The melting of methane hydrates on the seafloor can lead to a sharp rise in global temperatures because methane is a powerful greenhouse gas (true or false)

The dark lines in an absorption spectrum indicate that certain frequencies or wavelengths of light have been absorbed by the material that the light has passed through. Absorption occurs when an atom or molecule in the material absorbs a photon of a particular frequency, causing the electron in the atom or molecule to move to a higher energy level.

When white light is passed through a sample of a material, some of the frequencies of light are absorbed by the atoms or molecules in the material, causing dark lines to appear in the spectrum. The positions and intensities of these lines depend on the composition of the material and the conditions under which it is observed.

Absorption spectra are used in a wide range of fields, including astronomy, chemistry, and physics, to identify the composition of materials and study their properties. The dark lines in an absorption spectrum are sometimes called absorption lines or Fraunhofer lines, after the German physicist Joseph von Fraunhofer, who first discovered them in the 19th century.

The dark lines in an absorption spectrum indicate the wavelengths that have been absorbed by the substance.What is an absorption spectrum?An absorption spectrum is a graph that demonstrates the amount of light that is absorbed by a material as a function of wavelength. The graph depicts the amount of light that a sample absorbs at specific wavelengths. An absorption spectrum is created when a source of light is transmitted through a material, and certain wavelengths are absorbed and blocked by the material while others are not. The absorbed wavelengths appear as dark lines, whereas the non-absorbed wavelengths appear as bright lines on the graph. Absorption spectra are used to detect the presence of specific materials, as different substances absorb different wavelengths of light.

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In order to answer the question about how far a sound wave moves before the microphone first detects a minimum in the sound intensity, we need to use the formula for sound intensity and the properties of sound waves. The sound intensity formula is given by: I = P / A .

where I is the sound intensity, P is the sound power, and A is the area through which the sound wave is passing. The properties of sound waves include wavelength, frequency, and velocity. The distance traveled by a sound wave before the microphone first detects a minimum in the sound intensity depends on the wavelength of the sound wave and the distance from the sound source to the microphone.

Specifically, the distance traveled is equal to half of the wave length. Based on this information, we can use the following formula to find the distance traveled by a sound wave before the microphone first detects a minimum in the sound intensity: d = λ/2 where d is the distance traveled, and λ is the wavelength of the sound wave. Therefore, the answer to the question is that the distance traveled by the sound wave before the microphone first detects a minimum in the sound intensity is equal to half of the wavelength. The appropriate units for this answer are meters (m), which is the SI unit of length.

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Voyager 2 passed closer to the southern magnetic pole of Uranus.

During its flyby of Uranus in 1986. This was determined by the measurements taken by the spacecraft's instruments, which detected the magnetic field of Uranus and allowed scientists to map its magnetic structure.

The spacecraft's trajectory and the data collected indicated that Voyager 2 passed nearer to the southern magnetic pole than the northern one. This encounter provided valuable insights into the magnetic field and overall magnetosphere of Uranus, contributing to our understanding of the planet's unique characteristics and the dynamics of its magnetic environment.

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Answer:

work done = mgh

350×10×2

7000J

The work done by the forklift truck as it lifts the box to the given height is 6860J.

Work is simply referred to as the displacement of an object when a push or pull force is applied to the object. It is the energy transferred from or to an object when force is applied to it along a displacement.

It is expressed as;

W = F × s

Where F is force and s is displacement

Given the data in the question;

We substitute our given values into the expression above.

W = F × s

But F = Weight = mass × acceleration due to gravity = mg

acceleration due to gravity ( g = 9.8m/s²)

Hence,

W = mg × s

W = 350kg × 9.8m/s² × 2m

W = 6860kgm²/s²

W =  6860J

Therefore, the work done by the forklift truck as it lifts the box to the given height is 6860J.

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Electrical forces between charges are normally strongest when the charges are close together.

