The intersection of Beech Street and fourth Street is 150 yards east of the intersection of Fort Street and Clover Street how many yards south is it

Answer:

1/64

Step-by-step explanation:

\( \frac{ {8}^{2} }{ {8}^{4} } = \frac{1}{ {8}^{4 - 2} } = \frac{1}{ {8}^{2} } = \frac{1}{64} \\ \)

The name of the analytical technique that is less reliable for identifying acceptable projects as it ignores the time value of money is the payback period method.

The payback period method calculates the time required for the cash inflows from a project to equal the initial investment, without considering the time value of money. This technique may lead to incorrect decisions in situations where projects have different cash flow patterns over time or where the cost of capital is high.

Therefore, it is important to use more reliable analytical techniques, such as net present value (NPV) or internal rate of return (IRR), which take into account the time value of money and provide a more accurate evaluation of the project's profitability over time.

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--The complete question is, What is the name of the analytical technique that is less reliable for identifying acceptable projects as it ignores the time value of money? --

Here is a context-free grammar (CFG) that generates the language of all words of the form (a^x)(b^y)(a^z), where x, y, z = 1, 2, 3,... and x + z = y:

S -> AB

A -> aA | ε

B -> bB | ε

The start symbol S generates the entire word.

A generates the substring (a^x), where x = 1, 2, 3,...

B generates the substring (b^y)(a^z), where y = x + z and z = 1, 2, 3,...

The ε represents the empty string.

With this CFG, you can derive words such as abba, aabbba, abbbaa, aabbbbaa, and so on, which are in the specified form.

Note: In the CFG, ε represents the empty string or epsilon. If you don't want to include the empty string in the language, you can remove the ε productions from the CFG.

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Answer:

y = − 6 x + 7

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula

Answer:

a

Step-by-step explanation:

Answer:

a=2b-x

Step-by-step explanation:

As per the data Economic Order Quantity is the given equation TC = DC + (Q/2) H + (D/Q) S is 1118 units.

Annual ordering cost per order

The Total Annual Inventory Cost (TC) equation calculates the total cost of maintaining inventory over a given period, typically a year. The equation considers the cost of ordering inventory, holding inventory, and the cost of lost sales due to stockouts.

The equation is as follows: TC = DC + (Q/2) H + (D/Q) S where:

DC is the Annual Demand, the total quantity of products that must be purchased or manufactured to meet customer demand over a given period.

C is the Cost per unit, the cost to purchase or manufacture a single unit of the product.

H is the Annual holding cost per unit, the cost of storing inventory for a given period. This cost includes storage fees, insurance, and the opportunity cost of using funds that could have been invested elsewhere.

S is the Annual ordering cost per order, the cost of placing an order for inventory, including shipping fees and the cost of preparing the order.

Q is the Economic Order Quantity, the optimal order quantity that minimizes the total cost of ordering and holding inventory.

The first part of the equation, DC, calculates the cost of purchasing the necessary inventory to meet demand. The second part of the equation, (Q/2) H, calculates the cost of holding inventory. The third part of the equation, (D/Q) S, calculates the cost of placing orders for inventory.

If the question asks calculate EOQ, then

Annual Demand = 15,000 units

Unit Cost = $10

Holding Cost = 0.30 or 30% of unit cost per unit per year

Cost to place order = $125D = 15,000H = (0.30) (10) = 3C = 10S = 125

EOQ= √ (2(125) (15,000)/ (3) =1118 UNITS

Thus, Economic Order Quantity is 1118 units.

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Answer:

Step-by-step explanation:

The anwer is 6

Answer:

If I'm thinking about this right it should be 6

Answer:

The registration fee is $28

Step-by-step explanation:

5,600/100=56 which is 1% of 5,600.

56/2=28 which is 0.5% of 5,600.

;)

Answer: $28

Step-by-step explanation:

you calculate what 0.5 percent is of 5,600  :)

Answer:

I dont see the question but If you are asking if your statement is correct, my answer is yes.

Step-by-step explanation:

G(x) is inverted ( due to the ' - ' ) and 1/4 of the original size of  f(x)

The percentage of energy lost in the collision is approximately 79.16%.

To find the velocity of the second car after the collision, we can apply the law of conservation of momentum.

The law of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

(m1 * v1) + (m2 * v2) = (m1 * v1') + (m2 * v2')

where m1 and m2 are the masses of the cars, v1 and v2 are their initial velocities, and v1' and v2' are their final velocities.

