Maximum height could a person jump and land rigidly upright on both feet without breaking his legs: h = 0.30 m
Briefly:
Potential energy = m g h would be present in a jumper at height h, and as the jumper hits the ground, this potential energy will totally transform into kinetic energy. Now, the human can only absorb a maximum of 200 J of energy.
m = 67 kg
g = 9.8 m/s²
⇒ m g h = 200 J
⇒ h = 200 J / (67 kg × 9.8 m/s²) = 0.30 m
Therefore, a person can only fall from a height of 0.30 m safely and without breaking both of their legs.
Whatever produces the most energy?In metabolic processes, lipids provide the most energy. On reduction, lipids turn into fatty acids. As a result, fat has a higher energy content than both glycogen and proteins together.
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Question:-
the maximum energy a bone can absorb without breaking is surprisingly small. for a healthy human of mass 67 kg , experimental data show that the leg bones can absorb about 200 j . part a from what maximum height could a person jump and land rigidly upright on both feet without breaking his legs?
1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his trip
take?
Answer:
His trip took 5.78 seconds
Explanation:
23.7m divided by 4.1m/s = 5.78048780488
Read the description of the motion of the bold-faced objectand decide if the kinetic energy (KE) and the gravitationalpotential energy (PE) is increasing, decreasing, orremaining constant.After takeoff, the toy rocket climbed to aheight of 25 meters above the ground.
The total energy of the rocket is,
\(E=K+U\)where K is the kinetic energy and U is the potential energy,
The gravitational potential energy of the rocket is,
\(U=\text{mgh}\)where m is the mass, g is the acceleration due to gravity and h is the height of the rocket,
As the height of the rocket is increased, thus, the value of the potential energy of the rocket is increased.
According to the law of conservation of energy, the net energy of the rocket remains the same at every point.
Thus, with the increase in the value of potential energy of the rocket at 25 meters height, the value of kinetic energy decreases.
Hence,
What is the acceleration of the traveler if his/her speed is constant?
Answer: 0 m/s^2
Explanation: acceleration is the change in velocity per time (slope of the tangent line to the velocity-time graph), a=Δv/Δt. If the speed(velocity) is constant in any direction, there is no change to the velocity. if Δv=0, then a=0
why a moving body stop after some time
Explanation:
Friction acts between two surfaces in contact only and opposes the movement of one body with respect to another. Therefore friction is a force which opposes the relative motion between two bodies. If a body is moving it is slowed down by frictional force applied on it by the surface on which it is moving.
Why is it important to observe the necessary precautions in dancing??
Answer:
To Avoid accidents and injuries
Explanation:
Safety measures are vital dancing as this may prevent bad things like accidents and injuries from happening.
When dancing,the safety of dancers is a must to be observed and considered.
Dancers are also most likely to exert their full potential if they know that they are safe no matter what happen....
HAVE A GOOD DAY....
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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A jet airplane is in level flight. The mass of the airplane is m=9010kg. The airplane travels at a constant speed around a circular path of radius R=9.77mi and makes one revolution every T=0.129h. Given that the lift force acts perpendicular upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane? At what angle is the airplane banked?
Answer:
The magnitude of the lift force L = 92.12 kN
The required angle is ≅ 16.35°
Explanation:
From the given information:
mass of the airplane = 9010 kg
radius of the airplane R = 9.77 mi
period T = 0.129 hours = (0.129 × 3600) secs
= 464.4 secs
The angular speed can be determined by using the expression:
ω = 2π / T
ω = 2 π/ 464.4
ω = 0.01353 rad/sec
The direction \(\theta = tan^{-1} ( \dfrac{\omega ^2 R}{g})\)
\(\theta = tan^{-1} ( \dfrac{0.01353 ^2 \times (9.77\times 1609)}{9.81})\)
θ = 16.35°
The magnitude of the lift force L = mg ÷ Cos(θ)
L = (9010 × 9.81) ÷ Cos(16.35)
L = 88388.1 ÷ 0.9596
L = 92109.32 N
L = 92.12 kN
b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?
Answer:
Twice.
Explanation:
The momentum of an object is given by :
p = mv
Where
m is mass and v is the velocity
If the mass of the ball were doubled, m'=2m and v'=v=3 m/s
New momentum,
p'=m'v'
p'=2m × v
p'=2mv
or
p'=2p
So, the new momentum becomes twice the initial momentum.