The repulsive or attractive interplay among any charged bodies is known as an electric-powered force. just like any pressure, its effect and effects on the given frame are defined by means of Newton's laws of motion. the electric force is one of the diverse forces that act on gadgets.

Electric-powered force is the attractive pressure between the electrons and the nucleus. Now, a nice price or a bad price creates a field inside the empty space around it, and we call that empty area an electric field. electrical forces result from mutual interactions between prices. In situations involving three or greater expenses, the electric force on a single charge is merely the result of the blended results of every character fee interplay of that price with all different charges.

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The work done by Man = 963.45  - 413.4

The work done by the woman = 550 ft.lb

To calculate the work done by the woman and by the man as each dives from the boat.

we use, conservation of momentum:

if a woman dives first,

120 ( 16 - v) = ( 180 + 600)v

1920 - 120 v = 780 v

v1 = 2.133 ft/sec

so,

velocity of woman = 16 - 2.133 = 13.866 ft/sec

so,

work done = energy

work done = 1/2 * (120 / 32.2) 13.8662 + 1/2 * (600 + 180 / 32.2) 2.1332

work done = 413.4 ft. lb  ( this is work done by a woman)

Now if man dives first:

(600 + 180)v1 = - 600 v2 + 180 ( 16 - v2)

780 v1 =  -600 v2 + 2880 - 180 v2

780 v1 = -780 v2 + 2880

v2 = 2880 + 780v1 / 780

v2 = 2880 + 780 * 2.133 / 780

v2 = 5.825 ft/s

The velocity of man = 10.17 ft/sec

so,

total K.E = 1/2 *( (120 / 32.2) 13.8662 + 1/2 * (180 / 32.2) 10.172 + 1/2 * ( 600 /32.2) 5.8252

K.E = 963.45 J

therefore,

work done by Man = 963.45  - 413.4

work done by Woman = 550 ft.lb

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Higher frequency waves have higher energy, larger amplitude waves have higher energy, and shorter wavelength waves have higher energy. These relationships can be observed across various types of waves.

The relationships between wave properties (such as frequency, amplitude, and wavelength) and energy can be understood through the concept of the wave equation, which states that the energy of a wave is directly proportional to its frequency and amplitude.

1. Frequency: Frequency refers to the number of complete oscillations or cycles a wave completes in one second. It is measured in hertz (Hz). The relationship between frequency and energy is that higher frequency waves have higher energy, while lower frequency waves have lower energy. For example, in the electromagnetic spectrum, gamma rays have a higher frequency and higher energy than radio waves.

2. Amplitude: Amplitude refers to the maximum displacement or height of a wave from its rest position. It is a measure of the wave's intensity or strength. The relationship between amplitude and energy is that waves with larger amplitudes have higher energy, while waves with smaller amplitudes have lower energy. For example, a larger amplitude sound wave will have a louder volume compared to a smaller amplitude wave.

3. Wavelength: Wavelength refers to the distance between two consecutive points on a wave that are in phase, such as two peaks or two troughs. It is usually represented by the Greek letter lambda (λ) and is measured in meters. The relationship between wavelength and energy is inverse: shorter wavelength waves have higher energy, while longer wavelength waves have lower energy. For example, ultraviolet light has a shorter wavelength and higher energy than infrared light.

In summary, the relationships between wave properties and energy can be understood as follows: higher frequency waves have higher energy, larger amplitude waves have higher energy, and shorter wavelength waves have higher energy. These relationships can be observed across various types of waves, such as electromagnetic waves (light), sound waves, and water waves.

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The answer is E. recombination.

Recombination refers to the process of combining existing ideas or concepts in new and unique ways to create complex ideas.

This process involves taking previously learned information and combining it with other information to form new insights or perspectives. By recombining ideas, individuals are able to develop more complex thoughts and ideas that are not limited to their existing knowledge base.

This process is critical for creativity and problem-solving, as it allows individuals to approach challenges from different angles and generate innovative solutions. Additionally, recombination can lead to the development of new fields or areas of study, as individuals combine existing concepts to create entirely new disciplines.

