The last 4 miles in the activity series of metals are commonly referred to as the "coinage medals". Why would these metals be chosen over more active metals for the use in coins? Why do you think some more active metals, such as zinc or nickel, or sometimes used in coins?

Answers

Answer 1

Coinage metals, which typically include copper, silver, and gold, are chosen over more active metals for use in coins because they are less reactive and more resistant to corrosion.

This ensures durability and preserves the appearance of the coins. Some more active metals like zinc or nickel are sometimes used in coins due to their lower cost and availability, while still maintaining adequate resistance to corrosion and wear for everyday use.

The reason why the last 4 miles in the activity series of metals, which are gold, silver, platinum, and palladium, are commonly referred to as the "coinage medals" is because they are highly resistant to corrosion and have a low reactivity towards other chemicals, making them ideal for use in coins. These metals are also very rare and valuable, which adds to their appeal as a currency.

More active metals such as zinc or nickel are sometimes used in coins because they are more abundant and less expensive than the "coinage metals". However, these metals tend to be more reactive and therefore more prone to corrosion and other chemical reactions, which can affect the appearance and value of the coins over time. Additionally, the use of these metals in coins is often limited to lower denominations or commemorative coins, rather than as a standard currency.

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Answer 2

The "coinage metals" are typically gold, silver, copper, and platinum, which are the last 4 metals in the activity series. These metals are chosen over more active metals for use in coins because they are relatively unreactive and do not corrode easily, making them ideal for coins that need to be durable and long-lasting. Additionally, these metals have been historically valued and used as currency, making them culturally significant as well.

However, some more active metals such as zinc or nickel are sometimes used in coins because they are cheaper and more readily available than the coinage metals. These metals may be used as an alloy with the coinage metals to make coins more affordable, or they may be used as a substitute for the more expensive metals in lower denomination coins. However, these metals are not as durable as the coinage metals and may corrode more easily, leading to shorter lifespans for the coins.

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Related Questions

A barometer measures the pressure of the atmosphere at different altitudes. Identify the location where the column of mercury is lowest in the barometer.

A barometer measures the pressure of the atmosphere at different altitudes. Identify the location where

Answers

The location where the mercury level of the barometer would be the lowest is at the very high altitudes of the Earth's atmosphere (about 100 km), since air pressure decreases as altitude increases.

Answer:

the mercury would be lowest at location 4.

Explanation: this is because pressure and altitudes have inverse relationship at the troposphere. higher altitude has lower pressure. also pressure at location 4 contribute to pressure at location 1. but pressure at location 1 do not contribute to pressure at location 4.

What is a food chain? what does it show?

Answers

Answer:

A food chain shows how energy is transferred from one living organism to another via food. ... When these animals eat these plant products, food energy and organic compounds are transferred from the plants to the animals.

72.A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to reach the endpoint of the titration. The concentration (M) of the acid was __________.

Answers

Given data: Volume of HCl = 25.5 mL Volume of NaOH = 51.2 mL Concentration of NaOH = 0.113 M. We need to find the concentration of HCl. Let's calculate the number of moles of NaOH present in 51.2 mL of the solution using the formula: Moles of solute (NaOH) = concentration (M) × volume (L)Moles of NaOH = 0.113 M × 51.2 mL / 1000 mL= 0.0057976 mol

Now we know that according to the balanced chemical equation for the reaction between NaOH and HCl: HCl + NaOH → NaCl + H2OOne mole of NaOH reacts with one mole of HCl. So, the number of moles of HCl is also 0.0057976 mol.Let's calculate the concentration of HCl. Concentration (M) of HCl = Moles of HCl / Volume of HCl (in L)Volume of HCl = 25.5 mL = 25.5 / 1000 L= 0.0255 LMoles of HCl = 0.0057976 mol Concentration of HCl = 0.0057976 mol / 0.0255 L= 0.227 M Therefore, the concentration (M) of the HCl solution is 0.227 M.

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a compound with the empirical formula NH2 was found to have a molar mass of 32.05g. what is the molecular formula?

Answers

The molecular formula for the compound is \(N_{2}H_{4}\).

How to determine the molecular formula?

