the larger of two numbers is 15 more than the smaller number if the sum of the numbers is 91, find the two numbers . (write the answer as two numbers separated by a comma )

Answer:

h = -25

Step-by-step explanation:

h + 20 = 35 - 40​

Add 35 and -40.

h + 20 = 35 + - 40​

h + 20 = -5

Subtract 20 on both sides of the equation.

h + 20 - 20 = -5 - 20

h = - 5 - 20

h = -25

The value of h in the equation is -25.

Answer: 45.4% of students like both building snowmen and skiing

18.1% of students who do not like building snowmen also do not like skiing

Step-by-step explanation:

__________________________________________________

                 likes snowmen        doesn't like snowmen           total

__________________________________________________

 likes skiing    50                                30                                       80

__________________________________________________

doesn't like skiing   10                             20                                30

_________________________________________________

total                       60                                       50                         110

Answer:

0.318

Step-by-step explanation:

I hope this helps! :)

and can I get a brainliest?

Answer: 0.318

Step-by-step explanation:

The expression factoring out the greatest common factor is  (3pf - 21p²)(f + 2).

We have the expression as

3pf² - 21p²f + 6pf - 42p²

Now, factorising the expression as

= 3pf² + 6pf - 21p²f - 42p²

= 3pf(f +2) - 21p²(f + 2)

= (3pf - 21p²)(f +2)

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For the function  f(x) = 2x + 3 the third iterate x₃  is 37

To find the third iterate, x3, of the function f(x) = 2x + 3, given an initial value of x₀ = 2,

we can apply the function repeatedly.

Starting with x₀ = 2:

x₁ = f(x₀)

= 2(2) + 3

= 7

x₂ = f(x₁)

= 2(7) + 3 = 17

x₃ = f(x₂)

= 2(17) + 3

= 37

Therefore, the third iterate x₃  is 37.

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Answer:

9 3/5

Step-by-step explanation:

2+6+-4 4/5 ÷ -3

PEMDAS! First is multiplicationSo, solve the bold

2+6+ -4  4/5 ÷ -3

So,

2+6+ 1 3/5

Next is Addition(IN ORDER OF THE EQUATION), So solve the bold,

2+6+ 1 3/5

So, the answer is

9 3/5

The functions f and g are:

a. f(x) = 1/x

b. g(x) = x + 2

a) To find two functions f and g such that (fog)(x) = 1/(x + 2), we need to determine how the composition of the two functions f and g produces the given expression.

Let's start by assuming g(x) = x + a, where a is a constant. This means that g(x) adds the constant a to the input x.

Next, let's determine the function f(x) such that (fog)(x) results in the desired expression. We have:

(fog)(x) = f(g(x)) = f(x + a)

b) To simplify the expression 1/(x + 2) and make it match f(g(x)), we can consider f(x) = 1/x.

Substituting the expressions for f(x) and g(x) into (fog)(x), we have:

(fog)(x) = f(g(x)) = f(x + a) = 1/(x + a)

Comparing this with the desired expression 1/(x + 2), we see that a = 2. Therefore, the functions f and g are:

a. f(x) = 1/x

b. g(x) = x + 2

Using these functions, we can verify the composition (fog)(x):

(fog)(x) = f(g(x)) = f(x + 2) = 1/(x + 2)

Thus, (fog)(x) = 1/(x + 2), which matches the desired expression.

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(i) The first term (a) is 24 and the common difference (d) is -2.

(ii) The sum of the progression is 2520.

i) Finding the first term and common difference:

Given that the number of terms in the arithmetic progression is 40 and the last term is -54, we can use the formula for the nth term of an arithmetic progression to find the first term (a) and the common difference (d).

