The mass of a hoop with a radius of 1.0 m is 6.0 kg. It rolls across a horizontal surface with a speed of 10.0 m/s. How much work is required to stop the hoop?

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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The reactive force when a fish swims through water is the force of the water on the fish. This is an example of Newton’s third law of motion which states that for every action, there is an equal and opposite reaction. The active force is the fish pushing against the water, so the reactive force would be the reverse, the equal force of the water pushing back on the fish.

The initial velocity of this ball is equal to 38.85 m/s.

Deceleration can be defined as a negative rate of change of velocity of a physical object with respect to time. This ultimately implies that, deceleration connotes a decrease in the velcoity of an automobile vehicle.

Velocity can be defined as the distance covered by an object per unit of time. This ultimately implies that, velocity is a vector quantity because it has both magnitude and direction. Also, velocity can be measured as meter per seconds.

In order to determine the initial velocity of this ball, we would apply the first equation of motion:

V = U + at

U = V - at

U = 0 - (-2.10 × 10^4 × 1.85 × 10^{-3})

Initial velocity, U = 38.85 m/s.

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Complete Question:

A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10 × 10^4 m/s2, and 1.85 ms (1 ms = 10^-3 s) elapses from the time the ball first touches the mitt until it stops, what was the initial velocity of the ball?

The type of decay that has no charge associated with it is gamma decay (option C).

Gamma decay is a nuclear reaction with the emission of a gamma ray. A gamma ray is a high frequency/energy electromagnetic radiation emitted as a consequence of radioactivity.

Gamma rays are waves, not particles. This means that they have no mass and no charge.

This, therefore, suggests that when a gamma ray is emitted, no charge is involved.

Unlike alpha and beta decay that involves +2 and -1 charges respectively.

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Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

We are asked to determine the acceleration of the system. To do that we will consider the two masses to be a single system and we will use the following free-body diagram.

Where:

To determine the components of the weight of "A" we use the following triangle:

Therefore, the vertical component is given by:

Since the weight is the product of the mass and the acceleration we have;

The horizontal component is given by:

Substituting the formula for weight:

The friction force is given by:

The normal force "N" is equivalent to the vertical component of the weight since there is no acceleration in that direction. Therefore, we have:

Substituting the values:

Now, the net force is equivalent to the forces acting on the system. Therefore, the net force is:

Substituting we get:

According to Newton's second law we have that the net force is equal to the product of the mass and the acceleration:

The total mass is the sum of the masses "A" and "B".

Substituting the net force:

Now, we divide both sides by the total mass:

Since we have that the masses are equal:

Substituting we get:

Adding the masses in the denominator:

We can cancel out the "m":

Now, we plug in the values:

Solving the operations:

Therefore, the acceleration is 1.81 meters per second square.

Part B. To determine the value of the coefficient of friction that will keep the system from accelerating we must go back to the formula for the acceleration:

Now, we will set the acceleration to zero:

Multiplying both sides by 2:

Now, we can divide both sides by "g":

Now, we solve for the coefficient of friction. We subtract 1 to both sides:

Now, we add sin(30) to both sides:

Now, we divide both sides by -cos(30):

Now, we solve the operations:

Therefore, the friction coefficient is 0.58

jacob first stack is 1

Answer:

help

Explanation:

me

If the potential throughout a particular region is constant, the field throughout that region must be zero.[CORRECT]

The following are the characteristics of potential energy

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The statement which is correct about the lighter dart leaves the spring moving faster than the heavy dart. Option B is correct.

This is because both darts are launched with the same initial elastic potential energy from the compressed springs, but the lighter dart has less mass than the heavier dart. According to the law of conservation of energy, the lighter dart must move faster than the heavier dart in order to have the same amount of kinetic energy as the heavier dart once it leaves the spring.

The initial potential energy is the same for both darts, and since the potential energy is converted to kinetic energy, the lighter dart must have a higher velocity than the heavier dart in order to have the same amount of kinetic energy.

Therefore, option B is correct, while options A, C, D, and E are not, as they do not accurately describe the behavior of the darts in this scenario.

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--The complete question is, A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?

A) The darts both have the same kinetic energy just as they move free of the spring.

B) The lighter dart leaves the spring moving faster than the heavy dart.

C) The heavy dart had more initial elastic potential energy than the light dart.

D) Both darts move free of the spring with the same speed. E) Both darts had the same initial elastic potential energy.--

Answer:

D. 2.5 x 10^4

Explanation:

10 to the power of 4 is 10,000.

10,000 x 2.5 = 25,000

D. 2.5 x 10⁴ is the scientific notation of Ellie records.

Scientific Notation is the expression of a number n in the form a∗10ᵇ. where a is an integer such that 1≤|a|<10. and b is an integer too. It is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.

According to the question,

The given number is 25,000 m

i.e.

25 x 10³

Since we have to put the decimal  between 2 and 5

It becomes,

2.5  x 10⁴

or

10 to the power of 4 is 10,000.

