the gravitational potential energy of an realtive to the ground dependant on the objects​

Answer:

the magnitude F of the total friction force is 2456.7 lb

Explanation:

Given the data in the question;

maximum speed = 35 mi/hr = ( 35×5280 / 60×60) = 51.3333 ft/s

diameter = 200ft

radius = 200/2 = 100 ft

First we calculate the normal component of the acceleration;

\(a_{n}\) = v² / p

where v is the velocity of the car( 51.3333 ft/s)

p is the radius of the curvature( 100 ft)

so we substitute

\(a_{n}\) = (51.3333 ft/s)² / 100ft

\(a_{n}\) = (2635.1076 ft²/s²) / 100ft

\(a_{n}\) = 26.35 ft/s²

we convert Feet Per Second Squared (ft/s²) to Standard Gravity (g)

1 ft/s² = 0.0310809502 g

\(a_{n}\) = 26.35 ft/s² × 0.0310809502 g

\(a_{n}\) =  0.8189g

Now consider the dynamic equilibrium of forces in the Normal Direction;

∑\(F_{n}\) = m\(a_{n}\)

F = m\(a_{n}\)

we know that mass of the car is 3000-lb =  3000lb(\(\frac{1}{g}slug\)/1 lb)

so

we substitute

F =  3000lb(\(\frac{1}{g}slug\)/1 lb)  × 0.8189g

F = 2456.7 lb

Therefore; the magnitude F of the total friction force is 2456.7 lb

Answer:

Divide the change in distance by the change in time.

Explanation: Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

To my best knowledge It's D

The force needed to pull the wrench of 30 cm long is 643.95 N.

Force can be defined as the product of mass and aceleration.

To calculate the force that must be pull, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Note: The negative sign tells the direction of the force and can be ignored (Pull)

Hence, the force need to pull is 643.95 N.

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The skateboarder touches a distance of R= 7.09m from the end of the ramp.

Velocity can be defined as the rate of change of the object's position with respect to a frame of reference and time.

From the given instance, the skateboarder touches a distance of R= 7.09m from the end of the ramp

Velocity along y axis = 9.0 sin30 = 4.5m/s.

Velocity along x axis = 9cos30 = 7.79m/s

Vfinal -Vinitial  = acceleration * time

4.5 = 10t ; t(up) = 0.45s.

Hy =  9*(sin 30°)*T1 - (1/2)*g*T1^2  [ upward movement]

Hy= 9*(1/2)*0.45 - (1/2)*9.81*0.45^2

Hy = 2.025 - 0.993

Hy = 1.032

T2 = √[(2/9.81)*1.032] = 0.46

R = (T1 + T2)*9*(cos 30°)

R= (0.45+0.46)* 9* 0.8660

R= 7.09m

In conclusion, Velocity is a vector quantity that refers to "the rate at which an object changes its position.

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Volume of rectangular block is 75.4 cm^3

Density of the rectangular block is 8.02 g/cm^3

Volume is simply defined as the space occupied within the boundaries of an object in three-dimensional space.

It is also known as the capacity of the object.

Volume of rectangular block = length× breadth× height

=2.9 cm × 2.6 cm × 10.0 cm

=75.4 cm^3

Density is defined as the substance's mass per unit of volume.

Mathematically ,density is defined as mass divided by volume.

Density of the block = Mass of block / volume of block

=605.0 g / 75.4 cm^3

=8.02 g/cm^3

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Answer:

Crosstalk

Explanation:

The answer is Crosstalk as this phenomenon is most commonly associated with analog phone call.

Now, crosstalk is defined as a disturbance caused by the electric or magnetic fields of one telecommunication signal which affects a signal in an adjacent circuit. In a telephone circuit, crosstalk could result in hearing part of a voice conversation from another circuit. Hence, the phenomenon that causes crosstalk is called electromagnetic interference (EMI). This may occur in microcircuits within computers and audio equipments including within network circuits. This term is also usually applied to optical signals that interfere with each other.

The velocity distribution in the fluid can be found using the Navier-Stokes equation, which states that the net force on a fluid element is equal to its mass times its acceleration.

(a) Velocity distribution and torques on two coaxial cylinders:

The fluid is incompressible, so the continuity equation can be used to relate the fluid velocities at different radii. For the coaxial cylinders, the velocity distribution can be found by assuming a linear velocity profile between the two surfaces, where the velocity at the inner surface is ai * kr and the velocity at the outer surface is a * r. Therefore, the velocity profile is given by:

v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr

The torque required to maintain the motion of the cylinders can be found using the formula:

T = I * α

where T is the torque, I is the moment of inertia, and α is the angular acceleration. For each cylinder, the moment of inertia is given by:

I = (1/2) * m * R²

where m is the mass of the cylinder and R is its radius. The angular acceleration is related to the angular velocity by:

alpha = (a - ai) / (r - kr)

Therefore, the torque on the inner cylinder is:

Ti = (1/2) * m * kr² * (a - ai) / (r - kr)

and the torque on the outer cylinder is:

To = (1/2) * m * r² * (a - ai) / (r - kr)

(b) Velocity distribution and torques on two concentric spheres:

The velocity distribution and torques on two concentric spheres can be found in a similar way to the coaxial cylinders. Assuming a linear velocity profile between the two spheres, where the velocity at the inner sphere is ai * kr and the velocity at the outer sphere is a * r, the velocity profile is given by:

v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr

The torque required to maintain the motion of the spheres can be found using the same formula as for the cylinders, with the moment of inertia for each sphere given by:

I = (2/5) * m * R²

where m is the mass of the sphere and R is its radius. Therefore, the torque on the inner sphere is:

Ti = (2/5) * m * kr² * (a - ai) / (r - kr)

and the torque on the outer sphere is:

To = (2/5) * m * r² * (a - ai) / (r - kr)

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Answer:

ultraviolet light

plz mark me as brainliest.

