the kidneys in human beings are a part of the system for​

The new concentration of the solution can be calculated using the dilution formula, which states that the initial concentration multiplied by the initial volume (V1) is equal to the new concentration multiplied by the new volume (V2).

In this case, the equation would be: (3.5M)(0.20L) = (xM)(0.90L). Solving for x, we get the new concentration of the solution as 3.17M.

In other words, when a 3.5M solution of lici is diluted from 0.20L to 0.90L, the new concentration of the solution is 3.17M. This is because when the volume of a solution is increased, the concentration of the solution decreases proportionately.

Thus, when the volume of the solution is increased by a factor of four and a half, the concentration of the solution is reduced by the same factor.

Know more about Dilution formula here

https://brainly.com/question/30781795#

#SPJ11

Based on the above reaction, the energy change that occurs when 1.2 moles of methane reacts is A. 5.2 x 10⁵ J are released.

The given reaction is represented by the equation CH₄ + 4 Cl₂(g) -> CCl₄ (g) + 4 HCl(g) with an enthalpy change ΔH of -434 kJ. The energy change that occurs when 1.2 moles of methane react can be calculated by multiplying the ΔH by the moles of methane:

ΔH = -434 kJ/mol * 1.2 moles = -520.8 kJ = -5.2 x 10⁵ J

Since delta H is negative, this means that energy is released, which is represented by option A. 5.2 x 10⁵ J are released.

Learn more about enthalpy change ΔH here: https://brainly.com/question/16387742.

#SPJ11

Answer:

Fe

Iron – Ferrum (Fe)

Iron's Latin name, 'ferrum', gives it its symbol Fe; it simply means 'iron' or 'sword', and is possibly of Semitic origin.

Answer:

2.01588 grams

Explanation:

Answer:

D

Explanation:

Because it is the responding variable because you are looking for the weight or the amoount of salt in the water.

The dependent variable in this experiment number of plants living in the water.

Given:

An experiment design to test the effect of salt on the number of plants that live in water

To find:

The dependent variable in the experiment.

Solution:

We have two variables:

S = Amount of salt in water

P = Number of plants living in the water

This is because the amount of salt present in water is irrespective of the plants living in the water.

This is because the number of plants living in the water is gets affected by the amount of salt present in the water.

The dependent variable in this experiment number of plants living in the water.

Learn more about dependent and independent variables here:

brainly.com/question/1446733?referrer=searchResults

brainly.com/question/967776?referrer=searchResults

Answer: 4.74

Explanation:

First, we need to find the moles of each component in the buffer solution:

moles of HC2H3O2 = 0.20 mol/L x 0.100 L = 0.020 mol

moles of NaC2H3O2 = 0.10 mol/L x 0.100 L = 0.010 mol

Next, we can use the Henderson-Hasselbalch equation to find the pH of the buffer:

pH = pKa + log([C2H3O2-]/[HC2H3O2])

We know the pKa of HC2H3O2 is -4.8, and we can find the ratio of [C2H3O2-]/[HC2H3O2] using the moles and volumes of the components:

[C2H3O2-]/[HC2H3O2] = (moles of NaC2H3O2 / volume of solution containing HC2H3O2) / (moles of HC2H3O2 / volume of solution containing HC2H3O2)

= (0.010 mol / 0.200 L) / (0.020 mol / 0.200 L)

= 0.5

Plugging in these values to the Henderson-Hasselbalch equation, we get:

pH = -4.8 + log(0.5)

= 4.74

Therefore, the best estimate for the pH of the buffer is 4.74.

68.9g mass of the water would be boiled away

What is  specific heat capacity?

The amount of heat needed to raise a substance's temperature by one degree Celsius per gram is known as its specific heat. Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.

The amount of energy necessary to raise the temperature of 1 kilogram of tissue by 1 K (=1°C) is referred to as the specific heat capacity of tissue.

Q= mcdeltT

  = 350g x 418J x (100-20)c

  =  117,040J

Q total = Q1+Q2

             =275000J - 117040 J

             =  157960 J (left in beaker)

Q = mdelt Hv

m = Q2/0h

    = 157960 J / 2260J/g

    = 69.8g

To learn more about specific heat capacity use link below:

https://brainly.com/question/28825214

#SPJ1

Amplitude is the maximum distance that matter is displaced from the resting position. Amplitude is a measure of the maximum deviation or displacement of a wave or oscillation from its average or rest position.

In physics, the amplitude is used to describe the height or depth of the peaks and valleys of a periodic wave, such as a sine wave or the oscillation of a pendulum. In this sense, the amplitude can be used to describe the maximum displacement of matter in some situations, such as the maximum angle through which a pendulum swings from its resting position.