The empirical formula gives you the simplest whole-number ratio of atoms in a molecule or compound. The molecular formula gives you the actual number of atoms of each element in a molecule or compound.

To determine the molecular formula of a compound with the empirical formula  \(NH_{2}\) and a molar mass of 32.05 g/mol, follow these steps:

1. Calculate the molar mass of the empirical formula  \(NH_{2}\):
  - Molar mass of Nitrogen (N) = 14.01 g/mol
  - Molar mass of Hydrogen (H) = 1.01 g/mol
  - Molar mass of  \(NH_{2}\) = (1 x 14.01) + (2 x 1.01) = 16.03 g/mol

2. Divide the given molar mass (32.05 g/mol) by the molar mass of the empirical formula (16.03 g/mol):
  - Ratio = 32.05 g/mol / 16.03 g/mol ≈ 2

3. Multiply the empirical formula by the ratio to get the molecular formula:
  - Molecular formula = \(NH_{2}\) * 2 = \(N_{2}H_{4}\).

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The molar mass of aluminum oxide (Al2O3) is 102.0 g/mol. What is the correct way to write the inverted molar mass of aluminum oxide as a conversion factor?
StartFraction 102.0 grams upper A l subscript 2 upper O subscript 3 over 1 mole upper A l subscript 2 upper O subscript 3 EndFraction.
StartFraction 1 mole upper A l subscript 2 upper O subscript 3 over 102.0 grams upper A l subscript 2 upper O subscript 3 EndFraction.
StartFraction 1 mole upper A l subscript 2 upper O subscript 3 over 1 gram upper A l subscript 2 upper O subscript 3 EndFraction.
StartFraction 102.0 moles upper A l subscript 2 upper O subscript 3 over 102.0 grams upper A l subscript 2 upper O subscript 3 EndFraction.

Answers

The correct way to write the inverted molar mass of aluminum oxide (Al2O3) as a conversion factor is: Start Fraction 1 mole upper A l subscript 2 upper O subscript 3 over 102.0 grams upper A l subscript 2 upper O subscript 3 EndFraction.

The inverted molar mass of a substance is obtained by taking the reciprocal of its molar mass. In this case, the molar mass of aluminum oxide is given as 102.0 g/mol. To write the inverted molar mass as a conversion factor, we place 1 mole of Al2O3 in the numerator and the molar mass of Al2O3 (102.0 grams) in the denominator. This conversion factor allows us to convert between the number of moles and the mass of Al2O3.

In more detail, the conversion factor can be expressed as follows:

1 mole Al2O3 / 102.0 grams Al2O3

This means that for every 102.0 grams of aluminum oxide, there is 1 mole of aluminum oxide. Conversely, if we have a given mass of Al2O3, we can use this conversion factor to determine the corresponding number of moles, or vice versa. The conversion factor allows us to convert between the mass and the molar quantity of aluminum oxide, enabling us to perform calculations involving moles and grams of the substance.

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50 POINTSSSSS

LOOK AT PIC
-Does it look like i am doing this correct?? Also is 1.12 A ionic bond or is it a Polar covalent bond? ANSWER FAST PLEASE!!

50 POINTSSSSSLOOK AT PIC-Does it look like i am doing this correct?? Also is 1.12 A ionic bond or is

Answers

1.ONCl is polar covalent compound.

2.H₂O₂ is polar covalent compound.

3.C₂H₄ is non polar covalent compound.

4. O₂ is non polar covalent compound.

5.CH₂S is an ionic compound.

What is ionic and covalent compound ?

In most cases, ionic compounds are created when a metal interacts with a nonmetal. The reaction between two nonmetals produces covalent compounds. Binary compounds containing hydrogen are typically covalent compounds since hydrogen is a nonmetal.

Because of the largely minor difference in electronegativity, the covalent bond is sometimes referred to as nonpolar. It also implies that there is no charge gap between the two atoms or that their electronegativity is identical.

Two oxygen atoms make up one oxygen molecule. Two covalent connections, one of which is a sigma bond and the other a pi bond, are formed when each O atom shares its two electrons.

Thus,  O₂ is non polar covalent compound.

