the law of conservation of energy cannot be created nor destroyed, it can only change form. if this is the case, why are we worried about energy sources in our world?

Given :

A cell of e.m.f  1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

\(I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A\)

Therefore, the current in the circuit is 0.5 A.

Answer:

it will increase the frequency of collisions between the two reactants

Explanation:

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When a parallel beam of α particles with fixed kinetic energy is normally incident on a piece of gold foil,

a) If 100 α particles per minute are detected at 20°, 3.200 α particles, 9.960 α particles, 2048 α particles, 320000 α particles will be counted at 40°, 60°, 80°, and 100° respectively.

b) If the kinetic energy of the incident α particles is doubled, 50.0 alpha particles per minute will be observed at 20.

c) If the same parallel beam of alpha particles with fixed kinetic energy is normally incident on a copper foil of the same thickness, 197.4 alpha particles per minute would be detected at 20°.

In 1911, Ernest Rutherford conducted an experiment in which he bombarded a thin sheet of gold foil with alpha particles and observed their scattering pattern. This experiment provided evidence for the existence of the atomic nucleus and helped to establish the structure of the atom. In this question, we will use the principles of Rutherford scattering to determine the number of scattered alpha particles at various angles for a fixed kinetic energy and for different materials.

(a) The number of scattered alpha particles at an angle θ can be calculated using the Rutherford scattering formula:

dN/dΩ = (N1 * Z2² * e^4)/(16πε0² * E^2 * sin⁴(θ/2))

where dN/dΩ is the number of scattered alpha particles per unit solid angle, N1 is the number of incident alpha particles per unit time, Z2 is the atomic number of the target material, e is the elementary charge, ε0 is the electric constant, E is the kinetic energy of the incident alpha particles, and θ is the scattering angle.

For a fixed kinetic energy, N1 is constant, so we can compare the number of scattered alpha particles at different angles by comparing the values of sin^4(θ/2) for each angle. Using this formula, we can calculate the number of scattered alpha particles at 40°, 60°, 80°, and 100°, given that 100 alpha particles per minute are detected at 20°. The calculations are as follows:

dN/dΩ(20°) = 100 alpha particles per minute

sin^4(20°/2) = 0.03125

dN/dΩ(40°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(40°/2) = 100 * 0.03125 / 0.98438 = 3.200 alpha particles per minute

dN/dΩ(60°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(60°/2) = 100 * 0.03125 / 0.31641 = 9.960 alpha particles per minute

dN/dΩ(80°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(80°/2) = 100 * 0.03125 / 0.01563 = 2048 alpha particles per minute

dN/dΩ(100°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(100°/2) = 100 * 0.03125 / 0.00098 = 320000 alpha particles per minute

(b) If the kinetic energy of the incident alpha particles is doubled, the Rutherford scattering formula becomes:

dN/dΩ = (N1 * Z2² * e⁴)/(16πε0² * 4E² * sin⁴(θ/2))

The number of scattered alpha particles at 20° can be calculated using this formula with N1 doubled. The calculation is as follows:

dN/dΩ(20°) = (2 * 79² * (1.6022 x 10⁻¹⁹)⁴)/(16π(8.8542 x 10⁻¹²)^2 * 4 * (2E6)² * sin⁴(20°/2)) = 50.0 alpha particles per minute.

c) dN/dΩ = (N1 * Z2² * e⁴)/(16πε0² * E² * sin⁴(θ/2)) * (ρAu/ρCu)²

where ρAu is the density of gold and ρCu is the density of copper.

Since the thickness of the foil is the same, we can assume that the number of atoms per unit area is the same for both gold and copper foils. Therefore, N1 is the same for both cases.

Using the given values of ρAu = 19.3 g/cm³ and ρCu = 8.9 g/cm³, the ratio (ρAu/ρCu)²is:

(ρAu/ρCu)² = (19.3/8.9)² = 8.031

Substituting the values of N1, Z2, e, ε0, E, θ, and (ρAu/ρCu)² into the modified Rutherford scattering formula, we can calculate the number of scattered alpha particles at 20° for the copper foil:

dN/dΩ(20°) = (100 * 29² * (1.6022 x 10⁻¹⁹)⁴)/(16π(8.8542 x 10⁻¹²)² * (2E6)² * sin⁴(20°/2)) * 8.031 = 197.4 alpha particles per minute

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The maximum angle above the horizontal with which a projectile can be thrown can be found by considering the concept of range. The range of a projectile is the maximum horizontal distance it can cover before returning to the ground.

The range is maximum when the projectile is thrown at an angle of 45 degrees above the horizontal.

