The least dense gas is

neon
fluorine
krypton
chlorine

The given reaction is a redox reaction where ammonium phosphate and molybdenum oxide are formed as products, along with water.

In this redox reaction, the reactants HPO4, 3NH4, and 12MoO4 combine to form the products (NH4)3PO4(MoO3)12 and 12H2O. The reaction can be balanced as follows:

3HPO4²⁻ + 9NH4⁺ + 36MoO4²⁻ + 46H⁺ → (NH4)3PO4(MoO3)12 + 12H2O

The reactants undergo oxidation and reduction processes to form the products, ammonium phosphate [(NH4)3PO4] and molybdenum oxide (MoO3)12, along with water (12H2O).

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The regular insulin drip has an infusion rate of 33.33 gtts/min and 100 ml/hr.

Regular Insulin drip of 12 units/hr, 250ml bag of normal saline with 150 units of regular insulin, IV administration set delivers 20gtts/ml

To determine the infusion rate in gtts/min and mL/hr, we can use the following formula:

gtts/min = (volume to be infused × gtt factor) ÷ time in minutes

mL/hr = volume to be infused ÷ time in hours

Let's find the infusion rate in gtts/min and mL/hr:

First, let's calculate the infusion rate in mL/hr

Volume of the bag = 250 ml

Volume of insulin = 150 ml

Remaining volume is of saline solution = 250 - 150 = 100 ml

So, volume to be infused is 100 ml

Infusion rate in mL/hr = volume to be infused ÷ time in hours

Infusion rate in mL/hr = 100 ÷ 1

Infusion rate in mL/hr = 100 ml/hr

Now, let's find the infusion rate in gtts/min

gtt factor = 20 gtts/ml

Volume to be infused = 100 ml

Time = 60 mins (1 hour)

Infusion rate in gtts/min = (volume to be infused × gtt factor) ÷ time in minutes

Infusion rate in gtts/min = (100 × 20) ÷ 60

Infusion rate in gtts/min = 33.33 gtts/min

Therefore, the infusion rate in gtts/min is 33.33 and the infusion rate in mL/hr is 100 ml/hr.

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Answer:

momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle. See Newton's laws of motion.

Answer:

s-2 p-6 d-10 f-14

Explanation:

s orbital max can fit 2 electrons

p orbital max can fit 6 electrons

d orbital max can fit 10 electrons

f orbital max can fit 14 electrons

The approximate amount of water used in the reaction is 1000 g. Student B is correct.

From the equation of the reaction, the mole ratio of the H2 produced and the H2O separated is 1:1.

mole of H2 produced = mass/molar mass

                                        = 112/2

                                           = 56 moles

This means that 56 moles of H2O was also separated.

Mass of 56 moles of H2O = 56 x 18

                                           = 1,008 g

Also from the equation of the reaction, the mole ratio of O2 produced to water separated is 1:2.

Mole of O2 produced = 888/32

                                       = 27.75 moles

Equivalent mole of H2O = 27.75 x 2

                                        = 55.5 moles

Mass of 55.5 moles of H2O = 55.5 x 18

                                               = 999 g

Thus, the approximate amount of water used in the reaction must have been 1000 g. Student B is correct.

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The correct net ionic equation for the given reaction is option 3: 2OH⁻ + Fe²⁺ → Fe(OH)₂(s).

In a net ionic equation, we only include the species that actively participate in the reaction. The reaction shows that 2 moles of KOH (potassium hydroxide) react with 1 mole of FeCl₂ (iron(II) chloride) to form 2 moles of KCl (potassium chloride) and 1 mole of Fe(OH)₂ (iron(II) hydroxide) as a solid precipitate.

Breaking down the reaction into its ionic form, we have:
2KOH (aq) + FeCl₂ (aq) → 2KCl (aq) + Fe(OH)₂ (s)

The ionic equation can be further simplified by separating all the ions:
2K+ (aq) + 2OH⁻ (aq) + Fe²⁺ (aq) + 2Cl⁻ (aq) → 2K⁺ (aq) + 2Cl⁻ (aq) + Fe(OH)₂ (s)

In the net ionic equation, we eliminate the spectator ions (ions that are present on both sides of the equation and do not actively participate in the reaction), which are K⁺ and Cl⁻. Therefore, the net ionic equation is Option 3:
2OH⁻ (aq) + Fe²⁺ (aq) → Fe(OH)₂ (s)

This equation shows the actual chemical change occurring during the reaction, with hydroxide ions reacting with iron(II) ions to form a solid precipitate of iron(II) hydroxide.