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68.19g of magnesium phosphite from mass to grams

Answers

Magnesium phosphite is a white or off-white crystalline compound with a chemical formula of Mg3(PO3)2. It is a strong reducing agent and reacts violently with water, producing toxic fumes of phosphorus oxides. It is commonly used in the manufacture of fertilizers, insecticides, and herbicides.

In this problem, we have 68.19 g of magnesium phosphite, and we need to convert it to grams. The first step is to determine the molar mass of magnesium phosphite. Magnesium has a molar mass of 24.31 g/mol, phosphorus has a molar mass of 30.97 g/mol, and oxygen has a molar mass of 16.00 g/mol. Therefore, the molar mass of magnesium phosphite is:Mg3(PO3)2 = (3 x 24.31 g/mol) + (2 x 31.00 g/mol) + (6 x 16.00 g/mol) = 262.00 g/molNext, we can use the molar mass to convert the given mass of magnesium phosphite to moles:68.19 g Mg3(PO3)2 x (1 mol / 262.00 g) = 0.2605 mol Mg3(PO3)2Finally, we can convert moles to grams by multiplying by the molar mass:0.2605 mol Mg3(PO3)2 x 262.00 g/mol = 68.19 gTherefore, 68.19 g of magnesium phosphite is equal to 0.2605 moles of magnesium phosphite, and its mass is equal to 68.19 g.

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the normal boiling point of mercury (hg) is 356.7 °c. what is the vapor pressure of mercury at 340.5 °c in atm? (∆hvap = 58.51 kj/mol)

Answers

The vapour pressure of mercury at 340.5°C in atm is 1.06 x 10^(-13)  atm

The normal boiling point of mercury is 356.7 °C.

Given that, the ∆Hvap of mercury = 58.51 kJ/mol

We know that at boiling point, the vapour pressure of the substance is 1 atm and with the increase in temperature, the vapour pressure of the substance also increases. We can use Clausius-Clapeyron Equation to calculate the vapour pressure of mercury at 340.5°C.

Clausius-Clapeyron equation is given by :

log(P2/P1) = - ∆Hvap/R [1/T2 - 1/T1]

Where, P1 = vapour pressure at boiling point of mercury = 1 atm

T1 = boiling point of mercury = 356.7 °C = 629.85 K

T2 = 340.5 °C = 613.65 K

∆Hvap = 58.51 kJ/mol

R = gas constant = 0.0821 L atm/mol K

On substituting the values,

log(P2/1) = - 58510/(0.0821 ) x [1/613.65 - 1/629.85]

log(P2) = 29.87

(P2) =1.06 x 10^(-13)  atm

Thus, the vapour pressure of mercury at 340.5 °C is 1.06 x 10^(-13)  atm(approx).

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which probing question lies within the scope of physics

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A probing question that lies within the scope of physics could be: "What is the nature of dark matter and dark energy, and how do they influence the expansion of the universe?

Dark matter and dark energy are hypothetical forms of matter and energy that are believed to exist based on their observed gravitational effects on galaxies and the expansion of the universe.

Dark matter is thought to be a type of matter that does not interact with light or other electromagnetic radiation, while dark energy is an unknown form of energy that is causing the universe to expand at an accelerated rate.

Exploring the nature of dark matter and dark energy falls under the purview of physics because it involves understanding the fundamental forces and particles that govern the behavior of the universe.

Physicists study these phenomena by analyzing the gravitational effects they have on visible matter, conducting experiments to detect dark matter particles, and developing theoretical models to explain their properties and interactions.

Addressing this probing question requires the application of various branches of physics, such as cosmology, astrophysics, particle physics, and quantum mechanics.

Researchers employ observational data, theoretical frameworks, and advanced technologies to investigate the nature and origin of dark matter and dark energy, contributing to our understanding of the fundamental nature of the universe and its evolution.

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What are the solutions to problems caused by nitrogen gas in solution at certain depths?

Please Help!!!! 50 points

Answers

The solutions to problems caused by nitrogen gas in solution at certain depths is by discouraging deep diving.

What is Diving?

This involves moving around under water with the aid of special breathing equipment.

