The image blow shows a certain type of global wind:
What best describes these winds? Polar easterlies caused by air above poles being relatively warmer.
Polar easterlies caused by air above poles being relatively cooler.
Trade winds caused by air above equator being relatively warmer.
Trade winds caused by air above equator being relatively cooler.​

Answer:

Resultant = 54.67 N

Direction: 50.2° to the horizontal

Explanation:

Note: Since both forces form a right angle triangle, As shown in the diagram below,

Applying

Pythagoras theorem,

a² = b²+c²..................... Equation 1

From the question,

a = R, b = 42 N, c = 35 N

Substitute these values into equation 1

R² = 42²+35²

R² = 1764+1225

R² = 2989

R = √2989

R = 54.67 N

Direction

tanФ = a/b

Where Ф = direction of the resultant

tanФ = 42/35

tanФ = 1.2

Ф = tan⁻¹(1.2)

Ф = 50.2° to the horizontal

An annotated bibliography is a list of citations to books, articles, and documents. Each citation is followed by a brief descriptive and evaluative paragraph, the annotation. The purpose of the annotation is to inform the reader of the relevance, accuracy, and quality of the sources cited.

The cue column is typically located on the left-hand side of the page and is used to jot down keywords or questions that serve as cues for recalling the main points of the lecture or reading. The note-taking area is located on the right-hand side of the page and is used to write down detailed notes about the lecture or reading.

The summary section is located at the bottom of the page and is used to summarize the key points of the notes. Overall, the Cornell method is an effective way to organize and retain information during lectures and readings.

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Answer:

free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s/s in The Physics Classroom Tutorial in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy.

g = 9.8 m/s/s, downward

( ~ 10 m/s/s, downward)

Explanation:

Look It Up!

Even on the surface of the Earth, there are local variations in the value of the acceleration of gravity (g). These variations are due to latitude, altitude and the local geological structure of the region. Use the Gravitational Fields widget below to investigate how location affects the value of g.

Answer:

there is no acceleration

Explanation:

acceleration only occurs when the speed changes for example if you were to start at 10m/s and after ten seconds be at 50m/s then there would be acceleration but because speed is constant there is no acceleration

Answer: Is the bird balanced or unbalanced on the swing?

What kind of motion is acted on the swing by the bird?

Answer:

What is the chemical fórmula For the molecule modeled?

Explanation:

C6H12O2

20Kg x 1000g x 1 Equals 20000 gram of water. 10 000 gram times a temperature range of 40 to 80 is 12000 calories. 5023200 joules are equal to 10,000 gram times 4.186 joules at 40 or 80 degrees.

kilojoules (kJ), energy. A equation E Equals mc2, were E is already in joules, m is now in kilogrammes, and c seems to be the light speed in metres per second, can be used to recall the base unit conversion. To view the outcomes displayed in the table, enter the quantity of kJ you wish to convert into the text box.

Heat has kJ of energy (or BTU). The quantity of heat transmitted per unit of time is known as the rate of heat transfer. Heat has a magnitude, a direction, and an action point because it is a direction (or vector) quantity. Heat transmission quantity is noted as Q (kJ).

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Answer:

2 m/s2

Explanation:

Newton's 2nd law:

F=ma

20 N= (10 kg)a

a= 2 m/s2

The water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.

To find the water pressure at the base of the tank, take the formula:

Pressure = density × gravity × height

In which

Density = density of water (1000 kg/m³)

Gravity = acceleration due to gravity (9.8 m/s²)

Height = height of the column

According to question:

Height of the water column = 10 m

Take the formula:

P = 1000 kg/m³ × 9.8 m/s² × 10 m

= 98,000 Pa

To find the force at the base of the tank, take the formula:

Force = Pressure × Area

In which

Pressure = pressure at the base of the tank

Area = base area of the tank

The base area of a cylindrical tank can be found by the formula:

Area = π × r²

In which:

Diameter of the tank = 6 m

To find the radius, divide the diameter by 2:

Radius = 6 m ÷ 2

= 3 m

Put the values into the formula:

Area = π × (3 m)²

= 28.27 m²

Now, find the force:

Force = 98,000 Pa × 28.27 m²

= 2,768,460 N

Thus, the water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.

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The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.

We can use the formula Q = I * t,

where;

Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:

I = Q / t = 6.4 C / 2 s = 3.2 A

So, the current through the conductor is 3.2 A.

To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:

Q = I * t = 3.2 A * 60 s = 192 C

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Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

\(F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N\)

b)

\(F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N\)

c)

\(F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N\)

Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

Answer:

A is correct a.p.e.x approved

Explanation:

have a nice day

a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Answer:

C. That the small portion of the space we can see is truly representative of all the rest of the universe that we cannot see.

Explanation:

The Cosmological Principle assumes that the small portion of the universe that we can see is representative of the entire universe, even though we can only directly observe a tiny fraction of it. It's an assumption used by Cosmologists to simplify their models of the universe.

Answer:

11948.64 Newtons

Explanation:

Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

Answer:

pyramid, cone, sphere, cube

The type of problem that corresponds to a description is Inducing structure (option B)

An inducing structure is a type of problem that involves establishing one or more relationships between different elements. For example:

In this analogy problem, the answer would be animal.

This analogy requires people to identify the relationship between Rose and Plant and construct a similar relationship between the Lion and category similar to Plant.

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Answer:

 the motion of a spinning top, rotation of the earth and other planets, movement of hands of a clock, etc.

Answer:

the motion of a spinning top, rotation of the earth and other planets, movement of hand of a clock, etc.

Answer:

108 N

Explanation:

Divide the force by uk to get the normal force

(25.7)/(0.238) = 107.98 N = 108 N

Answer:

107

Explanation:

equal in magnitude but opposite in direction

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

First, we shall determine the work done in pushing the cart. Details below:

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

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Answer:

0.275J

Explanation:

Given parameters:

Extension  = 0.5m

Spring coefficient  = 2.2N/m

Unknown:

Energy stored in the rubberband  = ?

Solution:

The elastic potential energy is given as:

  Elastic potential energy  = \(\frac{1}{2}\) k e²  

 k is the spring constant

e is the extension

         Elastic potential energy  = \(\frac{1}{2}\)  x 2.2 x 0.5²  = 0.275J

1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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Answer:

The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.

Explanation:

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

Answer:

The scale at the North Pole is higher by 3.1 N.

Explanation:

The scale at the equator has a centripetal acceleration unlike the North Pole. So, finding acceleration at the equator from centripetal force,

(mv^2)/r = mg

v^2/r=g

463 m/s ^2 / 6378100 m = g

g = 0.0336

then multiply by the mass, 91 kg,

you'll get the difference of 3.06 or 3.1 rounded.

A man of weighs himself 91 kg at the north pole and at the equator, so the scale reading at the North Pole will be higher by 3.1 N.

The equator is a large circle that surrounds the Earth, lies in a plane perpendicular to its axis, and is evenly spaced from both geographic poles.

The geographic Equator, also known as the terrestrial Equator, is the imaginary line on the surface of the Earth from which latitude is calculated. It is also the line at 0° latitude. The geographic Equator separates the Earth into the Northern and Southern hemispheres.

According to the question,

The equator has a centripetal acceleration that is different from the North Pole. So, finding acceleration at the equator from the centripetal force,

mg = (mv²) / r

g = v²/r

g= 463 / 6378100

g = 0.0336

then,

0.0336 × 91

= 3.06

Hence, the difference will be 3.06.

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