The maximum range of projectle is R° if projected at angle of 45°. It'll be 300% of Range of projectile if projected at angle? a) 30° b) 45° c) 60° d) 76° Correct answer with good explanation

Answer:

ok what is the question

Explanation:

I don't know what the question is

The inductance (L) of the air-filled solenoid will be approximately 0.0329 henries (H).

To determine the inductance (L) of a 0.70-meter-long air-filled solenoid with a diameter of 2.8 cm containing 8500 loops, follow these steps:

1. Convert the diameter to meters: 2.8 cm = 0.028 m.
2. Calculate the solenoid's cross-sectional area (A) using the formula A = πr^2, where r is the radius (half of the diameter): A = π(0.014 m)^2 ≈ 0.00061575 m^2.
3. Determine the solenoid's length (l): 0.70 m.
4. Calculate the number of turns per unit length (n) by dividing the total number of loops (8500) by the solenoid's length (0.70 m): n = 8500 loops / 0.70 m ≈ 12142.86 turns/m.
5. Use the formula for inductance of an air-filled solenoid: L = (μ₀ * n^2 * A * l), where μ₀ is the permeability of free space (μ₀ ≈ 4π x 10^(-7) T·m/A).
6. Plug in the values: L = (4π x 10^(-7) T·m/A) * (12142.86 turns/m)^2 * 0.00061575 m^2 * 0.70 m ≈ 0.0329 H.

The inductance (L) of the air-filled solenoid is approximately 0.0329 henries (H).

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A one-time pad is a type of encryption that is completely unbreakable if it is done correctly. It works by generating a random key that is at least as long as the message being encrypted. The key is then combined with the message using an XOR operation.

This produces a ciphertext that cannot be decrypted without the key. The key is used only once and then discarded, hence the name "one-time pad". A one-time pad is completely unbreakable because there is no pattern to the key that can be used to decrypt the message. Each character in the key is generated randomly and independently of the other characters. Therefore, the key is completely unpredictable. Even if an attacker knows the key length and has access to the ciphertext, they cannot use any techniques to decrypt it.

This is because there is no pattern to the ciphertext that can be used to determine the key.The only way to decrypt a one-time pad is to have the key. If an attacker tries to brute-force the encryption by trying all possible keys, they will generate every possible message that is the same length as the original message. This means that the ciphertext is completely meaningless without the key. It is therefore important to keep the key secret and ensure that it is only used once. ,Message: yellow stone Key: wolf To encrypt the given message using the vigenere cipher, we follow the steps below:Step 1: Write the message and key in a tabular form as shown below. To keep the process organized, we use the letters of the key to label the columns.

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Answer:343m

Explanation:

Answer:

2.00

Explanation:

Answersdff:

Explanation:

Lengths of time it takes for new light bulbs to burn out are an example of quantitative data. Quantitative data refers to any information that can be expressed numerically or measured.

In this case, the lengths of time are numerical values that can be measured in hours, days, or any other unit of time. This data provides information about the lifespan or durability of the light bulbs. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends.

It is important to collect accurate and reliable data to ensure meaningful analysis. Quantitative data is often used in statistical analysis and can be used to draw conclusions, make predictions, or identify trends. In summary, the lengths of time it takes for new light bulbs to burn out represent quantitative data.

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The equation E = Eₘₐₓ cos(kx-ωt) is a solution to Equation 94.15, and the equation B = Bₘₐₓ cos(kx-ωt) is a solution to Equation 34.16.

Equation 94.15 represents the electric field (E) in an electromagnetic wave, while Equation 34.16 represents the magnetic field (B) in the same wave. These equations are known as the wave equations for electromagnetic fields.

In both equations, Eₘₐₓ and Bₘₐₓ represent the maximum amplitudes of the electric and magnetic fields, respectively. The variables k, x, ω, and t correspond to the wave number, position, angular frequency, and time, respectively.

By substituting these equations into Equations 94.15 and 34.16, we can verify if they satisfy the equations. When we substitute E = Eₘₐₓ cos(kx-ωt) into Equation 94.15, we get:

∂²E/∂x² - (1/c²) ∂²E/∂t² = 0

∂²(Eₘₐₓ cos(kx-ωt))/∂x² - (1/c²) ∂²(Eₘₐₓ cos(kx-ωt))/∂t² = 0

Expanding and simplifying the equation yields:

-Eₘₐₓ k² cos(kx-ωt) + (1/c²) Eₘₐₓ ω² cos(kx-ωt) = 0

Since cos(kx-ωt) is non-zero, we can cancel it out:

- Eₘₐₓ k² + (1/c²) Eₘₐₓ ω² = 0

Simplifying further:

- k² + (ω²/c²) = 0

Similarly, we can substitute B = Bₘₐₓ cos(kx-ωt) into Equation 34.16 and verify if it satisfies the equation. The process is similar to the one described above.

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The carousel is moving in a circular path. An outside force is acting on it which make the system accelerate and the force exerted by the railing of carousel cause the centripetal force.