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If 1.50 × 1024 molecules of oxygen are burned in a combustion reaction. The mass of O2 consumed in the reaction is 80.0 g.

The balanced chemical equation for the combustion of oxygen (O2) is:

2 O2 + energy → 2 O

This equation tells us that for every 2 molecules of O2 that are burned, 2 molecules of O are produced.

We are given the number of molecules of O2, which is 1.50 × 10^24. To determine the mass of O2 consumed in the reaction, we need to use the molar mass of O2 and stoichiometry.

The molar mass of O2 is 32.00 g/mol (2 × 16.00 g/mol). We can use this molar mass to convert the number of molecules of O2 to its mass:

1.50 × 10^24 molecules O2 × (1 mol O2 / 6.022 × 10^23 molecules O2) × (32.00 g O2 / 1 mol O2) = 80.0 g O2

Therefore, the mass of O2 consumed in the reaction is 80.0 g.

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Answer:

sodium ion

Explanation:

The correct reactant ratio for the reaction 2Fe + 3Cl2 → 2FeCl3 is 2 moles of iron (Fe) for every 3 moles of chlorine (Cl2).

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Answer:

Protection from elements and Identifying food

Explanation:

For example by use of legs animals can move from one place to another to find food.

Wings usually act as Protection objects in birds

The total reactive power supplied by the load is dependent on the voltage and can be determined using the formula Q = V^2 / X, where X is the impedance of the load.

To find the total reactive power supplied by the load, we need to calculate the impedance of the load. Given that the load has an inductive reactance of 60 ohms and the capacitor bank has a capacitive reactance of 60 ohms, these two reactances cancel each other out when connected in parallel. Therefore, the total impedance of the load is equal to the resistance of the load, which is 120 ohms.

Reactive power (Q) can be calculated using the formula

Q = V^2 / X, where V is the voltage and X is the impedance.

Since the voltage is not given in the question, we cannot calculate the exact value of the reactive power. However, we can conclude that the total reactive power supplied by the load is directly proportional to the impedance and the square of the voltage.

In summary, the total reactive power supplied by the load is dependent on the voltage and can be determined using the formula Q = V^2 / X, where X is the impedance of the load.

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Answer: 6

Explanation:

Because it's 6 after the decimal

The following chemical equation 2C8H18(g)+ 25O2(g)→ 16CO2(g)+ 18H2O(g) is balance and 48.64 grams of oxygen is required in the combustion of octane in gasoline.

When burning of petrol happens and releases toxic hydrocarbons and carbon dioxide gasses with some amount of oxygen is known as combustion.

The balanced chemical equation is 2C8H18(g)+ 25O2(g)→ 16CO2(g)+ 18H2O(g),

                      number of moles = mass / molar mass

substituting the value in equation,

                      number of moles = 14 / 114g = 0.122 moles.

number of moles of oxygen 0.122 × 0.122 moles. = 1.52 moles.

                    1.52 = mass / 32

                      mass = 48.64 gram.

Therefore,48.64 grams of oxygen is required in the combustion of octane in gasoline.

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The balanced chemical equation would be as follows,

C8H18(g)+12.5 O2(g)→ 8 CO2(g)+ 9 H2O(g)

105.26  grams of oxygen are required to react with 14.0 grams of octane ( C8H18 ) in the combustion of octane in gasoline.

A chemical reaction is a process in which one or more substances, also known as reactants are converted to one or more different substances, known as products. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products

The balanced chemical equation would be as follows,\

C8H18(g)+12.5 O2(g)→ 8 CO2(g)+ 9 H2O(g)

114 grams of octane ( C8H18 ) require 400 grams of oxygen

1 gram of octane requires 400/114 grams of oxygen

30 grams of octane require 400/114×30 grams of oxygen

30 grams of octane require 105.26  grams of oxygen

Thus,105.26  grams of oxygen are required to react with 14.0 grams of octane ( C8H18 ) in the combustion of octane in gasoline.

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The pH of a 0.1 M solution of ethylamine will be approximately 8.50.

To determine the pH of a solution of ethylamine (C₂H₅NH₂), we need to consider the dissociation of ethylamine in water. Ethylamine acts as a weak base and can accept a proton (H⁺) from water to form the ethyl ammonium ion (C₂H₅NH₃⁺) and hydroxide ion (OH⁻). The equilibrium reaction is as follows:

C₂H₅NH₂ + H₂O ⇌ C₂H₅NH₃⁺ + OH⁻

The pKa of the ethyl ammonium ion is given as 10.70, which means that the equilibrium constant for the dissociation reaction is Kₐ = 10^(-pKa). Therefore, Kₐ = \(10^{(-10.70)}\).