So, the maximum angle above the horizontal with which a projectile can be thrown is 45 degrees. It is worth noting that air resistance can affect the trajectory and the range of a projectile, but as per the problem statement, air resistance has been ignored.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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On electromagnetic force:

The interaction of electrically charged particles with the corresponding electric and magnetic fields is the subject of the area of physics known as electromagnetism. It examines the connections between and interactions between electricity and magnetism.

Electric fields, magnetic fields, electromagnetic waves, and the behavior of charged particles in electric and magnetic fields are only a few examples of the many phenomena that fall under the umbrella of electromagnetism.

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Answer:

we need more info

Explanation:

The energy delivered to the toaster is approximately 518,400 J or 518.4 kJ.

The energy delivered to the toaster can be calculated as the product of the power and time, or P × t.

The power, P, can be calculated using Ohm's law, which states that P = V^2 / R, where V is the voltage and R is the resistance.

Plugging in the values, we get

P = (120 V)^2 / (14 W)

P = 8640 W

Since the toaster was operated for one minute, or 60 seconds, the energy delivered to the toaster can be calculated as:

E = P × t

E = 8640 W × 60 s

E = 518400 J

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Answer:

d = 303.33 m

Explanation:

Given that,

Acceleration of Doc Brown is 2.52 m/s²

The initial speed of Doc Brown is 0 as it was at rest.

Final speed of Doc Brown is 39.1 m/s

We need to find the distance between he and Marty. Let the distance is d. Using equation of motion as follows :

\(v^2-u^2=2ad\\\\\text{Put u = 0}\\\\d=\dfrac{v^2}{2a}\\\\d=\dfrac{(39.1)^2}{2\times 2.52}\\\\d=303.33\ m\)

So, the distance between he and Marty is 303.33 m.

Answer:

A

Explanation:

Because plants cant move and animals can.

The characteristic which describes an organism of kingdom Animalia is able to move on its own when compared to the plants kingdom. Thus, the correct option is A.

Animals are the multicellular, eukaryotic organisms in the biological kingdom Animalia. Animals are the organisms which consume organic material, breathe oxygen gas, are able to move on their own, can reproduce sexually and produce organisms which contain genetic information which is recombination of both the parents, and these organisms go through an ontogenetic stage in which their body consists of a hollow sphere of the cells, the blastula, during the embryonic development of organisms.

Organisms belong to Animal kingdom show some characteristics which are not found in the organisms which belong to the plant kingdom including movement. Animals can move on their own while plants cannot.

Therefore, the correct option is A.

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Answer:

61.62 N/m

Explanation:

Applying,

1/F = 2π\(\sqrt{m/k}\).................. Equation 1

Where F = frequency, m = mass of the spring, k = spring constant, π = pie.

make k the subject of the equation

k = m(2πF)²............... Equation 2

From the question,

Given: m = 1.00 kg, F = 1.25 Hz

Constant: π = 3.14

Substitute these values into equation 2

k = 1(2×3.14×1.25)²

k = 61.62 N/m

The two equal-mass objects will stick together and move as one object after the completely inelastic collision.

In an inelastic collision, the two objects involved stick together and move as a single object after the collision. Since the objects have equal masses and are moving towards each other at equal speeds, their momenta will be equal and opposite before the collision.

During the collision, the objects come into contact and exert forces on each other. These internal forces cause the objects to deform and redistribute their velocities. However, due to the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision.

Since the initial momenta of the objects are equal and opposite, the final momentum of the combined object will also be zero. This means the objects will stick together and move as one object after the collision, with a common velocity. This scenario is known as a completely inelastic collision.

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Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

It's on Edge

Taking into account the definition of Avogadro's Number, 5.029×10²⁴ atoms of zinc are in 8.35 moles.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: If 1 mole of zinc contains 6.023×10²³ atoms, 8.35 moles of zinc contains how many atoms?

amount of atoms of zinc= (6.023×10²³ atoms× 8.35 moles)÷ 1 mole

amount of atoms of zinc= 5.029×10²⁴ atoms

Finally, 5.029×10²⁴ atoms of zinc are in 8.35 moles.

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Answer:

The branch of biology that deals with the normal functions of living organisms and their parts.

Answer:

W = F × d

W = 15 × 3

W = 45 Joules

Hi, you did not enter the text about the Suarez family, which makes it impossible for this question to be answered accurately. However, from the context of your question, it is possible to see that you want to know two positive and negative points that the Suarez family would observe when starting a planting of organic agriculture.