Limiting the depth of a dive should he encouraged as the maximum depth limit for a diver to use compressed air is 30 to 50 meters.

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when an acid such as hcl reacts with a metal, such as zinc (shown here) the gas produced is

Answers

When an acid such as hydrochloric acid (HCl) reacts with a metal like zinc (Zn), the gas produced is hydrogen gas (H₂).

When hydrochloric acid (HCl) reacts with zinc (Zn), something interesting happens. The acid gives away its hydrogen atoms (H⁺) to the zinc. At the same time, the zinc gives away some of its electrons. As a result, hydrogen gas (H₂) is produced. The gas forms little bubbles that you might see during the reaction. The remaining zinc combines with the chlorine atoms (Cl⁻) from the acid to form zinc chloride (ZnCl₂). So, to sum it up, when acid (like HCl) and metal (like zinc) react, they create hydrogen gas and a compound called zinc chloride. The hydrogen gas bubbles out, and the zinc chloride dissolves in the remaining acid.

A single displacement reaction, also known as a metal-acid reaction, occurs when hydrochloric acid (HCl) and zinc (Zn) are in contact. This reaction results in the creation of zinc chloride (ZnCl₂) and hydrogen gas (H₂) as the zinc metal displaces the hydrogen in the hydrochloric acid. While the acid's hydrogen ions lose electrons and undergo oxidation, the zinc atoms acquire electrons and undergo reduction. It is a redox (reduction-oxidation) reaction because it includes both oxidation and reduction reactions.

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Which option describes a benefit of rotating crops?
Responses

maintains nutrient levels in soil
helps irrigate the crops
prevents weed from growing in the crops
makes the soil more organic

Answers

Crop rotation is the technique of planting crops in a different area of the garden so that no single crop will be planted in the same place two—or more—years in a row.

Crop rotation aids in preserving the structure and nutrient content of the soil as well as helping to keep pests that are carried by the soil from colonizing the garden.

As the same nutrients are repeatedly consumed when a single crop is planted in the same location each year, the soil structure slowly deteriorates. After a while, the soil loses those particular nutrients and becomes unhealthy. At the same time, insect pests that feed on a single crop and spend their larval stage in the soil multiply as long as their food supply is still present. As their number grows, these pests get harder to control every year.

There are four key benefits of crop rotation: (1) Plants that fix nitrogen, like legumes and peas, enhance the quality of the soil for subsequent vegetable plantings in the same bed. (2) Plants with shallow and deep roots alternately extracted nutrients from the soil at various depths. (3) Because their food source is not in the same place each year, soilborne pests that feed on a particular plant family are inhibited. (4) Farmers and gardeners that use crop rotation don't have to leave their fields or beds fallow as frequently as they might otherwise.

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how many grams of c are in 34.00 grams of propane c3h8

Answers

Answer:

There are 2.34×1023 atoms C 2.34 × 10 23 a t o m s C in 5.72 g of propane. To determine the number of carbon atoms in 5.72 grams of propane we.

Explanation:

the movement carbon from which reservoir to another has the greatest potential to affect earth's climate
PLEASE HELP

Answers

The movement of carbon across oceans has the greatest potential to affect earth's climate

What  are Carbon reservoirs?

Carbon reservoirs are the parts of the Earth that store carbon, such as the ocean. Other examples of carbon reservoirs are the soil, land vegetation and the atmosphere. More so, fossil fuels are large reservoirs.

Carbon moves through nature in a balanced way. It moves from one reservoir to another in a carbon cycle. More so, the amount of carbon naturally released tends to be the same as the amount naturally absorbed. This so-called carbon balance allows life to thrive on the planet.

The ocean is there­fore the greatest of the carbon reservoirs, and essentially determines the atmospheric CO₂ content. The carbon, however, requires centuries to penetrate into the deep ocean, because the mixing of the oceans is a rather slow.

Therefore, the movement of carbon across oceans has the greatest potential to affect earth's climate

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What is the difference between dissolving and dissociating and how does this relate to the van't hoff factor?

Answers

Solvation is the process of dissolving.

Dissociation is the separation of a substance into charged components during dissolution.

