.

When electrons are shared between two atoms, they make a bond called a covalent bond. Let us illustrate a covalent bond by using H atoms, with the understanding that H atoms need only two electrons to fill the 1s subshell.

The approximate resistance value at 45 degrees Celsius is around 5.8 ohms.

To calculate the value of the resistance temperature coefficient at 45 degrees Celsius using linear approximation, we can use the formula:

R(T) = R0 + α(T - T0),

where R(T) is the resistance at temperature T, R0 is the resistance at a reference temperature T0, α is the resistance temperature coefficient, and (T - T0) is the temperature difference.

Given that the resistance at 25 degrees Celsius is 5 ohms (R0 = 5) and the resistance at 50 degrees Celsius is 6 ohms (R(T) = 6), we can calculate the value of α.

6 = 5 + α(50 - 25),

Simplifying the equation:

1 = 25α,

Therefore, α = 1/25 = 0.04 ohm/degree Celsius.

Using the linear approximation, we can approximate the value of the resistance at 45 degrees Celsius:

R(45) = 5 + 0.04(45 - 25) = 5 + 0.04(20) = 5 + 0.8 = 5.8 ohms.

Therefore, the value of the resistance at 45 degrees Celsius is approximately 5.8 ohms.

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C Cl is a covalently bonded compound with the formula CCl₄. MgCl is an ionic compound with the formula MgCl₂.

The formation of a chemical bond between two or more atoms, ions or molecules to form a chemical compound is known as chemical bonding. The chemical bonding makes sure the atoms are together in the resulting compound.

Chemical bonding is made possible by an attractive force resulting from the overall loss of energy in the resultant molecule compared to its constituents.

Chemical compounds depend on chemical bonding for their stability. There are various kinds of chemical bonds formed. Covalent bonds and ionic bonds are 2 of the most commonly known chemical bonds.

Covalent bonds are formed by the sharing of electrons and an ionic bond is formed by the electrostatic force of attraction between the atoms.

Therefore, in the given examples, C Cl is a covalently bonded compound with the formula CCl₄. MgCl is an ionic compound with the formula MgCl₂.

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The bond of the following atoms in C-Cl and Mg-Cl is polar covalent bond in C-Cl  and  Mg-Cl ionic bond.

Polar covalent bonds are created between two non-metal atoms or molecules  that do consist of different  electronegativity. and the electronegativity difference that is not equal to zero and the shared pair of electrons forming a bond between will always be towards the high electronegative atom.

An ionic bond the  complete sharing or the  electron transfer. Ionic bonds basically form or created when the difference in the electronegativity of the two atoms is great or more as compare to   covalent bonds form when the electronegativity is same.

Therefore,  bond of the following atoms in C-Cl and Mg-Cl is polar covalent bond in C-Cl  and  Mg-Cl ionic bond.

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The enthalpy change per mole of the substance is approximately 967.8 kJ/mol.

To calculate the enthalpy change per mole of the substance, we need to use the given information: mass of the substance, molecular weight, and heat produced. Here are the steps:
1. Determine the number of moles of the substance combusted:
Number of moles =\frac{ mass }{molecular weight}
Number of moles = \frac{72.476 g }{183.031 g/mol}
Number of moles ≈ 0.396 mol
2. Calculate the enthalpy change per mole:
Enthalpy change per mole = \frac{heat produced }{ number of moles}
Enthalpy change per mole =\frac{ 383.35 kJ }{ 0.396 mol}
Enthalpy change per mole ≈ 967.8 kJ/mol

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