In a 0.1 M solution of ethylamine, assuming complete dissociation, we can consider the concentration of ethylamine as the initial concentration since the reaction shifts mostly towards the products. Let's assume the concentration of ethylamine is [C₂H₅NH₂] = 0.1 M.

Since ethylamine is a weak base, we can assume that x moles of ethylamine react with x moles of water to form x moles of ethyl ammonium ion and x moles of hydroxide ion. At equilibrium, the concentration of the ethyl ammonium ion and hydroxide ion will be equal to x M.

Using the equilibrium constant expression;

Kₐ = [C₂H₅NH₃⁺] × [OH⁻] / [C₂H₅NH₂] × [H₂O]

Substituting the values;

\(10^{(-10.70)\\ }\) = x × x / (0.1 - x) × (0.1 - x)

Since x will be small compared to 0.1, we will approximate (0.1 - x) as 0.1;

\(10^{(-10.70)}\) ≈ x × x / (0.1 × 0.1)

Simplifying;

\(10^{(-10.70)}\) ≈ x² / 0.01

x² ≈ \(10^{(-10.70)}\) × 0.01

x ≈ √\(10^{(-10.70)}\) × 0.01)

x ≈ \(10x^{(-10.70/2)}\) × √0.01

x ≈ \(10^{(-5.35)}\) × 0.1

x ≈ 3.16 × 10⁻⁶ M

The concentration of ethyl ammonium ion and hydroxide ion at equilibrium is approximately 3.16 × 10⁻⁶ M.

To calculate the pH, we need to find the pOH of the solution. The pOH is given by the equation;

pOH = -log[OH⁻]

pOH = -log(3.16 × 10⁻⁶

pOH = -(-5.50) (approximating to two decimal places)

pOH = 5.50

Now, we will find the pH using the equation:

pH = 14 - pOH

pH = 14 - 5.50

pH = 8.50

Therefore, the pH of a 0.1 M solution of ethylamine is approximately 8.50.

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Nowadays, it is very important to reduce one's carbon "footprint" (how much carbon we produce in our daily lifestyles). By limiting the use of fossil fuels and instead turning to renewable sources of energy, we can significantly reduce our carbon emissions and mitigate the impacts of climate change.

One way to reduce our carbon footprint is by transitioning to renewable energy sources such as solar, wind, and hydropower. These sources of energy produce minimal greenhouse gas emissions compared to fossil fuels like coal, oil, and natural gas. Installing solar panels on rooftops, utilizing wind turbines, and supporting hydroelectric power can help generate clean and sustainable energy.

Another important aspect is adopting energy-efficient practices and technologies. This includes using energy-efficient appliances, LED lighting, and improving insulation in buildings to reduce energy consumption. Conserving energy in transportation by opting for public transportation, carpooling, biking, or walking can also make a significant difference.

Additionally, reducing waste and promoting recycling and composting can help minimize greenhouse gas emissions. Waste decomposition in landfills produces methane, a potent greenhouse gas. By reducing, reusing, and recycling materials, we can lower our carbon emissions and conserve resources.

Furthermore, making conscious choices in our daily lives can contribute to reducing our carbon footprint. This includes minimizing water usage, eating a plant-based diet or reducing meat consumption, and supporting sustainable and local products.

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Since the notebook and cubes are balanced at the same level on the scale, the mass of the notebook and sugar cubes are equal.

The correct option is C.

The amount of matter that makes up every object or body is the greatest way to understand mass. Everything that we can see has mass. Examples of objects with mass include a table, a chair, your bed, a football, a glass, and even air.

Masses are measured using scales.

The most typical way to measure it is as inertial mass, which refers to an object's resistance to acceleration under the influence of a net force.

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Complete question:

Ashley placed a notebook and sugar cubes on a scale.

The notebook and cubes are balanced at the same level on the scale.

Which of these describes the mass of the notebook and sugar cubes?

a. The mass of the notebook is greater than the mass of the sugar cubes

b. The mass of the notebook is less than the mass of the sugar cubes

c. The mass of the notebook is equal to the mass of the sugar cubes

Answer:

If the reactants in the chemical reactions are known, then the products can be predicted because the pattern of the chemical reactions is being followed. The pattern for a single replacement is A + BC --> AC + B. This is like the Hear It Pop Chemical Reaction which is also an example of the single replacement.