What is the difference between dissolving and dissociating?

Dissolution (dissolving), which simply refers to becoming solvated by the solvent, is a subset of dissociation, which is particularly the separation of two charged ions in solution. When the solvent completely envelops each individual solute molecule, solvation takes place. By definition, something that is dissociated in a solvent must be dissolved in it. For instance, the salt dissociates in water, which is how it dissolves in water. In water, ethanol dissolves but does not dissociate; it remains ethanol.

How does Van't Hoff's factor work?

The Van't Hoff factor is a tool used to compare the real number of moles of solute injected to create a solution to the apparent amount produced by colloidal characteristics.

What is the Van't Hoff factor's value?

Van't Hoff factor's value is:-

No association or dissociation                  i=1 Dissociation                                             i<1 Association                                               i>1

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13. In the reaction: A + B = C, if 4.2 grams of A react to make 6.8 grams of C, then how many grams of B were reacted? Hint: Mass, like charge and energy, is conserved in all reactions. pls i need quick help

Answers

2.6 grams because A equals 6.8 and C is the final answer of the equation so you would subtract the answer from a which gives you 2.6 grams

Answer:

Hit me with brainlist pls

Explanation:

A equals 6.8 and C is the final answer of the equation so you would subtract the answer from a which gives you 2.6 grams

what component in the solar cell provides electrons to replace the electrons released by the dye?

Answers

The component in the solar cell system which provides electrons to replace the electrons released by the dye simply is the graphite layer.

How the graphite layer release electrons to replace the dye electrons

The graphite layer is one of the major parts oth the solar cell. It help in the provision of electrons by acting as a counter electrode within the electrolyte. In order, this layer is part responsible for replacing electrons produced by dyes.

In conclusion, we can now confirm from all said and done from above that the solar cell too has a way of producing electrons.

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How many liters of HCI at STP are produced from 150.0 g of chlorine gas?

Answers

Answer:

As we know that

At STP

1 mole of any gas occupies 22.4L  

so

15.7L / 22.4L/mole = 0.7moles Cl2  

0.7moles x 6.022x10^23molecules/mole = 4.22x10^23molecules

hope it helps

what chromatographic method should make it possible to isolate pure a and b chains?

Answers

Size-exclusion chromatography (SEC) is a suitable chromatographic method for isolating pure a and b chains.

SEC is a technique that separates molecules based on their size. In this case, the a and b chains can be separated from other components based on their molecular weight. SEC columns have porous beads that allow smaller molecules to enter and travel through the beads, while larger molecules are excluded and elute first. By choosing an appropriate SEC column, the a and b chains, which typically have different molecular weights than other components, can be isolated and collected separately. This method ensures the purity of the isolated a and b chains.

Size-exclusion chromatography (SEC) is a useful chromatographic method for isolating pure a and b chains. The technique separates molecules based on their size, and by utilizing a suitable SEC column, the a and b chains can be separated from other components due to their distinct molecular weights. This approach guarantees the purity of the isolated a and b chains, making it an effective method for their isolation.

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Approximately how many times greater is the diame-
ter of an atom than the diameter of its nucleus?
Knowing that most of an atom's mass is contained in
the nucleus, what can you conclude about the density
of the nucleus?

Answers

A typical atom's diameter is 10,000 times greater than its nucleus' diameter, and the nucleus is where the majority of the mass and density of the atom are concentrated.

Nucleus :

At the center of each atom, there is a tiny, dense area known as the nucleus. It has a net positive charge because it is made up of positive protons and neutral neutrons. Although the nucleus only makes up a very small portion of the atom, it is where almost all of its mass is found.

A positively charged nucleus and one or more negatively charged particles known as electrons make up an atom. The atom has no excess of electrons because the positive charges cancel out the negative charges, making it electrically neutral.

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Describe the appropriate way to smell an unknown substance in the lab.

Answers

Answer:

smelling it without glasses or putting your face/nose really close to the substance

Explanation:

You waft it and try to smell it without holding it directly to your face

a. at a particular temperature, the pka of isobutyric acid (present in certain seeds including carob and vanilla) is 4.87. what is the ph of a 0.10 m solution of isobutyric acid acid?