Given the following values:

m1 = 1.3 kg (mass of the first car)

v1 = 2 m/s (initial velocity of the first car)

m2 = 1 kg (mass of the second car)

v1' = -0.99 m/s (final velocity of the first car)

We can substitute these values into the conservation of momentum equation:

(1.3 kg * 2 m/s) + (1 kg * v2) = (1.3 kg * -0.99 m/s) + (1 kg * v2')

Simplifying the equation:

2.6 kg m/s + v2 = -1.287 kg m/s + v2'

Rearranging the equation to solve for v2':

v2' = v2 + (2.6 kg m/s - 1.287 kg m/s)

Given that v2 = 1 m/s, we can substitute this value into the equation:

v2' = 1 m/s + (2.6 kg m/s - 1.287 kg m/s)

Simplifying the equation:

v2' = 1.313 kg m/s

Therefore, the velocity of the second car after the collision is approximately 1.313 m/s.

Next, let's calculate the initial and final kinetic energy and then determine the percentage of energy lost.

The initial kinetic energy (K0) is given by the formula:

K0 = (1/2) * m1 * v1^2 + (1/2) * m2 * v2^2

Substituting the given values:

K0 = (1/2) * 1.3 kg * (2 m/s)^2 + (1/2) * 1 kg * (2.2 m/s)^2

Calculating the value of K0:

K0 = 5.72 J

The final kinetic energy (K) is given by the formula:

K = (1/2) * m1 * v1'^2 + (1/2) * m2 * v2'^2

Substituting the given values:

K = (1/2) * 1.3 kg * (-0.99 m/s)^2 + (1/2) * 1 kg * (1.313 m/s)^2

Calculating the value of K:

K = 1.194 J

The energy lost is given by the difference between the initial and final kinetic energies:

Energy Lost = K0 - K

Energy Lost = 5.72 J - 1.194 J

Energy Lost = 4.526 J

To determine the percentage of energy lost, we can use the formula:

% Energy Lost = (Energy Lost / K0) * 100

Substituting the values:

% Energy Lost = (4.526 J / 5.72 J) * 100

% Energy Lost ≈ 79.16%

Therefore, the percentage of energy lost in the collision is approximately 79.16%.

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Given the following information: Five years ago, someone used her $40,000 saving to make a down payment for a townhouse in RTP. The house is a three-bedroom townhouse and sold for $200,000 when she bought it. After paying down payment, she financed the house by borrowing a 30-year mortgage.

Mortgage interest rate is 4.25%. Right after closing, she rent out the house for $1,800 per month. In addition to mortgage payment and rent revenue, she listed the following information so as to figure out investment return: 1. HOA fee is $75 per month and due at end of each year 2. Property tax and insurance together are 3% of house value 3. She has to pay 10% of rent revenue for an agent who manages her renting regularly 4. Her personal income tax rate is 20%. While rent revenue is taxable, the mortgage interest is tax deductible. She has to make the mortgage amortization table to figure out how much interest she paid each year 5. In the last five years, the market value of the house has increased by 4.8% per year 6.

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The Fourier Cosine transform of e^(-t^2) is not expressible in terms of elementary functions.

To find the Fourier Cosine transform of e^(-t^2), we need to evaluate the integral ∫e^(-t^2)cos(ωt) dt over the range -∞ to +∞. However, this integral does not have a closed-form solution in terms of elementary functions. The function e^(-t^2) is a standard Gaussian function, and its Fourier transform involves the error function, which does not have a simple algebraic expression.

While there are numerical methods and approximations available to calculate the Fourier Cosine transform of e^(-t^2), there is no simple analytical formula to represent it.

The Fourier Cosine transform of e^(-t^2) cannot be expressed in terms of elementary functions. It is a complex integral involving the error function, which requires numerical methods or approximations for computation.

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Answer:

Solutions

Step-by-step explanation:

El ángulo de 45 grados es uno de los ángulos notables en trigonometría. La razón trigonométrica más comúnmente asociada con este ángulo es:

- La razón trigonométrica del seno: sin(45°) = 1/√2 ≈ 0.7071

- La razón trigonométrica del coseno: cos(45°) = 1/√2 ≈ 0.7071

- La razón trigonométrica de la tangente: tan(45°) = sin(45°)/cos(45°) = 1

Recuerda que estas razones trigonométricas se obtienen a partir de la relación entre los lados de un triángulo rectángulo y se utilizan para calcular longitudes, ángulos y relaciones en problemas trigonométricos.