Overall, the process of recombination plays a fundamental role in human cognition, allowing individuals to generate complex and novel ideas that can shape the course of history.

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Answer:Hetero

Explanation: Honestly, same as the last guy said

The Ideal gas law is given by the formula PV = nRT. Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

The law explains the relationship between temperature, pressure, volume, and the number of moles of gas for an ideal gas. This law is also known as Boyle’s law and was discovered in 1662.

Avogadro’s Law is also called the Avogadro’s hypothesis. This law is expressed as V = kN, where V is the volume, k is a constant, and N is the number of molecules.

This law is expressed as\(V/T = k or V1/T1 = V2/T2.\)

This law was discovered in 1787 by Jacques Charles.

The solution to the problem is given below:

Initial conditions for tank A:

Mass of CO2 = 3 kg

Temperature of CO2 = 27°C = 27 + 273 = 300 K

Pressure of CO2 = 300 kPa

Volume of CO2 = unknown Initial conditions for tank B:

Mass of N2 = unknown Temperature of N2 = 50°C = 50 + 273 = 323 K Pressure of N2 = 500 kPa V

olume of N2 = 4 m3

Final conditions for tank A and B:

Volume of CO2 + Volume of N2 = total volume of mixture Pressure of CO2 = Pressure of N2 = final pressure of the mixture Temperature of CO2 = Temperature of N2 = final temperature of the mixture = 25°C = 25 + 273 = 298 K

Let’s find the number of moles of CO2 from the initial conditions of tank A.

Number of moles of CO2 = Mass of CO2/Molar mass of CO2Molar mass of CO2 = 44 g/mo

lNumber of moles of CO2 = 3,000/44 = 68.18 moles

The Ideal gas law formula is PV = nRTNumber of moles of N2 can be found using Avogadro’s law.
Volume of N2 = 4 m3Volume of CO2 + Volume of N2 = total volume of mixture

Volume of CO2 = total volume of mixture - volume of N2Substituting the values,

we get Volume of CO2 = V = 6 m3 Let’s calculate the initial pressure of CO2 using the Ideal gas law.

\(PV = nRTP × V = n × R × TP = nRT/V\)

we get P = \((68.18 × 8.314 × 300)/6P = 1372.03 kPa\)

Let’s calculate the initial number of moles of N2 using Charles’ law.V1/T1 \(= V2/T2V1/V2 = T1/T2\)

we get (4/V2) = (323/298)

Solving for V2, we get V2 = 3.7 m3Let’s calculate the number of moles of N2 using Avogadro’s law.

\(N1/V1 = N2/V2N2 = (N1 × V2)/V1\)

we getN2 =\((68.18 × 3.7)/6N2 = 42.12 moles\)

The total number of moles of gas in the mixture is the sum of the number of moles of CO2 and N2.N = 68.18 + 42.12N = 110.3 moles

we can find the final pressure of the mixture.

\(PV = nRTP × V = n × R × TP = nRT/V\)

we getP =\((110.3 × 8.314 × 298)/(6 + 3.7)P = 845.72 kPa\)

The final pressure of the mixture is 845.72 kPa.

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Part A:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

The tangential acceleration of a point at the start (αₓ) =

= αₓ = αₐ × r

= αₓ = 0.200 × 0.600

= αₓ = 0.12 m/s²

Part B:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Angular speed = ω = 0 m/s²

Magnitude of radial acceleration of a point on rim at the start (αₙ)=

= (angular speed)² × r

= 0 × 0.600

= 0 m/s²

Part C:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Resultant acceleration of a point on the rim at the start =

= α =√(αₙ² + αₓ²)

= α = √ (0² + 0.12²)

= α = 0.12 m/s²

Part D:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Angular speed = ω = 0 m/s²

The tangential acceleration of a point after 60° turn (αₓ₁) = The tangential acceleration of a point at the start (αₓ)

