the initial velocity of a military jet is 195 m/s eastward. the pilot ignites the afterburners, and the jet accelerates eastward at a constant rate for 1.65 s. the final velocity of the jet is 345 m/s eastward. what was the jet's displacement during the time it was accelerating?

Answer:

A, I think, hope this helps!

Answer:

i think d because some people are talented even though they are suffering

Answer:

I think its O A. True.

The distance between your eye and the image of the butterfly in the mirror is 70 cm.

To find the distance between your eye and the image of the butterfly in the mirror, The concept of virtual images formed by plane mirrors.

Given:

Distance of the butterfly from the mirror \(\rm ($d_{\text{butterfly}}$)\) = 20 cm

Distance of you from the mirror \(\rm ($d_{\text{you}}$)\) = 50 cm

Known, that the distance of the virtual image \(\rm ($d_{\text{image}}$)\) formed by a plane mirror is the same as the distance of the object from the mirror:

\(\rm $d_{\text{image}} = d_{\text{butterfly}}$\)

Calculate the distance between your eye and the image of the butterfly in the mirror:

\(\rm $d_{\text{eye-image}} = d_{\text{you}} + d_{\text{image}}$\)

Substitute the given values:

\(\rm $d_{\text{eye-image}} = 50 \ \text{cm} + 20 \ \text{cm} \\= 70 \ \text{cm}$\)

The distance between your eye and the image of the butterfly in the mirror is 70 cm.

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To calculate the percent crystallinity of branched polyethylene, you need to know its density. However, the density alone is not sufficient to determine the crystallinity.

Crystallinity is usually determined using techniques such as X-ray diffraction or differential scanning calorimetry. These techniques analyze the polymer's structure and thermal behavior to determine the percentage of crystalline regions.

If you have additional information, such as the degree of branching or molecular weight, please provide it so that I can assist you further. Crystallinity is usually determined using techniques such as X-ray diffraction or differential scanning calorimetry (DSC).

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The statement that describes energy of the roller coaster as it slows down while travelling to the top of the coaster is 'The cart loses kinetic energy and gains potential energy.'

Consider three roller coaster points that are each at a different height from the ground. If we disregard all frictional and drag forces and focus just on the conservative forces acting on the roller coaster car, we may assume that all kinetic and potential energy is conserved. As a result, energy only transforms from one form to another.

When the roller coaster vehicle hits the bottom, it will have reached its maximum level of kinetic energy since all of the gravitational potential energy has been transformed into kinetic energy.

At the top of the roller coaster, the object has its maximum gravitational potential energy and none at all (assumed there is no velocity). As the object begins to fall to the bottom, its gravitational potential energy falls and its kinetic energy increases.

Hence, as the cart reaches the top, it slows down because it loses kinetic energy and gains potential energy.

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Answer:

9000N

Explanation:

gravitational field strength of earth is approximately 10N/kg .

900kg×10N/kg

=9000N

Hi! Based on your description, it seems the figure is not provided, but I will assume the capacitors are connected in series. For capacitors of equal capacitance (C) connected in series, the equivalent capacitance (Ceq) is given by:

1/Ceq = 1/C1 + 1/C2 + 1/C3

Since all capacitors have equal capacitance (C), the equation becomes:

1/Ceq = 1/C + 1/C + 1/C = 3/C

To find Ceq, we can rearrange the equation:

Ceq = C/3

So the equivalent capacitance of this combination is C/3, which corresponds to option E.

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a) The statement regarding inductance measuring the opposition to change in current in a loop or coil is true.

b) In a RL circuit, the resistor, capacitor, and the inductor are not connected in series with the battery Hence, it is false.

c) The statement about time constant of the circuit being 5.0 ms is true.

d) The statement about the frequency of oscillation of the circuit being 5.9 x105 Hz is false.

e) The statement about the inductance of this solenoid being 0.754 mH is true.

Inductance quantifies the resistance encountered when attempting to alter the flow of electric current. The presence of an electrical current in a conductor generates a surrounding magnetic field. Inductance is a measure of the strength of the magnetic field generated by the coil when the current flowing through it varies. A unit of measurement for inductance is the henry (H).