Answer:

m1=45

m1=88

m2=42

m3=113

Step-by-step explanation:

a) The range is 14.

b) The sample variance is 20.78.

c) The sample standard deviation is 4.56.

a) Range

The range of a given set of data values is the difference between the maximum and minimum values in the set. In this case, the maximum value is 15 and the minimum value is 1. So, the range is:

Range = maximum value - minimum value

Range = 15 - 1

Range = 14

b) Sample variance

To calculate the sample variance, follow these steps:

1. Calculate the sample mean (X). To do this, add up all of the data values and divide by the total number of values:

n = 9

∑x = 7 + 4 + 6 + 12 + 8 + 15 + 1 + 9 + 13 = 75

X = ∑x/n = 75/9 = 8.33

2. Subtract the sample mean from each data value, square the result, and add up all of the squares:

(7 - 8.33)² + (4 - 8.33)² + (6 - 8.33)² + (12 - 8.33)² + (8 - 8.33)² + (15 - 8.33)² + (1 - 8.33)² + (9 - 8.33)² + (13 - 8.33)² = 166.23

3. Divide the sum of squares by one less than the total number of values to get the sample variance:

s² = ∑(x - X)²/(n - 1) = 166.23/8 = 20.78

Therefore, the sample variance is 20.78 (rounded to two decimal places).

c) Sample standard deviation

To calculate the sample standard deviation, take the square root of the sample variance:

s = √s² = √20.78 = 4.56

Therefore, the sample standard deviation is 4.56 (rounded to two decimal places).

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Answer:

um.................

Step-by-step explanation:

Using the triangle inequality theorem, the largest possible whole-number length for the third side is 4.

The third side of a triangle must be shorter than the sum of the other two sides and longer than the difference between the other two sides.

So, for a triangle with sides of length 1, 4, and x (where x is the length of the third side), we have:

1 + 4 > x

4 + x > 1

1 + x > 4

Simplifying these inequalities, we get:

5 > x

x > 3

x > -3 (this inequality is always true)

The largest possible whole-number length for the third side is 4, since it is the largest integer that satisfies the above inequalities.

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Answer:

b)

...............

Answer:64

Step-by-step explanation:

Answer:

A scalene triangle is one whose sides are all a different length. So there is no way you can find the length of b when you are only given the length of a and the perimeter.

Step-by-step explanation:

hopes it help :)

Answer:

25 minutes.

Step-by-step explanation:

From 7:45 to 8:00 is 15 minutes.
From 8:00 to 8:10 is 10 minutes.
15 + 10 = 25
15 minutes + 10 minutes = 25 minutes,

Answer:

1. -3, -2.5, -3/4, -3/8, 1/4, 16/5, 3.1, 6

Step-by-step explanation:

2. -2.7<4.5

I know 1. is right but 2. I'm not sure how advance the math is but that is what I got for the answer

Answer:

Yes

Step-by-step explanation:

What Are The Questions

Answer:

3.125 cm

Step-by-step explanation:

cos50 ≈ 0.64 = b/h
b = 2
∴ h = 2/0.64 = 3.125 cm

The algorithm also runs in exponential time, since the number of possible strings, partitions, and paths is exponential in the size of M. Therefore, REPEAT DFA is in EP.

a. To show that REPEAT DFA is decidable, we need to show that there exists an algorithm that can determine whether a given DFA M satisfies the condition that for every string s in L(M), s can be written as s = uv where u = v.

One way to do this is as follows:

Construct the reverse DFA M' of M.

Compute the set R of all reachable states in M' starting from the set of accepting states of M.

For each state r in R, construct a regular expression that describes the set of all strings that can be read by M' from r to any accepting state.

Construct a regular expression R that is the union of all the regular expressions computed in step 3.

Check if R contains the pattern (.)\1+, which matches any string that contains a repeated substring.

If R contains the pattern from step 5, then M is not in REPEAT DFA; otherwise, it is.

Since this algorithm terminates and correctly determines whether M is in REPEAT DFA, REPEAT DFA is decidable.

b. To show that REPEAT DFA is in the class EP (exponential time), we need to show that there exists a nondeterministic algorithm that can solve REPEAT DFA in exponential time.

One way to do this is as follows:

For each state q in M, nondeterministically guess a string s in L(M) that ends in q.

For each guessed string s, nondeterministically guess a partition of s into two equal-length substrings u and v.

For each guessed partition (u,v), nondeterministically guess a path in M from the start state to q that reads u and another path that reads v.

If there exists a guessed string, partition, and pair of paths such that u = v, then accept; otherwise, reject.

This algorithm correctly determines whether M is in REPEAT DFA, since if M is in REPEAT DFA, then there exists a string s in L(M) such that s = uv and u = v, and the algorithm will guess this string, its partition, and its paths. The algorithm also runs in exponential time, since the number of possible strings, partitions, and paths is exponential in the size of M. Therefore, REPEAT DFA is in EP.

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