The forces exerted on an object are shown. (3 points)

A box has an arrow pointing up labeled F and an arrow pointing down labeled 3 N.

If the net force on the object along the vertical plane is zero, which statement is correct?
F equals 3 N and the object moves up.
F equals 3 N and the object remains stationary.
F equals 0 N and the object moves down.
F equals 0 N and the object remains stationary.

Answer:

Merritt Island i think

The final velocity of the student after travelling 12 m is 4 m/s.

The final velocity of the student is determined by applying the following Kinematic equation.

v² = u² + 2as

where;

v² = (2)² + 2(0.5)(12)

v² = 16

v = √16

v = 4 m/s

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The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

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Answer:

5.03

Explanation:

trust me

The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².

Acceleration is change of velocity with respect to time (can include deceleration or changing direction).

The acceleration of a body can be calculated by using the following expression;

a = F/m

Where;

According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:

a = 4N ÷ 2.55kg

a = 1.57m/s²

Therefore, 1.57m/s² is the acceleration of the object.

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The gravitational pull of the sun is equal to the gravitational pull of the moon on the earth.

On the surface of the Moon, the acceleration caused by gravity is roughly 1.625 m/s2, or 0.166, or about 16.6% of that on the surface of the Earth. Approximately 0.0253 m/s2 (1.6% of the gravitational acceleration) of gravitational acceleration varies over the entire surface.

The moon is 1100 times as massive as the earth and has a radius that is 14 times as large. As a result, the gravitational pull on the moon is roughly one sixth of what it is on the earth. As a result, an object's weight on the moon is 16 times that of an object on Earth.

Despite having a surface gravity that is only 17% that of the Earth, the moon's gravitational pull is great enough to prevent the Earth from significantly modifying the tilt of its orbit.

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Answer:

We know that,

Pressure = Force ÷ Area

First let's find the force of the cube.

F = m × g

  = 20 kg  × 10 ms⁻²

  = 200N

Now let us find the Area of the cube.

A = 6 a²

   = 6 × \(\frac{50}{100}\) × \(\frac{50}{100}\)

   = 1.5 m²

Now let us find the pressure.

Pressure = Force ÷ Area

               = 200 N ÷ 1.5 m²

               = 133 . 33 N m⁻² / 133 . 33 Pa

Hope this helps you :-)

Explanation:

We know that

F = ma

Here,

a = g = 10 m/s²

So,

F = mg

=> F = 20 × 10

=> F = 200 N

now,

As 1 m = 100 cm

50 cm = 50/100 = 0.5 m

=> SA of cube = 6a²

=> SA = 6(0.5)²

=> SA = 6 × 0.25

=> SA = 1.5 m²

Now,

P = F/A

=> P = 200/1.5

=> P = 2000/15

=> P = 400/3

=> P = 133.3 Pa

Potholder should have high insulation and low conductivity, therefore the correct answer is the option B

Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.

For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.

The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.

Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B

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your question seems incomplete, the complete question is

To be effective, a pot holder should have low _____. viscosity conductivity malleability density

Answer:

Explanation:

To calculate the elastic potential energy stored in the flea's legs before the leap, we need to use the conservation of energy principle, which states that the total energy of a system is constant.

Initially, the flea was at rest on the dog's cranium, so it had zero kinetic energy. However, it had some elastic potential energy stored in its legs due to the compression of its leg muscles before the leap. This energy was converted into kinetic energy as the flea jumped.

At the highest point of the flea's trajectory, it had reached its maximum height, so it had zero kinetic energy. However, it had some gravitational potential energy due to its height above the dog's cranium. This energy was equal to the amount of elastic potential energy stored in its legs before the leap.

Using the conservation of energy principle, we can equate the elastic potential energy stored in the flea's legs to its gravitational potential energy at the highest point of its trajectory:

Elastic potential energy = Gravitational potential energy

1/2 kx^2 = mgh

where k is the spring constant of the flea's leg muscles, x is the distance the flea's legs were compressed before the leap, m is the mass of the flea, g is the acceleration due to gravity, and h is the maximum height of the flea's trajectory.

We need to express all the quantities in SI units:

m = 0.10 g = 0.0001 kg

v = 1.25 m/s

h = 5.00 cm = 0.05 m

g = 9.81 m/s^2

To determine k and x, we need to use the fact that the kinetic energy of the flea at the moment of the leap is equal to the elastic potential energy stored in its legs:

1/2 mv^2 = 1/2 kx^2

Solving for x:

x = sqrt(mv^2/k)

Substituting the known values:

x = sqrt(0.0001*1.25^2/k)

Now, we can substitute the values of m, x, and h into the equation for the elastic potential energy:

1/2 kx^2 = mgh

1/2 k (0.00011.25^2/k) = 0.00019.81*0.05

0.000078125 k = 0.00004905

k = 0.627 N/m

Finally, we can substitute the value of k and x into the equation for the elastic potential energy:

1/2 kx^2 = 1/20.627(0.0001*1.25^2/k)^2

Elastic potential energy = 0.0000156 J

Therefore, the elastic potential energy stored in the flea's legs before the leap was 0.0000156 J.

Answer:

The rate of deceleration is 15 km/h^2.

