The lowest common denominator is...

3/4 + 4/12

Don’t add them just answer the question please

The angles of the cyclic quadrilateral are: P = 43°, O = 88°, R = 137°, and Q = 92°

The sum of the opposite angles of a cyclic quadrilateral is equal to 180°, so we solve for the angles of the quadrilateral PORQ as follows:

3y + 8 + y = 180°

4y = 180° - 8 {collect like terms}

4y = 172°

y = 172°/4 {divide through by 4}

y = 43°

2x + 2x + 4 = 180°

4x = 180° - 4 {collect like terms}

4x = 176

x = 176/4 {divide through by 4}

x = 44°

Therefore the measures of the angles of the cyclic quadrilateral PORQ are:

P = 43°

O = 2(44°) = 88°

R = 3(43°) + 8 = 137°

Q = 2(44°) + 4 = 92°

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Answer:

Step-by-step explanation:

No, at 0°F the ticket sales would be -631.25 and it is not reasonable (or possible) to have negative ticket sales in a linear regression model for predicting ticket sales.

In the statistics, the concept of regression analysis is useful for creating a predictive model that predicts the value of a target or dependent variable using all the controlling independent or explanatory variables. Depending on the number of independent variables, regression can be called simple regression or multiple regression. We have a linear regression model that predicts ticket sales for popular water parks.

The regression line equion in this model is written as -631.25 + 11.25 (current temperature in degree F). Comparing above equation with y = a + bx, here, the interaction in the equation above means that hourly ticket sales will be -631.25 when the current temperature (in degrees Fahrenheit) is 0. This does not make sense because hourly ticket sales can be at least 0 but never a negative number. So, it is not reasonable interpretation.

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Rounding to two decimal places, the minimum acceptable weight of a box of cookies is 15.42 ounces.

weight of the boxes of cookies follows a normal distribution with a mean of 16 ounces and a standard deviation of 0.25 ounces.

To find the minimum acceptable weight of a box of cookies, we need to find the value that corresponds to the 1st percentile of the normal distribution.

Using a standard normal distribution table or calculator, we find that the z-score corresponding to the 1st percentile is approximately -2.33.

We can use the formula z = (x - μ) / σ, where x is the minimum acceptable weight, μ is the mean, and σ is the standard deviation, to solve for x.

Plugging in the values, we get:

-2.33 = (x - 16) / 0.25

Solving for x, we get:

x = -2.33 * 0.25 + 16 = 15.4175

Rounding to two decimal places, the minimum acceptable weight of a box of cookies is 15.42 ounces.

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the trigonometric ratios of angle C in right triangle ABC are: sin(C) = 8/17,  cos(C) = 15/17, tan(C) = 8/15, csc(C) = 17/8, sec(C) = 17/15 and cot(C) = 15/8

To determine the trigonometric ratios of angle C in right triangle ABC, we can use the values of the sides AC and BC. Here's how we can find the trigonometric ratios:

Given: AC = 17 units and BC = 8 units

Using the Pythagorean theorem, we can find the length of side AB:

AB² = AC² - BC²

AB² = 17² - 8²

AB² = 289 - 64

AB² = 225

AB = 15 units

Now we have the lengths of all three sides of the triangle:

AC = 17 units

BC = 8 units

AB = 15 units

Using these values, we can find the trigonometric ratios:

1. Sine (sin) of angle C:

sin(C) = BC/AC

sin(C) = 8/17

2. Cosine (cos) of angle C:

cos(C) = AB/AC

cos(C) = 15/17

3. Tangent (tan) of angle C:

tan(C) = BC/AB

tan(C) = 8/15

4. Cosecant (csc) of angle C:

csc(C) = 1/sin(C)

csc(C) = 1/(8/17)

csc(C) = 17/8

5. Secant (sec) of angle C:

sec(C) = 1/cos(C)

sec(C) = 1/(15/17)

sec(C) = 17/15

6. Cotangent (cot) of angle C:

cot(C) = 1/tan(C)

cot(C) = 1/(8/15)

cot(C) = 15/8

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Answer:

y=4/5x-2

Step-by-step explanation:

8x-10y=20

-10y=-8x+20 subtract 8x from both sides

x=4/5x-2   divide everything by -10

Answer:

\(C. x<5\)

Step-by-step explanation:

Step-by-step explanation:

C.x<5 is an inequality sentence.