The force which make an object moves through a curvature path is called centripetal force. Similar to other forces, centripetal force also assciated with an acceleration.

The centripetal force in terms of mass and velocity for a moving body is given as:

Fc = Mv²/r

where r is the radius of curvature.

According to the second law of motion, a force is made by the mass and acceleration in the body.

A carousel is moving through a circular path. The force acting on the rails of carousel make its movement through the curved path and the motion is associated with an acceleration.

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Giants are known to be large in radius because of various scientific studies and observations. Astronomers and astrophysicists use methods such as photometry and spectroscopy to analyze the physical properties of stars, including their size and temperature.

These studies have shown that giants are typically much larger in radius than main sequence stars, with radii that can be up to ten times larger than the radius of the Sun.

This increase in size is due to the fact that giants have evolved to a later stage in their life cycle, where they have exhausted the hydrogen fuel in their cores and have expanded and cooled as a result.

Additionally, observational studies of binary star systems have provided further evidence for the large size of giants, as the gravitational influence of the giant star on its companion can be used to measure its size and mass.

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The indirect method is used to determine total power in a parallel circuit through the following:

This involves the circuit which has branches and a portion of the total current flows through it as a result.

In determining the total power in a parallel circuit, the indirect method is used only if the parameters mentioned above are available.

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Answer:

BLACKPINK IN YOUR AREA MATH IS SO MUCH FUN

Explanation:

PERIOD AHH

The magnitude of ant's total displacement is 96.23 cm in a direction 41 degrees North of East.

The total displacement of the is obtained by resolving the displacement of the ant into x and y components as shown below.

horizontal displacement (x) = d cosθ

vertical displacement (y) = d sinθ

where;

First displacement at 50 cm East; (θ = 0⁰)

x = 50 cm x cos(0) = 50 cm

y = 50 cm x sin(0) = 0

second displacement at 40 cm at 35 degrees North of East;

(θ = 90⁰ - 35⁰ = 55⁰)

x = 40 cm x cos(55) = 22.94 cm

y = 40 cm x sin(55) = 32.77 cm

third displacement at 30 cm North; (θ = 90⁰)

x = 30 cm x cos(90) = 0

y = 30 cm x sin(90) = 30 cm

Net horizontal displacement;

∑x = 50 cm + 22.94 cm + 0 = 72.94 cm

Net vertical displacement;

∑y = 0cm + 32.77 cm + 30 cm = 62.77 cm

The total displacement is calculated as;

D = √[ (∑x)² + (∑y)² ]

D = √[ (72.94)² + (62.77)² ]

D = 96.23 cm

The direction of the total displacement;

θ = arc tan (Σy/Σx)

θ = arc tan (62.77/72.94)

θ =  40.7⁰ ≈ 41⁰

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Answer:

The DART mission proved to be successful. Its ultimate goal was to alter the trajectory of the asteroid Dimorphous. It was successful because the asteroid's trajectory was in fact altered. This mission is the first mission that intentionally altered the trajectory of a non man made object in space.

Mechanical waves can be classified as either transverse or longitudinal waves depending on the sort of motion they undergo. It should be noted that longitudinal and transverse waves can both be periodic.

The disruption of a transverse wave propagates perpendicular to the direction of propagation. Similar to sound waves, ocean waves also transport energy from one location to another. Through a medium, such as water or air, this energy moves. Additionally, this energy travels in a transverse wave, which is a repeating up-and-down motion. Echolocation is the process of using sound waves and their echoes to locate things in space. In the dark, bats use echolocation to navigate and locate food.

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Answer:

✏︎A. Matter made up of only one type of atom

Explanation:

✏︎An element is a pure substance which cannot be broken down by chemical means, consisting of atoms which have identical numbers of protons in their atomic nuclei. The number of protons in the nucleus is the defining property of an element, and is referred to as the atomic number.

Can you plz mark as brainliest

Answer:

Education is a human endeavor. it prepares the individual for life and for the future.

Explanation:

perhaps we can say that a "human endeavor" is one in which humans strive to achieve something of significance, or something of significance which only can be achieved via human intelligence.

Answer:

The correct answer is - distress.

Explanation:

Eustress is a type of stress that is beneficial to person and caused by adrenaline. Hypostress is a stress that is caused due to boredom or no work. It is stress comes with wasting the time.

Distress is the bad stress caused by anxiety, sadness, grief, and such type of stress that is caused irritability. Irritability is caused not just by stress but many factors.

The ultraviolet (UV) radiations in the stratosphere are primarily absorbed by a layer of gas called the ozone layer.

The ozone (O3) molecules in the ozone layer have the ability to absorb UV radiation, particularly in the UV-C and most of the UV-B regions of the electromagnetic spectrum. When UV radiation interacts with ozone molecules, it can cause the breaking and reformation of ozone bonds, resulting in the absorption of UV energy.

This absorption process is important because it prevents a significant amount of UV radiation from reaching the Earth's surface. It acts as a protective shield against harmful UV rays that can have detrimental effects on living organisms, including increased risk of skin cancer, cataracts, and damage to marine ecosystems.