10,000 x 2.5  = 25,000

Therefore,

The answer is 2.25 x 10⁻⁶ M

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Answer:

 F = 2,8289 i ^ + 1,0909 j ^) 10⁻² N

F = 3.0226 10⁻² N ,  θ  = 21.16º

Explanation:

For this exercise we use Coulomb's law

         F = k q₁q₂ / r₁₂²

We also use that the force is a vector magnitude, so we must calculate each component of the force , see the adjoint for the direction of the vectors

X axis

          Fₓ = -F₁₄ + F₁₃ₓ

Y axis

        \(F_{y}\) = F₁₂ -F_{13y}

let's look for the expression for each force

where the side of the square is a = 1.25 m

  F₁₂ = k Q₁Q₂ / a²

  F₁₄ = k Q₁Q₄ / a²

the distance between 1 and 3 is

         d = √(a² + a²) = a √2

   F₁₃ = k Q₁Q₃ / d²

let's use trigonometry to find the components

              cos 45 = F₁₃ₓ / F₁₃

              F₁₃ₓ = F₁₃ cos 45

              F₁₃ₓ = k Q₁Q₃ / 2a²

              sin 45 = F_{13y} / F₁₃

              F_{13y} = F₁₃ sin 45

              F_{13y} = k Q₁Q₃ / 2a²  sin 45

Taking all terms, we substitute in the force for each axis

X axis

          Fₓ = - k Q₁Q₄ / a² + k Q₁Q₃ / 2a₂ cos 45

          Fₓ = k Q₁ / a² ( -Q₄ + Q₃ /2   cos 45)

          Fₓ = 9 10⁹ 1.5 10⁻⁶ / 1.25²   (- 4.5 10⁻⁶ + 3.5/2  cos 45  10⁻⁶)

          Fₓ = 8.64 10³ (3.2626 10⁻⁶)

          Fₓ = 2.8189 10⁻² N

Y axis

          F_{y} = k Q₁Q₂ / a² - k Q₁Q₃ /2a²   sin 45

          F_{y} = k Q₁ / a² (Q₂ - Q₃ /2 sin45)      

          F_{y} = 9 10⁹ 1.5 10⁻⁶/ 1.25²    (2.5 10⁻⁶ - 3.5/2   sin 45  10⁻⁶)

          F_{y} = 8.64 10³ (1.26256 10⁻⁶)

          F_{y} = 1.0909 10⁻² N

The result can be given in two ways

1) F = Fₓ i ^ + F_{y} j ^

     F = 2,8289 i ^ + 1,0909 j ^) 10⁻² N

2) in the form of a module and an angle, for which we use the Pythagorean theorem and trigonometry

       F = √ (Fₓ² + F_{y}²)

       F = 10⁻² √ (2,8189² + 1,0909²)

       F = 3.0226 10⁻² N

       tan θ = F_{y} / Fx

       θ = tan⁻¹ (F_{y} / Fₓ)

       θ = tan⁻¹ (1.0909 / 2.8189)

        θ  = 21.16º

Answer:

30,000dB

Explanation:

30,000dB because 30 multiplied by a factor of 1000 is 30,000

Hope this helps! :)

To find the input amperes, we need to use the equation that relates power, voltage, and current:

Power = Voltage x Current x Efficiency

We can rearrange this equation to solve for current:

Current = Power / (Voltage x Efficiency)

Plugging in the given values:

Current = 1600 W / (120 V x 0.88)

Current = 1600 W / 105.6

Current = 15.15 A

Therefore, the input amperes at 120V is approximately 15.15 A.

A. The electric field is null at the point C; located in the middle of the

segment AB.

Electric field is the region of space where the influence of electric force is felt.

E = kq/r²

where;

E(+6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)

E(+6μC) = +216,000

E(-6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)

E(-6μC) = -216,000

E(net) = E(+6μC) + E(-6μC)

E(net) = 216,000 - 216,000 = 0

Thus, the electric field is null at the point C; located in the middle of the

segment AB.

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I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².

The relationship between the temperature,T and the peak wavelength, \(\lambda\) emitted by a black body is given by wien's displacement law:

\(\lambda\) = b / T

Where, b is a constant and it's value is 2.898 * 10-3 m-K

Given: T = 8400 K

So, \(\lambda\) =   (2.898 * 10-3 )/8400

\lambda = 3.45 * 10-7  

\lambda = 345 nm

Hence, the peak wavelength of the object at this temperature is 345 nanometre.

The amount of power emitted per unit area, P is given by Stefan Boltzmann law:

P =\(\sigma\)T⁴

Where,

Absolute temperature, T = 8400 K

Stefan Boltzmann constant, \(\sigma\) = 5.67 * 10-8 W/m²K⁴

So, P = 5.67 * 10-8 * (8400)⁴

P = 2.82 * 10⁸  W/m²

Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².

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Answer: The coefficient of static friction between the coin and the turntable is 0.13.