Key points:

Learn more about amplitude here:

https://brainly.com/question/19036728

#SPJ4

Answer: True

Explanation:

Answer:

Luster: Metals are shiny when cut, scratched, or polished.

Malleability: Metals are strong but malleable, which means that they can be easily bent or shaped. ...

Conductivity: Metals are excellent conductors of electricity and heat.

Three properties of metals are:

Good conductors of electricity and heat: Metals have a high electrical and thermal conductivity, meaning they allow the flow of electricity and heat through them with ease. This property makes metals valuable in various applications, such as electrical wiring and heat transfer.

Malleability: Metals can be easily shaped and molded into various forms without breaking. They can be hammered, rolled, or pressed into thin sheets without losing their structural integrity. This property allows metals to be used in manufacturing processes and the creation of different products.

Ductility: Metals can be drawn into thin wires without breaking. This property makes them suitable for electrical wiring and cable manufacturing, where flexibility is required.

Learn more about Metals, here:

https://brainly.com/question/29404080

#SPJ6

Explanation:

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

\(2Ca+O_2\rightarrow 2CaO\)

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

\(mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa\)

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

\(mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa\)

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

\(m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO\)

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

Answer:

69.9 g of CaO will be produced. ≅ 70 g

Explanation:

First of all you need to make the reaction:

2Ca + O₂ → 2 CaO

Determine the moles of each reactant:

10 g Ca / 40.08 g/mol = 0.25 moles

4 g O₂ / 32 g/mol = 0.125 moles

There is no limiting reagent in this reaction, we can use both elements.

Ratio between Ca and CaO, is 2:2. For 0.25 moles of Ca I would make 0.25 moles of CaO. We convert the moles to mass:

0.25 mol . 56.08 g / 1mol = 14 g

Let's think when you have the same mass of reactant:

50 g Ca/ 40.08 g/mol = 1.24 moles

50 g O₂ / 32 g/mol = 1.56 moles

For 1 mol of oxygen I need 2 moles of calcium, so If I have 1.56 moles, I would need the double, 3.12. Notice that Ca is the limiting reagent (we need 3.12 moles of reactant, but we only have 1.24). Now we need to work with it. If 2 moles of Ca, makes 2 moles of CaO, then 1.24 moles, will produce the same amount of oxide. We finally convert the moles to mass: 1.24 mol . 56.08 g/mol = 69.9 g

The solution would not have the same pH because the concentration of the hydrogen ions is not the same.

A solution's acidity or basicity is determined by its pH. It is referred to as the negative logarithm of the hydrogen ion (H+) concentration in a solution.

The pH scale runs from 0 to 14, with 14 being the most basic and 0 being the most acidic (or alkaline). Because hydrogen ions and hydroxide ions are present in an equal amount in a solution with a pH of 7, it is said to be neutral (OH-).

Learn more about pH:https://brainly.com/question/15289714

#SPJ1

The cathodic protection of Cu(s) can be provided if it is connected galvanically to Zn.

The metal with the more reduction potential will act as the anode and undergo oxidation, while the metal with the more positive standard reduction potential will act as the cathode and undergo reduction.

As Cu has a greater reduction potential than Zn, it has a greater capacity to reduce than that of Zn. So by galvanically connecting to zn, we can say that the cathodic protection of Cu can be obtained.

To learn more about cathodic protection :

brainly.com/question/32659293

Answer:

24.66%

Explanation:

To find the percent of water (H2O) in the following compound: Zn3(PO4)2. 7H2O

The atomic mass of the elements are as follows:

Zn = 65g/mol

P = 31g/mol

O = 16g/mol

H = 1g/mol

Hence, molar mass of the compound is as follows:

65(3) + {31 + 16(4)} 2 + 7{1(2) + 16}

195 + 95(2) + 7(18)

195 + 190 + 126

511g/mol

Molar mass of 7H2O

= 7(18)

= 126g/mol

Hence, the percent of H2O in the compound is:

Molar Mass of 7H2O/molar mass of compound × 100

= 126/511 × 100

= 0.2466 × 100

= 24.66%

Answer: The molar mass of magnesium chloride, MgCl2 is 95.21 g/mole.

How to calculate the molar mass of magnesium chloride, MgCl2?

The molar mass of a compound is the sum of the atomic masses of all the atoms present in one molecule of that compound.

The atomic mass of magnesium is 24.31 g/mole and the atomic mass of chlorine is 35.45 g/mole (17.77 g/mole for each Cl atom).

So, the molar mass of magnesium chloride, MgCl2 is:

Molar mass of MgCl2= (Molar mass of Mg) + 2 x (Molar mass of Cl)

= 24.31 + 2 x 35.45= 95.21 g/mole

Therefore, the molar mass of magnesium chloride, MgCl2 is 95.21 g/mole.

Learn more about molar mass here:

https://brainly.com/question/22997914#




#SPJ11

Answer:

The mass number (A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus. The mass number is different for each different isotope of a chemical element.

[Kr]5s²4d10⁵p² represents iodine element. The fundamental components of matter are thought to be the elements.

A material is considered an element if it cannot be divided into two or even more simpler compounds by any kind of chemical process, including the use of light or warmth. For instance, when melting the chunk of gold, it nevertheless melts but remains as the precious metal element. 

The fundamental components of matter are thought to be the elements. There are currently 118 known elements, 94 of which are found in nature while the remaining 24 are created artificially. [Kr]5s²4d10⁵p² represents iodine element.

Therefore,  [Kr]5s²4d10⁵p² represents iodine element.

To know more about element, here:

https://brainly.com/question/29792173

#SPJ2

Answer:

A.producing hook-and-loop tape

Explanation:

hope it's help..

Answer:

A) producing hook-and-loop tape

Explanation:

Answer:

B)The atoms form a bond with a bond length of 75 pm

Answer:

(i) In a bond amortization schedule, the book value represents the remaining amount of the bond principal that hasn't been paid off at a given point in time. When a bond is first issued, its book value equals its face value. As payments are made over the life of the bond, a portion of these payments reduces the book value. By the end of the bond's life, its book value will be zero, as the entire principal will have been paid off.

(ii) The formula for the book value B at time k, where k is the number of periods elapsed, is B = C + Cg - jan-kj.

Here:

- C is the redemption amount,

- g is the modified coupon rate per period,

- j is the yield rate per period, and

- a_n-kj is the present value of an annuity immediate with n - k periods at the yield rate j.

This formula states that the book value at any time k is the redemption amount plus the present value of the future coupon payments (Cg), minus the present value of the annuity that represents the repayments of the bond (jan-kj).

The amortized amount at time k is the change in the book value from time k-1 to time k, plus the coupon payment at time k. It represents the portion of the bond's principal (and interest) that has been repaid up to time k.

(iii) If K is defined as the present value of the redemption value C, according to the Makeham formula, (C-K) would represent the difference between the redemption value of the bond and its present value. This difference is the amount of interest that will accumulate over the life of the bond. In other words, (C-K) can be interpreted as the total interest that the bondholder will earn from holding the bond until redemption, assuming that all coupon payments are reinvested at the yield rate j.

Explanation:

The composition of the alpha phase in the alloy is 45 wt % A.

To find the composition of the alpha phase in the alloy (A-B), we can use a mass balance approach.

Let's assume we have a total mass of 100 grams of the alloy. Given that the mass fraction of both the alpha and beta phases is 0.5, we can determine the mass of each phase.

Mass of alpha phase = 0.5 × 100 grams

= 50 grams

Mass of beta phase = 0.5 × 100 grams

= 50 grams

Now, let's consider the composition of the beta phase, which is 90 wt % B and 10 wt % A. We can calculate the mass of each element in the beta phase.

Mass of B in beta phase = 90 wt % × 50 grams

= 45 grams

Mass of A in beta phase = 10 wt % × 50 grams

= 5 grams

Since the total mass of the alpha phase is 50 grams and the total mass of A in the beta phase is 5 grams, we can subtract the A mass in the beta phase from the alpha phase to get the composition of the alpha phase.

Composition of A in alpha phase = 50 grams - 5 grams

= 45 grams

To learn more about alloy follow the link:

https://brainly.com/question/29345796

#SPJ4

Answer:

is that in a molecule of an element, all the atoms are the same. For example, in a molecule of water (a compound), there is one oxygen atom and two hydrogen atoms. But in a molecule of oxygen (an element), both of the atoms are oxygen.

Explanation:

Answer:

The only difference between a molecule of a compound and a molecule of an element is that in a molecule of an element all the atoms are the same.

Explanation:  A molecule of an element all the atoms are the same.

(1a) 3-Chlorophenol is more acidic than cyclopentanol (chlorine atom electron-withdrawal). (1b) Cyclohexanecarboxylic acid is more acidic than cyclohexanol (stronger carboxylic acid group).

(2a) Propan-2-ol is more soluble in water than butan-1-ol and pentan-1-ol (hydrogen bonding ability). (2b) Cyclohexanol is more soluble in water than chlorocyclohexane (hydroxyl group enables hydrogen bonding).