It's important to note that not all UV radiation is absorbed by the ozone layer. Some UV-B and a majority of UV-A radiation reach the Earth's surface, but they are less harmful compared to the shorter wavelength UV-C radiation that is almost entirely absorbed by the ozone layer.

Hence, The ultraviolet (UV) radiations in the stratosphere are primarily absorbed by a layer of gas called the ozone layer.

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Answer:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Liquid P - \(Q = 3840\,J\), Liquid Q - \(Q = 5500\,J\), Liquid R - \(Q = 7800\,J\), Liquid S - \(Q = 2856\,J\)

Explanation:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:

\(Q = m\cdot c\cdot (T_{r} - T_{f})\) (1)

Where:

\(m\) - Mass of the liquid, in kilograms.

\(c\) - Specific heat capacity, in joules per kilogram-degree Celsius.

\(T_{r}\) - Initial temperature of the sample, in degrees Celsius.

\(T_{f}\) - Freezing point, in degrees Celsius.

Liquid P (\(m = 1\,kg\), \(c = 160\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 6\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)\)

\(Q = 3840\,J\)

Liquid Q (\(m = 1\,kg\), \(c = 220\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 5\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)\)

\(Q = 5500\,J\)

Liquid R (\(m = 1\,kg\), \(c = 300\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 4\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)\)

\(Q = 7800\,J\)

Liquid S (\(m = 1\,kg\), \(c = 102\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 2\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)\)

\(Q = 2856\,J\)

A coin falls off a table and is traveling to the ground. There is a net force on the coin which is responsible for the motion of the coin. Thus, the correct option is A.

The net force can be defined as is the sum of all the forces which are acting on an object. Net force acting upon an object can accelerate its mass. Some other forces also acts on a body either at rest or motion. The net force is used in a system when there is a significant number of forces acting on the object.

A coin which falls off a table and is still traveling to the ground. Then, it can be concluded that there is a net force which is acting on that coin which is responsible for the motion of the coin.

Therefore, the correct option is A.

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 15 mL

density = 7.1 g/mL

We have

mass = 7.1 × 15

We have the final answer as

Hope this helps you

Initial velocity = 0 m/s

Displacement = 5 m

Acceleration = 10cos25° = 9.06 m/s^2

time = ? (To be calculated)

Using, S = ut + at^2/2, we have

5 = 0(t)+9.06t^2/2

10/9.06 = t^2

t = 1.006 seconds

The distance (in meters) of an object that has an angular diameter of 75 arcseconds and a linear diameter of 65 meters is 178762.96 meter.

As per the data given the angular diameter is of 75 arcseconds.

And the linear diameter is of 65 meters.

Angular diameter, \($\delta\) = 75 arcsecs.

Linear diameter, α = 65 meters

Here we have to determine the distance (in meters) of an object.

Distance D =?

We know that:

Linear diameter: The distance between the two specified sites or objects is the linear measurement.

Angular diameter: The apparent diameter of a planet or other celestial object as determined by the observational angle it assumes.

\(\delta=2 \arctan \left(\frac{d}{2 D}\right)\)

For the small angle approximations

\($ \left.\delta=\frac{d}{D}\)

\(& \delta\) = 75 ( 1 arcsec = 4.8481 \(\times 10^{-6}\) Radians)

\(& \delta\) = 75 × 4.8481 \(\times 10^{-6}\)  Radians

\(& \delta\) = 0.00036361 Radian

Hence distance can be calculated by:

D = \($\frac{d}{\delta} \\\)

D = \($\frac{65}{0.00036361} \\\)

D = 178762.96 meter

Therefore the distance (in meters) of an object is 178762.96 meters.

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Answer:

measure what

Explanation:

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Answer:

B. Mass

Explanation:

Answer:

hope this helps

Explanation:

Of the three phases of matter (gas, liquid, and solid), sound waves travel the slowest through gases, faster through liquids, and fastest through solids

so your answer would be B.

If the plates of a spherical capacitor have radii 38.0 mm and 40.0 mm then the capacitance is 1.03 × 10^-11 F and the plate area of a parallel-plate capacitor 20 mm square.

A capacitor is an electronic component that stores electrical energy in an electric field. It consists of two conductive plates separated by an insulating material, which is called a dielectric. The conductive plates are usually made of metal and the dielectric can be made of various materials such as paper, ceramic, plastic, or air.

To calculate the capacitance of a spherical capacitor with radii of 38.0 mm and 40.0 mm, we can use the formula:

C = 4πε₀ / (1/R₁ - 1/R₂)

where C is the capacitance, ε₀ is the permittivity of free space (8.85 × 10^-12 F/m), R₁ is the radius of the inner sphere (in meters), and R₂ is the radius of the outer sphere (in meters).

Converting the radii to meters, we have R₁ = 0.038 m and R₂ = 0.04 m. Plugging in these values, we get:

C = 4πε₀ / (1/0.038 - 1/0.04)

= 1.03 × 10^-11 F

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