The nth term formula is: An = a + (n-1)d

Using the given information, we can substitute the values:

-54 = a + (40-1)d

-54 = a + 39d

We also know that the sum of the first 15 terms added to the sum of the first 30 terms is zero:

S15 + S30 = 0

The sum of the first n terms of an arithmetic progression can be calculated using the formula:

Sn = (n/2)(2a + (n-1)d)

Substituting the values for S15 and S30:

[(15/2)(2a + (15-1)d)] + [(30/2)(2a + (30-1)d)] = 0

Simplifying the equation:

15(2a + 14d) + 30(2a + 29d) = 0

30a + 210d + 60a + 870d = 0

90a + 1080d = 0

a + 12d = 0

a = -12d

Substituting this value into the equation -54 = a + 39d:

-54 = -12d + 39d

-54 = 27d

d = -2

Now we can find the value of a by substituting d = -2 into the equation a = -12d:

a = -12(-2)

a = 24

Therefore, the first term (a) is 24 and the common difference (d) is -2.

ii) Finding the sum of the progression:

The sum of the first n terms of an arithmetic progression can be calculated using the formula:

Sn = (n/2)(2a + (n-1)d)

Substituting the values:

S40 = (40/2)(2(24) + (40-1)(-2))

S40 = 20(48 - 39(-2))

S40 = 20(48 + 78)

S40 = 20(126)

S40 = 2520

Therefore, the sum of the arithmetic progression is 2520.

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Answer: .025

Step-by-step explanation: we first have to find the distance between each term we divide 12/5 by 6 you have to change it into multiplication so you invert is to 12/5 times 1/6 you then get 12/30 you reduce that to become 2/5 if you want to test this to make sure it is right then you can. you then use a formula but I can't remember it so then you can just multiply it several times to find the answer. you get the answer by round from the thousandths

Answer:

bjuk

Step-by-step explanation:

ftftrtt987652123456789

The correct answer is B. The sample represents a proportion of the population.

A point estimate is a single value used to estimate a population's unknown parameter. The sample proportion (denoted by p), in the context of determining the population proportion, is a widely used point estimate. The sample proportion is determined by dividing the sample's success rate by the sample size.

The sample must be representative of the population for it to be a reliable point estimate of the population proportion. To accurately reflect the proportions of various groups or categories present in the population, the sample should be chosen at random.

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Given:

Consider the given expression is

\(\log_59+\log_521-\log_57\)

To find:

The simplified form of the given expression.

Solution:

We have,

\(\log_59+\log_521-\log_57\)

It can be written as

\(=\log_5(9\times 21)-\log_57\)       \([\because \log_ax+\log_ay=log_a(xy)]\)

\(=\log_5\dfrac{9\times 21}{7}\)       \([\because \log_ax-\log_ay=log_a\dfrac{x}{y}]\)

\(=\log_5(9\times 3)\)

\(=\log_527\)

Therefore, the simplified form of the given expression is \(\log_527\).

Using trigonometric function the length to the nearest foot of the shortest ladder that will safely reach a roof that is 23 feet high is calculated as 25 feet.

What are trigonometric functions?

Simply put, trigonometric functions—also called circular functions—are the functions of a triangle's angle. This means that these trigonometric functions provide the relationship between the angles and sides of a triangle. Sine, cosine, tangent, cotangent, secant, and cosecant are the fundamental trigonometric functions.

Given the angle a ladder makes with the ground should be no greater than 67°.

So the angle θ ≤ 67°.

Let us assume the angle to be equal to 67°

The height of the roof from the ground is 23 feet.

The ladder and wall form the right triangle where the ladder works as hypotenuse and the wall as perpendicular.

With the sine function, find the length of the ladder -

sin θ = perpendicular/hypotenuse

Let the length of ladder be x.

sin 67° = 23/x

x = 23/sin 67°

x = 23/0.920

x = 25 feet

Therefore, the length of the ladder is 25 feet.

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The equation of the tangent at (2,7) is y = 4x - 1.y = x^2 + 3; t = 2

Given: y = x^2 + 3 and t = 2

We need to find the equation of the tangent at (2,7).

First, we find the slope of the tangent line by taking the derivative of the function:

y' = 2x

At x = 2, the slope is 2*2 = 4.

Now, we can use the point-slope form of the equation of a line to find the equation of the tangent line:

y - y1 = m(x - x1)

y - 7 = 4(x - 2)

Simplifying:

y = 4x - 1

Therefore, the equation of the tangent at (2,7) is y = 4x - 1.