False because in an RL circuit, the resistor, inductor, and battery are connected in series, but the capacitor is not present in this circuit. Hence the answer is False. 

True since time constant (T) = L/R = 60 × 10^-3/12 Ω = 5.0 × 10^-3 s or 5.0 ms

False because the frequency of oscillation in the LC circuit is given by f = 1/2π√(LC), where L and C are the inductance and capacitance of the circuit, respectively. Hence, the answer is False. 

True because the inductance of a solenoid is given by L = μ0n2A/l, where A is the cross-sectional area of the solenoid, l is the length of the solenoid, n is the number of turns per unit length, and μ0 is the magnetic constant. Substituting the given values, we have L = 4π × 10^-7 × 5002 × 6.0 × 10^-4/0.25 mH = 0.754 mH. Hence the answer is True.

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King tide happens during a king tide when the moon is between the earth and the sun. When the Moon's orbit around Earth is at its first and last quarter phases, neap tides happen.

Turns it so that it is parallel to the Sun. Extremely high or extremely low tides can occur when Earth, the Moon's orbit, and the Sun line up because of the combined gravitational effect. Moderate tides occur when the Sun and the Moon are at a straight angle. Its gravitational pull causes the Earth's tides and somewhat lengthens the day as it orbits the planet at a distance of 384,400 km (238,900 mi), or about 30 times the diameter of the planet. A sidereal period of 27.3 days characterizes the Moon's orbit of the Earth.

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Answer for the first one is 2. The answer for the 3rd one is 8

Answer: Element

Explanation:Elements are the simpilist kind of matter thefor can not break down

During daytime, the positions of the three bodies - the Sun, Moon, and Earth - are as follows: The Sun is located above the horizon, providing the primary source of light and illuminating the sky.

The Earth is beneath the Sun, with the observer standing on its surface. The Moon, although present in the sky, may or may not be visible, depending on its phase and position relative to the Sun and Earth.

During nighttime, the positions change. The Sun is located on the opposite side of the Earth, causing the sky to darken. The Moon may be visible, appearing in various phases depending on its position in its orbit around the Earth.

Overall, the positions of the Sun, Moon, and Earth change throughout the day and night due to the rotation and orbiting motion of the Earth and Moon.

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Answer:

The energy that can be stored in the capacitor is 239 nJ

Explanation:

We first calculate the capacitance of each material. Let C₁ be the capacitance of pyrex glass and C₂ be the capacitance of polystyrene.

C₁ = κ₁ε₀A/d where κ₁ = dielectric constant of pyrex glass = 5, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of pyrex slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m

C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 5 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 2424.2252/1.60 × 10⁻¹¹ F = 1515.14 × 10⁻¹¹ F = 15.2 × 10⁻⁹ F = 15.2 nF

C₂ = κ₂ε₀A/d where κ₂ = dielectric constant of polystyrene = 3, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of polystyrene slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m

C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 3 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 1454.5351/1.60 × 10⁻¹¹ F = 909.08 × 10⁻¹¹ F = 9.09 × 10⁻⁹ F = 9.09 nF

Since the capacitors are in series, we find their effective capacitance C from

1/C = 1/C₁ + 1/C₂

C = C₁C₂/(C₁ + C₂)

= 15.2 × 10⁻⁹ F × 9.09 × 10⁻⁹ F/(15.2 × 10⁻⁹ F + 9.09 × 10⁻⁹ F)

= 138.168 × 10⁻¹⁸/24.29 × 10⁻⁹ F

= 5.69 × 10⁻⁹ F

The amount of electrical energy stored in a capacitor is given by W = 1/2CV² where C = capacitance and v = voltage applied. Now C = 5.69 × 10⁻⁹ F and V = 84.0 V for this capacitor

So W = 1/2 × 5.69 × 10⁻⁹ F × 84.0 V

= 238.98 × 10⁻⁹ J

≅ 239 × 10⁻⁹ J

= 239 nJ

So the energy that can be stored in the capacitor is 239 nJ

Answer:

9 m/s

Explanation:

speed = distance ÷ time

27÷3

=9

Total Cost is =  $107,380 if The farm is 340 acres and had corn planted  add fertilizer to the soil before you plant this years' crop.