Answer:

72 cm

Step-by-step explanation:

24cm x 3 = 72cm

A= 72cm

Answer:

27cm

Step-by-step explanation:

24=p w=x         L=3x

x+x+3x+3X=24

8X=24

X=3

w=3

L=9

3*9=27

A=27

Answer:

288 lbs

Step-by-step explanation:

since it is 1/6 of the amount on the moon compare to the earth

take 48 and multiply it by 6

48x6=288

Answer:add all the numbers together then divide the answer by 10

Step-by-step explanation:

Answer:

AC = 15

Step-by-step explanation:

Use segment addition postulate to add AB + BC = AC. 10 + 5 = 15.

(drawing out the line helps you visualize the problem better)

Answer:

Step-by-step explanation:

Candice = 25mph for 4 hours.

Candice has driven= 25 * 4= 100miles.

Liz =50mph

Liz time to catch up to candice= 50 * 2= 100miles.

Therefore, It would have taken Liz two hours to catch up with Candice

Answer: C. 4

Step-by-step explanation:

First, we can prime factorize 52.

52 = 2^2 * 13

13 is not a square number, but 4 is a square number because it equals 2 squared.

Therefore, the correct answer is C. 4

\(\pi \int\limits^6_0 {\frac{26}{3} } \, x^{2} -\frac{1}{9} x^{4} dx\) is the integral that uses the method of disks/washers to find the volume v of the solid obtained by rotating the region bounded by the given curves about the specified lines.

A method for determining the volume of a solid of revolution of a solid-state material while integrating along an axis "parallel" to the axis of revolution is known as disc integration, also known as the disc method in integral calculus.

This technique stacks an endless number of discs with varied radii and minuscule thickness to produce the final three-dimensional form. To create hollow solids of revolutions, the same ideas may also be applied when using rings in place of discs (this is known as the "washer technique").

As opposed to this, shell integration integrates along an axis that is parallel to the axis of revolution. The solution can be seen in the attached images below.

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The probability of this occurring is 4C2/5C2 = 3/5

What is the meaning of probability in math?

Three Types of Probability-

Let's assume we don't stop picking until all of the chips are picked.

To satisfy this condition, we have to arrange the letters: W, W, R, R, R such that both W's appear in the first 4.

We find the number of ways to arrange the white chips in the first 4 and divide that by the total ways to choose all the chips.

Therefore, the probability of this occurring is 4C2/5C2 = 3/5

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The inequality involving an absolute value that describes the set is |X| >= 1

A real number is the value of a continuous quantity that may either be represented as an infinite decimal expansion or as a distance along a line. All rational and irrational numbers are included in the real numbers. Real numbers consist of non-zero positive and negative number, the set of real numbers is denoted using the symbol R.

Positive real numbers are denoted by

X > 0 £ R

For negative number

X < 0 £ R

Which can be combined as

-X < 0 < X £ R

The above inequality can be expressed as absolute quantity which is shown below

|X| £ R

For the line diagram given in this question showing real numbers from -5 to +5 is expressed as

-5 < X < 5 £ R

X <= -1 £ R For negative

X >= 1 £ R For positve

|X| >= 1

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Total degrees of freedom needs to be known to determine the critical values for an independent-samples t-test. So, option 3 is correct.

To evaluate whether the null hypothesis should be rejected or not, a critical value is a value that is contrasted with a test statistic in hypothesis testing. The null hypothesis cannot be rejected if the test statistic's value is not more extreme than the crucial value.

In the sampling distribution of a test statistic, a crucial value delimits areas. Both hypothesis tests and confidence intervals take these values into consideration. When conducting hypothesis testing, crucial values are used to assess whether the findings are statistically significant.

A t-test with independent samples.

To compute the critical values, one must therefore be aware of the degrees of freedom and significance level.

Therefore, total degrees of freedom needs to be known to determine the critical values for an independent-samples t-test.

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Answer:

Step-by-step explanation:

If a line is parallel to a side of a triangle, then the intersected sides are divided proportionally

4/2=y/3

2=y/3

y=2*3 = 6

next,

If the angles of one triangle are equal to the angles of another triangle, then the triangles are said to be equiangular.