Explanation:

Answer:

should be 2M

Explanation:

:)

The electronic structure is defined by the movement of the electrons in the electrostatic field when the nuclei are in a stable state. It depicts both the energy and the wave function.

The electronic structure is the representation of the electrons, a sub-atomic particle in the orbitals and sub-shells of the atom. They follow various rules and principles to fill their energy levels.

The electronic structure depicts the electronic arrangement and organization within the atom and shows its property of electronegativity and size.

Therefore, the electronic structure is the arrangement of the electrons in the orbit.

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Answer:

Mixtures are one product of mechanically blending or mixing chemical substances such as elements and compounds, without chemical bonding or other chemical change, so that each ingredient substance retains its own chemical properties and makeup.

The pressure inside the vessel would be 15 atm if we increased the temperature of the vessel to 450 K at constant volume. As a result, Option D is right.

According to the Ideal Gas Law, the pressure inside the vessel is directly proportional to the temperature (Kelvin) and the number of moles of gas present in the vessel, if the volume is kept constant. In other words, if we increase the temperature of the gas, the pressure inside the vessel will also increase.

The Ideal Gas Law equation is:

Where:

Given that V is constant, we can rearrange the equation to solve for P:

Assuming that n and V are constants, then P is directly proportional to T. So, if the temperature increases by a factor of T2/T1, the pressure will increase by the same factor.

Let's say the initial pressure was 10 atm, and the initial temperature was 400 K. Then P1/T1 = 10 atm/400 K.

When the temperature is increased to 450 K, the pressure will become:

So, when the temperature of the vessel is increased to 450 K at constant volume, the pressure inside the vessel will increase, and the answer is "d. 15 atm".

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Answer:

2 homogenous mixture

Explanation:

To make a 50.0 mL solution of 1.7 M sodium carbonate (Na₂CO3), we need to determine the mass of Na₂CO3 required.

To calculate the mass of Na₂CO3 needed, we can use the formula:

Mass = Concentration x Volume x Molar Mass

First, we convert the given volume from milliliters to liters:

Volume = 50.0 mL = 50.0/1000 L = 0.05 L

Next, we substitute the given concentration and volume values into the formula:

Mass = 1.7 M x 0.05 L x Molar Mass of Na₂CO3

The molar mass of Na₂CO3 can be calculated by adding the atomic masses of sodium (Na), carbon (C), and three oxygen (O) atoms:

Molar Mass of Na₂CO3 = (2 x Atomic Mass of Na) + Atomic Mass of C + (3 x Atomic Mass of O)

After obtaining the molar mass value, we can substitute it into the formula and perform the calculation to determine the mass of Na₂CO3 required to make the 50.0 mL solution of 1.7 M sodium carbonate.

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In response to the question, 48.2 gram of CH4 contain 1.81*10²⁴ molecules of CH4.

A molecule is the simplest unit of any material that is composed of one or more elements and is capable of existing independently while maintaining all of the material's physical and chemical characteristics. Further atom division occurs within molecules. For instance, the symbols for the atom and molecule are O and O2, respectively.

Large biomolecules can be divided into four categories: lipids, proteins, nucleic acids, and carbohydrates. Monomers called oligosaccharides, which comprise oxygen, oxygen, or hydrogen, are the building blocks of carbs.

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The complete question is-

How many molecules of ch4 are in 48.2 g of this compound?

(a). 3.00

(b). 4.00

(c). 2.90*10²⁵

(d). 5.00*10²⁴

(e). 1.81*10²⁴

The described process is the six-electron reduction of Cr3+ ions to solid chromium (Cr) and solid selenium (Se). We can determine the accuracy of the following claims using the information provided:

G > 0: Under normal circumstances, the reaction is not spontaneous because it entails reducing Cr3+ ions to Cr, which requires energy input. G is hence positive.

S > 0: Without extra system knowledge, it is challenging to discern the sign of S. The total change in entropy (S) may, however, be little or even negative because the reaction results in the production of two solid products from two watery reactants.

Since G is positive, the reaction is reactant-favored and not product-favored. The claim that "The reaction is reactant-favored" is thus true.

Since the reaction involves the transfer of six electrons from Cr3+ to Se, the statement "n = 6 mol electrons" is accurate.

G > 0: Since the reaction is not spontaneous under normal circumstances, G is higher than zero.

The appropriate answers are thus:

The reaction is reactant-favored.

n = 6 mol electrons.

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