Among the negative points, we can say that organic agriculture has a high cost, as the techniques used in it require a greater number of resources, which can make not only the service more expensive, but also the product. A second negative point is that the techniques used in organic agriculture are more difficult than the techniques used in conventional agriculture, since all management of organic crops must be carried out without the application of chemical products.

Among the positive points, we can say that the growing number of consumers of organic products can increase the profit that the family will have from the sale of these products. In addition, the family will have healthier, less polluted and more productive land.

Answer:

Sample response: Organic farming would have higher costs, and would be more complex than conventional farming. However, the Suarez family could charge a higher price for organic produce. This type of farming also would be better for the land.

Explanation:

The correct answer is 70 meter displacement in the east.

Let's assume that he departs from point O and follows the path ABC.

The man's displacement will be revealed if we join the start and end points of the path he took.

O's distance from A is 40 meters.

70 meters separate A and B.

From B to C, it is 40 meters.

Distance from B to C equals the distance between O and A.

We're looking for the displacement, which is the separation between points O and C.

The opposing sides of a rectangle are equal. Hence A to B is separated by the distance from O to C.

Distance from A to B equals displacement.

70 meter displacement in the east.

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Answer:

temperature inside the balloon so it is warmer than the surrounding air

Explanation:

For the balloon to get an uplift , it should be lighter than air . That means the density of the gas inside should be less than the density of air outside . only then ,  weight of the balloon plus the weight of the air inside balloon  will become less than the weight of displaced air outside . This can be achieved by warming up the air inside. Its temperature must exceed that of outside air.

The option that best explain how the pilot can make the balloon rise is option D. The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air

An object will float in air when the density of the object is lower than the density of the air.

Increase in temperature of a gas decreases the density of the gas.

For the pilot to make the balloon rise, he must find a way to make the balloon more lighter than air. To do this, he has to increase the temperature of the balloon.

In this question, the pilot can increase the temperature inside the balloon so it is warmer than the surrounding air in order for the balloon to quickly rise several feet higher above some trees in distance.

Therefore, option D best explain how the pilot can make the balloon rise.

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One second later its speed in meters per second is approximately a. 40 m/s.

Given that a heavy object is moving upward at 50 meters per second, we need to determine its speed one second later. To do this, we will consider the effects of gravity on the object's motion.

Gravity exerts a force on the object which causes it to decelerate. On Earth, the acceleration due to gravity is approximately 9.8 meters per second squared (m/s²) acting downwards. As the object is moving upwards, the gravitational force will reduce its speed by 9.8 m/s every second.

After one second, the object's speed will be reduced by 9.8 m/s. Therefore, the new speed can be calculated as follows:

Initial speed - deceleration due to gravity = New speed
50 m/s - 9.8 m/s = 40.2 m/s

Based on the available options, the closest approximation to the object's speed after one second is 40 m/s (option a).

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Answer:

The tin fork and knife, the copper coin, and the steel fence pole.

Explanation:

Those are both what people would call soft metals so they are malleable to the extent of probably not needing heavy duty equipment. It depends on you description of malleable because the steel fence pole could be malleable with the correct equipment and not snap in half if bent slowly enough.

The definition of malleable: (of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking.

But the glass table, marble sculpture and antique ceramic vase are nowhere near malleable because if you tried bending them they wouldn't bend but would shatter and break into pieces.

The tin fork and knife, the copper coin, and the steel fence pole are malleable, the correct option is A, C, and F.

A malleable material is one that can be easily formed into a thin sheet by hammering. The most malleable metal is gold. In contrast, ductility is a solid material's ability to deform under tensile stress.

Metals are malleable because when a force is applied, layers of ions can slide over each other. Metallic bonding allows metal to change shape without breaking.

Gold, iron, aluminum, copper, silver, and lead are examples of malleable metals. Ductility and malleability do not always correlate; for example, gold is both ductile and malleable, whereas lead is only malleable.

Tin fork and knife, copper coin, and steel fence pole are all malleable.

Thus, the correct options are A, C, and F.

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A particle composed of three quarks is classified as a Baryon. They are not to be confused with mesons, which are made up of two quarks.

Baryons are a class of particles that include protons and neutrons, which are composed of three quarks. Mesons are a class of particles made up of two quarks, whereas leptons, such as electrons, do not contain quarks at all. Photons are particles of light, which have no mass and are not made up of quarks.

Antiparticles are the opposites of particles and can be made up of quarks or other subatomic particles. Baryons are identified as particles that contain three quarks, and these quarks are held together by a strong nuclear force. The protons and neutrons in atomic nuclei are examples of baryons. The three quarks that makeup baryons can be the same or different types of quarks, depending on the specific particle being considered.