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Answer:

A.

The graph shows trigonometric functions intercept the x-axis at minus 3, 0.2, and 3.5 units also pass parallel to the g of the x-axis.

The domain of the question is expressed as; 0 ≤ x ≤ 4

The range of the question is expressed as; 100 ≤ f(x) ≤ 207.36

The domain of a graph is defined as the set of all possible input values that makes the function possible while the range is defined as the set of all possible output values that can result from the possible input values.

Now, we are told that the insect population increases by 20% each month from May 1 to September 1.

The function that represents the insect population after x months is;

f(x) = 100(1.2)ˣ

Thus, the domain is from x = 0 to 4 months inclusive. 0 ≤ x ≤ 4

f(0) = 100(1.2)⁰

f(0) = 100

f(4) = 100(1.2)⁴

f(4) = 207.36

100 ≤ f(x) ≤ 207.36

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Sarah's fuel efficiency is approximately 32.91 miles per gallon.

From the question, we are to calculate Sarah's fuel efficiency.

To find Sarah's fuel efficiency in miles per gallon, we need to convert the distance she drove to miles and the amount of gasoline she used to gallons.

From the given information,

1 km = 0.6214 mi

1 gal = 3.8 L

First, let's convert the distance from kilometers to miles:

691.4 km × 0.6214 mi/km = 430.10196 mi

So, Sarah drove a distance of 430.1 miles.

Also,

Convert the amount of gasoline from liters to gallons:

49.7 L ÷ 3.8 L/gal = 13.0789 gal

So, Sarah used 13.0789 gallons of gasoline.

Calculate her fuel efficiency in miles per gallon:

Fuel efficiency = distance ÷ gasoline used

Fuel efficiency = 430.1 mi ÷ 13.0789 gal

Fuel efficiency = 32.9065 mi/gal

Hence, Sarah's fuel efficiency is 32.91 mi/gal

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H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.

A language is referred to as Decidable or Recursive if there is a Turing machine that accepts and halts on every input string w. This tells us that every decidable language is Turing-Acceptable.

Now, we are told that the halting language is reducible to some language B. This means that it is an undecidability via reduction.

Now, Using the idea that “ If A is undecidable and reducible to B, then B is undecidable.” Suppose R decides HALT_TM, we will construct S to decide ATM .

S = “On input (M, B)

This means that H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.

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So the new coordinates of point C are (1, 2), and the image of Triangle ABC is congruent to the original triangle.

A triangle is a closed, two-dimensional geometric figure with three straight sides and three angles. It is one of the basic shapes in geometry and can be classified based on the length of its sides or the size of its angles. A triangle with all sides of equal length is called an equilateral triangle, while a triangle with two sides of equal length is called an isosceles triangle. A triangle with no sides of equal length is called a scalene triangle. Triangles can also be classified based on the size of their angles, with an acute triangle having all angles less than 90 degrees, a right triangle having one angle equal to 90 degrees, and an obtuse triangle having one angle greater than 90 degrees.

Here,

To find the new coordinates of point C after the rotation and translation, we need to perform each transformation separately and then combine them.

Rotation:

To rotate a point 180° counterclockwise about the origin, we switch the sign of both coordinates. Therefore, the new coordinates of point C after the rotation are (-3, -2).

Translation:

To translate a point to the right 4 and up 4, we add 4 to the x-coordinate and 4 to the y-coordinate. Therefore, the new coordinates of point C after the translation are (1, 2).

To determine if the image of Triangle ABC is similar or congruent to the original triangle, we need to compare the corresponding sides and angles of both triangles.

Since we performed a rotation of 180°, all the angles in the image triangle are congruent to the corresponding angles in the original triangle. Additionally, since we performed a translation, the sides of the image triangle are congruent to the corresponding sides of the original triangle. Therefore, the image triangle is congruent to the original triangle.

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The solution of the given equation is (-11, 4). the graph is attached below.

Simultaneous equations, a system of equations are Two or more equations in algebra that must be solved jointly (i.e., the solution must satisfy all the equations in the system). The number of equations must match the number of unknowns for a system to have a singular solution.