Answers

It is an n-butyric acid isomer. It falls within the category of a short-chain fatty acid. Isobutyrates are derivatives produced by esterification or deprotonation. The colourless liquid isobutyric acid has a pungent smell.

What result in change of temperature on pka?

A proton is not retained securely when the pKa is low. Sometimes, the value of pKa is so low that it is a negative number. A proton is strongly retained when the pKa value is high.

These Brønsted acidic chemicals can all very easily give protons. Nitric acid and hydrochloric acid, for instance, both readily release their protons.

Therefore, By pushing the equilibrium to the right and toward higher ionization, which increases the Ka and decreases pKa, increasing temperature is equivalent to increasing the concentration of the reactant heat (less positive).

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In a steady flow combustion chamber , liquid enthyl alcohol ( C2H5OH(l)) at 25 degrees celsius (density : 790 kg/m^3; Specific heat at constant pressure: 114.08 kJ/kmol*K and enthalphy of vaporization: 42,340 kJ/kmol) is burned with 40 percent excess air that also enters at the same temperature as the fuel. combustion products leave thr chamber at 600K. Assuming a complete combustion. Determine the following:
A. The required volume flow rate of the liquid ethyl alcohol to supply at a rate of 2000kJ/s (answer should be in units of L/min)

Answers

The required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

To determine the required volume flow rate of liquid ethyl alcohol, we need to calculate the fuel flow rate first. Then, we can convert it to volume flow rate.

Given:

Rate of energy release (Q) = 2000 kJ/s

Excess air = 40% (or 0.4)

First, let's calculate the fuel flow rate (m f):

Q = m f × Lower Heating Value (LHV)

The Lower Heating Value (LHV) for ethyl alcohol can be calculated using the enthalpy of vaporization:

LHV = enthalpy of vaporization / molecular weight of fuel

LHV = 42,340 kJ/k mol / 46.07 kg/k mol = 920.11 kJ/kg

Now, we can calculate the fuel flow rate:

m f = Q / LHV

m f = 2000 kJ/s / 920.11 kJ/kg ≈ 2.173 kg/s

Next, let's convert the fuel flow rate to volume flow rate:

Volume flow rate (V f) = m f / density

V f = 2.173 kg/s / 790 kg/m³ = 0.002749 m³/s

Finally, we can convert the volume flow rate to L/min:

V f = 0.002749 m³/s × (1000 L/1 m³) × (60 s/1 min) ≈ 164.9 L/min

Therefore, the required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

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When 535) of heat is added to 8.5g of cooking oil at 22°C, the temperature increases to 79°C. What is the specific heat
of the cooking oil?

Answers

When 535) of heat is added to 8.5g of cooking oil at 22°C, the temperature increases to 79°C, 0.797 J/g°C is the specific heat of the cooking oil.

What is specific heat?

The amount of heat needed to increase a substance's temperature by one degree Celsius in one gram, also known as specific heat.

According to the definition, a material's specific heat capacity is normally calculated by measuring the heat capacity of a sample of the substance, commonly using a calorimeter, and dividing by the sample's mass.

Given that,

Heat absorbed (Q) = 535 J

Mass = 8.5 gm

Change in temperature (ΔT) = 79°C

Now, Specific heat (S) is given by the formula:

S = Q/(m × ΔT)

or, S = 535 J/ (8.5 gm × 79°C)

or, S = 0.797 J/g°C.

Thus, 0.797 J/g°C is the specific heat of the cooking oil.

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Early historical models of the solar system were geocentric. Which of these phrases describes a geocentric solar system?

A. the sun as a reference point

B. existing in a star system

C. Earth as a reference point

D. circular, orbital path of travel

Answers

I believe the answer is A

The accurate description of a geocentric solar system is the earth as a reference point.

The solar system refers to the arrangement of the sun and the planets. The description of the solar system in which the earth constitutes the center or reference point is called the geocentric model.

An alternative and more accurate model devised by Copernicus is the heliocentric model in which the sun lies at the center of the solar system.

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Fluorine,chlorine and bromine are all in the same group (group7) of the periodic table because they ______ in a similar way

Answers

Because they have low melting and boiling points in a similar way.