Engineers are working on a design for a cylindrical space habitation with a diameter of 7.50 km and length of 29.0 km. The habitation will simulate gravity by rotating along its axis. With what speed (in rad/s) should the habitation rotate so that the acceleration on its inner curved walls equals 8 times Earth's gravity
Answer:
The speed will be "0.144 rad/s".
Explanation:
Given that,
Diameter,
d = 7.50 km
Radius,
R = \(\frac{7.5}{2} \ Km\)
Acceleration on inner curve,
= 8 times
Now,
As we know,
⇒ \(\omega^2R=8g\)
or,
⇒ \(\omega=\sqrt{\frac{8g}{R} }\)
On substituting the values, we get
⇒ \(=\sqrt{\frac{8\times 9.8}{\frac{7.5}{2}\times 10^3 } }\)
⇒ \(=\sqrt{\frac{78.4}{3750} }\)
⇒ \(=\sqrt{0.0209}\)
⇒ \(=0.144 \ rad/s\)
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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Question 8 of 10
On which parts of the heating curve for water does adding thermal energy
mainly cause the particles to move faster?
200
150 -
B
To
100
Temperature ('C)
A
50
С
0
-50
10
40
50
60
70
Time (min)
O A. C and D
B. A and B
O O O O
O C. Band C
OD. B and D
Answer:
The correct answer is A
Explanation:
In this exercise we are given a graph of temperature versus time.
In calorimeter processes there are two types
* one that when giving thermal energy to the system its temperature increases, this fundamentally due to the greater kinetic energy of the molecular ones, this process observes in the graphs as a straight line of constant slope
* A process donates all the thermal energy that is introduced is cracked in breaking the molecular bonds, taking matter from one thermodynamic state to another, for example: liquid to gas.
This process in curves as a horizontal line, that is, there is no temperature change,
When analyzing the graph shown, parts C and D are the one that show a change in temperature with thermal energy. The correct answer is A
Answer:
C and D
Explanation:
Just took the quiz
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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a ship's sonar sends messages and receives the echoes from the ocean bottom 0.6 seconds after the sound is sent down from the ship.how Deep is the water beneath the ship? (Given speed of sound in still water = 1450m/s)
Answer:
Speed of Sound = 2D
Time
Where D is the depth of water
2D = Speed × Time
2D = 1450m/s × 0.6s
D = 1450m/s × 0.6s
D
Depth D = 870m
1. An engine absorbs 600 J of heat while doing 650 J of work. What is the change
in internal energy of the enginge? *
1250 J
-50 J
-1250 J
50 J
The change in internal energy of the engine is -50 joule. Hence, option (B) is correct.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.
The absorb energy: Q = 600 Joule
Work done: W = 650 Joule.
Let, the change in internal energy of the engine= dU.
According to conservation of energy:
The absorb energy = change in internal energy + Work done
Q = dU + W
dU = Q - W
= 600 joule - 650 joule
= - 50 joule.
Hence, the change in internal energy of the engine is -50 joule.
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During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels the balloon. What does this most likely tell you about the charges of the two objects?
Both objects have negative charges.
The tissue has a positive charge, and the balloon has a negative charge.
The tissue has a negative charge, and the balloon has a positive charge.
The objects have no interactive with each other.
Answer:
i think your answer is this: the objects have no interactive with each other.
Explanation:
if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.
A package is on a ramp that is inclined 31° to the horizontal, as shown.To prevent the package from sliding, a force Q of magnitude 105 N is required.The figure is not drawn to scale.Р310GVComolate the following Do not found any interme
Given
Let's draw a scheme
Procedure
Sum of axis x
P - Q = 0
P = Q
P = 105 N
Also
P = GSin 31
G = P/sin 31
G = 105 N / sin 31
G = 203.86 N
For C
C = G Cos 31
C = 203.86 cos 31
C = 174.75 N
Find the force diagram, the box is moving along the horizontal direction.where F_N is the normal force
Given data:
* The value of the force F_1 acting at 20 degree is,
\(F_1=60\text{ N}\)* The value of the force F_2 is,
\(F_2=10\text{ N}\)* The mass of the box is 8 kg.