= αₓ₁ = αₐ × r

= αₓ₁ = 0.200 × 0.600

= αₓ₁ =  0.12 m/s²

Part E:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Angular speed = ω = 0 m/s²

Angular speed after 60° turn = ω₁ = √(ω² + (2×α×θ))

To find θ,

= θ = 60Π / 180

= θ = Π/30

= θ = 1.04 rad

Thus, ω₁ = √(0 + 2 × 1.04 × 0.2)

= ω₁ = 0.644 rad/s

The radial acceleration of a point after 60° turn (αₓ₂) =

= αₓ₂ = r × ω₁²

= αₓ₂ = 0.600 × 0.644²

= αₓ₂ = 0.248 m/s²

Part F:

Radius of flywheel = 0.600 m

The tangential acceleration of a point after 60° turn (αₓ₁) = 0.12 m/s²

The radial acceleration of a point after 60° turn (αₓ₂) = 0.248 m/s²

The magnitude of resultant acceleration of a point on the rim after 60° turn (α₃) =

= α₃ = √ (αₓ₂² + αₓ₁²)

= α₃ = √ (0.12² + 0.248²)

= α₃ = 0.275 m/s²

Part G:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Angular speed = ω = 0 m/s²

The tangential acceleration of a point after 120° turn (αₓ₁) = The tangential acceleration of a point at the start (αₓ)

= αₓ₁ = αₐ × r

= αₓ₁ = 0.200 × 0.600

= αₓ₁ =  0.12 m/s²

Part H:

Radius of flywheel = 0.600 m

Angular acceleration of flywheel (αₐ) = 0.200 rad/s²

Angular speed = ω = 0 m/s²

Angular speed after 120° turn = ω₁ = √(ω² + (2×α×θ))

To find θ,

= θ = 120Π / 180

= θ = 2Π/3

= θ = 2.09 rad

Thus, ω₁ = √(0 + 2 × 2.09 × 0.2)

= ω₁ = 0.836 rad/s

The radial acceleration of a point after 120° turn (αₓ₂) =

= αₓ₂ = r × ω₁²

= αₓ₂ = 0.600 × 0.836²

= αₓ₂ = 0.502 m/s²

Part I:

Radius of flywheel = 0.600 m

The tangential acceleration of a point after 120° turn (αₓ₁) = 0.12 m/s²

The radial acceleration of a point after 120° turn (αₓ₂) = 0.502 m/s²

The magnitude of resultant acceleration of a point on the rim after 120° turn (α₃) =

= α₃ = √ (αₓ₂² + αₓ₁²)

= α₃ = √ (0.12² + 0.502²)

= α₃ = 0.515 m/s²

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The arrow we draw for Bi should be pointing out of the page.When two infinitely long wires carrying current are perpendicular to each other, a magnetic field is produced. In this case, we are given that one wire carries a current of Ij = 250 mA, and the other carries a current of 12 = 120 mA.

We need to draw an arrow on the diagram to represent the direction of the magnetic field at point P due to current Ij.

To do this, we can use the right-hand rule. We place our right hand with our fingers pointing in the direction of the current Ij, and our thumb will point in the direction of the magnetic field at point P. The arrow we draw should represent this direction and be labeled Bi.

Using this method, we can determine that the magnetic field produced by Ij will be perpendicular to the page and point out of the page. This is because the current is flowing towards us from the page, so the magnetic field will be in the opposite direction. Therefore, the arrow we draw for Bi should be pointing out of the page.

In summary, when two perpendicular wires carrying current are present, we can determine the direction of the magnetic field at a point using the right-hand rule. In this case, the magnetic field produced by Ij will be perpendicular to the page and point out of the page.

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Answer:

The work done by the engine is 50 J.

Explanation:

Given;

amount of heat energy added to the heat engine, Q = 75 J

energy lost in the process, E = 50 J

let the work done by the engine (system) = W

Apply the first law of thermodynamic;

ΔU = Q - W

where;

ΔU is change in internal energy = 75 J - 50 J = 25 J

25 = 75 - W

25 - 75 = - W

-50 J = - W

W = 50 J

Therefore, the work done by the engine is 50 J.

Disequilibrium occurs when the quantity of supply does not equal the quantity of demand.

The market is experiencing a disequilibrium when the market price is above or below the equilibrium price. Whenever markets experience imbalances—it creates disequilibrium prices, surpluses, and shortages—market forces drive prices toward equilibrium.

A surplus exists when the price is above equilibrium, which encourages sellers to lower their prices to eliminate the surplus.

A shortage will exist at any price below equilibrium, which leads to the price of the good increasing.

For example, imagine the price of dragon repellent is currently $6 per can. People only want to buy 400 cans of dragon repellent, but the sellers are willing to sell 600 cans at that price. This creates a surplus because there are unsold units. Sellers will lower their prices to attract buyers for their unsold cans of dragon repellant.

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Answer:

C

Explanation:

The base of the lightbulb should touch the positive end and also the negative end of the battery.

To determine the distance spanned by the diffraction spot, we need to consider the properties of the diffraction pattern and the given information.

Given:

- The screen is 30 cm behind the fish.

- The entire path of the laser, including the water and tissue, has an index of refraction close to that of water.

- The properties of the diffraction pattern are determined by the wavelength in water.

Since the diffraction pattern is formed by the interaction of light waves with obstacles or apertures, the spot's size or spread depends on factors such as the wavelength of light and the size of the aperture.

Without specific information about the wavelength or aperture size, it is not possible to determine the exact distance spanned by the diffraction spot. Additional details regarding the specific setup or measurements would be necessary to calculate or estimate the distance spanned by the diffraction spot.

Please provide further information or clarify the parameters related to the diffraction setup if you require a more specific answer.

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Answer:

5.0 ohms is the answer

Explanation:

(why was my answer deleted????????)

Answer:

right to vote, the right to a fair trial, the right to government services, the right to a public education, and the right to use public facilities.

a) The block goes 7.4 m up the plane

b) It takes 1.62 seconds to get there

c) The speed at the bottom is -9.1 m/s

The initial speed, v₀ = 9.12 m/s

Angle of inclination, θ = 35°

Note that the summation forces on the block as it goes up the inclined plane is 0. That is, ΣF = 0

mgsinθ + ma = 0

mgsinθ = -ma

a = -gsinθ

The acceleration of the block up the plane is:

a = -9.8 sin 35

a = -5.62 m/s²

a) How far up the plane does it go?

Using the equation v² = v₀² + 2as

At the maximum distance up the plane, v = 0

0² = 9.12² + 2(-5.62)s

0 = 83.17 - 11.24s

11.24s = 83.17

s = 83.17/11.24

s = 7.4 m

The block goes 7.4 m up the plane

b) How long does it take to get there?

Using the equation v = v₀ + at

Since we want to calculate the time taken to reach the maximum distance, the speed at this point is 0. v = 0m/s

Substitute a = -5.62, v₀ = 9.12, and v = 0 into v = v₀ + at

0 = 9.12 + (-5.62)t

5.62t = 9.12

t = 9.12 / 5.62

t = 1.62 seconds

c) What is its speed when it gets back to the bottom?

The total time it takes the block to go up and down the plane = 2(1.62)

The total time it takes the block to go up and down the plane = 3.24 s

To calculate the speed of the block when it gets back to the bottom, use the equation v = v₀ + at

v = 9.12 + (-5.62)(3.24)

v = 9.12 - 18.21

v = -9.1 m/s

Human pathogens are typically mesophiles, which means they thrive in temperatures ranging from 20-45°C, the temperature range of the human body.

However, some human pathogens are also thermophiles, which means they prefer temperatures between 45-80°C, such as those found in hot springs. Hyperthermophiles, which thrive in temperatures above 80°C, are less commonly associated with human pathogens. Psychrophiles, which thrive in cold temperatures, and hypermesophiles, which thrive in even higher temperatures than mesophiles, are not commonly associated with human pathogens.

Human pathogens are mesophiles. Mesophiles are microorganisms that thrive at moderate temperatures, typically between 20°C and 45°C (68°F to 113°F). Most human pathogens fall into this category because the human body's average temperature is 37°C (98.6°F), creating an optimal environment for these microorganisms to grow and reproduce. In contrast, psychrophiles prefer cold environments, thermophiles prefer high temperatures, and hyperthermophiles thrive at extremely high temperatures. Hypermesophiles is not a recognized term in microbiology.

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Answer:

the density is 2

Explanation:

mass divided by volume is density

16 divided by 8 is 2

The x-component of the vector is -6.81. To find the x-component of a vector, we need to use trigonometry. First, we need to determine the angle between the vector and the x-axis. To do this, we subtract 73o from 90o (the angle between the negative y-axis and the x-axis) to get 17o.

Next, we use the cosine function to find the x-component:

cos(17o) = adjacent/hypotenuse

The adjacent side is the x-component, and the hypotenuse is the magnitude of the vector (27.0).

x-component = cos(17o) * 27.0

x-component = -6.81

Therefore, the x-component of the vector is -6.81.
To find the x-component of a vector, we use trigonometry and the cosine function. We first determine the angle between the vector and the x-axis by subtracting the angle between the negative y-axis and the x-axis from the angle given in the problem. Then, we use the cosine function with the angle and the magnitude of the vector to find the x-component. In this problem, the x-component of the vector with a magnitude of 27.0 directed at 73o counterclockwise from the negative y-axis is -6.81.

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In the earliest moments of the universe, shortly after the Big Bang, the universe was incredibly hot, dense, and filled with energy. At that time, all four fundamental forces of nature—the gravitational force, electromagnetic force, strong nuclear force.

As the universe expanded and cooled down, an event called cosmic inflation occurred. During this rapid expansion, the universe underwent a phase transition, causing it to expand exponentially within an extremely short period. This inflationary phase resulted in the uniformity and large-scale structure we observe in the universe today.

As the universe continued to cool down, it entered a phase known as the electroweak epoch. At this point, the strong nuclear force and the electroweak force were still combined. However, as the universe cooled further, the Higgs field, which is associated with the electroweak force, underwent a phase transition known as electroweak symmetry breaking. This led to the separation of the electromagnetic force from the weak nuclear force and the acquisition of mass by particles through their interactions with the Higgs field.

After the electroweak symmetry breaking, the universe entered the quark-gluon plasma phase, where particles called quarks and gluons roamed freely. As the universe cooled even more, the strong nuclear force, mediated by gluons, became confined within individual protons and neutrons. This confinement led to the formation of atomic nuclei during a period known as nucleosynthesis.

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Answer: accretion......

Answer:

Unlike most volcanoes and earthquakes, tsunamis are not direct consequences of plate tectonics. The most common tsunami trigger is submarine earthquakes, but they can also be set off by a volcanic eruption under, or next to, the sea. Thus volcanoes, earthquakes and tsunamis are part of the same story.

Explanation:

The charge on the point as it passes is 10τ, the charge on this point is 10τ(1-e-10), and the charge that passes this point is 10τ.

The charge that passes this point between t = 0 and t = τ can be calculated using the following equation:

Q(τ) = I0τ

Therefore, Q(τ) = I0τ = I0 × τ.

The charge that passes this point between t = 0 and t = 10τ can be calculated using the following equation:

Q(10τ) = I0τ(1-e-10)

Therefore, Q(10τ) = I0τ(1-e-10) = I0 × τ × (1-e-10).

The charge that passes this point between t = 0 and t = [infinity] can be calculated using the following equation: Q([infinity]) = I0τ

Therefore, Q([infinity]) = I0τ = I0 × τ.

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Answer:

v = 27.5 m/s

Explanation:

p = m × v

6,875 = 250 × v

250v = 6,875

v = 6,875/250

v = 27.5 m/s