The maximum ims voltage appears across the load of single-phase AC voltage regulator when the firing angle equal to a. 00 b. 1200 c.1800 d.90° a. 00 Ob. 1200 c.1800 d.900

Answer:

14.5° ; THD % = 3.873 × 100 = 387.3%.

Explanation:

Okay, in this question we are given the following parameters or data or information which is going to assist us in solving the question efficiently and they are;

(1). "500 VAR reactive power from 230 Vrms 50 Hz 1.5 KVAR reactor".

(2). Consideration of up to 12th harmonic.

So, let us delve right into the solution to the question above;

Step one: Calculate the Irms and Irms(12th) by using the formula for the equation below;

Irms = reactive power /Vrms = 500/230 = 2.174 A.

Irms(12th) = 1.5 × 10^3/ 12 × 230 = 0.543 A.

Step two: Calculate the THD.

Before the Calculation of the THD, there is the need to determine the value for the dissociation factor, h.

h = Irms(12th)/Irms = 0.543/ 2.174 = 0.25.

Thus, THD = [1/ (h)^2 - 1 ] ^1/2. = 3.873.

THD % = 3.873 × 100 = 387.3%.

Step four: angle AC - Ac converter

theta = sin^-1 (1.5 × 10^3/ 12 × 500) = 14.5°.

Answer:

A sand bed is necessary because it provides a refractory bottom for molten metal

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To calculate FTE (Full-Time Equivalent) for indoor water use, you typically need the following factors:

   The amount of water used in the baseline design case: This refers to the estimated amount of water that would be used by the building's occupants under normal operating conditions. This can be based on factors such as the number of occupants, their behavior, and the types of fixtures installed in the building.

   The flush and flow rates of fixtures: This refers to the rate at which water is used by various fixtures in the building, such as toilets, faucets, and showers. The flow rates can be measured in gallons per minute (GPM) or liters per minute (LPM), and the flush rates can be measured in gallons per flush (GPF) or liters per flush (LPF).

   The type of building occupant (full time, part time, transient): This refers to the nature of the building's occupants and their expected water usage patterns. For example, full-time occupants may use more water than part-time or transient occupants.

   Hours worked per week: This refers to the number of hours that the building's occupants are expected to be on site and using water. This factor can be used to estimate the amount of water used during different times of day and days of the week.

Building density is not typically a factor in calculating FTE for indoor water use, as it is more relevant for outdoor water use.

(i) The normal force exerted on the plate is 1368 N

(i)the work done per second on the plate and the efficiency is 0.051 or 5.1%.

The velocity of the water relative to the plate is found using vector subtraction:

Vw = \sqrt((Q/(\pid²/4))^2 + Vp^2 - 2(Vp)(Q/(\pid²/4))cos(30°)), where Q = 0.2388 m³/s, d = 0.225 m, and Vp = 1.5 m/s.

The change in momentum of the water in the normal direction per second is: Δp = 2Q(Vw*cos(30°)-Vp).

The normal force exerted on the plate is F = Δp = 1368 N (rounded to nearest integer).

The work done per second (power) is: P = F * Vp = 2052 W. The efficiency is the ratio of useful work done to the energy supplied by the water jet: η = P / (0.5 * Q * Vw²) = 0.051 or 5.1%.

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Answer:

What specific fluid goes in the windshield wipers.

Distilled water

How much to put in fluid ounces?

There should be a tiny bit more than 3/4 of the way full.

A comparator compares two voltages and produces an output signal based on the comparison. If the voltage on the data line is higher than the reference voltage, the comparator will output a 1.

What is Voltages?

If the voltage on the data line is lower than the reference voltage, the comparator will output a 0; if the voltage on the data line is equal to the reference voltage, the comparator will output an undetermined signal.

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The length of the chain of dislocations can be calculated by multiplying the volume of the crystal (3800 mm³) by the dislocation density. However, since the dislocation density is not given in the question, we cannot determine the exact distance covered by the chain in miles.

Dislocation density is typically expressed in terms of dislocations per unit area (e.g., dislocations per square meter). Without this crucial information, we are unable to perform the necessary calculations to determine the length of the chain in miles.

To obtain the distance in miles, we would need to convert the length obtained from the multiplication of volume and dislocation density from millimeters to miles using the conversion factor provided (1 m = 0.0006214 mile). However, since the dislocation density is missing, we cannot proceed with the calculation.

In conclusion, without the specific value for the dislocation density, we cannot determine the distance covered by the chain of dislocations in miles.

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(a) The required thickness to the nearest millimeter is approximately 196 mm

(b) The maximum permissible internal pressure for a tank wall thickness of 85 mm is approximately 1.68 MPa.

(a) To determine the required thickness to the nearest millimeter, we'll use the formula for the thickness of a pressure vessel:
t = (P * D) / (2 * S)
where:
t = thickness
P = internal pressure = 3.85 MPa
D = diameter = 20 m = 20,000 mm (converting to millimeters)
S = yield stress / factor of safety = 590 MPa / 3.0 = 196.67 MPa (rounded)
Now, we can plug in the values:
t = (3.85 * 20,000) / (2 * 196.67)
t = 77,000 / 393.34
t ≈ 195.66 mm
So, the required thickness to the nearest millimeter is approximately 196 mm.