Answer:

Ultra violet

Explanation:

Answer:

Heat gain = Heat loss

Latent heat of fusion of water = 80 kcal/kg

Specific heat of water = 1 kcal /kg deg C

Heat gain = 1.33 * 80 + (12.4 + 1.33) T = 106 + 13.7 T

Heat Loss = 12.4 * (20 - T) = 248 - 12.4 ΔT

106 + 13.7 T = 248 - 12.4 T

26.1 T = 142

T = 5.4       final temperature

Answer: 10.310406 (works for acellus)

I tried to add an explanation but it wouldn't let me for some reason

Anyways watch the end of the video to see how to get the equation

the equation is hard and for this equation to be solved download e book

The Doubling Theory is a mathematical concept that involves finding a number that, when doubled repeatedly, equals a given value. To solve an equation using the Doubling Theory, you need to determine the number of doublings required to reach the given value.

The Doubling Theory is a mathematical concept that involves finding a number that, when doubled repeatedly, equals a given value. To solve an equation using the Doubling Theory, you need to determine the number of doublings required to reach the given value. Let's say the equation is 2^n = 64. We can start with 2 and double it repeatedly until we reach 64:

It took 5 doublings to reach 64, so the value of n in the equation 2^n = 64 is 5.

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Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer:

875 Watts

Explanation:

P = W/t = mgh/t = 700(10)/8 = 875 Watts

Answer:

hi

Explanation:

hey

Answer:

(A) potential energy

I think it helps you

24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using linear perspective in art.

One of the pioneers of modern art, Cezanne used a novel approach to painting at the time. In his still life paintings, Cezanne represented things utilizing a system of flattened planes and simplified forms rather than the conventional perspective techniques that provide the impression of depth and space.

Additionally, he played around with color, relying on color blocks rather than shading and modeling to convey a sense of volume and form.

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The statements that apply to inertia are that it is a force that maintains moving objects in motion, a force that keeps stationary objects at rest, a force that causes stationary objects to naturally resist motion, and a force that causes moving objects to naturally resist changes in velocity.

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.

As given all the following the statements that are true about inertia are,

1. Inertia is the force that keeps a moving object in motion.

2. Inertia is the force that keeps a stationary object at rest.

3. Inertia is the natural tendency of a stationary object to resist motion.

4. Inertia is the natural tendency of a moving object to resist a change in its velocity.

Thus, all the given options are correct about inertia.

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Answer:

your

answer is

12.004

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

\(v_{f}=v_{o}+a*t\)

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

\(v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}\)

Answer:

yes u are correct

Explanation:

Answer:

240 C

Explanation:

Given:

To find:

Solution: Formula relating Q, I and t is given as:

Thus, 240 Coulomb charge will pass through the wire.

Answer: 197,500 mi/s into yd/s Is 347600000 yd/s

Explanation:

Answer:

1200 lb-ft

Explanation:

Weight of diver W = 150 lb

length of board L = 8 ft  

This board is pivoted at one end therefore, the perpendicular distance from the pivot = 8 ft

Torque = weight x perpendicular distance from pivot

T = WL

Torque = 150 x 8 = 1200 lb-ft

Bright lines in its emission spectrum have the same wavelengths as the dark lines of its absorption spectrum. Hence, option (d) is correct.

The electromagnetic radiation spectrum that is emitted when an atom or molecule changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound.

Absorption spectrum: An electromagnetic spectrum where a drop in radiation strength at particular wavelengths or ranges of wavelengths indicative of an absorbing substance (such as chlorophyll) is particularly visible as a pattern of dark lines or bands, in contrast to emission spectrum.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

The speed (magnitude of the velocity) is 14.4 m/s

Explanation:

Vertical Launch Upwards

It occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the speed vf at any time is calculated by:

\(v_f=v_o-g.t\)

A tennis ball is launched vertically up with an initial speed of vo=34 m/s. At time t=2 s, its speed is:

\(v_f=34-9.8*2\)

\(v_f=34-19.6\)

\(v_f=14.4\ m/s\)

The speed (magnitude of the velocity) is 14.4 m/s

the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s

the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(1.5g * 13m)

v = sqrt(22.5 * 9.8)

v = sqrt(219.5)

v = 14.8 m/s

(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(g * 13m)

v = sqrt(9.8 * 13m)

v = sqrt(127.4)

v = 11.3 m/s

So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

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