Therefore,  the Baryons are particles that consist of three quarks, which are held together by strong nuclear force. They include protons and neutrons and are not to be confused with mesons, which are composed of two quarks.

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The correct condition for rolling without slipping is v = rw

Hence, the correct option is C.

The correct condition for rolling without slipping is

v = rw

In this equation:

v is the linear velocity of the center of mass,

r is the radius of the rolling object, and

w is the angular velocity (angular speed) of the rolling object.

This equation states that the linear velocity of the center of mass is equal to the product of the radius and the angular velocity.

In order for an object to roll without slipping, the linear velocity of the center of mass must match the speed at which the object is rotating around its axis. This ensures that there is no slipping between the object and the surface it is rolling on.

Therefore, The correct condition for rolling without slipping is v = rw

Hence, the correct option is C.

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The bed slope required to produce the same tractive force on the bed with a discharge of 365 million m³/day can be determined using the given equation for mean velocity variation.

Bed width (B) = 600 m

Initial discharge (Q1) = 120 million m³/day

Initial bed slope (S1) = 7.5 cm/km

The equation for mean velocity (v) = 120 y^(2/3), where y is the water depth.

To find the bed slope (S2) for a new discharge (Q2) of 365 million m³/day, we need to equate the tractive force on the bed for both scenarios.

The tractive force on the bed can be represented as:

Tractive force =\((Rho * g * S * B * v^2) / (R * D50)\)

where:

Rho is the density of water,

g is the acceleration due to gravity,

S is the bed slope,

B is the bed width,

v is the mean velocity, and

R and D50 are constants.

Since we are comparing two scenarios with the same tractive force, the following equation can be formed:

\((Rho * g * S1 * B * v1^2) / (R * D50) = (Rho * g * S2 * B * v2^2) / (R * D50)\)

Simplifying the equation:

\(S1 * v1^2 = S2 * v2^2\)

Substituting the given values:

\(S_1 * (120 y_1^{(2/3))^2 = S_2 * (120 y_2^{(2/3))^2\)

Rearranging the equation:

\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)

We know that Q = B * v * y, where Q is the discharge. Rearranging this equation gives:

\(v = Q / (B * y)\)

Substituting the values for Q1 and Q2, we have:

\(v1 = 120 million / (B * y1)\)

\(v2 = 365 million / (B * y2)\)

Substituting the expressions for v1 and v2 in the equation from step 7:

\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)

\(= S_1 * (120^2 * y_1^{(4/3)}) / (120^2 * y_2^{(4/3)})\)

\(= S_1 * (y_1^{(4/3)} / y2^{(4/3)})\)

Since the bed material just begins to move when Q = 120 million m³/day, the velocity can be expressed as \(v = v_1 = 120 y1^{(2/3)}.\)

Therefore, the equation for S2 becomes:

\(S_2 = S_1 * (y_1^{(4/3)} / y_2^{(4/3)})\)

=\(S_1 * (120^{(4/3)} * y_1^{(4/3) }/ (120 y_2^{(2/3)})^{(4/3))\)

\(= S_1 * (120^{(4/3)} * y1^{(4/3)} / (120^{(4/3)} * y2^{(4/3)}))\)

\(= S_{1 * (y_1^{(4/3)} / y_2^{(4/3)})\)

Finally, substituting the values for y1 and y2:

\(S_2 = S_1 * (y_1^{(4/3) }/ y_2^{(4/3)})\)

= \(S_1 * (y_1^{(4/3)} / (365 / 120)^{(4/3)})\)

Now, you can substitute the values for y1, and S1, and calculate S2 accordingly.

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Answer:

Crust

Explanation:

Answer:

I kinda dont remember the 1st law so search it up on

and it should tell u , but if u need any help from the

Answer:

a) 103.32 m

b) 9.18 s

Explanation:

a) Let's use the knowledge that at the top of its trajectory, the baseball will have a final velocity of 0 m/s.

The acceleration due to gravity is -9.8 m/s², assuming the upwards direction is positive and the downwards direction is negative.

The initial velocity of the baseball is 45 m/s.

We are trying to find the vertical displacement of the baseball, Δx, and we have the variables v, a, and v₀.

Find the constant acceleration equation that contains all four of these variables:

Substitute the known values into the equation.

The maximum height of the ball before it falls back down is 103.32 m.

b) Now we want to solve for time t. Find a constant acceleration equation that contains three known variables.

Substitute known values into this equation.

Remember that this is only half of the baseball's flight since we are using the final velocity for when the ball is halfway through its trajectory.

To solve for the total time the baseball is in the air, double the time t we solved for.

The baseball is in the air for 9.18 s.