(4+2)/4=6/x

6/4=6/x

x=4

Let Charles age be x

Adam age will be 5x  

8 years later , add 8 to both expressions

Charles age = x+8

Adam age = 5x+8

add their ages and equate them to twice adam's present age 2*5x

x+8+5x+8 = 2*5x

6x+16=10x

4x=16

x=4

x = Charles' age

Adam's age  5x = 5(4) = 20

Answer: 18,15

Step-by-step explanation:

Perimeter is 4+8+6 = 18

Area is 1/2*6*5 = 15 the formula is 1/2 bh

The population grows according to the recursive rule is-

For the stated question-

Then,

P1 = P0 + 80

P1 = 60 + 80 = 140

P2 = P1 + 80

P2 = 140 + 80 = 220

Thus, an explicit formula for the population

Pn = P0 + n×80 = 60 + n×80

P100 = 60 + 100×80 = 8060

Thus, explicit formula for the  population growth is

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The complete question is-

Consider a population that grows according to the recursive rule pn = p

(n − 1) + 80 , with initial population p0 = 60

Find an explicit formula for the population. Your formula should involve  n  (use lowercase n)

Pn=    

Use your explicit formula to find

P100  =

Given:

The data values are 4, 5, 7, 7, 7, 8, 10, 11, 11, 13, 13, 14.

To find:

The box plot for the given data set.

Solution:

The data values are

4, 5, 7, 7, 7, 8, 10, 11, 11, 13, 13, 14

Divide these values in two equal parts.

(4, 5, 7, 7, 7, 8), (10, 11, 11, 13, 13, 14)

Divide each group again in two equal parts.

(4, 5, 7), (7, 7, 8), (10, 11, 11), (13, 13, 14)

Here,

Minimum value = 4

\(Q_1=\dfrac{7+7}{2}=\dfrac{14}{2}=7\)

\(Median=\dfrac{8+10}{2}=\dfrac{18}{2}=9\)

\(Q_3=\dfrac{11+13}{2}=\dfrac{24}{2}=12\)

Maximum value = 14

It means, the starting point is 4 and end point is 14 of the box plot.

Box is lies from 7 to 12 and one line inside the box at 9.

Therefore, the box plot of the given data set is shown below.

The machine is not operating satisfactorily, and an adjustment is needed because the sample mean is outside the acceptable range.

Based on the given information, we need to determine if the soft-drink machine is operating satisfactorily and does not require any adjustment.

To do this, we will compare the sample mean (x) with the acceptable interval of the population mean (µ) as per the provided condition.

We are given that:
Population mean (µ) = 12 ounces
Standard deviation (σ) = 0.15 ounces
Sample size (n) = 81 drinks
Sample mean (x) = 11.8 ounces
z-score = ±1.960

Step 1: Calculate the standard error (SE) using the formula SE = σ/√n:
SE = 0.15/√81 = 0.15/9 = 0.0167

Step 2: Calculate the acceptable range using the provided z-score:
Lower limit = µ - z × SE

= 12 - 1.960 × 0.0167

≈ 11.967

Upper limit = µ + z × SE

= 12 + 1.960 × 0.0167

≈ 12.033

The acceptable range for the average content of the drinks is between 11.967 ounces and 12.033 ounces.

Since the sample mean (11.8 ounces) is outside this acceptable range, the machine is not operating satisfactorily, and an adjustment is needed.

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If A is a subset of B, it does not necessarily mean that A is a proper subset of B. The union of any set A and its complement is indeed the universal set.

1. False: If A is a subset of B, it does not necessarily mean that A is a proper subset of B. A proper subset is a subset that contains some, but not all, elements of the superset. In other words, if A is a proper subset of B, it means that there exists at least one element in B that is not in A. However, if A is simply a subset of B, it is possible for A and B to have the same elements, making them equal sets.

For example, let's consider two sets:

A = {1, 2}

B = {1, 2, 3}

In this case, A is a subset of B because every element in A (1 and 2) is also in B. However, A is not a proper subset of B since there are no elements in B that are not in A. Therefore, statement 1 is false.

2. True: The union of any set A and its complement is indeed the universal set. The complement of a set A, denoted as A', consists of all elements that are not in A but are in the universal set U. When we take the union of A and its complement, we are effectively combining all elements from A and all elements not in A.

Let's consider a set A and its complement A' within a universal set U. The union of A and A' is denoted as A ∪ A' and can be represented as U. This is because every element in the universal set U is either in A or not in A (in A').

For example, let's consider the following sets:

U = {1, 2, 3, 4, 5}

A = {1, 2}

The complement of A, A', would be {3, 4, 5}. The union of A and A' (A ∪ A') is {1, 2} ∪ {3, 4, 5}, which is equal to U: {1, 2, 3, 4, 5}. Thus, the union of any set A and its complement is indeed the universal set. Therefore, statement 2 is true.

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Answer:

d ≈ 15.8

Step-by-step explanation:

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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Answer:

302.5

Step-by-step explanation:

30 x 8

5/8

I hope this helps I'm like 90 percent sure this is right. There is no other answer I could think of so I hope Hope helpa