A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".

Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.

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The telescope that allowed astronomers to discover most of the planets found with the transit method was called the Kepler mission.

Through only this one telescope, Kepler, astronomers have found thousands of extrasolar planets, or exoplanets, since its inception. Most of them are planets with diameters ranging from Earth's to Neptune's (which is four times the size of Earth). Where Kepler was directed for the first four years of its mission, in an area of the constellation Cygnus roughly the size of the palm of a hand held at arm's length, many of these planets were found.

According to the NASA Exoplanet Archive, as of November 2020, Kepler was credited with finding 2,392 exoplanets, with 2,368 candidate planets still awaiting confirmation.

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Deposition occurs when the agents (wind or water) of erosion lay down sediment. Deposition changes the shape of the land. Erosion, weathering, and deposition are at work everywhere on Earth. Gravity pulls everything toward the center of Earth causing rock and other materials to move downhill

Answer: I solved it and got 30.65 meters.

Explanation: Pic Attached. Hope this helps.

Answer:

30.65

Explanation:

becuase i read the othe part

The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.

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Answer: Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart.

Answer:

conduction occurs when gas becomes liquid.

Explanation:

Efficiency is a way of describing the amount of useful ​output​ a process or machine can generate as a percentage of the ​input​ required to make it go. In other words, it compares how much energy is used to do work versus how much is lost or wasted to the environment. The more efficient the machine, the less energy wasted.

For example, if a heat engine is able to turn 75 percent of the fuel it receives into motion, while 25 percent is lost as heat in the process, it would be 75 percent efficient. Out of the original 100 percent of the fuel, 75 percent was output as useful work.  

the equation:

energy efficiency =useful output energy/total input energy

According to the kinetic molecular theory, gas particle collisions are completely elastic. When two objects collide in an elastic collision, their combined kinetic energy is preserved during the collision.

There is no force of attraction between the molecules of a gas, which is one of the two kinetic theory's presumptions that does not hold true. ii As relation to the space a gas occupies, a gas's molecular volume is extremely small.

The theory assumes that gases consist of widely separated molecules of negligible volume that are in constant motion, colliding elastically with one their absolute temperatures are used to calculate the average velocities between one another and the container walls.

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Answer:

To find the distance, use the formula for distance d = st, or distance equals speed times time.

Answer:

Speed=distance/time

time=distance/speed

distance=speed *time

(a) The magnitude of the net electric field at x = -0.17 m is 1.01x10^5 N/C.

(b) The magnitude of the net electric field at x = +0.17 m is 1.01x10^5 N/C.

(c) The magnitude of the net electric field at y = +0.17 m is 4650 N/C.

Explanation:

To solve this problem, we can use the formula for electric field due to a point charge and the principle of superposition of electric fields.

The electric field due to a point charge is given by:

E = k*q/r^2

where E is the electric field, k is Coulomb's constant (9x10^9 N m^2/C^2), q is the charge, and r is the distance from the point charge.

(a) To find the net electric field at x = -0.17 m, we need to consider the electric field due to the point charge and the uniform electric field. The distance from the point charge to x = -0.17 m is:

r = sqrt((0.17)^2) = 0.17 m

The electric field due to the point charge at x = -0.17 m is:

E1 = kq/r^2 = (9x10^9 N m^2/C^2)(-8.40x10^-9 C)/(0.17 m)^2 = -1.06x10^5 N/C (in the negative x direction)

The electric field due to the uniform electric field is given by:

E2 = 4650 N/C (in the positive x direction)

The net electric field at x = -0.17 m is the vector sum of E1 and E2:

E_net = E1 + E2 = -1.06x10^5 N/C + 4650 N/C = -1.01x10^5 N/C

Therefore, the magnitude of the net electric field at x = -0.17 m is 1.01x10^5 N/C.

(b) To find the net electric field at x = +0.17 m, we follow the same procedure as in part (a). The distance from the point charge to x = +0.17 m is:

r = sqrt((0.17)^2) = 0.17 m

The electric field due to the point charge at x = +0.17 m is:

E1 = kq/r^2 = (9x10^9 N m^2/C^2)(-8.40x10^-9 C)/(0.17 m)^2 = -1.06x10^5 N/C (in the positive x direction)

The electric field due to the uniform electric field is given by:

E2 = 4650 N/C (in the positive x direction)

The net electric field at x = +0.17 m is the vector sum of E1 and E2:

E_net = E1 + E2 = -1.06x10^5 N/C + 4650 N/C = -1.01x10^5 N/C

Therefore, the magnitude of the net electric field at x = +0.17 m is 1.01x10^5 N/C.

(c) To find the net electric field at y = +0.17 m, we only need to consider the electric field due to the uniform electric field, since the point charge is located on the x-axis. The electric field due to the uniform electric field is given by:

E = 4650 N/C (in the positive x direction)

Therefore, the magnitude of the net electric field at y = +0.17 m is 4650 N/C, in the positive x direction

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Answer:

a)  v = 126.5 m / s,  b)   λ₁ = 1.6 m,   λ₂ = 0.8 m, λ₃ = 0.533 m,   f1 = 79 Hz,    

λ₂ = 0.8 m,   f₃ = 237 Hz

Explanation:

This is an exercise we are going to solve in parts, let's start by looking for the speed of the wave in the string.

         v = \(\sqrt { \frac{T}{ \mu } }\)

the rope tension is T = 90 N and the density can be calculated

         μ = m / l

let's calculate

         μ = 4.5 10⁻³ / 0.80

         μ = 5.625 10⁻³  kg/m

let's calculate the speed

         v = \(\sqrt{ \frac{90 }{5.625 \ 10^{-3}} }\)

         v = 126.5 m / s

For the second part there is a process of resonance in the string. The points where it is attached are nodes so, if L is the length of the chord

         L = ½ λ         1st harmonic

         L = 2/2 λ      2nd harmonic

         L = 3/2 λ      3rd harmonic

         L = n/2 λ      n harmonic

the wavelength of the first three harmonics is requested

let's calculate

          λ₁ = 2L

          λ₁ = 2 0.8

          λ₁ = 1.6 m

          λ₂ = L

          λ₂ = 0.8 m

          λ₃ = ⅔ L

          λ₃ = ⅔ 0.8

          λ₃ = 0.533 m

To calculate the frequency we use that the speed is related to the wavelength and the frequency

           v = lam f

           f = v / lam

we calculate

           f1 = 126.5 / 1.6

           f1 = 79 Hz

           f2 = 126.5 / 0.8

           f2 = 158 Hz

           f3 = 126.5 / 0.533

           f3 = 237 Hz

The molality of the nonvolatile, nonelectrolyte solute needed to lower the melting point of camphor by 1.035 degrees C (Kf = 39.7 degrees C/m) is 0.026 M.


The molality of the nonvolatile, nonelectrolyte solute needed to lower the melting point of camphor by 1.035 degrees C (Kf = 39.7 degrees C/m) can be calculated using the formula:

ΔTf = Kf x m

Where ΔTf is the change in freezing point, Kf is the freezing point depression constant, and m is the molality of the solute. The freezing point depression is a colligative property that depends on the number of solute particles in a solution, not their identity or chemical properties.

Camphor is a nonpolar compound that forms a lattice structure in the solid state. When a nonvolatile, nonelectrolyte solute is added to the camphor solution, it lowers the freezing point of the solution by disrupting the crystal lattice and making it more difficult for the solvent molecules to form the ordered arrangement required for freezing. This is why the freezing point of the solution is lower than that of the pure solvent.

In this case, we are given ΔTf = 1.035 degrees C and Kf = 39.7 degrees C/m. Substituting these values into the formula above, we get:

m = ΔTf / Kf = 1.035 / 39.7 = 0.026 M

Therefore, the molality of the solute needed to lower the melting point of camphor by 1.035 degrees C is 0.026 M.

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