Solution:
As box is not moving along the vertical direction, thus, the normal force acting on the body must balancing the y-comonents of the forces acting on the body,
The equation for the normal force is,
\(F_N+F_1\sin (20^{\circ}_{})-mg=0\)Here the negative sign is indicating the direction force towards downward, and the positive sign indicates the direction of force towards the upward direction,
Substituting the known values,
\(\begin{gathered} F_N+60\times\sin (20^{\circ})-(8\times9.8)=0 \\ F_N+20.52-78.4=0 \\ F_N-57.88=0 \\ F_N=57.88\text{ N} \end{gathered}\)Thus, the normal force acting on the box is 57.88 N.
Tom applied 10 000J of heat energy to four (4) metals A, B, C and D. All the metals were of the same mass and were initially at the same temperature. After heating the metals the temperature change was noted as shown in the table below. Metal 9 A.25 B.35 C.10 D.15 Which of these four (4) metals has the highest heat capacity?
The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.
How to determine heat capacity?Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.
Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.
Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.
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In hiking, what fitness component is required of you
The philosopher Robert Nozick imagined an “experience machine” to show that a core feature of utilitarianism (as conceived by Bentham and Mill) does not conform with most people’s intuitions about “the good life.” Which of these core features of utilitarianism was Nozick’s main target?
Robert Nozick opines that individuals own themselves and hence have a right to own property.
What is utilitarianism?The term utilitarianism refers to the philosophical ideology that in the use of commodities, the best options is that which maximizes utility or satisfaction derived from the commodity.
In the position of Robert Nozick, utilitarianism means that individuals own themselves and hence have a right to own property.
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An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. It stretches 1 millimeter. What is this strand made of?
Based on the value of the Young's modulus, the strand of the metal is made of copper.
Young's modulus of the metalThe Young's modulus of the metal is calculated as follows;
E = stress/strain
Stress of the metalThe stress of the metal is calculated as follows;
σ = F/A = mg/A
where;
A is area of the metal
A = πr²
A = π( 2 x 10⁻³)²
A = 1.257 x 10⁻⁵ m²
σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)
σ = 5.5 x 10⁷ N/m²
Strain of the metalThe strain is calculated as follows;
strain = x/L
where;
x is extension
L is original length
strain = (1 x 10⁻³ m) / 2 m
strain = 5 x 10⁻⁴
Young's modulus of the metal
E = stress/strain
E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)
E = 1.1 x 10¹¹ N/m²
E = 110 Gpa
The Young's modulus of copper metal is 110 Gpa
Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.
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As the shuttle bus comes to a sudden stop to avoid hitting a dog. It accelerates unfirmly at -4.1m/s^2 as it slow down from 9.0m/s to 0.0m/s. Find the interval of acceleration for the bus
The interval of acceleration of the bus will be 2.19 seconds.
What is acceleration?An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change.
Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.
Acceleration is a vector quantity.
SI unit of acceleration is m/s.
According to the question, the given values are :
Acceleration, a=-4.1 m/s²
Initial velocity, u=9.0 m/s and,
Final velocity, v=0 m/s
By using Equation of motion, i.e.,
v=u+at
⇒0 m/s=9m/s+(-4.1 m/s²)(t)
⇒-9 m/s=-4.1 m/s²×t
t=(-9 m/s)/(-4.1 m/s²)
t= 2.19 seconds.
Hence, the time interval of acceleration of the bus will be 2.19 seconds.
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If one oscillation has 3.0 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
The ratio of their amplitudes is 3.
The relation between energy and amplitude is as follows:
\(E_{1} = \frac{1}{2} KA_{1} ^{2}\)
\(E_{2} =\frac{1}{2} KA_{2} ^{2}\)
As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,
\(E_{1} = 3E_{2}\)
So, \(\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )\)
\(A_{1} ^{2} = 3A_{2} ^{2}\)
\(\frac{A_{1}^{2} }{A_{2}^{2} } = 3\)
Therefore, the ratio of their amplitudes is 3.
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A 1,470-N force pushes a 500-kg piano up along a ramp. What is the work done by the 1,470-N pushing force on the piano as it moves 10 m up the ramp
Answer:
W = 14700 J
Explanation:
This is an exercise on Newton's second law.