There are four methods for solving systems of equations: graphing, substitution, elimination, and matrices.

Given a system of equation x + 3y = 1 and  -3 - 3y = -15

Before solving it with a graph we need to simplify the equation:

From equation 1

=> -3 - 3y = -15

=> -3y = -12

=> y = 4

From substitution in equation 1

x = -11

therefore, The solution of the given equation is (-11, 4).

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Answer:

i think c

i'm not sure tho

Step-by-step explanation:

There is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

To find the probability that a box of cereal is underfilled by 5 g or more, we need to calculate the probability of obtaining a weight measurement below 345 g.

First, we can standardize the problem by using the z-score formula:

z = (x - μ) / σ

Where:

x = the weight value we want to find the probability for (345 g in this case)

μ = the mean weight (350 g)

σ = the standard deviation (4 g)

Substituting the values into the formula:

z = (345 - 350) / 4 = -1.25

Next, we can find the probability associated with this z-score using a standard normal distribution table or a statistical calculator.

The probability of obtaining a z-score less than -1.25 is approximately 0.1056.

However, we are interested in the probability of underfilling by 5 g or more, which means we need to find the complement of this probability.

The probability of underfilling by 5 g or more is 1 - 0.1056 = 0.8944, or approximately 89.44%.

Therefore, there is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

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Answer:

\(6 \sqrt{8} \sqrt{2} = 6 \sqrt{16} = 6(4) = 24\)

B is the correct answer.

Answer:

it too far i can't see it

Step-by-step explanation:

The method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

In order to enhance strong number sense in children, there are various methods that can be used.

In the given scenario, Mme Potatana asked the children to count as a whole class from 1 to 20 while Ntate Mafodi asked the children in his class to count seeds from the school's ground in a pile by touching each as they count.

Both methods have their own benefits, but the method of counting seeds by touching each can be more effective in enhancing strong number sense in children.

The method of counting seeds by touching each can be more effective in enhancing strong number sense in children because it allows them to experience each number physically.

This helps them in developing a strong sense of numbers. By touching each seed as they count, children can feel and see each number, which helps them in understanding numbers better. Additionally, it helps in developing the concept of one-to-one correspondence and counting by rote.

Here are some appropriate examples for enhancing strong number sense using the method of counting seeds by touching each:

1. Use counters: Provide children with counters such as small objects, blocks, or toys. Ask them to count the number of counters by touching each as they count.

2. Counting on fingers: Encourage children to count on their fingers. This helps them in developing a strong sense of numbers and helps them in understanding the concept of one-to-one correspondence.

3. Counting objects in a pile: Ask children to count objects in a pile by touching each as they count. This helps in developing the concept of counting by rote and helps in enhancing strong number sense.

Overall, the method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

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The total surface area of the metal used to make the rubbish bin is approximately 2199 cm² to the nearest cm².

To calculate the total surface area of the metal used for the cylindrical rubbish bin, we need to find the area of the base and the lateral surface area.

The base of the cylindrical bin is a circle with a diameter of 20 cm, so its radius is 10 cm.

Therefore, the area of the base is:

Area of base = π × radius²

Area of base = π × 10²

Area of base = 100π ≈ 314.16 cm²

The lateral surface area of the cylinder can be found using the formula:

Lateral surface area = height × circumference of the base

The circumference of the base can be found using the formula:

Circumference = π × diameter

Circumference = π × 20

Circumference = 20π ≈ 62.83 cm

So, the lateral surface area of the cylinder is:

Lateral surface area = 30 × 62.83

Lateral surface area ≈ 1884.9 cm²

Therefore, the total surface area of the metal used is:

Total surface area = area of base + lateral surface area

Total surface area ≈ 314.16 + 1884.9

Total surface area ≈ 2199.06 cm²

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Answer:

17

Step-by-step explanation:

first write the equation:

twice a number x is 2x

six less is -6

so equation is 2x - 6 = 38

solve for x:

2x = 34

x = 17

Answer:16

Step-by-step explanation: