The isomerization of cyclopropane follows first order kinetics. The rate constant at 700 k is 6. 20 × 10^-4 min-1, and the half-life at 760 k is 29. 0 min. Calculate the activation energy for this reaction.

Answer:

electrochemical process is a chemical reaction caused by the applied electrical current.

Explanation:

Electrochemical processes involve the transfer of electrons between chemical species, resulting in the conversion of chemical energy into electrical energy or vice versa.

Through redox reactions, chemical energy can be transformed into electrical energy or vice versa in electrochemical processes. They happen where an electrode and an electrolyte solution meet. In these procedures, electrons are moved from the electrode to the electrolyte, causing an electric current to flow.

While reduction takes place at the cathode, where electrons are obtained, oxidation happens at the anode, where electrons are expelled. Numerous applications, such as batteries, fuel cells, corrosion, electroplating, and electrolysis, depend on electrochemical processes.

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The mass of I2 reacted is  142.2 g

The mass of PCl3 reacted is 153.4 g

Stoichiometry is a fundamental concept in chemistry and is used in many different areas of science and industry.

We know that;

Number of moles of the F2 produced = 21.1 g/38 g/mol

= 0.56 moles

If 1 mole of I2 produced 1 mole of F2

Then 0.56 moles of I2 reacted

Mass of the I2 reacted = 0.56 mol * 254 g/mol

= 142.2 g

Number of moles of PCl5 = 234.1 g/208 g/mol

= 1.12 moles

If the reaction is 1:1:1

Mass of the PCl3 reacted = 1.12 moles * 137 g/mol

= 153.4 g

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Answer:

Sodium chloride

Explanation:

There are several salts in seawater, but the most abundant is ordinary table salt or sodium chloride (NaCl). Sodium chloride, like other salts, dissolves in water into its ions, so this is really a question about which ions are present in the greatest concentration. Sodium chloride dissociates into Na+ and Cl- ions.

Convert the moles of ammonia gas to liters using the ideal gas law.

If 3.8 liters of nitrogen gas and 26.66 liters of hydrogen gas were allowed to react, we need to determine how many liters of ammonia gas could form.

To solve this, we need to know the balanced chemical equation for the reaction between nitrogen gas and hydrogen gas to form ammonia gas.

Once we have the equation, we can use the stoichiometry to find the molar ratio between the reactants and products.

This ratio will tell us how many moles of ammonia gas can be formed.

Finally, we can convert the moles of ammonia gas to liters using the ideal gas law.

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In the presence of water, ionic and hydrogen bonds can be disrupted.

Water is a polar molecule, meaning it has a partial positive charge on one end and a partial negative charge on the other end.

This polarity allows water to interact with other polar molecules, including ionic compounds and molecules containing hydrogen bonds.

Ionic compounds are held together by strong electrostatic forces between positively and negatively charged ions.

In the presence of water, the partial charges on the water molecule can attract and surround the ions, weakening the electrostatic forces and causing the ionic compound to dissociate into its component ions.This is why ionic compounds dissolve readily in water.

Hydrogen bonds are a type of intermolecular force that forms between a hydrogen atom bonded to an electronegative atom and another electronegative atom in a different molecule.

Water molecules can form hydrogen bonds with other polar molecules, and in the presence of water, these hydrogen bonds can be disrupted as water molecules compete for hydrogen bonding partners. This can affect the solubility and reactivity of molecules containing hydrogen bonds.

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Answer:

Answer: a, b, c, d, e, f. a) 1 significant figure b) 3 significant figures c) 2 significant figures d) 4 significant figures e) 5 significant figures f) 6 significant figures Note that non-integers are rounded to the nearest integer and then count as the number of significant figures. For example, rounding 1.5 to two significant figures would mean one significant figure because it is an integer, not because it is a decimal.

Answer explanation: 26.000 cm = 2.6 x 10^2 cm. 0.800 km = 8 x 10^-3 km. 0.00050 g = 5 x 10^-4 g. 7300 m = 7.3 x 10^2 m. 3 x 10^5 mL = 3000000 ml or 300 L

Explanation:

How many significant figures are in each of these measurements?

32.14 cm

4.34 x 10^3 cm

2 g

13000 L

1.007 g/mL

6 mL

0.000005 L

2.7 mL

Answer: a, b and c contain 7 significant figures and the others each have 4 significant figures.

Incorrect answers indicate incorrect choices made for this problem or other problems on the worksheet . Answer explanation: 32.14 cm = 3.214 x 10^2cm 4.34 x 10^3cm = 4.34x10^5 cm 2 g = 2 grams 13000 L = 13 kiloliters 1.