Explanation:

As we know that,

   Centripetal force = static frictional force

   \(\frac{mv^{2}}{r} = F_{s}\)

or,  \(\frac{mv^{2}}{r} = \mu_{s} \times m \times g\)

     v = \(\sqrt{\mu_{s} \times r \times g}\)

or,  \(\mu_{s} = \frac{v^{2}}{rg}\) ......... (1)

Here, it is given that

       r = 17 cm,      \(\omega\) = 26 rpm,    

and  v = \(r \omega\) ..........(2)

Putting equation (2) in equation (1) we get the following.

\(\mu_{s} = \frac{r^{2}\omega^{2}}{rg}\)

            = \(\frac{17 \times 10^{-2} \times (26 \times [\frac{2 \times \pi}{60}]^{2})}{9.8}\)

            = 0.128

            = 0.13 (approx)

Thus, we can conclude that the coefficient of static friction between the coin and the turntable is 0.13.

The electric force on the charge Fc = 9.439 x 10⁹N(m/C)²

To calculate the electric force on different charges and a certain distance,

Use formula,

Fc = k (q₁q₂)/r²

Where,

Fc is electric force

k is coulomb's constant

q₁ is charge at one point

q₂ is charge at second point

r is the distance

Known values,

q₁ = 15μC

q₂ = 7μC

k =  8.99 × 10⁹ Nm² /C²

r = 10cm

Fc = ?

Now, putting the values

Fc =  8.99 × 10⁹ Nm² /C² (15μC x 7μC)/(10cm)²

Fc =  8.99 × 10⁹ N(m/C)² x 1.05

Fc = 9.439 x 10⁹N(m/C)²

Hence, the electric force is Fc = 9.439 x 10⁹N(m/C)².

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We would find the time at which the ball arrives the goal from the constant velocity model in the x direction. We have

xf = xi + vit

vit = xf - xi

t = (xf - xi)/vi

where

xf is the final position of ball

xi is the initial position of ball

vi is the initial velocity of the ball in the x direction

t is the time

From the information given,

xi = 0

xf = 36

vxi = vicosθ

θ = 47

v = 20.6

vxi = 20.6cos47

t = (36 - 0)/20.6cos47

t = 2.56 s

We would find the height of the ball at time of t = 2.56 from the particle under constant acceleration model in the y direction. We have

yf = yi + vyit + 1/2ayt^2

From the information given,

yf = 0 + 20.6sin47 * 2.56 + 1/2 * 9.81 * 2.56^2

yf = 38.569 - 32.145

yf = 6.42

The ball clears the crossbar by 6.42 - 3.05

= 3.27 m

Answer:

1lb = 4.448N.

63lb = ... 4.448x63

=280.224N.

Don't know if you meant to write Convert lb to N tho cos mg is measured in Newtons.

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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Answer:

its c

Explanation:

Answer:0.2 m/s^2

Explanation:

mass=18.15kg

Force=3.63N

Acceleration=force ➗ mass

Acceleration=3.63 ➗ 18.15

Acceleration=0.2 m/s^2

A girl pushes a wagon of mass 18.15 kg with a force of 3.63 N, so the acceleration of the wagon will be 0.2 m/s².

In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. Accelerations as a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.

A vector quantity, acceleration, is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.

Mass, m =18.15 kg

Force, f = 3.63 N

Force = m × a

a= f / m

a =3.63 / 18.15

a = 0.2 m/s²

Hence, the acceleration of the wagon will be 0.2 m/s².

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Answer:

1.) Q T U W 

Explanation:

1.) QTUW

2.) UW

3.) QU

4.) QTUC

According to first law of thermodynamics

dU = Q - W

Where

dU = change in internal energy

Q = heat added

W = work done by the system

2.) UW

Work is been done on the system. The pressure will surely distort the internal energy of the system

Pressure = Force/area.

3.) QU

The melting process begins because the air temperature around the ice cubes is warmer

The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another.

4.) Chemical reaction can be exothermic or endothermic which involves absorption or release of heat. Since it is subjected to small spark, there is definitely a change in internal energy.

In this exercise we have to have knowledge about thermodynamics in order to identify the alternatives that are correctly classified, so we can say that:

1.) QTUW

2.) UW

3.) QU

4.) QTUC

According to first law of thermodynamics:

\(dU = Q - W\)

Where:

1.) The first alternative corresponds to:

In other words QTUW.

2.) The second alternative corresponds to:

Work happen been finished ahead of the system. The pressure will without doubt deform the internal strength of bureaucracy:

\(Pressure = Force/area\)

In other words UW.

3.) The third alternative corresponds to:

The softening process begins cause the air coldness of some degree around the frozen water cubes happen warmer The complete frozen water particles take in heat strength from the warmer air, bestowing the piece energy and allowing to happen them to move out each one.

In other words QU.

4.) The fourth alternative corresponds to:

Chemical reaction maybe exothermic or endothermic that involves assimilation or release of heat. Since it happen commit small spark, skilled happen certainly a change in within strength.

In other words QTUC

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