Which
element does the electron configuration 1s?2s?2p? represent?
O B
O C
ON
O K

Answers

Boron you are count to the 5th element

a- What is the balanced equation for the reaction of aluminum metal with liquid bromine to produce aluminum bromide?b- How many atoms of aluminum are present initially?c- How many MOLECULES of bromine (Br2) are present initially?d- How many molecules of aluminum bromide (AlBr3) will be produced?e- Which reactant, aluminum or bromine, is the limiting reactant?f- Which reactant, aluminum or bromine, is the excess reactant?g- How many molecules/atoms of excess reactant will remain after the reaction is complete?

a- What is the balanced equation for the reaction of aluminum metal with liquid bromine to produce aluminum

Answers

a- Aluminium bromide has the following formula: AlBr₃, so the unbalanced equation is:

\(Al+Br_2\to AlBr_3\)

As we can see, for now the aluminium atoms are balanced, but the bromine is not. To balance the bromine, we can put 3 in front of Br₂ and 2 in front of AlBr₃. That way, we will have a total of 6 bromine atoms in each side:

\(Al+3Br_2\to2AlBr_3\)

But now the Al is unbalaced, so to fix it we can add a 2 in front of Al to get the balanced equation:

\(2Al+3Br_2\to2AlBr_3\)

b- The aluminium are the lone atoms, so, counting them, we see that there are 8 atoms initially.

c- Each pair of empty circles represent a molecule of Br₂, counting them we have 6 molecules initially.

d- The proportion of Al to AlBr₃ is 2:2, that is, 1:1, so if all Al reacts, we would produce the same amount of AlBr₃ as Al, which would be 8 molecules.

The proportion of Br₂ to AlBr₃ is 3:2, so is all Br₂ reacts we will get 2/3 of that as AlBr₃, which would be 6*2/3 = 4 molecules.

This shows that there is not enough Br₂ to react with all 8 atoms of Al, meaning only 4 molecules of AlBr₃ will be produced.

e- Since there is not enough Br₂ to react with all Al present, the limiting reactant is the bromine.

f- The excess reactant is the other one, so if bromine is the limiting, the aluminium is the excess reactant.

g- Since only 4 molecules of AlBr₃ will be formed with all the bromine present, since the proportion of Al to AlBr₃ is 1:1, we wil need only 4 atoms of Al to produce them, which meand that, from the total 8 atoms, we will get

\(8-4=4\)

4 atoms of Al as excess reactant after the reaction is complete.

the chemical equation for reduction of phosphorite Ca3(PO4)2

Answers

Answer:

The chemical equation is;

Ca3(PO4)2 + 8C ———> Ca3P2 + 8CO

Explanation:

Here, we are interested in writing a chemical equation that is useful in the reduction of phosphorite.

We should understand that to be able to reduce phosphorite, there is need for a reducing agent.

Solid carbon can be used here.

The products formed are shown in the equation as follows;

Ca3(PO4)2 + 8C ———> Ca3P2 + 8CO


Each molecule in a gas has some kinetic energy. What is the
total kinetic energy of all the molecules in 2.23 mol of a gas
whose temperature is 334 K?

Answers

Therefore, the total kinetic energy of all the molecules in 2.23 mol of gas at 334 K is 35,510.2 J.

The kinetic energy of a molecule in gas depends on its mass and velocity. As temperature increases, the average velocity of gas molecules increases, leading to an increase in kinetic energy. The total kinetic energy of all the molecules in a gas is calculated using the formula K.E. = 1/2 mv², where m is the mass of the molecule and v is its velocity.
Given:
n = 2.23 mol
T = 334 K
We can calculate the total kinetic energy of all the molecules using the formula K.E. = 3/2 nRT. Here, R is the gas constant (8.314 J/K·mol), and we use the factor 3/2 instead of 1/2 to account for the three degrees of freedom in kinetic energy of a molecule in a gas.
K.E. = 3/2 nRT
K.E. = 3/2 (2.23 mol) (8.314 J/K·mol) (334 K)
K.E. = 35,510.2 J
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