Explanation:

Since the car comes in 90km/h, it will need deceleration for 15 km/h for 6 seconds to finally stop the car. 15*6=90

Answer:

upward thrust, makes the rocket go up

and kentic energy, you swing and the energy that was built up before you hit the ball was transferred

Explanation:

\(\\ \bull\tt\dashrightarrow Density=\dfrac{Mass}{Volume}\)

\(\\ \bull\tt\dashrightarrow Volume=\dfrac{Mass}{Density}\)

\(\\ \bull\tt\dashrightarrow Volume=\dfrac{15}{0.789}\)

\(\\ \bull\tt\dashrightarrow Volume=19.01mL\)

Use the definition of average acceleration:

a = ∆v / ∆t

Let x be the final velocity. Then

7.5 m/s² = (x - 25 m/s) / (8.0 s)

x = 25 m/s + (7.5 m/s²) (8.0 s)

x = 85 m/s

Answer:

A) It is the length from the midpoint to the crest.

Explanation:

The correct statement about the amplitude of any transverse wave is: It is the length from the midpoint to the crest. The correct option is A.

A transverse wave is a type of wave in which the displacement of the medium is perpendicular to the direction of wave propagation.

Examples of transverse waves include light waves and water waves in which the surface of the water oscillates up and down while the wave moves horizontally.

The properties of a transverse wave include:

Amplitude: The maximum displacement of the medium from its rest position. This represents the intensity or strength of the wave.

Wavelength: The distance between two adjacent points in the wave that are in phase with each other, for example, between two consecutive crests or troughs. It is typically represented by the symbol λ.

Frequency: The number of complete wave cycles that pass a point in a given amount of time, usually measured in hertz (Hz). The frequency is inversely proportional to the wavelength and is represented by the symbol f.

Period: The time taken for one complete wave cycle to pass a given point, usually represented by the symbol T. The period is directly proportional to the wavelength and inversely proportional to the frequency.

Speed: The speed at which the wave propagates through the medium, usually represented by the symbol v. The speed is directly proportional to the frequency and wavelength.

These properties are related to each other by the wave equation:

v = fλ,

Where v = the speed of the wave,

f = the frequency,

and λ = the wavelength.

Therefore, The correct statement about the amplitude of any transverse wave is A. It is the length from the midpoint to the crest.

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Answer:

Three controls on a car can change its velocity - the accelerator pedal, brake pedal, and steering wheel. Velocity changes if either speed or direction change.

Explanation:

Hope it helps

Answer:

A force

Explanation:

A force is that which causes a change in velocity, or acceleration. The amount of acceleration produced on an object by a given force is determined by the object's mass.

If the potential throughout a particular region is constant, the field throughout that region must be zero.[CORRECT]

The following are the characteristics of potential energy

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Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

\(v_{f} - v_{i} = at\)

\(v_{i}=22.54m/s\)

also the speed after 0.5 s is

\(v_{f} = 17.64m/s\)

So, the speed of the ball at launch is 23m/s.

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Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.

Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

The current in the circuit is 2.5 A.

Voltage across the wire AX, V = 4 - 2 = 2V

Resistance per unit length of wire AX, R/l = 2 Ω/m

Length of the wire, l = 0.4 m

Resistance of the wire,

R = R/l x R

R = 2 x 0.4 = 0.8 Ω

According to Ohm's law, the current in the wire AX,

I = V/R

I = 2/0.8

I = 2.5 A

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If all conditions are ideal, you may harvest about five to 10 potatoes per plant for your gardening efforts. Yields are based on both the care your give your plants during the growing season and the variety of potatoes you choose to grow.

answer

7.5×10.000=75÷3=25

Answer:

Before providing an answer to the question, the values for acceleration given in questions A and B were written twice. So correction would go like this: For (a) when the truck accelerates at 2.20m/s2 northward, and for (b) when it accelerates at 3.40m/s2 southward.

The answer:

(a) 88N, northward.

(b) 78.4‬, southward.

Explanation:

(a) Maximum frictional force acting on the packing case= (coefficient of static friction) X (Normal force)

Normal force = mass X acceleration due to gravity

Maximum static frictional force acting on the packing case = (coefficient of static friction) X (mass of packing case  X acceleration due to gravity)

Maximum static frictional force = (0.30) X (40.0-kg) X (9.8m/s 2) = 117.6N

While Reaction force acting on the packing case = (mass of packing case) x (acceleration generated by the pickup truck)

Reaction force acting on the case = (40.0-kg) X (2.20m/s2) = 88N

With these values, one can conclude that the packing case is at rest since the reaction force of the case acting in the opposite direction is lesser than the frictional force. Making the magnitude and direction of the friction force acting on the case still move northward, and the static frictional force acting on equals the reaction force.

The answer is 88N, northward.

(b)  Here too, we need to still compare the reaction force with the value of the already determined Maximum static frictional force (117.6N) above. This is necessary to know the frictional force between the pickup truck"s floor and the packing case.

Reaction force acting on the case when acceleration is 3.40m/s2 = (40.0-kg) X (3.40m/s2) = 136‬ N

We can conclude that the reaction force (136‬ N) is greater than the maximum static frictional force (117.6N), suggesting that the packing case is in motion and the frictional force is no longer static.

This means a kinetic force is now acting on the pickup truck"s floor causing the packing case to also move. This kinetic force can be calculated as:

kinetic force = (coefficient of kinetic friction) X  (mass of packing case  X acceleration due to gravity)

= (0,20) X (40.0-kg) X (9.8m/s 2) = 78.4‬N