To solve it we must fix a coordinate system, the most common is an axis parallel to the ramp and the other perpendicular axis, we write Newton's second law
Y Axis . Perpendicular to the ramp
N - Wy = 0
X axis. Parallel to the ramp, we assume it is positive when the ramp is going up
F - Wx = m a
in this case F = 1470 N and it is parallel to the plane.
Work is defined by
W = F .d
boldface indicates vectors
W = F d cos θ
let's calculate
W = 1470 10 cos 0
W = 14700 J
can someone tell me if this is right (it's for my presentation)
model table for boron
neutral atom has 5 protons, 5 electrons, and 6 neutrons
isotope (106) has 5 protons, 5 electrons, and 5 neutrons
ion has 5 protons, 3 electrons,
neutrons 6, charge +3, ion loses electrons instead
of gains, and it is a nonmetal
Answer:
It is right!! Keep going.. fighting ✊
Answer:
Yes it is right!
Explanation:
I just went over it and it sounds good.
Good luck!
A liquid fueled rocket is red on a test stand. The rocket nozzle has an exit diameter of 30 cm and the combustion gases leave the nozzle at a velocity of 3800 m/s and a pressure of 100 kPa, which is the same as the ambient pressure. The temperature of the gases in the combustion area is 2400 C. Find (a) the temperature of the gases at the nozzle exit plane, (b) the pressure in the combustion area, and (c) the thrust developed. Assume that the gases have a speci c heat ratio of 1.3, and a molar mass of 9. Assume that the ow in the nozzle is isentropic.
Answer:
1. Temperature= 869.35 K
2. Pressure of combustion = 12994.043 kpa
3. Thrust = 127x10⁶N
Explanation:
this problem has been fully explained in the attachment. please use it to get a clearer explanation of the answer.
1.
The temperature = (273+2400k) - (3800)²/2(4003)
= 2673 - 14440000/8006
= 2673 - 1803.65
= 869.35 K
Approximately 869.4K
2. We first get mach number
= 3800/√1.3(923.8)(869.35)
= 3800/1021.78
= 3.719
Pressure = 100kpa[1+2.07464415]^1.3/0.3
= 12995.043kpa
C. Thrust
Pi/4(3800)²(0.3)²(100x10³)/(923.8)(869.4)
= 12678.621
= 126.781 kN
Thrust is approximately 127kN = 127x10⁶N
You are traveling through the forest and encounter an ancient well. You want to know how deep the well is. If you drop a coin and hear it hit the bottom of the well in 3 seconds, how deep is the well?
eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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A solid sphere of radius R, a solid cylinder of radius R, and a rod of length R all have the same mass, and all three are rotating with the same angular velocity The sphere is rotating around an axis through its center. The cylinder is rotating around its long axis, and the rod is rotating around an axis through its center but perpendicular to the rod. Which one has the greatest rotational kinetic energy? a. the sphere b. the cylinder c. the rod d. the rod and the cylinder have the same rotational kinetic energy e. they all have the same kinetic energy
Answer:
b. the cylinder
Explanation:
From the information given:
We understood that the mass of the sphere, cylinder, and rod length is the same with the same angular speed.
Taking their moments:
For the solid sphere; \(\text{The moment of inertia :}\) \(I_s\) = \(\dfrac{2}{5} \times m \times r^2\)
The moment of inertia of the cylinder, \(I_c = 0.5\times m \times r^2\)
The moment of inertia of rod, \(I_r =\dfrac{ m * r^2 }{12}\)
The rotational kinetic energy is directly corresponding to the moment of inertia.
Thus, the cylinder has the greatest rotational kinetic energy.
What is the mean absolute deviation of the data set?2, 2, 5, 6, 8, 4, 8, 51.752.255.158.00
First, find the mean.
Add all values and divide by the number of values:
(2 + 2 + 5 + 6 + 8 + 4 + 8 + 5 ) / 8 = 40/8 = 5
Calculate the positive distance of each value to the mean.
5 - 2 = 3
5 - 2 = 3
5 - 5 = 0
6 - 5 = 1
8 - 5 = 3
5-4= 1
8-5= 3
5 - 5 = 0
Sum all results and divide by the number of values
( 3 +3 + 0 + 1 +3 +1 +3 + 0) /8 = 14/8 = 1.75
MAD = 1.75