Part 1: Comparing Acidic Strength

a) 3-chlorophenol is more acidic than cyclopentanol. This is because the presence of a chlorine atom in 3-chlorophenol can stabilize the negative charge on the phenoxide ion through inductive and resonance effects, making it more stable and easier to form.

b) Cyclohexanecarboxylic acid is more acidic than cyclohexanol. The carboxylic acid group (-COOH) is a stronger acid functional group compared to the hydroxyl group (-OH) present in cyclohexanol.

c) 2,2-dichlorobutan-1-ol is more acidic than butan-1-ol. The presence of the electron-withdrawing chlorine atoms in 2,2-dichlorobutan-1-ol enhances the acidity by stabilizing the negative charge on the alkoxide ion formed upon deprotonation.

d) Cyclohexanecarboxylic acid is more acidic than cyclohexanol. The carboxylic acid group (-COOH) is a stronger acid functional group compared to the hydroxyl group (-OH) present in cyclohexanol.

Part 2: Comparing Solubility in Water

a) Propan-2-ol is more soluble in water than butan-1-ol and pentan-1-ol. Propan-2-ol has a hydroxyl group (-OH) that can form hydrogen bonds with water molecules, increasing its solubility.

b) Cyclohexanol is more soluble in water than chlorocyclohexane. The presence of the hydroxyl group in cyclohexanol allows for hydrogen bonding with water molecules, enhancing its solubility. Chlorocyclohexane, on the other hand, is nonpolar and lacks the ability to form significant hydrogen bonds with water.

c) Cyclohexanol is more soluble in water than phenol and 4-methylcyclohexanol. Both cyclohexanol and phenol can form hydrogen bonds with water, but phenol's aromatic ring reduces its solubility. 4-methylcyclohexanol is also less soluble than cyclohexanol due to the steric hindrance from the methyl group, which disrupts hydrogen bonding.

To know more about the aromatic ring refer here,

https://brainly.com/question/32170261#

#SPJ11

The plant's glucose, C6H12O6, will include the 18O-radiolabeled CO2 when enough time has passed for photosynthesis. Option D

Green plants use the power of sunshine to produce their nourishment via a process called photosynthesis.

In the process of photosynthesis, plants use the energy of the sun to drive chemical processes that transform atmospheric carbon dioxide, or CO2, and water vapor into glucose.

Taking into account the provided research:

In an illuminated room with 18O-radiolabeled CO2, a researcher cultivated a plant.

The 18O-radiolabeled CO2 will be absorbed into the glucose the plant produces during photosynthesis when enough time has passed for photosynthesis.

After being generated, glucose is subsequently stored as starch.

To learn more about photosynthesis.

https://brainly.com/question/1388366

#SPJ1

Complete question:

A researcher grew a plant in an illuminated chamber with ¹⁸O-radiolabeled CO₂. After allowing time for photosynthesis, where will the radiolabeled ¹⁸O be found?

A. O₂ in the chamber

B. H₂O in the plant

C. H₂O vapor in the chamber

D. C₆H₁₂O₆ in the plant

Answer:

True.

Explanation:

According to this, an object's rate of change in velocity is directly proportional to the force used and moves in the direction of the applied force. The following formula encapsulates it: force (N) = mass (kg) x acceleration (m/s2). A constant mass item will therefore accelerate in direct proportion to the force exerted.

Answer:

true, I am pretty sure it's true

Answer:

Solid turns to liquid and liquid to gas

Explanation:

ice cube to water, water to carbon

If 170 milligrams of a radioactive substance decays to 85 g after 16 hours. Then, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

The decay of the radioactive substance follows an exponential decay equation of the form:

\(N(t) = N_{o} \times e^{-kt}\)

Where:

N(t) is the amount of substance remaining at time t

N₀ is the initial amount of substance

k is the decay constant

t is the time elapsed

Given to us is N₀ = 170 mg and N(16) = 85 mg. We can use this information to find the decay constant, k.

\(85 = 170 \times e^{-k \times 16}\)

Dividing both sides by 170:

\(0.5 = e^{-k \times 16}\)

To solve for k, we can take the natural logarithm (ln) of both sides:

ln(0.5) = -k × 16

from this, the value of k comes out to be:

k = 0.0431

Now we can use the decay equation to find the amount of substance remaining after 21 hours, N(21):

\(N(21) = 170 \times e^{-0.0431 \times 21}\)

Calculating this expression:

N(21) = 75.2

Therefore, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

Learn more about radioactive decay here:

https://brainly.com/question/1770619

#SPJ4

Answer:

True

Explanation: