Answer:
Step-by-step explanation:
The key to solving this question is to find the distance bwtween the two points given
distance=y2-y1/x2-x1
(2,4)(4,8)
2=x1,4=y1
4=x2
8=y2
8-4/4-2
4/2=2
The depth of the water is increasing by 2 ft each minute
Answer:
it is incresing by two feet each minute
Step-by-step explanation:
John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collection is eleven less than five times John’s collection, and three times Jonathan’s collection is three less than seven times John’s collection.
The number of postage stamps in John’s collection is?
The number of postage stamps in John’s collection is 27.
What is an elimination method?The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with multiplication or division of coefficients of the variables.
Johan and Jonathan have the same number of stamps.
Let x be the Johan and Jonathan postal stamps.
Let y be the John postal stamps.
Two times Johan’s collection is eleven less than five times John’s collection.
2x = 5y - 11............(1)
Three times Jonathan’s collection is three less than seven times John’s collection.
3x = 7y - 3............(2)
Multiply equation 1 with 3
3(2x = 5y - 11)
⇒ 6x = 15y - 33.........(3)
Multiply equation 2 with 2
2(3x = 7y - 3)
⇒ 6x = 14y - 6.............(4)
Subtract equation 4 from equation 3
⇒ 6x - 6x = 15y - 33 - (14y - 6)
⇒ 0 = y - 27
⇒ y = 27
Hence, the number of postage stamps in John’s collection is 27.
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14. Find the value of x if QS bisects
m
PQS= (10x+1)
Answer:
4
Step-by-step explanation:
So when an angle is bisected, it splits it perfectly in half. The entire angle (PQR) is equal to 82 degrees, therefore PQS must be equal to half of 82, or 41.
So set up your equation: 10x+1=41. Just use basic algebra from here. Subtract 1 from both sides, then divide by 10. x=4. Hope this helps!
Need help asap please
Answer:
2) y= 4x+17
Step-by-step explanation:
y- y1 = m(x- x1)
y- 5 = 4 (x - (-3))
y-5= 4( x+ 3)
y-5= 4x+ 12
y= 4x+17
Find the next three terms in each geometric sequence.
1. 638, -216, 72.......
2. 1/6, 1/2, 4.......
3. 72, 36, 18.......
The next three terms in each geometric sequence is 72, 36, 18, 9, 4.5, 2.25.
What is the general form of geometric progression?The general form of Geometric Progression is: a, ar, ar 2, ar 3, ar 4,…,a n. Where,
a = First term.
r = common ratio.
a n = nth term.
General Term or Nth Term of GP.
Let a be the first term
And, r be the common ratio for a G.P.
The general form of Geometric Progression is:
GP-series
Where,
a = First term
r = common ratio
arⁿ ⁻¹ = nth term
The next three terms of the GP is :
2.25 + 2.25 = 4.5
4.5 + 4.5 = 9
9 + 9 = 18
18 + 18 = 36
36 + 36 = 72
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A bag contains a mixture of identical coloured balls.
The probability of selecting a blue ball from the bag is 0.6
There are 70 balls in the bag. How many are blue?
Answer:
42 blue balls
Step-by-step explanation:
\(p=\frac{Blue Balls}{TotalBalls}\)
\(0.6=\frac{BlueBalls}{70}\)
\(BlueBalls=70(0.6)=42\)
Hope this helps
Priya pours the same amount of orange juice every time she fills a glass. Each glass she pours
contains 21 grams of sugar.
1. Write an equation that represents how many grams of sugar (s) are in some number of
glasses of orange juice (g).
2. How much sugar is in 4 glasses of orange juice?
grams
Report a problem
The equation that represents how many grams of sugar (s) are in some number of glasses of orange juice (g) is s = 21g. There are 84 grams of sugar in 4 glasses.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.
Let s represent the amount of sugar in grams contained in g glasses of orange juice.
1) Each glass she pours contains 21 grams of sugar. Hence:
s = 21g
2) for g = 4:
s = 21(4) = 84
The equation that represents how many grams of sugar (s) are in some number of glasses of orange juice (g) is s = 21g. There are 84 grams of sugar in 4 glasses.
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Answer:
what the expert say
Step-by-step explanation:
A random sample of 70 observations produced a mean of x=30.9x from a population with a normal distribution and a standard deviation σ=2.47
(a) Find a 99% confidence interval for μ
(b) Find a 95% confidence interval for μ
c) Find a 90% confidence interval for μ
a) The population means 99% confidence interval is (28.861, 32.939).
(b) The 95% confidence interval for the population mean μ is (29.258, 32.542).
(c) The 90% confidence interval for the population mean μ is (29.567, 32.233).
To calculate confidence intervals, we can use the formula:
Confidence Interval = Sample Mean ± (Critical Value) * (Standard Deviation / √Sample Size)
(a) For a 99% confidence level, the critical value is obtained from the standard normal distribution as 2.576.
Using the formula's provided values, we obtain:
Confidence Interval = 30.9 ± (2.576) * (2.47 / √70) = (28.861, 32.939).
(b) For a 95% confidence level, the critical value is 1.96. Substituting the values, we have:
Confidence Interval = 30.9 ± (1.96) * (2.47 / √70) = (29.258, 32.542).
(c) For a 90% confidence level, the critical value is 1.645. Using the formula:
Confidence Interval = 30.9 ± (1.645) * (2.47 / √70) = (29.567, 32.233).
In each case, the confidence interval gives us a range of values within which we can be confident that the population mean lies, based on the sample mean and the given level of confidence. The interval is wider the higher the confidence level.
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public class BinarySearch \{ public static void main(Stringll args) f int [1]yl ist ={1,2,3,7,10,12,20}; int result = binarysearch ( inylist, 20); if (result =−1 ) System, out, println("Not found:"); else System.out.println("The index of the input key is " + result+ ". "): y public static int binarysearch(int]l List, int key) \{ int low =0; int high = iist. length −1 while (high >= low) \& int mid =( low + high )/2; if (key < List [mid] high = mid −1; else if (key =1 ist [ mid ] ) return inid; else low = mid +1; return −1; // Not found \} l TASK 4: Binary Search in descending order We have learned and practiced the implementation of the binary search approach that works on an array in ascending order. Now let's think about how to modify the above code to make it work on an array in descending order. Name your new binary search method as "binarysearch2". Implement your own code in Eclipse, and ensure it runs without errors. Submit your source code file (.java file) and your console output screenshot. Hint: In the ascending order case, our logic is as follows: int mid =( low + high )/2 if ( key < list [mid] ) else if (key = ist [mid]) return mid; In the descending order case; what should our logic be like? (Swap two lines in the above code.)
The task involves modifying the given code to implement binary search on an array in descending order. The logic of the code needs to be adjusted accordingly.
The task requires modifying the existing code to perform binary search on an array sorted in descending order. In the original code, the logic for the ascending order was based on comparing the key with the middle element of the list. However, in the descending order case, we need to adjust the logic.
To implement binary search on a descending array, we need to swap the order of the conditions in the code. Instead of checking if the key is less than the middle element, we need to check if the key is greater than the middle element. Similarly, the condition for equality also needs to be adjusted.
The modified code for binary search in descending order would look like this:
public static int binarysearch2(int[] list, int key) {
int low = 0;
int high = list.length - 1;
while (high >= low) {
int mid = (low + high) / 2;
if (key > list[mid])
high = mid - 1;
else if (key < list[mid])
low = mid + 1;
else
return mid;
}
return -1; // Not found
}
By swapping the conditions, we ensure that the algorithm correctly searches for the key in a descending ordered array.
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demand is modeled with a normal distribution that has a mean of 300 and a standard deviation of 50. what is the probability that demand is 400 or more?
The area to the right of z = 2 is approximately 0.0228 or 2.28%. So, there is a 2.28% probability that demand is 400 or more.
To answer this question, we need to use the concept of deviation and distribution. In this case, we know that demand is normally distributed with a mean of 300 and a standard deviation of 50.
To find the probability that demand is 400 or more, we need to find the area under the normal curve to the right of 400. We can use a standard normal distribution table or a calculator to find this probability.
Using a calculator, we can standardize the value of 400 as follows:
z = (400 - 300) / 50
z = 2
We then look up the probability of a standard normal distribution being greater than 2, which is approximately 0.0228.
Therefore, the probability that demand is 400 or more is approximately 0.0228 or 2.28%.
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Round answer to the nearest hundredth
Answer:
10.7
Step-by-step explanation:
use
a^2+b^2=c^2
...........
Answer:
x ≈ 10.72
Step-by-step explanation:
Use the Pythagorean Theorem, or
a² + b² = c²
to find x.
a² + b² = c²
9² + x² = 14²
81 + x² = 196
Subtract 81 from both sides.
x² = 115
Take the square root.
x = √115
When rounded to the nearest hundredth as a decimal, the answer is
x = 10.72.
Please help me what is a NOW a/4 − 5/6 = −1/2
Answer:
Step-by-step explanation:
Change the denominator of the 1/2 to sixths. Multiply the top and bottom by 3 to get 3/6
\(\frac{a}{4}-\frac{5}{6}=-\frac{3}{6} \\\)
Add 5/6 to both sides and simplify
\(\frac{a}{4} =\frac{1}{3}\)
Multiply both sides by 4 to get
a=4/3
3/5 of an apple tree are ripe what PERCENT of the tree is NOT ripe?
Answer:
40 percent
Step-by-step explanation:
100 / 5 = 20
⅕ = 20 percent
⅗ = 60 percent
100 - 60 = 40
Find the product.
-7(-a 2)(-5)
Answer:
3
5
(
−
2
)
Step-by-step explanation:
Simplify then multiple the numbers
John worked "x" hours this week and Shanique worked eight hours less than John. Write an algebraic expression for the number of
hours that Shanique worked this week.
A) 8x
B) X-8
C)8-X
D)X - 8
Answer:
B or D, I can't tell from these answer choices. X-8
Step-by-step explanation:
Shanique has 8 less questions than John (X).
Find the rate of change
Answer:
the rate of change is 16. 2÷32 = 16
4÷32 is 16 etc
Answer:
1X = 16Y every time the X value goes up by one it increase by 16.
Step-by-step explanation:
If you do 32/2 you will get the answer 16 and if you do 4/64 it also says 16.
The difference between (2,32) and (4,64) 64-32 is 32 4-2 is 2 and you also get 32,2 from that equation.
Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x
Answer:
Option (1)
Step-by-step explanation:
Given equation is,
\(2^x=1-3^x\)
To determine the solution of the equation we will substitute the values of 'x' given in the options,
Option (1)
For x = -0.75
\(2^{-0.75}=1-3^{-0.75}\)
0.59 = 1 - 0.44
0.59 = 0.56
Since, values on both the sides are approximately same.
Therefore, x = -0.75 will be the answer.
Option (2)
For x = -1.25
\(2^{-1.25}=1-3^{-1.25}\)
0.42 = 1 - 0.25
0.42 = 0.75
Which is not true.
Therefore, x = -1.25 is not the answer.
Option (3)
For x = 0.75
\(2^{0.75}=1-3^{0.75}\)
1.68 = 1 - 2.28
1.68 = -1.28
Which is not true.
Therefore, x = 0.75 is not the answer.
Option (4)
For x = 1.25
\(2^{1.25}=1-3^{1.25}\)
2.38 = 1 - 3.95
2.38 = -2.95
It's not true.
Therefore, x = 1.25 is not the answer.
Please help due soon.
Answer:
-3x>24
Step-by-step explanation:
-3x-10>14
now we add 10 to both sides, 10+14 is 24
so, the missing step is -3x>24
Use Algorithm 1 to find the transitive closures of these relations on {1, 2, 3, 4}.
a. {(1,2), (2,1), (2,3), (3,4), (4,1)}
b. {(2,1), (2, 3), (3,1), (3,4), (4,1), (4, 3)}
c. {(1,2), (1,3), (1,4), (2,3), (2,4), (3, 4)}
d. {(1, 1), (1,4), (2,1), (2,3), (3, 1), (3, 2), (3,4), (4, 2)}
To find the transitive closures of the given relations, we can use Algorithm 1, also known as the Warshall's algorithm. Here are the transitive closures for each relation:
a. Relation: {(1,2), (2,1), (2,3), (3,4), (4,1)}
Transitive Closure: {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3), (4,4)}
b. Relation: {(2,1), (2, 3), (3,1), (3,4), (4,1), (4, 3)}
Transitive Closure: {(2,1), (2,3), (2,4), (3,1), (3,3), (3,4), (4,1), (4,3), (4,4)}
c. Relation: {(1,2), (1,3), (1,4), (2,3), (2,4), (3,4)}
Transitive Closure: {(1,2), (1,3), (1,4), (2,3), (2,4), (3,4)}
d. Relation: {(1, 1), (1,4), (2,1), (2,3), (3, 1), (3, 2), (3,4), (4, 2)}
Transitive Closure: {(1,1), (1,4), (2,1), (2,3), (2,4), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3), (4,4)}
In the transitive closure, every pair (i, j) represents a directed edge from i to j in the transitive closure graph.
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Statistics indicate that 45% of all small businesses ______... · 1) B) fail after three · 2) C) with losses to creditors · 3) B) risk tolerance · 4) D) financing ·
Statistics indicate that 45% of all small businesses fail after three years. This is a concerning statistic for entrepreneurs who are considering starting their own business.
It is important for potential business owners to understand the reasons why small businesses fail and take steps to mitigate these risks. Some common reasons for failure include poor management, insufficient funding, lack of market demand, and competition.
One way to mitigate these risks is by having a solid business plan in place that includes a realistic assessment of the market, a clear understanding of the competition, and a plan for securing financing. Additionally, having a strong risk tolerance and the ability to adapt to changing market conditions can also increase the chances of success for small businesses.
Ultimately, the key to success for small businesses is a combination of careful planning, strong management, and a willingness to take calculated risks.
One of the contributing factors to this failure rate is the business owner's risk tolerance (3) B), which may lead them to take on more financial obligations than they can handle. Additionally, securing proper financing (4) D) is crucial for the success and growth of a small business, and a lack of adequate funding may contribute to the high failure rate.
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There are 2 seats on the left side of a plane and three seats on the right. If there are 45 seats on the right, how many are on the left?
Answer:
30 seats
Step-by-step explanation:
For every row, there are 2 seats on the left and 3 seats on the right.
If there are 45 seats total on the right side, then there must be 45/3 = 15 rows. Therefore, there are 15*2= 30 seats on the left.
write the equation in spherical coordinates. (a) x2 + y2 + z2 = 81
The equation in spherical coordinates is:
\($\sin^2(\phi)\cos^2(\theta) + \sin^2(\phi)\sin^2(\theta) + \cos^2(\phi) = 1$\)
What is Equation in Spherical Coordinates?
A mathematical equation that is represented in terms of the spherical coordinates of a point is known as an equation in spherical coordinates. A three-dimensional coordinate system known as spherical coordinates makes use of two angles, typically represented by symbols and a radial distance (r), and a coordinate system to find points in space.
\($r^2 = 81$\)
To represent the equation in spherical coordinates, we substitute the Cartesian coordinates \($x = r\sin(\phi)\cos(\theta)$, $y = r\sin(\phi)\sin(\theta)$, and $z = r\cos(\phi)$\) into the equation. After substitution and simplification, we have:
\($r^2\sin^2(\phi)\cos^2(\theta) + r^2\sin^2(\phi)\sin^2(\theta) + r^2\cos^2(\phi) = 81$\)
Since \(r^2 = 81,\) we can substitute it into the equation:
\($81\sin^2(\phi)\cos^2(\theta) + 81\sin^2(\phi)\sin^2(\theta) + 81\cos^2(\phi) = 81$\)
Finally, we divide the equation by 81 to simplify:
\($\sin^2(\phi)\cos^2(\theta) + \sin^2(\phi)\sin^2(\theta) + \cos^2(\phi) = 1$\)
So, the equation in spherical coordinates is:
\($\sin^2(\phi)\cos^2(\theta) + \sin^2(\phi)\sin^2(\theta) + \cos^2(\phi) = 1$\)
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HELP!!!! I NEED TO SUBMIT THIS WITHIN 3 HOURS!!!!!!
At a dinner party, two desserts are being served. Six of the guests choose cheesecake, and eight of the guests choose apple pie. Write two associated part-to-whole ratios for this situation, in simplest form. Then, interpret these ratios within the situation.
Answer:
6:8, 3:4
hope this helps, im not sure if im correct tho sorry
Step-by-step explanation:
evaluate 2ps for p=3 and s=5
A)30
B)23
C)6
D)10
Answer: the real answer for this will be p=3/2 and s=5
Step-by-step explanation: here
2p=3
2p/2=3b/2 divide both sides by 2
P=3/2
3/2 for p in s=5
S=5
S=5
Answer P=3/2 and s= 5
Got it
Hey there!
“Evaluate 2ps for p=3 and s=5”
• Side note: If p = 3 then SUBSTITUTE where “p” is at in the equation; if s = 5 then SUBSTITUTE where “s” is at in the equation!
• New equation: 2(3)(5)
2(3)(5)
2(3) = 6
6(5) = 30
Answer: A. 30 ☑️
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
A farmer is selling watermelons. She has 43 watermelons and plans to sell them for $3 each. The farmer’s total sales, in dollars, is a function of the number of watermelons she sells. Select all the statements that correctly describe the domain or range of this function.
Responses
The domain is the set of all integers from 0 to 43.
The domain is the set of all real numbers from 0 to 43.
The range is the set of all integers between 0 and 129.
The range is the set of all multiples of 3 from 0 to 129.
all that apply
The range is the set of all multiples of 43 from 43 to 129.
Answer:
In summary, the correct statements are:
The domain is the set of all integers from 0 to 43.
The range is the set of all multiples of 3 from 0 to 129.
this is the best i could do, make what you want of it, good luck
Step-by-step explanation:
he domain of this function is the set of all possible inputs, which in this case is the number of watermelons the farmer can sell. Since the farmer has 43 watermelons and cannot sell a fraction of a watermelon, the domain is the set of all integers from 0 to 43. So, the first statement is correct.
The second statement is incorrect because the farmer cannot sell a fraction of a watermelon, so the domain cannot include all real numbers from 0 to 43.
The range of this function is the set of all possible outputs, which in this case is the total sales in dollars. Since the farmer sells each watermelon for $3, her total sales will be a multiple of 3. The minimum sales value is $0 (if she sells no watermelons) and the maximum sales value is $129 (if she sells all 43 watermelons). So, the range is the set of all multiples of 3 from 0 to 129. Therefore, the fourth statement is correct.
The third statement is incorrect because not all integers between 0 and 129 are possible values for the farmer’s total sales. For example, she cannot make $2 in sales because her sales will always be a multiple of 3.
The fifth statement is incorrect because it implies that the farmer can only make sales in multiples of 43, which is not true since she sells each watermelon for $3.
In summary, the correct statements are:
The domain is the set of all integers from 0 to 43.
The range is the set of all multiples of 3 from 0 to 129.
the diagonals of rhombus WXYZ intersect avfm angle w z x equals 39.5 find M angle zyx
Since WXYZ is a rhombus, the diagonal segment ZX bisects the angle WZY. Therefore,
Since WXYZ is a rhombus, segment WZ is parallel to segment XY and segment ZY is a transversal. So,
Therefore, the measure of the angle ZYX is 101.
Point A has coordinates (3,4) . After a translation 4 units left, a reflection across the x-axis, and a translation 2 units down, what are the coordinates of the image?
Answer:
(-1,-6)
Step-by-step explanation:
1. Translation 4 units to the left - (-1,4)
2. Reflection across the x axis - (-1,-4)
3. Translation 2 units down - (-1,-6)
A triangle has side measurements of
2x² + 3x -5, 5x² - 2x + 3, and 4x²+x-1
What is the perimeter of the triangle?
The perimeter of the triangle is 11x² + 2x - 3.
How to find the perimeter of a triangle?A triangle is a polygon with three sides. The sum of angles in a triangle is 180 degrees.
The perimeter of a triangle is the sum of the whole sides of the triangle.
Therefore, the triangle has the side length 2x² + 3x -5, 5x² - 2x + 3, and 4x²+ x - 1.
Hence,
perimeter of the triangle = 2x² + 3x -5 + 5x² - 2x + 3 + 4x²+ x - 1
combine like terms
perimeter of the triangle = 2x² + 5x² + 4x² + 3x - 2x + x - 5 + 3 - 1
perimeter of the triangle = 11x² + 2x - 3
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What is –9.2(8x – 4) 0.7(2 6.3x) simplified? –69.19x – 32.39 –69.19x 38.2 –72.2x 41.21 75x – 338.2
The simplified form of the expression –9.2(8x – 4) + 0.7(2 – 6.3x) is:
–78.01x + 38.2.
To simplify the expression –9.2(8x – 4) + 0.7(2 – 6.3x), we start by applying the distributive property.
First, we distribute –9.2 to the terms inside the first parentheses:
–9.2(8x – 4) = –9.2 * 8x + –9.2 * (-4) = –73.6x + 36.8
Next, we distribute 0.7 to the terms inside the second parentheses:
0.7(2 – 6.3x) = 0.7 * 2 + 0.7 * (-6.3x) = 1.4 – 4.41x
Now, we combine the simplified terms:
–73.6x + 36.8 + 1.4 – 4.41x = –73.6x – 4.41x + 36.8 + 1.4
Finally, we combine like terms:
–73.6x – 4.41x + 36.8 + 1.4 = –78.01x + 38.2
Therefore, the simplified expression is –78.01x + 38.2.
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The ones digit in the cube of 529 is??
Answer:9
Step-by-step explanation: 529 x 529 x 529=
148035889
Use the Central Limit Theorem to find the probability of the indicated event, assuming that the distribution of the population data is unknown. In a certain city, employees work an average of 18.9 hours of overtime every month, with a standard deviation of 7.8 hours. What is the probability that the average number of hours of overtime worked last month by a random sample of 140 employees in the city exceeds 20 hours? Provide a solution showing your calculations and submit your work for marking. Include a sketch as part of your complete solution. P(X > 20)=
The probability that the average number of hours of overtime worked last month by a random sample of 140 employees in the city exceeds 20 hours is approximately 0.9564, or 95.64%.
To find the probability that the average number of hours of overtime worked by a random sample of 140 employees exceeds 20 hours, we can use the Central Limit Theorem (CLT). The CLT states that for a large enough sample size, the sampling distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.
Given that the population mean is 18.9 hours and the population standard deviation is 7.8 hours, we can calculate the standard error of the mean using the formula: standard error = population standard deviation / sqrt(sample size).
For this problem, the sample size is 140, so the standard error is 7.8 / sqrt(140) ≈ 0.659.
To calculate the probability, we need to standardize the sample mean using the z-score formula: z = (sample mean - population mean) / standard error.
In this case, the sample mean is 20 hours, the population mean is 18.9 hours, and the standard error is 0.659. Plugging these values into the formula, we get z = (20 - 18.9) / 0.659 ≈ 1.71.
Now, we can use a standard normal distribution table or calculator to find the probability associated with a z-score of 1.71. Looking up this value in the table, we find that the probability is approximately 0.9564.
Therefore, the probability that the average number of hours of overtime worked last month by a random sample of 140 employees in the city exceeds 20 hours is approximately 0.9564, or 95.64%.
Here's a sketch to visualize the calculation:
|
|
|
| **
| * *
| * *
| * *
| * *
| * *
| * *
-------------------|--------------------------
18.9 | 20
The area under the curve to the right of 20 represents the probability we're interested in, which is approximately 0.9564 or 95.64%.
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