Answer:

Two electrons

Explanation:

Answer:

The number will appear to become smaller (from 5800 mL to 5.8 L).

Explanation:

The conversion of milliliters to liters is the following:

1 L = 1000 mL

Hence, the volume of 5800 mL to L is:

\( V = 5800 mL*\frac{1 L}{1000 mL} = 5.8 L \)      

Therefore, the number will appear to become smaller (from 5800 mL to 5.8 L).

I hope it helps you!

Explanation:

probably protons would be released and cause a spontaneous reaction

t = 57 min., Therefore, we can say that it takes 57 minutes for cyclopropane's partial pressure to drop from 1 atm to 0.125 atm at 500°C.

Propene (CH3CH=CH2) is produced by the isomerization of cyclopropane, which is a first-order process. A sample of cyclopropane converts to propene in 79 minutes at 760 K.

The reaction is a first-order reaction because it is an isomerization reaction, and its rate constant is expressed in terms of minutes. The sum of the powers or exponents that the concentration terms are raised in the rate law expression can be used to define the order of a reaction.

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\(\\ \sf\longmapsto c=\lambda v\)

\(\\ \sf\longmapsto v=\dfrac{c}{\lambda}\)

Now

\(\\ \sf\longmapsto E=hv\)

Put value of v found before

\(\\ \sf\longmapsto E=\dfrac{hc}{\lambda}\)

The measurement can be written as 5.6 ± 0.05 grams, indicating that the true value of the weight lies between 5.55 grams and 5.65 grams with a confidence level of 68%. The uncertain digit(s) should always be recorded, along with the certain digits, to communicate the precision and accuracy of the measurement.

In a measured quantity, the digits that are certain are the digits that can be read directly from the measuring instrument or specified by the definition of the unit of measurement. The digits that are uncertain are the last digit or digits that are estimated or interpolated based on the measuring instrument's resolution or the observer's judgment.

For example, if a scale displays a weight of 5.6 grams, the digit 5 is certain, and the digit 6 is uncertain, as it is estimated based on the scale's resolution. If the scale has a resolution of 0.1 grams, then the uncertainty in the measurement is ±0.05 grams.

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Answer:

The answer is SiO2

Explanation:

Because nonmetals are those who gain electrons and form ve ions

Answer:

Mosty Oil but it depends there is lots of things that can damage soil  

Explanation:

Answer:

Sheet erosion by water, wind erosion, and rill erosion

Answer:

I believe it is C2H5OH

Explanation:

hopefully it's right

To prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.The ratio of benzoic acid to sodium benzoate in the buffer solution using the Henderson-Hasselbalch equation.

To prepare a pH 4.00 buffer solution using benzoic acid and sodium benzoate, we need to calculate the appropriate volumes of the 0.100 M benzoic acid and 0.240 M sodium benzoate solutions.

First, we need to determine the ratio of benzoic acid to sodium benzoate in the buffer solution. The Henderson-Hasselbalch equation can help us with this calculation:

pH = pKa + log([A-]/[HA])

Given that the pH is 4.00 and pKa is 4.20, we can rearrange the equation:

log([A-]/[HA]) = pH - pKa

log([A-]/[HA]) = 4.00 - 4.20

log([A-]/[HA]) = -0.20

Next, we take the antilog of -0.20 to find the ratio of [A-] to [HA]:

[A-]/[HA] = antilog(-0.20)

[A-]/[HA] = 0.63

The ratio of [A-] to [HA] is 0.63.

Now, let's calculate the volumes of each solution needed. Let's assume x represents the volume (in mL) of the 0.100 M benzoic acid solution and y represents the volume (in mL) of the 0.240 M sodium benzoate solution.

Since the total volume is 100.0 mL, we have the equation: x + y = 100

Considering the ratio of [A-] to [HA] as 0.63, we can write the equation: y/x = 0.63

Solving these two equations simultaneously will give us the volumes of each solution:

x + y = 100

y/x = 0.63

By substituting y = 0.63x from the second equation into the first equation, we get:

x + 0.63x = 100

1.63x = 100

x = 61.35 mL (rounded to two decimal places)

Substituting this value back into the equation x + y = 100, we find:

61.35 + y = 100

y = 38.65 mL (rounded to two decimal places)

Therefore, to prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.

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Answer:  The mass M = 9g, so G = 9g x 9.8 m/s² = 88.2gm/s², or 88.2 newtons. Insert the tension and gravitational force you just calculated into the original equation: -F = T + G = 18N + 88.2N = 106.2N. The force is negative because the object in the pulley system is accelerating upwards.

Explanation:

An individual is hospitalized and the initial blood work indicates high levels of \(HCO_{3} ^{-}\) in the blood and a pH of 7. 47. This would indicate the individual probably has compensated respiratory acidosis.

A chronic illness usually leads to compensated respiratory acidosis because the kidneys have time to adjust to the delayed onset. Even if the \(PCO_{2}\) is elevated in a compensated respiratory acidosis, the pH is within the usual range.

The kidneys counteract a respiratory acidosis by increasing the amount of \(HCO_{3}\) that tubular cells reabsorb from the tubular fluid, the amount of \(H^{+}\) that collecting duct cells secrete while also producing \(HCO_{3}\) , and the amount of \(NH_{3}\) buffer that is formed through ammoniagenesis.

Respiratory acidosis is frequently brought on by hypoventilation as a result of: breathing depression , paralysis of the respiratory muscles, diseases of the chest wall , abnormalities of the lung parenchyma and abdominal squeezing.

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Answer:

Double replacement reaction

Explanation:

This is what is known as a double replacement reaction. The two parts of each molecule separate and recombine to form two new compounds. For instance, \(Al_2(SiO_3)_3\) separates into \(Al_2\) and \((SiO_3)_3\), while \(NaOH\) separates into \(Na\) and \(OH\), and then they recombine with the other compound.

Hope this helps!

Answer:

double replacment reaction

Explanation:

srry if it is wrong

The number of protons and neutrons together makes the total atomic mass of the element. The atom of chromium has 28 neutrons. Thus, option b is correct.

An atomic mass is the property of an element that defines the number of protons and neutrons of the atom placed in a periodic table. The atomic mass is represented at the lower half of the atomic symbol.

The atomic mass is the sum of the neutrons and the protons that are held together in the nucleus of the atom as a concentrated mass. The atomic number is given as,

Atomic number = number of protons + number of neutrons

Given,

The atomic mass of chromium = 52

Number of protons = 24

Substituting values above:

52 = 24 + number of neutrons

number of neutrons = 52-24

= 28

Therefore, the number of neutrons of a chromium atom is 28.

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Answer: option b, 28

the speed of arrow is 83m/per second

that means

83metres = 1 second

●The arrow would cover the distance of 83 metres in 1 second

may this helps you

bye

The amount of energy required to change a liquid to a gas is called the__enthalpy of vapourization_

The amount of energy required to change a solid to a liquid is called the ___fusing (melting)__

In the ___solid___ state, particles interact so strongly that the only movement is in the form of _vibration_.

If enough energy is added, the particles can escape the strongest interactions and move freely, _gaseous__ phase.

A substance's behaviour of its atoms and molecules is referred to as its "state of matter." Generally speaking, matter exists in three states: Solids have a distinct shape and are comparatively hard. The molecules and atoms in a solid are bound to one another. Instead of moving, they only vibrate still.

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Answer:

Structural formula

Explanation:

Structural formulas are usually represented as such.

Answer:

A) Product

Explanation:

the products is what is left after the reaction with has taken place

Answer:

Baking Soda a base

Explanation:

We know that to neutralize an acid we add base to it. Baking Soda is a type of base so when we add Baking Soda or any other base to battery acid or any other acid we can neutralize it and get salt and water.

Acids are the substance which are sour in taste and can turn blue litmus paper red. For example, Lemon and Orange.

Bases are the substance which are bitter in taste and can turn red litmus paper blue. For example, Baking Soda and Soap.

One FADH2 molecule is created for every beta oxidation cycle. Consequently, after the provided fatty acid is completely oxidised, a total of 7 FADH2 molecules will be created.

In seven cycles of this oxidation, a 16-carbon fatty acid loses two carbons as acetyl-CoA, producing a total of eight molecules of acetyl-CoA.

Nine rounds of beta oxidation are necessary to completely oxidise a fatty acid with a 20-carbon hydrocarbon tail because the organic byproduct of beta oxidation has two carbons.

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A rate law can be deduced from the change in concentration over time by comparing the initial and final concentrations and finding the rate constant.

The rate law represents the relationship between the concentration of reactants and the rate of reaction. To deduce the rate law from the change in concentration over time, the initial and final concentrations of the reactants must be compared. The order of the reaction with respect to each reactant can be determined by changing the concentration of one reactant and measuring the resulting change in reaction rate.

By performing this analysis for each reactant, the overall rate law can be determined. The rate constant can then be calculated by measuring the reaction rate at different concentrations and plugging the data into the rate law equation. The rate constant represents the speed of the reaction at a particular temperature and is used to predict the reaction rate at different concentrations.

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The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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