(b) To find the maximum permissible internal pressure with a tank wall thickness of 85 mm, we'll use the same formula, but rearrange it to solve for P:
P = (2 * S * t) / D
where:
t = 85 mm (given tank wall thickness)
Plugging in the values:
P = (2 * 196.67 * 85) / 20,000
P = 33,534.9 / 20,000
P ≈ 1.68 MPa
Therefore, the maximum permissible internal pressure for a tank wall thickness of 85 mm is approximately 1.68 MPa.

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The multiplication of the set load when Euler's critical load for a perfect structure is reached is known as the buckling factor. As an illustration, the elastic critical buckling load Pe is established by compressive compressing a column.

The buckling load factor, also known as the ratio of the buckling loads to the applied loads at the time, is a measure of the factor of safety against buckling.

Because buckling is caused by compressive or axial forces, which are more frequent in columns than beams, columns are frequently the topic of buckling inspections.

Therefore, For buckling loads, you should use a high factor of safety (at least >3) because buckling frequently results in negative or even disastrous outcomes.

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Answer:

the third anwser is right on edgeinuity

Explanation:

Answer:

Technology can pull students’ focus away from their tasks.

Explanation:

Answer:

Explanation:

From  the given question:

Using the distortion energy theory to determine the  factors of safety  FOS can be expressed  by the relation:

\(\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma y^2-\sigma x \sigma y+3 \tau_{xy^2}}\)

where; syt = strength in tension and compression = 350 MPa

The maximum shear stress theory  can be expressed as:

\(\tau_{max} = \dfrac{Syt}{2FOS}\)

where;

\(\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma y}{2})^2+ \tau _{xy^2\)

a. Using distortion - energy theory formula:

\(\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}\)

\(\dfrac{350}{FOS}=160.35\)

\({FOS}=\dfrac{350}{160.35}\)

FOS = 2.183

USing the maximum-shear stress theory;

\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2\)

\(\dfrac{350}{2 FOS} =88.51\)

\(\dfrac{350}{ FOS} =2 \times 88.51\)

\({ FOS} =\dfrac{350}{2 \times 88.51}\)

FOS = 1.977

b. σx = 110 MPa, σy = 100 MPa

Using distortion - energy theory formula:

\(\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}\)

\(\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000\)

\(\dfrac{350}{FOS}=105.3565\)

\(FOS=\dfrac{350}{105.3565}\)

FOS =3.322

USing the maximum-shear stress theory;

\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2\)

\(\dfrac{350}{2 FOS} ={ (\dfrac{110-100}{2})^2\)

\(\dfrac{350}{2 FOS} =25\)

FOS = 350/2×25

FOS = 350/50

FOS = 70

c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa

Using distortion- energy theory formula:

\(\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}\)

\(\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}\)

\(\dfrac{350}{FOS}= 88.88\)

FOS = 350/88.88

FOS = 3.939

USing the maximum-shear stress theory;

\(\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2\)

\(\dfrac{350}{2 FOS} =\sqrt{ (35)^2+ (-20)^2\)

\(\dfrac{350}{2 FOS} =\sqrt{ 1225+ 400\)

\(\dfrac{350}{2 FOS} =40.31\)

\(FOS} =\dfrac{350}{2*40.31}\)

FOS = 4.341

Answer:

True ❤️

-Solid by solid can make Cylindrical wire doubles Strengths in tension

The two duct connection combinations for a package unit are upflow and downflow.

An upflow duct connection is when the air handler is located in the basement or crawlspace and the ducts are run through the floor to distribute the conditioned air. A downflow duct connection is when the air handler is located in the attic and the ducts are run through the ceiling to distribute the conditioned air. These two types of duct connections are used in different situations depending on the layout of the home and the location of the package unit. Horizontal supply and return ducts are also a possible configurations, but they are less common in package unit installations.

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Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution

Answer:

\(0.015\ \text{W}\)

Explanation:

\(T_{set}\) = Set temperature = \(70^{\circ}\text{C}\)

\(T_\infty\) = Air temperature = \(50^{\circ}\text{C}\)

A = Surface area = \(30\ \text{mm}^2=30\times 10^{-6}\ \text{m}^2\)

h = Convection heat transfer coefficient = \(25\ \text{W/m}^2\text{K}\)

Heater power is given by

\(P_e=hA(T_{set}-T_\infty)\\\Rightarrow P_e=25\times 30\times 10^{-6}(70-50)\\\Rightarrow P_e=0.015\ \text{W}\)

The required heater power is \(0.015\ \text{W}\)

For every (,) direction, the intensity is independent of the radius. So, at any position between p1 and p2, the intensities would be equal.

The power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation. Watts per square meter (W/m2) and kilograms per square meter (kg/s3) are the units used in the SI system.

With waves like acoustic waves (sound) or electromagnetic waves like light or radio waves, intensity is most usually employed to describe the average power transfer across one period of the wave. Other situations where energy is exchanged can also be described in terms of intensity. One could, for instance, figure out how much kinetic energy each drop of water from a sprinkler is carrying.

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The current in the incandescent bulb is approximately 0.625 Amperes (A).

An incandescent light bulb, incandescent lamp or incandescent light globe is an electric light with a wire filament heated until it glows. The filament is enclosed in a glass bulb with a vacuum or inert gas to protect the filament from oxidation.

The amount of current in an incandescent bulb rated at 75W and 120V can be calculated using Ohm's Law, which states that current (I) is equal to power (P) divided by voltage (V).

Using this formula, the current can be calculated as:

I = P / V

I = 75W / 120V

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Answer:

The thickness of the oil reservoir is 10cm, the production rate of oil is 100m3, the well radius is 10cm, the permeability of the reservoir is 1um2, the porosity is 0.2, the viscosity of the oil is 4mPa.s, the density of oil is 850kg/m3. If the flow regime can be considered as linear flow, can this flow in the reservoir satisfy Darcy's

Answer:

Named Binary Tag ( NBT)

Explanation:

The format is designed to store data in a tree structure made up of various tags

The meaning of the given word NBT is called; National Benchmark Test.

The meaning of the given word NBT is called National Benchmark Test.

NBT ( national benchmark test ) is defined as a national test which must be written and passed by High school students that intend to go to the university ( i.e. passport to the university ).

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Technician A is correct because the automotive batteries can be recycled and the materials used to make new batteries.

Materials present in the battery;

Lead-acid batteries are used to store chemical energies and they are highly recyclable.

To recycle a lead-acid battery, first step is to break it into smaller fragments such as lead, plastic coating and the toxic material (sulfuric acid).

Thus, we can conclude that Technician A is correct because the automotive batteries can be recycled and the materials used to make new batteries.

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Answer:

b

Explanation:

A closed section will have a bottom surface.

When we say that a data structure is immutable in Python, it means that its values cannot be changed after it has been created. Any attempt to modify an immutable object will result in the creation of a new object with the updated value, rather than changing the original object. This property of immutability is useful for ensuring data integrity and avoiding accidental modifications to important data. Examples of immutable data structures in Python include strings, tuples, and frozensets.

In Python, an immutable data structure is a data structure that cannot be changed once it is created. This means that if a value is assigned to an immutable data structure, it cannot be modified later, and any operation that attempts to modify the data structure will create a new object with the modified value.For example, tuples in Python are immutable data structures. Once a tuple is created, its contents cannot be changed. If you try to modify a tuple, Python will raise a TypeError.

my_tuple = (1, 2, 3)

my_tuple[0] = 4  # This will raise a TypeError because tuples are immutable

In contrast, mutable data structures, such as lists and dictionaries, can be modified after they are created. This means that you can add, remove, or modify elements in a list or dictionary after they are created.Overall, immutability is a useful property in programming because it makes it easier to reason about the behavior of code and reduces the risk of unintended side effects. In Python, when we say that a data structure is immutable, it means that the elements within the data structure cannot be changed or modified after they are created. Some examples of immutable data structures are strings and tuples. Once an immutable object is created, its state and contents remain constant throughout its lifetime.

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Answer: i believe it’s acoustics

Explanation:

Answer:

try settings and go to updates?

Explanation:

Answer:

Hence the given statement is false.

Explanation:

For low-speed subsonic wind tunnels, the air density remains nearly constant decreasing the cross-section area cause the flow to extend velocity, and reduce pressure. Similarly increasing the world cause to decrease and therefore the pressure to extend.

The speed within the test section is decided by the planning of the tunnel.  

Thus by adjusting the pressure difference won't change the worth of test section velocity.

Answer:

The given statement is false .

Given, Diameter of the punch, d = 15 mm Radius of the punch, r = d/2 = 15/2 mm = 7.5 mmThickness of the steel plate, t = 5 mmForce required to produce the hole, F = 80 N.

The average shear stress acting over the newly formed surfaces of the hole can be calculated using the formula:

τ = (4F)/(πd t) Where,τ = Shear stress F = Force required to produce the holed = Diameter of the punch t = Thickness of the steel plate Substituting the given values in the above formula:τ = (4F)/(πd t)τ = (4 x 80)/(π x 15 x 5)τ = 0.85 MP a   Therefore, the average shear stress acting over the newly formed surfaces of the hole is 0.85 MP a.

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Answer:

oh god... i have no idea lm.ao

Explanation:

Answer:

I can help you with your calculation.

To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:

Align the angles so that the degrees, minutes, and seconds are in the same column.

Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.

Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.

Add or subtract the degrees last.

Using this method, your calculation can be done as follows:

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’

Therefore, the answer is 59º27’55.75’’. I hope this helps!

Explanation: